contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
714 | A | Meeting of Old Friends | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | null | null | Today an outstanding event is going to happen in the forest — hedgehog Filya will come to his old fried Sonya!
Sonya is an owl and she sleeps during the day and stay awake from minute *l*1 to minute *r*1 inclusive. Also, during the minute *k* she prinks and is unavailable for Filya.
Filya works a lot and he plans to visit Sonya from minute *l*2 to minute *r*2 inclusive.
Calculate the number of minutes they will be able to spend together. | The only line of the input contains integers *l*1, *r*1, *l*2, *r*2 and *k* (1<=≤<=*l*1,<=*r*1,<=*l*2,<=*r*2,<=*k*<=≤<=1018, *l*1<=≤<=*r*1, *l*2<=≤<=*r*2), providing the segments of time for Sonya and Filya and the moment of time when Sonya prinks. | Print one integer — the number of minutes Sonya and Filya will be able to spend together. | [
"1 10 9 20 1\n",
"1 100 50 200 75\n"
] | [
"2\n",
"50\n"
] | In the first sample, they will be together during minutes 9 and 10.
In the second sample, they will be together from minute 50 to minute 74 and from minute 76 to minute 100. | 500 | [
{
"input": "1 10 9 20 1",
"output": "2"
},
{
"input": "1 100 50 200 75",
"output": "50"
},
{
"input": "6 6 5 8 9",
"output": "1"
},
{
"input": "1 1000000000 1 1000000000 1",
"output": "999999999"
},
{
"input": "5 100 8 8 8",
"output": "0"
},
{
"input":... | 1,585,609,811 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 9 | 124 | 0 | l1, r1, l2, r2, k= map(int,input().split())
l = max(l1,l2)
r = min(r1,r2)
if l<=k<=r:
print(r-l)
else:
print(r-l+1) | Title: Meeting of Old Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today an outstanding event is going to happen in the forest — hedgehog Filya will come to his old fried Sonya!
Sonya is an owl and she sleeps during the day and stay awake from minute *l*1 to minute *r*1 inclusive. Also, during the minute *k* she prinks and is unavailable for Filya.
Filya works a lot and he plans to visit Sonya from minute *l*2 to minute *r*2 inclusive.
Calculate the number of minutes they will be able to spend together.
Input Specification:
The only line of the input contains integers *l*1, *r*1, *l*2, *r*2 and *k* (1<=≤<=*l*1,<=*r*1,<=*l*2,<=*r*2,<=*k*<=≤<=1018, *l*1<=≤<=*r*1, *l*2<=≤<=*r*2), providing the segments of time for Sonya and Filya and the moment of time when Sonya prinks.
Output Specification:
Print one integer — the number of minutes Sonya and Filya will be able to spend together.
Demo Input:
['1 10 9 20 1\n', '1 100 50 200 75\n']
Demo Output:
['2\n', '50\n']
Note:
In the first sample, they will be together during minutes 9 and 10.
In the second sample, they will be together from minute 50 to minute 74 and from minute 76 to minute 100. | ```python
l1, r1, l2, r2, k= map(int,input().split())
l = max(l1,l2)
r = min(r1,r2)
if l<=k<=r:
print(r-l)
else:
print(r-l+1)
``` | 0 | |
617 | A | Elephant | PROGRAMMING | 800 | [
"math"
] | null | null | An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make in order to get to his friend's house. | The first line of the input contains an integer *x* (1<=≤<=*x*<=≤<=1<=000<=000) — The coordinate of the friend's house. | Print the minimum number of steps that elephant needs to make to get from point 0 to point *x*. | [
"5\n",
"12\n"
] | [
"1\n",
"3\n"
] | In the first sample the elephant needs to make one step of length 5 to reach the point *x*.
In the second sample the elephant can get to point *x* if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach *x* in less than three moves. | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "12",
"output": "3"
},
{
"input": "999999",
"output": "200000"
},
{
"input": "41",
"output": "9"
},
{
"input": "1000000",
"output": "200000"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
... | 1,694,231,348 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 77 | 0 | n=int(input())
counter=0
while n>0:
for i in range(5,0,-1):
while n>=i:
n-=i
counter+=1
if n==0:
break
print(counter) | Title: Elephant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make in order to get to his friend's house.
Input Specification:
The first line of the input contains an integer *x* (1<=≤<=*x*<=≤<=1<=000<=000) — The coordinate of the friend's house.
Output Specification:
Print the minimum number of steps that elephant needs to make to get from point 0 to point *x*.
Demo Input:
['5\n', '12\n']
Demo Output:
['1\n', '3\n']
Note:
In the first sample the elephant needs to make one step of length 5 to reach the point *x*.
In the second sample the elephant can get to point *x* if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach *x* in less than three moves. | ```python
n=int(input())
counter=0
while n>0:
for i in range(5,0,-1):
while n>=i:
n-=i
counter+=1
if n==0:
break
print(counter)
``` | 3 | |
194 | A | Exams | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | One day the Codeforces round author sat exams. He had *n* exams and he needed to get an integer from 2 to 5 for each exam. He will have to re-sit each failed exam, i.e. the exam that gets mark 2.
The author would need to spend too much time and effort to make the sum of his marks strictly more than *k*. That could have spoilt the Codeforces round. On the other hand, if the sum of his marks is strictly less than *k*, the author's mum won't be pleased at all.
The Codeforces authors are very smart and they always get the mark they choose themselves. Also, the Codeforces authors just hate re-sitting exams.
Help the author and find the minimum number of exams he will have to re-sit if he passes the exams in the way that makes the sum of marks for all *n* exams equal exactly *k*. | The single input line contains space-separated integers *n* and *k* (1<=≤<=*n*<=≤<=50, 1<=≤<=*k*<=≤<=250) — the number of exams and the required sum of marks.
It is guaranteed that there exists a way to pass *n* exams in the way that makes the sum of marks equal exactly *k*. | Print the single number — the minimum number of exams that the author will get a 2 for, considering that the sum of marks for all exams must equal *k*. | [
"4 8\n",
"4 10\n",
"1 3\n"
] | [
"4\n",
"2\n",
"0\n"
] | In the first sample the author has to get a 2 for all his exams.
In the second sample he should get a 3 for two exams and a 2 for two more.
In the third sample he should get a 3 for one exam. | 500 | [
{
"input": "4 8",
"output": "4"
},
{
"input": "4 10",
"output": "2"
},
{
"input": "1 3",
"output": "0"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "4 9",
"output": "3"
},
{
"input": "50 234",
"output": "0"
},
{
"input": "50 100",
"... | 1,617,997,368 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 92 | 0 | n, k = map(int, input().split())
if k/n > 2:
print(0)
else:
print(n-(k%n))
| Title: Exams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day the Codeforces round author sat exams. He had *n* exams and he needed to get an integer from 2 to 5 for each exam. He will have to re-sit each failed exam, i.e. the exam that gets mark 2.
The author would need to spend too much time and effort to make the sum of his marks strictly more than *k*. That could have spoilt the Codeforces round. On the other hand, if the sum of his marks is strictly less than *k*, the author's mum won't be pleased at all.
The Codeforces authors are very smart and they always get the mark they choose themselves. Also, the Codeforces authors just hate re-sitting exams.
Help the author and find the minimum number of exams he will have to re-sit if he passes the exams in the way that makes the sum of marks for all *n* exams equal exactly *k*.
Input Specification:
The single input line contains space-separated integers *n* and *k* (1<=≤<=*n*<=≤<=50, 1<=≤<=*k*<=≤<=250) — the number of exams and the required sum of marks.
It is guaranteed that there exists a way to pass *n* exams in the way that makes the sum of marks equal exactly *k*.
Output Specification:
Print the single number — the minimum number of exams that the author will get a 2 for, considering that the sum of marks for all exams must equal *k*.
Demo Input:
['4 8\n', '4 10\n', '1 3\n']
Demo Output:
['4\n', '2\n', '0\n']
Note:
In the first sample the author has to get a 2 for all his exams.
In the second sample he should get a 3 for two exams and a 2 for two more.
In the third sample he should get a 3 for one exam. | ```python
n, k = map(int, input().split())
if k/n > 2:
print(0)
else:
print(n-(k%n))
``` | 0 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word. | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,598,139,015 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 216 | 6,656,000 | import sys
lower = 0
upper = 0
for word in sys.stdin:
for char in word:
if(char.islower()):
lower+=1
if(char.isupper()):
upper+=1
if(lower >= upper):
print(word.lower().rstrip())
else:
print(word.upper().rstrip())
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word.
Input Specification:
The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100.
Output Specification:
Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one.
Demo Input:
['HoUse\n', 'ViP\n', 'maTRIx\n']
Demo Output:
['house\n', 'VIP\n', 'matrix\n']
Note:
none | ```python
import sys
lower = 0
upper = 0
for word in sys.stdin:
for char in word:
if(char.islower()):
lower+=1
if(char.isupper()):
upper+=1
if(lower >= upper):
print(word.lower().rstrip())
else:
print(word.upper().rstrip())
``` | 3.933602 |
152 | B | Steps | PROGRAMMING | 1,300 | [
"binary search",
"implementation"
] | null | null | One day Vasya went out for a walk in the yard but there weren't any of his friends outside and he had no one to play touch and run. But the boy didn't lose the high spirits and decided to play touch and run with himself. You may ask: "How did he do that?" The answer is simple.
Vasya noticed that the yard is a rectangular *n*<=×<=*m* field. The squares have coordinates (*x*,<=*y*) (1<=≤<=*x*<=≤<=*n*,<=1<=≤<=*y*<=≤<=*m*), where *x* is the index of the row and *y* is the index of the column.
Initially Vasya stands in the square with coordinates (*x**c*,<=*y**c*). To play, he has got a list of *k* vectors (*dx**i*,<=*dy**i*) of non-zero length. The game goes like this. The boy considers all vectors in the order from 1 to *k*, and consecutively chooses each vector as the current one. After the boy has chosen a current vector, he makes the maximally possible number of valid steps in the vector's direction (it is possible that he makes zero steps).
A step is defined as one movement from the square where the boy is standing now, in the direction of the current vector. That is, if Vasya is positioned in square (*x*,<=*y*), and the current vector is (*dx*,<=*dy*), one step moves Vasya to square (*x*<=+<=*dx*,<=*y*<=+<=*dy*). A step is considered valid, if the boy does not go out of the yard if he performs the step.
Vasya stepped on and on, on and on until he ran out of vectors in his list. Ha had been stepping for so long that he completely forgot how many steps he had made. Help the boy and count how many steps he had made. | The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=109) — the yard's sizes. The second line contains integers *x**c* and *y**c* — the initial square's coordinates (1<=≤<=*x**c*<=≤<=*n*,<=1<=≤<=*y**c*<=≤<=*m*).
The third line contains an integer *k* (1<=≤<=*k*<=≤<=104) — the number of vectors. Then follow *k* lines, each of them contains two integers *dx**i* and *dy**i* (|*dx**i*|,<=|*dy**i*|<=≤<=109,<=|*dx*|<=+<=|*dy*|<=≥<=1). | Print the single number — the number of steps Vasya had made.
Please do not use the %lld specificator to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specificator. | [
"4 5\n1 1\n3\n1 1\n1 1\n0 -2\n",
"10 10\n1 2\n1\n-1 0\n"
] | [
"4\n",
"0\n"
] | In the first sample Vasya is initially positioned at square (1, 1) and makes 3 steps by the first vector (1, 1). So, he consecutively visits the squares (2, 2), (3, 3), (4, 4). Then he makes 0 steps by the second vector (1, 1). He makes 1 more step by the third vector (0, - 2) and he ends up in square (4, 2). Overall, Vasya makes 4 steps.
In the second sample Vasya is initially positioned in square (1, 2) and makes 0 steps by vector ( - 1, 0), as the square with coordinates (0, 2) is located outside the yard. | 1,000 | [
{
"input": "4 5\n1 1\n3\n1 1\n1 1\n0 -2",
"output": "4"
},
{
"input": "10 10\n1 2\n1\n-1 0",
"output": "0"
},
{
"input": "10 20\n10 3\n10\n-2 -6\n-1 0\n-8 0\n0 5\n-1 3\n16 -16\n-1 9\n0 -18\n9 -1\n-9 5",
"output": "13"
},
{
"input": "20 10\n14 4\n10\n6 0\n-7 -7\n12 -2\n-4 9\n2... | 1,674,786,916 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 124 | 0 | n, m = map(int, input().split())
xc, yc = map(int, input().split())
k = int(input())
ans = 0
for i in range(k):
dx, dy = map(int, input().split())
if (xc + dx <= m and xc + dx > 0) and (yc + dy <= n and yc + dy > 0):
mxmn = min(n, m)
x = (mxmn - xc) if xc < mxmn else xc
y = (mxmn - yc) if yc < mxmn else yc
if dx != 0 and dy != 0:
mxx = (x) // dx
myy = (y) // dy
addx = addy = min(mxx, myy)
else:
if dx == 0:
addx = 0
else:
addx = (x - 1) // abs(dx)
if dy == 0:
addy = 0
else:
addy = (y - 1) // abs(dy)
xc += addx * dx
yc += addy * dy
ans += max(abs(addx), abs(addy))
print('ans', ans) | Title: Steps
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya went out for a walk in the yard but there weren't any of his friends outside and he had no one to play touch and run. But the boy didn't lose the high spirits and decided to play touch and run with himself. You may ask: "How did he do that?" The answer is simple.
Vasya noticed that the yard is a rectangular *n*<=×<=*m* field. The squares have coordinates (*x*,<=*y*) (1<=≤<=*x*<=≤<=*n*,<=1<=≤<=*y*<=≤<=*m*), where *x* is the index of the row and *y* is the index of the column.
Initially Vasya stands in the square with coordinates (*x**c*,<=*y**c*). To play, he has got a list of *k* vectors (*dx**i*,<=*dy**i*) of non-zero length. The game goes like this. The boy considers all vectors in the order from 1 to *k*, and consecutively chooses each vector as the current one. After the boy has chosen a current vector, he makes the maximally possible number of valid steps in the vector's direction (it is possible that he makes zero steps).
A step is defined as one movement from the square where the boy is standing now, in the direction of the current vector. That is, if Vasya is positioned in square (*x*,<=*y*), and the current vector is (*dx*,<=*dy*), one step moves Vasya to square (*x*<=+<=*dx*,<=*y*<=+<=*dy*). A step is considered valid, if the boy does not go out of the yard if he performs the step.
Vasya stepped on and on, on and on until he ran out of vectors in his list. Ha had been stepping for so long that he completely forgot how many steps he had made. Help the boy and count how many steps he had made.
Input Specification:
The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=109) — the yard's sizes. The second line contains integers *x**c* and *y**c* — the initial square's coordinates (1<=≤<=*x**c*<=≤<=*n*,<=1<=≤<=*y**c*<=≤<=*m*).
The third line contains an integer *k* (1<=≤<=*k*<=≤<=104) — the number of vectors. Then follow *k* lines, each of them contains two integers *dx**i* and *dy**i* (|*dx**i*|,<=|*dy**i*|<=≤<=109,<=|*dx*|<=+<=|*dy*|<=≥<=1).
Output Specification:
Print the single number — the number of steps Vasya had made.
Please do not use the %lld specificator to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specificator.
Demo Input:
['4 5\n1 1\n3\n1 1\n1 1\n0 -2\n', '10 10\n1 2\n1\n-1 0\n']
Demo Output:
['4\n', '0\n']
Note:
In the first sample Vasya is initially positioned at square (1, 1) and makes 3 steps by the first vector (1, 1). So, he consecutively visits the squares (2, 2), (3, 3), (4, 4). Then he makes 0 steps by the second vector (1, 1). He makes 1 more step by the third vector (0, - 2) and he ends up in square (4, 2). Overall, Vasya makes 4 steps.
In the second sample Vasya is initially positioned in square (1, 2) and makes 0 steps by vector ( - 1, 0), as the square with coordinates (0, 2) is located outside the yard. | ```python
n, m = map(int, input().split())
xc, yc = map(int, input().split())
k = int(input())
ans = 0
for i in range(k):
dx, dy = map(int, input().split())
if (xc + dx <= m and xc + dx > 0) and (yc + dy <= n and yc + dy > 0):
mxmn = min(n, m)
x = (mxmn - xc) if xc < mxmn else xc
y = (mxmn - yc) if yc < mxmn else yc
if dx != 0 and dy != 0:
mxx = (x) // dx
myy = (y) // dy
addx = addy = min(mxx, myy)
else:
if dx == 0:
addx = 0
else:
addx = (x - 1) // abs(dx)
if dy == 0:
addy = 0
else:
addy = (y - 1) // abs(dy)
xc += addx * dx
yc += addy * dy
ans += max(abs(addx), abs(addy))
print('ans', ans)
``` | 0 | |
701 | B | Cells Not Under Attack | PROGRAMMING | 1,200 | [
"data structures",
"math"
] | null | null | Vasya has the square chessboard of size *n*<=×<=*n* and *m* rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.
The cell of the field is under rook's attack, if there is at least one rook located in the same row or in the same column with this cell. If there is a rook located in the cell, this cell is also under attack.
You are given the positions of the board where Vasya will put rooks. For each rook you have to determine the number of cells which are not under attack after Vasya puts it on the board. | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*m*<=≤<=*min*(100<=000,<=*n*2)) — the size of the board and the number of rooks.
Each of the next *m* lines contains integers *x**i* and *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*) — the number of the row and the number of the column where Vasya will put the *i*-th rook. Vasya puts rooks on the board in the order they appear in the input. It is guaranteed that any cell will contain no more than one rook. | Print *m* integer, the *i*-th of them should be equal to the number of cells that are not under attack after first *i* rooks are put. | [
"3 3\n1 1\n3 1\n2 2\n",
"5 2\n1 5\n5 1\n",
"100000 1\n300 400\n"
] | [
"4 2 0 \n",
"16 9 \n",
"9999800001 \n"
] | On the picture below show the state of the board after put each of the three rooks. The cells which painted with grey color is not under the attack. | 750 | [
{
"input": "3 3\n1 1\n3 1\n2 2",
"output": "4 2 0 "
},
{
"input": "5 2\n1 5\n5 1",
"output": "16 9 "
},
{
"input": "100000 1\n300 400",
"output": "9999800001 "
},
{
"input": "10 4\n2 8\n1 8\n9 8\n6 9",
"output": "81 72 63 48 "
},
{
"input": "30 30\n3 13\n27 23\n18... | 1,615,006,652 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 93 | 0 | n,m=map(int,input().split())
col=set();row=set()
old=n*n;coll=0
for i in range(m):
a,b=map(int,input().split())
if a not in row and b not in col:old-=(n+n-1-len(row)-len(col));print(old,end=" ")
elif b not in col:old-=n-len(row);print(old,end=" ")
elif a not in row:old-=n-len(col);print(old,end=" ")
row.add(a)
col.add(b)
#print(old)
| Title: Cells Not Under Attack
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has the square chessboard of size *n*<=×<=*n* and *m* rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.
The cell of the field is under rook's attack, if there is at least one rook located in the same row or in the same column with this cell. If there is a rook located in the cell, this cell is also under attack.
You are given the positions of the board where Vasya will put rooks. For each rook you have to determine the number of cells which are not under attack after Vasya puts it on the board.
Input Specification:
The first line of the input contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100<=000, 1<=≤<=*m*<=≤<=*min*(100<=000,<=*n*2)) — the size of the board and the number of rooks.
Each of the next *m* lines contains integers *x**i* and *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=*n*) — the number of the row and the number of the column where Vasya will put the *i*-th rook. Vasya puts rooks on the board in the order they appear in the input. It is guaranteed that any cell will contain no more than one rook.
Output Specification:
Print *m* integer, the *i*-th of them should be equal to the number of cells that are not under attack after first *i* rooks are put.
Demo Input:
['3 3\n1 1\n3 1\n2 2\n', '5 2\n1 5\n5 1\n', '100000 1\n300 400\n']
Demo Output:
['4 2 0 \n', '16 9 \n', '9999800001 \n']
Note:
On the picture below show the state of the board after put each of the three rooks. The cells which painted with grey color is not under the attack. | ```python
n,m=map(int,input().split())
col=set();row=set()
old=n*n;coll=0
for i in range(m):
a,b=map(int,input().split())
if a not in row and b not in col:old-=(n+n-1-len(row)-len(col));print(old,end=" ")
elif b not in col:old-=n-len(row);print(old,end=" ")
elif a not in row:old-=n-len(col);print(old,end=" ")
row.add(a)
col.add(b)
#print(old)
``` | 0 | |
291 | A | Spyke Talks | PROGRAMMING | 800 | [
"*special",
"implementation",
"sortings"
] | null | null | Polycarpus is the director of a large corporation. There are *n* secretaries working for the corporation, each of them corresponds via the famous Spyke VoIP system during the day. We know that when two people call each other via Spyke, the Spyke network assigns a unique ID to this call, a positive integer session number.
One day Polycarpus wondered which secretaries are talking via the Spyke and which are not. For each secretary, he wrote out either the session number of his call or a 0 if this secretary wasn't talking via Spyke at that moment.
Help Polycarpus analyze these data and find out the number of pairs of secretaries that are talking. If Polycarpus has made a mistake in the data and the described situation could not have taken place, say so.
Note that the secretaries can correspond via Spyke not only with each other, but also with the people from other places. Also, Spyke conferences aren't permitted — that is, one call connects exactly two people. | The first line contains integer *n* (1<=≤<=*n*<=≤<=103) — the number of secretaries in Polycarpus's corporation. The next line contains *n* space-separated integers: *id*1,<=*id*2,<=...,<=*id**n* (0<=≤<=*id**i*<=≤<=109). Number *id**i* equals the number of the call session of the *i*-th secretary, if the secretary is talking via Spyke, or zero otherwise.
Consider the secretaries indexed from 1 to *n* in some way. | Print a single integer — the number of pairs of chatting secretaries, or -1 if Polycarpus's got a mistake in his records and the described situation could not have taken place. | [
"6\n0 1 7 1 7 10\n",
"3\n1 1 1\n",
"1\n0\n"
] | [
"2\n",
"-1\n",
"0\n"
] | In the first test sample there are two Spyke calls between secretaries: secretary 2 and secretary 4, secretary 3 and secretary 5.
In the second test sample the described situation is impossible as conferences aren't allowed. | 500 | [
{
"input": "6\n0 1 7 1 7 10",
"output": "2"
},
{
"input": "3\n1 1 1",
"output": "-1"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "5\n2 2 1 1 3",
"output": "2"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "10\n4 21 3 21 21 1 1 2 2 3",
"ou... | 1,400,311,340 | 2,147,483,647 | Python 3 | OK | TESTS | 38 | 124 | 0 | n = int(input())
s = list(map(int, input().split()))
x = set(s)
r = 0
for i in x:
if i != 0:
p = s.count(i)
if p == 2:
r += 1
elif p > 2:
print(-1)
exit()
print(r)
| Title: Spyke Talks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus is the director of a large corporation. There are *n* secretaries working for the corporation, each of them corresponds via the famous Spyke VoIP system during the day. We know that when two people call each other via Spyke, the Spyke network assigns a unique ID to this call, a positive integer session number.
One day Polycarpus wondered which secretaries are talking via the Spyke and which are not. For each secretary, he wrote out either the session number of his call or a 0 if this secretary wasn't talking via Spyke at that moment.
Help Polycarpus analyze these data and find out the number of pairs of secretaries that are talking. If Polycarpus has made a mistake in the data and the described situation could not have taken place, say so.
Note that the secretaries can correspond via Spyke not only with each other, but also with the people from other places. Also, Spyke conferences aren't permitted — that is, one call connects exactly two people.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=103) — the number of secretaries in Polycarpus's corporation. The next line contains *n* space-separated integers: *id*1,<=*id*2,<=...,<=*id**n* (0<=≤<=*id**i*<=≤<=109). Number *id**i* equals the number of the call session of the *i*-th secretary, if the secretary is talking via Spyke, or zero otherwise.
Consider the secretaries indexed from 1 to *n* in some way.
Output Specification:
Print a single integer — the number of pairs of chatting secretaries, or -1 if Polycarpus's got a mistake in his records and the described situation could not have taken place.
Demo Input:
['6\n0 1 7 1 7 10\n', '3\n1 1 1\n', '1\n0\n']
Demo Output:
['2\n', '-1\n', '0\n']
Note:
In the first test sample there are two Spyke calls between secretaries: secretary 2 and secretary 4, secretary 3 and secretary 5.
In the second test sample the described situation is impossible as conferences aren't allowed. | ```python
n = int(input())
s = list(map(int, input().split()))
x = set(s)
r = 0
for i in x:
if i != 0:
p = s.count(i)
if p == 2:
r += 1
elif p > 2:
print(-1)
exit()
print(r)
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Mashmokh's boss, Bimokh, didn't like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh's team. In order to join he was given some programming tasks and one week to solve them. Mashmokh is not a very experienced programmer. Actually he is not a programmer at all. So he wasn't able to solve them. That's why he asked you to help him with these tasks. One of these tasks is the following.
A sequence of *l* integers *b*1,<=*b*2,<=...,<=*b**l* (1<=≤<=*b*1<=≤<=*b*2<=≤<=...<=≤<=*b**l*<=≤<=*n*) is called good if each number divides (without a remainder) by the next number in the sequence. More formally for all *i* (1<=≤<=*i*<=≤<=*l*<=-<=1).
Given *n* and *k* find the number of good sequences of length *k*. As the answer can be rather large print it modulo 1000000007 (109<=+<=7). | The first line of input contains two space-separated integers *n*,<=*k* (1<=≤<=*n*,<=*k*<=≤<=2000). | Output a single integer — the number of good sequences of length *k* modulo 1000000007 (109<=+<=7). | [
"3 2\n",
"6 4\n",
"2 1\n"
] | [
"5\n",
"39\n",
"2\n"
] | In the first sample the good sequences are: [1, 1], [2, 2], [3, 3], [1, 2], [1, 3]. | 0 | [
{
"input": "3 2",
"output": "5"
},
{
"input": "6 4",
"output": "39"
},
{
"input": "2 1",
"output": "2"
},
{
"input": "1478 194",
"output": "312087753"
},
{
"input": "1415 562",
"output": "953558593"
},
{
"input": "1266 844",
"output": "735042656"
... | 1,396,804,986 | 6,186 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 3 | 1,000 | 1,331,200 | n,k=map(int,input().split())
a=[[0]*n for i in range(k)]
for i in range(n):
a[0][i]=1
for i in range(1,k):
for j in range(n):
for s in range(2**j):
if (j+1)%(s+1)==0:
a[i][j]+=a[i-1][s]
print(sum(a[-1])%(10**9+7)) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mashmokh's boss, Bimokh, didn't like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh's team. In order to join he was given some programming tasks and one week to solve them. Mashmokh is not a very experienced programmer. Actually he is not a programmer at all. So he wasn't able to solve them. That's why he asked you to help him with these tasks. One of these tasks is the following.
A sequence of *l* integers *b*1,<=*b*2,<=...,<=*b**l* (1<=≤<=*b*1<=≤<=*b*2<=≤<=...<=≤<=*b**l*<=≤<=*n*) is called good if each number divides (without a remainder) by the next number in the sequence. More formally for all *i* (1<=≤<=*i*<=≤<=*l*<=-<=1).
Given *n* and *k* find the number of good sequences of length *k*. As the answer can be rather large print it modulo 1000000007 (109<=+<=7).
Input Specification:
The first line of input contains two space-separated integers *n*,<=*k* (1<=≤<=*n*,<=*k*<=≤<=2000).
Output Specification:
Output a single integer — the number of good sequences of length *k* modulo 1000000007 (109<=+<=7).
Demo Input:
['3 2\n', '6 4\n', '2 1\n']
Demo Output:
['5\n', '39\n', '2\n']
Note:
In the first sample the good sequences are: [1, 1], [2, 2], [3, 3], [1, 2], [1, 3]. | ```python
n,k=map(int,input().split())
a=[[0]*n for i in range(k)]
for i in range(n):
a[0][i]=1
for i in range(1,k):
for j in range(n):
for s in range(2**j):
if (j+1)%(s+1)==0:
a[i][j]+=a[i-1][s]
print(sum(a[-1])%(10**9+7))
``` | 0 | |
300 | A | Array | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. The product of all numbers in the second set is greater than zero (<=><=0). 1. The product of all numbers in the third set is equal to zero. 1. Each number from the initial array must occur in exactly one set.
Help Vitaly. Divide the given array. | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=100). The second line contains *n* space-separated distinct integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=103) — the array elements. | In the first line print integer *n*1 (*n*1<=><=0) — the number of elements in the first set. Then print *n*1 numbers — the elements that got to the first set.
In the next line print integer *n*2 (*n*2<=><=0) — the number of elements in the second set. Then print *n*2 numbers — the elements that got to the second set.
In the next line print integer *n*3 (*n*3<=><=0) — the number of elements in the third set. Then print *n*3 numbers — the elements that got to the third set.
The printed sets must meet the described conditions. It is guaranteed that the solution exists. If there are several solutions, you are allowed to print any of them. | [
"3\n-1 2 0\n",
"4\n-1 -2 -3 0\n"
] | [
"1 -1\n1 2\n1 0\n",
"1 -1\n2 -3 -2\n1 0\n"
] | none | 500 | [
{
"input": "3\n-1 2 0",
"output": "1 -1\n1 2\n1 0"
},
{
"input": "4\n-1 -2 -3 0",
"output": "1 -1\n2 -3 -2\n1 0"
},
{
"input": "5\n-1 -2 1 2 0",
"output": "1 -1\n2 1 2\n2 0 -2"
},
{
"input": "100\n-64 -51 -75 -98 74 -26 -1 -8 -99 -76 -53 -80 -43 -22 -100 -62 -34 -5 -65 -81 -1... | 1,650,609,670 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 92 | 512,000 | n = int(input())
nums = [int(x) for x in input().split()]
a1 = []
a2 = []
a3 = []
a1_mul = 1
for i in range(len(nums)):
if nums[i] == 0:
a3.append(0)
elif i % 2 == 1:
a1.append(nums[i])
a1_mul *= nums[i]
else:
a2.append(nums[i])
if a1_mul < 0:
print("1", ' '.join(map(str, a1)))
print("2", ' '.join(map(str, a2)))
else:
print("1", ' '.join(map(str, a2)))
print("2", ' '.join(map(str, a1)))
print("3", ' '.join(map(str, a3))) | Title: Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. The product of all numbers in the second set is greater than zero (<=><=0). 1. The product of all numbers in the third set is equal to zero. 1. Each number from the initial array must occur in exactly one set.
Help Vitaly. Divide the given array.
Input Specification:
The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=100). The second line contains *n* space-separated distinct integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=103) — the array elements.
Output Specification:
In the first line print integer *n*1 (*n*1<=><=0) — the number of elements in the first set. Then print *n*1 numbers — the elements that got to the first set.
In the next line print integer *n*2 (*n*2<=><=0) — the number of elements in the second set. Then print *n*2 numbers — the elements that got to the second set.
In the next line print integer *n*3 (*n*3<=><=0) — the number of elements in the third set. Then print *n*3 numbers — the elements that got to the third set.
The printed sets must meet the described conditions. It is guaranteed that the solution exists. If there are several solutions, you are allowed to print any of them.
Demo Input:
['3\n-1 2 0\n', '4\n-1 -2 -3 0\n']
Demo Output:
['1 -1\n1 2\n1 0\n', '1 -1\n2 -3 -2\n1 0\n']
Note:
none | ```python
n = int(input())
nums = [int(x) for x in input().split()]
a1 = []
a2 = []
a3 = []
a1_mul = 1
for i in range(len(nums)):
if nums[i] == 0:
a3.append(0)
elif i % 2 == 1:
a1.append(nums[i])
a1_mul *= nums[i]
else:
a2.append(nums[i])
if a1_mul < 0:
print("1", ' '.join(map(str, a1)))
print("2", ' '.join(map(str, a2)))
else:
print("1", ' '.join(map(str, a2)))
print("2", ' '.join(map(str, a1)))
print("3", ' '.join(map(str, a3)))
``` | 0 | |
1,003 | B | Binary String Constructing | PROGRAMMING | 1,300 | [
"constructive algorithms"
] | null | null | You are given three integers $a$, $b$ and $x$. Your task is to construct a binary string $s$ of length $n = a + b$ such that there are exactly $a$ zeroes, exactly $b$ ones and exactly $x$ indices $i$ (where $1 \le i < n$) such that $s_i \ne s_{i + 1}$. It is guaranteed that the answer always exists.
For example, for the string "01010" there are four indices $i$ such that $1 \le i < n$ and $s_i \ne s_{i + 1}$ ($i = 1, 2, 3, 4$). For the string "111001" there are two such indices $i$ ($i = 3, 5$).
Recall that binary string is a non-empty sequence of characters where each character is either 0 or 1. | The first line of the input contains three integers $a$, $b$ and $x$ ($1 \le a, b \le 100, 1 \le x < a + b)$. | Print only one string $s$, where $s$ is any binary string satisfying conditions described above. It is guaranteed that the answer always exists. | [
"2 2 1\n",
"3 3 3\n",
"5 3 6\n"
] | [
"1100\n",
"101100\n",
"01010100\n"
] | All possible answers for the first example:
- 1100; - 0011.
All possible answers for the second example:
- 110100; - 101100; - 110010; - 100110; - 011001; - 001101; - 010011; - 001011. | 0 | [
{
"input": "2 2 1",
"output": "1100"
},
{
"input": "3 3 3",
"output": "101100"
},
{
"input": "5 3 6",
"output": "01010100"
},
{
"input": "100 1 2",
"output": "01000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000"
},
{
... | 1,606,885,976 | 2,147,483,647 | PyPy 3 | OK | TESTS | 43 | 156 | 0 |
def mp():return map(int,input().split())
def it():return int(input())
a,b,x=mp()
s=''
if x&1==0:
if a>b:
s+='01'*(x//2)
s+='1'*(b-(x//2))
s+='0'*(a-(x//2))
else:
s+='10'*(x//2)
s+='0'*(a-(x//2))
s+='1'*(b-(x//2))
else:
if a>b:
s+='01'*(x//2)
s+='0'*(a-(x//2))
s+='1'*(b-(x//2))
else:
s+='10'*(x//2)
s+='1'*(b-(x//2))
s+='0'*(a-(x//2))
print(s)
| Title: Binary String Constructing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given three integers $a$, $b$ and $x$. Your task is to construct a binary string $s$ of length $n = a + b$ such that there are exactly $a$ zeroes, exactly $b$ ones and exactly $x$ indices $i$ (where $1 \le i < n$) such that $s_i \ne s_{i + 1}$. It is guaranteed that the answer always exists.
For example, for the string "01010" there are four indices $i$ such that $1 \le i < n$ and $s_i \ne s_{i + 1}$ ($i = 1, 2, 3, 4$). For the string "111001" there are two such indices $i$ ($i = 3, 5$).
Recall that binary string is a non-empty sequence of characters where each character is either 0 or 1.
Input Specification:
The first line of the input contains three integers $a$, $b$ and $x$ ($1 \le a, b \le 100, 1 \le x < a + b)$.
Output Specification:
Print only one string $s$, where $s$ is any binary string satisfying conditions described above. It is guaranteed that the answer always exists.
Demo Input:
['2 2 1\n', '3 3 3\n', '5 3 6\n']
Demo Output:
['1100\n', '101100\n', '01010100\n']
Note:
All possible answers for the first example:
- 1100; - 0011.
All possible answers for the second example:
- 110100; - 101100; - 110010; - 100110; - 011001; - 001101; - 010011; - 001011. | ```python
def mp():return map(int,input().split())
def it():return int(input())
a,b,x=mp()
s=''
if x&1==0:
if a>b:
s+='01'*(x//2)
s+='1'*(b-(x//2))
s+='0'*(a-(x//2))
else:
s+='10'*(x//2)
s+='0'*(a-(x//2))
s+='1'*(b-(x//2))
else:
if a>b:
s+='01'*(x//2)
s+='0'*(a-(x//2))
s+='1'*(b-(x//2))
else:
s+='10'*(x//2)
s+='1'*(b-(x//2))
s+='0'*(a-(x//2))
print(s)
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null |
Nephren is playing a game with little leprechauns.
She gives them an infinite array of strings, *f*0... ∞.
*f*0 is "What are you doing at the end of the world? Are you busy? Will you save us?".
She wants to let more people know about it, so she defines *f**i*<==<= "What are you doing while sending "*f**i*<=-<=1"? Are you busy? Will you send "*f**i*<=-<=1"?" for all *i*<=≥<=1.
For example, *f*1 is
"What are you doing while sending "What are you doing at the end of the world? Are you busy? Will you save us?"? Are you busy? Will you send "What are you doing at the end of the world? Are you busy? Will you save us?"?". Note that the quotes in the very beginning and in the very end are for clarity and are not a part of *f*1.
It can be seen that the characters in *f**i* are letters, question marks, (possibly) quotation marks and spaces.
Nephren will ask the little leprechauns *q* times. Each time she will let them find the *k*-th character of *f**n*. The characters are indexed starting from 1. If *f**n* consists of less than *k* characters, output '.' (without quotes).
Can you answer her queries? | The first line contains one integer *q* (1<=≤<=*q*<=≤<=10) — the number of Nephren's questions.
Each of the next *q* lines describes Nephren's question and contains two integers *n* and *k* (0<=≤<=*n*<=≤<=105,<=1<=≤<=*k*<=≤<=1018). | One line containing *q* characters. The *i*-th character in it should be the answer for the *i*-th query. | [
"3\n1 1\n1 2\n1 111111111111\n",
"5\n0 69\n1 194\n1 139\n0 47\n1 66\n",
"10\n4 1825\n3 75\n3 530\n4 1829\n4 1651\n3 187\n4 584\n4 255\n4 774\n2 474\n"
] | [
"Wh.",
"abdef",
"Areyoubusy"
] | For the first two examples, refer to *f*<sub class="lower-index">0</sub> and *f*<sub class="lower-index">1</sub> given in the legend. | 0 | [
{
"input": "3\n1 1\n1 2\n1 111111111111",
"output": "Wh."
},
{
"input": "5\n0 69\n1 194\n1 139\n0 47\n1 66",
"output": "abdef"
},
{
"input": "10\n4 1825\n3 75\n3 530\n4 1829\n4 1651\n3 187\n4 584\n4 255\n4 774\n2 474",
"output": "Areyoubusy"
},
{
"input": "1\n0 1",
"outpu... | 1,512,229,306 | 5,806 | PyPy 3 | MEMORY_LIMIT_EXCEEDED | PRETESTS | 4 | 499 | 268,390,400 | a="What are you doing at the end of the world? Are you busy? Will you save us?"
q=int(input())
for i in range(q):
n,k=map(int,input().split())
b=a
for i in range(n):
b="What are you doing while sending \"" + b +"\"? Are you busy? Will you send \""+b+"\"?"
if(k-1>(len(b))):
print(".",end="")
else :print(b[k-1],end="")
del(b)
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nephren is playing a game with little leprechauns.
She gives them an infinite array of strings, *f*0... ∞.
*f*0 is "What are you doing at the end of the world? Are you busy? Will you save us?".
She wants to let more people know about it, so she defines *f**i*<==<= "What are you doing while sending "*f**i*<=-<=1"? Are you busy? Will you send "*f**i*<=-<=1"?" for all *i*<=≥<=1.
For example, *f*1 is
"What are you doing while sending "What are you doing at the end of the world? Are you busy? Will you save us?"? Are you busy? Will you send "What are you doing at the end of the world? Are you busy? Will you save us?"?". Note that the quotes in the very beginning and in the very end are for clarity and are not a part of *f*1.
It can be seen that the characters in *f**i* are letters, question marks, (possibly) quotation marks and spaces.
Nephren will ask the little leprechauns *q* times. Each time she will let them find the *k*-th character of *f**n*. The characters are indexed starting from 1. If *f**n* consists of less than *k* characters, output '.' (without quotes).
Can you answer her queries?
Input Specification:
The first line contains one integer *q* (1<=≤<=*q*<=≤<=10) — the number of Nephren's questions.
Each of the next *q* lines describes Nephren's question and contains two integers *n* and *k* (0<=≤<=*n*<=≤<=105,<=1<=≤<=*k*<=≤<=1018).
Output Specification:
One line containing *q* characters. The *i*-th character in it should be the answer for the *i*-th query.
Demo Input:
['3\n1 1\n1 2\n1 111111111111\n', '5\n0 69\n1 194\n1 139\n0 47\n1 66\n', '10\n4 1825\n3 75\n3 530\n4 1829\n4 1651\n3 187\n4 584\n4 255\n4 774\n2 474\n']
Demo Output:
['Wh.', 'abdef', 'Areyoubusy']
Note:
For the first two examples, refer to *f*<sub class="lower-index">0</sub> and *f*<sub class="lower-index">1</sub> given in the legend. | ```python
a="What are you doing at the end of the world? Are you busy? Will you save us?"
q=int(input())
for i in range(q):
n,k=map(int,input().split())
b=a
for i in range(n):
b="What are you doing while sending \"" + b +"\"? Are you busy? Will you send \""+b+"\"?"
if(k-1>(len(b))):
print(".",end="")
else :print(b[k-1],end="")
del(b)
``` | 0 | |
534 | A | Exam | PROGRAMMING | 1,100 | [
"constructive algorithms",
"implementation",
"math"
] | null | null | An exam for *n* students will take place in a long and narrow room, so the students will sit in a line in some order. The teacher suspects that students with adjacent numbers (*i* and *i*<=+<=1) always studied side by side and became friends and if they take an exam sitting next to each other, they will help each other for sure.
Your task is to choose the maximum number of students and make such an arrangement of students in the room that no two students with adjacent numbers sit side by side. | A single line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of students at an exam. | In the first line print integer *k* — the maximum number of students who can be seated so that no two students with adjacent numbers sit next to each other.
In the second line print *k* distinct integers *a*1,<=*a*2,<=...,<=*a**k* (1<=≤<=*a**i*<=≤<=*n*), where *a**i* is the number of the student on the *i*-th position. The students on adjacent positions mustn't have adjacent numbers. Formally, the following should be true: |*a**i*<=-<=*a**i*<=+<=1|<=≠<=1 for all *i* from 1 to *k*<=-<=1.
If there are several possible answers, output any of them. | [
"6",
"3\n"
] | [
"6\n1 5 3 6 2 4",
"2\n1 3"
] | none | 500 | [
{
"input": "6",
"output": "6\n5 3 1 6 4 2 "
},
{
"input": "3",
"output": "2\n1 3"
},
{
"input": "1",
"output": "1\n1 "
},
{
"input": "2",
"output": "1\n1"
},
{
"input": "4",
"output": "4\n3 1 4 2 "
},
{
"input": "5",
"output": "5\n5 3 1 4 2 "
},
... | 1,430,382,104 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 109 | 5,632,000 | a = []
for i in range(6000):
a = a + [i]
inp = int(input())
if inp == 1 or inp == 2:
print(1)
print(1)
elif inp == 3:
print(2)
print(1,3)
else:
print(inp)
print(2,end = '')
for i in a[4:inp+1:2]:
print(' ',i,end = '')
for i in a[1:inp+1:2]:
print(' ',i,end = '')
print()
| Title: Exam
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An exam for *n* students will take place in a long and narrow room, so the students will sit in a line in some order. The teacher suspects that students with adjacent numbers (*i* and *i*<=+<=1) always studied side by side and became friends and if they take an exam sitting next to each other, they will help each other for sure.
Your task is to choose the maximum number of students and make such an arrangement of students in the room that no two students with adjacent numbers sit side by side.
Input Specification:
A single line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of students at an exam.
Output Specification:
In the first line print integer *k* — the maximum number of students who can be seated so that no two students with adjacent numbers sit next to each other.
In the second line print *k* distinct integers *a*1,<=*a*2,<=...,<=*a**k* (1<=≤<=*a**i*<=≤<=*n*), where *a**i* is the number of the student on the *i*-th position. The students on adjacent positions mustn't have adjacent numbers. Formally, the following should be true: |*a**i*<=-<=*a**i*<=+<=1|<=≠<=1 for all *i* from 1 to *k*<=-<=1.
If there are several possible answers, output any of them.
Demo Input:
['6', '3\n']
Demo Output:
['6\n1 5 3 6 2 4', '2\n1 3']
Note:
none | ```python
a = []
for i in range(6000):
a = a + [i]
inp = int(input())
if inp == 1 or inp == 2:
print(1)
print(1)
elif inp == 3:
print(2)
print(1,3)
else:
print(inp)
print(2,end = '')
for i in a[4:inp+1:2]:
print(' ',i,end = '')
for i in a[1:inp+1:2]:
print(' ',i,end = '')
print()
``` | 3 | |
171 | A | Mysterious numbers - 1 | PROGRAMMING | 1,200 | [
"*special",
"constructive algorithms"
] | null | null | The input contains two integers *a*1,<=*a*2 (0<=≤<=*a**i*<=≤<=109), separated by a single space.
Output a single integer. | The input contains two integers *a*1,<=*a*2 (0<=≤<=*a**i*<=≤<=109), separated by a single space. | Output a single integer. | [
"3 14\n",
"27 12\n",
"100 200\n"
] | [
"44\n",
"48\n",
"102\n"
] | none | 0 | [
{
"input": "3 14",
"output": "44"
},
{
"input": "27 12",
"output": "48"
},
{
"input": "100 200",
"output": "102"
},
{
"input": "0 0",
"output": "0"
},
{
"input": "31415 92653",
"output": "67044"
},
{
"input": "1000000000 0",
"output": "1000000000"
... | 1,675,847,325 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 92 | 0 | # LUOGU_RID: 101709040
a=input().split()
a[1]=a[1][-1::-1]
print(int(a[0])+int(a[1])) | Title: Mysterious numbers - 1
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The input contains two integers *a*1,<=*a*2 (0<=≤<=*a**i*<=≤<=109), separated by a single space.
Output a single integer.
Input Specification:
The input contains two integers *a*1,<=*a*2 (0<=≤<=*a**i*<=≤<=109), separated by a single space.
Output Specification:
Output a single integer.
Demo Input:
['3 14\n', '27 12\n', '100 200\n']
Demo Output:
['44\n', '48\n', '102\n']
Note:
none | ```python
# LUOGU_RID: 101709040
a=input().split()
a[1]=a[1][-1::-1]
print(int(a[0])+int(a[1]))
``` | 3 | |
65 | A | Harry Potter and Three Spells | PROGRAMMING | 1,800 | [
"implementation",
"math"
] | A. Harry Potter and Three Spells | 2 | 256 | A long time ago (probably even in the first book), Nicholas Flamel, a great alchemist and the creator of the Philosopher's Stone, taught Harry Potter three useful spells. The first one allows you to convert *a* grams of sand into *b* grams of lead, the second one allows you to convert *c* grams of lead into *d* grams of gold and third one allows you to convert *e* grams of gold into *f* grams of sand. When Harry told his friends about these spells, Ron Weasley was amazed. After all, if they succeed in turning sand into lead, lead into gold, and then turning part of the gold into sand again and so on, then it will be possible to start with a small amount of sand and get huge amounts of gold! Even an infinite amount of gold! Hermione Granger, by contrast, was skeptical about that idea. She argues that according to the law of conservation of matter getting an infinite amount of matter, even using magic, is impossible. On the contrary, the amount of matter may even decrease during transformation, being converted to magical energy. Though Hermione's theory seems convincing, Ron won't believe her. As far as Ron is concerned, Hermione made up her law of conservation of matter to stop Harry and Ron wasting their time with this nonsense, and to make them go and do homework instead. That's why Ron has already collected a certain amount of sand for the experiments. A quarrel between the friends seems unavoidable...
Help Harry to determine which one of his friends is right, and avoid the quarrel after all. To do this you have to figure out whether it is possible to get the amount of gold greater than any preassigned number from some finite amount of sand. | The first line contains 6 integers *a*, *b*, *c*, *d*, *e*, *f* (0<=≤<=*a*,<=*b*,<=*c*,<=*d*,<=*e*,<=*f*<=≤<=1000). | Print "Ron", if it is possible to get an infinitely large amount of gold having a certain finite amount of sand (and not having any gold and lead at all), i.e., Ron is right. Otherwise, print "Hermione". | [
"100 200 250 150 200 250\n",
"100 50 50 200 200 100\n",
"100 10 200 20 300 30\n",
"0 0 0 0 0 0\n",
"1 1 0 1 1 1\n",
"1 0 1 2 1 2\n",
"100 1 100 1 0 1\n"
] | [
"Ron\n",
"Hermione\n",
"Hermione\n",
"Hermione\n",
"Ron\n",
"Hermione\n",
"Ron\n"
] | Consider the first sample. Let's start with the 500 grams of sand. Apply the first spell 5 times and turn the sand into 1000 grams of lead. Then apply the second spell 4 times to get 600 grams of gold. Let’s take 400 grams from the resulting amount of gold turn them back into sand. We get 500 grams of sand and 200 grams of gold. If we apply the same operations to 500 grams of sand again, we can get extra 200 grams of gold every time. Thus, you can get 200, 400, 600 etc. grams of gold, i.e., starting with a finite amount of sand (500 grams), you can get the amount of gold which is greater than any preassigned number.
In the forth sample it is impossible to get sand, or lead, or gold, applying the spells.
In the fifth sample an infinitely large amount of gold can be obtained by using only the second spell, which allows you to receive 1 gram of gold out of nothing. Note that if such a second spell is available, then the first and the third one do not affect the answer at all.
The seventh sample is more interesting. We can also start with a zero amount of sand there. With the aid of the third spell you can get sand out of nothing. We get 10000 grams of sand in this manner. Let's get 100 grams of lead using the first spell 100 times. Then make 1 gram of gold from them. We managed to receive 1 gram of gold, starting with a zero amount of sand! Clearly, in this manner you can get an infinitely large amount of gold. | 500 | [
{
"input": "100 200 250 150 200 250",
"output": "Ron"
},
{
"input": "100 50 50 200 200 100",
"output": "Hermione"
},
{
"input": "100 10 200 20 300 30",
"output": "Hermione"
},
{
"input": "0 0 0 0 0 0",
"output": "Hermione"
},
{
"input": "1 1 0 1 1 1",
"output"... | 1,636,559,779 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 0 | 124 | 31,744,000 | a, b, c, d, e, f = map(int, input().split())
print('Hermione', 'Ron')[e * c * a < f * d *
b or a == 0 and b * d > 0 or c == 0 and d > 0]
| Title: Harry Potter and Three Spells
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A long time ago (probably even in the first book), Nicholas Flamel, a great alchemist and the creator of the Philosopher's Stone, taught Harry Potter three useful spells. The first one allows you to convert *a* grams of sand into *b* grams of lead, the second one allows you to convert *c* grams of lead into *d* grams of gold and third one allows you to convert *e* grams of gold into *f* grams of sand. When Harry told his friends about these spells, Ron Weasley was amazed. After all, if they succeed in turning sand into lead, lead into gold, and then turning part of the gold into sand again and so on, then it will be possible to start with a small amount of sand and get huge amounts of gold! Even an infinite amount of gold! Hermione Granger, by contrast, was skeptical about that idea. She argues that according to the law of conservation of matter getting an infinite amount of matter, even using magic, is impossible. On the contrary, the amount of matter may even decrease during transformation, being converted to magical energy. Though Hermione's theory seems convincing, Ron won't believe her. As far as Ron is concerned, Hermione made up her law of conservation of matter to stop Harry and Ron wasting their time with this nonsense, and to make them go and do homework instead. That's why Ron has already collected a certain amount of sand for the experiments. A quarrel between the friends seems unavoidable...
Help Harry to determine which one of his friends is right, and avoid the quarrel after all. To do this you have to figure out whether it is possible to get the amount of gold greater than any preassigned number from some finite amount of sand.
Input Specification:
The first line contains 6 integers *a*, *b*, *c*, *d*, *e*, *f* (0<=≤<=*a*,<=*b*,<=*c*,<=*d*,<=*e*,<=*f*<=≤<=1000).
Output Specification:
Print "Ron", if it is possible to get an infinitely large amount of gold having a certain finite amount of sand (and not having any gold and lead at all), i.e., Ron is right. Otherwise, print "Hermione".
Demo Input:
['100 200 250 150 200 250\n', '100 50 50 200 200 100\n', '100 10 200 20 300 30\n', '0 0 0 0 0 0\n', '1 1 0 1 1 1\n', '1 0 1 2 1 2\n', '100 1 100 1 0 1\n']
Demo Output:
['Ron\n', 'Hermione\n', 'Hermione\n', 'Hermione\n', 'Ron\n', 'Hermione\n', 'Ron\n']
Note:
Consider the first sample. Let's start with the 500 grams of sand. Apply the first spell 5 times and turn the sand into 1000 grams of lead. Then apply the second spell 4 times to get 600 grams of gold. Let’s take 400 grams from the resulting amount of gold turn them back into sand. We get 500 grams of sand and 200 grams of gold. If we apply the same operations to 500 grams of sand again, we can get extra 200 grams of gold every time. Thus, you can get 200, 400, 600 etc. grams of gold, i.e., starting with a finite amount of sand (500 grams), you can get the amount of gold which is greater than any preassigned number.
In the forth sample it is impossible to get sand, or lead, or gold, applying the spells.
In the fifth sample an infinitely large amount of gold can be obtained by using only the second spell, which allows you to receive 1 gram of gold out of nothing. Note that if such a second spell is available, then the first and the third one do not affect the answer at all.
The seventh sample is more interesting. We can also start with a zero amount of sand there. With the aid of the third spell you can get sand out of nothing. We get 10000 grams of sand in this manner. Let's get 100 grams of lead using the first spell 100 times. Then make 1 gram of gold from them. We managed to receive 1 gram of gold, starting with a zero amount of sand! Clearly, in this manner you can get an infinitely large amount of gold. | ```python
a, b, c, d, e, f = map(int, input().split())
print('Hermione', 'Ron')[e * c * a < f * d *
b or a == 0 and b * d > 0 or c == 0 and d > 0]
``` | -1 |
818 | B | Permutation Game | PROGRAMMING | 1,600 | [
"implementation"
] | null | null | *n* children are standing in a circle and playing a game. Children's numbers in clockwise order form a permutation *a*1,<=*a*2,<=...,<=*a**n* of length *n*. It is an integer sequence such that each integer from 1 to *n* appears exactly once in it.
The game consists of *m* steps. On each step the current leader with index *i* counts out *a**i* people in clockwise order, starting from the next person. The last one to be pointed at by the leader becomes the new leader.
You are given numbers *l*1,<=*l*2,<=...,<=*l**m* — indices of leaders in the beginning of each step. Child with number *l*1 is the first leader in the game.
Write a program which will restore a possible permutation *a*1,<=*a*2,<=...,<=*a**n*. If there are multiple solutions then print any of them. If there is no solution then print -1. | The first line contains two integer numbers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100).
The second line contains *m* integer numbers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*) — indices of leaders in the beginning of each step. | Print such permutation of *n* numbers *a*1,<=*a*2,<=...,<=*a**n* that leaders in the game will be exactly *l*1,<=*l*2,<=...,<=*l**m* if all the rules are followed. If there are multiple solutions print any of them.
If there is no permutation which satisfies all described conditions print -1. | [
"4 5\n2 3 1 4 4\n",
"3 3\n3 1 2\n"
] | [
"3 1 2 4 \n",
"-1\n"
] | Let's follow leadership in the first example:
- Child 2 starts. - Leadership goes from 2 to 2 + *a*<sub class="lower-index">2</sub> = 3. - Leadership goes from 3 to 3 + *a*<sub class="lower-index">3</sub> = 5. As it's greater than 4, it's going in a circle to 1. - Leadership goes from 1 to 1 + *a*<sub class="lower-index">1</sub> = 4. - Leadership goes from 4 to 4 + *a*<sub class="lower-index">4</sub> = 8. Thus in circle it still remains at 4. | 0 | [
{
"input": "4 5\n2 3 1 4 4",
"output": "3 1 2 4 "
},
{
"input": "3 3\n3 1 2",
"output": "-1"
},
{
"input": "1 100\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1... | 1,498,751,564 | 2,864 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 4,608,000 | n, m =[int(i) for i in input().split()]
l = [int(i) - 1 for i in input().split()]
ans = [-1] * n
flag = 0
for i in range(m - 1):
t = (l[i + 1] - l[i]) % n
if t == 0:
t = n
if ans[l[i]] != -1 and ans[l[i]] != t:
break
ans[l[i]] = t
else:
s = set()
for i in ans:
if i != -1:
s.add(i)
c = 1
for i in range(n):
if ans[i] != -1:
while c in s:
c += 1
ans[i] = c
if len(set(ans)) == n:
print(' '.join([str(i) for i in ans]))
else:
print(-1) | Title: Permutation Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
*n* children are standing in a circle and playing a game. Children's numbers in clockwise order form a permutation *a*1,<=*a*2,<=...,<=*a**n* of length *n*. It is an integer sequence such that each integer from 1 to *n* appears exactly once in it.
The game consists of *m* steps. On each step the current leader with index *i* counts out *a**i* people in clockwise order, starting from the next person. The last one to be pointed at by the leader becomes the new leader.
You are given numbers *l*1,<=*l*2,<=...,<=*l**m* — indices of leaders in the beginning of each step. Child with number *l*1 is the first leader in the game.
Write a program which will restore a possible permutation *a*1,<=*a*2,<=...,<=*a**n*. If there are multiple solutions then print any of them. If there is no solution then print -1.
Input Specification:
The first line contains two integer numbers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100).
The second line contains *m* integer numbers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*) — indices of leaders in the beginning of each step.
Output Specification:
Print such permutation of *n* numbers *a*1,<=*a*2,<=...,<=*a**n* that leaders in the game will be exactly *l*1,<=*l*2,<=...,<=*l**m* if all the rules are followed. If there are multiple solutions print any of them.
If there is no permutation which satisfies all described conditions print -1.
Demo Input:
['4 5\n2 3 1 4 4\n', '3 3\n3 1 2\n']
Demo Output:
['3 1 2 4 \n', '-1\n']
Note:
Let's follow leadership in the first example:
- Child 2 starts. - Leadership goes from 2 to 2 + *a*<sub class="lower-index">2</sub> = 3. - Leadership goes from 3 to 3 + *a*<sub class="lower-index">3</sub> = 5. As it's greater than 4, it's going in a circle to 1. - Leadership goes from 1 to 1 + *a*<sub class="lower-index">1</sub> = 4. - Leadership goes from 4 to 4 + *a*<sub class="lower-index">4</sub> = 8. Thus in circle it still remains at 4. | ```python
n, m =[int(i) for i in input().split()]
l = [int(i) - 1 for i in input().split()]
ans = [-1] * n
flag = 0
for i in range(m - 1):
t = (l[i + 1] - l[i]) % n
if t == 0:
t = n
if ans[l[i]] != -1 and ans[l[i]] != t:
break
ans[l[i]] = t
else:
s = set()
for i in ans:
if i != -1:
s.add(i)
c = 1
for i in range(n):
if ans[i] != -1:
while c in s:
c += 1
ans[i] = c
if len(set(ans)) == n:
print(' '.join([str(i) for i in ans]))
else:
print(-1)
``` | 0 | |
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
The head of the SSU OPTC is recently gathering teams to participate in the world championship. Each team must consist of exactly three people, at that, any person cannot be a member of two or more teams. What maximum number of teams can the head make if he wants each team to participate in the world championship with the same members at least *k* times? | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,663,578,491 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 35 | 233 | 15,667,200 | import math
import random
from collections import Counter, deque
from sys import stdout
import time
from math import factorial, log, gcd
import sys
from decimal import Decimal
import heapq
from copy import deepcopy
import itertools
import datetime
def S():
return sys.stdin.readline().split()
def I():
return [int(i) for i in sys.stdin.readline().split()]
def II():
return int(sys.stdin.readline())
def IS():
return sys.stdin.readline().replace('\n', '')
def main():
n, k = I()
z = I()
count = 0
for i in range(n):
if z[i] + k <= 5:
count += 1
print(count // 3)
if __name__ == '__main__':
#for _ in range(II()):
#main()
main() | Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
The head of the SSU OPTC is recently gathering teams to participate in the world championship. Each team must consist of exactly three people, at that, any person cannot be a member of two or more teams. What maximum number of teams can the head make if he wants each team to participate in the world championship with the same members at least *k* times?
Input Specification:
The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship.
Output Specification:
Print a single number — the answer to the problem.
Demo Input:
['5 2\n0 4 5 1 0\n', '6 4\n0 1 2 3 4 5\n', '6 5\n0 0 0 0 0 0\n']
Demo Output:
['1\n', '0\n', '2\n']
Note:
In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | ```python
import math
import random
from collections import Counter, deque
from sys import stdout
import time
from math import factorial, log, gcd
import sys
from decimal import Decimal
import heapq
from copy import deepcopy
import itertools
import datetime
def S():
return sys.stdin.readline().split()
def I():
return [int(i) for i in sys.stdin.readline().split()]
def II():
return int(sys.stdin.readline())
def IS():
return sys.stdin.readline().replace('\n', '')
def main():
n, k = I()
z = I()
count = 0
for i in range(n):
if z[i] + k <= 5:
count += 1
print(count // 3)
if __name__ == '__main__':
#for _ in range(II()):
#main()
main()
``` | 3 | |
967 | A | Mind the Gap | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | These days Arkady works as an air traffic controller at a large airport. He controls a runway which is usually used for landings only. Thus, he has a schedule of planes that are landing in the nearest future, each landing lasts $1$ minute.
He was asked to insert one takeoff in the schedule. The takeoff takes $1$ minute itself, but for safety reasons there should be a time space between the takeoff and any landing of at least $s$ minutes from both sides.
Find the earliest time when Arkady can insert the takeoff. | The first line of input contains two integers $n$ and $s$ ($1 \le n \le 100$, $1 \le s \le 60$) — the number of landings on the schedule and the minimum allowed time (in minutes) between a landing and a takeoff.
Each of next $n$ lines contains two integers $h$ and $m$ ($0 \le h \le 23$, $0 \le m \le 59$) — the time, in hours and minutes, when a plane will land, starting from current moment (i. e. the current time is $0$ $0$). These times are given in increasing order. | Print two integers $h$ and $m$ — the hour and the minute from the current moment of the earliest time Arkady can insert the takeoff. | [
"6 60\n0 0\n1 20\n3 21\n5 0\n19 30\n23 40\n",
"16 50\n0 30\n1 20\n3 0\n4 30\n6 10\n7 50\n9 30\n11 10\n12 50\n14 30\n16 10\n17 50\n19 30\n21 10\n22 50\n23 59\n",
"3 17\n0 30\n1 0\n12 0\n"
] | [
"6 1\n",
"24 50\n",
"0 0\n"
] | In the first example note that there is not enough time between 1:20 and 3:21, because each landing and the takeoff take one minute.
In the second example there is no gaps in the schedule, so Arkady can only add takeoff after all landings. Note that it is possible that one should wait more than $24$ hours to insert the takeoff.
In the third example Arkady can insert the takeoff even between the first landing. | 500 | [
{
"input": "6 60\n0 0\n1 20\n3 21\n5 0\n19 30\n23 40",
"output": "6 1"
},
{
"input": "16 50\n0 30\n1 20\n3 0\n4 30\n6 10\n7 50\n9 30\n11 10\n12 50\n14 30\n16 10\n17 50\n19 30\n21 10\n22 50\n23 59",
"output": "24 50"
},
{
"input": "3 17\n0 30\n1 0\n12 0",
"output": "0 0"
},
{
... | 1,601,679,293 | 2,147,483,647 | PyPy 3 | OK | TESTS | 34 | 155 | 0 | n, k = map(int, input().split())
h, m = map(int, input().split())
if 60 * h + m >= k + 1:
print(0, 0)
else:
prev_hours, prev_minutes = h, m + 1
flag = 0
for _ in range(n - 1):
h, m = map(int, input().split())
if 60 * prev_hours + prev_minutes + k + 1 + k <= 60 * h + m:
prev_minutes += k
print(prev_hours + prev_minutes // 60, prev_minutes % 60)
flag = 1
break
else:
prev_hours, prev_minutes = h, m + 1
if flag == 0:
# print('Here')
prev_minutes += k
print(prev_hours + prev_minutes // 60, prev_minutes % 60)
| Title: Mind the Gap
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
These days Arkady works as an air traffic controller at a large airport. He controls a runway which is usually used for landings only. Thus, he has a schedule of planes that are landing in the nearest future, each landing lasts $1$ minute.
He was asked to insert one takeoff in the schedule. The takeoff takes $1$ minute itself, but for safety reasons there should be a time space between the takeoff and any landing of at least $s$ minutes from both sides.
Find the earliest time when Arkady can insert the takeoff.
Input Specification:
The first line of input contains two integers $n$ and $s$ ($1 \le n \le 100$, $1 \le s \le 60$) — the number of landings on the schedule and the minimum allowed time (in minutes) between a landing and a takeoff.
Each of next $n$ lines contains two integers $h$ and $m$ ($0 \le h \le 23$, $0 \le m \le 59$) — the time, in hours and minutes, when a plane will land, starting from current moment (i. e. the current time is $0$ $0$). These times are given in increasing order.
Output Specification:
Print two integers $h$ and $m$ — the hour and the minute from the current moment of the earliest time Arkady can insert the takeoff.
Demo Input:
['6 60\n0 0\n1 20\n3 21\n5 0\n19 30\n23 40\n', '16 50\n0 30\n1 20\n3 0\n4 30\n6 10\n7 50\n9 30\n11 10\n12 50\n14 30\n16 10\n17 50\n19 30\n21 10\n22 50\n23 59\n', '3 17\n0 30\n1 0\n12 0\n']
Demo Output:
['6 1\n', '24 50\n', '0 0\n']
Note:
In the first example note that there is not enough time between 1:20 and 3:21, because each landing and the takeoff take one minute.
In the second example there is no gaps in the schedule, so Arkady can only add takeoff after all landings. Note that it is possible that one should wait more than $24$ hours to insert the takeoff.
In the third example Arkady can insert the takeoff even between the first landing. | ```python
n, k = map(int, input().split())
h, m = map(int, input().split())
if 60 * h + m >= k + 1:
print(0, 0)
else:
prev_hours, prev_minutes = h, m + 1
flag = 0
for _ in range(n - 1):
h, m = map(int, input().split())
if 60 * prev_hours + prev_minutes + k + 1 + k <= 60 * h + m:
prev_minutes += k
print(prev_hours + prev_minutes // 60, prev_minutes % 60)
flag = 1
break
else:
prev_hours, prev_minutes = h, m + 1
if flag == 0:
# print('Here')
prev_minutes += k
print(prev_hours + prev_minutes // 60, prev_minutes % 60)
``` | 3 | |
460 | A | Vasya and Socks | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it late in the evening, so that Vasya cannot put on a new pair of socks before the next day. How many consecutive days pass until Vasya runs out of socks? | The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space. | Print a single integer — the answer to the problem. | [
"2 2\n",
"9 3\n"
] | [
"3\n",
"13\n"
] | In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on the third, sixth and ninth days. Than he spends another day wearing the socks that were bought on the twelfth day. | 500 | [
{
"input": "2 2",
"output": "3"
},
{
"input": "9 3",
"output": "13"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 3",
"output": "2"
},
{
"input": "1 99",
"output": "1"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "10 2",
"outp... | 1,662,342,531 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 46 | 0 | s,m=[int(i) for i in input().split()]
c=1
while s!=0:
s-=1
if c%m==0:
s+=1
if s==0:
break
else:
c+=1
print(c) | Title: Vasya and Socks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it late in the evening, so that Vasya cannot put on a new pair of socks before the next day. How many consecutive days pass until Vasya runs out of socks?
Input Specification:
The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space.
Output Specification:
Print a single integer — the answer to the problem.
Demo Input:
['2 2\n', '9 3\n']
Demo Output:
['3\n', '13\n']
Note:
In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on the third, sixth and ninth days. Than he spends another day wearing the socks that were bought on the twelfth day. | ```python
s,m=[int(i) for i in input().split()]
c=1
while s!=0:
s-=1
if c%m==0:
s+=1
if s==0:
break
else:
c+=1
print(c)
``` | 3 | |
637 | B | Chat Order | PROGRAMMING | 1,200 | [
"*special",
"binary search",
"constructive algorithms",
"data structures",
"sortings"
] | null | null | Polycarp is a big lover of killing time in social networks. A page with a chatlist in his favourite network is made so that when a message is sent to some friend, his friend's chat rises to the very top of the page. The relative order of the other chats doesn't change. If there was no chat with this friend before, then a new chat is simply inserted to the top of the list.
Assuming that the chat list is initially empty, given the sequence of Polycaprus' messages make a list of chats after all of his messages are processed. Assume that no friend wrote any message to Polycarpus. | The first line contains integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of Polycarpus' messages. Next *n* lines enlist the message recipients in the order in which the messages were sent. The name of each participant is a non-empty sequence of lowercase English letters of length at most 10. | Print all the recipients to who Polycarp talked to in the order of chats with them, from top to bottom. | [
"4\nalex\nivan\nroman\nivan\n",
"8\nalina\nmaria\nekaterina\ndarya\ndarya\nekaterina\nmaria\nalina\n"
] | [
"ivan\nroman\nalex\n",
"alina\nmaria\nekaterina\ndarya\n"
] | In the first test case Polycarpus first writes to friend by name "alex", and the list looks as follows:
1. alex
Then Polycarpus writes to friend by name "ivan" and the list looks as follows:
1. ivan 1. alex
Polycarpus writes the third message to friend by name "roman" and the list looks as follows:
1. roman 1. ivan 1. alex
Polycarpus writes the fourth message to friend by name "ivan", to who he has already sent a message, so the list of chats changes as follows:
1. ivan 1. roman 1. alex | 1,000 | [
{
"input": "4\nalex\nivan\nroman\nivan",
"output": "ivan\nroman\nalex"
},
{
"input": "8\nalina\nmaria\nekaterina\ndarya\ndarya\nekaterina\nmaria\nalina",
"output": "alina\nmaria\nekaterina\ndarya"
},
{
"input": "1\nwdi",
"output": "wdi"
},
{
"input": "2\nypg\nypg",
"outpu... | 1,460,732,156 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 3,000 | 716,800 | #Fucking hate this problem
n = int(input())
d = []
for i in range(n):
s = str(input())
if s in d:
d.remove(s)
d.insert(i, s)
else:
d.insert(i, s)
for x in d[::-1]:
print(x) | Title: Chat Order
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is a big lover of killing time in social networks. A page with a chatlist in his favourite network is made so that when a message is sent to some friend, his friend's chat rises to the very top of the page. The relative order of the other chats doesn't change. If there was no chat with this friend before, then a new chat is simply inserted to the top of the list.
Assuming that the chat list is initially empty, given the sequence of Polycaprus' messages make a list of chats after all of his messages are processed. Assume that no friend wrote any message to Polycarpus.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of Polycarpus' messages. Next *n* lines enlist the message recipients in the order in which the messages were sent. The name of each participant is a non-empty sequence of lowercase English letters of length at most 10.
Output Specification:
Print all the recipients to who Polycarp talked to in the order of chats with them, from top to bottom.
Demo Input:
['4\nalex\nivan\nroman\nivan\n', '8\nalina\nmaria\nekaterina\ndarya\ndarya\nekaterina\nmaria\nalina\n']
Demo Output:
['ivan\nroman\nalex\n', 'alina\nmaria\nekaterina\ndarya\n']
Note:
In the first test case Polycarpus first writes to friend by name "alex", and the list looks as follows:
1. alex
Then Polycarpus writes to friend by name "ivan" and the list looks as follows:
1. ivan 1. alex
Polycarpus writes the third message to friend by name "roman" and the list looks as follows:
1. roman 1. ivan 1. alex
Polycarpus writes the fourth message to friend by name "ivan", to who he has already sent a message, so the list of chats changes as follows:
1. ivan 1. roman 1. alex | ```python
#Fucking hate this problem
n = int(input())
d = []
for i in range(n):
s = str(input())
if s in d:
d.remove(s)
d.insert(i, s)
else:
d.insert(i, s)
for x in d[::-1]:
print(x)
``` | 0 | |
818 | A | Diplomas and Certificates | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | There are *n* students who have taken part in an olympiad. Now it's time to award the students.
Some of them will receive diplomas, some wiil get certificates, and others won't receive anything. Students with diplomas and certificates are called winners. But there are some rules of counting the number of diplomas and certificates. The number of certificates must be exactly *k* times greater than the number of diplomas. The number of winners must not be greater than half of the number of all students (i.e. not be greater than half of *n*). It's possible that there are no winners.
You have to identify the maximum possible number of winners, according to these rules. Also for this case you have to calculate the number of students with diplomas, the number of students with certificates and the number of students who are not winners. | The first (and the only) line of input contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1012), where *n* is the number of students and *k* is the ratio between the number of certificates and the number of diplomas. | Output three numbers: the number of students with diplomas, the number of students with certificates and the number of students who are not winners in case when the number of winners is maximum possible.
It's possible that there are no winners. | [
"18 2\n",
"9 10\n",
"1000000000000 5\n",
"1000000000000 499999999999\n"
] | [
"3 6 9\n",
"0 0 9\n",
"83333333333 416666666665 500000000002\n",
"1 499999999999 500000000000\n"
] | none | 0 | [
{
"input": "18 2",
"output": "3 6 9"
},
{
"input": "9 10",
"output": "0 0 9"
},
{
"input": "1000000000000 5",
"output": "83333333333 416666666665 500000000002"
},
{
"input": "1000000000000 499999999999",
"output": "1 499999999999 500000000000"
},
{
"input": "1 1",... | 1,589,906,051 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 124 | 0 | n , k = map(int,input().split())
a = n//2
b = a//(k+1)
print(b,k*b,n-(k+1)*b) | Title: Diplomas and Certificates
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* students who have taken part in an olympiad. Now it's time to award the students.
Some of them will receive diplomas, some wiil get certificates, and others won't receive anything. Students with diplomas and certificates are called winners. But there are some rules of counting the number of diplomas and certificates. The number of certificates must be exactly *k* times greater than the number of diplomas. The number of winners must not be greater than half of the number of all students (i.e. not be greater than half of *n*). It's possible that there are no winners.
You have to identify the maximum possible number of winners, according to these rules. Also for this case you have to calculate the number of students with diplomas, the number of students with certificates and the number of students who are not winners.
Input Specification:
The first (and the only) line of input contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1012), where *n* is the number of students and *k* is the ratio between the number of certificates and the number of diplomas.
Output Specification:
Output three numbers: the number of students with diplomas, the number of students with certificates and the number of students who are not winners in case when the number of winners is maximum possible.
It's possible that there are no winners.
Demo Input:
['18 2\n', '9 10\n', '1000000000000 5\n', '1000000000000 499999999999\n']
Demo Output:
['3 6 9\n', '0 0 9\n', '83333333333 416666666665 500000000002\n', '1 499999999999 500000000000\n']
Note:
none | ```python
n , k = map(int,input().split())
a = n//2
b = a//(k+1)
print(b,k*b,n-(k+1)*b)
``` | 3 | |
214 | A | System of Equations | PROGRAMMING | 800 | [
"brute force"
] | null | null | Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you?
You are given a system of equations:
You should count, how many there are pairs of integers (*a*,<=*b*) (0<=≤<=*a*,<=*b*) which satisfy the system. | A single line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the parameters of the system. The numbers on the line are separated by a space. | On a single line print the answer to the problem. | [
"9 3\n",
"14 28\n",
"4 20\n"
] | [
"1\n",
"1\n",
"0\n"
] | In the first sample the suitable pair is integers (3, 0). In the second sample the suitable pair is integers (3, 5). In the third sample there is no suitable pair. | 500 | [
{
"input": "9 3",
"output": "1"
},
{
"input": "14 28",
"output": "1"
},
{
"input": "4 20",
"output": "0"
},
{
"input": "18 198",
"output": "1"
},
{
"input": "22 326",
"output": "1"
},
{
"input": "26 104",
"output": "1"
},
{
"input": "14 10"... | 1,670,850,540 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 11 | 92 | 0 | m,n=map(int, input().split())
k=0
for i in range(min(n,m)+1):
for j in range(min(n,m)+1):
if (i**2+j==n and i+j**2==m):
k=+1
print(k)
| Title: System of Equations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you?
You are given a system of equations:
You should count, how many there are pairs of integers (*a*,<=*b*) (0<=≤<=*a*,<=*b*) which satisfy the system.
Input Specification:
A single line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the parameters of the system. The numbers on the line are separated by a space.
Output Specification:
On a single line print the answer to the problem.
Demo Input:
['9 3\n', '14 28\n', '4 20\n']
Demo Output:
['1\n', '1\n', '0\n']
Note:
In the first sample the suitable pair is integers (3, 0). In the second sample the suitable pair is integers (3, 5). In the third sample there is no suitable pair. | ```python
m,n=map(int, input().split())
k=0
for i in range(min(n,m)+1):
for j in range(min(n,m)+1):
if (i**2+j==n and i+j**2==m):
k=+1
print(k)
``` | 0 | |
893 | A | Chess For Three | PROGRAMMING | 900 | [
"implementation"
] | null | null | Alex, Bob and Carl will soon participate in a team chess tournament. Since they are all in the same team, they have decided to practise really hard before the tournament. But it's a bit difficult for them because chess is a game for two players, not three.
So they play with each other according to following rules:
- Alex and Bob play the first game, and Carl is spectating; - When the game ends, the one who lost the game becomes the spectator in the next game, and the one who was spectating plays against the winner.
Alex, Bob and Carl play in such a way that there are no draws.
Today they have played *n* games, and for each of these games they remember who was the winner. They decided to make up a log of games describing who won each game. But now they doubt if the information in the log is correct, and they want to know if the situation described in the log they made up was possible (that is, no game is won by someone who is spectating if Alex, Bob and Carl play according to the rules). Help them to check it! | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of games Alex, Bob and Carl played.
Then *n* lines follow, describing the game log. *i*-th line contains one integer *a**i* (1<=≤<=*a**i*<=≤<=3) which is equal to 1 if Alex won *i*-th game, to 2 if Bob won *i*-th game and 3 if Carl won *i*-th game. | Print YES if the situation described in the log was possible. Otherwise print NO. | [
"3\n1\n1\n2\n",
"2\n1\n2\n"
] | [
"YES\n",
"NO\n"
] | In the first example the possible situation is:
1. Alex wins, Carl starts playing instead of Bob; 1. Alex wins, Bob replaces Carl; 1. Bob wins.
The situation in the second example is impossible because Bob loses the first game, so he cannot win the second one. | 0 | [
{
"input": "3\n1\n1\n2",
"output": "YES"
},
{
"input": "2\n1\n2",
"output": "NO"
},
{
"input": "100\n2\n3\n1\n2\n3\n3\n3\n1\n1\n1\n1\n3\n3\n3\n3\n1\n2\n3\n3\n3\n3\n3\n3\n3\n1\n2\n2\n2\n3\n1\n1\n3\n3\n3\n3\n3\n3\n3\n3\n1\n2\n3\n3\n3\n1\n1\n1\n1\n3\n3\n3\n3\n1\n2\n3\n1\n2\n2\n2\n3\n3\n2\n1... | 1,637,398,023 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 46 | 0 | n=int(input())
lst=[]
res=[1,2]
for i in range(n):
lst.append(int(input()))
check=1
for i in lst:
if i not in res:
check=0
break
else:
if i==1:
if sum(res)==3:
res.remove(2)
res.append(3)
else:
res.remove(3)
res.append(2)
elif i==2:
if sum(res)==3:
res.remove(1)
res.append(3)
else:
res.remove(3)
res.append(1)
else:
if sum(res)==4:
res.remove(1)
res.append(2)
else:
res.remove(2)
res.append(1)
if check==1:
print('YES')
else:
print('NO') | Title: Chess For Three
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alex, Bob and Carl will soon participate in a team chess tournament. Since they are all in the same team, they have decided to practise really hard before the tournament. But it's a bit difficult for them because chess is a game for two players, not three.
So they play with each other according to following rules:
- Alex and Bob play the first game, and Carl is spectating; - When the game ends, the one who lost the game becomes the spectator in the next game, and the one who was spectating plays against the winner.
Alex, Bob and Carl play in such a way that there are no draws.
Today they have played *n* games, and for each of these games they remember who was the winner. They decided to make up a log of games describing who won each game. But now they doubt if the information in the log is correct, and they want to know if the situation described in the log they made up was possible (that is, no game is won by someone who is spectating if Alex, Bob and Carl play according to the rules). Help them to check it!
Input Specification:
The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of games Alex, Bob and Carl played.
Then *n* lines follow, describing the game log. *i*-th line contains one integer *a**i* (1<=≤<=*a**i*<=≤<=3) which is equal to 1 if Alex won *i*-th game, to 2 if Bob won *i*-th game and 3 if Carl won *i*-th game.
Output Specification:
Print YES if the situation described in the log was possible. Otherwise print NO.
Demo Input:
['3\n1\n1\n2\n', '2\n1\n2\n']
Demo Output:
['YES\n', 'NO\n']
Note:
In the first example the possible situation is:
1. Alex wins, Carl starts playing instead of Bob; 1. Alex wins, Bob replaces Carl; 1. Bob wins.
The situation in the second example is impossible because Bob loses the first game, so he cannot win the second one. | ```python
n=int(input())
lst=[]
res=[1,2]
for i in range(n):
lst.append(int(input()))
check=1
for i in lst:
if i not in res:
check=0
break
else:
if i==1:
if sum(res)==3:
res.remove(2)
res.append(3)
else:
res.remove(3)
res.append(2)
elif i==2:
if sum(res)==3:
res.remove(1)
res.append(3)
else:
res.remove(3)
res.append(1)
else:
if sum(res)==4:
res.remove(1)
res.append(2)
else:
res.remove(2)
res.append(1)
if check==1:
print('YES')
else:
print('NO')
``` | 3 | |
507 | B | Amr and Pins | PROGRAMMING | 1,400 | [
"geometry",
"math"
] | null | null | Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius *r* and center in point (*x*,<=*y*). He wants the circle center to be in new position (*x*',<=*y*').
In one step Amr can put a pin to the border of the circle in a certain point, then rotate the circle around that pin by any angle and finally remove the pin.
Help Amr to achieve his goal in minimum number of steps. | Input consists of 5 space-separated integers *r*, *x*, *y*, *x*' *y*' (1<=≤<=*r*<=≤<=105, <=-<=105<=≤<=*x*,<=*y*,<=*x*',<=*y*'<=≤<=105), circle radius, coordinates of original center of the circle and coordinates of destination center of the circle respectively. | Output a single integer — minimum number of steps required to move the center of the circle to the destination point. | [
"2 0 0 0 4\n",
"1 1 1 4 4\n",
"4 5 6 5 6\n"
] | [
"1\n",
"3\n",
"0\n"
] | In the first sample test the optimal way is to put a pin at point (0, 2) and rotate the circle by 180 degrees counter-clockwise (or clockwise, no matter).
<img class="tex-graphics" src="https://espresso.codeforces.com/4e40fd4cc24a2050a0488aa131e6244369328039.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "2 0 0 0 4",
"output": "1"
},
{
"input": "1 1 1 4 4",
"output": "3"
},
{
"input": "4 5 6 5 6",
"output": "0"
},
{
"input": "10 20 0 40 0",
"output": "1"
},
{
"input": "9 20 0 40 0",
"output": "2"
},
{
"input": "5 -1 -6 -5 1",
"output": "... | 1,560,902,342 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 108 | 0 | import math as m
r,x,y,x_,y_ = [int(i) for i in input().split()]
d = m.sqrt((x_-x)**2 +(y_-y)**2)
print(m.ceil(d/(2*r))) | Title: Amr and Pins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius *r* and center in point (*x*,<=*y*). He wants the circle center to be in new position (*x*',<=*y*').
In one step Amr can put a pin to the border of the circle in a certain point, then rotate the circle around that pin by any angle and finally remove the pin.
Help Amr to achieve his goal in minimum number of steps.
Input Specification:
Input consists of 5 space-separated integers *r*, *x*, *y*, *x*' *y*' (1<=≤<=*r*<=≤<=105, <=-<=105<=≤<=*x*,<=*y*,<=*x*',<=*y*'<=≤<=105), circle radius, coordinates of original center of the circle and coordinates of destination center of the circle respectively.
Output Specification:
Output a single integer — minimum number of steps required to move the center of the circle to the destination point.
Demo Input:
['2 0 0 0 4\n', '1 1 1 4 4\n', '4 5 6 5 6\n']
Demo Output:
['1\n', '3\n', '0\n']
Note:
In the first sample test the optimal way is to put a pin at point (0, 2) and rotate the circle by 180 degrees counter-clockwise (or clockwise, no matter).
<img class="tex-graphics" src="https://espresso.codeforces.com/4e40fd4cc24a2050a0488aa131e6244369328039.png" style="max-width: 100.0%;max-height: 100.0%;"/> | ```python
import math as m
r,x,y,x_,y_ = [int(i) for i in input().split()]
d = m.sqrt((x_-x)**2 +(y_-y)**2)
print(m.ceil(d/(2*r)))
``` | 3 | |
812 | C | Sagheer and Nubian Market | PROGRAMMING | 1,500 | [
"binary search",
"sortings"
] | null | null | On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friends and relatives. The market has some strange rules. It contains *n* different items numbered from 1 to *n*. The *i*-th item has base cost *a**i* Egyptian pounds. If Sagheer buys *k* items with indices *x*1,<=*x*2,<=...,<=*x**k*, then the cost of item *x**j* is *a**x**j*<=+<=*x**j*·*k* for 1<=≤<=*j*<=≤<=*k*. In other words, the cost of an item is equal to its base cost in addition to its index multiplied by the factor *k*.
Sagheer wants to buy as many souvenirs as possible without paying more than *S* Egyptian pounds. Note that he cannot buy a souvenir more than once. If there are many ways to maximize the number of souvenirs, he will choose the way that will minimize the total cost. Can you help him with this task? | The first line contains two integers *n* and *S* (1<=≤<=*n*<=≤<=105 and 1<=≤<=*S*<=≤<=109) — the number of souvenirs in the market and Sagheer's budget.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105) — the base costs of the souvenirs. | On a single line, print two integers *k*, *T* — the maximum number of souvenirs Sagheer can buy and the minimum total cost to buy these *k* souvenirs. | [
"3 11\n2 3 5\n",
"4 100\n1 2 5 6\n",
"1 7\n7\n"
] | [
"2 11\n",
"4 54\n",
"0 0\n"
] | In the first example, he cannot take the three items because they will cost him [5, 9, 14] with total cost 28. If he decides to take only two items, then the costs will be [4, 7, 11]. So he can afford the first and second items.
In the second example, he can buy all items as they will cost him [5, 10, 17, 22].
In the third example, there is only one souvenir in the market which will cost him 8 pounds, so he cannot buy it. | 1,500 | [
{
"input": "3 11\n2 3 5",
"output": "2 11"
},
{
"input": "4 100\n1 2 5 6",
"output": "4 54"
},
{
"input": "1 7\n7",
"output": "0 0"
},
{
"input": "1 7\n5",
"output": "1 6"
},
{
"input": "1 1\n1",
"output": "0 0"
},
{
"input": "4 33\n4 3 2 1",
"outp... | 1,540,563,447 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 5 | 124 | 0 | from operator import itemgetter
n, money = list(map(int, input().split()))
costs = list(map(int, input().split()))
# def check(i, total, indices, taken, left):
#
# # if i in arr:
# # print(i, arr)
# # return arr[i]
# if i > len(costs)-1 and taken != 0:
#
# return ((left)-total-indices*taken, taken)
# elif i < len(costs):
#
# if (total+costs[i]) + (indices+i+1)*(taken+1) <= left:
#
# boo = max(check(i+1, total+costs[i], indices+i+1,taken+1, left), check(i+1, total, indices, taken, left), key=itemgetter(1,0))
# return boo
# else:
# return ((left)-total-indices*taken, taken)
# return (0,0)
#
# a = list(check(0,0,0,0,money)[::-1])
# a[1] = money-a[1]
# print(*a)
#
def binary_search():
cost = 0
ans = 0
u = len(costs)+1
d = 0
while u-1 >= d:
mid = (u+d)//2
k = price(mid, n)
if k > money:
u = mid-1
elif k < money:
d = mid +1
cost = k
ans = mid
else:
print(mid, money)
return
print(ans, cost)
def price(k, n):
b = []
for i in range(1,n+1):
b.append(costs[i-1]+i*k)
b.sort()
return sum(b[:k])
binary_search() | Title: Sagheer and Nubian Market
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friends and relatives. The market has some strange rules. It contains *n* different items numbered from 1 to *n*. The *i*-th item has base cost *a**i* Egyptian pounds. If Sagheer buys *k* items with indices *x*1,<=*x*2,<=...,<=*x**k*, then the cost of item *x**j* is *a**x**j*<=+<=*x**j*·*k* for 1<=≤<=*j*<=≤<=*k*. In other words, the cost of an item is equal to its base cost in addition to its index multiplied by the factor *k*.
Sagheer wants to buy as many souvenirs as possible without paying more than *S* Egyptian pounds. Note that he cannot buy a souvenir more than once. If there are many ways to maximize the number of souvenirs, he will choose the way that will minimize the total cost. Can you help him with this task?
Input Specification:
The first line contains two integers *n* and *S* (1<=≤<=*n*<=≤<=105 and 1<=≤<=*S*<=≤<=109) — the number of souvenirs in the market and Sagheer's budget.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=105) — the base costs of the souvenirs.
Output Specification:
On a single line, print two integers *k*, *T* — the maximum number of souvenirs Sagheer can buy and the minimum total cost to buy these *k* souvenirs.
Demo Input:
['3 11\n2 3 5\n', '4 100\n1 2 5 6\n', '1 7\n7\n']
Demo Output:
['2 11\n', '4 54\n', '0 0\n']
Note:
In the first example, he cannot take the three items because they will cost him [5, 9, 14] with total cost 28. If he decides to take only two items, then the costs will be [4, 7, 11]. So he can afford the first and second items.
In the second example, he can buy all items as they will cost him [5, 10, 17, 22].
In the third example, there is only one souvenir in the market which will cost him 8 pounds, so he cannot buy it. | ```python
from operator import itemgetter
n, money = list(map(int, input().split()))
costs = list(map(int, input().split()))
# def check(i, total, indices, taken, left):
#
# # if i in arr:
# # print(i, arr)
# # return arr[i]
# if i > len(costs)-1 and taken != 0:
#
# return ((left)-total-indices*taken, taken)
# elif i < len(costs):
#
# if (total+costs[i]) + (indices+i+1)*(taken+1) <= left:
#
# boo = max(check(i+1, total+costs[i], indices+i+1,taken+1, left), check(i+1, total, indices, taken, left), key=itemgetter(1,0))
# return boo
# else:
# return ((left)-total-indices*taken, taken)
# return (0,0)
#
# a = list(check(0,0,0,0,money)[::-1])
# a[1] = money-a[1]
# print(*a)
#
def binary_search():
cost = 0
ans = 0
u = len(costs)+1
d = 0
while u-1 >= d:
mid = (u+d)//2
k = price(mid, n)
if k > money:
u = mid-1
elif k < money:
d = mid +1
cost = k
ans = mid
else:
print(mid, money)
return
print(ans, cost)
def price(k, n):
b = []
for i in range(1,n+1):
b.append(costs[i-1]+i*k)
b.sort()
return sum(b[:k])
binary_search()
``` | 0 | |
814 | A | An abandoned sentiment from past | PROGRAMMING | 900 | [
"constructive algorithms",
"greedy",
"implementation",
"sortings"
] | null | null | A few years ago, Hitagi encountered a giant crab, who stole the whole of her body weight. Ever since, she tried to avoid contact with others, for fear that this secret might be noticed.
To get rid of the oddity and recover her weight, a special integer sequence is needed. Hitagi's sequence has been broken for a long time, but now Kaiki provides an opportunity.
Hitagi's sequence *a* has a length of *n*. Lost elements in it are denoted by zeros. Kaiki provides another sequence *b*, whose length *k* equals the number of lost elements in *a* (i.e. the number of zeros). Hitagi is to replace each zero in *a* with an element from *b* so that each element in *b* should be used exactly once. Hitagi knows, however, that, apart from 0, no integer occurs in *a* and *b* more than once in total.
If the resulting sequence is not an increasing sequence, then it has the power to recover Hitagi from the oddity. You are to determine whether this is possible, or Kaiki's sequence is just another fake. In other words, you should detect whether it is possible to replace each zero in *a* with an integer from *b* so that each integer from *b* is used exactly once, and the resulting sequence is not increasing. | The first line of input contains two space-separated positive integers *n* (2<=≤<=*n*<=≤<=100) and *k* (1<=≤<=*k*<=≤<=*n*) — the lengths of sequence *a* and *b* respectively.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=200) — Hitagi's broken sequence with exactly *k* zero elements.
The third line contains *k* space-separated integers *b*1,<=*b*2,<=...,<=*b**k* (1<=≤<=*b**i*<=≤<=200) — the elements to fill into Hitagi's sequence.
Input guarantees that apart from 0, no integer occurs in *a* and *b* more than once in total. | Output "Yes" if it's possible to replace zeros in *a* with elements in *b* and make the resulting sequence not increasing, and "No" otherwise. | [
"4 2\n11 0 0 14\n5 4\n",
"6 1\n2 3 0 8 9 10\n5\n",
"4 1\n8 94 0 4\n89\n",
"7 7\n0 0 0 0 0 0 0\n1 2 3 4 5 6 7\n"
] | [
"Yes\n",
"No\n",
"Yes\n",
"Yes\n"
] | In the first sample:
- Sequence *a* is 11, 0, 0, 14. - Two of the elements are lost, and the candidates in *b* are 5 and 4. - There are two possible resulting sequences: 11, 5, 4, 14 and 11, 4, 5, 14, both of which fulfill the requirements. Thus the answer is "Yes".
In the second sample, the only possible resulting sequence is 2, 3, 5, 8, 9, 10, which is an increasing sequence and therefore invalid. | 500 | [
{
"input": "4 2\n11 0 0 14\n5 4",
"output": "Yes"
},
{
"input": "6 1\n2 3 0 8 9 10\n5",
"output": "No"
},
{
"input": "4 1\n8 94 0 4\n89",
"output": "Yes"
},
{
"input": "7 7\n0 0 0 0 0 0 0\n1 2 3 4 5 6 7",
"output": "Yes"
},
{
"input": "40 1\n23 26 27 28 31 35 38 4... | 1,529,006,972 | 2,147,483,647 | Python 3 | OK | TESTS | 96 | 78 | 0 | a=[int(q) for q in input().strip().split()]
b=[int(q) for q in input().strip().split()]
c=[int(q) for q in input().strip().split()]
if a[1]>1:
print('Yes')
else:
for k in range(a[0]):
if b[k]==0:
b[k]=c[0]
break
if len(b)>len(set(b)):
print('Yes')
else:
d=[]
for k in range(a[0]):
d.append(b[k])
d.sort()
if b==d:
print('No')
else:
print('Yes') | Title: An abandoned sentiment from past
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A few years ago, Hitagi encountered a giant crab, who stole the whole of her body weight. Ever since, she tried to avoid contact with others, for fear that this secret might be noticed.
To get rid of the oddity and recover her weight, a special integer sequence is needed. Hitagi's sequence has been broken for a long time, but now Kaiki provides an opportunity.
Hitagi's sequence *a* has a length of *n*. Lost elements in it are denoted by zeros. Kaiki provides another sequence *b*, whose length *k* equals the number of lost elements in *a* (i.e. the number of zeros). Hitagi is to replace each zero in *a* with an element from *b* so that each element in *b* should be used exactly once. Hitagi knows, however, that, apart from 0, no integer occurs in *a* and *b* more than once in total.
If the resulting sequence is not an increasing sequence, then it has the power to recover Hitagi from the oddity. You are to determine whether this is possible, or Kaiki's sequence is just another fake. In other words, you should detect whether it is possible to replace each zero in *a* with an integer from *b* so that each integer from *b* is used exactly once, and the resulting sequence is not increasing.
Input Specification:
The first line of input contains two space-separated positive integers *n* (2<=≤<=*n*<=≤<=100) and *k* (1<=≤<=*k*<=≤<=*n*) — the lengths of sequence *a* and *b* respectively.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=200) — Hitagi's broken sequence with exactly *k* zero elements.
The third line contains *k* space-separated integers *b*1,<=*b*2,<=...,<=*b**k* (1<=≤<=*b**i*<=≤<=200) — the elements to fill into Hitagi's sequence.
Input guarantees that apart from 0, no integer occurs in *a* and *b* more than once in total.
Output Specification:
Output "Yes" if it's possible to replace zeros in *a* with elements in *b* and make the resulting sequence not increasing, and "No" otherwise.
Demo Input:
['4 2\n11 0 0 14\n5 4\n', '6 1\n2 3 0 8 9 10\n5\n', '4 1\n8 94 0 4\n89\n', '7 7\n0 0 0 0 0 0 0\n1 2 3 4 5 6 7\n']
Demo Output:
['Yes\n', 'No\n', 'Yes\n', 'Yes\n']
Note:
In the first sample:
- Sequence *a* is 11, 0, 0, 14. - Two of the elements are lost, and the candidates in *b* are 5 and 4. - There are two possible resulting sequences: 11, 5, 4, 14 and 11, 4, 5, 14, both of which fulfill the requirements. Thus the answer is "Yes".
In the second sample, the only possible resulting sequence is 2, 3, 5, 8, 9, 10, which is an increasing sequence and therefore invalid. | ```python
a=[int(q) for q in input().strip().split()]
b=[int(q) for q in input().strip().split()]
c=[int(q) for q in input().strip().split()]
if a[1]>1:
print('Yes')
else:
for k in range(a[0]):
if b[k]==0:
b[k]=c[0]
break
if len(b)>len(set(b)):
print('Yes')
else:
d=[]
for k in range(a[0]):
d.append(b[k])
d.sort()
if b==d:
print('No')
else:
print('Yes')
``` | 3 | |
451 | B | Sort the Array | PROGRAMMING | 1,300 | [
"implementation",
"sortings"
] | null | null | Being a programmer, you like arrays a lot. For your birthday, your friends have given you an array *a* consisting of *n* distinct integers.
Unfortunately, the size of *a* is too small. You want a bigger array! Your friends agree to give you a bigger array, but only if you are able to answer the following question correctly: is it possible to sort the array *a* (in increasing order) by reversing exactly one segment of *a*? See definitions of segment and reversing in the notes. | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=105) — the size of array *a*.
The second line contains *n* distinct space-separated integers: *a*[1],<=*a*[2],<=...,<=*a*[*n*] (1<=≤<=*a*[*i*]<=≤<=109). | Print "yes" or "no" (without quotes), depending on the answer.
If your answer is "yes", then also print two space-separated integers denoting start and end (start must not be greater than end) indices of the segment to be reversed. If there are multiple ways of selecting these indices, print any of them. | [
"3\n3 2 1\n",
"4\n2 1 3 4\n",
"4\n3 1 2 4\n",
"2\n1 2\n"
] | [
"yes\n1 3\n",
"yes\n1 2\n",
"no\n",
"yes\n1 1\n"
] | Sample 1. You can reverse the entire array to get [1, 2, 3], which is sorted.
Sample 3. No segment can be reversed such that the array will be sorted.
Definitions
A segment [*l*, *r*] of array *a* is the sequence *a*[*l*], *a*[*l* + 1], ..., *a*[*r*].
If you have an array *a* of size *n* and you reverse its segment [*l*, *r*], the array will become:
*a*[1], *a*[2], ..., *a*[*l* - 2], *a*[*l* - 1], *a*[*r*], *a*[*r* - 1], ..., *a*[*l* + 1], *a*[*l*], *a*[*r* + 1], *a*[*r* + 2], ..., *a*[*n* - 1], *a*[*n*]. | 1,000 | [
{
"input": "3\n3 2 1",
"output": "yes\n1 3"
},
{
"input": "4\n2 1 3 4",
"output": "yes\n1 2"
},
{
"input": "4\n3 1 2 4",
"output": "no"
},
{
"input": "2\n1 2",
"output": "yes\n1 1"
},
{
"input": "2\n58 4",
"output": "yes\n1 2"
},
{
"input": "5\n69 37 2... | 1,689,268,753 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | input()
z = []
a = list(map(int,input().split()))
b = a.copy()
b.sort()
c = 0
l = 1
m = 1
if a == b :
print('yes')
print('1 1')
elif a[::-1] == b :
print('yes')
print(f'1 {len(a)}')
else :
for i in range(len(a)-1) :
if a[i]>a[i+1] :
if c == 0 :
l = i
c = 1
for k in range(l,len(a)-1) :
if a[k]<a[k+1] :
m = k
break
else :
0z.append(a[k])
else :
print('no')
if a == b :
print('yes')
print(l+1,m+1)
else:
print('no')
| Title: Sort the Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Being a programmer, you like arrays a lot. For your birthday, your friends have given you an array *a* consisting of *n* distinct integers.
Unfortunately, the size of *a* is too small. You want a bigger array! Your friends agree to give you a bigger array, but only if you are able to answer the following question correctly: is it possible to sort the array *a* (in increasing order) by reversing exactly one segment of *a*? See definitions of segment and reversing in the notes.
Input Specification:
The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=105) — the size of array *a*.
The second line contains *n* distinct space-separated integers: *a*[1],<=*a*[2],<=...,<=*a*[*n*] (1<=≤<=*a*[*i*]<=≤<=109).
Output Specification:
Print "yes" or "no" (without quotes), depending on the answer.
If your answer is "yes", then also print two space-separated integers denoting start and end (start must not be greater than end) indices of the segment to be reversed. If there are multiple ways of selecting these indices, print any of them.
Demo Input:
['3\n3 2 1\n', '4\n2 1 3 4\n', '4\n3 1 2 4\n', '2\n1 2\n']
Demo Output:
['yes\n1 3\n', 'yes\n1 2\n', 'no\n', 'yes\n1 1\n']
Note:
Sample 1. You can reverse the entire array to get [1, 2, 3], which is sorted.
Sample 3. No segment can be reversed such that the array will be sorted.
Definitions
A segment [*l*, *r*] of array *a* is the sequence *a*[*l*], *a*[*l* + 1], ..., *a*[*r*].
If you have an array *a* of size *n* and you reverse its segment [*l*, *r*], the array will become:
*a*[1], *a*[2], ..., *a*[*l* - 2], *a*[*l* - 1], *a*[*r*], *a*[*r* - 1], ..., *a*[*l* + 1], *a*[*l*], *a*[*r* + 1], *a*[*r* + 2], ..., *a*[*n* - 1], *a*[*n*]. | ```python
input()
z = []
a = list(map(int,input().split()))
b = a.copy()
b.sort()
c = 0
l = 1
m = 1
if a == b :
print('yes')
print('1 1')
elif a[::-1] == b :
print('yes')
print(f'1 {len(a)}')
else :
for i in range(len(a)-1) :
if a[i]>a[i+1] :
if c == 0 :
l = i
c = 1
for k in range(l,len(a)-1) :
if a[k]<a[k+1] :
m = k
break
else :
0z.append(a[k])
else :
print('no')
if a == b :
print('yes')
print(l+1,m+1)
else:
print('no')
``` | -1 | |
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
The head of the SSU OPTC is recently gathering teams to participate in the world championship. Each team must consist of exactly three people, at that, any person cannot be a member of two or more teams. What maximum number of teams can the head make if he wants each team to participate in the world championship with the same members at least *k* times? | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,690,199,369 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | n,k = input().split()
n=int(n)
k=int(k)
lst = list(map(int,input().split()))
new_lst = []
c=0
for i in range(n):
new_lst.append(lst[i]+k)
if new_lst[i]<5:
c+=1
print(c//3) | Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
The head of the SSU OPTC is recently gathering teams to participate in the world championship. Each team must consist of exactly three people, at that, any person cannot be a member of two or more teams. What maximum number of teams can the head make if he wants each team to participate in the world championship with the same members at least *k* times?
Input Specification:
The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship.
Output Specification:
Print a single number — the answer to the problem.
Demo Input:
['5 2\n0 4 5 1 0\n', '6 4\n0 1 2 3 4 5\n', '6 5\n0 0 0 0 0 0\n']
Demo Output:
['1\n', '0\n', '2\n']
Note:
In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | ```python
n,k = input().split()
n=int(n)
k=int(k)
lst = list(map(int,input().split()))
new_lst = []
c=0
for i in range(n):
new_lst.append(lst[i]+k)
if new_lst[i]<5:
c+=1
print(c//3)
``` | 0 | |
349 | A | Cinema Line | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | The new "Die Hard" movie has just been released! There are *n* people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the booking clerk sell a ticket to each person and give the change if he initially has no money and sells the tickets strictly in the order people follow in the line? | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of people in the line. The next line contains *n* integers, each of them equals 25, 50 or 100 — the values of the bills the people have. The numbers are given in the order from the beginning of the line (at the box office) to the end of the line. | Print "YES" (without the quotes) if the booking clerk can sell a ticket to each person and give the change. Otherwise print "NO". | [
"4\n25 25 50 50\n",
"2\n25 100\n",
"4\n50 50 25 25\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "4\n25 25 50 50",
"output": "YES"
},
{
"input": "2\n25 100",
"output": "NO"
},
{
"input": "4\n50 50 25 25",
"output": "NO"
},
{
"input": "3\n25 50 100",
"output": "NO"
},
{
"input": "10\n25 25 25 25 25 25 25 25 25 25",
"output": "YES"
},
{
"... | 1,656,677,220 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 40 | 248 | 6,758,400 | n=int(input())
lst=[int(x) for x in input().split()]
dic={25:0,50:0}
for i in lst:
if i==25:dic[25]+=1
elif i==50:
if dic[25]==0:
print('NO')
break
else:
dic[25]-=1
dic[50]+=1
else:
if dic[25]>0 and dic[50]>0:
dic[25]-=1
dic[50]-=1
elif dic[25]>=3:dic[25]-=3
else:
print('NO')
break
else:print('YES')
| Title: Cinema Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The new "Die Hard" movie has just been released! There are *n* people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the booking clerk sell a ticket to each person and give the change if he initially has no money and sells the tickets strictly in the order people follow in the line?
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of people in the line. The next line contains *n* integers, each of them equals 25, 50 or 100 — the values of the bills the people have. The numbers are given in the order from the beginning of the line (at the box office) to the end of the line.
Output Specification:
Print "YES" (without the quotes) if the booking clerk can sell a ticket to each person and give the change. Otherwise print "NO".
Demo Input:
['4\n25 25 50 50\n', '2\n25 100\n', '4\n50 50 25 25\n']
Demo Output:
['YES\n', 'NO\n', 'NO\n']
Note:
none | ```python
n=int(input())
lst=[int(x) for x in input().split()]
dic={25:0,50:0}
for i in lst:
if i==25:dic[25]+=1
elif i==50:
if dic[25]==0:
print('NO')
break
else:
dic[25]-=1
dic[50]+=1
else:
if dic[25]>0 and dic[50]>0:
dic[25]-=1
dic[50]-=1
elif dic[25]>=3:dic[25]-=3
else:
print('NO')
break
else:print('YES')
``` | 3 | |
990 | A | Commentary Boxes | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Berland Football Cup starts really soon! Commentators from all over the world come to the event.
Organizers have already built $n$ commentary boxes. $m$ regional delegations will come to the Cup. Every delegation should get the same number of the commentary boxes. If any box is left unoccupied then the delegations will be upset. So each box should be occupied by exactly one delegation.
If $n$ is not divisible by $m$, it is impossible to distribute the boxes to the delegations at the moment.
Organizers can build a new commentary box paying $a$ burles and demolish a commentary box paying $b$ burles. They can both build and demolish boxes arbitrary number of times (each time paying a corresponding fee). It is allowed to demolish all the existing boxes.
What is the minimal amount of burles organizers should pay to satisfy all the delegations (i.e. to make the number of the boxes be divisible by $m$)? | The only line contains four integer numbers $n$, $m$, $a$ and $b$ ($1 \le n, m \le 10^{12}$, $1 \le a, b \le 100$), where $n$ is the initial number of the commentary boxes, $m$ is the number of delegations to come, $a$ is the fee to build a box and $b$ is the fee to demolish a box. | Output the minimal amount of burles organizers should pay to satisfy all the delegations (i.e. to make the number of the boxes be divisible by $m$). It is allowed that the final number of the boxes is equal to $0$. | [
"9 7 3 8\n",
"2 7 3 7\n",
"30 6 17 19\n"
] | [
"15\n",
"14\n",
"0\n"
] | In the first example organizers can build $5$ boxes to make the total of $14$ paying $3$ burles for the each of them.
In the second example organizers can demolish $2$ boxes to make the total of $0$ paying $7$ burles for the each of them.
In the third example organizers are already able to distribute all the boxes equally among the delegations, each one get $5$ boxes. | 0 | [
{
"input": "9 7 3 8",
"output": "15"
},
{
"input": "2 7 3 7",
"output": "14"
},
{
"input": "30 6 17 19",
"output": "0"
},
{
"input": "500000000001 1000000000000 100 100",
"output": "49999999999900"
},
{
"input": "1000000000000 750000000001 10 100",
"output": "... | 1,608,736,766 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 124 | 0 | a,b,c,d=[int(i) for i in input().split()]
if(a%b==0):
print(0)
else:
a1=(a%b)
a2=a-(a//b)
print(min(a1*c,a2*d,a1*d,a2*c)) | Title: Commentary Boxes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland Football Cup starts really soon! Commentators from all over the world come to the event.
Organizers have already built $n$ commentary boxes. $m$ regional delegations will come to the Cup. Every delegation should get the same number of the commentary boxes. If any box is left unoccupied then the delegations will be upset. So each box should be occupied by exactly one delegation.
If $n$ is not divisible by $m$, it is impossible to distribute the boxes to the delegations at the moment.
Organizers can build a new commentary box paying $a$ burles and demolish a commentary box paying $b$ burles. They can both build and demolish boxes arbitrary number of times (each time paying a corresponding fee). It is allowed to demolish all the existing boxes.
What is the minimal amount of burles organizers should pay to satisfy all the delegations (i.e. to make the number of the boxes be divisible by $m$)?
Input Specification:
The only line contains four integer numbers $n$, $m$, $a$ and $b$ ($1 \le n, m \le 10^{12}$, $1 \le a, b \le 100$), where $n$ is the initial number of the commentary boxes, $m$ is the number of delegations to come, $a$ is the fee to build a box and $b$ is the fee to demolish a box.
Output Specification:
Output the minimal amount of burles organizers should pay to satisfy all the delegations (i.e. to make the number of the boxes be divisible by $m$). It is allowed that the final number of the boxes is equal to $0$.
Demo Input:
['9 7 3 8\n', '2 7 3 7\n', '30 6 17 19\n']
Demo Output:
['15\n', '14\n', '0\n']
Note:
In the first example organizers can build $5$ boxes to make the total of $14$ paying $3$ burles for the each of them.
In the second example organizers can demolish $2$ boxes to make the total of $0$ paying $7$ burles for the each of them.
In the third example organizers are already able to distribute all the boxes equally among the delegations, each one get $5$ boxes. | ```python
a,b,c,d=[int(i) for i in input().split()]
if(a%b==0):
print(0)
else:
a1=(a%b)
a2=a-(a//b)
print(min(a1*c,a2*d,a1*d,a2*c))
``` | 0 | |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square. | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,668,068,813 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | n=int(input())
m=int(input())
a=int(input())
if (n//a)==n/a:
k = n/a
else:
k =(n//a)+1
if (m//a)==m/a:
l = m/a
else:
l =(n//a)+1
print(l*k) | Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square.
Input Specification:
The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109).
Output Specification:
Write the needed number of flagstones.
Demo Input:
['6 6 4\n']
Demo Output:
['4\n']
Note:
none | ```python
n=int(input())
m=int(input())
a=int(input())
if (n//a)==n/a:
k = n/a
else:
k =(n//a)+1
if (m//a)==m/a:
l = m/a
else:
l =(n//a)+1
print(l*k)
``` | -1 |
109 | A | Lucky Sum of Digits | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | A. Lucky Sum of Digits | 2 | 256 | Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya wonders eagerly what minimum lucky number has the sum of digits equal to *n*. Help him cope with the task. | The single line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the sum of digits of the required lucky number. | Print on the single line the result — the minimum lucky number, whose sum of digits equals *n*. If such number does not exist, print -1. | [
"11\n",
"10\n"
] | [
"47\n",
"-1\n"
] | none | 500 | [
{
"input": "11",
"output": "47"
},
{
"input": "10",
"output": "-1"
},
{
"input": "64",
"output": "4477777777"
},
{
"input": "1",
"output": "-1"
},
{
"input": "4",
"output": "4"
},
{
"input": "7",
"output": "7"
},
{
"input": "12",
"outpu... | 1,680,350,323 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 51 | 154 | 921,600 | #IMPORTS
from sys import stdin, stdout
#INPUTS
N = int(stdin.readline())
#CODE
SEVEN = 0
FOUR = 0
POSS = True
while(N%4!=0):
N-=7
SEVEN+=1
if N<0:
POSS = False
break
FOUR+=N//4
if FOUR>=7:
X = FOUR//7
SEVEN+=4*X
FOUR-=7*X
if POSS:
OP = "4"*FOUR + "7"*SEVEN
else:
OP = "-1"
#OUTPUT
stdout.write(f"{OP}\n")
| Title: Lucky Sum of Digits
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya wonders eagerly what minimum lucky number has the sum of digits equal to *n*. Help him cope with the task.
Input Specification:
The single line contains an integer *n* (1<=≤<=*n*<=≤<=106) — the sum of digits of the required lucky number.
Output Specification:
Print on the single line the result — the minimum lucky number, whose sum of digits equals *n*. If such number does not exist, print -1.
Demo Input:
['11\n', '10\n']
Demo Output:
['47\n', '-1\n']
Note:
none | ```python
#IMPORTS
from sys import stdin, stdout
#INPUTS
N = int(stdin.readline())
#CODE
SEVEN = 0
FOUR = 0
POSS = True
while(N%4!=0):
N-=7
SEVEN+=1
if N<0:
POSS = False
break
FOUR+=N//4
if FOUR>=7:
X = FOUR//7
SEVEN+=4*X
FOUR-=7*X
if POSS:
OP = "4"*FOUR + "7"*SEVEN
else:
OP = "-1"
#OUTPUT
stdout.write(f"{OP}\n")
``` | 3.959783 |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpredictable place.
But to their great regret, the leave turned to be very short, so it will be enough to visit one of the three above named places. That's why Yakko, as the cleverest, came up with a truly genius idea: let each of the three roll an ordinary six-sided die, and the one with the highest amount of points will be the winner, and will take the other two to the place of his/her dreams.
Yakko thrown a die and got Y points, Wakko — W points. It was Dot's turn. But she didn't hurry. Dot wanted to know for sure what were her chances to visit Transylvania.
It is known that Yakko and Wakko are true gentlemen, that's why if they have the same amount of points with Dot, they will let Dot win. | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,617,921,776 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 184 | 1,024,000 | from fractions import Fraction
A, W = map(int, input().split())
Max = max(A, W)
prob = 6 - Max + 1
if Max == 6:
print('0/1')
elif Max == 1:
print('1/1')
else:
print(Fraction(prob , 6)) | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpredictable place.
But to their great regret, the leave turned to be very short, so it will be enough to visit one of the three above named places. That's why Yakko, as the cleverest, came up with a truly genius idea: let each of the three roll an ordinary six-sided die, and the one with the highest amount of points will be the winner, and will take the other two to the place of his/her dreams.
Yakko thrown a die and got Y points, Wakko — W points. It was Dot's turn. But she didn't hurry. Dot wanted to know for sure what were her chances to visit Transylvania.
It is known that Yakko and Wakko are true gentlemen, that's why if they have the same amount of points with Dot, they will let Dot win.
Input Specification:
The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls.
Output Specification:
Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1».
Demo Input:
['4 2\n']
Demo Output:
['1/2\n']
Note:
Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | ```python
from fractions import Fraction
A, W = map(int, input().split())
Max = max(A, W)
prob = 6 - Max + 1
if Max == 6:
print('0/1')
elif Max == 1:
print('1/1')
else:
print(Fraction(prob , 6))
``` | 0 |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpredictable place.
But to their great regret, the leave turned to be very short, so it will be enough to visit one of the three above named places. That's why Yakko, as the cleverest, came up with a truly genius idea: let each of the three roll an ordinary six-sided die, and the one with the highest amount of points will be the winner, and will take the other two to the place of his/her dreams.
Yakko thrown a die and got Y points, Wakko — W points. It was Dot's turn. But she didn't hurry. Dot wanted to know for sure what were her chances to visit Transylvania.
It is known that Yakko and Wakko are true gentlemen, that's why if they have the same amount of points with Dot, they will let Dot win. | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,697,126,249 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 60 | 0 | from math import gcd
Y,X=map(int,input().split())
m=max(Y,X)
D=(6-m)+1
g=gcd(D,6)
if(D==6):
print("1")
else:
print(str(D//g)+"/"+str(6//g)) | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpredictable place.
But to their great regret, the leave turned to be very short, so it will be enough to visit one of the three above named places. That's why Yakko, as the cleverest, came up with a truly genius idea: let each of the three roll an ordinary six-sided die, and the one with the highest amount of points will be the winner, and will take the other two to the place of his/her dreams.
Yakko thrown a die and got Y points, Wakko — W points. It was Dot's turn. But she didn't hurry. Dot wanted to know for sure what were her chances to visit Transylvania.
It is known that Yakko and Wakko are true gentlemen, that's why if they have the same amount of points with Dot, they will let Dot win.
Input Specification:
The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls.
Output Specification:
Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1».
Demo Input:
['4 2\n']
Demo Output:
['1/2\n']
Note:
Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | ```python
from math import gcd
Y,X=map(int,input().split())
m=max(Y,X)
D=(6-m)+1
g=gcd(D,6)
if(D==6):
print("1")
else:
print(str(D//g)+"/"+str(6//g))
``` | 0 |
218 | B | Airport | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen plane has *x* (*x*<=><=0) empty seats at the given moment, then the ticket for such a plane costs *x* zlotys (units of Polish currency).
The only ticket office of the airport already has a queue of *n* passengers in front of it. Lolek and Bolek have not stood in the queue yet, but they are already wondering what is the maximum and the minimum number of zlotys the airport administration can earn if all *n* passengers buy tickets according to the conditions of this offer?
The passengers buy tickets in turn, the first person in the queue goes first, then goes the second one, and so on up to *n*-th person. | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of passengers in the queue and the number of planes in the airport, correspondingly. The next line contains *m* integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=1000) — *a**i* stands for the number of empty seats in the *i*-th plane before the ticket office starts selling tickets.
The numbers in the lines are separated by a space. It is guaranteed that there are at least *n* empty seats in total. | Print two integers — the maximum and the minimum number of zlotys that the airport administration can earn, correspondingly. | [
"4 3\n2 1 1\n",
"4 3\n2 2 2\n"
] | [
"5 5\n",
"7 6\n"
] | In the first test sample the number of passengers is equal to the number of empty seats, so regardless of the way the planes are chosen, the administration will earn the same sum.
In the second sample the sum is maximized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 2-nd plane, the 3-rd person — to the 3-rd plane, the 4-th person — to the 1-st plane. The sum is minimized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 1-st plane, the 3-rd person — to the 2-nd plane, the 4-th person — to the 2-nd plane. | 500 | [
{
"input": "4 3\n2 1 1",
"output": "5 5"
},
{
"input": "4 3\n2 2 2",
"output": "7 6"
},
{
"input": "10 5\n10 3 3 1 2",
"output": "58 26"
},
{
"input": "10 1\n10",
"output": "55 55"
},
{
"input": "10 1\n100",
"output": "955 955"
},
{
"input": "10 2\n4 7... | 1,664,547,242 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | for b in range(len(c)):
if b<len(c)/2:
liste1.append(c[b])
else:
liste2.append(c[b])
mn=0
mx=0
for i in range(a):
l=min(liste1)
mn=mn+l
t=liste1.index(min(liste1))
liste1[t]=liste1[t]-1
if liste1[t]==0:
liste1.pop(t)
for i in range(a):
e=max(liste2)
mx=mx+e
p=liste2.index(max(liste2))
liste2[p]=liste2[p]-1
print(mx,mn) | Title: Airport
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen plane has *x* (*x*<=><=0) empty seats at the given moment, then the ticket for such a plane costs *x* zlotys (units of Polish currency).
The only ticket office of the airport already has a queue of *n* passengers in front of it. Lolek and Bolek have not stood in the queue yet, but they are already wondering what is the maximum and the minimum number of zlotys the airport administration can earn if all *n* passengers buy tickets according to the conditions of this offer?
The passengers buy tickets in turn, the first person in the queue goes first, then goes the second one, and so on up to *n*-th person.
Input Specification:
The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of passengers in the queue and the number of planes in the airport, correspondingly. The next line contains *m* integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=1000) — *a**i* stands for the number of empty seats in the *i*-th plane before the ticket office starts selling tickets.
The numbers in the lines are separated by a space. It is guaranteed that there are at least *n* empty seats in total.
Output Specification:
Print two integers — the maximum and the minimum number of zlotys that the airport administration can earn, correspondingly.
Demo Input:
['4 3\n2 1 1\n', '4 3\n2 2 2\n']
Demo Output:
['5 5\n', '7 6\n']
Note:
In the first test sample the number of passengers is equal to the number of empty seats, so regardless of the way the planes are chosen, the administration will earn the same sum.
In the second sample the sum is maximized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 2-nd plane, the 3-rd person — to the 3-rd plane, the 4-th person — to the 1-st plane. The sum is minimized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 1-st plane, the 3-rd person — to the 2-nd plane, the 4-th person — to the 2-nd plane. | ```python
for b in range(len(c)):
if b<len(c)/2:
liste1.append(c[b])
else:
liste2.append(c[b])
mn=0
mx=0
for i in range(a):
l=min(liste1)
mn=mn+l
t=liste1.index(min(liste1))
liste1[t]=liste1[t]-1
if liste1[t]==0:
liste1.pop(t)
for i in range(a):
e=max(liste2)
mx=mx+e
p=liste2.index(max(liste2))
liste2[p]=liste2[p]-1
print(mx,mn)
``` | -1 | |
811 | A | Vladik and Courtesy | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | At regular competition Vladik and Valera won *a* and *b* candies respectively. Vladik offered 1 his candy to Valera. After that Valera gave Vladik 2 his candies, so that no one thought that he was less generous. Vladik for same reason gave 3 candies to Valera in next turn.
More formally, the guys take turns giving each other one candy more than they received in the previous turn.
This continued until the moment when one of them couldn’t give the right amount of candy. Candies, which guys got from each other, they don’t consider as their own. You need to know, who is the first who can’t give the right amount of candy. | Single line of input data contains two space-separated integers *a*, *b* (1<=≤<=*a*,<=*b*<=≤<=109) — number of Vladik and Valera candies respectively. | Pring a single line "Vladik’’ in case, if Vladik first who can’t give right amount of candy, or "Valera’’ otherwise. | [
"1 1\n",
"7 6\n"
] | [
"Valera\n",
"Vladik\n"
] | Illustration for first test case:
<img class="tex-graphics" src="https://espresso.codeforces.com/ad9b7d0e481208de8e3a585aa1d96b9e1dda4fd7.png" style="max-width: 100.0%;max-height: 100.0%;"/>
Illustration for second test case:
<img class="tex-graphics" src="https://espresso.codeforces.com/9f4836d2ccdffaee5a63898e5d4e6caf2ed4678c.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 500 | [
{
"input": "1 1",
"output": "Valera"
},
{
"input": "7 6",
"output": "Vladik"
},
{
"input": "25 38",
"output": "Vladik"
},
{
"input": "8311 2468",
"output": "Valera"
},
{
"input": "250708 857756",
"output": "Vladik"
},
{
"input": "957985574 24997558",
... | 1,687,098,926 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 46 | 0 | vladiks_candies, valeras_candies = map(int, input().split())
candies = 1
while True:
# VLADIKS TURN
if vladiks_candies >= candies:
vladiks_candies -= candies
else:
print("Vladik")
break
candies += 1
# VALERAS TURN
if valeras_candies >= candies:
valeras_candies -= candies
else:
print("Valera")
break
candies += 1
| Title: Vladik and Courtesy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
At regular competition Vladik and Valera won *a* and *b* candies respectively. Vladik offered 1 his candy to Valera. After that Valera gave Vladik 2 his candies, so that no one thought that he was less generous. Vladik for same reason gave 3 candies to Valera in next turn.
More formally, the guys take turns giving each other one candy more than they received in the previous turn.
This continued until the moment when one of them couldn’t give the right amount of candy. Candies, which guys got from each other, they don’t consider as their own. You need to know, who is the first who can’t give the right amount of candy.
Input Specification:
Single line of input data contains two space-separated integers *a*, *b* (1<=≤<=*a*,<=*b*<=≤<=109) — number of Vladik and Valera candies respectively.
Output Specification:
Pring a single line "Vladik’’ in case, if Vladik first who can’t give right amount of candy, or "Valera’’ otherwise.
Demo Input:
['1 1\n', '7 6\n']
Demo Output:
['Valera\n', 'Vladik\n']
Note:
Illustration for first test case:
<img class="tex-graphics" src="https://espresso.codeforces.com/ad9b7d0e481208de8e3a585aa1d96b9e1dda4fd7.png" style="max-width: 100.0%;max-height: 100.0%;"/>
Illustration for second test case:
<img class="tex-graphics" src="https://espresso.codeforces.com/9f4836d2ccdffaee5a63898e5d4e6caf2ed4678c.png" style="max-width: 100.0%;max-height: 100.0%;"/> | ```python
vladiks_candies, valeras_candies = map(int, input().split())
candies = 1
while True:
# VLADIKS TURN
if vladiks_candies >= candies:
vladiks_candies -= candies
else:
print("Vladik")
break
candies += 1
# VALERAS TURN
if valeras_candies >= candies:
valeras_candies -= candies
else:
print("Valera")
break
candies += 1
``` | 3 | |
802 | G | Fake News (easy) | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it... | The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z). | Output YES if the string *s* contains heidi as a subsequence and NO otherwise. | [
"abcheaibcdi\n",
"hiedi\n"
] | [
"YES",
"NO"
] | A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | 0 | [
{
"input": "abcheaibcdi",
"output": "YES"
},
{
"input": "hiedi",
"output": "NO"
},
{
"input": "ihied",
"output": "NO"
},
{
"input": "diehi",
"output": "NO"
},
{
"input": "deiih",
"output": "NO"
},
{
"input": "iheid",
"output": "NO"
},
{
"in... | 1,619,330,151 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 61 | 0 | x = ("heidi")
letters = input("Enter letters: ")
if letters in x:
print("YES")
else:
print("NO")
| Title: Fake News (easy)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it...
Input Specification:
The first and only line of input contains a single nonempty string *s* of length at most 1000 composed of lowercase letters (a-z).
Output Specification:
Output YES if the string *s* contains heidi as a subsequence and NO otherwise.
Demo Input:
['abcheaibcdi\n', 'hiedi\n']
Demo Output:
['YES', 'NO']
Note:
A string *s* contains another string *p* as a subsequence if it is possible to delete some characters from *s* and obtain *p*. | ```python
x = ("heidi")
letters = input("Enter letters: ")
if letters in x:
print("YES")
else:
print("NO")
``` | 0 | |
701 | A | Cards | PROGRAMMING | 800 | [
"greedy",
"implementation"
] | null | null | There are *n* cards (*n* is even) in the deck. Each card has a positive integer written on it. *n*<=/<=2 people will play new card game. At the beginning of the game each player gets two cards, each card is given to exactly one player.
Find the way to distribute cards such that the sum of values written of the cards will be equal for each player. It is guaranteed that it is always possible. | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=100) — the number of cards in the deck. It is guaranteed that *n* is even.
The second line contains the sequence of *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is equal to the number written on the *i*-th card. | Print *n*<=/<=2 pairs of integers, the *i*-th pair denote the cards that should be given to the *i*-th player. Each card should be given to exactly one player. Cards are numbered in the order they appear in the input.
It is guaranteed that solution exists. If there are several correct answers, you are allowed to print any of them. | [
"6\n1 5 7 4 4 3\n",
"4\n10 10 10 10\n"
] | [
"1 3\n6 2\n4 5\n",
"1 2\n3 4\n"
] | In the first sample, cards are distributed in such a way that each player has the sum of numbers written on his cards equal to 8.
In the second sample, all values *a*<sub class="lower-index">*i*</sub> are equal. Thus, any distribution is acceptable. | 500 | [
{
"input": "6\n1 5 7 4 4 3",
"output": "1 3\n6 2\n4 5"
},
{
"input": "4\n10 10 10 10",
"output": "1 4\n2 3"
},
{
"input": "100\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ... | 1,666,262,897 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 46 | 0 | # 6
# 1 5 7 4 4 3
import math
number = int(input())
arr = list(map(int , input().split()))
info = {
"max" : {
'num' : 0 ,
"rebeat" : 0 ,
}
}
numbers = {}
def comapre(number):
if number == info['max']['num'] :
info['max']['rebeat'] += 1
else :
if info[number] > info['max']['rebeat'] :
info['max']['num'] = number
info['max']['rebeat'] = info[number]
for i in range(0 , len(arr)) :
operation = {}
if not arr[i] in numbers.keys() :
numbers[arr[i]] = {
'index' : [] ,
'rebeat': 0
}
numbers[arr[i]]['rebeat'] += 1
numbers[arr[i]]['index'].append(i)
for j in range(i+1 , len(arr)) :
if f"[{arr[i]} , {arr[j]}]" in operation :
continue
operation[f"[{arr[i]} , {arr[j]}]"] = 1
x = arr[i] + arr[j]
if not x in info :
info[x] = 0
info[x] += 1
comapre(x)
while len(numbers) != 0 :
delete = []
for i in numbers.keys():
if numbers[i]['rebeat'] == 0 :
continue
if numbers[info['max']['num'] - i]['rebeat'] == 0 :
continue
x = numbers[i]['index'][0]
numbers[i]['rebeat'] -= 1
numbers[i]['index'].pop(0)
if numbers[i]['rebeat'] == 0 :
delete.append(i)
y = numbers[info['max']['num'] - i ]['index'][0]
numbers[info['max']['num'] - i]['rebeat'] -= 1
numbers[info['max']['num'] - i]['index'].pop(0)
if numbers[info['max']['num'] - i]['rebeat'] == 0 :
delete.append(info['max']['num'] - i)
print(f'{x+1} {y+1}')
for i in delete :
if i in numbers.keys() :
numbers.pop(i) | Title: Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cards (*n* is even) in the deck. Each card has a positive integer written on it. *n*<=/<=2 people will play new card game. At the beginning of the game each player gets two cards, each card is given to exactly one player.
Find the way to distribute cards such that the sum of values written of the cards will be equal for each player. It is guaranteed that it is always possible.
Input Specification:
The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=100) — the number of cards in the deck. It is guaranteed that *n* is even.
The second line contains the sequence of *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is equal to the number written on the *i*-th card.
Output Specification:
Print *n*<=/<=2 pairs of integers, the *i*-th pair denote the cards that should be given to the *i*-th player. Each card should be given to exactly one player. Cards are numbered in the order they appear in the input.
It is guaranteed that solution exists. If there are several correct answers, you are allowed to print any of them.
Demo Input:
['6\n1 5 7 4 4 3\n', '4\n10 10 10 10\n']
Demo Output:
['1 3\n6 2\n4 5\n', '1 2\n3 4\n']
Note:
In the first sample, cards are distributed in such a way that each player has the sum of numbers written on his cards equal to 8.
In the second sample, all values *a*<sub class="lower-index">*i*</sub> are equal. Thus, any distribution is acceptable. | ```python
# 6
# 1 5 7 4 4 3
import math
number = int(input())
arr = list(map(int , input().split()))
info = {
"max" : {
'num' : 0 ,
"rebeat" : 0 ,
}
}
numbers = {}
def comapre(number):
if number == info['max']['num'] :
info['max']['rebeat'] += 1
else :
if info[number] > info['max']['rebeat'] :
info['max']['num'] = number
info['max']['rebeat'] = info[number]
for i in range(0 , len(arr)) :
operation = {}
if not arr[i] in numbers.keys() :
numbers[arr[i]] = {
'index' : [] ,
'rebeat': 0
}
numbers[arr[i]]['rebeat'] += 1
numbers[arr[i]]['index'].append(i)
for j in range(i+1 , len(arr)) :
if f"[{arr[i]} , {arr[j]}]" in operation :
continue
operation[f"[{arr[i]} , {arr[j]}]"] = 1
x = arr[i] + arr[j]
if not x in info :
info[x] = 0
info[x] += 1
comapre(x)
while len(numbers) != 0 :
delete = []
for i in numbers.keys():
if numbers[i]['rebeat'] == 0 :
continue
if numbers[info['max']['num'] - i]['rebeat'] == 0 :
continue
x = numbers[i]['index'][0]
numbers[i]['rebeat'] -= 1
numbers[i]['index'].pop(0)
if numbers[i]['rebeat'] == 0 :
delete.append(i)
y = numbers[info['max']['num'] - i ]['index'][0]
numbers[info['max']['num'] - i]['rebeat'] -= 1
numbers[info['max']['num'] - i]['index'].pop(0)
if numbers[info['max']['num'] - i]['rebeat'] == 0 :
delete.append(info['max']['num'] - i)
print(f'{x+1} {y+1}')
for i in delete :
if i in numbers.keys() :
numbers.pop(i)
``` | 3 | |
950 | A | Left-handers, Right-handers and Ambidexters | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.
The coach decided to form a team of even number of players, exactly half of the players should play with their right hand, and exactly half of the players should play with their left hand. One player should use only on of his hands.
Ambidexters play as well with their right hand as with their left hand. In the team, an ambidexter can play with their left hand, or with their right hand.
Please find the maximum possible size of the team, where equal number of players use their left and right hands, respectively. | The only line contains three integers *l*, *r* and *a* (0<=≤<=*l*,<=*r*,<=*a*<=≤<=100) — the number of left-handers, the number of right-handers and the number of ambidexters at the training. | Print a single even integer — the maximum number of players in the team. It is possible that the team can only have zero number of players. | [
"1 4 2\n",
"5 5 5\n",
"0 2 0\n"
] | [
"6\n",
"14\n",
"0\n"
] | In the first example you can form a team of 6 players. You should take the only left-hander and two ambidexters to play with left hand, and three right-handers to play with right hand. The only person left can't be taken into the team.
In the second example you can form a team of 14 people. You have to take all five left-handers, all five right-handers, two ambidexters to play with left hand and two ambidexters to play with right hand. | 500 | [
{
"input": "1 4 2",
"output": "6"
},
{
"input": "5 5 5",
"output": "14"
},
{
"input": "0 2 0",
"output": "0"
},
{
"input": "30 70 34",
"output": "128"
},
{
"input": "89 32 24",
"output": "112"
},
{
"input": "89 44 77",
"output": "210"
},
{
... | 1,564,293,392 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 0 | # import sys
# sys.stdin = open("test.in","r")
# sys.stdout = open("test.out","w")
l,r,a=map(int,input().split())
if l>r:
if r+a==l:
print(l+r+a)
elif r+a>l:
c=r+a-l
print(2*l+c//2)
else:
print(2*(r+a))
elif l<r:
if l+a==r:
print(l+r+a)
elif l+a>r:
c=l+a-r
print(2*l+c//2)
else:
print(2*(l+a))
else:
print(2*l) | Title: Left-handers, Right-handers and Ambidexters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.
The coach decided to form a team of even number of players, exactly half of the players should play with their right hand, and exactly half of the players should play with their left hand. One player should use only on of his hands.
Ambidexters play as well with their right hand as with their left hand. In the team, an ambidexter can play with their left hand, or with their right hand.
Please find the maximum possible size of the team, where equal number of players use their left and right hands, respectively.
Input Specification:
The only line contains three integers *l*, *r* and *a* (0<=≤<=*l*,<=*r*,<=*a*<=≤<=100) — the number of left-handers, the number of right-handers and the number of ambidexters at the training.
Output Specification:
Print a single even integer — the maximum number of players in the team. It is possible that the team can only have zero number of players.
Demo Input:
['1 4 2\n', '5 5 5\n', '0 2 0\n']
Demo Output:
['6\n', '14\n', '0\n']
Note:
In the first example you can form a team of 6 players. You should take the only left-hander and two ambidexters to play with left hand, and three right-handers to play with right hand. The only person left can't be taken into the team.
In the second example you can form a team of 14 people. You have to take all five left-handers, all five right-handers, two ambidexters to play with left hand and two ambidexters to play with right hand. | ```python
# import sys
# sys.stdin = open("test.in","r")
# sys.stdout = open("test.out","w")
l,r,a=map(int,input().split())
if l>r:
if r+a==l:
print(l+r+a)
elif r+a>l:
c=r+a-l
print(2*l+c//2)
else:
print(2*(r+a))
elif l<r:
if l+a==r:
print(l+r+a)
elif l+a>r:
c=l+a-r
print(2*l+c//2)
else:
print(2*(l+a))
else:
print(2*l)
``` | 0 | |
185 | A | Plant | PROGRAMMING | 1,300 | [
"math"
] | null | null | Dwarfs have planted a very interesting plant, which is a triangle directed "upwards". This plant has an amusing feature. After one year a triangle plant directed "upwards" divides into four triangle plants: three of them will point "upwards" and one will point "downwards". After another year, each triangle plant divides into four triangle plants: three of them will be directed in the same direction as the parent plant, and one of them will be directed in the opposite direction. Then each year the process repeats. The figure below illustrates this process.
Help the dwarfs find out how many triangle plants that point "upwards" will be in *n* years. | The first line contains a single integer *n* (0<=≤<=*n*<=≤<=1018) — the number of full years when the plant grew.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specifier. | Print a single integer — the remainder of dividing the number of plants that will point "upwards" in *n* years by 1000000007 (109<=+<=7). | [
"1\n",
"2\n"
] | [
"3\n",
"10\n"
] | The first test sample corresponds to the second triangle on the figure in the statement. The second test sample corresponds to the third one. | 500 | [
{
"input": "1",
"output": "3"
},
{
"input": "2",
"output": "10"
},
{
"input": "385599124",
"output": "493875375"
},
{
"input": "989464295",
"output": "31966163"
},
{
"input": "376367012",
"output": "523204186"
},
{
"input": "529357306",
"output": "... | 1,664,596,973 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 2 | 404 | 249,446,400 | n = int(input())
print(int((4**n + 2**n) / 2)) | Title: Plant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dwarfs have planted a very interesting plant, which is a triangle directed "upwards". This plant has an amusing feature. After one year a triangle plant directed "upwards" divides into four triangle plants: three of them will point "upwards" and one will point "downwards". After another year, each triangle plant divides into four triangle plants: three of them will be directed in the same direction as the parent plant, and one of them will be directed in the opposite direction. Then each year the process repeats. The figure below illustrates this process.
Help the dwarfs find out how many triangle plants that point "upwards" will be in *n* years.
Input Specification:
The first line contains a single integer *n* (0<=≤<=*n*<=≤<=1018) — the number of full years when the plant grew.
Please do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specifier.
Output Specification:
Print a single integer — the remainder of dividing the number of plants that will point "upwards" in *n* years by 1000000007 (109<=+<=7).
Demo Input:
['1\n', '2\n']
Demo Output:
['3\n', '10\n']
Note:
The first test sample corresponds to the second triangle on the figure in the statement. The second test sample corresponds to the third one. | ```python
n = int(input())
print(int((4**n + 2**n) / 2))
``` | -1 | |
287 | B | Pipeline | PROGRAMMING | 1,700 | [
"binary search",
"math"
] | null | null | Vova, the Ultimate Thule new shaman, wants to build a pipeline. As there are exactly *n* houses in Ultimate Thule, Vova wants the city to have exactly *n* pipes, each such pipe should be connected to the water supply. A pipe can be connected to the water supply if there's water flowing out of it. Initially Vova has only one pipe with flowing water. Besides, Vova has several splitters.
A splitter is a construction that consists of one input (it can be connected to a water pipe) and *x* output pipes. When a splitter is connected to a water pipe, water flows from each output pipe. You can assume that the output pipes are ordinary pipes. For example, you can connect water supply to such pipe if there's water flowing out from it. At most one splitter can be connected to any water pipe.
Vova has one splitter of each kind: with 2, 3, 4, ..., *k* outputs. Help Vova use the minimum number of splitters to build the required pipeline or otherwise state that it's impossible.
Vova needs the pipeline to have exactly *n* pipes with flowing out water. Note that some of those pipes can be the output pipes of the splitters. | The first line contains two space-separated integers *n* and *k* (1<=≤<=*n*<=≤<=1018, 2<=≤<=*k*<=≤<=109).
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | Print a single integer — the minimum number of splitters needed to build the pipeline. If it is impossible to build a pipeline with the given splitters, print -1. | [
"4 3\n",
"5 5\n",
"8 4\n"
] | [
"2\n",
"1\n",
"-1\n"
] | none | 1,500 | [
{
"input": "4 3",
"output": "2"
},
{
"input": "5 5",
"output": "1"
},
{
"input": "8 4",
"output": "-1"
},
{
"input": "1000000000000000000 1000000000",
"output": "-1"
},
{
"input": "499999998500000001 1000000000",
"output": "999955279"
},
{
"input": "49... | 1,691,012,548 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 31 | 0 | n, k = map(int, input().split())
def check(mid):
if mid == 0:
return 1
if mid == 1:
return 2
l = max(2, k - mid + 1)
r = k
return (l + r) * mid // 2 + 1
l = 0
r = k
while l < r:
mid = (l + r) // 2
if check(mid) >= n:
r = mid
else:
l = mid + 1
if check(l) < n:
print(-1)
else:
print(l)
| Title: Pipeline
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vova, the Ultimate Thule new shaman, wants to build a pipeline. As there are exactly *n* houses in Ultimate Thule, Vova wants the city to have exactly *n* pipes, each such pipe should be connected to the water supply. A pipe can be connected to the water supply if there's water flowing out of it. Initially Vova has only one pipe with flowing water. Besides, Vova has several splitters.
A splitter is a construction that consists of one input (it can be connected to a water pipe) and *x* output pipes. When a splitter is connected to a water pipe, water flows from each output pipe. You can assume that the output pipes are ordinary pipes. For example, you can connect water supply to such pipe if there's water flowing out from it. At most one splitter can be connected to any water pipe.
Vova has one splitter of each kind: with 2, 3, 4, ..., *k* outputs. Help Vova use the minimum number of splitters to build the required pipeline or otherwise state that it's impossible.
Vova needs the pipeline to have exactly *n* pipes with flowing out water. Note that some of those pipes can be the output pipes of the splitters.
Input Specification:
The first line contains two space-separated integers *n* and *k* (1<=≤<=*n*<=≤<=1018, 2<=≤<=*k*<=≤<=109).
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output Specification:
Print a single integer — the minimum number of splitters needed to build the pipeline. If it is impossible to build a pipeline with the given splitters, print -1.
Demo Input:
['4 3\n', '5 5\n', '8 4\n']
Demo Output:
['2\n', '1\n', '-1\n']
Note:
none | ```python
n, k = map(int, input().split())
def check(mid):
if mid == 0:
return 1
if mid == 1:
return 2
l = max(2, k - mid + 1)
r = k
return (l + r) * mid // 2 + 1
l = 0
r = k
while l < r:
mid = (l + r) // 2
if check(mid) >= n:
r = mid
else:
l = mid + 1
if check(l) < n:
print(-1)
else:
print(l)
``` | 0 | |
200 | B | Drinks | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Little Vasya loves orange juice very much. That's why any food and drink in his kitchen necessarily contains orange juice. There are *n* drinks in his fridge, the volume fraction of orange juice in the *i*-th drink equals *p**i* percent.
One day Vasya decided to make himself an orange cocktail. He took equal proportions of each of the *n* drinks and mixed them. Then he wondered, how much orange juice the cocktail has.
Find the volume fraction of orange juice in the final drink. | The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of orange-containing drinks in Vasya's fridge. The second line contains *n* integers *p**i* (0<=≤<=*p**i*<=≤<=100) — the volume fraction of orange juice in the *i*-th drink, in percent. The numbers are separated by a space. | Print the volume fraction in percent of orange juice in Vasya's cocktail. The answer will be considered correct if the absolute or relative error does not exceed 10<=<=-<=4. | [
"3\n50 50 100\n",
"4\n0 25 50 75\n"
] | [
"66.666666666667\n",
"37.500000000000\n"
] | Note to the first sample: let's assume that Vasya takes *x* milliliters of each drink from the fridge. Then the volume of pure juice in the cocktail will equal <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c1fac6e64d3a8ee6a5ac138cbe51e60039b22473.png" style="max-width: 100.0%;max-height: 100.0%;"/> milliliters. The total cocktail's volume equals 3·*x* milliliters, so the volume fraction of the juice in the cocktail equals <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/ceb0664e55a1f9f5fa1243ec74680a4665a4d58d.png" style="max-width: 100.0%;max-height: 100.0%;"/>, that is, 66.(6) percent. | 500 | [
{
"input": "3\n50 50 100",
"output": "66.666666666667"
},
{
"input": "4\n0 25 50 75",
"output": "37.500000000000"
},
{
"input": "3\n0 1 8",
"output": "3.000000000000"
},
{
"input": "5\n96 89 93 95 70",
"output": "88.600000000000"
},
{
"input": "7\n62 41 78 4 38 39... | 1,692,547,502 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 92 | 0 | n = int(input())
pi_values = list(map(int, input().split()))
total_volume = sum(pi_values)
average_fraction = total_volume / n
print("{:.12f}".format(average_fraction))
| Title: Drinks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Vasya loves orange juice very much. That's why any food and drink in his kitchen necessarily contains orange juice. There are *n* drinks in his fridge, the volume fraction of orange juice in the *i*-th drink equals *p**i* percent.
One day Vasya decided to make himself an orange cocktail. He took equal proportions of each of the *n* drinks and mixed them. Then he wondered, how much orange juice the cocktail has.
Find the volume fraction of orange juice in the final drink.
Input Specification:
The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of orange-containing drinks in Vasya's fridge. The second line contains *n* integers *p**i* (0<=≤<=*p**i*<=≤<=100) — the volume fraction of orange juice in the *i*-th drink, in percent. The numbers are separated by a space.
Output Specification:
Print the volume fraction in percent of orange juice in Vasya's cocktail. The answer will be considered correct if the absolute or relative error does not exceed 10<=<=-<=4.
Demo Input:
['3\n50 50 100\n', '4\n0 25 50 75\n']
Demo Output:
['66.666666666667\n', '37.500000000000\n']
Note:
Note to the first sample: let's assume that Vasya takes *x* milliliters of each drink from the fridge. Then the volume of pure juice in the cocktail will equal <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c1fac6e64d3a8ee6a5ac138cbe51e60039b22473.png" style="max-width: 100.0%;max-height: 100.0%;"/> milliliters. The total cocktail's volume equals 3·*x* milliliters, so the volume fraction of the juice in the cocktail equals <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/ceb0664e55a1f9f5fa1243ec74680a4665a4d58d.png" style="max-width: 100.0%;max-height: 100.0%;"/>, that is, 66.(6) percent. | ```python
n = int(input())
pi_values = list(map(int, input().split()))
total_volume = sum(pi_values)
average_fraction = total_volume / n
print("{:.12f}".format(average_fraction))
``` | 3 | |
706 | B | Interesting drink | PROGRAMMING | 1,100 | [
"binary search",
"dp",
"implementation"
] | null | null | Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known that the price of one bottle in the shop *i* is equal to *x**i* coins.
Vasiliy plans to buy his favorite drink for *q* consecutive days. He knows, that on the *i*-th day he will be able to spent *m**i* coins. Now, for each of the days he want to know in how many different shops he can buy a bottle of "Beecola". | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of shops in the city that sell Vasiliy's favourite drink.
The second line contains *n* integers *x**i* (1<=≤<=*x**i*<=≤<=100<=000) — prices of the bottles of the drink in the *i*-th shop.
The third line contains a single integer *q* (1<=≤<=*q*<=≤<=100<=000) — the number of days Vasiliy plans to buy the drink.
Then follow *q* lines each containing one integer *m**i* (1<=≤<=*m**i*<=≤<=109) — the number of coins Vasiliy can spent on the *i*-th day. | Print *q* integers. The *i*-th of them should be equal to the number of shops where Vasiliy will be able to buy a bottle of the drink on the *i*-th day. | [
"5\n3 10 8 6 11\n4\n1\n10\n3\n11\n"
] | [
"0\n4\n1\n5\n"
] | On the first day, Vasiliy won't be able to buy a drink in any of the shops.
On the second day, Vasiliy can buy a drink in the shops 1, 2, 3 and 4.
On the third day, Vasiliy can buy a drink only in the shop number 1.
Finally, on the last day Vasiliy can buy a drink in any shop. | 1,000 | [
{
"input": "5\n3 10 8 6 11\n4\n1\n10\n3\n11",
"output": "0\n4\n1\n5"
},
{
"input": "5\n868 987 714 168 123\n10\n424\n192\n795\n873\n117\n914\n735\n158\n631\n471",
"output": "2\n2\n3\n4\n0\n4\n3\n1\n2\n2"
},
{
"input": "3\n435 482 309\n7\n245\n241\n909\n745\n980\n29\n521",
"output": "... | 1,698,330,896 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 2,000 | 13,516,800 | n = int(input()) # the number of shops in the city that sell Vasiliy's favourite drink
x = list(map(int,input().split())) # prices of the bottles of the drink in the i-th shop.
x.sort()
q = int(input()) # the number of days Vasiliy plans to buy the drink.
for i in range(q):
mi = int(input()) # the number of coins Vasiliy can spent on the i-th day.
# for mi in m:
qi = 0 # The i-th of them should be equal to the number of shops where Vasiliy will be able to buy a bottle of the drink on the i-th day.
for idx, xi in enumerate(x):
if xi > mi:
idx -= 1
break
print(idx+1) | Title: Interesting drink
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasiliy likes to rest after a hard work, so you may often meet him in some bar nearby. As all programmers do, he loves the famous drink "Beecola", which can be bought in *n* different shops in the city. It's known that the price of one bottle in the shop *i* is equal to *x**i* coins.
Vasiliy plans to buy his favorite drink for *q* consecutive days. He knows, that on the *i*-th day he will be able to spent *m**i* coins. Now, for each of the days he want to know in how many different shops he can buy a bottle of "Beecola".
Input Specification:
The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of shops in the city that sell Vasiliy's favourite drink.
The second line contains *n* integers *x**i* (1<=≤<=*x**i*<=≤<=100<=000) — prices of the bottles of the drink in the *i*-th shop.
The third line contains a single integer *q* (1<=≤<=*q*<=≤<=100<=000) — the number of days Vasiliy plans to buy the drink.
Then follow *q* lines each containing one integer *m**i* (1<=≤<=*m**i*<=≤<=109) — the number of coins Vasiliy can spent on the *i*-th day.
Output Specification:
Print *q* integers. The *i*-th of them should be equal to the number of shops where Vasiliy will be able to buy a bottle of the drink on the *i*-th day.
Demo Input:
['5\n3 10 8 6 11\n4\n1\n10\n3\n11\n']
Demo Output:
['0\n4\n1\n5\n']
Note:
On the first day, Vasiliy won't be able to buy a drink in any of the shops.
On the second day, Vasiliy can buy a drink in the shops 1, 2, 3 and 4.
On the third day, Vasiliy can buy a drink only in the shop number 1.
Finally, on the last day Vasiliy can buy a drink in any shop. | ```python
n = int(input()) # the number of shops in the city that sell Vasiliy's favourite drink
x = list(map(int,input().split())) # prices of the bottles of the drink in the i-th shop.
x.sort()
q = int(input()) # the number of days Vasiliy plans to buy the drink.
for i in range(q):
mi = int(input()) # the number of coins Vasiliy can spent on the i-th day.
# for mi in m:
qi = 0 # The i-th of them should be equal to the number of shops where Vasiliy will be able to buy a bottle of the drink on the i-th day.
for idx, xi in enumerate(x):
if xi > mi:
idx -= 1
break
print(idx+1)
``` | 0 | |
334 | A | Candy Bags | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Gerald has *n* younger brothers and their number happens to be even. One day he bought *n*2 candy bags. One bag has one candy, one bag has two candies, one bag has three candies and so on. In fact, for each integer *k* from 1 to *n*2 he has exactly one bag with *k* candies.
Help him give *n* bags of candies to each brother so that all brothers got the same number of candies. | The single line contains a single integer *n* (*n* is even, 2<=≤<=*n*<=≤<=100) — the number of Gerald's brothers. | Let's assume that Gerald indexes his brothers with numbers from 1 to *n*. You need to print *n* lines, on the *i*-th line print *n* integers — the numbers of candies in the bags for the *i*-th brother. Naturally, all these numbers should be distinct and be within limits from 1 to *n*2. You can print the numbers in the lines in any order.
It is guaranteed that the solution exists at the given limits. | [
"2\n"
] | [
"1 4\n2 3\n"
] | The sample shows Gerald's actions if he has two brothers. In this case, his bags contain 1, 2, 3 and 4 candies. He can give the bags with 1 and 4 candies to one brother and the bags with 2 and 3 to the other brother. | 500 | [
{
"input": "2",
"output": "1 4\n2 3"
},
{
"input": "4",
"output": "1 16 2 15\n3 14 4 13\n5 12 6 11\n7 10 8 9"
},
{
"input": "6",
"output": "1 36 2 35 3 34\n4 33 5 32 6 31\n7 30 8 29 9 28\n10 27 11 26 12 25\n13 24 14 23 15 22\n16 21 17 20 18 19"
},
{
"input": "8",
"output"... | 1,620,543,879 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 124 | 6,656,000 | n=int(input())
j=1
for i in range(n):
res=[]
for k in range(n//2):
res.append(j)
res.append(n**2-j+1)
j+=1
print(" ".join([str(k) for k in res])) | Title: Candy Bags
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gerald has *n* younger brothers and their number happens to be even. One day he bought *n*2 candy bags. One bag has one candy, one bag has two candies, one bag has three candies and so on. In fact, for each integer *k* from 1 to *n*2 he has exactly one bag with *k* candies.
Help him give *n* bags of candies to each brother so that all brothers got the same number of candies.
Input Specification:
The single line contains a single integer *n* (*n* is even, 2<=≤<=*n*<=≤<=100) — the number of Gerald's brothers.
Output Specification:
Let's assume that Gerald indexes his brothers with numbers from 1 to *n*. You need to print *n* lines, on the *i*-th line print *n* integers — the numbers of candies in the bags for the *i*-th brother. Naturally, all these numbers should be distinct and be within limits from 1 to *n*2. You can print the numbers in the lines in any order.
It is guaranteed that the solution exists at the given limits.
Demo Input:
['2\n']
Demo Output:
['1 4\n2 3\n']
Note:
The sample shows Gerald's actions if he has two brothers. In this case, his bags contain 1, 2, 3 and 4 candies. He can give the bags with 1 and 4 candies to one brother and the bags with 2 and 3 to the other brother. | ```python
n=int(input())
j=1
for i in range(n):
res=[]
for k in range(n//2):
res.append(j)
res.append(n**2-j+1)
j+=1
print(" ".join([str(k) for k in res]))
``` | 3 | |
577 | A | Multiplication Table | PROGRAMMING | 1,000 | [
"implementation",
"number theory"
] | null | null | Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
You are given a positive integer *x*. Your task is to count the number of cells in a table that contain number *x*. | The single line contains numbers *n* and *x* (1<=≤<=*n*<=≤<=105, 1<=≤<=*x*<=≤<=109) — the size of the table and the number that we are looking for in the table. | Print a single number: the number of times *x* occurs in the table. | [
"10 5\n",
"6 12\n",
"5 13\n"
] | [
"2\n",
"4\n",
"0\n"
] | A table for the second sample test is given below. The occurrences of number 12 are marked bold. | 500 | [
{
"input": "10 5",
"output": "2"
},
{
"input": "6 12",
"output": "4"
},
{
"input": "5 13",
"output": "0"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "100000 1",
"output": "1"
},
{
"input": "1 10000000... | 1,672,221,946 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 47 | 62 | 1,536,000 | import math
n, x = list(map(int, input().split()))
nb = 0
sq = int(math.sqrt(x))
if sq**2 == x and sq<=n: # is square
nb += 1
# trig sup
i = 1
while i*i < x and i<n:
if x%i == 0 and x//i <= n:
nb += 2
i += 1
print(nb) | Title: Multiplication Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
You are given a positive integer *x*. Your task is to count the number of cells in a table that contain number *x*.
Input Specification:
The single line contains numbers *n* and *x* (1<=≤<=*n*<=≤<=105, 1<=≤<=*x*<=≤<=109) — the size of the table and the number that we are looking for in the table.
Output Specification:
Print a single number: the number of times *x* occurs in the table.
Demo Input:
['10 5\n', '6 12\n', '5 13\n']
Demo Output:
['2\n', '4\n', '0\n']
Note:
A table for the second sample test is given below. The occurrences of number 12 are marked bold. | ```python
import math
n, x = list(map(int, input().split()))
nb = 0
sq = int(math.sqrt(x))
if sq**2 == x and sq<=n: # is square
nb += 1
# trig sup
i = 1
while i*i < x and i<n:
if x%i == 0 and x//i <= n:
nb += 2
i += 1
print(nb)
``` | 3 | |
250 | A | Paper Work | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | Polycarpus has been working in the analytic department of the "F.R.A.U.D." company for as much as *n* days. Right now his task is to make a series of reports about the company's performance for the last *n* days. We know that the main information in a day report is value *a**i*, the company's profit on the *i*-th day. If *a**i* is negative, then the company suffered losses on the *i*-th day.
Polycarpus should sort the daily reports into folders. Each folder should include data on the company's performance for several consecutive days. Of course, the information on each of the *n* days should be exactly in one folder. Thus, Polycarpus puts information on the first few days in the first folder. The information on the several following days goes to the second folder, and so on.
It is known that the boss reads one daily report folder per day. If one folder has three or more reports for the days in which the company suffered losses (*a**i*<=<<=0), he loses his temper and his wrath is terrible.
Therefore, Polycarpus wants to prepare the folders so that none of them contains information on three or more days with the loss, and the number of folders is minimal.
Write a program that, given sequence *a**i*, will print the minimum number of folders. | The first line contains integer *n* (1<=≤<=*n*<=≤<=100), *n* is the number of days. The second line contains a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=100), where *a**i* means the company profit on the *i*-th day. It is possible that the company has no days with the negative *a**i*. | Print an integer *k* — the required minimum number of folders. In the second line print a sequence of integers *b*1, *b*2, ..., *b**k*, where *b**j* is the number of day reports in the *j*-th folder.
If there are multiple ways to sort the reports into *k* days, print any of them. | [
"11\n1 2 3 -4 -5 -6 5 -5 -6 -7 6\n",
"5\n0 -1 100 -1 0\n"
] | [
"3\n5 3 3 ",
"1\n5 "
] | Here goes a way to sort the reports from the first sample into three folders:
In the second sample you can put all five reports in one folder. | 500 | [
{
"input": "11\n1 2 3 -4 -5 -6 5 -5 -6 -7 6",
"output": "3\n5 3 3 "
},
{
"input": "5\n0 -1 100 -1 0",
"output": "1\n5 "
},
{
"input": "1\n0",
"output": "1\n1 "
},
{
"input": "1\n-1",
"output": "1\n1 "
},
{
"input": "2\n0 0",
"output": "1\n2 "
},
{
"inp... | 1,653,764,291 | 2,147,483,647 | Python 3 | OK | TESTS | 69 | 92 | 0 | n = int(input())
a = list(map(int, input().split()))
f = []
cur = 0
f.append(0)
curr = 0
for i in a:
if i < 0:
curr += 1
if curr >= 3:
curr = 1
f.append(1)
cur += 1
continue
else:
f[cur] += 1
else:
f[cur] += 1
print(len(f))
print(*f) | Title: Paper Work
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has been working in the analytic department of the "F.R.A.U.D." company for as much as *n* days. Right now his task is to make a series of reports about the company's performance for the last *n* days. We know that the main information in a day report is value *a**i*, the company's profit on the *i*-th day. If *a**i* is negative, then the company suffered losses on the *i*-th day.
Polycarpus should sort the daily reports into folders. Each folder should include data on the company's performance for several consecutive days. Of course, the information on each of the *n* days should be exactly in one folder. Thus, Polycarpus puts information on the first few days in the first folder. The information on the several following days goes to the second folder, and so on.
It is known that the boss reads one daily report folder per day. If one folder has three or more reports for the days in which the company suffered losses (*a**i*<=<<=0), he loses his temper and his wrath is terrible.
Therefore, Polycarpus wants to prepare the folders so that none of them contains information on three or more days with the loss, and the number of folders is minimal.
Write a program that, given sequence *a**i*, will print the minimum number of folders.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=100), *n* is the number of days. The second line contains a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=100), where *a**i* means the company profit on the *i*-th day. It is possible that the company has no days with the negative *a**i*.
Output Specification:
Print an integer *k* — the required minimum number of folders. In the second line print a sequence of integers *b*1, *b*2, ..., *b**k*, where *b**j* is the number of day reports in the *j*-th folder.
If there are multiple ways to sort the reports into *k* days, print any of them.
Demo Input:
['11\n1 2 3 -4 -5 -6 5 -5 -6 -7 6\n', '5\n0 -1 100 -1 0\n']
Demo Output:
['3\n5 3 3 ', '1\n5 ']
Note:
Here goes a way to sort the reports from the first sample into three folders:
In the second sample you can put all five reports in one folder. | ```python
n = int(input())
a = list(map(int, input().split()))
f = []
cur = 0
f.append(0)
curr = 0
for i in a:
if i < 0:
curr += 1
if curr >= 3:
curr = 1
f.append(1)
cur += 1
continue
else:
f[cur] += 1
else:
f[cur] += 1
print(len(f))
print(*f)
``` | 3 | |
873 | A | Chores | PROGRAMMING | 800 | [
"implementation"
] | null | null | Luba has to do *n* chores today. *i*-th chore takes *a**i* units of time to complete. It is guaranteed that for every the condition *a**i*<=≥<=*a**i*<=-<=1 is met, so the sequence is sorted.
Also Luba can work really hard on some chores. She can choose not more than *k* any chores and do each of them in *x* units of time instead of *a**i* ().
Luba is very responsible, so she has to do all *n* chores, and now she wants to know the minimum time she needs to do everything. Luba cannot do two chores simultaneously. | The first line contains three integers *n*,<=*k*,<=*x* (1<=≤<=*k*<=≤<=*n*<=≤<=100,<=1<=≤<=*x*<=≤<=99) — the number of chores Luba has to do, the number of chores she can do in *x* units of time, and the number *x* itself.
The second line contains *n* integer numbers *a**i* (2<=≤<=*a**i*<=≤<=100) — the time Luba has to spend to do *i*-th chore.
It is guaranteed that , and for each *a**i*<=≥<=*a**i*<=-<=1. | Print one number — minimum time Luba needs to do all *n* chores. | [
"4 2 2\n3 6 7 10\n",
"5 2 1\n100 100 100 100 100\n"
] | [
"13\n",
"302\n"
] | In the first example the best option would be to do the third and the fourth chore, spending *x* = 2 time on each instead of *a*<sub class="lower-index">3</sub> and *a*<sub class="lower-index">4</sub>, respectively. Then the answer is 3 + 6 + 2 + 2 = 13.
In the second example Luba can choose any two chores to spend *x* time on them instead of *a*<sub class="lower-index">*i*</sub>. So the answer is 100·3 + 2·1 = 302. | 0 | [
{
"input": "4 2 2\n3 6 7 10",
"output": "13"
},
{
"input": "5 2 1\n100 100 100 100 100",
"output": "302"
},
{
"input": "1 1 1\n100",
"output": "1"
},
{
"input": "100 1 99\n100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 ... | 1,698,416,397 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | def findMaxAverage(self, nums, k):
max_average = float('-inf')
window_sum = sum(nums[:k])
for i in range(k, len(nums)):
window_sum += nums[i] - nums[i-k]
max_average = max(max_average, window_sum / k)
return max_average
| Title: Chores
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luba has to do *n* chores today. *i*-th chore takes *a**i* units of time to complete. It is guaranteed that for every the condition *a**i*<=≥<=*a**i*<=-<=1 is met, so the sequence is sorted.
Also Luba can work really hard on some chores. She can choose not more than *k* any chores and do each of them in *x* units of time instead of *a**i* ().
Luba is very responsible, so she has to do all *n* chores, and now she wants to know the minimum time she needs to do everything. Luba cannot do two chores simultaneously.
Input Specification:
The first line contains three integers *n*,<=*k*,<=*x* (1<=≤<=*k*<=≤<=*n*<=≤<=100,<=1<=≤<=*x*<=≤<=99) — the number of chores Luba has to do, the number of chores she can do in *x* units of time, and the number *x* itself.
The second line contains *n* integer numbers *a**i* (2<=≤<=*a**i*<=≤<=100) — the time Luba has to spend to do *i*-th chore.
It is guaranteed that , and for each *a**i*<=≥<=*a**i*<=-<=1.
Output Specification:
Print one number — minimum time Luba needs to do all *n* chores.
Demo Input:
['4 2 2\n3 6 7 10\n', '5 2 1\n100 100 100 100 100\n']
Demo Output:
['13\n', '302\n']
Note:
In the first example the best option would be to do the third and the fourth chore, spending *x* = 2 time on each instead of *a*<sub class="lower-index">3</sub> and *a*<sub class="lower-index">4</sub>, respectively. Then the answer is 3 + 6 + 2 + 2 = 13.
In the second example Luba can choose any two chores to spend *x* time on them instead of *a*<sub class="lower-index">*i*</sub>. So the answer is 100·3 + 2·1 = 302. | ```python
def findMaxAverage(self, nums, k):
max_average = float('-inf')
window_sum = sum(nums[:k])
for i in range(k, len(nums)):
window_sum += nums[i] - nums[i-k]
max_average = max(max_average, window_sum / k)
return max_average
``` | 0 | |
459 | B | Pashmak and Flowers | PROGRAMMING | 1,300 | [
"combinatorics",
"implementation",
"sortings"
] | null | null | Pashmak decided to give Parmida a pair of flowers from the garden. There are *n* flowers in the garden and the *i*-th of them has a beauty number *b**i*. Parmida is a very strange girl so she doesn't want to have the two most beautiful flowers necessarily. She wants to have those pairs of flowers that their beauty difference is maximal possible!
Your task is to write a program which calculates two things:
1. The maximum beauty difference of flowers that Pashmak can give to Parmida. 1. The number of ways that Pashmak can pick the flowers. Two ways are considered different if and only if there is at least one flower that is chosen in the first way and not chosen in the second way. | The first line of the input contains *n* (2<=≤<=*n*<=≤<=2·105). In the next line there are *n* space-separated integers *b*1, *b*2, ..., *b**n* (1<=≤<=*b**i*<=≤<=109). | The only line of output should contain two integers. The maximum beauty difference and the number of ways this may happen, respectively. | [
"2\n1 2\n",
"3\n1 4 5\n",
"5\n3 1 2 3 1\n"
] | [
"1 1",
"4 1",
"2 4"
] | In the third sample the maximum beauty difference is 2 and there are 4 ways to do this:
1. choosing the first and the second flowers; 1. choosing the first and the fifth flowers; 1. choosing the fourth and the second flowers; 1. choosing the fourth and the fifth flowers. | 500 | [
{
"input": "2\n1 2",
"output": "1 1"
},
{
"input": "3\n1 4 5",
"output": "4 1"
},
{
"input": "5\n3 1 2 3 1",
"output": "2 4"
},
{
"input": "2\n1 1",
"output": "0 1"
},
{
"input": "3\n1 1 1",
"output": "0 3"
},
{
"input": "4\n1 1 1 1",
"output": "0 ... | 1,698,503,370 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 58 | 140 | 21,504,000 | n = int(input())
l = [int(a) for a in input().split()]
if min(l) == max(l):
print(0, len(l) * (len(l)-1) // 2)
else:
print(max(l) - min(l), l.count(max(l)) * l.count(min(l))) | Title: Pashmak and Flowers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pashmak decided to give Parmida a pair of flowers from the garden. There are *n* flowers in the garden and the *i*-th of them has a beauty number *b**i*. Parmida is a very strange girl so she doesn't want to have the two most beautiful flowers necessarily. She wants to have those pairs of flowers that their beauty difference is maximal possible!
Your task is to write a program which calculates two things:
1. The maximum beauty difference of flowers that Pashmak can give to Parmida. 1. The number of ways that Pashmak can pick the flowers. Two ways are considered different if and only if there is at least one flower that is chosen in the first way and not chosen in the second way.
Input Specification:
The first line of the input contains *n* (2<=≤<=*n*<=≤<=2·105). In the next line there are *n* space-separated integers *b*1, *b*2, ..., *b**n* (1<=≤<=*b**i*<=≤<=109).
Output Specification:
The only line of output should contain two integers. The maximum beauty difference and the number of ways this may happen, respectively.
Demo Input:
['2\n1 2\n', '3\n1 4 5\n', '5\n3 1 2 3 1\n']
Demo Output:
['1 1', '4 1', '2 4']
Note:
In the third sample the maximum beauty difference is 2 and there are 4 ways to do this:
1. choosing the first and the second flowers; 1. choosing the first and the fifth flowers; 1. choosing the fourth and the second flowers; 1. choosing the fourth and the fifth flowers. | ```python
n = int(input())
l = [int(a) for a in input().split()]
if min(l) == max(l):
print(0, len(l) * (len(l)-1) // 2)
else:
print(max(l) - min(l), l.count(max(l)) * l.count(min(l)))
``` | 3 | |
892 | B | Wrath | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"two pointers"
] | null | null | Hands that shed innocent blood!
There are *n* guilty people in a line, the *i*-th of them holds a claw with length *L**i*. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the *i*-th person kills the *j*-th person if and only if *j*<=<<=*i* and *j*<=≥<=*i*<=-<=*L**i*.
You are given lengths of the claws. You need to find the total number of alive people after the bell rings. | The first line contains one integer *n* (1<=≤<=*n*<=≤<=106) — the number of guilty people.
Second line contains *n* space-separated integers *L*1,<=*L*2,<=...,<=*L**n* (0<=≤<=*L**i*<=≤<=109), where *L**i* is the length of the *i*-th person's claw. | Print one integer — the total number of alive people after the bell rings. | [
"4\n0 1 0 10\n",
"2\n0 0\n",
"10\n1 1 3 0 0 0 2 1 0 3\n"
] | [
"1\n",
"2\n",
"3\n"
] | In first sample the last person kills everyone in front of him. | 1,000 | [
{
"input": "4\n0 1 0 10",
"output": "1"
},
{
"input": "2\n0 0",
"output": "2"
},
{
"input": "10\n1 1 3 0 0 0 2 1 0 3",
"output": "3"
},
{
"input": "10\n0 0 2 0 0 3 3 2 2 0",
"output": "2"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "5\n0 0 0 1 0"... | 1,510,948,595 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 857 | 77,004,800 | n=int(input())
a=list(map(int,input().split()))
y=n-1
ans=0
for i in range(n-1,-1,-1):
q=i-a[i]-1
if i<=y:
ans+=1
if q<0:
break
if q<y:
y=q
print(ans)
| Title: Wrath
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hands that shed innocent blood!
There are *n* guilty people in a line, the *i*-th of them holds a claw with length *L**i*. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the *i*-th person kills the *j*-th person if and only if *j*<=<<=*i* and *j*<=≥<=*i*<=-<=*L**i*.
You are given lengths of the claws. You need to find the total number of alive people after the bell rings.
Input Specification:
The first line contains one integer *n* (1<=≤<=*n*<=≤<=106) — the number of guilty people.
Second line contains *n* space-separated integers *L*1,<=*L*2,<=...,<=*L**n* (0<=≤<=*L**i*<=≤<=109), where *L**i* is the length of the *i*-th person's claw.
Output Specification:
Print one integer — the total number of alive people after the bell rings.
Demo Input:
['4\n0 1 0 10\n', '2\n0 0\n', '10\n1 1 3 0 0 0 2 1 0 3\n']
Demo Output:
['1\n', '2\n', '3\n']
Note:
In first sample the last person kills everyone in front of him. | ```python
n=int(input())
a=list(map(int,input().split()))
y=n-1
ans=0
for i in range(n-1,-1,-1):
q=i-a[i]-1
if i<=y:
ans+=1
if q<0:
break
if q<y:
y=q
print(ans)
``` | 3 | |
133 | A | HQ9+ | PROGRAMMING | 900 | [
"implementation"
] | null | null | HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-sensitive and must be uppercase. The characters of the program which are not instructions are ignored.
You are given a program written in HQ9+. You have to figure out whether executing this program will produce any output. | The input will consist of a single line *p* which will give a program in HQ9+. String *p* will contain between 1 and 100 characters, inclusive. ASCII-code of each character of *p* will be between 33 (exclamation mark) and 126 (tilde), inclusive. | Output "YES", if executing the program will produce any output, and "NO" otherwise. | [
"Hi!\n",
"Codeforces\n"
] | [
"YES\n",
"NO\n"
] | In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions. | 500 | [
{
"input": "Hi!",
"output": "YES"
},
{
"input": "Codeforces",
"output": "NO"
},
{
"input": "a+b=c",
"output": "NO"
},
{
"input": "hq-lowercase",
"output": "NO"
},
{
"input": "Q",
"output": "YES"
},
{
"input": "9",
"output": "YES"
},
{
"inpu... | 1,693,372,101 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | p = input()
count = 0
for i in p:
if i == 'H':
count += 1
elif i == 'Q' and count > 0:
count += 1
elif i == '9' and count > 1:
count += 1
elif i == '+' and count > 2:
print('YES')
else:
print('NO') | Title: HQ9+
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
HQ9+ is a joke programming language which has only four one-character instructions:
- "H" prints "Hello, World!",- "Q" prints the source code of the program itself,- "9" prints the lyrics of "99 Bottles of Beer" song, - "+" increments the value stored in the internal accumulator.
Instructions "H" and "Q" are case-sensitive and must be uppercase. The characters of the program which are not instructions are ignored.
You are given a program written in HQ9+. You have to figure out whether executing this program will produce any output.
Input Specification:
The input will consist of a single line *p* which will give a program in HQ9+. String *p* will contain between 1 and 100 characters, inclusive. ASCII-code of each character of *p* will be between 33 (exclamation mark) and 126 (tilde), inclusive.
Output Specification:
Output "YES", if executing the program will produce any output, and "NO" otherwise.
Demo Input:
['Hi!\n', 'Codeforces\n']
Demo Output:
['YES\n', 'NO\n']
Note:
In the first case the program contains only one instruction — "H", which prints "Hello, World!".
In the second case none of the program characters are language instructions. | ```python
p = input()
count = 0
for i in p:
if i == 'H':
count += 1
elif i == 'Q' and count > 0:
count += 1
elif i == '9' and count > 1:
count += 1
elif i == '+' and count > 2:
print('YES')
else:
print('NO')
``` | 0 | |
831 | B | Keyboard Layouts | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | There are two popular keyboard layouts in Berland, they differ only in letters positions. All the other keys are the same. In Berland they use alphabet with 26 letters which coincides with English alphabet.
You are given two strings consisting of 26 distinct letters each: all keys of the first and the second layouts in the same order.
You are also given some text consisting of small and capital English letters and digits. It is known that it was typed in the first layout, but the writer intended to type it in the second layout. Print the text if the same keys were pressed in the second layout.
Since all keys but letters are the same in both layouts, the capitalization of the letters should remain the same, as well as all other characters. | The first line contains a string of length 26 consisting of distinct lowercase English letters. This is the first layout.
The second line contains a string of length 26 consisting of distinct lowercase English letters. This is the second layout.
The third line contains a non-empty string *s* consisting of lowercase and uppercase English letters and digits. This is the text typed in the first layout. The length of *s* does not exceed 1000. | Print the text if the same keys were pressed in the second layout. | [
"qwertyuiopasdfghjklzxcvbnm\nveamhjsgqocnrbfxdtwkylupzi\nTwccpQZAvb2017\n",
"mnbvcxzlkjhgfdsapoiuytrewq\nasdfghjklqwertyuiopzxcvbnm\n7abaCABAABAcaba7\n"
] | [
"HelloVKCup2017\n",
"7uduGUDUUDUgudu7\n"
] | none | 750 | [
{
"input": "qwertyuiopasdfghjklzxcvbnm\nveamhjsgqocnrbfxdtwkylupzi\nTwccpQZAvb2017",
"output": "HelloVKCup2017"
},
{
"input": "mnbvcxzlkjhgfdsapoiuytrewq\nasdfghjklqwertyuiopzxcvbnm\n7abaCABAABAcaba7",
"output": "7uduGUDUUDUgudu7"
},
{
"input": "ayvguplhjsoiencbkxdrfwmqtz\nkhzvtbspcndier... | 1,646,127,302 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | x=input()
y=input()
l=input()
d={}
for i in range(len(x)):
if(x[i].isnumeric()):
pass
d[x[i]]=y[i]
d[x[i].capitalize()]=y[i].capitalize()
print(d)
s=""
for i in l:
if i.isnumeric():
s=s+i
else:
s=s+d[i]
print(s) | Title: Keyboard Layouts
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are two popular keyboard layouts in Berland, they differ only in letters positions. All the other keys are the same. In Berland they use alphabet with 26 letters which coincides with English alphabet.
You are given two strings consisting of 26 distinct letters each: all keys of the first and the second layouts in the same order.
You are also given some text consisting of small and capital English letters and digits. It is known that it was typed in the first layout, but the writer intended to type it in the second layout. Print the text if the same keys were pressed in the second layout.
Since all keys but letters are the same in both layouts, the capitalization of the letters should remain the same, as well as all other characters.
Input Specification:
The first line contains a string of length 26 consisting of distinct lowercase English letters. This is the first layout.
The second line contains a string of length 26 consisting of distinct lowercase English letters. This is the second layout.
The third line contains a non-empty string *s* consisting of lowercase and uppercase English letters and digits. This is the text typed in the first layout. The length of *s* does not exceed 1000.
Output Specification:
Print the text if the same keys were pressed in the second layout.
Demo Input:
['qwertyuiopasdfghjklzxcvbnm\nveamhjsgqocnrbfxdtwkylupzi\nTwccpQZAvb2017\n', 'mnbvcxzlkjhgfdsapoiuytrewq\nasdfghjklqwertyuiopzxcvbnm\n7abaCABAABAcaba7\n']
Demo Output:
['HelloVKCup2017\n', '7uduGUDUUDUgudu7\n']
Note:
none | ```python
x=input()
y=input()
l=input()
d={}
for i in range(len(x)):
if(x[i].isnumeric()):
pass
d[x[i]]=y[i]
d[x[i].capitalize()]=y[i].capitalize()
print(d)
s=""
for i in l:
if i.isnumeric():
s=s+i
else:
s=s+d[i]
print(s)
``` | 0 | |
461 | A | Appleman and Toastman | PROGRAMMING | 1,200 | [
"greedy",
"sortings"
] | null | null | Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman. - Each time Appleman gets a group consisting of a single number, he throws this group out. Each time Appleman gets a group consisting of more than one number, he splits the group into two non-empty groups (he can do it in any way) and gives each of them to Toastman.
After guys complete all the tasks they look at the score value. What is the maximum possible value of score they can get? | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=106) — the initial group that is given to Toastman. | Print a single integer — the largest possible score. | [
"3\n3 1 5\n",
"1\n10\n"
] | [
"26\n",
"10\n"
] | Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and gives the group to Appleman (he will throw it out). When Toastman receives group [3, 5], he adds 8 to the score and gives the group to Appleman. Appleman splits [3, 5] in the only possible way: [5] and [3]. Then he gives both groups to Toastman. When Toastman receives [5], he adds 5 to the score and gives the group to Appleman (he will throws it out). When Toastman receives [3], he adds 3 to the score and gives the group to Appleman (he will throws it out). Finally Toastman have added 9 + 1 + 8 + 5 + 3 = 26 to the score. This is the optimal sequence of actions. | 500 | [
{
"input": "3\n3 1 5",
"output": "26"
},
{
"input": "1\n10",
"output": "10"
},
{
"input": "10\n8 10 2 5 6 2 4 7 2 1",
"output": "376"
},
{
"input": "10\n171308 397870 724672 431255 228496 892002 542924 718337 888642 161821",
"output": "40204082"
},
{
"input": "10\... | 1,503,846,437 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 5,734,400 | n = int(input())
l = list(map(int, input().split()))
l = sorted(l)
s = sum(l)
while(len(l)>1):
s += l[0]
l.pop(0)
s += sum(l)
print(s) | Title: Appleman and Toastman
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman. - Each time Appleman gets a group consisting of a single number, he throws this group out. Each time Appleman gets a group consisting of more than one number, he splits the group into two non-empty groups (he can do it in any way) and gives each of them to Toastman.
After guys complete all the tasks they look at the score value. What is the maximum possible value of score they can get?
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=106) — the initial group that is given to Toastman.
Output Specification:
Print a single integer — the largest possible score.
Demo Input:
['3\n3 1 5\n', '1\n10\n']
Demo Output:
['26\n', '10\n']
Note:
Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and gives the group to Appleman (he will throw it out). When Toastman receives group [3, 5], he adds 8 to the score and gives the group to Appleman. Appleman splits [3, 5] in the only possible way: [5] and [3]. Then he gives both groups to Toastman. When Toastman receives [5], he adds 5 to the score and gives the group to Appleman (he will throws it out). When Toastman receives [3], he adds 3 to the score and gives the group to Appleman (he will throws it out). Finally Toastman have added 9 + 1 + 8 + 5 + 3 = 26 to the score. This is the optimal sequence of actions. | ```python
n = int(input())
l = list(map(int, input().split()))
l = sorted(l)
s = sum(l)
while(len(l)>1):
s += l[0]
l.pop(0)
s += sum(l)
print(s)
``` | 0 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,678,515,724 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 81 | 124 | 0 | a = int(input())
x = y = z = 0
for _ in range(a):
xx, yy, zz = map(int, input().split())
x += xx
y += yy
z += zz
if x == y == z == 0:
print("YES")
else:
print("NO") | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).
Output Specification:
Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.
Demo Input:
['3\n4 1 7\n-2 4 -1\n1 -5 -3\n', '3\n3 -1 7\n-5 2 -4\n2 -1 -3\n']
Demo Output:
['NO', 'YES']
Note:
none | ```python
a = int(input())
x = y = z = 0
for _ in range(a):
xx, yy, zz = map(int, input().split())
x += xx
y += yy
z += zz
if x == y == z == 0:
print("YES")
else:
print("NO")
``` | 3.969 |
476 | A | Dreamoon and Stairs | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dreamoon wants to climb up a stair of *n* steps. He can climb 1 or 2 steps at each move. Dreamoon wants the number of moves to be a multiple of an integer *m*.
What is the minimal number of moves making him climb to the top of the stairs that satisfies his condition? | The single line contains two space separated integers *n*, *m* (0<=<<=*n*<=≤<=10000,<=1<=<<=*m*<=≤<=10). | Print a single integer — the minimal number of moves being a multiple of *m*. If there is no way he can climb satisfying condition print <=-<=1 instead. | [
"10 2\n",
"3 5\n"
] | [
"6\n",
"-1\n"
] | For the first sample, Dreamoon could climb in 6 moves with following sequence of steps: {2, 2, 2, 2, 1, 1}.
For the second sample, there are only three valid sequence of steps {2, 1}, {1, 2}, {1, 1, 1} with 2, 2, and 3 steps respectively. All these numbers are not multiples of 5. | 500 | [
{
"input": "10 2",
"output": "6"
},
{
"input": "3 5",
"output": "-1"
},
{
"input": "29 7",
"output": "21"
},
{
"input": "2 2",
"output": "2"
},
{
"input": "1 2",
"output": "-1"
},
{
"input": "10000 2",
"output": "5000"
},
{
"input": "10000 ... | 1,670,390,970 | 2,147,483,647 | PyPy 3 | OK | TESTS | 35 | 93 | 0 | n,m = map(int,input().split())
ans = 0
if m>n:
ans = -1
else:
if n%2 == 0:
ans = n//2
else:
ans = n//2+1
while ans%m != 0:
ans+=1
print(ans)
| Title: Dreamoon and Stairs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dreamoon wants to climb up a stair of *n* steps. He can climb 1 or 2 steps at each move. Dreamoon wants the number of moves to be a multiple of an integer *m*.
What is the minimal number of moves making him climb to the top of the stairs that satisfies his condition?
Input Specification:
The single line contains two space separated integers *n*, *m* (0<=<<=*n*<=≤<=10000,<=1<=<<=*m*<=≤<=10).
Output Specification:
Print a single integer — the minimal number of moves being a multiple of *m*. If there is no way he can climb satisfying condition print <=-<=1 instead.
Demo Input:
['10 2\n', '3 5\n']
Demo Output:
['6\n', '-1\n']
Note:
For the first sample, Dreamoon could climb in 6 moves with following sequence of steps: {2, 2, 2, 2, 1, 1}.
For the second sample, there are only three valid sequence of steps {2, 1}, {1, 2}, {1, 1, 1} with 2, 2, and 3 steps respectively. All these numbers are not multiples of 5. | ```python
n,m = map(int,input().split())
ans = 0
if m>n:
ans = -1
else:
if n%2 == 0:
ans = n//2
else:
ans = n//2+1
while ans%m != 0:
ans+=1
print(ans)
``` | 3 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word. | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,631,181,726 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 154 | 6,758,400 | in_str = input()
size = len(in_str)
c_lower = 0
c_upper = 0
for i in in_str:
if i.islower():
c_lower += 1
else:
c_upper += 1
if c_upper > c_lower:
print(in_str.upper())
else:
print(in_str.lower())
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word.
Input Specification:
The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100.
Output Specification:
Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one.
Demo Input:
['HoUse\n', 'ViP\n', 'maTRIx\n']
Demo Output:
['house\n', 'VIP\n', 'matrix\n']
Note:
none | ```python
in_str = input()
size = len(in_str)
c_lower = 0
c_upper = 0
for i in in_str:
if i.islower():
c_lower += 1
else:
c_upper += 1
if c_upper > c_lower:
print(in_str.upper())
else:
print(in_str.lower())
``` | 3.948911 |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word. | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,571,233,740 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 186 | 0 | string= input()
l=u=0
for i in string :
if(i.islower()):
l+=1
else:
u+=1
if(l>u):
print(string.lower())
else:
print(string.upper()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word.
Input Specification:
The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100.
Output Specification:
Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one.
Demo Input:
['HoUse\n', 'ViP\n', 'maTRIx\n']
Demo Output:
['house\n', 'VIP\n', 'matrix\n']
Note:
none | ```python
string= input()
l=u=0
for i in string :
if(i.islower()):
l+=1
else:
u+=1
if(l>u):
print(string.lower())
else:
print(string.upper())
``` | 0 |
954 | A | Diagonal Walking | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mikhail walks on a 2D plane. He can go either up or right. You are given a sequence of Mikhail's moves. He thinks that this sequence is too long and he wants to make it as short as possible.
In the given sequence moving up is described by character U and moving right is described by character R. Mikhail can replace any pair of consecutive moves RU or UR with a diagonal move (described as character D). After that, he can go on and do some other replacements, until there is no pair of consecutive moves RU or UR left.
Your problem is to print the minimum possible length of the sequence of moves after the replacements. | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=100) — the length of the sequence. The second line contains the sequence consisting of *n* characters U and R. | Print the minimum possible length of the sequence of moves after all replacements are done. | [
"5\nRUURU\n",
"17\nUUURRRRRUUURURUUU\n"
] | [
"3\n",
"13\n"
] | In the first test the shortened sequence of moves may be DUD (its length is 3).
In the second test the shortened sequence of moves can be UUDRRRDUDDUUU (its length is 13). | 0 | [
{
"input": "5\nRUURU",
"output": "3"
},
{
"input": "17\nUUURRRRRUUURURUUU",
"output": "13"
},
{
"input": "100\nUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUU",
"output": "100"
},
{
"input": "100\nRRURRUUUURURRRURRRRURRRRRR... | 1,640,701,163 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | n=input()
s=input()
l=len(s)
e=""
d=0
for i in range(l):
if s[i:i+2]=="UR" or s[i:i+2]=="RU" not in e:
d+=1
e+=s[i:i+2]
if "UR" or "RU" in e:
print(l-d)
else:
print(l) | Title: Diagonal Walking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mikhail walks on a 2D plane. He can go either up or right. You are given a sequence of Mikhail's moves. He thinks that this sequence is too long and he wants to make it as short as possible.
In the given sequence moving up is described by character U and moving right is described by character R. Mikhail can replace any pair of consecutive moves RU or UR with a diagonal move (described as character D). After that, he can go on and do some other replacements, until there is no pair of consecutive moves RU or UR left.
Your problem is to print the minimum possible length of the sequence of moves after the replacements.
Input Specification:
The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=100) — the length of the sequence. The second line contains the sequence consisting of *n* characters U and R.
Output Specification:
Print the minimum possible length of the sequence of moves after all replacements are done.
Demo Input:
['5\nRUURU\n', '17\nUUURRRRRUUURURUUU\n']
Demo Output:
['3\n', '13\n']
Note:
In the first test the shortened sequence of moves may be DUD (its length is 3).
In the second test the shortened sequence of moves can be UUDRRRDUDDUUU (its length is 13). | ```python
n=input()
s=input()
l=len(s)
e=""
d=0
for i in range(l):
if s[i:i+2]=="UR" or s[i:i+2]=="RU" not in e:
d+=1
e+=s[i:i+2]
if "UR" or "RU" in e:
print(l-d)
else:
print(l)
``` | 0 | |
615 | A | Bulbs | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is pressed, it turns on all the bulbs it's connected to. Can Vasya light up all the bulbs?
If Vasya presses the button such that some bulbs connected to it are already turned on, they do not change their state, i.e. remain turned on. | The first line of the input contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of buttons and the number of bulbs respectively.
Each of the next *n* lines contains *x**i* (0<=≤<=*x**i*<=≤<=*m*) — the number of bulbs that are turned on by the *i*-th button, and then *x**i* numbers *y**ij* (1<=≤<=*y**ij*<=≤<=*m*) — the numbers of these bulbs. | If it's possible to turn on all *m* bulbs print "YES", otherwise print "NO". | [
"3 4\n2 1 4\n3 1 3 1\n1 2\n",
"3 3\n1 1\n1 2\n1 1\n"
] | [
"YES\n",
"NO\n"
] | In the first sample you can press each button once and turn on all the bulbs. In the 2 sample it is impossible to turn on the 3-rd lamp. | 500 | [
{
"input": "3 4\n2 1 4\n3 1 3 1\n1 2",
"output": "YES"
},
{
"input": "3 3\n1 1\n1 2\n1 1",
"output": "NO"
},
{
"input": "3 4\n1 1\n1 2\n1 3",
"output": "NO"
},
{
"input": "1 5\n5 1 2 3 4 5",
"output": "YES"
},
{
"input": "1 5\n5 4 4 1 2 3",
"output": "NO"
},... | 1,681,149,582 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 31 | 0 | n, m = map(int, input().split())
a = set()
for i in range(n):
a |= set(map(int, input().split()))
print('YES' if len(a) == m else 'NO') | Title: Bulbs
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya wants to turn on Christmas lights consisting of *m* bulbs. Initially, all bulbs are turned off. There are *n* buttons, each of them is connected to some set of bulbs. Vasya can press any of these buttons. When the button is pressed, it turns on all the bulbs it's connected to. Can Vasya light up all the bulbs?
If Vasya presses the button such that some bulbs connected to it are already turned on, they do not change their state, i.e. remain turned on.
Input Specification:
The first line of the input contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of buttons and the number of bulbs respectively.
Each of the next *n* lines contains *x**i* (0<=≤<=*x**i*<=≤<=*m*) — the number of bulbs that are turned on by the *i*-th button, and then *x**i* numbers *y**ij* (1<=≤<=*y**ij*<=≤<=*m*) — the numbers of these bulbs.
Output Specification:
If it's possible to turn on all *m* bulbs print "YES", otherwise print "NO".
Demo Input:
['3 4\n2 1 4\n3 1 3 1\n1 2\n', '3 3\n1 1\n1 2\n1 1\n']
Demo Output:
['YES\n', 'NO\n']
Note:
In the first sample you can press each button once and turn on all the bulbs. In the 2 sample it is impossible to turn on the 3-rd lamp. | ```python
n, m = map(int, input().split())
a = set()
for i in range(n):
a |= set(map(int, input().split()))
print('YES' if len(a) == m else 'NO')
``` | 0 | |
591 | A | Wizards' Duel | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length *l*. Two opponents simultaneously charge a deadly spell in the enemy. We know that the impulse of Harry's magic spell flies at a speed of *p* meters per second, and the impulse of You-Know-Who's magic spell flies at a speed of *q* meters per second.
The impulses are moving through the corridor toward each other, and at the time of the collision they turn round and fly back to those who cast them without changing their original speeds. Then, as soon as the impulse gets back to it's caster, the wizard reflects it and sends again towards the enemy, without changing the original speed of the impulse.
Since Harry has perfectly mastered the basics of magic, he knows that after the second collision both impulses will disappear, and a powerful explosion will occur exactly in the place of their collision. However, the young wizard isn't good at math, so he asks you to calculate the distance from his position to the place of the second meeting of the spell impulses, provided that the opponents do not change positions during the whole fight. | The first line of the input contains a single integer *l* (1<=≤<=*l*<=≤<=1<=000) — the length of the corridor where the fight takes place.
The second line contains integer *p*, the third line contains integer *q* (1<=≤<=*p*,<=*q*<=≤<=500) — the speeds of magical impulses for Harry Potter and He-Who-Must-Not-Be-Named, respectively. | Print a single real number — the distance from the end of the corridor, where Harry is located, to the place of the second meeting of the spell impulses. Your answer will be considered correct if its absolute or relative error will not exceed 10<=-<=4.
Namely: let's assume that your answer equals *a*, and the answer of the jury is *b*. The checker program will consider your answer correct if . | [
"100\n50\n50\n",
"199\n60\n40\n"
] | [
"50\n",
"119.4\n"
] | In the first sample the speeds of the impulses are equal, so both of their meetings occur exactly in the middle of the corridor. | 500 | [
{
"input": "100\n50\n50",
"output": "50"
},
{
"input": "199\n60\n40",
"output": "119.4"
},
{
"input": "1\n1\n1",
"output": "0.5"
},
{
"input": "1\n1\n500",
"output": "0.001996007984"
},
{
"input": "1\n500\n1",
"output": "0.998003992"
},
{
"input": "1\n... | 1,445,939,422 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 62 | 0 | l,a,b=int(input()),int(input()),int(input())
print(a*(l/(a+b))) | Title: Wizards' Duel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length *l*. Two opponents simultaneously charge a deadly spell in the enemy. We know that the impulse of Harry's magic spell flies at a speed of *p* meters per second, and the impulse of You-Know-Who's magic spell flies at a speed of *q* meters per second.
The impulses are moving through the corridor toward each other, and at the time of the collision they turn round and fly back to those who cast them without changing their original speeds. Then, as soon as the impulse gets back to it's caster, the wizard reflects it and sends again towards the enemy, without changing the original speed of the impulse.
Since Harry has perfectly mastered the basics of magic, he knows that after the second collision both impulses will disappear, and a powerful explosion will occur exactly in the place of their collision. However, the young wizard isn't good at math, so he asks you to calculate the distance from his position to the place of the second meeting of the spell impulses, provided that the opponents do not change positions during the whole fight.
Input Specification:
The first line of the input contains a single integer *l* (1<=≤<=*l*<=≤<=1<=000) — the length of the corridor where the fight takes place.
The second line contains integer *p*, the third line contains integer *q* (1<=≤<=*p*,<=*q*<=≤<=500) — the speeds of magical impulses for Harry Potter and He-Who-Must-Not-Be-Named, respectively.
Output Specification:
Print a single real number — the distance from the end of the corridor, where Harry is located, to the place of the second meeting of the spell impulses. Your answer will be considered correct if its absolute or relative error will not exceed 10<=-<=4.
Namely: let's assume that your answer equals *a*, and the answer of the jury is *b*. The checker program will consider your answer correct if .
Demo Input:
['100\n50\n50\n', '199\n60\n40\n']
Demo Output:
['50\n', '119.4\n']
Note:
In the first sample the speeds of the impulses are equal, so both of their meetings occur exactly in the middle of the corridor. | ```python
l,a,b=int(input()),int(input()),int(input())
print(a*(l/(a+b)))
``` | 3 | |
840 | D | Destiny | PROGRAMMING | 2,500 | [
"data structures",
"probabilities"
] | null | null | Once, Leha found in the left pocket an array consisting of *n* integers, and in the right pocket *q* queries of the form *l* *r* *k*. If there are queries, then they must be answered. Answer for the query is minimal *x* such that *x* occurs in the interval *l* *r* strictly more than times or <=-<=1 if there is no such number. Help Leha with such a difficult task. | First line of input data contains two integers *n* and *q* (1<=≤<=*n*,<=*q*<=≤<=3·105) — number of elements in the array and number of queries respectively.
Next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — Leha's array.
Each of next *q* lines contains three integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*,<=2<=≤<=*k*<=≤<=5) — description of the queries. | Output answer for each query in new line. | [
"4 2\n1 1 2 2\n1 3 2\n1 4 2\n",
"5 3\n1 2 1 3 2\n2 5 3\n1 2 3\n5 5 2\n"
] | [
"1\n-1\n",
"2\n1\n2\n"
] | none | 2,000 | [] | 1,689,194,449 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | print("_RANDOM_GUESS_1689194449.240316")# 1689194449.240362 | Title: Destiny
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once, Leha found in the left pocket an array consisting of *n* integers, and in the right pocket *q* queries of the form *l* *r* *k*. If there are queries, then they must be answered. Answer for the query is minimal *x* such that *x* occurs in the interval *l* *r* strictly more than times or <=-<=1 if there is no such number. Help Leha with such a difficult task.
Input Specification:
First line of input data contains two integers *n* and *q* (1<=≤<=*n*,<=*q*<=≤<=3·105) — number of elements in the array and number of queries respectively.
Next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — Leha's array.
Each of next *q* lines contains three integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=*n*,<=2<=≤<=*k*<=≤<=5) — description of the queries.
Output Specification:
Output answer for each query in new line.
Demo Input:
['4 2\n1 1 2 2\n1 3 2\n1 4 2\n', '5 3\n1 2 1 3 2\n2 5 3\n1 2 3\n5 5 2\n']
Demo Output:
['1\n-1\n', '2\n1\n2\n']
Note:
none | ```python
print("_RANDOM_GUESS_1689194449.240316")# 1689194449.240362
``` | 0 | |
296 | A | Yaroslav and Permutations | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would be distinct in a finite time.
Help Yaroslav. | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in the array. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000) — the array elements. | In the single line print "YES" (without the quotes) if Yaroslav can obtain the array he needs, and "NO" (without the quotes) otherwise. | [
"1\n1\n",
"3\n1 1 2\n",
"4\n7 7 7 7\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first sample the initial array fits well.
In the second sample Yaroslav can get array: 1, 2, 1. He can swap the last and the second last elements to obtain it.
In the third sample Yarosav can't get the array he needs. | 500 | [
{
"input": "1\n1",
"output": "YES"
},
{
"input": "3\n1 1 2",
"output": "YES"
},
{
"input": "4\n7 7 7 7",
"output": "NO"
},
{
"input": "4\n479 170 465 146",
"output": "YES"
},
{
"input": "5\n996 437 605 996 293",
"output": "YES"
},
{
"input": "6\n727 53... | 1,594,810,922 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 218 | 6,758,400 | n=int(input())
a=[int(x) for x in input().split()]
for i in a:
if a.count(i)*2>n+1:
print("NO")
break
else:
print("YES") | Title: Yaroslav and Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would be distinct in a finite time.
Help Yaroslav.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in the array. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000) — the array elements.
Output Specification:
In the single line print "YES" (without the quotes) if Yaroslav can obtain the array he needs, and "NO" (without the quotes) otherwise.
Demo Input:
['1\n1\n', '3\n1 1 2\n', '4\n7 7 7 7\n']
Demo Output:
['YES\n', 'YES\n', 'NO\n']
Note:
In the first sample the initial array fits well.
In the second sample Yaroslav can get array: 1, 2, 1. He can swap the last and the second last elements to obtain it.
In the third sample Yarosav can't get the array he needs. | ```python
n=int(input())
a=[int(x) for x in input().split()]
for i in a:
if a.count(i)*2>n+1:
print("NO")
break
else:
print("YES")
``` | 3 | |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consists of several words. For each language, all words are distinct, i.e. they are spelled differently. Moreover, the words of these languages have a one-to-one correspondence, that is, for each word in each language, there exists exactly one word in the other language having has the same meaning.
You can write down every word the professor says in either the first language or the second language. Of course, during the lecture you write down each word in the language in which the word is shorter. In case of equal lengths of the corresponding words you prefer the word of the first language.
You are given the text of the lecture the professor is going to read. Find out how the lecture will be recorded in your notes. | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* belongs to the first language, the word *b**i* belongs to the second language, and these two words have the same meaning. It is guaranteed that no word occurs in both languages, and each word occurs in its language exactly once.
The next line contains *n* space-separated strings *c*1,<=*c*2,<=...,<=*c**n* — the text of the lecture. It is guaranteed that each of the strings *c**i* belongs to the set of strings {*a*1,<=*a*2,<=... *a**m*}.
All the strings in the input are non-empty, each consisting of no more than 10 lowercase English letters. | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,694,803,474 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 19 | 1,000 | 1,331,200 | n,m = map(int,input().split())
words = []
for i in range(m):
l = input().split()
words.append(l)
lecture = input().split()
l1 = []
for i in lecture:
for j in words:
if j[0] == i or j[1] == i:
if len(j[0])>len(j[1]):
l1.append(j[1])
else:
l1.append(j[0])
for i in l1:
print(i, end=" ") | Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consists of several words. For each language, all words are distinct, i.e. they are spelled differently. Moreover, the words of these languages have a one-to-one correspondence, that is, for each word in each language, there exists exactly one word in the other language having has the same meaning.
You can write down every word the professor says in either the first language or the second language. Of course, during the lecture you write down each word in the language in which the word is shorter. In case of equal lengths of the corresponding words you prefer the word of the first language.
You are given the text of the lecture the professor is going to read. Find out how the lecture will be recorded in your notes.
Input Specification:
The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* belongs to the first language, the word *b**i* belongs to the second language, and these two words have the same meaning. It is guaranteed that no word occurs in both languages, and each word occurs in its language exactly once.
The next line contains *n* space-separated strings *c*1,<=*c*2,<=...,<=*c**n* — the text of the lecture. It is guaranteed that each of the strings *c**i* belongs to the set of strings {*a*1,<=*a*2,<=... *a**m*}.
All the strings in the input are non-empty, each consisting of no more than 10 lowercase English letters.
Output Specification:
Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input.
Demo Input:
['4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n', '5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n']
Demo Output:
['codeforces round letter round\n', 'hbnyiyc joll joll un joll\n']
Note:
none | ```python
n,m = map(int,input().split())
words = []
for i in range(m):
l = input().split()
words.append(l)
lecture = input().split()
l1 = []
for i in lecture:
for j in words:
if j[0] == i or j[1] == i:
if len(j[0])>len(j[1]):
l1.append(j[1])
else:
l1.append(j[0])
for i in l1:
print(i, end=" ")
``` | 0 | |
495 | A | Digital Counter | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Malek lives in an apartment block with 100 floors numbered from 0 to 99. The apartment has an elevator with a digital counter showing the floor that the elevator is currently on. The elevator shows each digit of a number with 7 light sticks by turning them on or off. The picture below shows how the elevator shows each digit.
One day when Malek wanted to go from floor 88 to floor 0 using the elevator he noticed that the counter shows number 89 instead of 88. Then when the elevator started moving the number on the counter changed to 87. After a little thinking Malek came to the conclusion that there is only one explanation for this: One of the sticks of the counter was broken. Later that day Malek was thinking about the broken stick and suddenly he came up with the following problem.
Suppose the digital counter is showing number *n*. Malek calls an integer *x* (0<=≤<=*x*<=≤<=99) good if it's possible that the digital counter was supposed to show *x* but because of some(possibly none) broken sticks it's showing *n* instead. Malek wants to know number of good integers for a specific *n*. So you must write a program that calculates this number. Please note that the counter always shows two digits. | The only line of input contains exactly two digits representing number *n* (0<=≤<=*n*<=≤<=99). Note that *n* may have a leading zero. | In the only line of the output print the number of good integers. | [
"89\n",
"00\n",
"73\n"
] | [
"2\n",
"4\n",
"15\n"
] | In the first sample the counter may be supposed to show 88 or 89.
In the second sample the good integers are 00, 08, 80 and 88.
In the third sample the good integers are 03, 08, 09, 33, 38, 39, 73, 78, 79, 83, 88, 89, 93, 98, 99. | 500 | [
{
"input": "89",
"output": "2"
},
{
"input": "00",
"output": "4"
},
{
"input": "73",
"output": "15"
},
{
"input": "08",
"output": "2"
},
{
"input": "26",
"output": "4"
},
{
"input": "49",
"output": "6"
},
{
"input": "88",
"output": "1"
... | 1,434,293,035 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 13 | 62 | 0 | a , b = map(int, input())
col = 0
if a == 0 or a == 9 or a == 6 or a == 2:
col = col + 1
elif a == 3 or a == 4 or a == 5:
col = col + 2
elif a == 7:
col = col + 4
elif a == 1:
col = col + 6
t = col + 1
col = 0
if b == 0 or b == 9 or b == 6 or b == 2:
col = col + 1
elif b == 3 or b == 4 or b == 5:
col = col + 2
elif b == 7:
col = col + 4
elif b == 1:
col = col + 6
print(t * (col + 1))
| Title: Digital Counter
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Malek lives in an apartment block with 100 floors numbered from 0 to 99. The apartment has an elevator with a digital counter showing the floor that the elevator is currently on. The elevator shows each digit of a number with 7 light sticks by turning them on or off. The picture below shows how the elevator shows each digit.
One day when Malek wanted to go from floor 88 to floor 0 using the elevator he noticed that the counter shows number 89 instead of 88. Then when the elevator started moving the number on the counter changed to 87. After a little thinking Malek came to the conclusion that there is only one explanation for this: One of the sticks of the counter was broken. Later that day Malek was thinking about the broken stick and suddenly he came up with the following problem.
Suppose the digital counter is showing number *n*. Malek calls an integer *x* (0<=≤<=*x*<=≤<=99) good if it's possible that the digital counter was supposed to show *x* but because of some(possibly none) broken sticks it's showing *n* instead. Malek wants to know number of good integers for a specific *n*. So you must write a program that calculates this number. Please note that the counter always shows two digits.
Input Specification:
The only line of input contains exactly two digits representing number *n* (0<=≤<=*n*<=≤<=99). Note that *n* may have a leading zero.
Output Specification:
In the only line of the output print the number of good integers.
Demo Input:
['89\n', '00\n', '73\n']
Demo Output:
['2\n', '4\n', '15\n']
Note:
In the first sample the counter may be supposed to show 88 or 89.
In the second sample the good integers are 00, 08, 80 and 88.
In the third sample the good integers are 03, 08, 09, 33, 38, 39, 73, 78, 79, 83, 88, 89, 93, 98, 99. | ```python
a , b = map(int, input())
col = 0
if a == 0 or a == 9 or a == 6 or a == 2:
col = col + 1
elif a == 3 or a == 4 or a == 5:
col = col + 2
elif a == 7:
col = col + 4
elif a == 1:
col = col + 6
t = col + 1
col = 0
if b == 0 or b == 9 or b == 6 or b == 2:
col = col + 1
elif b == 3 or b == 4 or b == 5:
col = col + 2
elif b == 7:
col = col + 4
elif b == 1:
col = col + 6
print(t * (col + 1))
``` | 0 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,587,636,490 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 80 | 216 | 0 | n = int(input())
javab = []
for i in range(n):
listans = [int(n) for n in input().split()]
javab.append(listans)
javab = [int(x) for c in javab for x in c]
if sum(javab) == 0:
print("YES")
else:
print("NO")
| Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).
Output Specification:
Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.
Demo Input:
['3\n4 1 7\n-2 4 -1\n1 -5 -3\n', '3\n3 -1 7\n-5 2 -4\n2 -1 -3\n']
Demo Output:
['NO', 'YES']
Note:
none | ```python
n = int(input())
javab = []
for i in range(n):
listans = [int(n) for n in input().split()]
javab.append(listans)
javab = [int(x) for c in javab for x in c]
if sum(javab) == 0:
print("YES")
else:
print("NO")
``` | 0 |
16 | A | Flag | PROGRAMMING | 800 | [
"implementation"
] | A. Flag | 2 | 64 | According to a new ISO standard, a flag of every country should have a chequered field *n*<=×<=*m*, each square should be of one of 10 colours, and the flag should be «striped»: each horizontal row of the flag should contain squares of the same colour, and the colours of adjacent horizontal rows should be different. Berland's government asked you to find out whether their flag meets the new ISO standard. | The first line of the input contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), *n* — the amount of rows, *m* — the amount of columns on the flag of Berland. Then there follows the description of the flag: each of the following *n* lines contain *m* characters. Each character is a digit between 0 and 9, and stands for the colour of the corresponding square. | Output YES, if the flag meets the new ISO standard, and NO otherwise. | [
"3 3\n000\n111\n222\n",
"3 3\n000\n000\n111\n",
"3 3\n000\n111\n002\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 0 | [
{
"input": "3 3\n000\n111\n222",
"output": "YES"
},
{
"input": "3 3\n000\n000\n111",
"output": "NO"
},
{
"input": "3 3\n000\n111\n002",
"output": "NO"
},
{
"input": "10 10\n2222222222\n5555555555\n0000000000\n4444444444\n1111111111\n3333333393\n3333333333\n5555555555\n0000000... | 1,548,563,573 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 248 | 0 | from sys import stdin
def main():
a,b=[int(x)for x in stdin.readline().strip().split()]
T=True
for x in range(a):
per=stdin.readline().strip()
if T:
for y in range(1,b):
if per[0]!=per[y]:T=False
if x==0:prob=per[0]
else:
if prob==per[0]:T=False
else: prob=per[0]
if T:print("YES")
else:print("NO")
main() | Title: Flag
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
According to a new ISO standard, a flag of every country should have a chequered field *n*<=×<=*m*, each square should be of one of 10 colours, and the flag should be «striped»: each horizontal row of the flag should contain squares of the same colour, and the colours of adjacent horizontal rows should be different. Berland's government asked you to find out whether their flag meets the new ISO standard.
Input Specification:
The first line of the input contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), *n* — the amount of rows, *m* — the amount of columns on the flag of Berland. Then there follows the description of the flag: each of the following *n* lines contain *m* characters. Each character is a digit between 0 and 9, and stands for the colour of the corresponding square.
Output Specification:
Output YES, if the flag meets the new ISO standard, and NO otherwise.
Demo Input:
['3 3\n000\n111\n222\n', '3 3\n000\n000\n111\n', '3 3\n000\n111\n002\n']
Demo Output:
['YES\n', 'NO\n', 'NO\n']
Note:
none | ```python
from sys import stdin
def main():
a,b=[int(x)for x in stdin.readline().strip().split()]
T=True
for x in range(a):
per=stdin.readline().strip()
if T:
for y in range(1,b):
if per[0]!=per[y]:T=False
if x==0:prob=per[0]
else:
if prob==per[0]:T=False
else: prob=per[0]
if T:print("YES")
else:print("NO")
main()
``` | 3.938 |
154 | B | Colliders | PROGRAMMING | 1,600 | [
"math",
"number theory"
] | null | null | By 2312 there were *n* Large Hadron Colliders in the inhabited part of the universe. Each of them corresponded to a single natural number from 1 to *n*. However, scientists did not know what activating several colliders simultaneously could cause, so the colliders were deactivated.
In 2312 there was a startling discovery: a collider's activity is safe if and only if all numbers of activated colliders are pairwise relatively prime to each other (two numbers are relatively prime if their greatest common divisor equals 1)! If two colliders with relatively nonprime numbers are activated, it will cause a global collapse.
Upon learning this, physicists rushed to turn the colliders on and off and carry out all sorts of experiments. To make sure than the scientists' quickness doesn't end with big trouble, the Large Hadron Colliders' Large Remote Control was created. You are commissioned to write the software for the remote (well, you do not expect anybody to operate it manually, do you?).
Initially, all colliders are deactivated. Your program receives multiple requests of the form "activate/deactivate the *i*-th collider". The program should handle requests in the order of receiving them. The program should print the processed results in the format described below.
To the request of "+ i" (that is, to activate the *i*-th collider), the program should print exactly one of the following responses:
- "Success" if the activation was successful. - "Already on", if the *i*-th collider was already activated before the request. - "Conflict with j", if there is a conflict with the *j*-th collider (that is, the *j*-th collider is on, and numbers *i* and *j* are not relatively prime). In this case, the *i*-th collider shouldn't be activated. If a conflict occurs with several colliders simultaneously, you should print the number of any of them.
The request of "- i" (that is, to deactivate the *i*-th collider), should receive one of the following responses from the program:
- "Success", if the deactivation was successful. - "Already off", if the *i*-th collider was already deactivated before the request.
You don't need to print quotes in the output of the responses to the requests. | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105) — the number of colliders and the number of requests, correspondingly.
Next *m* lines contain numbers of requests, one per line, in the form of either "+ i" (without the quotes) — activate the *i*-th collider, or "- i" (without the quotes) — deactivate the *i*-th collider (1<=≤<=*i*<=≤<=*n*). | Print *m* lines — the results of executing requests in the above given format. The requests should be processed in the order, in which they are given in the input. Don't forget that the responses to the requests should be printed without quotes. | [
"10 10\n+ 6\n+ 10\n+ 5\n- 10\n- 5\n- 6\n+ 10\n+ 3\n+ 6\n+ 3\n"
] | [
"Success\nConflict with 6\nSuccess\nAlready off\nSuccess\nSuccess\nSuccess\nSuccess\nConflict with 10\nAlready on\n"
] | Note that in the sample the colliders don't turn on after the second and ninth requests. The ninth request could also receive response "Conflict with 3". | 1,000 | [
{
"input": "10 10\n+ 6\n+ 10\n+ 5\n- 10\n- 5\n- 6\n+ 10\n+ 3\n+ 6\n+ 3",
"output": "Success\nConflict with 6\nSuccess\nAlready off\nSuccess\nSuccess\nSuccess\nSuccess\nConflict with 10\nAlready on"
},
{
"input": "7 5\n+ 7\n+ 6\n+ 4\n+ 3\n- 7",
"output": "Success\nSuccess\nConflict with 6\nConfli... | 1,683,131,224 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 26 | 2,000 | 9,625,600 | p = [[0]*10 for _ in range(100005)]
b = [0]*100005
v = [0]*100005
c = [0]*100005
t = [0]*100005
def A(x):
if c[x]:
print("Already on")
return
for y in p[x]:
if y and v[y]:
print("Conflict with", v[y])
return
for y in p[x]:
v[y] = x
c[x] = x
print("Success")
def D(x):
if not c[x]:
print("Already off")
return
for y in p[x]:
v[y] = 0
c[x] = 0
print("Success")
n, m = map(int, input().split())
for i in range(2, n+1):
if not b[i]:
for j in range(i, n+1, i):
t[j] += 1
p[j][t[j]] = i
b[j] = 1
for _ in range(m):
s = input().split()
x = int(s[1])
if s[0] == '+':
A(x)
else:
D(x)
| Title: Colliders
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
By 2312 there were *n* Large Hadron Colliders in the inhabited part of the universe. Each of them corresponded to a single natural number from 1 to *n*. However, scientists did not know what activating several colliders simultaneously could cause, so the colliders were deactivated.
In 2312 there was a startling discovery: a collider's activity is safe if and only if all numbers of activated colliders are pairwise relatively prime to each other (two numbers are relatively prime if their greatest common divisor equals 1)! If two colliders with relatively nonprime numbers are activated, it will cause a global collapse.
Upon learning this, physicists rushed to turn the colliders on and off and carry out all sorts of experiments. To make sure than the scientists' quickness doesn't end with big trouble, the Large Hadron Colliders' Large Remote Control was created. You are commissioned to write the software for the remote (well, you do not expect anybody to operate it manually, do you?).
Initially, all colliders are deactivated. Your program receives multiple requests of the form "activate/deactivate the *i*-th collider". The program should handle requests in the order of receiving them. The program should print the processed results in the format described below.
To the request of "+ i" (that is, to activate the *i*-th collider), the program should print exactly one of the following responses:
- "Success" if the activation was successful. - "Already on", if the *i*-th collider was already activated before the request. - "Conflict with j", if there is a conflict with the *j*-th collider (that is, the *j*-th collider is on, and numbers *i* and *j* are not relatively prime). In this case, the *i*-th collider shouldn't be activated. If a conflict occurs with several colliders simultaneously, you should print the number of any of them.
The request of "- i" (that is, to deactivate the *i*-th collider), should receive one of the following responses from the program:
- "Success", if the deactivation was successful. - "Already off", if the *i*-th collider was already deactivated before the request.
You don't need to print quotes in the output of the responses to the requests.
Input Specification:
The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105) — the number of colliders and the number of requests, correspondingly.
Next *m* lines contain numbers of requests, one per line, in the form of either "+ i" (without the quotes) — activate the *i*-th collider, or "- i" (without the quotes) — deactivate the *i*-th collider (1<=≤<=*i*<=≤<=*n*).
Output Specification:
Print *m* lines — the results of executing requests in the above given format. The requests should be processed in the order, in which they are given in the input. Don't forget that the responses to the requests should be printed without quotes.
Demo Input:
['10 10\n+ 6\n+ 10\n+ 5\n- 10\n- 5\n- 6\n+ 10\n+ 3\n+ 6\n+ 3\n']
Demo Output:
['Success\nConflict with 6\nSuccess\nAlready off\nSuccess\nSuccess\nSuccess\nSuccess\nConflict with 10\nAlready on\n']
Note:
Note that in the sample the colliders don't turn on after the second and ninth requests. The ninth request could also receive response "Conflict with 3". | ```python
p = [[0]*10 for _ in range(100005)]
b = [0]*100005
v = [0]*100005
c = [0]*100005
t = [0]*100005
def A(x):
if c[x]:
print("Already on")
return
for y in p[x]:
if y and v[y]:
print("Conflict with", v[y])
return
for y in p[x]:
v[y] = x
c[x] = x
print("Success")
def D(x):
if not c[x]:
print("Already off")
return
for y in p[x]:
v[y] = 0
c[x] = 0
print("Success")
n, m = map(int, input().split())
for i in range(2, n+1):
if not b[i]:
for j in range(i, n+1, i):
t[j] += 1
p[j][t[j]] = i
b[j] = 1
for _ in range(m):
s = input().split()
x = int(s[1])
if s[0] == '+':
A(x)
else:
D(x)
``` | 0 | |
767 | A | Snacktower | PROGRAMMING | 1,100 | [
"data structures",
"implementation"
] | null | null | According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents should build a Snacktower of them by placing snacks one on another. Of course, big snacks should be at the bottom of the tower, while small snacks should be at the top.
Years passed, and once different snacks started to fall onto the city, and the residents began to build the Snacktower.
However, they faced some troubles. Each day exactly one snack fell onto the city, but their order was strange. So, at some days the residents weren't able to put the new stack on the top of the Snacktower: they had to wait until all the bigger snacks fell. Of course, in order to not to anger miss Fortune again, the residents placed each snack on the top of the tower immediately as they could do it.
Write a program that models the behavior of Ankh-Morpork residents. | The first line contains single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the total number of snacks.
The second line contains *n* integers, the *i*-th of them equals the size of the snack which fell on the *i*-th day. Sizes are distinct integers from 1 to *n*. | Print *n* lines. On the *i*-th of them print the sizes of the snacks which the residents placed on the top of the Snacktower on the *i*-th day in the order they will do that. If no snack is placed on some day, leave the corresponding line empty. | [
"3\n3 1 2\n",
"5\n4 5 1 2 3\n"
] | [
"3\n \n2 1",
"5 4\n \n \n3 2 1\n"
] | In the example a snack of size 3 fell on the first day, and the residents immediately placed it. On the second day a snack of size 1 fell, and the residents weren't able to place it because they were missing the snack of size 2. On the third day a snack of size 2 fell, and the residents immediately placed it. Right after that they placed the snack of size 1 which had fallen before. | 500 | [
{
"input": "3\n3 1 2",
"output": "3 \n\n2 1 "
},
{
"input": "5\n4 5 1 2 3",
"output": "5 4 \n\n\n3 2 1 "
},
{
"input": "1\n1",
"output": "1 "
},
{
"input": "2\n1 2",
"output": "2 1 "
},
{
"input": "10\n5 1 6 2 8 3 4 10 9 7",
"output": "10 \n9 8 \n7 6 5 4 3 2 1... | 1,601,043,013 | 2,147,483,647 | PyPy 3 | OK | TESTS | 25 | 545 | 11,161,600 | n = int(input())
arr = list(map(int, input().split()))
marked = [None] + [False for i in range(n)]
j = n
for i in range(n):
marked[arr[i]] = True
while marked[j] and j > 0:
print(j, end=" ")
j -= 1
print()
| Title: Snacktower
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
According to an old legeng, a long time ago Ankh-Morpork residents did something wrong to miss Fortune, and she cursed them. She said that at some time *n* snacks of distinct sizes will fall on the city, and the residents should build a Snacktower of them by placing snacks one on another. Of course, big snacks should be at the bottom of the tower, while small snacks should be at the top.
Years passed, and once different snacks started to fall onto the city, and the residents began to build the Snacktower.
However, they faced some troubles. Each day exactly one snack fell onto the city, but their order was strange. So, at some days the residents weren't able to put the new stack on the top of the Snacktower: they had to wait until all the bigger snacks fell. Of course, in order to not to anger miss Fortune again, the residents placed each snack on the top of the tower immediately as they could do it.
Write a program that models the behavior of Ankh-Morpork residents.
Input Specification:
The first line contains single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the total number of snacks.
The second line contains *n* integers, the *i*-th of them equals the size of the snack which fell on the *i*-th day. Sizes are distinct integers from 1 to *n*.
Output Specification:
Print *n* lines. On the *i*-th of them print the sizes of the snacks which the residents placed on the top of the Snacktower on the *i*-th day in the order they will do that. If no snack is placed on some day, leave the corresponding line empty.
Demo Input:
['3\n3 1 2\n', '5\n4 5 1 2 3\n']
Demo Output:
['3\n\xa0\n2 1', '5 4\n\xa0\n\xa0\n3 2 1\n']
Note:
In the example a snack of size 3 fell on the first day, and the residents immediately placed it. On the second day a snack of size 1 fell, and the residents weren't able to place it because they were missing the snack of size 2. On the third day a snack of size 2 fell, and the residents immediately placed it. Right after that they placed the snack of size 1 which had fallen before. | ```python
n = int(input())
arr = list(map(int, input().split()))
marked = [None] + [False for i in range(n)]
j = n
for i in range(n):
marked[arr[i]] = True
while marked[j] and j > 0:
print(j, end=" ")
j -= 1
print()
``` | 3 | |
195 | A | Let's Watch Football | PROGRAMMING | 1,000 | [
"binary search",
"brute force",
"math"
] | null | null | Valeric and Valerko missed the last Euro football game, so they decided to watch the game's key moments on the Net. They want to start watching as soon as possible but the connection speed is too low. If they turn on the video right now, it will "hang up" as the size of data to watch per second will be more than the size of downloaded data per second.
The guys want to watch the whole video without any pauses, so they have to wait some integer number of seconds for a part of the video to download. After this number of seconds passes, they can start watching. Waiting for the whole video to download isn't necessary as the video can download after the guys started to watch.
Let's suppose that video's length is *c* seconds and Valeric and Valerko wait *t* seconds before the watching. Then for any moment of time *t*0, *t*<=≤<=*t*0<=≤<=*c*<=+<=*t*, the following condition must fulfill: the size of data received in *t*0 seconds is not less than the size of data needed to watch *t*0<=-<=*t* seconds of the video.
Of course, the guys want to wait as little as possible, so your task is to find the minimum integer number of seconds to wait before turning the video on. The guys must watch the video without pauses. | The first line contains three space-separated integers *a*, *b* and *c* (1<=≤<=*a*,<=*b*,<=*c*<=≤<=1000,<=*a*<=><=*b*). The first number (*a*) denotes the size of data needed to watch one second of the video. The second number (*b*) denotes the size of data Valeric and Valerko can download from the Net per second. The third number (*c*) denotes the video's length in seconds. | Print a single number — the minimum integer number of seconds that Valeric and Valerko must wait to watch football without pauses. | [
"4 1 1\n",
"10 3 2\n",
"13 12 1\n"
] | [
"3\n",
"5\n",
"1\n"
] | In the first sample video's length is 1 second and it is necessary 4 units of data for watching 1 second of video, so guys should download 4 · 1 = 4 units of data to watch the whole video. The most optimal way is to wait 3 seconds till 3 units of data will be downloaded and then start watching. While guys will be watching video 1 second, one unit of data will be downloaded and Valerik and Valerko will have 4 units of data by the end of watching. Also every moment till the end of video guys will have more data then necessary for watching.
In the second sample guys need 2 · 10 = 20 units of data, so they have to wait 5 seconds and after that they will have 20 units before the second second ends. However, if guys wait 4 seconds, they will be able to watch first second of video without pauses, but they will download 18 units of data by the end of second second and it is less then necessary. | 500 | [
{
"input": "4 1 1",
"output": "3"
},
{
"input": "10 3 2",
"output": "5"
},
{
"input": "13 12 1",
"output": "1"
},
{
"input": "2 1 3",
"output": "3"
},
{
"input": "6 2 4",
"output": "8"
},
{
"input": "5 2 1",
"output": "2"
},
{
"input": "2 1... | 1,602,784,412 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 218 | 0 | if __name__ == "__main__":
a, b, c = map(int, input().split())
res = ((a * c) - (b * c)) / b
if res == int(res):
print(int(res))
else:
print(int(res) + 1)
| Title: Let's Watch Football
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valeric and Valerko missed the last Euro football game, so they decided to watch the game's key moments on the Net. They want to start watching as soon as possible but the connection speed is too low. If they turn on the video right now, it will "hang up" as the size of data to watch per second will be more than the size of downloaded data per second.
The guys want to watch the whole video without any pauses, so they have to wait some integer number of seconds for a part of the video to download. After this number of seconds passes, they can start watching. Waiting for the whole video to download isn't necessary as the video can download after the guys started to watch.
Let's suppose that video's length is *c* seconds and Valeric and Valerko wait *t* seconds before the watching. Then for any moment of time *t*0, *t*<=≤<=*t*0<=≤<=*c*<=+<=*t*, the following condition must fulfill: the size of data received in *t*0 seconds is not less than the size of data needed to watch *t*0<=-<=*t* seconds of the video.
Of course, the guys want to wait as little as possible, so your task is to find the minimum integer number of seconds to wait before turning the video on. The guys must watch the video without pauses.
Input Specification:
The first line contains three space-separated integers *a*, *b* and *c* (1<=≤<=*a*,<=*b*,<=*c*<=≤<=1000,<=*a*<=><=*b*). The first number (*a*) denotes the size of data needed to watch one second of the video. The second number (*b*) denotes the size of data Valeric and Valerko can download from the Net per second. The third number (*c*) denotes the video's length in seconds.
Output Specification:
Print a single number — the minimum integer number of seconds that Valeric and Valerko must wait to watch football without pauses.
Demo Input:
['4 1 1\n', '10 3 2\n', '13 12 1\n']
Demo Output:
['3\n', '5\n', '1\n']
Note:
In the first sample video's length is 1 second and it is necessary 4 units of data for watching 1 second of video, so guys should download 4 · 1 = 4 units of data to watch the whole video. The most optimal way is to wait 3 seconds till 3 units of data will be downloaded and then start watching. While guys will be watching video 1 second, one unit of data will be downloaded and Valerik and Valerko will have 4 units of data by the end of watching. Also every moment till the end of video guys will have more data then necessary for watching.
In the second sample guys need 2 · 10 = 20 units of data, so they have to wait 5 seconds and after that they will have 20 units before the second second ends. However, if guys wait 4 seconds, they will be able to watch first second of video without pauses, but they will download 18 units of data by the end of second second and it is less then necessary. | ```python
if __name__ == "__main__":
a, b, c = map(int, input().split())
res = ((a * c) - (b * c)) / b
if res == int(res):
print(int(res))
else:
print(int(res) + 1)
``` | 3 | |
272 | A | Dima and Friends | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the apartment, the friends want to play a counting-out game. First, all the guys stand in a circle, and then each of them shows some number of fingers on one hand (one to five), and then the boys count in a circle, starting from Dima, the number of people, respective to the total number of fingers shown. The person on who the countdown stops will clean the apartment.
For example, if Dima and one of his friends played hide and seek, and 7 fingers were shown during the counting-out, then Dima would clean the place. If there were 2 or say, 8 fingers shown, then his friend would clean the place.
Dima knows how many fingers each of his friends will show during the counting-out. Now he is interested in the number of ways to show some number of fingers on one hand (one to five), so that he did not have to clean the place. Help Dima. | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of Dima's friends. Dima himself isn't considered to be his own friend. The second line contains *n* positive integers, not exceeding 5, representing, how many fingers the Dima's friends will show.
The numbers in the lines are separated by a single space. | In a single line print the answer to the problem. | [
"1\n1\n",
"1\n2\n",
"2\n3 5\n"
] | [
"3\n",
"2\n",
"3\n"
] | In the first sample Dima can show 1, 3 or 5 fingers. If Dima shows 3 fingers, then the counting-out will go like that: Dima, his friend, Dima, his friend.
In the second sample Dima can show 2 or 4 fingers. | 500 | [
{
"input": "1\n1",
"output": "3"
},
{
"input": "1\n2",
"output": "2"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "1\n5",
"output": "3"
},
{
"input": "5\n4 4 3 5 1",
"output": "4"
},
{
"input": "... | 1,591,953,103 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 186 | 0 | n=int(input())
a=list(map(int,input().split(" ")))
b=sum(a)
c=n+1
if b==c:
print(2)
elif c>b:
print(3)
else:
e=(b%c)
if e==c:
print(e)
elif e>c:
print(3)
else:
f=c-e
g=f+2
print(g) | Title: Dima and Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the apartment, the friends want to play a counting-out game. First, all the guys stand in a circle, and then each of them shows some number of fingers on one hand (one to five), and then the boys count in a circle, starting from Dima, the number of people, respective to the total number of fingers shown. The person on who the countdown stops will clean the apartment.
For example, if Dima and one of his friends played hide and seek, and 7 fingers were shown during the counting-out, then Dima would clean the place. If there were 2 or say, 8 fingers shown, then his friend would clean the place.
Dima knows how many fingers each of his friends will show during the counting-out. Now he is interested in the number of ways to show some number of fingers on one hand (one to five), so that he did not have to clean the place. Help Dima.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of Dima's friends. Dima himself isn't considered to be his own friend. The second line contains *n* positive integers, not exceeding 5, representing, how many fingers the Dima's friends will show.
The numbers in the lines are separated by a single space.
Output Specification:
In a single line print the answer to the problem.
Demo Input:
['1\n1\n', '1\n2\n', '2\n3 5\n']
Demo Output:
['3\n', '2\n', '3\n']
Note:
In the first sample Dima can show 1, 3 or 5 fingers. If Dima shows 3 fingers, then the counting-out will go like that: Dima, his friend, Dima, his friend.
In the second sample Dima can show 2 or 4 fingers. | ```python
n=int(input())
a=list(map(int,input().split(" ")))
b=sum(a)
c=n+1
if b==c:
print(2)
elif c>b:
print(3)
else:
e=(b%c)
if e==c:
print(e)
elif e>c:
print(3)
else:
f=c-e
g=f+2
print(g)
``` | 0 | |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square. | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,697,158,240 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 46 | 0 | n,m,a=map(int,input().split())
if (n%a==0):
X=n//a
else:
X=(n//a)+1
if (m%a==0):
Y=m//a
else:
Y=(m//a)+1
print(X*Y) | Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square.
Input Specification:
The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109).
Output Specification:
Write the needed number of flagstones.
Demo Input:
['6 6 4\n']
Demo Output:
['4\n']
Note:
none | ```python
n,m,a=map(int,input().split())
if (n%a==0):
X=n//a
else:
X=(n//a)+1
if (m%a==0):
Y=m//a
else:
Y=(m//a)+1
print(X*Y)
``` | 3.977 |
525 | C | Ilya and Sticks | PROGRAMMING | 1,600 | [
"greedy",
"math",
"sortings"
] | null | null | In the evening, after the contest Ilya was bored, and he really felt like maximizing. He remembered that he had a set of *n* sticks and an instrument. Each stick is characterized by its length *l**i*.
Ilya decided to make a rectangle from the sticks. And due to his whim, he decided to make rectangles in such a way that maximizes their total area. Each stick is used in making at most one rectangle, it is possible that some of sticks remain unused. Bending sticks is not allowed.
Sticks with lengths *a*1, *a*2, *a*3 and *a*4 can make a rectangle if the following properties are observed:
- *a*1<=≤<=*a*2<=≤<=*a*3<=≤<=*a*4 - *a*1<==<=*a*2 - *a*3<==<=*a*4
A rectangle can be made of sticks with lengths of, for example, 3 3 3 3 or 2 2 4 4. A rectangle cannot be made of, for example, sticks 5 5 5 7.
Ilya also has an instrument which can reduce the length of the sticks. The sticks are made of a special material, so the length of each stick can be reduced by at most one. For example, a stick with length 5 can either stay at this length or be transformed into a stick of length 4.
You have to answer the question — what maximum total area of the rectangles can Ilya get with a file if makes rectangles from the available sticks? | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=105) — the number of the available sticks.
The second line of the input contains *n* positive integers *l**i* (2<=≤<=*l**i*<=≤<=106) — the lengths of the sticks. | The first line of the output must contain a single non-negative integer — the maximum total area of the rectangles that Ilya can make from the available sticks. | [
"4\n2 4 4 2\n",
"4\n2 2 3 5\n",
"4\n100003 100004 100005 100006\n"
] | [
"8\n",
"0\n",
"10000800015\n"
] | none | 1,000 | [
{
"input": "4\n2 4 4 2",
"output": "8"
},
{
"input": "4\n2 2 3 5",
"output": "0"
},
{
"input": "4\n100003 100004 100005 100006",
"output": "10000800015"
},
{
"input": "8\n5 3 3 3 3 4 4 4",
"output": "25"
},
{
"input": "10\n123 124 123 124 2 2 2 2 9 9",
"output... | 1,427,390,670 | 3,270 | Python 3 | TIME_LIMIT_EXCEEDED | PRETESTS | 7 | 2,000 | 7,680,000 | count = int(input())
sticks = [int(s) for s in input().split()]
sticks.sort()
result = 0
while len(sticks) >= 4:
i = 1
while i < len(sticks) - 1:
if sticks[i] - sticks[i - 1] >= 2 and sticks[i + 1] - sticks[i] >= 2:
sticks.pop(i)
else:
i += 1
i = len(sticks) - 1
while i > 3 and sticks[i] - sticks[i - 1] >= 2:
i -= 1
j = i - 2
while j > 1 and sticks[j] - sticks[j - 1] >= 2:
j -= 1
if sticks[i] - sticks[i - 1] < 2 and sticks[j] - sticks[j - 1] < 2:
result += sticks[i - 1] * sticks[j - 1]
sticks.pop(i)
sticks.pop(i - 1)
sticks.pop(j)
sticks.pop(j - 1)
else:
break
print(result) | Title: Ilya and Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In the evening, after the contest Ilya was bored, and he really felt like maximizing. He remembered that he had a set of *n* sticks and an instrument. Each stick is characterized by its length *l**i*.
Ilya decided to make a rectangle from the sticks. And due to his whim, he decided to make rectangles in such a way that maximizes their total area. Each stick is used in making at most one rectangle, it is possible that some of sticks remain unused. Bending sticks is not allowed.
Sticks with lengths *a*1, *a*2, *a*3 and *a*4 can make a rectangle if the following properties are observed:
- *a*1<=≤<=*a*2<=≤<=*a*3<=≤<=*a*4 - *a*1<==<=*a*2 - *a*3<==<=*a*4
A rectangle can be made of sticks with lengths of, for example, 3 3 3 3 or 2 2 4 4. A rectangle cannot be made of, for example, sticks 5 5 5 7.
Ilya also has an instrument which can reduce the length of the sticks. The sticks are made of a special material, so the length of each stick can be reduced by at most one. For example, a stick with length 5 can either stay at this length or be transformed into a stick of length 4.
You have to answer the question — what maximum total area of the rectangles can Ilya get with a file if makes rectangles from the available sticks?
Input Specification:
The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=105) — the number of the available sticks.
The second line of the input contains *n* positive integers *l**i* (2<=≤<=*l**i*<=≤<=106) — the lengths of the sticks.
Output Specification:
The first line of the output must contain a single non-negative integer — the maximum total area of the rectangles that Ilya can make from the available sticks.
Demo Input:
['4\n2 4 4 2\n', '4\n2 2 3 5\n', '4\n100003 100004 100005 100006\n']
Demo Output:
['8\n', '0\n', '10000800015\n']
Note:
none | ```python
count = int(input())
sticks = [int(s) for s in input().split()]
sticks.sort()
result = 0
while len(sticks) >= 4:
i = 1
while i < len(sticks) - 1:
if sticks[i] - sticks[i - 1] >= 2 and sticks[i + 1] - sticks[i] >= 2:
sticks.pop(i)
else:
i += 1
i = len(sticks) - 1
while i > 3 and sticks[i] - sticks[i - 1] >= 2:
i -= 1
j = i - 2
while j > 1 and sticks[j] - sticks[j - 1] >= 2:
j -= 1
if sticks[i] - sticks[i - 1] < 2 and sticks[j] - sticks[j - 1] < 2:
result += sticks[i - 1] * sticks[j - 1]
sticks.pop(i)
sticks.pop(i - 1)
sticks.pop(j)
sticks.pop(j - 1)
else:
break
print(result)
``` | 0 | |
82 | A | Double Cola | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | A. Double Cola | 1 | 256 | Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, drinks it and gets to the end of the queue as two Leonards, and so on. This process continues ad infinitum.
For example, Penny drinks the third can of cola and the queue will look like this: Rajesh, Howard, Sheldon, Sheldon, Leonard, Leonard, Penny, Penny.
Write a program that will print the name of a man who will drink the *n*-th can.
Note that in the very beginning the queue looks like that: Sheldon, Leonard, Penny, Rajesh, Howard. The first person is Sheldon. | The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers. | Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially. | [
"1\n",
"6\n",
"1802\n"
] | [
"Sheldon\n",
"Sheldon\n",
"Penny\n"
] | none | 500 | [
{
"input": "1",
"output": "Sheldon"
},
{
"input": "6",
"output": "Sheldon"
},
{
"input": "1802",
"output": "Penny"
},
{
"input": "1",
"output": "Sheldon"
},
{
"input": "2",
"output": "Leonard"
},
{
"input": "3",
"output": "Penny"
},
{
"inpu... | 1,544,368,857 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 109 | 0 | names = ['Sheldon','Leonard','Penny','Rajesh','Howard']
n = 5
prev = 0
inp = int(input())
i = 1
while n < 10**10:
if inp <= n:
break
prev = n
n = n+5*2**i
i += 1
incr = (n-prev)/5
resInd = 0
while True:
prev += incr
if inp <= prev:
break
resInd += 1
print(names[resInd]) | Title: Double Cola
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sheldon, Leonard, Penny, Rajesh and Howard are in the queue for a "Double Cola" drink vending machine; there are no other people in the queue. The first one in the queue (Sheldon) buys a can, drinks it and doubles! The resulting two Sheldons go to the end of the queue. Then the next in the queue (Leonard) buys a can, drinks it and gets to the end of the queue as two Leonards, and so on. This process continues ad infinitum.
For example, Penny drinks the third can of cola and the queue will look like this: Rajesh, Howard, Sheldon, Sheldon, Leonard, Leonard, Penny, Penny.
Write a program that will print the name of a man who will drink the *n*-th can.
Note that in the very beginning the queue looks like that: Sheldon, Leonard, Penny, Rajesh, Howard. The first person is Sheldon.
Input Specification:
The input data consist of a single integer *n* (1<=≤<=*n*<=≤<=109).
It is guaranteed that the pretests check the spelling of all the five names, that is, that they contain all the five possible answers.
Output Specification:
Print the single line — the name of the person who drinks the *n*-th can of cola. The cans are numbered starting from 1. Please note that you should spell the names like this: "Sheldon", "Leonard", "Penny", "Rajesh", "Howard" (without the quotes). In that order precisely the friends are in the queue initially.
Demo Input:
['1\n', '6\n', '1802\n']
Demo Output:
['Sheldon\n', 'Sheldon\n', 'Penny\n']
Note:
none | ```python
names = ['Sheldon','Leonard','Penny','Rajesh','Howard']
n = 5
prev = 0
inp = int(input())
i = 1
while n < 10**10:
if inp <= n:
break
prev = n
n = n+5*2**i
i += 1
incr = (n-prev)/5
resInd = 0
while True:
prev += incr
if inp <= prev:
break
resInd += 1
print(names[resInd])
``` | 3.9455 |
461 | A | Appleman and Toastman | PROGRAMMING | 1,200 | [
"greedy",
"sortings"
] | null | null | Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman. - Each time Appleman gets a group consisting of a single number, he throws this group out. Each time Appleman gets a group consisting of more than one number, he splits the group into two non-empty groups (he can do it in any way) and gives each of them to Toastman.
After guys complete all the tasks they look at the score value. What is the maximum possible value of score they can get? | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=106) — the initial group that is given to Toastman. | Print a single integer — the largest possible score. | [
"3\n3 1 5\n",
"1\n10\n"
] | [
"26\n",
"10\n"
] | Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and gives the group to Appleman (he will throw it out). When Toastman receives group [3, 5], he adds 8 to the score and gives the group to Appleman. Appleman splits [3, 5] in the only possible way: [5] and [3]. Then he gives both groups to Toastman. When Toastman receives [5], he adds 5 to the score and gives the group to Appleman (he will throws it out). When Toastman receives [3], he adds 3 to the score and gives the group to Appleman (he will throws it out). Finally Toastman have added 9 + 1 + 8 + 5 + 3 = 26 to the score. This is the optimal sequence of actions. | 500 | [
{
"input": "3\n3 1 5",
"output": "26"
},
{
"input": "1\n10",
"output": "10"
},
{
"input": "10\n8 10 2 5 6 2 4 7 2 1",
"output": "376"
},
{
"input": "10\n171308 397870 724672 431255 228496 892002 542924 718337 888642 161821",
"output": "40204082"
},
{
"input": "10\... | 1,512,549,018 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 5,529,600 | n = int(input())
L = input()
L = L.split()
L.sort(reverse = True)
total = 0
if n == 1:
total = int(L[0])
else:
total = total + n * int(L[0])
for i in range(1, n):
total = total + (n + 1 - i) * int(L[i])
print(total)
| Title: Appleman and Toastman
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman. - Each time Appleman gets a group consisting of a single number, he throws this group out. Each time Appleman gets a group consisting of more than one number, he splits the group into two non-empty groups (he can do it in any way) and gives each of them to Toastman.
After guys complete all the tasks they look at the score value. What is the maximum possible value of score they can get?
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=106) — the initial group that is given to Toastman.
Output Specification:
Print a single integer — the largest possible score.
Demo Input:
['3\n3 1 5\n', '1\n10\n']
Demo Output:
['26\n', '10\n']
Note:
Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and gives the group to Appleman (he will throw it out). When Toastman receives group [3, 5], he adds 8 to the score and gives the group to Appleman. Appleman splits [3, 5] in the only possible way: [5] and [3]. Then he gives both groups to Toastman. When Toastman receives [5], he adds 5 to the score and gives the group to Appleman (he will throws it out). When Toastman receives [3], he adds 3 to the score and gives the group to Appleman (he will throws it out). Finally Toastman have added 9 + 1 + 8 + 5 + 3 = 26 to the score. This is the optimal sequence of actions. | ```python
n = int(input())
L = input()
L = L.split()
L.sort(reverse = True)
total = 0
if n == 1:
total = int(L[0])
else:
total = total + n * int(L[0])
for i in range(1, n):
total = total + (n + 1 - i) * int(L[i])
print(total)
``` | 0 | |
894 | A | QAQ | PROGRAMMING | 800 | [
"brute force",
"dp"
] | null | null | "QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ" in the string (Diamond is so cute!).
Bort wants to know how many subsequences "QAQ" are in the string Diamond has given. Note that the letters "QAQ" don't have to be consecutive, but the order of letters should be exact. | The only line contains a string of length *n* (1<=≤<=*n*<=≤<=100). It's guaranteed that the string only contains uppercase English letters. | Print a single integer — the number of subsequences "QAQ" in the string. | [
"QAQAQYSYIOIWIN\n",
"QAQQQZZYNOIWIN\n"
] | [
"4\n",
"3\n"
] | In the first example there are 4 subsequences "QAQ": "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN". | 500 | [
{
"input": "QAQAQYSYIOIWIN",
"output": "4"
},
{
"input": "QAQQQZZYNOIWIN",
"output": "3"
},
{
"input": "QA",
"output": "0"
},
{
"input": "IAQVAQZLQBQVQFTQQQADAQJA",
"output": "24"
},
{
"input": "QQAAQASGAYAAAAKAKAQIQEAQAIAAIAQQQQQ",
"output": "378"
},
{
... | 1,671,000,188 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 46 | 0 | t=input()
t=t[:t.rfind('Q')+1]
n=len(t)
count=0
for i in range(n):
if(t[i]!='Q'):
continue
else:
for j in range(i+1,n):
if t[j]=='A':
for k in range(j+1,n):
if(t[k]=='Q'):
count+=1
print(count) | Title: QAQ
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length *n*. There is a great number of "QAQ" in the string (Diamond is so cute!).
Bort wants to know how many subsequences "QAQ" are in the string Diamond has given. Note that the letters "QAQ" don't have to be consecutive, but the order of letters should be exact.
Input Specification:
The only line contains a string of length *n* (1<=≤<=*n*<=≤<=100). It's guaranteed that the string only contains uppercase English letters.
Output Specification:
Print a single integer — the number of subsequences "QAQ" in the string.
Demo Input:
['QAQAQYSYIOIWIN\n', 'QAQQQZZYNOIWIN\n']
Demo Output:
['4\n', '3\n']
Note:
In the first example there are 4 subsequences "QAQ": "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN". | ```python
t=input()
t=t[:t.rfind('Q')+1]
n=len(t)
count=0
for i in range(n):
if(t[i]!='Q'):
continue
else:
for j in range(i+1,n):
if t[j]=='A':
for k in range(j+1,n):
if(t[k]=='Q'):
count+=1
print(count)
``` | 3 | |
276 | A | Lunch Rush | PROGRAMMING | 900 | [
"implementation"
] | null | null | Having written another programming contest, three Rabbits decided to grab some lunch. The coach gave the team exactly *k* time units for the lunch break.
The Rabbits have a list of *n* restaurants to lunch in: the *i*-th restaurant is characterized by two integers *f**i* and *t**i*. Value *t**i* shows the time the Rabbits need to lunch in the *i*-th restaurant. If time *t**i* exceeds the time *k* that the coach has given for the lunch break, then the Rabbits' joy from lunching in this restaurant will equal *f**i*<=-<=(*t**i*<=-<=*k*). Otherwise, the Rabbits get exactly *f**i* units of joy.
Your task is to find the value of the maximum joy the Rabbits can get from the lunch, depending on the restaurant. The Rabbits must choose exactly one restaurant to lunch in. Note that the joy value isn't necessarily a positive value. | The first line contains two space-separated integers — *n* (1<=≤<=*n*<=≤<=104) and *k* (1<=≤<=*k*<=≤<=109) — the number of restaurants in the Rabbits' list and the time the coach has given them to lunch, correspondingly. Each of the next *n* lines contains two space-separated integers — *f**i* (1<=≤<=*f**i*<=≤<=109) and *t**i* (1<=≤<=*t**i*<=≤<=109) — the characteristics of the *i*-th restaurant. | In a single line print a single integer — the maximum joy value that the Rabbits will get from the lunch. | [
"2 5\n3 3\n4 5\n",
"4 6\n5 8\n3 6\n2 3\n2 2\n",
"1 5\n1 7\n"
] | [
"4\n",
"3\n",
"-1\n"
] | none | 500 | [
{
"input": "2 5\n3 3\n4 5",
"output": "4"
},
{
"input": "4 6\n5 8\n3 6\n2 3\n2 2",
"output": "3"
},
{
"input": "1 5\n1 7",
"output": "-1"
},
{
"input": "4 9\n10 13\n4 18\n13 3\n10 6",
"output": "13"
},
{
"input": "1 1\n1 1000000000",
"output": "-999999998"
}... | 1,639,477,376 | 2,147,483,647 | PyPy 3 | OK | TESTS | 35 | 372 | 3,891,200 | n, k = map(int, input().split())
pleasure = []
for i in range(n):
f, t = map(int, input().split())
res = 0
if t > k:
res = f - (t - k)
else:
res = f
pleasure.append(res)
print(max(pleasure))
| Title: Lunch Rush
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Having written another programming contest, three Rabbits decided to grab some lunch. The coach gave the team exactly *k* time units for the lunch break.
The Rabbits have a list of *n* restaurants to lunch in: the *i*-th restaurant is characterized by two integers *f**i* and *t**i*. Value *t**i* shows the time the Rabbits need to lunch in the *i*-th restaurant. If time *t**i* exceeds the time *k* that the coach has given for the lunch break, then the Rabbits' joy from lunching in this restaurant will equal *f**i*<=-<=(*t**i*<=-<=*k*). Otherwise, the Rabbits get exactly *f**i* units of joy.
Your task is to find the value of the maximum joy the Rabbits can get from the lunch, depending on the restaurant. The Rabbits must choose exactly one restaurant to lunch in. Note that the joy value isn't necessarily a positive value.
Input Specification:
The first line contains two space-separated integers — *n* (1<=≤<=*n*<=≤<=104) and *k* (1<=≤<=*k*<=≤<=109) — the number of restaurants in the Rabbits' list and the time the coach has given them to lunch, correspondingly. Each of the next *n* lines contains two space-separated integers — *f**i* (1<=≤<=*f**i*<=≤<=109) and *t**i* (1<=≤<=*t**i*<=≤<=109) — the characteristics of the *i*-th restaurant.
Output Specification:
In a single line print a single integer — the maximum joy value that the Rabbits will get from the lunch.
Demo Input:
['2 5\n3 3\n4 5\n', '4 6\n5 8\n3 6\n2 3\n2 2\n', '1 5\n1 7\n']
Demo Output:
['4\n', '3\n', '-1\n']
Note:
none | ```python
n, k = map(int, input().split())
pleasure = []
for i in range(n):
f, t = map(int, input().split())
res = 0
if t > k:
res = f - (t - k)
else:
res = f
pleasure.append(res)
print(max(pleasure))
``` | 3 | |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a player gains or loses a particular number of points. In the course of the game the number of points is registered in the line "name score", where name is a player's name, and score is the number of points gained in this round, which is an integer number. If score is negative, this means that the player has lost in the round. So, if two or more players have the maximum number of points (say, it equals to *m*) at the end of the game, than wins the one of them who scored at least *m* points first. Initially each player has 0 points. It's guaranteed that at the end of the game at least one player has a positive number of points. | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is an integer number between -1000 and 1000, inclusive. | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,457,559,431 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 124 | 0 | names = []
players = {}
rounds = int(input())
win = ["", 0]
for i in range(rounds):
ns = input()
name = ns.split()[0]
score = int(ns.split()[1])
if players.get(name):
players[name] += score
if score < 0 and win[0] == name:
win[1] = 0
for k in players.keys():
if players[k] > win[1]:
win[0] = k
win[1] = players[k]
if players[name] > win[1]:
win[0] = name
win[1] = players[name]
else:
players.update({name: score})
if players[name] > win[1]:
win[0] = name
win[1] = score
print(win[0])
| Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a player gains or loses a particular number of points. In the course of the game the number of points is registered in the line "name score", where name is a player's name, and score is the number of points gained in this round, which is an integer number. If score is negative, this means that the player has lost in the round. So, if two or more players have the maximum number of points (say, it equals to *m*) at the end of the game, than wins the one of them who scored at least *m* points first. Initially each player has 0 points. It's guaranteed that at the end of the game at least one player has a positive number of points.
Input Specification:
The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is an integer number between -1000 and 1000, inclusive.
Output Specification:
Print the name of the winner.
Demo Input:
['3\nmike 3\nandrew 5\nmike 2\n', '3\nandrew 3\nandrew 2\nmike 5\n']
Demo Output:
['andrew\n', 'andrew\n']
Note:
none | ```python
names = []
players = {}
rounds = int(input())
win = ["", 0]
for i in range(rounds):
ns = input()
name = ns.split()[0]
score = int(ns.split()[1])
if players.get(name):
players[name] += score
if score < 0 and win[0] == name:
win[1] = 0
for k in players.keys():
if players[k] > win[1]:
win[0] = k
win[1] = players[k]
if players[name] > win[1]:
win[0] = name
win[1] = players[name]
else:
players.update({name: score})
if players[name] > win[1]:
win[0] = name
win[1] = score
print(win[0])
``` | 0 |
96 | A | Football | PROGRAMMING | 900 | [
"implementation",
"strings"
] | A. Football | 2 | 256 | Petya loves football very much. One day, as he was watching a football match, he was writing the players' current positions on a piece of paper. To simplify the situation he depicted it as a string consisting of zeroes and ones. A zero corresponds to players of one team; a one corresponds to players of another team. If there are at least 7 players of some team standing one after another, then the situation is considered dangerous. For example, the situation 00100110111111101 is dangerous and 11110111011101 is not. You are given the current situation. Determine whether it is dangerous or not. | The first input line contains a non-empty string consisting of characters "0" and "1", which represents players. The length of the string does not exceed 100 characters. There's at least one player from each team present on the field. | Print "YES" if the situation is dangerous. Otherwise, print "NO". | [
"001001\n",
"1000000001\n"
] | [
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "001001",
"output": "NO"
},
{
"input": "1000000001",
"output": "YES"
},
{
"input": "00100110111111101",
"output": "YES"
},
{
"input": "11110111111111111",
"output": "YES"
},
{
"input": "01",
"output": "NO"
},
{
"input": "10100101",
"outp... | 1,671,954,566 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | s=input()
ic=1
oc=1
l=len(s)
for i in range(1,l):
if(s[i-1]==s[i]):
if(s[i]==1):
ic=ic+1
else:
oc=oc+1
print(ic,oc)
if(ic>=7 or oc>=7):
print("YES")
else:
print("NO") | Title: Football
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya loves football very much. One day, as he was watching a football match, he was writing the players' current positions on a piece of paper. To simplify the situation he depicted it as a string consisting of zeroes and ones. A zero corresponds to players of one team; a one corresponds to players of another team. If there are at least 7 players of some team standing one after another, then the situation is considered dangerous. For example, the situation 00100110111111101 is dangerous and 11110111011101 is not. You are given the current situation. Determine whether it is dangerous or not.
Input Specification:
The first input line contains a non-empty string consisting of characters "0" and "1", which represents players. The length of the string does not exceed 100 characters. There's at least one player from each team present on the field.
Output Specification:
Print "YES" if the situation is dangerous. Otherwise, print "NO".
Demo Input:
['001001\n', '1000000001\n']
Demo Output:
['NO\n', 'YES\n']
Note:
none | ```python
s=input()
ic=1
oc=1
l=len(s)
for i in range(1,l):
if(s[i-1]==s[i]):
if(s[i]==1):
ic=ic+1
else:
oc=oc+1
print(ic,oc)
if(ic>=7 or oc>=7):
print("YES")
else:
print("NO")
``` | 0 |
208 | A | Dubstep | PROGRAMMING | 900 | [
"strings"
] | null | null | Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain number of words "WUB" before the first word of the song (the number may be zero), after the last word (the number may be zero), and between words (at least one between any pair of neighbouring words), and then the boy glues together all the words, including "WUB", in one string and plays the song at the club.
For example, a song with words "I AM X" can transform into a dubstep remix as "WUBWUBIWUBAMWUBWUBX" and cannot transform into "WUBWUBIAMWUBX".
Recently, Petya has heard Vasya's new dubstep track, but since he isn't into modern music, he decided to find out what was the initial song that Vasya remixed. Help Petya restore the original song. | The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the song had at least one word. | Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space. | [
"WUBWUBABCWUB\n",
"WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB\n"
] | [
"ABC ",
"WE ARE THE CHAMPIONS MY FRIEND "
] | In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE" and "THE" — between them Vasya added two "WUB". | 500 | [
{
"input": "WUBWUBABCWUB",
"output": "ABC "
},
{
"input": "WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB",
"output": "WE ARE THE CHAMPIONS MY FRIEND "
},
{
"input": "WUBWUBWUBSR",
"output": "SR "
},
{
"input": "RWUBWUBWUBLWUB",
"output": "R L "
},
{
"input": "... | 1,695,201,007 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 0 | x=input();
z=x.split("WUB")
x=""
for i in z:
if i!=" ":
x+=i+" "
print(x[1::]) | Title: Dubstep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain number of words "WUB" before the first word of the song (the number may be zero), after the last word (the number may be zero), and between words (at least one between any pair of neighbouring words), and then the boy glues together all the words, including "WUB", in one string and plays the song at the club.
For example, a song with words "I AM X" can transform into a dubstep remix as "WUBWUBIWUBAMWUBWUBX" and cannot transform into "WUBWUBIAMWUBX".
Recently, Petya has heard Vasya's new dubstep track, but since he isn't into modern music, he decided to find out what was the initial song that Vasya remixed. Help Petya restore the original song.
Input Specification:
The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the song had at least one word.
Output Specification:
Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space.
Demo Input:
['WUBWUBABCWUB\n', 'WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB\n']
Demo Output:
['ABC ', 'WE ARE THE CHAMPIONS MY FRIEND ']
Note:
In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE" and "THE" — between them Vasya added two "WUB". | ```python
x=input();
z=x.split("WUB")
x=""
for i in z:
if i!=" ":
x+=i+" "
print(x[1::])
``` | 0 | |
987 | A | Infinity Gauntlet | PROGRAMMING | 800 | [
"implementation"
] | null | null | You took a peek on Thanos wearing Infinity Gauntlet. In the Gauntlet there is a place for six Infinity Gems:
- the Power Gem of purple color, - the Time Gem of green color, - the Space Gem of blue color, - the Soul Gem of orange color, - the Reality Gem of red color, - the Mind Gem of yellow color.
Using colors of Gems you saw in the Gauntlet determine the names of absent Gems. | In the first line of input there is one integer $n$ ($0 \le n \le 6$) — the number of Gems in Infinity Gauntlet.
In next $n$ lines there are colors of Gems you saw. Words used for colors are: purple, green, blue, orange, red, yellow. It is guaranteed that all the colors are distinct. All colors are given in lowercase English letters. | In the first line output one integer $m$ ($0 \le m \le 6$) — the number of absent Gems.
Then in $m$ lines print the names of absent Gems, each on its own line. Words used for names are: Power, Time, Space, Soul, Reality, Mind. Names can be printed in any order. Keep the first letter uppercase, others lowercase. | [
"4\nred\npurple\nyellow\norange\n",
"0\n"
] | [
"2\nSpace\nTime\n",
"6\nTime\nMind\nSoul\nPower\nReality\nSpace\n"
] | In the first sample Thanos already has Reality, Power, Mind and Soul Gems, so he needs two more: Time and Space.
In the second sample Thanos doesn't have any Gems, so he needs all six. | 500 | [
{
"input": "4\nred\npurple\nyellow\norange",
"output": "2\nSpace\nTime"
},
{
"input": "0",
"output": "6\nMind\nSpace\nPower\nTime\nReality\nSoul"
},
{
"input": "6\npurple\nblue\nyellow\nred\ngreen\norange",
"output": "0"
},
{
"input": "1\npurple",
"output": "5\nTime\nReal... | 1,647,279,742 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 64 | 62 | 0 | n=int(input())
gems={'purple':'Power','green':'Time','blue':'Space','orange':'Soul','red':'Reality','yellow':'Mind'}
k=[]
for i in range(n):
g=input()
k.append(g)
if len(set(k))==n:
print(6-n)
for i in gems.keys():
if i not in k:
print(gems.get(i))
| Title: Infinity Gauntlet
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You took a peek on Thanos wearing Infinity Gauntlet. In the Gauntlet there is a place for six Infinity Gems:
- the Power Gem of purple color, - the Time Gem of green color, - the Space Gem of blue color, - the Soul Gem of orange color, - the Reality Gem of red color, - the Mind Gem of yellow color.
Using colors of Gems you saw in the Gauntlet determine the names of absent Gems.
Input Specification:
In the first line of input there is one integer $n$ ($0 \le n \le 6$) — the number of Gems in Infinity Gauntlet.
In next $n$ lines there are colors of Gems you saw. Words used for colors are: purple, green, blue, orange, red, yellow. It is guaranteed that all the colors are distinct. All colors are given in lowercase English letters.
Output Specification:
In the first line output one integer $m$ ($0 \le m \le 6$) — the number of absent Gems.
Then in $m$ lines print the names of absent Gems, each on its own line. Words used for names are: Power, Time, Space, Soul, Reality, Mind. Names can be printed in any order. Keep the first letter uppercase, others lowercase.
Demo Input:
['4\nred\npurple\nyellow\norange\n', '0\n']
Demo Output:
['2\nSpace\nTime\n', '6\nTime\nMind\nSoul\nPower\nReality\nSpace\n']
Note:
In the first sample Thanos already has Reality, Power, Mind and Soul Gems, so he needs two more: Time and Space.
In the second sample Thanos doesn't have any Gems, so he needs all six. | ```python
n=int(input())
gems={'purple':'Power','green':'Time','blue':'Space','orange':'Soul','red':'Reality','yellow':'Mind'}
k=[]
for i in range(n):
g=input()
k.append(g)
if len(set(k))==n:
print(6-n)
for i in gems.keys():
if i not in k:
print(gems.get(i))
``` | 3 | |
768 | A | Oath of the Night's Watch | PROGRAMMING | 900 | [
"constructive algorithms",
"sortings"
] | null | null | "Night gathers, and now my watch begins. It shall not end until my death. I shall take no wife, hold no lands, father no children. I shall wear no crowns and win no glory. I shall live and die at my post. I am the sword in the darkness. I am the watcher on the walls. I am the shield that guards the realms of men. I pledge my life and honor to the Night's Watch, for this night and all the nights to come." — The Night's Watch oath.
With that begins the watch of Jon Snow. He is assigned the task to support the stewards.
This time he has *n* stewards with him whom he has to provide support. Each steward has his own strength. Jon Snow likes to support a steward only if there exists at least one steward who has strength strictly less than him and at least one steward who has strength strictly greater than him.
Can you find how many stewards will Jon support? | First line consists of a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of stewards with Jon Snow.
Second line consists of *n* space separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) representing the values assigned to the stewards. | Output a single integer representing the number of stewards which Jon will feed. | [
"2\n1 5\n",
"3\n1 2 5\n"
] | [
"0",
"1"
] | In the first sample, Jon Snow cannot support steward with strength 1 because there is no steward with strength less than 1 and he cannot support steward with strength 5 because there is no steward with strength greater than 5.
In the second sample, Jon Snow can support steward with strength 2 because there are stewards with strength less than 2 and greater than 2. | 500 | [
{
"input": "2\n1 5",
"output": "0"
},
{
"input": "3\n1 2 5",
"output": "1"
},
{
"input": "4\n1 2 3 4",
"output": "2"
},
{
"input": "8\n7 8 9 4 5 6 1 2",
"output": "6"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n100",
"output": "0"
},
... | 1,663,878,694 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 88 | 93 | 13,516,800 | N = int(input())
arr = list(map(int, input().split()))
if N < 3:
print(0)
else:
arr.sort()
f = arr[0]
l = arr[-1]
if f == l:
print(0)
else:
cnt = 0
for i in range(1, len(arr)-1):
if arr[i] != f and arr[i] != l:
cnt += 1
print(cnt) | Title: Oath of the Night's Watch
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"Night gathers, and now my watch begins. It shall not end until my death. I shall take no wife, hold no lands, father no children. I shall wear no crowns and win no glory. I shall live and die at my post. I am the sword in the darkness. I am the watcher on the walls. I am the shield that guards the realms of men. I pledge my life and honor to the Night's Watch, for this night and all the nights to come." — The Night's Watch oath.
With that begins the watch of Jon Snow. He is assigned the task to support the stewards.
This time he has *n* stewards with him whom he has to provide support. Each steward has his own strength. Jon Snow likes to support a steward only if there exists at least one steward who has strength strictly less than him and at least one steward who has strength strictly greater than him.
Can you find how many stewards will Jon support?
Input Specification:
First line consists of a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of stewards with Jon Snow.
Second line consists of *n* space separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) representing the values assigned to the stewards.
Output Specification:
Output a single integer representing the number of stewards which Jon will feed.
Demo Input:
['2\n1 5\n', '3\n1 2 5\n']
Demo Output:
['0', '1']
Note:
In the first sample, Jon Snow cannot support steward with strength 1 because there is no steward with strength less than 1 and he cannot support steward with strength 5 because there is no steward with strength greater than 5.
In the second sample, Jon Snow can support steward with strength 2 because there are stewards with strength less than 2 and greater than 2. | ```python
N = int(input())
arr = list(map(int, input().split()))
if N < 3:
print(0)
else:
arr.sort()
f = arr[0]
l = arr[-1]
if f == l:
print(0)
else:
cnt = 0
for i in range(1, len(arr)-1):
if arr[i] != f and arr[i] != l:
cnt += 1
print(cnt)
``` | 3 | |
361 | A | Levko and Table | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation"
] | null | null | Levko loves tables that consist of *n* rows and *n* columns very much. He especially loves beautiful tables. A table is beautiful to Levko if the sum of elements in each row and column of the table equals *k*.
Unfortunately, he doesn't know any such table. Your task is to help him to find at least one of them. | The single line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=1000). | Print any beautiful table. Levko doesn't like too big numbers, so all elements of the table mustn't exceed 1000 in their absolute value.
If there are multiple suitable tables, you are allowed to print any of them. | [
"2 4\n",
"4 7\n"
] | [
"1 3\n3 1\n",
"2 1 0 4\n4 0 2 1\n1 3 3 0\n0 3 2 2\n"
] | In the first sample the sum in the first row is 1 + 3 = 4, in the second row — 3 + 1 = 4, in the first column — 1 + 3 = 4 and in the second column — 3 + 1 = 4. There are other beautiful tables for this sample.
In the second sample the sum of elements in each row and each column equals 7. Besides, there are other tables that meet the statement requirements. | 500 | [
{
"input": "2 4",
"output": "4 0 \n0 4 "
},
{
"input": "4 7",
"output": "7 0 0 0 \n0 7 0 0 \n0 0 7 0 \n0 0 0 7 "
},
{
"input": "1 8",
"output": "8 "
},
{
"input": "9 3",
"output": "3 0 0 0 0 0 0 0 0 \n0 3 0 0 0 0 0 0 0 \n0 0 3 0 0 0 0 0 0 \n0 0 0 3 0 0 0 0 0 \n0 0 0 0 3 0... | 1,699,662,803 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 31 | 0 | n,k=list(map(int,input().split()))
if k%2==0 and n<=k:
for i in range(n):
print(*[k//n]*n)
else:
if n<=k:
arr=([k//n]*(n-1))+[k%n+1]
x=k%n+1
else:
arr=([0]*(n-1))+[k]
x=k
z=len(arr)-1
for i in range(len(arr)):
if i==0:
print(*arr)
else:
arr.pop(z)
z-=1
arr.insert(z,x)
print(*arr) | Title: Levko and Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Levko loves tables that consist of *n* rows and *n* columns very much. He especially loves beautiful tables. A table is beautiful to Levko if the sum of elements in each row and column of the table equals *k*.
Unfortunately, he doesn't know any such table. Your task is to help him to find at least one of them.
Input Specification:
The single line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=1000).
Output Specification:
Print any beautiful table. Levko doesn't like too big numbers, so all elements of the table mustn't exceed 1000 in their absolute value.
If there are multiple suitable tables, you are allowed to print any of them.
Demo Input:
['2 4\n', '4 7\n']
Demo Output:
['1 3\n3 1\n', '2 1 0 4\n4 0 2 1\n1 3 3 0\n0 3 2 2\n']
Note:
In the first sample the sum in the first row is 1 + 3 = 4, in the second row — 3 + 1 = 4, in the first column — 1 + 3 = 4 and in the second column — 3 + 1 = 4. There are other beautiful tables for this sample.
In the second sample the sum of elements in each row and each column equals 7. Besides, there are other tables that meet the statement requirements. | ```python
n,k=list(map(int,input().split()))
if k%2==0 and n<=k:
for i in range(n):
print(*[k//n]*n)
else:
if n<=k:
arr=([k//n]*(n-1))+[k%n+1]
x=k%n+1
else:
arr=([0]*(n-1))+[k]
x=k
z=len(arr)-1
for i in range(len(arr)):
if i==0:
print(*arr)
else:
arr.pop(z)
z-=1
arr.insert(z,x)
print(*arr)
``` | 0 | |
1,008 | A | Romaji | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after every consonant, but there can be any letter after any vowel. The only exception is a consonant "n"; after this letter, there can be any letter (not only a vowel) or there can be no letter at all. For example, the words "harakiri", "yupie", "man", and "nbo" are Berlanese while the words "horse", "king", "my", and "nz" are not.
Help Vitya find out if a word $s$ is Berlanese. | The first line of the input contains the string $s$ consisting of $|s|$ ($1\leq |s|\leq 100$) lowercase Latin letters. | Print "YES" (without quotes) if there is a vowel after every consonant except "n", otherwise print "NO".
You can print each letter in any case (upper or lower). | [
"sumimasen\n",
"ninja\n",
"codeforces\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first and second samples, a vowel goes after each consonant except "n", so the word is Berlanese.
In the third sample, the consonant "c" goes after the consonant "r", and the consonant "s" stands on the end, so the word is not Berlanese. | 500 | [
{
"input": "sumimasen",
"output": "YES"
},
{
"input": "ninja",
"output": "YES"
},
{
"input": "codeforces",
"output": "NO"
},
{
"input": "auuaoonntanonnuewannnnpuuinniwoonennyolonnnvienonpoujinndinunnenannmuveoiuuhikucuziuhunnnmunzancenen",
"output": "YES"
},
{
"in... | 1,678,520,418 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 61 | 0 | s=input()
n=len(s)
result="YES"
for i in range(0,n):
if s[i] != 'a' and s[i] != 'e' and s[i] != 'i' and s[i] != 'o' and s[i] != 'u':
result="NO"
break
print(result) | Title: Romaji
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after every consonant, but there can be any letter after any vowel. The only exception is a consonant "n"; after this letter, there can be any letter (not only a vowel) or there can be no letter at all. For example, the words "harakiri", "yupie", "man", and "nbo" are Berlanese while the words "horse", "king", "my", and "nz" are not.
Help Vitya find out if a word $s$ is Berlanese.
Input Specification:
The first line of the input contains the string $s$ consisting of $|s|$ ($1\leq |s|\leq 100$) lowercase Latin letters.
Output Specification:
Print "YES" (without quotes) if there is a vowel after every consonant except "n", otherwise print "NO".
You can print each letter in any case (upper or lower).
Demo Input:
['sumimasen\n', 'ninja\n', 'codeforces\n']
Demo Output:
['YES\n', 'YES\n', 'NO\n']
Note:
In the first and second samples, a vowel goes after each consonant except "n", so the word is Berlanese.
In the third sample, the consonant "c" goes after the consonant "r", and the consonant "s" stands on the end, so the word is not Berlanese. | ```python
s=input()
n=len(s)
result="YES"
for i in range(0,n):
if s[i] != 'a' and s[i] != 'e' and s[i] != 'i' and s[i] != 'o' and s[i] != 'u':
result="NO"
break
print(result)
``` | 0 | |
644 | A | Parliament of Berland | PROGRAMMING | 1,000 | [
"*special",
"constructive algorithms"
] | null | null | There are *n* parliamentarians in Berland. They are numbered with integers from 1 to *n*. It happened that all parliamentarians with odd indices are Democrats and all parliamentarians with even indices are Republicans.
New parliament assembly hall is a rectangle consisting of *a*<=×<=*b* chairs — *a* rows of *b* chairs each. Two chairs are considered neighbouring if they share as side. For example, chair number 5 in row number 2 is neighbouring to chairs number 4 and 6 in this row and chairs with number 5 in rows 1 and 3. Thus, chairs have four neighbours in general, except for the chairs on the border of the hall
We know that if two parliamentarians from one political party (that is two Democrats or two Republicans) seat nearby they spent all time discussing internal party issues.
Write the program that given the number of parliamentarians and the sizes of the hall determine if there is a way to find a seat for any parliamentarian, such that no two members of the same party share neighbouring seats. | The first line of the input contains three integers *n*, *a* and *b* (1<=≤<=*n*<=≤<=10<=000, 1<=≤<=*a*,<=*b*<=≤<=100) — the number of parliamentarians, the number of rows in the assembly hall and the number of seats in each row, respectively. | If there is no way to assigns seats to parliamentarians in a proper way print -1.
Otherwise print the solution in *a* lines, each containing *b* integers. The *j*-th integer of the *i*-th line should be equal to the index of parliamentarian occupying this seat, or 0 if this seat should remain empty. If there are multiple possible solution, you may print any of them. | [
"3 2 2\n",
"8 4 3\n",
"10 2 2\n"
] | [
"0 3\n1 2\n",
"7 8 3\n0 1 4\n6 0 5\n0 2 0\n",
"-1\n"
] | In the first sample there are many other possible solutions. For example,
and
The following assignment
is incorrect, because parliamentarians 1 and 3 are both from Democrats party but will occupy neighbouring seats. | 500 | [
{
"input": "3 2 2",
"output": "1 2 \n0 3 "
},
{
"input": "8 4 3",
"output": "1 2 3 \n4 5 6 \n7 8 0 \n0 0 0 "
},
{
"input": "10 2 2",
"output": "-1"
},
{
"input": "1 1 1",
"output": "1 "
},
{
"input": "8 3 3",
"output": "1 2 3 \n4 5 6 \n7 8 0 "
},
{
"in... | 1,620,152,887 | 2,147,483,647 | PyPy 3 | OK | TESTS | 85 | 124 | 2,867,200 | n, a, b = map(int, input().split())
ans = [[0] * b for _ in range(a)]
if n > a * b:
print(-1)
else:
for i in range(n):
ans[i // b][i % b] = i + 1
for i in range(a):
if b % 2 == 0 and i % 2 == 1:
ans[i] = ans[i][1:] + [ans[i][0]]
print(*ans[i]) | Title: Parliament of Berland
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* parliamentarians in Berland. They are numbered with integers from 1 to *n*. It happened that all parliamentarians with odd indices are Democrats and all parliamentarians with even indices are Republicans.
New parliament assembly hall is a rectangle consisting of *a*<=×<=*b* chairs — *a* rows of *b* chairs each. Two chairs are considered neighbouring if they share as side. For example, chair number 5 in row number 2 is neighbouring to chairs number 4 and 6 in this row and chairs with number 5 in rows 1 and 3. Thus, chairs have four neighbours in general, except for the chairs on the border of the hall
We know that if two parliamentarians from one political party (that is two Democrats or two Republicans) seat nearby they spent all time discussing internal party issues.
Write the program that given the number of parliamentarians and the sizes of the hall determine if there is a way to find a seat for any parliamentarian, such that no two members of the same party share neighbouring seats.
Input Specification:
The first line of the input contains three integers *n*, *a* and *b* (1<=≤<=*n*<=≤<=10<=000, 1<=≤<=*a*,<=*b*<=≤<=100) — the number of parliamentarians, the number of rows in the assembly hall and the number of seats in each row, respectively.
Output Specification:
If there is no way to assigns seats to parliamentarians in a proper way print -1.
Otherwise print the solution in *a* lines, each containing *b* integers. The *j*-th integer of the *i*-th line should be equal to the index of parliamentarian occupying this seat, or 0 if this seat should remain empty. If there are multiple possible solution, you may print any of them.
Demo Input:
['3 2 2\n', '8 4 3\n', '10 2 2\n']
Demo Output:
['0 3\n1 2\n', '7 8 3\n0 1 4\n6 0 5\n0 2 0\n', '-1\n']
Note:
In the first sample there are many other possible solutions. For example,
and
The following assignment
is incorrect, because parliamentarians 1 and 3 are both from Democrats party but will occupy neighbouring seats. | ```python
n, a, b = map(int, input().split())
ans = [[0] * b for _ in range(a)]
if n > a * b:
print(-1)
else:
for i in range(n):
ans[i // b][i % b] = i + 1
for i in range(a):
if b % 2 == 0 and i % 2 == 1:
ans[i] = ans[i][1:] + [ans[i][0]]
print(*ans[i])
``` | 3 | |
525 | B | Pasha and String | PROGRAMMING | 1,400 | [
"constructive algorithms",
"greedy",
"math",
"strings"
] | null | null | Pasha got a very beautiful string *s* for his birthday, the string consists of lowercase Latin letters. The letters in the string are numbered from 1 to |*s*| from left to right, where |*s*| is the length of the given string.
Pasha didn't like his present very much so he decided to change it. After his birthday Pasha spent *m* days performing the following transformations on his string — each day he chose integer *a**i* and reversed a piece of string (a segment) from position *a**i* to position |*s*|<=-<=*a**i*<=+<=1. It is guaranteed that 2·*a**i*<=≤<=|*s*|.
You face the following task: determine what Pasha's string will look like after *m* days. | The first line of the input contains Pasha's string *s* of length from 2 to 2·105 characters, consisting of lowercase Latin letters.
The second line contains a single integer *m* (1<=≤<=*m*<=≤<=105) — the number of days when Pasha changed his string.
The third line contains *m* space-separated elements *a**i* (1<=≤<=*a**i*; 2·*a**i*<=≤<=|*s*|) — the position from which Pasha started transforming the string on the *i*-th day. | In the first line of the output print what Pasha's string *s* will look like after *m* days. | [
"abcdef\n1\n2\n",
"vwxyz\n2\n2 2\n",
"abcdef\n3\n1 2 3\n"
] | [
"aedcbf\n",
"vwxyz\n",
"fbdcea\n"
] | none | 750 | [
{
"input": "abcdef\n1\n2",
"output": "aedcbf"
},
{
"input": "vwxyz\n2\n2 2",
"output": "vwxyz"
},
{
"input": "abcdef\n3\n1 2 3",
"output": "fbdcea"
},
{
"input": "jc\n5\n1 1 1 1 1",
"output": "cj"
},
{
"input": "wljqgdlxyc\n13\n3 4 3 3 5 4 4 2 4 4 5 3 3",
"out... | 1,590,319,849 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 21 | 2,000 | 19,763,200 | if __name__ == "__main__":
string = input()
string = list(string)
m = int(input())
A = [int(x) for x in input().split(' ')]
A = [x - 1 for x in A]
s = len(string)
for i in A:
string[i:s-i]= string[i:s-i][::-1]
print(''.join(string)) | Title: Pasha and String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pasha got a very beautiful string *s* for his birthday, the string consists of lowercase Latin letters. The letters in the string are numbered from 1 to |*s*| from left to right, where |*s*| is the length of the given string.
Pasha didn't like his present very much so he decided to change it. After his birthday Pasha spent *m* days performing the following transformations on his string — each day he chose integer *a**i* and reversed a piece of string (a segment) from position *a**i* to position |*s*|<=-<=*a**i*<=+<=1. It is guaranteed that 2·*a**i*<=≤<=|*s*|.
You face the following task: determine what Pasha's string will look like after *m* days.
Input Specification:
The first line of the input contains Pasha's string *s* of length from 2 to 2·105 characters, consisting of lowercase Latin letters.
The second line contains a single integer *m* (1<=≤<=*m*<=≤<=105) — the number of days when Pasha changed his string.
The third line contains *m* space-separated elements *a**i* (1<=≤<=*a**i*; 2·*a**i*<=≤<=|*s*|) — the position from which Pasha started transforming the string on the *i*-th day.
Output Specification:
In the first line of the output print what Pasha's string *s* will look like after *m* days.
Demo Input:
['abcdef\n1\n2\n', 'vwxyz\n2\n2 2\n', 'abcdef\n3\n1 2 3\n']
Demo Output:
['aedcbf\n', 'vwxyz\n', 'fbdcea\n']
Note:
none | ```python
if __name__ == "__main__":
string = input()
string = list(string)
m = int(input())
A = [int(x) for x in input().split(' ')]
A = [x - 1 for x in A]
s = len(string)
for i in A:
string[i:s-i]= string[i:s-i][::-1]
print(''.join(string))
``` | 0 | |
278 | A | Circle Line | PROGRAMMING | 800 | [
"implementation"
] | null | null | The circle line of the Berland subway has *n* stations. We know the distances between all pairs of neighboring stations:
- *d*1 is the distance between the 1-st and the 2-nd station;- *d*2 is the distance between the 2-nd and the 3-rd station;...- *d**n*<=-<=1 is the distance between the *n*<=-<=1-th and the *n*-th station;- *d**n* is the distance between the *n*-th and the 1-st station.
The trains go along the circle line in both directions. Find the shortest distance between stations with numbers *s* and *t*. | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — the number of stations on the circle line. The second line contains *n* integers *d*1,<=*d*2,<=...,<=*d**n* (1<=≤<=*d**i*<=≤<=100) — the distances between pairs of neighboring stations. The third line contains two integers *s* and *t* (1<=≤<=*s*,<=*t*<=≤<=*n*) — the numbers of stations, between which you need to find the shortest distance. These numbers can be the same.
The numbers in the lines are separated by single spaces. | Print a single number — the length of the shortest path between stations number *s* and *t*. | [
"4\n2 3 4 9\n1 3\n",
"4\n5 8 2 100\n4 1\n",
"3\n1 1 1\n3 1\n",
"3\n31 41 59\n1 1\n"
] | [
"5\n",
"15\n",
"1\n",
"0\n"
] | In the first sample the length of path 1 → 2 → 3 equals 5, the length of path 1 → 4 → 3 equals 13.
In the second sample the length of path 4 → 1 is 100, the length of path 4 → 3 → 2 → 1 is 15.
In the third sample the length of path 3 → 1 is 1, the length of path 3 → 2 → 1 is 2.
In the fourth sample the numbers of stations are the same, so the shortest distance equals 0. | 500 | [
{
"input": "4\n2 3 4 9\n1 3",
"output": "5"
},
{
"input": "4\n5 8 2 100\n4 1",
"output": "15"
},
{
"input": "3\n1 1 1\n3 1",
"output": "1"
},
{
"input": "3\n31 41 59\n1 1",
"output": "0"
},
{
"input": "5\n16 13 10 30 15\n4 2",
"output": "23"
},
{
"inpu... | 1,653,441,290 | 2,147,483,647 | Python 3 | OK | TESTS | 23 | 92 | 0 | n = int(input())
d = list(map(int, input().split()))
s, t = sorted(list(map(lambda x: int(x)-1, input().split())))
tot = sum(d)
print(min(sum(d[s:t]), tot-sum(d[s:t]))) | Title: Circle Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The circle line of the Berland subway has *n* stations. We know the distances between all pairs of neighboring stations:
- *d*1 is the distance between the 1-st and the 2-nd station;- *d*2 is the distance between the 2-nd and the 3-rd station;...- *d**n*<=-<=1 is the distance between the *n*<=-<=1-th and the *n*-th station;- *d**n* is the distance between the *n*-th and the 1-st station.
The trains go along the circle line in both directions. Find the shortest distance between stations with numbers *s* and *t*.
Input Specification:
The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — the number of stations on the circle line. The second line contains *n* integers *d*1,<=*d*2,<=...,<=*d**n* (1<=≤<=*d**i*<=≤<=100) — the distances between pairs of neighboring stations. The third line contains two integers *s* and *t* (1<=≤<=*s*,<=*t*<=≤<=*n*) — the numbers of stations, between which you need to find the shortest distance. These numbers can be the same.
The numbers in the lines are separated by single spaces.
Output Specification:
Print a single number — the length of the shortest path between stations number *s* and *t*.
Demo Input:
['4\n2 3 4 9\n1 3\n', '4\n5 8 2 100\n4 1\n', '3\n1 1 1\n3 1\n', '3\n31 41 59\n1 1\n']
Demo Output:
['5\n', '15\n', '1\n', '0\n']
Note:
In the first sample the length of path 1 → 2 → 3 equals 5, the length of path 1 → 4 → 3 equals 13.
In the second sample the length of path 4 → 1 is 100, the length of path 4 → 3 → 2 → 1 is 15.
In the third sample the length of path 3 → 1 is 1, the length of path 3 → 2 → 1 is 2.
In the fourth sample the numbers of stations are the same, so the shortest distance equals 0. | ```python
n = int(input())
d = list(map(int, input().split()))
s, t = sorted(list(map(lambda x: int(x)-1, input().split())))
tot = sum(d)
print(min(sum(d[s:t]), tot-sum(d[s:t])))
``` | 3 | |
714 | B | Filya and Homework | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | null | null | Today, hedgehog Filya went to school for the very first time! Teacher gave him a homework which Filya was unable to complete without your help.
Filya is given an array of non-negative integers *a*1,<=*a*2,<=...,<=*a**n*. First, he pick an integer *x* and then he adds *x* to some elements of the array (no more than once), subtract *x* from some other elements (also, no more than once) and do no change other elements. He wants all elements of the array to be equal.
Now he wonders if it's possible to pick such integer *x* and change some elements of the array using this *x* in order to make all elements equal. | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of integers in the Filya's array. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) — elements of the array. | If it's impossible to make all elements of the array equal using the process given in the problem statement, then print "NO" (without quotes) in the only line of the output. Otherwise print "YES" (without quotes). | [
"5\n1 3 3 2 1\n",
"5\n1 2 3 4 5\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Filya should select *x* = 1, then add it to the first and the last elements of the array and subtract from the second and the third elements. | 1,000 | [
{
"input": "5\n1 3 3 2 1",
"output": "YES"
},
{
"input": "5\n1 2 3 4 5",
"output": "NO"
},
{
"input": "2\n1 2",
"output": "YES"
},
{
"input": "3\n1 2 3",
"output": "YES"
},
{
"input": "3\n1 1 1",
"output": "YES"
},
{
"input": "2\n1 1000000000",
"ou... | 1,573,486,929 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 140 | 512,000 | # ip = open("testdata.txt", "r")
# def input():
# return ip.readline().strip()
from collections import Counter
n = int(input())
arr = list(map(int, input().split()))
total = sum(arr)
med = total / n
if med != int(med):
print("NO")
else:
for i in range(n):
arr[i] -= med
counter = Counter(arr)
is_ok = True
if len(counter)==1:
is_ok == (0 in counter)
elif 0 in counter:
if len(counter) != 3:
is_ok = False
else:
for c in counter:
if -c not in counter:
is_ok = False
break
else:
if len(counter) != 2:
is_ok = False
else:
for c in counter:
if -c not in counter:
is_ok = False
break
print("YES" if is_ok else "NO") | Title: Filya and Homework
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today, hedgehog Filya went to school for the very first time! Teacher gave him a homework which Filya was unable to complete without your help.
Filya is given an array of non-negative integers *a*1,<=*a*2,<=...,<=*a**n*. First, he pick an integer *x* and then he adds *x* to some elements of the array (no more than once), subtract *x* from some other elements (also, no more than once) and do no change other elements. He wants all elements of the array to be equal.
Now he wonders if it's possible to pick such integer *x* and change some elements of the array using this *x* in order to make all elements equal.
Input Specification:
The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of integers in the Filya's array. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=109) — elements of the array.
Output Specification:
If it's impossible to make all elements of the array equal using the process given in the problem statement, then print "NO" (without quotes) in the only line of the output. Otherwise print "YES" (without quotes).
Demo Input:
['5\n1 3 3 2 1\n', '5\n1 2 3 4 5\n']
Demo Output:
['YES\n', 'NO\n']
Note:
In the first sample Filya should select *x* = 1, then add it to the first and the last elements of the array and subtract from the second and the third elements. | ```python
# ip = open("testdata.txt", "r")
# def input():
# return ip.readline().strip()
from collections import Counter
n = int(input())
arr = list(map(int, input().split()))
total = sum(arr)
med = total / n
if med != int(med):
print("NO")
else:
for i in range(n):
arr[i] -= med
counter = Counter(arr)
is_ok = True
if len(counter)==1:
is_ok == (0 in counter)
elif 0 in counter:
if len(counter) != 3:
is_ok = False
else:
for c in counter:
if -c not in counter:
is_ok = False
break
else:
if len(counter) != 2:
is_ok = False
else:
for c in counter:
if -c not in counter:
is_ok = False
break
print("YES" if is_ok else "NO")
``` | 0 | |
456 | A | Laptops | PROGRAMMING | 1,100 | [
"sortings"
] | null | null | One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the first laptop is less (strictly smaller) than the price of the second laptop but the quality of the first laptop is higher (strictly greater) than the quality of the second laptop.
Please, check the guess of Alex. You are given descriptions of *n* laptops. Determine whether two described above laptops exist. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105) — the number of laptops.
Next *n* lines contain two integers each, *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*), where *a**i* is the price of the *i*-th laptop, and *b**i* is the number that represents the quality of the *i*-th laptop (the larger the number is, the higher is the quality).
All *a**i* are distinct. All *b**i* are distinct. | If Alex is correct, print "Happy Alex", otherwise print "Poor Alex" (without the quotes). | [
"2\n1 2\n2 1\n"
] | [
"Happy Alex\n"
] | none | 500 | [
{
"input": "2\n1 2\n2 1",
"output": "Happy Alex"
},
{
"input": "2\n1 1\n2 2",
"output": "Poor Alex"
},
{
"input": "3\n2 2\n3 3\n1 1",
"output": "Poor Alex"
},
{
"input": "3\n3 3\n1 2\n2 1",
"output": "Happy Alex"
},
{
"input": "1\n1 1",
"output": "Poor Alex"
... | 1,663,937,019 | 2,147,483,647 | Python 3 | OK | TESTS | 46 | 405 | 11,161,600 | n=int(input())
l=[]
for a in range(0,n):
l.append(list(map(int,input().split())))
def key_function1(x):
return x[0]
def key_function2(x):
return x[1]
l1=sorted(l,key=key_function1)
l2=sorted(l,key=key_function2)
print(['Happy Alex','Poor Alex'][l1==l2]) | Title: Laptops
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Dima and Alex had an argument about the price and quality of laptops. Dima thinks that the more expensive a laptop is, the better it is. Alex disagrees. Alex thinks that there are two laptops, such that the price of the first laptop is less (strictly smaller) than the price of the second laptop but the quality of the first laptop is higher (strictly greater) than the quality of the second laptop.
Please, check the guess of Alex. You are given descriptions of *n* laptops. Determine whether two described above laptops exist.
Input Specification:
The first line contains an integer *n* (1<=≤<=*n*<=≤<=105) — the number of laptops.
Next *n* lines contain two integers each, *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*), where *a**i* is the price of the *i*-th laptop, and *b**i* is the number that represents the quality of the *i*-th laptop (the larger the number is, the higher is the quality).
All *a**i* are distinct. All *b**i* are distinct.
Output Specification:
If Alex is correct, print "Happy Alex", otherwise print "Poor Alex" (without the quotes).
Demo Input:
['2\n1 2\n2 1\n']
Demo Output:
['Happy Alex\n']
Note:
none | ```python
n=int(input())
l=[]
for a in range(0,n):
l.append(list(map(int,input().split())))
def key_function1(x):
return x[0]
def key_function2(x):
return x[1]
l1=sorted(l,key=key_function1)
l2=sorted(l,key=key_function2)
print(['Happy Alex','Poor Alex'][l1==l2])
``` | 3 | |
1,006 | F | Xor-Paths | PROGRAMMING | 2,100 | [
"bitmasks",
"brute force",
"dp",
"meet-in-the-middle"
] | null | null | There is a rectangular grid of size $n \times m$. Each cell has a number written on it; the number on the cell ($i, j$) is $a_{i, j}$. Your task is to calculate the number of paths from the upper-left cell ($1, 1$) to the bottom-right cell ($n, m$) meeting the following constraints:
- You can move to the right or to the bottom only. Formally, from the cell ($i, j$) you may move to the cell ($i, j + 1$) or to the cell ($i + 1, j$). The target cell can't be outside of the grid. - The xor of all the numbers on the path from the cell ($1, 1$) to the cell ($n, m$) must be equal to $k$ (xor operation is the bitwise exclusive OR, it is represented as '^' in Java or C++ and "xor" in Pascal).
Find the number of such paths in the given grid. | The first line of the input contains three integers $n$, $m$ and $k$ ($1 \le n, m \le 20$, $0 \le k \le 10^{18}$) — the height and the width of the grid, and the number $k$.
The next $n$ lines contain $m$ integers each, the $j$-th element in the $i$-th line is $a_{i, j}$ ($0 \le a_{i, j} \le 10^{18}$). | Print one integer — the number of paths from ($1, 1$) to ($n, m$) with xor sum equal to $k$. | [
"3 3 11\n2 1 5\n7 10 0\n12 6 4\n",
"3 4 2\n1 3 3 3\n0 3 3 2\n3 0 1 1\n",
"3 4 1000000000000000000\n1 3 3 3\n0 3 3 2\n3 0 1 1\n"
] | [
"3\n",
"5\n",
"0\n"
] | All the paths from the first example:
- $(1, 1) \rightarrow (2, 1) \rightarrow (3, 1) \rightarrow (3, 2) \rightarrow (3, 3)$; - $(1, 1) \rightarrow (2, 1) \rightarrow (2, 2) \rightarrow (2, 3) \rightarrow (3, 3)$; - $(1, 1) \rightarrow (1, 2) \rightarrow (2, 2) \rightarrow (3, 2) \rightarrow (3, 3)$.
All the paths from the second example:
- $(1, 1) \rightarrow (2, 1) \rightarrow (3, 1) \rightarrow (3, 2) \rightarrow (3, 3) \rightarrow (3, 4)$; - $(1, 1) \rightarrow (2, 1) \rightarrow (2, 2) \rightarrow (3, 2) \rightarrow (3, 3) \rightarrow (3, 4)$; - $(1, 1) \rightarrow (2, 1) \rightarrow (2, 2) \rightarrow (2, 3) \rightarrow (2, 4) \rightarrow (3, 4)$; - $(1, 1) \rightarrow (1, 2) \rightarrow (2, 2) \rightarrow (2, 3) \rightarrow (3, 3) \rightarrow (3, 4)$; - $(1, 1) \rightarrow (1, 2) \rightarrow (1, 3) \rightarrow (2, 3) \rightarrow (3, 3) \rightarrow (3, 4)$. | 0 | [
{
"input": "3 3 11\n2 1 5\n7 10 0\n12 6 4",
"output": "3"
},
{
"input": "3 4 2\n1 3 3 3\n0 3 3 2\n3 0 1 1",
"output": "5"
},
{
"input": "3 4 1000000000000000000\n1 3 3 3\n0 3 3 2\n3 0 1 1",
"output": "0"
},
{
"input": "1 1 1000000000000000000\n1000000000000000000",
"outpu... | 1,651,611,695 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 38 | 233 | 34,918,400 | from sys import stdin
raw_input = lambda: stdin.readline().rstrip()
input = lambda: int(raw_input())
I=lambda: list(map(int, raw_input().split()))
xrange = range
n,m,k = I()
mat = []
dp = []
dp1 = []
for _ in xrange(n):
a = I()
mat.append(a)
dp.append([{} for _ in xrange(m)])
dp1.append([{} for _ in xrange(m)])
dp[n-1][m-1] = {mat[n-1][m-1]: 1}
for i in xrange(m-2, -1, -1):
for x in dp[n-1][i+1]:
d = x
dp[n-1][i] = {mat[n-1][i]^d: 1}
for i in xrange(n-2, -1, -1):
for x in dp[i+1][m-1]:
d = x
dp[i][m-1] = {mat[i][m-1]^d: 1}
for i in xrange(n-2, -1, -1):
for j in xrange(m-2, n-i-2, -1):
d1 = dp[i+1][j]
d2 = dp[i][j+1]
d = {}
for x in d1:
q = x^mat[i][j]
if q not in d:
d[q] = d1[x]
else:
d[q] += d1[x]
for x in d2:
q = x^mat[i][j]
if q not in d:
d[q] = d2[x]
else:
d[q] += d2[x]
# del dp[i+1][j]
dp[i][j] = d
dp1[0][0] = {mat[0][0]: 1}
for i in xrange(1, m):
for x in dp1[0][i-1]:
d = x
dp1[0][i] = {mat[0][i]^d: 1}
for i in xrange(1, n):
for x in dp1[i-1][0]:
d = x
dp1[i][0] = {mat[i][0]^d: 1}
for i in xrange(1, n-1):
for j in xrange(1, min(n-i, m)):
d1 = dp1[i-1][j]
d2 = dp1[i][j-1]
d = {}
for x in d1:
q = x^mat[i][j]
if q not in d:
d[q] = d1[x]
else:
d[q] += d1[x]
for x in d2:
q = x^mat[i][j]
if q not in d:
d[q] = d2[x]
else:
d[q] += d2[x]
dp1[i][j] = d
res = 0
for i in xrange(min(n, m)):
j = min(n,m)-i-1
d1 = dp[i][j]
d2 = dp1[i][j]
# print d1
# print d2
# print i,j,mat[i][j],k
for x in d1:
q = x^mat[i][j]^k
if q in d2:
res += d2[q]*d1[x]
print(res) | Title: Xor-Paths
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a rectangular grid of size $n \times m$. Each cell has a number written on it; the number on the cell ($i, j$) is $a_{i, j}$. Your task is to calculate the number of paths from the upper-left cell ($1, 1$) to the bottom-right cell ($n, m$) meeting the following constraints:
- You can move to the right or to the bottom only. Formally, from the cell ($i, j$) you may move to the cell ($i, j + 1$) or to the cell ($i + 1, j$). The target cell can't be outside of the grid. - The xor of all the numbers on the path from the cell ($1, 1$) to the cell ($n, m$) must be equal to $k$ (xor operation is the bitwise exclusive OR, it is represented as '^' in Java or C++ and "xor" in Pascal).
Find the number of such paths in the given grid.
Input Specification:
The first line of the input contains three integers $n$, $m$ and $k$ ($1 \le n, m \le 20$, $0 \le k \le 10^{18}$) — the height and the width of the grid, and the number $k$.
The next $n$ lines contain $m$ integers each, the $j$-th element in the $i$-th line is $a_{i, j}$ ($0 \le a_{i, j} \le 10^{18}$).
Output Specification:
Print one integer — the number of paths from ($1, 1$) to ($n, m$) with xor sum equal to $k$.
Demo Input:
['3 3 11\n2 1 5\n7 10 0\n12 6 4\n', '3 4 2\n1 3 3 3\n0 3 3 2\n3 0 1 1\n', '3 4 1000000000000000000\n1 3 3 3\n0 3 3 2\n3 0 1 1\n']
Demo Output:
['3\n', '5\n', '0\n']
Note:
All the paths from the first example:
- $(1, 1) \rightarrow (2, 1) \rightarrow (3, 1) \rightarrow (3, 2) \rightarrow (3, 3)$; - $(1, 1) \rightarrow (2, 1) \rightarrow (2, 2) \rightarrow (2, 3) \rightarrow (3, 3)$; - $(1, 1) \rightarrow (1, 2) \rightarrow (2, 2) \rightarrow (3, 2) \rightarrow (3, 3)$.
All the paths from the second example:
- $(1, 1) \rightarrow (2, 1) \rightarrow (3, 1) \rightarrow (3, 2) \rightarrow (3, 3) \rightarrow (3, 4)$; - $(1, 1) \rightarrow (2, 1) \rightarrow (2, 2) \rightarrow (3, 2) \rightarrow (3, 3) \rightarrow (3, 4)$; - $(1, 1) \rightarrow (2, 1) \rightarrow (2, 2) \rightarrow (2, 3) \rightarrow (2, 4) \rightarrow (3, 4)$; - $(1, 1) \rightarrow (1, 2) \rightarrow (2, 2) \rightarrow (2, 3) \rightarrow (3, 3) \rightarrow (3, 4)$; - $(1, 1) \rightarrow (1, 2) \rightarrow (1, 3) \rightarrow (2, 3) \rightarrow (3, 3) \rightarrow (3, 4)$. | ```python
from sys import stdin
raw_input = lambda: stdin.readline().rstrip()
input = lambda: int(raw_input())
I=lambda: list(map(int, raw_input().split()))
xrange = range
n,m,k = I()
mat = []
dp = []
dp1 = []
for _ in xrange(n):
a = I()
mat.append(a)
dp.append([{} for _ in xrange(m)])
dp1.append([{} for _ in xrange(m)])
dp[n-1][m-1] = {mat[n-1][m-1]: 1}
for i in xrange(m-2, -1, -1):
for x in dp[n-1][i+1]:
d = x
dp[n-1][i] = {mat[n-1][i]^d: 1}
for i in xrange(n-2, -1, -1):
for x in dp[i+1][m-1]:
d = x
dp[i][m-1] = {mat[i][m-1]^d: 1}
for i in xrange(n-2, -1, -1):
for j in xrange(m-2, n-i-2, -1):
d1 = dp[i+1][j]
d2 = dp[i][j+1]
d = {}
for x in d1:
q = x^mat[i][j]
if q not in d:
d[q] = d1[x]
else:
d[q] += d1[x]
for x in d2:
q = x^mat[i][j]
if q not in d:
d[q] = d2[x]
else:
d[q] += d2[x]
# del dp[i+1][j]
dp[i][j] = d
dp1[0][0] = {mat[0][0]: 1}
for i in xrange(1, m):
for x in dp1[0][i-1]:
d = x
dp1[0][i] = {mat[0][i]^d: 1}
for i in xrange(1, n):
for x in dp1[i-1][0]:
d = x
dp1[i][0] = {mat[i][0]^d: 1}
for i in xrange(1, n-1):
for j in xrange(1, min(n-i, m)):
d1 = dp1[i-1][j]
d2 = dp1[i][j-1]
d = {}
for x in d1:
q = x^mat[i][j]
if q not in d:
d[q] = d1[x]
else:
d[q] += d1[x]
for x in d2:
q = x^mat[i][j]
if q not in d:
d[q] = d2[x]
else:
d[q] += d2[x]
dp1[i][j] = d
res = 0
for i in xrange(min(n, m)):
j = min(n,m)-i-1
d1 = dp[i][j]
d2 = dp1[i][j]
# print d1
# print d2
# print i,j,mat[i][j],k
for x in d1:
q = x^mat[i][j]^k
if q in d2:
res += d2[q]*d1[x]
print(res)
``` | 0 | |
978 | A | Remove Duplicates | PROGRAMMING | 800 | [
"implementation"
] | null | null | Petya has an array $a$ consisting of $n$ integers. He wants to remove duplicate (equal) elements.
Petya wants to leave only the rightmost entry (occurrence) for each element of the array. The relative order of the remaining unique elements should not be changed. | The first line contains a single integer $n$ ($1 \le n \le 50$) — the number of elements in Petya's array.
The following line contains a sequence $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 1\,000$) — the Petya's array. | In the first line print integer $x$ — the number of elements which will be left in Petya's array after he removed the duplicates.
In the second line print $x$ integers separated with a space — Petya's array after he removed the duplicates. For each unique element only the rightmost entry should be left. | [
"6\n1 5 5 1 6 1\n",
"5\n2 4 2 4 4\n",
"5\n6 6 6 6 6\n"
] | [
"3\n5 6 1 \n",
"2\n2 4 \n",
"1\n6 \n"
] | In the first example you should remove two integers $1$, which are in the positions $1$ and $4$. Also you should remove the integer $5$, which is in the position $2$.
In the second example you should remove integer $2$, which is in the position $1$, and two integers $4$, which are in the positions $2$ and $4$.
In the third example you should remove four integers $6$, which are in the positions $1$, $2$, $3$ and $4$. | 0 | [
{
"input": "6\n1 5 5 1 6 1",
"output": "3\n5 6 1 "
},
{
"input": "5\n2 4 2 4 4",
"output": "2\n2 4 "
},
{
"input": "5\n6 6 6 6 6",
"output": "1\n6 "
},
{
"input": "7\n1 2 3 4 2 2 3",
"output": "4\n1 4 2 3 "
},
{
"input": "9\n100 100 100 99 99 99 100 100 100",
... | 1,665,409,153 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | n=int(input())
list1=list(map(int,input().split()))
set1=set(list1)
list2=list(set1)
i=n-1
list3=[]
while i>=0:
if list2.count(list1[i])>0:
list3.append(list1[i])
list2.remove(list1[i])
if len(list2)==0:
break
i-=1
print(*list3[::-1]) | Title: Remove Duplicates
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya has an array $a$ consisting of $n$ integers. He wants to remove duplicate (equal) elements.
Petya wants to leave only the rightmost entry (occurrence) for each element of the array. The relative order of the remaining unique elements should not be changed.
Input Specification:
The first line contains a single integer $n$ ($1 \le n \le 50$) — the number of elements in Petya's array.
The following line contains a sequence $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 1\,000$) — the Petya's array.
Output Specification:
In the first line print integer $x$ — the number of elements which will be left in Petya's array after he removed the duplicates.
In the second line print $x$ integers separated with a space — Petya's array after he removed the duplicates. For each unique element only the rightmost entry should be left.
Demo Input:
['6\n1 5 5 1 6 1\n', '5\n2 4 2 4 4\n', '5\n6 6 6 6 6\n']
Demo Output:
['3\n5 6 1 \n', '2\n2 4 \n', '1\n6 \n']
Note:
In the first example you should remove two integers $1$, which are in the positions $1$ and $4$. Also you should remove the integer $5$, which is in the position $2$.
In the second example you should remove integer $2$, which is in the position $1$, and two integers $4$, which are in the positions $2$ and $4$.
In the third example you should remove four integers $6$, which are in the positions $1$, $2$, $3$ and $4$. | ```python
n=int(input())
list1=list(map(int,input().split()))
set1=set(list1)
list2=list(set1)
i=n-1
list3=[]
while i>=0:
if list2.count(list1[i])>0:
list3.append(list1[i])
list2.remove(list1[i])
if len(list2)==0:
break
i-=1
print(*list3[::-1])
``` | 0 | |
612 | A | The Text Splitting | PROGRAMMING | 1,300 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string *s* to the strings only of length *p* or to the strings only of length *q* (see the second sample test). | The first line contains three positive integers *n*,<=*p*,<=*q* (1<=≤<=*p*,<=*q*<=≤<=*n*<=≤<=100).
The second line contains the string *s* consists of lowercase and uppercase latin letters and digits. | If it's impossible to split the string *s* to the strings of length *p* and *q* print the only number "-1".
Otherwise in the first line print integer *k* — the number of strings in partition of *s*.
Each of the next *k* lines should contain the strings in partition. Each string should be of the length *p* or *q*. The string should be in order of their appearing in string *s* — from left to right.
If there are several solutions print any of them. | [
"5 2 3\nHello\n",
"10 9 5\nCodeforces\n",
"6 4 5\nPrivet\n",
"8 1 1\nabacabac\n"
] | [
"2\nHe\nllo\n",
"2\nCodef\norces\n",
"-1\n",
"8\na\nb\na\nc\na\nb\na\nc\n"
] | none | 0 | [
{
"input": "5 2 3\nHello",
"output": "2\nHe\nllo"
},
{
"input": "10 9 5\nCodeforces",
"output": "2\nCodef\norces"
},
{
"input": "6 4 5\nPrivet",
"output": "-1"
},
{
"input": "8 1 1\nabacabac",
"output": "8\na\nb\na\nc\na\nb\na\nc"
},
{
"input": "1 1 1\n1",
"ou... | 1,538,000,024 | 2,147,483,647 | Python 3 | OK | TESTS | 72 | 124 | 0 | n,p,q = map(int,input().split())
s = input()
def problem6(n,p,q,s):
cont = 0
cont2 = 0
j = 0
while n>=0:
if n%p==0:
break
cont+=1
n -= q
if n<0:
print("-1")
return
cont2 = int(n/p)
num = cont+cont2
print(num)
for i in range(cont2):
print(s[j:j+p])
j+=p
for i in range(cont):
print(s[j:j+q])
j+=q
problem6(n,p,q,s)
| Title: The Text Splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string *s* to the strings only of length *p* or to the strings only of length *q* (see the second sample test).
Input Specification:
The first line contains three positive integers *n*,<=*p*,<=*q* (1<=≤<=*p*,<=*q*<=≤<=*n*<=≤<=100).
The second line contains the string *s* consists of lowercase and uppercase latin letters and digits.
Output Specification:
If it's impossible to split the string *s* to the strings of length *p* and *q* print the only number "-1".
Otherwise in the first line print integer *k* — the number of strings in partition of *s*.
Each of the next *k* lines should contain the strings in partition. Each string should be of the length *p* or *q*. The string should be in order of their appearing in string *s* — from left to right.
If there are several solutions print any of them.
Demo Input:
['5 2 3\nHello\n', '10 9 5\nCodeforces\n', '6 4 5\nPrivet\n', '8 1 1\nabacabac\n']
Demo Output:
['2\nHe\nllo\n', '2\nCodef\norces\n', '-1\n', '8\na\nb\na\nc\na\nb\na\nc\n']
Note:
none | ```python
n,p,q = map(int,input().split())
s = input()
def problem6(n,p,q,s):
cont = 0
cont2 = 0
j = 0
while n>=0:
if n%p==0:
break
cont+=1
n -= q
if n<0:
print("-1")
return
cont2 = int(n/p)
num = cont+cont2
print(num)
for i in range(cont2):
print(s[j:j+p])
j+=p
for i in range(cont):
print(s[j:j+q])
j+=q
problem6(n,p,q,s)
``` | 3 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,668,969,105 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 92 | 0 | forces = int(input())
total = [0,0,0]
for i in range(forces):
x,y,z = (int(x) for x in input().split(' '))
total[0] += x
total[1] += y
total[2] += z
if total[0] == 0 and total[1] == 0 and total[2] == 0:
print("YES")
else:
print("NO")
| Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).
Output Specification:
Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.
Demo Input:
['3\n4 1 7\n-2 4 -1\n1 -5 -3\n', '3\n3 -1 7\n-5 2 -4\n2 -1 -3\n']
Demo Output:
['NO', 'YES']
Note:
none | ```python
forces = int(input())
total = [0,0,0]
for i in range(forces):
x,y,z = (int(x) for x in input().split(' '))
total[0] += x
total[1] += y
total[2] += z
if total[0] == 0 and total[1] == 0 and total[2] == 0:
print("YES")
else:
print("NO")
``` | 3.977 |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square. | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,695,629,798 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | from math import ceil
class Solution:
def __init__(self):
pass
def solve(self):
n, m, a = map(int, input())
print(ceil(n/a) * ceil(m/a))
if __name__ == "__main__":
sol = Solution()
sol.solve()
| Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square.
Input Specification:
The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109).
Output Specification:
Write the needed number of flagstones.
Demo Input:
['6 6 4\n']
Demo Output:
['4\n']
Note:
none | ```python
from math import ceil
class Solution:
def __init__(self):
pass
def solve(self):
n, m, a = map(int, input())
print(ceil(n/a) * ceil(m/a))
if __name__ == "__main__":
sol = Solution()
sol.solve()
``` | -1 |
1,003 | A | Polycarp's Pockets | PROGRAMMING | 800 | [
"implementation"
] | null | null | Polycarp has $n$ coins, the value of the $i$-th coin is $a_i$. Polycarp wants to distribute all the coins between his pockets, but he cannot put two coins with the same value into the same pocket.
For example, if Polycarp has got six coins represented as an array $a = [1, 2, 4, 3, 3, 2]$, he can distribute the coins into two pockets as follows: $[1, 2, 3], [2, 3, 4]$.
Polycarp wants to distribute all the coins with the minimum number of used pockets. Help him to do that. | The first line of the input contains one integer $n$ ($1 \le n \le 100$) — the number of coins.
The second line of the input contains $n$ integers $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 100$) — values of coins. | Print only one integer — the minimum number of pockets Polycarp needs to distribute all the coins so no two coins with the same value are put into the same pocket. | [
"6\n1 2 4 3 3 2\n",
"1\n100\n"
] | [
"2\n",
"1\n"
] | none | 0 | [
{
"input": "6\n1 2 4 3 3 2",
"output": "2"
},
{
"input": "1\n100",
"output": "1"
},
{
"input": "100\n100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100... | 1,603,469,826 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 124 | 0 | input()
t = input().split()
print (max(t.count(x) for x in t)) | Title: Polycarp's Pockets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has $n$ coins, the value of the $i$-th coin is $a_i$. Polycarp wants to distribute all the coins between his pockets, but he cannot put two coins with the same value into the same pocket.
For example, if Polycarp has got six coins represented as an array $a = [1, 2, 4, 3, 3, 2]$, he can distribute the coins into two pockets as follows: $[1, 2, 3], [2, 3, 4]$.
Polycarp wants to distribute all the coins with the minimum number of used pockets. Help him to do that.
Input Specification:
The first line of the input contains one integer $n$ ($1 \le n \le 100$) — the number of coins.
The second line of the input contains $n$ integers $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 100$) — values of coins.
Output Specification:
Print only one integer — the minimum number of pockets Polycarp needs to distribute all the coins so no two coins with the same value are put into the same pocket.
Demo Input:
['6\n1 2 4 3 3 2\n', '1\n100\n']
Demo Output:
['2\n', '1\n']
Note:
none | ```python
input()
t = input().split()
print (max(t.count(x) for x in t))
``` | 3 | |
538 | B | Quasi Binary | PROGRAMMING | 1,400 | [
"constructive algorithms",
"dp",
"greedy",
"implementation"
] | null | null | A number is called quasibinary if its decimal representation contains only digits 0 or 1. For example, numbers 0, 1, 101, 110011 — are quasibinary and numbers 2, 12, 900 are not.
You are given a positive integer *n*. Represent it as a sum of minimum number of quasibinary numbers. | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=106). | In the first line print a single integer *k* — the minimum number of numbers in the representation of number *n* as a sum of quasibinary numbers.
In the second line print *k* numbers — the elements of the sum. All these numbers should be quasibinary according to the definition above, their sum should equal *n*. Do not have to print the leading zeroes in the numbers. The order of numbers doesn't matter. If there are multiple possible representations, you are allowed to print any of them. | [
"9\n",
"32\n"
] | [
"9\n1 1 1 1 1 1 1 1 1 \n",
"3\n10 11 11 \n"
] | none | 1,000 | [
{
"input": "9",
"output": "9\n1 1 1 1 1 1 1 1 1 "
},
{
"input": "32",
"output": "3\n10 11 11 "
},
{
"input": "1",
"output": "1\n1 "
},
{
"input": "415",
"output": "5\n1 101 101 101 111 "
},
{
"input": "10011",
"output": "1\n10011 "
},
{
"input": "10201... | 1,451,318,431 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 62 | 0 | n = int(input())
s = list(map(int, str(n)))
print(max(s))
l = len(s)
for i in range(max(s)):
f = 0
for i in range(l):
if s[i] > 0:
s[i] -= 1
print(1, end = '')
f = 1
else:
if f:
print(0, end = '')
print(' ', end = '') | Title: Quasi Binary
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A number is called quasibinary if its decimal representation contains only digits 0 or 1. For example, numbers 0, 1, 101, 110011 — are quasibinary and numbers 2, 12, 900 are not.
You are given a positive integer *n*. Represent it as a sum of minimum number of quasibinary numbers.
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=106).
Output Specification:
In the first line print a single integer *k* — the minimum number of numbers in the representation of number *n* as a sum of quasibinary numbers.
In the second line print *k* numbers — the elements of the sum. All these numbers should be quasibinary according to the definition above, their sum should equal *n*. Do not have to print the leading zeroes in the numbers. The order of numbers doesn't matter. If there are multiple possible representations, you are allowed to print any of them.
Demo Input:
['9\n', '32\n']
Demo Output:
['9\n1 1 1 1 1 1 1 1 1 \n', '3\n10 11 11 \n']
Note:
none | ```python
n = int(input())
s = list(map(int, str(n)))
print(max(s))
l = len(s)
for i in range(max(s)):
f = 0
for i in range(l):
if s[i] > 0:
s[i] -= 1
print(1, end = '')
f = 1
else:
if f:
print(0, end = '')
print(' ', end = '')
``` | 3 | |
630 | J | Divisibility | PROGRAMMING | 1,100 | [
"math",
"number theory"
] | null | null | IT City company developing computer games invented a new way to reward its employees. After a new game release users start buying it actively, and the company tracks the number of sales with precision to each transaction. Every time when the next number of sales is divisible by all numbers from 2 to 10 every developer of this game gets a small bonus.
A game designer Petya knows that the company is just about to release a new game that was partly developed by him. On the basis of his experience he predicts that *n* people will buy the game during the first month. Now Petya wants to determine how many times he will get the bonus. Help him to know it. | The only line of the input contains one integer *n* (1<=≤<=*n*<=≤<=1018) — the prediction on the number of people who will buy the game. | Output one integer showing how many numbers from 1 to *n* are divisible by all numbers from 2 to 10. | [
"3000\n"
] | [
"1"
] | none | 0 | [
{
"input": "3000",
"output": "1"
},
{
"input": "2520",
"output": "1"
},
{
"input": "2519",
"output": "0"
},
{
"input": "2521",
"output": "1"
},
{
"input": "1",
"output": "0"
},
{
"input": "314159265",
"output": "124666"
},
{
"input": "71828... | 1,694,746,699 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 500 | 1,331,200 | n=int(input())
count=0
lk=2520
i=1
while((lk*i)<=n):
count+=1
i+=1
print(count) | Title: Divisibility
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
IT City company developing computer games invented a new way to reward its employees. After a new game release users start buying it actively, and the company tracks the number of sales with precision to each transaction. Every time when the next number of sales is divisible by all numbers from 2 to 10 every developer of this game gets a small bonus.
A game designer Petya knows that the company is just about to release a new game that was partly developed by him. On the basis of his experience he predicts that *n* people will buy the game during the first month. Now Petya wants to determine how many times he will get the bonus. Help him to know it.
Input Specification:
The only line of the input contains one integer *n* (1<=≤<=*n*<=≤<=1018) — the prediction on the number of people who will buy the game.
Output Specification:
Output one integer showing how many numbers from 1 to *n* are divisible by all numbers from 2 to 10.
Demo Input:
['3000\n']
Demo Output:
['1']
Note:
none | ```python
n=int(input())
count=0
lk=2520
i=1
while((lk*i)<=n):
count+=1
i+=1
print(count)
``` | 0 | |
8 | A | Train and Peter | PROGRAMMING | 1,200 | [
"strings"
] | A. Train and Peter | 1 | 64 | Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours. | The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order. | Output one of the four words without inverted commas:
- «forward» — if Peter could see such sequences only on the way from A to B; - «backward» — if Peter could see such sequences on the way from B to A; - «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A; - «fantasy» — if Peter could not see such sequences. | [
"atob\na\nb\n",
"aaacaaa\naca\naa\n"
] | [
"forward\n",
"both\n"
] | It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B. | 0 | [
{
"input": "atob\na\nb",
"output": "forward"
},
{
"input": "aaacaaa\naca\naa",
"output": "both"
},
{
"input": "aaa\naa\naa",
"output": "fantasy"
},
{
"input": "astalavista\nastla\nlavista",
"output": "fantasy"
},
{
"input": "abacabadabacaba\nabacaba\nabacaba",
... | 1,691,302,457 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 92 | 102,400 | # LUOGU_RID: 119299363
w = input()
a = input()
b = input()
v = n = 0
if (w.find(a)!=-1 and w.find(a) <= w.rfind(b)-len(a)):
v = 1
w = w[::-1]
if (w.find(a)!=-1 and w.find(a) <= w.rfind(b)-len(a)):
n = 1
if v and n:
print("both")
elif v:
print("forward")
elif n:
print("backward")
else:
print("fantasy")
| Title: Train and Peter
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours.
Input Specification:
The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order.
Output Specification:
Output one of the four words without inverted commas:
- «forward» — if Peter could see such sequences only on the way from A to B; - «backward» — if Peter could see such sequences on the way from B to A; - «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A; - «fantasy» — if Peter could not see such sequences.
Demo Input:
['atob\na\nb\n', 'aaacaaa\naca\naa\n']
Demo Output:
['forward\n', 'both\n']
Note:
It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B. | ```python
# LUOGU_RID: 119299363
w = input()
a = input()
b = input()
v = n = 0
if (w.find(a)!=-1 and w.find(a) <= w.rfind(b)-len(a)):
v = 1
w = w[::-1]
if (w.find(a)!=-1 and w.find(a) <= w.rfind(b)-len(a)):
n = 1
if v and n:
print("both")
elif v:
print("forward")
elif n:
print("backward")
else:
print("fantasy")
``` | 3.953237 |
160 | A | Twins | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | null | null | Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, *n* coins of arbitrary values *a*1,<=*a*2,<=...,<=*a**n*. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" — you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner. | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces. | In the single line print the single number — the minimum needed number of coins. | [
"2\n3 3\n",
"3\n2 1 2\n"
] | [
"2\n",
"2\n"
] | In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2. | 500 | [
{
"input": "2\n3 3",
"output": "2"
},
{
"input": "3\n2 1 2",
"output": "2"
},
{
"input": "1\n5",
"output": "1"
},
{
"input": "5\n4 2 2 2 2",
"output": "3"
},
{
"input": "7\n1 10 1 2 1 1 1",
"output": "1"
},
{
"input": "5\n3 2 3 3 1",
"output": "3"
... | 1,696,060,517 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 |
n = int(input())
coins = list(map(int, input().split()))
coins.sort(reverse=True)
sum = 0
remaining = sum(coins)
num = 0
for coin in coins:
sum += coin
remaining -= coin
num
if sum > remaining:
break
print(num)
| Title: Twins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, *n* coins of arbitrary values *a*1,<=*a*2,<=...,<=*a**n*. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" — you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces.
Output Specification:
In the single line print the single number — the minimum needed number of coins.
Demo Input:
['2\n3 3\n', '3\n2 1 2\n']
Demo Output:
['2\n', '2\n']
Note:
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2. | ```python
n = int(input())
coins = list(map(int, input().split()))
coins.sort(reverse=True)
sum = 0
remaining = sum(coins)
num = 0
for coin in coins:
sum += coin
remaining -= coin
num
if sum > remaining:
break
print(num)
``` | -1 | |
214 | A | System of Equations | PROGRAMMING | 800 | [
"brute force"
] | null | null | Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you?
You are given a system of equations:
You should count, how many there are pairs of integers (*a*,<=*b*) (0<=≤<=*a*,<=*b*) which satisfy the system. | A single line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the parameters of the system. The numbers on the line are separated by a space. | On a single line print the answer to the problem. | [
"9 3\n",
"14 28\n",
"4 20\n"
] | [
"1\n",
"1\n",
"0\n"
] | In the first sample the suitable pair is integers (3, 0). In the second sample the suitable pair is integers (3, 5). In the third sample there is no suitable pair. | 500 | [
{
"input": "9 3",
"output": "1"
},
{
"input": "14 28",
"output": "1"
},
{
"input": "4 20",
"output": "0"
},
{
"input": "18 198",
"output": "1"
},
{
"input": "22 326",
"output": "1"
},
{
"input": "26 104",
"output": "1"
},
{
"input": "14 10"... | 1,679,738,391 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 54 | 124 | 1,945,600 | a,b=map(int,input().split())
count =0
for i in range(0,a+1):
for j in range(0,b+1):
if(i**2 + j == a and i+(j**2)==b):
count+=1
print(count) | Title: System of Equations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you?
You are given a system of equations:
You should count, how many there are pairs of integers (*a*,<=*b*) (0<=≤<=*a*,<=*b*) which satisfy the system.
Input Specification:
A single line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the parameters of the system. The numbers on the line are separated by a space.
Output Specification:
On a single line print the answer to the problem.
Demo Input:
['9 3\n', '14 28\n', '4 20\n']
Demo Output:
['1\n', '1\n', '0\n']
Note:
In the first sample the suitable pair is integers (3, 0). In the second sample the suitable pair is integers (3, 5). In the third sample there is no suitable pair. | ```python
a,b=map(int,input().split())
count =0
for i in range(0,a+1):
for j in range(0,b+1):
if(i**2 + j == a and i+(j**2)==b):
count+=1
print(count)
``` | 3 | |
236 | A | Boy or Girl | PROGRAMMING | 800 | [
"brute force",
"implementation",
"strings"
] | null | null | Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he thought so). After that they talked very often and eventually they became a couple in the network.
But yesterday, he came to see "her" in the real world and found out "she" is actually a very strong man! Our hero is very sad and he is too tired to love again now. So he came up with a way to recognize users' genders by their user names.
This is his method: if the number of distinct characters in one's user name is odd, then he is a male, otherwise she is a female. You are given the string that denotes the user name, please help our hero to determine the gender of this user by his method. | The first line contains a non-empty string, that contains only lowercase English letters — the user name. This string contains at most 100 letters. | If it is a female by our hero's method, print "CHAT WITH HER!" (without the quotes), otherwise, print "IGNORE HIM!" (without the quotes). | [
"wjmzbmr\n",
"xiaodao\n",
"sevenkplus\n"
] | [
"CHAT WITH HER!\n",
"IGNORE HIM!\n",
"CHAT WITH HER!\n"
] | For the first example. There are 6 distinct characters in "wjmzbmr". These characters are: "w", "j", "m", "z", "b", "r". So wjmzbmr is a female and you should print "CHAT WITH HER!". | 500 | [
{
"input": "wjmzbmr",
"output": "CHAT WITH HER!"
},
{
"input": "xiaodao",
"output": "IGNORE HIM!"
},
{
"input": "sevenkplus",
"output": "CHAT WITH HER!"
},
{
"input": "pezu",
"output": "CHAT WITH HER!"
},
{
"input": "wnemlgppy",
"output": "CHAT WITH HER!"
},... | 1,695,160,835 | 2,147,483,647 | Python 3 | OK | TESTS | 85 | 92 | 0 |
x=input()
c=0
for i,j in enumerate(x):
if (j in x[:i]):
continue
c=c+1
if c%2==0:
print("CHAT WITH HER!")
else:
print("IGNORE HIM!")
| Title: Boy or Girl
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he thought so). After that they talked very often and eventually they became a couple in the network.
But yesterday, he came to see "her" in the real world and found out "she" is actually a very strong man! Our hero is very sad and he is too tired to love again now. So he came up with a way to recognize users' genders by their user names.
This is his method: if the number of distinct characters in one's user name is odd, then he is a male, otherwise she is a female. You are given the string that denotes the user name, please help our hero to determine the gender of this user by his method.
Input Specification:
The first line contains a non-empty string, that contains only lowercase English letters — the user name. This string contains at most 100 letters.
Output Specification:
If it is a female by our hero's method, print "CHAT WITH HER!" (without the quotes), otherwise, print "IGNORE HIM!" (without the quotes).
Demo Input:
['wjmzbmr\n', 'xiaodao\n', 'sevenkplus\n']
Demo Output:
['CHAT WITH HER!\n', 'IGNORE HIM!\n', 'CHAT WITH HER!\n']
Note:
For the first example. There are 6 distinct characters in "wjmzbmr". These characters are: "w", "j", "m", "z", "b", "r". So wjmzbmr is a female and you should print "CHAT WITH HER!". | ```python
x=input()
c=0
for i,j in enumerate(x):
if (j in x[:i]):
continue
c=c+1
if c%2==0:
print("CHAT WITH HER!")
else:
print("IGNORE HIM!")
``` | 3 | |
268 | A | Games | PROGRAMMING | 800 | [
"brute force"
] | null | null | Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as a guest on somebody else's stadium, the players put on the guest uniform. The only exception to that rule is: when the home uniform color of the host team matches the guests' uniform, the host team puts on its guest uniform as well. For each team the color of the home and guest uniform is different.
There are *n* teams taking part in the national championship. The championship consists of *n*·(*n*<=-<=1) games: each team invites each other team to its stadium. At this point Manao wondered: how many times during the championship is a host team going to put on the guest uniform? Note that the order of the games does not affect this number.
You know the colors of the home and guest uniform for each team. For simplicity, the colors are numbered by integers in such a way that no two distinct colors have the same number. Help Manao find the answer to his question. | The first line contains an integer *n* (2<=≤<=*n*<=≤<=30). Each of the following *n* lines contains a pair of distinct space-separated integers *h**i*, *a**i* (1<=≤<=*h**i*,<=*a**i*<=≤<=100) — the colors of the *i*-th team's home and guest uniforms, respectively. | In a single line print the number of games where the host team is going to play in the guest uniform. | [
"3\n1 2\n2 4\n3 4\n",
"4\n100 42\n42 100\n5 42\n100 5\n",
"2\n1 2\n1 2\n"
] | [
"1\n",
"5\n",
"0\n"
] | In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host team is written first). | 500 | [
{
"input": "3\n1 2\n2 4\n3 4",
"output": "1"
},
{
"input": "4\n100 42\n42 100\n5 42\n100 5",
"output": "5"
},
{
"input": "2\n1 2\n1 2",
"output": "0"
},
{
"input": "7\n4 7\n52 55\n16 4\n55 4\n20 99\n3 4\n7 52",
"output": "6"
},
{
"input": "10\n68 42\n1 35\n25 70\n... | 1,673,916,530 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 124 | 0 | a=[];b=[]
n=int(input())
for ___ in range(n):
x,y =map(int,input().split())
a.append(x)
b.append(y)
sm=0
for i in range(len(a)):
for j in range(len(b)):
if a[i]==b[j]:
sm+=1
print(sm)
| Title: Games
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as a guest on somebody else's stadium, the players put on the guest uniform. The only exception to that rule is: when the home uniform color of the host team matches the guests' uniform, the host team puts on its guest uniform as well. For each team the color of the home and guest uniform is different.
There are *n* teams taking part in the national championship. The championship consists of *n*·(*n*<=-<=1) games: each team invites each other team to its stadium. At this point Manao wondered: how many times during the championship is a host team going to put on the guest uniform? Note that the order of the games does not affect this number.
You know the colors of the home and guest uniform for each team. For simplicity, the colors are numbered by integers in such a way that no two distinct colors have the same number. Help Manao find the answer to his question.
Input Specification:
The first line contains an integer *n* (2<=≤<=*n*<=≤<=30). Each of the following *n* lines contains a pair of distinct space-separated integers *h**i*, *a**i* (1<=≤<=*h**i*,<=*a**i*<=≤<=100) — the colors of the *i*-th team's home and guest uniforms, respectively.
Output Specification:
In a single line print the number of games where the host team is going to play in the guest uniform.
Demo Input:
['3\n1 2\n2 4\n3 4\n', '4\n100 42\n42 100\n5 42\n100 5\n', '2\n1 2\n1 2\n']
Demo Output:
['1\n', '5\n', '0\n']
Note:
In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host team is written first). | ```python
a=[];b=[]
n=int(input())
for ___ in range(n):
x,y =map(int,input().split())
a.append(x)
b.append(y)
sm=0
for i in range(len(a)):
for j in range(len(b)):
if a[i]==b[j]:
sm+=1
print(sm)
``` | 3 | |
691 | B | s-palindrome | PROGRAMMING | 1,600 | [
"implementation",
"strings"
] | null | null | Let's call a string "s-palindrome" if it is symmetric about the middle of the string. For example, the string "oHo" is "s-palindrome", but the string "aa" is not. The string "aa" is not "s-palindrome", because the second half of it is not a mirror reflection of the first half.
You are given a string *s*. Check if the string is "s-palindrome". | The only line contains the string *s* (1<=≤<=|*s*|<=≤<=1000) which consists of only English letters. | Print "TAK" if the string *s* is "s-palindrome" and "NIE" otherwise. | [
"oXoxoXo\n",
"bod\n",
"ER\n"
] | [
"TAK\n",
"TAK\n",
"NIE\n"
] | none | 0 | [
{
"input": "oXoxoXo",
"output": "TAK"
},
{
"input": "bod",
"output": "TAK"
},
{
"input": "ER",
"output": "NIE"
},
{
"input": "o",
"output": "TAK"
},
{
"input": "a",
"output": "NIE"
},
{
"input": "opo",
"output": "NIE"
},
{
"input": "HCMoxkg... | 1,535,872,669 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 109 | 0 | d={}
d['A']='A'
d['X']='X'
d['W']='W'
d['Y']='Y'
d['O']='O'
d['I']='I'
d['M']='M'
d['N']='N'
d['T'],d['U'],d['V'],d['H']='T','U','V','H'
d['m'],d['o'],d['v'],d['w'],d['x'],d['q'],d['p'],d['d'],d['b']='m','o','v','w','x','p','q','b','d'
s=input()
j=len(s)//2
k=len(s)-1
i,flag=0,True
#pdq
while i<j:
try:
x=d[s[i]]
y=s[k]
if x!=y:
flag=False
break
i+=1
k-=1
except:
print('NIE')
exit(0)
if flag:
print('TAK')
else:
print('NIE') | Title: s-palindrome
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's call a string "s-palindrome" if it is symmetric about the middle of the string. For example, the string "oHo" is "s-palindrome", but the string "aa" is not. The string "aa" is not "s-palindrome", because the second half of it is not a mirror reflection of the first half.
You are given a string *s*. Check if the string is "s-palindrome".
Input Specification:
The only line contains the string *s* (1<=≤<=|*s*|<=≤<=1000) which consists of only English letters.
Output Specification:
Print "TAK" if the string *s* is "s-palindrome" and "NIE" otherwise.
Demo Input:
['oXoxoXo\n', 'bod\n', 'ER\n']
Demo Output:
['TAK\n', 'TAK\n', 'NIE\n']
Note:
none | ```python
d={}
d['A']='A'
d['X']='X'
d['W']='W'
d['Y']='Y'
d['O']='O'
d['I']='I'
d['M']='M'
d['N']='N'
d['T'],d['U'],d['V'],d['H']='T','U','V','H'
d['m'],d['o'],d['v'],d['w'],d['x'],d['q'],d['p'],d['d'],d['b']='m','o','v','w','x','p','q','b','d'
s=input()
j=len(s)//2
k=len(s)-1
i,flag=0,True
#pdq
while i<j:
try:
x=d[s[i]]
y=s[k]
if x!=y:
flag=False
break
i+=1
k-=1
except:
print('NIE')
exit(0)
if flag:
print('TAK')
else:
print('NIE')
``` | 0 |
Subsets and Splits
Successful Python Submissions
Retrieves all records from the train dataset where the verdict is 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Retrieves records of users with a rating of 1600 or higher and a verdict of 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Counts the number of entries with a rating above 2000 and a verdict of 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Counts the number of entries with a 'OK' verdict, providing a basic overview of a specific category within the dataset.