contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
527 | A | Playing with Paper | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | null | null | One day Vasya was sitting on a not so interesting Maths lesson and making an origami from a rectangular *a* mm <=×<= *b* mm sheet of paper (*a*<=><=*b*). Usually the first step in making an origami is making a square piece of paper from the rectangular sheet by folding the sheet along the bisector of the right angle, and cutting the excess part.
After making a paper ship from the square piece, Vasya looked on the remaining (*a*<=-<=*b*) mm <=×<= *b* mm strip of paper. He got the idea to use this strip of paper in the same way to make an origami, and then use the remainder (if it exists) and so on. At the moment when he is left with a square piece of paper, he will make the last ship from it and stop.
Can you determine how many ships Vasya will make during the lesson? | The first line of the input contains two integers *a*, *b* (1<=≤<=*b*<=<<=*a*<=≤<=1012) — the sizes of the original sheet of paper. | Print a single integer — the number of ships that Vasya will make. | [
"2 1\n",
"10 7\n",
"1000000000000 1\n"
] | [
"2\n",
"6\n",
"1000000000000\n"
] | Pictures to the first and second sample test. | 500 | [
{
"input": "2 1",
"output": "2"
},
{
"input": "10 7",
"output": "6"
},
{
"input": "1000000000000 1",
"output": "1000000000000"
},
{
"input": "3 1",
"output": "3"
},
{
"input": "4 1",
"output": "4"
},
{
"input": "3 2",
"output": "3"
},
{
"in... | 1,670,254,161 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 21 | 2,000 | 0 | from sys import stdin
input = stdin.readline
def main():
a, b = map(int, input().split())
w = 0
# ~ breakpoint()
if b == 1:
w += a
print(w)
return 0
while (b > 0 and a > 0):
if a > b:
a, b = b, a - b
w += 1
else:
a, b = b - a, a
w += 1
if b == 1:
w += a
print(w)
main()
| Title: Playing with Paper
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya was sitting on a not so interesting Maths lesson and making an origami from a rectangular *a* mm <=×<= *b* mm sheet of paper (*a*<=><=*b*). Usually the first step in making an origami is making a square piece of paper from the rectangular sheet by folding the sheet along the bisector of the right angle, and cutting the excess part.
After making a paper ship from the square piece, Vasya looked on the remaining (*a*<=-<=*b*) mm <=×<= *b* mm strip of paper. He got the idea to use this strip of paper in the same way to make an origami, and then use the remainder (if it exists) and so on. At the moment when he is left with a square piece of paper, he will make the last ship from it and stop.
Can you determine how many ships Vasya will make during the lesson?
Input Specification:
The first line of the input contains two integers *a*, *b* (1<=≤<=*b*<=<<=*a*<=≤<=1012) — the sizes of the original sheet of paper.
Output Specification:
Print a single integer — the number of ships that Vasya will make.
Demo Input:
['2 1\n', '10 7\n', '1000000000000 1\n']
Demo Output:
['2\n', '6\n', '1000000000000\n']
Note:
Pictures to the first and second sample test. | ```python
from sys import stdin
input = stdin.readline
def main():
a, b = map(int, input().split())
w = 0
# ~ breakpoint()
if b == 1:
w += a
print(w)
return 0
while (b > 0 and a > 0):
if a > b:
a, b = b, a - b
w += 1
else:
a, b = b - a, a
w += 1
if b == 1:
w += a
print(w)
main()
``` | 0 | |
407 | C | Curious Array | PROGRAMMING | 2,500 | [
"brute force",
"combinatorics",
"implementation",
"math"
] | null | null | You've got an array consisting of *n* integers: *a*[1],<=*a*[2],<=...,<=*a*[*n*]. Moreover, there are *m* queries, each query can be described by three integers *l**i*,<=*r**i*,<=*k**i*. Query *l**i*,<=*r**i*,<=*k**i* means that we should add to each element *a*[*j*], where *l**i*<=≤<=*j*<=≤<=*r**i*.
Record means the binomial coefficient, or the number of combinations from *y* elements into groups of *x* elements.
You need to fulfil consecutively all queries and then print the final array. | The first line contains integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=105).
The second line contains *n* integers *a*[1],<=*a*[2],<=...,<=*a*[*n*] (0<=≤<=*a**i*<=≤<=109) — the initial array.
Next *m* lines contain queries in the format *l**i*,<=*r**i*,<=*k**i* — to all elements of the segment *l**i*... *r**i* add number (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*; 0<=≤<=*k*<=≤<=100). | Print *n* integers: the *i*-th number is the value of element *a*[*i*] after all the queries. As the values can be rather large, print them modulo 1000000007 (109<=+<=7). | [
"5 1\n0 0 0 0 0\n1 5 0\n",
"10 2\n1 2 3 4 5 0 0 0 0 0\n1 6 1\n6 10 2\n"
] | [
"1 1 1 1 1\n",
"2 4 6 8 10 7 3 6 10 15\n"
] | none | 2,000 | [
{
"input": "5 1\n0 0 0 0 0\n1 5 0",
"output": "1 1 1 1 1"
},
{
"input": "10 2\n1 2 3 4 5 0 0 0 0 0\n1 6 1\n6 10 2",
"output": "2 4 6 8 10 7 3 6 10 15"
},
{
"input": "5 3\n0 0 0 0 0\n1 5 0\n1 5 1\n1 5 2",
"output": "3 6 10 15 21"
},
{
"input": "10 2\n0 0 0 0 0 0 0 0 0 0\n7 9 4... | 1,659,256,166 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 77 | 1,331,200 | from math import factorial as fact
def binomial(ai,bi):
ai=ai%1000000007
bi=bi%1000000007
m=(fact(ai)%1000000007//fact(bi)%1000000007//fact(ai-bi)%1000000007)%1000000007
return m
n,m=map(int,input().split())
Ai=list(map(int,input().split()))
while m>0:
li,ri,qi=map(int,input().split())
for j in range(li,ri+1):
Ai[j-1]+=binomial(j-li+qi,qi)%1000000007
m-=1
print(*Ai) | Title: Curious Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got an array consisting of *n* integers: *a*[1],<=*a*[2],<=...,<=*a*[*n*]. Moreover, there are *m* queries, each query can be described by three integers *l**i*,<=*r**i*,<=*k**i*. Query *l**i*,<=*r**i*,<=*k**i* means that we should add to each element *a*[*j*], where *l**i*<=≤<=*j*<=≤<=*r**i*.
Record means the binomial coefficient, or the number of combinations from *y* elements into groups of *x* elements.
You need to fulfil consecutively all queries and then print the final array.
Input Specification:
The first line contains integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=105).
The second line contains *n* integers *a*[1],<=*a*[2],<=...,<=*a*[*n*] (0<=≤<=*a**i*<=≤<=109) — the initial array.
Next *m* lines contain queries in the format *l**i*,<=*r**i*,<=*k**i* — to all elements of the segment *l**i*... *r**i* add number (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*; 0<=≤<=*k*<=≤<=100).
Output Specification:
Print *n* integers: the *i*-th number is the value of element *a*[*i*] after all the queries. As the values can be rather large, print them modulo 1000000007 (109<=+<=7).
Demo Input:
['5 1\n0 0 0 0 0\n1 5 0\n', '10 2\n1 2 3 4 5 0 0 0 0 0\n1 6 1\n6 10 2\n']
Demo Output:
['1 1 1 1 1\n', '2 4 6 8 10 7 3 6 10 15\n']
Note:
none | ```python
from math import factorial as fact
def binomial(ai,bi):
ai=ai%1000000007
bi=bi%1000000007
m=(fact(ai)%1000000007//fact(bi)%1000000007//fact(ai-bi)%1000000007)%1000000007
return m
n,m=map(int,input().split())
Ai=list(map(int,input().split()))
while m>0:
li,ri,qi=map(int,input().split())
for j in range(li,ri+1):
Ai[j-1]+=binomial(j-li+qi,qi)%1000000007
m-=1
print(*Ai)
``` | 0 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*. | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,524,661,767 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 0 | 1,000 | 6,963,200 | flag=0
t=input()
i=0
while i<=len(t)-1:
if t[i]=="h":
#print('t[i]',t[i])
flag=1
#print('flag=',flag)
i+=1
if flag==1 and t[i]=="e":
#print('t[i]',t[i])
flag=2
#print('flag=',flag)
i+=1
if flag==2 and t[i]=="l":
#print('t[i]',t[i])
flag=3
#print('flag=',flag)
i+=1
if flag==3 and t[i]=="l":
#print('t[i]',t[i])
flag=4
#print('flag=',flag)
i+=1
if flag==4 and t[i]=="o":
#print('t[i]',t[i])
flag=5
#print('flag=',flag)
break
if flag==5:
print("YES")
else:
print("NO") | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*.
Input Specification:
The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters.
Output Specification:
If Vasya managed to say hello, print "YES", otherwise print "NO".
Demo Input:
['ahhellllloou\n', 'hlelo\n']
Demo Output:
['YES\n', 'NO\n']
Note:
none | ```python
flag=0
t=input()
i=0
while i<=len(t)-1:
if t[i]=="h":
#print('t[i]',t[i])
flag=1
#print('flag=',flag)
i+=1
if flag==1 and t[i]=="e":
#print('t[i]',t[i])
flag=2
#print('flag=',flag)
i+=1
if flag==2 and t[i]=="l":
#print('t[i]',t[i])
flag=3
#print('flag=',flag)
i+=1
if flag==3 and t[i]=="l":
#print('t[i]',t[i])
flag=4
#print('flag=',flag)
i+=1
if flag==4 and t[i]=="o":
#print('t[i]',t[i])
flag=5
#print('flag=',flag)
break
if flag==5:
print("YES")
else:
print("NO")
``` | 0 |
39 | B | Company Income Growth | PROGRAMMING | 1,300 | [
"greedy"
] | B. Company Income Growth | 2 | 64 | Petya works as a PR manager for a successful Berland company BerSoft. He needs to prepare a presentation on the company income growth since 2001 (the year of its founding) till now. Petya knows that in 2001 the company income amounted to *a*1 billion bourles, in 2002 — to *a*2 billion, ..., and in the current (2000<=+<=*n*)-th year — *a**n* billion bourles. On the base of the information Petya decided to show in his presentation the linear progress history which is in his opinion perfect. According to a graph Petya has already made, in the first year BerSoft company income must amount to 1 billion bourles, in the second year — 2 billion bourles etc., each following year the income increases by 1 billion bourles. Unfortunately, the real numbers are different from the perfect ones. Among the numbers *a**i* can even occur negative ones that are a sign of the company’s losses in some years. That is why Petya wants to ignore some data, in other words, cross some numbers *a**i* from the sequence and leave only some subsequence that has perfect growth.
Thus Petya has to choose a sequence of years *y*1, *y*2, ..., *y**k*,so that in the year *y*1 the company income amounted to 1 billion bourles, in the year *y*2 — 2 billion bourles etc., in accordance with the perfect growth dynamics. Help him to choose the longest such sequence. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). The next line contains *n* integers *a**i* (<=-<=100<=≤<=*a**i*<=≤<=100). The number *a**i* determines the income of BerSoft company in the (2000<=+<=*i*)-th year. The numbers in the line are separated by spaces. | Output *k* — the maximum possible length of a perfect sequence. In the next line output the sequence of years *y*1, *y*2, ..., *y**k*. Separate the numbers by spaces. If the answer is not unique, output any. If no solution exist, output one number 0. | [
"10\n-2 1 1 3 2 3 4 -10 -2 5\n",
"3\n-1 -2 -3\n"
] | [
"5\n2002 2005 2006 2007 2010\n",
"0\n"
] | none | 0 | [
{
"input": "10\n-2 1 1 3 2 3 4 -10 -2 5",
"output": "5\n2002 2005 2006 2007 2010 "
},
{
"input": "3\n-1 -2 -3",
"output": "0"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "2\n-1 1",
"output": "1\n2002 "
},
{
"in... | 1,650,557,068 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 35 | 92 | 0 | n = int(input())
arr = list(map(int,input().split()))
ans = []
curr = 1
for i in range(n):
if arr[i]==curr:
curr+=1
ans.append(2001+i)
if ans:
print(len(ans))
print(*ans)
else:
print(0) | Title: Company Income Growth
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Petya works as a PR manager for a successful Berland company BerSoft. He needs to prepare a presentation on the company income growth since 2001 (the year of its founding) till now. Petya knows that in 2001 the company income amounted to *a*1 billion bourles, in 2002 — to *a*2 billion, ..., and in the current (2000<=+<=*n*)-th year — *a**n* billion bourles. On the base of the information Petya decided to show in his presentation the linear progress history which is in his opinion perfect. According to a graph Petya has already made, in the first year BerSoft company income must amount to 1 billion bourles, in the second year — 2 billion bourles etc., each following year the income increases by 1 billion bourles. Unfortunately, the real numbers are different from the perfect ones. Among the numbers *a**i* can even occur negative ones that are a sign of the company’s losses in some years. That is why Petya wants to ignore some data, in other words, cross some numbers *a**i* from the sequence and leave only some subsequence that has perfect growth.
Thus Petya has to choose a sequence of years *y*1, *y*2, ..., *y**k*,so that in the year *y*1 the company income amounted to 1 billion bourles, in the year *y*2 — 2 billion bourles etc., in accordance with the perfect growth dynamics. Help him to choose the longest such sequence.
Input Specification:
The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). The next line contains *n* integers *a**i* (<=-<=100<=≤<=*a**i*<=≤<=100). The number *a**i* determines the income of BerSoft company in the (2000<=+<=*i*)-th year. The numbers in the line are separated by spaces.
Output Specification:
Output *k* — the maximum possible length of a perfect sequence. In the next line output the sequence of years *y*1, *y*2, ..., *y**k*. Separate the numbers by spaces. If the answer is not unique, output any. If no solution exist, output one number 0.
Demo Input:
['10\n-2 1 1 3 2 3 4 -10 -2 5\n', '3\n-1 -2 -3\n']
Demo Output:
['5\n2002 2005 2006 2007 2010\n', '0\n']
Note:
none | ```python
n = int(input())
arr = list(map(int,input().split()))
ans = []
curr = 1
for i in range(n):
if arr[i]==curr:
curr+=1
ans.append(2001+i)
if ans:
print(len(ans))
print(*ans)
else:
print(0)
``` | 3.977 |
119 | A | Epic Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* stones. The players take turns to make a move and Simon starts. During a move a player should take from the heap the number of stones equal to the greatest common divisor of the fixed number he has received and the number of stones left in the heap. A player loses when he cannot take the required number of stones (i. e. the heap has strictly less stones left than one needs to take).
Your task is to determine by the given *a*, *b* and *n* who wins the game. | The only string contains space-separated integers *a*, *b* and *n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=100) — the fixed numbers Simon and Antisimon have received correspondingly and the initial number of stones in the pile. | If Simon wins, print "0" (without the quotes), otherwise print "1" (without the quotes). | [
"3 5 9\n",
"1 1 100\n"
] | [
"0",
"1"
] | The greatest common divisor of two non-negative integers *a* and *b* is such maximum positive integer *k*, that *a* is divisible by *k* without remainder and similarly, *b* is divisible by *k* without remainder. Let *gcd*(*a*, *b*) represent the operation of calculating the greatest common divisor of numbers *a* and *b*. Specifically, *gcd*(*x*, 0) = *gcd*(0, *x*) = *x*.
In the first sample the game will go like that:
- Simon should take *gcd*(3, 9) = 3 stones from the heap. After his move the heap has 6 stones left.- Antisimon should take *gcd*(5, 6) = 1 stone from the heap. After his move the heap has 5 stones left.- Simon should take *gcd*(3, 5) = 1 stone from the heap. After his move the heap has 4 stones left.- Antisimon should take *gcd*(5, 4) = 1 stone from the heap. After his move the heap has 3 stones left.- Simon should take *gcd*(3, 3) = 3 stones from the heap. After his move the heap has 0 stones left.- Antisimon should take *gcd*(5, 0) = 5 stones from the heap. As 0 < 5, it is impossible and Antisimon loses.
In the second sample each player during each move takes one stone from the heap. As *n* is even, Antisimon takes the last stone and Simon can't make a move after that. | 500 | [
{
"input": "3 5 9",
"output": "0"
},
{
"input": "1 1 100",
"output": "1"
},
{
"input": "23 12 16",
"output": "1"
},
{
"input": "95 26 29",
"output": "1"
},
{
"input": "73 32 99",
"output": "1"
},
{
"input": "1 1 1",
"output": "0"
},
{
"inpu... | 1,680,865,994 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 122 | 0 | def main():
a, b, n = map(int,input().split())
x = n
for i in range(n):
for j in range(a):
if a%a-j ==0 and x%a-j==0:
x -= a-j
break
if x == 0:
print('0')
return
for j in range(b):
if b%b-j ==0 and x%b-j ==0:
x -= b-j
break
if x == 0:
print('1')
return
main()
| Title: Epic Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon and Antisimon play a game. Initially each player receives one fixed positive integer that doesn't change throughout the game. Simon receives number *a* and Antisimon receives number *b*. They also have a heap of *n* stones. The players take turns to make a move and Simon starts. During a move a player should take from the heap the number of stones equal to the greatest common divisor of the fixed number he has received and the number of stones left in the heap. A player loses when he cannot take the required number of stones (i. e. the heap has strictly less stones left than one needs to take).
Your task is to determine by the given *a*, *b* and *n* who wins the game.
Input Specification:
The only string contains space-separated integers *a*, *b* and *n* (1<=≤<=*a*,<=*b*,<=*n*<=≤<=100) — the fixed numbers Simon and Antisimon have received correspondingly and the initial number of stones in the pile.
Output Specification:
If Simon wins, print "0" (without the quotes), otherwise print "1" (without the quotes).
Demo Input:
['3 5 9\n', '1 1 100\n']
Demo Output:
['0', '1']
Note:
The greatest common divisor of two non-negative integers *a* and *b* is such maximum positive integer *k*, that *a* is divisible by *k* without remainder and similarly, *b* is divisible by *k* without remainder. Let *gcd*(*a*, *b*) represent the operation of calculating the greatest common divisor of numbers *a* and *b*. Specifically, *gcd*(*x*, 0) = *gcd*(0, *x*) = *x*.
In the first sample the game will go like that:
- Simon should take *gcd*(3, 9) = 3 stones from the heap. After his move the heap has 6 stones left.- Antisimon should take *gcd*(5, 6) = 1 stone from the heap. After his move the heap has 5 stones left.- Simon should take *gcd*(3, 5) = 1 stone from the heap. After his move the heap has 4 stones left.- Antisimon should take *gcd*(5, 4) = 1 stone from the heap. After his move the heap has 3 stones left.- Simon should take *gcd*(3, 3) = 3 stones from the heap. After his move the heap has 0 stones left.- Antisimon should take *gcd*(5, 0) = 5 stones from the heap. As 0 < 5, it is impossible and Antisimon loses.
In the second sample each player during each move takes one stone from the heap. As *n* is even, Antisimon takes the last stone and Simon can't make a move after that. | ```python
def main():
a, b, n = map(int,input().split())
x = n
for i in range(n):
for j in range(a):
if a%a-j ==0 and x%a-j==0:
x -= a-j
break
if x == 0:
print('0')
return
for j in range(b):
if b%b-j ==0 and x%b-j ==0:
x -= b-j
break
if x == 0:
print('1')
return
main()
``` | 0 | |
239 | A | Two Bags of Potatoes | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"math"
] | null | null | Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* potatoes) Valera lost. Valera remembers that the total amount of potatoes (*x*<=+<=*y*) in the two bags, firstly, was not gerater than *n*, and, secondly, was divisible by *k*.
Help Valera to determine how many potatoes could be in the first bag. Print all such possible numbers in ascending order. | The first line of input contains three integers *y*, *k*, *n* (1<=≤<=*y*,<=*k*,<=*n*<=≤<=109; <=≤<=105). | Print the list of whitespace-separated integers — all possible values of *x* in ascending order. You should print each possible value of *x* exactly once.
If there are no such values of *x* print a single integer -1. | [
"10 1 10\n",
"10 6 40\n"
] | [
"-1\n",
"2 8 14 20 26 \n"
] | none | 500 | [
{
"input": "10 1 10",
"output": "-1"
},
{
"input": "10 6 40",
"output": "2 8 14 20 26 "
},
{
"input": "10 1 20",
"output": "1 2 3 4 5 6 7 8 9 10 "
},
{
"input": "1 10000 1000000000",
"output": "9999 19999 29999 39999 49999 59999 69999 79999 89999 99999 109999 119999 12999... | 1,675,833,225 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 31 | 342 | 0 | y,k,n=map(int,input().split())
#(x+y)%k=0
#x+y<=n
x=[]
p=1
c=False
#print('p1')
for i in range(k-y,n-y+1,k):
if (i+y)%k==0 and i>0:
#print('p2')
p=i
break
for i in range(p,n-y+1,k):
#print('p3')
c=True
print(i,end=' ')
if c==False:
print(-1)
| Title: Two Bags of Potatoes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* potatoes) Valera lost. Valera remembers that the total amount of potatoes (*x*<=+<=*y*) in the two bags, firstly, was not gerater than *n*, and, secondly, was divisible by *k*.
Help Valera to determine how many potatoes could be in the first bag. Print all such possible numbers in ascending order.
Input Specification:
The first line of input contains three integers *y*, *k*, *n* (1<=≤<=*y*,<=*k*,<=*n*<=≤<=109; <=≤<=105).
Output Specification:
Print the list of whitespace-separated integers — all possible values of *x* in ascending order. You should print each possible value of *x* exactly once.
If there are no such values of *x* print a single integer -1.
Demo Input:
['10 1 10\n', '10 6 40\n']
Demo Output:
['-1\n', '2 8 14 20 26 \n']
Note:
none | ```python
y,k,n=map(int,input().split())
#(x+y)%k=0
#x+y<=n
x=[]
p=1
c=False
#print('p1')
for i in range(k-y,n-y+1,k):
if (i+y)%k==0 and i>0:
#print('p2')
p=i
break
for i in range(p,n-y+1,k):
#print('p3')
c=True
print(i,end=' ')
if c==False:
print(-1)
``` | 0 | |
4 | A | Watermelon | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Watermelon | 1 | 64 | One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and Billy are great fans of even numbers, that's why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that's why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight. | The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys. | Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case. | [
"8\n"
] | [
"YES\n"
] | For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | 0 | [
{
"input": "8",
"output": "YES"
},
{
"input": "5",
"output": "NO"
},
{
"input": "4",
"output": "YES"
},
{
"input": "3",
"output": "NO"
},
{
"input": "2",
"output": "NO"
},
{
"input": "1",
"output": "NO"
},
{
"input": "7",
"output": "NO"... | 1,694,102,349 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | def isPossible(input):
portion1 = 2
while portion1 < input:
portion2 = input-portion1
if portion2 % 2 == 0:
return "YES"
portion1 += 2
return "NO" | Title: Watermelon
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed *w* kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.
Pete and Billy are great fans of even numbers, that's why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that's why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight.
Input Specification:
The first (and the only) input line contains integer number *w* (1<=≤<=*w*<=≤<=100) — the weight of the watermelon bought by the boys.
Output Specification:
Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case.
Demo Input:
['8\n']
Demo Output:
['YES\n']
Note:
For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos). | ```python
def isPossible(input):
portion1 = 2
while portion1 < input:
portion2 = input-portion1
if portion2 % 2 == 0:
return "YES"
portion1 += 2
return "NO"
``` | 0 |
122 | A | Lucky Division | PROGRAMMING | 1,000 | [
"brute force",
"number theory"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find out if the given number *n* is almost lucky. | The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked. | In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes). | [
"47\n",
"16\n",
"78\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | 500 | [
{
"input": "47",
"output": "YES"
},
{
"input": "16",
"output": "YES"
},
{
"input": "78",
"output": "NO"
},
{
"input": "48",
"output": "YES"
},
{
"input": "100",
"output": "YES"
},
{
"input": "107",
"output": "NO"
},
{
"input": "77",
"ou... | 1,691,406,095 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 92 | 0 | s = int(input())
fl = False
l = [4, 7, 44, 47, 74, 77, 447, 474, 477, 744, 747, 774, 777]
for i in l:
if s in l or s%i == 0:
fl = True
break
if fl == False:
print('NO')
else:
print("YES") | Title: Lucky Division
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find out if the given number *n* is almost lucky.
Input Specification:
The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked.
Output Specification:
In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes).
Demo Input:
['47\n', '16\n', '78\n']
Demo Output:
['YES\n', 'YES\n', 'NO\n']
Note:
Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | ```python
s = int(input())
fl = False
l = [4, 7, 44, 47, 74, 77, 447, 474, 477, 744, 747, 774, 777]
for i in l:
if s in l or s%i == 0:
fl = True
break
if fl == False:
print('NO')
else:
print("YES")
``` | 3 | |
78 | A | Haiku | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Haiku | 2 | 256 | Haiku is a genre of Japanese traditional poetry.
A haiku poem consists of 17 syllables split into three phrases, containing 5, 7 and 5 syllables correspondingly (the first phrase should contain exactly 5 syllables, the second phrase should contain exactly 7 syllables, and the third phrase should contain exactly 5 syllables). A haiku masterpiece contains a description of a moment in those three phrases. Every word is important in a small poem, which is why haiku are rich with symbols. Each word has a special meaning, a special role. The main principle of haiku is to say much using a few words.
To simplify the matter, in the given problem we will consider that the number of syllable in the phrase is equal to the number of vowel letters there. Only the following letters are regarded as vowel letters: "a", "e", "i", "o" and "u".
Three phases from a certain poem are given. Determine whether it is haiku or not. | The input data consists of three lines. The length of each line is between 1 and 100, inclusive. The *i*-th line contains the *i*-th phrase of the poem. Each phrase consists of one or more words, which are separated by one or more spaces. A word is a non-empty sequence of lowercase Latin letters. Leading and/or trailing spaces in phrases are allowed. Every phrase has at least one non-space character. See the example for clarification. | Print "YES" (without the quotes) if the poem is a haiku. Otherwise, print "NO" (also without the quotes). | [
"on codeforces \nbeta round is running\n a rustling of keys \n",
"how many gallons\nof edo s rain did you drink\n cuckoo\n"
] | [
"YES",
"NO"
] | none | 500 | [
{
"input": "on codeforces \nbeta round is running\n a rustling of keys ",
"output": "YES"
},
{
"input": "how many gallons\nof edo s rain did you drink\n cuckoo",
"output": "NO"
},
{
"input": " hatsu shigure\n saru mo komino wo\nhoshige nari",
... | 1,600,887,454 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 340 | 307,200 | x = input()
y = input ()
z = input ()
ans = 0
lis = [5, 7, 5]
lis2 = [x, y, z]
def check (str) :
cnt = 0
for i in str :
if i == 'a' or i == 'e' or i == 'i' or i == 'o' or i == 'u' :
cnt += 1
return cnt
for i in range (len (lis)):
if check (lis2[i]) == lis[i] :
ans += 1
if ans == 3 :
print ('YES')
else :
print ('NO') | Title: Haiku
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Haiku is a genre of Japanese traditional poetry.
A haiku poem consists of 17 syllables split into three phrases, containing 5, 7 and 5 syllables correspondingly (the first phrase should contain exactly 5 syllables, the second phrase should contain exactly 7 syllables, and the third phrase should contain exactly 5 syllables). A haiku masterpiece contains a description of a moment in those three phrases. Every word is important in a small poem, which is why haiku are rich with symbols. Each word has a special meaning, a special role. The main principle of haiku is to say much using a few words.
To simplify the matter, in the given problem we will consider that the number of syllable in the phrase is equal to the number of vowel letters there. Only the following letters are regarded as vowel letters: "a", "e", "i", "o" and "u".
Three phases from a certain poem are given. Determine whether it is haiku or not.
Input Specification:
The input data consists of three lines. The length of each line is between 1 and 100, inclusive. The *i*-th line contains the *i*-th phrase of the poem. Each phrase consists of one or more words, which are separated by one or more spaces. A word is a non-empty sequence of lowercase Latin letters. Leading and/or trailing spaces in phrases are allowed. Every phrase has at least one non-space character. See the example for clarification.
Output Specification:
Print "YES" (without the quotes) if the poem is a haiku. Otherwise, print "NO" (also without the quotes).
Demo Input:
['on codeforces \nbeta round is running\n a rustling of keys \n', 'how many gallons\nof edo s rain did you drink\n cuckoo\n']
Demo Output:
['YES', 'NO']
Note:
none | ```python
x = input()
y = input ()
z = input ()
ans = 0
lis = [5, 7, 5]
lis2 = [x, y, z]
def check (str) :
cnt = 0
for i in str :
if i == 'a' or i == 'e' or i == 'i' or i == 'o' or i == 'u' :
cnt += 1
return cnt
for i in range (len (lis)):
if check (lis2[i]) == lis[i] :
ans += 1
if ans == 3 :
print ('YES')
else :
print ('NO')
``` | 3.914428 |
47 | A | Triangular numbers | PROGRAMMING | 800 | [
"brute force",
"math"
] | A. Triangular numbers | 2 | 256 | A triangular number is the number of dots in an equilateral triangle uniformly filled with dots. For example, three dots can be arranged in a triangle; thus three is a triangular number. The *n*-th triangular number is the number of dots in a triangle with *n* dots on a side. . You can learn more about these numbers from Wikipedia (http://en.wikipedia.org/wiki/Triangular_number).
Your task is to find out if a given integer is a triangular number. | The first line contains the single number *n* (1<=≤<=*n*<=≤<=500) — the given integer. | If the given integer is a triangular number output YES, otherwise output NO. | [
"1\n",
"2\n",
"3\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "1",
"output": "YES"
},
{
"input": "2",
"output": "NO"
},
{
"input": "3",
"output": "YES"
},
{
"input": "4",
"output": "NO"
},
{
"input": "5",
"output": "NO"
},
{
"input": "6",
"output": "YES"
},
{
"input": "7",
"output": "NO... | 1,632,590,231 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 154 | 6,758,400 | n =int(input())
sum =0
i=1
while(sum<=n):
sum = sum+i;
if(sum == n):
print("YES")
break
i = i+1
else:
print("NO")
| Title: Triangular numbers
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A triangular number is the number of dots in an equilateral triangle uniformly filled with dots. For example, three dots can be arranged in a triangle; thus three is a triangular number. The *n*-th triangular number is the number of dots in a triangle with *n* dots on a side. . You can learn more about these numbers from Wikipedia (http://en.wikipedia.org/wiki/Triangular_number).
Your task is to find out if a given integer is a triangular number.
Input Specification:
The first line contains the single number *n* (1<=≤<=*n*<=≤<=500) — the given integer.
Output Specification:
If the given integer is a triangular number output YES, otherwise output NO.
Demo Input:
['1\n', '2\n', '3\n']
Demo Output:
['YES\n', 'NO\n', 'YES\n']
Note:
none | ```python
n =int(input())
sum =0
i=1
while(sum<=n):
sum = sum+i;
if(sum == n):
print("YES")
break
i = i+1
else:
print("NO")
``` | 3.948911 |
607 | B | Zuma | PROGRAMMING | 1,900 | [
"dp"
] | null | null | Genos recently installed the game Zuma on his phone. In Zuma there exists a line of *n* gemstones, the *i*-th of which has color *c**i*. The goal of the game is to destroy all the gemstones in the line as quickly as possible.
In one second, Genos is able to choose exactly one continuous substring of colored gemstones that is a palindrome and remove it from the line. After the substring is removed, the remaining gemstones shift to form a solid line again. What is the minimum number of seconds needed to destroy the entire line?
Let us remind, that the string (or substring) is called palindrome, if it reads same backwards or forward. In our case this means the color of the first gemstone is equal to the color of the last one, the color of the second gemstone is equal to the color of the next to last and so on. | The first line of input contains a single integer *n* (1<=≤<=*n*<=≤<=500) — the number of gemstones.
The second line contains *n* space-separated integers, the *i*-th of which is *c**i* (1<=≤<=*c**i*<=≤<=*n*) — the color of the *i*-th gemstone in a line. | Print a single integer — the minimum number of seconds needed to destroy the entire line. | [
"3\n1 2 1\n",
"3\n1 2 3\n",
"7\n1 4 4 2 3 2 1\n"
] | [
"1\n",
"3\n",
"2\n"
] | In the first sample, Genos can destroy the entire line in one second.
In the second sample, Genos can only destroy one gemstone at a time, so destroying three gemstones takes three seconds.
In the third sample, to achieve the optimal time of two seconds, destroy palindrome 4 4 first and then destroy palindrome 1 2 3 2 1. | 1,250 | [
{
"input": "3\n1 2 1",
"output": "1"
},
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "7\n1 4 4 2 3 2 1",
"output": "2"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "2\n1 1",
"output": "1"
},
{
"input": "2\n1 2",
"output": "2"
},
{
... | 1,603,460,678 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 12 | 2,000 | 10,444,800 | from sys import stdin,stdout
def fn(i,j):
if j<i:return 0
if i==j:return 1
if j==i+1:return 1 if (a[i]==a[j]) else 2
if (i,j) in dp:return dp[i,j]
ans=n
if a[i]==a[j]:ans=fn(i+1,j-1)
for k in range(i,j):
ans=min(ans,fn(i,k)+fn(k+1,j))
dp[i,j]=ans
return ans
for _ in range(1):#(stdin.readline())):
n=int(stdin.readline())
# n,m=list(map(int,stdin.readline().split()))
a=list(map(int,stdin.readline().split()))
dp={}
print(fn(0,n-1))
| Title: Zuma
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Genos recently installed the game Zuma on his phone. In Zuma there exists a line of *n* gemstones, the *i*-th of which has color *c**i*. The goal of the game is to destroy all the gemstones in the line as quickly as possible.
In one second, Genos is able to choose exactly one continuous substring of colored gemstones that is a palindrome and remove it from the line. After the substring is removed, the remaining gemstones shift to form a solid line again. What is the minimum number of seconds needed to destroy the entire line?
Let us remind, that the string (or substring) is called palindrome, if it reads same backwards or forward. In our case this means the color of the first gemstone is equal to the color of the last one, the color of the second gemstone is equal to the color of the next to last and so on.
Input Specification:
The first line of input contains a single integer *n* (1<=≤<=*n*<=≤<=500) — the number of gemstones.
The second line contains *n* space-separated integers, the *i*-th of which is *c**i* (1<=≤<=*c**i*<=≤<=*n*) — the color of the *i*-th gemstone in a line.
Output Specification:
Print a single integer — the minimum number of seconds needed to destroy the entire line.
Demo Input:
['3\n1 2 1\n', '3\n1 2 3\n', '7\n1 4 4 2 3 2 1\n']
Demo Output:
['1\n', '3\n', '2\n']
Note:
In the first sample, Genos can destroy the entire line in one second.
In the second sample, Genos can only destroy one gemstone at a time, so destroying three gemstones takes three seconds.
In the third sample, to achieve the optimal time of two seconds, destroy palindrome 4 4 first and then destroy palindrome 1 2 3 2 1. | ```python
from sys import stdin,stdout
def fn(i,j):
if j<i:return 0
if i==j:return 1
if j==i+1:return 1 if (a[i]==a[j]) else 2
if (i,j) in dp:return dp[i,j]
ans=n
if a[i]==a[j]:ans=fn(i+1,j-1)
for k in range(i,j):
ans=min(ans,fn(i,k)+fn(k+1,j))
dp[i,j]=ans
return ans
for _ in range(1):#(stdin.readline())):
n=int(stdin.readline())
# n,m=list(map(int,stdin.readline().split()))
a=list(map(int,stdin.readline().split()))
dp={}
print(fn(0,n-1))
``` | 0 | |
567 | A | Lineland Mail | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love to send letters to each other. A person may send a letter only if the recipient lives in another city (because if they live in the same city, then it is easier to drop in).
Strange but true, the cost of sending the letter is exactly equal to the distance between the sender's city and the recipient's city.
For each city calculate two values *min**i* and *max**i*, where *min**i* is the minimum cost of sending a letter from the *i*-th city to some other city, and *max**i* is the the maximum cost of sending a letter from the *i*-th city to some other city | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=105) — the number of cities in Lineland. The second line contains the sequence of *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=109<=≤<=*x**i*<=≤<=109), where *x**i* is the *x*-coordinate of the *i*-th city. All the *x**i*'s are distinct and follow in ascending order. | Print *n* lines, the *i*-th line must contain two integers *min**i*,<=*max**i*, separated by a space, where *min**i* is the minimum cost of sending a letter from the *i*-th city, and *max**i* is the maximum cost of sending a letter from the *i*-th city. | [
"4\n-5 -2 2 7\n",
"2\n-1 1\n"
] | [
"3 12\n3 9\n4 7\n5 12\n",
"2 2\n2 2\n"
] | none | 500 | [
{
"input": "4\n-5 -2 2 7",
"output": "3 12\n3 9\n4 7\n5 12"
},
{
"input": "2\n-1 1",
"output": "2 2\n2 2"
},
{
"input": "3\n-1 0 1",
"output": "1 2\n1 1\n1 2"
},
{
"input": "4\n-1 0 1 3",
"output": "1 4\n1 3\n1 2\n2 4"
},
{
"input": "3\n-1000000000 0 1000000000",
... | 1,674,522,368 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 655 | 7,987,200 | n=int(input())
l=[]
for i in input().split():
l.append(int(i))
first_city=l[0]
last_city=l[-1]
mx=10e9
mn=-10e9
for i in range(n):
if i==0:
mx=abs(l[i]-last_city)
mn=abs(l[i]-l[i+1])
elif i==n-1:
mx=abs(l[i]-first_city)
mn=abs(l[i]-l[i-1])
else:
mn = min(abs(l[i] - l[i - 1]), abs(l[i] - l[i + 1]));
mx = max(abs(l[i] - first_city), abs(l[i] - last_city));
print(mn," ",mx)
mx = 10e9
mn = -10e9 | Title: Lineland Mail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love to send letters to each other. A person may send a letter only if the recipient lives in another city (because if they live in the same city, then it is easier to drop in).
Strange but true, the cost of sending the letter is exactly equal to the distance between the sender's city and the recipient's city.
For each city calculate two values *min**i* and *max**i*, where *min**i* is the minimum cost of sending a letter from the *i*-th city to some other city, and *max**i* is the the maximum cost of sending a letter from the *i*-th city to some other city
Input Specification:
The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=105) — the number of cities in Lineland. The second line contains the sequence of *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=109<=≤<=*x**i*<=≤<=109), where *x**i* is the *x*-coordinate of the *i*-th city. All the *x**i*'s are distinct and follow in ascending order.
Output Specification:
Print *n* lines, the *i*-th line must contain two integers *min**i*,<=*max**i*, separated by a space, where *min**i* is the minimum cost of sending a letter from the *i*-th city, and *max**i* is the maximum cost of sending a letter from the *i*-th city.
Demo Input:
['4\n-5 -2 2 7\n', '2\n-1 1\n']
Demo Output:
['3 12\n3 9\n4 7\n5 12\n', '2 2\n2 2\n']
Note:
none | ```python
n=int(input())
l=[]
for i in input().split():
l.append(int(i))
first_city=l[0]
last_city=l[-1]
mx=10e9
mn=-10e9
for i in range(n):
if i==0:
mx=abs(l[i]-last_city)
mn=abs(l[i]-l[i+1])
elif i==n-1:
mx=abs(l[i]-first_city)
mn=abs(l[i]-l[i-1])
else:
mn = min(abs(l[i] - l[i - 1]), abs(l[i] - l[i + 1]));
mx = max(abs(l[i] - first_city), abs(l[i] - last_city));
print(mn," ",mx)
mx = 10e9
mn = -10e9
``` | 3 | |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consists of several words. For each language, all words are distinct, i.e. they are spelled differently. Moreover, the words of these languages have a one-to-one correspondence, that is, for each word in each language, there exists exactly one word in the other language having has the same meaning.
You can write down every word the professor says in either the first language or the second language. Of course, during the lecture you write down each word in the language in which the word is shorter. In case of equal lengths of the corresponding words you prefer the word of the first language.
You are given the text of the lecture the professor is going to read. Find out how the lecture will be recorded in your notes. | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* belongs to the first language, the word *b**i* belongs to the second language, and these two words have the same meaning. It is guaranteed that no word occurs in both languages, and each word occurs in its language exactly once.
The next line contains *n* space-separated strings *c*1,<=*c*2,<=...,<=*c**n* — the text of the lecture. It is guaranteed that each of the strings *c**i* belongs to the set of strings {*a*1,<=*a*2,<=... *a**m*}.
All the strings in the input are non-empty, each consisting of no more than 10 lowercase English letters. | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,595,447,963 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 1,000 | 7,270,400 | n, m = map(int, input().split())
slova=[[j for j in input().split()] for i in range(m)]
fraza = input().split()
ans=[]
for i in range(n):
for j in range(m):
if fraza[i] == slova[j][0]:
if len(slova[j][0])<=len(slova[j][1]):
ans.append(slova[j][0])
else:
ans.append(slova[j][1])
for i in range(n):
print(ans[i], end = ' ') | Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consists of several words. For each language, all words are distinct, i.e. they are spelled differently. Moreover, the words of these languages have a one-to-one correspondence, that is, for each word in each language, there exists exactly one word in the other language having has the same meaning.
You can write down every word the professor says in either the first language or the second language. Of course, during the lecture you write down each word in the language in which the word is shorter. In case of equal lengths of the corresponding words you prefer the word of the first language.
You are given the text of the lecture the professor is going to read. Find out how the lecture will be recorded in your notes.
Input Specification:
The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* belongs to the first language, the word *b**i* belongs to the second language, and these two words have the same meaning. It is guaranteed that no word occurs in both languages, and each word occurs in its language exactly once.
The next line contains *n* space-separated strings *c*1,<=*c*2,<=...,<=*c**n* — the text of the lecture. It is guaranteed that each of the strings *c**i* belongs to the set of strings {*a*1,<=*a*2,<=... *a**m*}.
All the strings in the input are non-empty, each consisting of no more than 10 lowercase English letters.
Output Specification:
Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input.
Demo Input:
['4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n', '5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n']
Demo Output:
['codeforces round letter round\n', 'hbnyiyc joll joll un joll\n']
Note:
none | ```python
n, m = map(int, input().split())
slova=[[j for j in input().split()] for i in range(m)]
fraza = input().split()
ans=[]
for i in range(n):
for j in range(m):
if fraza[i] == slova[j][0]:
if len(slova[j][0])<=len(slova[j][1]):
ans.append(slova[j][0])
else:
ans.append(slova[j][1])
for i in range(n):
print(ans[i], end = ' ')
``` | 0 | |
189 | A | Cut Ribbon | PROGRAMMING | 1,300 | [
"brute force",
"dp"
] | null | null | Polycarpus has a ribbon, its length is *n*. He wants to cut the ribbon in a way that fulfils the following two conditions:
- After the cutting each ribbon piece should have length *a*, *b* or *c*. - After the cutting the number of ribbon pieces should be maximum.
Help Polycarpus and find the number of ribbon pieces after the required cutting. | The first line contains four space-separated integers *n*, *a*, *b* and *c* (1<=≤<=*n*,<=*a*,<=*b*,<=*c*<=≤<=4000) — the length of the original ribbon and the acceptable lengths of the ribbon pieces after the cutting, correspondingly. The numbers *a*, *b* and *c* can coincide. | Print a single number — the maximum possible number of ribbon pieces. It is guaranteed that at least one correct ribbon cutting exists. | [
"5 5 3 2\n",
"7 5 5 2\n"
] | [
"2\n",
"2\n"
] | In the first example Polycarpus can cut the ribbon in such way: the first piece has length 2, the second piece has length 3.
In the second example Polycarpus can cut the ribbon in such way: the first piece has length 5, the second piece has length 2. | 500 | [
{
"input": "5 5 3 2",
"output": "2"
},
{
"input": "7 5 5 2",
"output": "2"
},
{
"input": "4 4 4 4",
"output": "1"
},
{
"input": "1 1 1 1",
"output": "1"
},
{
"input": "4000 1 2 3",
"output": "4000"
},
{
"input": "4000 3 4 5",
"output": "1333"
},
... | 1,697,026,986 | 2,147,483,647 | Python 3 | OK | TESTS | 58 | 46 | 0 | n, a, b, c = input().split()
n = int(n)
a = int(a)
b = int(b)
c = int(c)
dp = [-float('inf')] * (n+1)
def iterative_soln(length):
dp[0] = 0
for i in range(1, length+1):
if i >= a:
dp[i] = max(dp[i], 1+ dp[i-a])
if i >= b:
dp[i] = max(dp[i], 1+ dp[i-b])
if i >= c:
dp[i] = max(dp[i], 1+ dp[i-c])
return dp[length]
print(iterative_soln(n)) | Title: Cut Ribbon
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has a ribbon, its length is *n*. He wants to cut the ribbon in a way that fulfils the following two conditions:
- After the cutting each ribbon piece should have length *a*, *b* or *c*. - After the cutting the number of ribbon pieces should be maximum.
Help Polycarpus and find the number of ribbon pieces after the required cutting.
Input Specification:
The first line contains four space-separated integers *n*, *a*, *b* and *c* (1<=≤<=*n*,<=*a*,<=*b*,<=*c*<=≤<=4000) — the length of the original ribbon and the acceptable lengths of the ribbon pieces after the cutting, correspondingly. The numbers *a*, *b* and *c* can coincide.
Output Specification:
Print a single number — the maximum possible number of ribbon pieces. It is guaranteed that at least one correct ribbon cutting exists.
Demo Input:
['5 5 3 2\n', '7 5 5 2\n']
Demo Output:
['2\n', '2\n']
Note:
In the first example Polycarpus can cut the ribbon in such way: the first piece has length 2, the second piece has length 3.
In the second example Polycarpus can cut the ribbon in such way: the first piece has length 5, the second piece has length 2. | ```python
n, a, b, c = input().split()
n = int(n)
a = int(a)
b = int(b)
c = int(c)
dp = [-float('inf')] * (n+1)
def iterative_soln(length):
dp[0] = 0
for i in range(1, length+1):
if i >= a:
dp[i] = max(dp[i], 1+ dp[i-a])
if i >= b:
dp[i] = max(dp[i], 1+ dp[i-b])
if i >= c:
dp[i] = max(dp[i], 1+ dp[i-c])
return dp[length]
print(iterative_soln(n))
``` | 3 | |
624 | B | Making a String | PROGRAMMING | 1,100 | [
"greedy",
"sortings"
] | null | null | You are given an alphabet consisting of *n* letters, your task is to make a string of the maximum possible length so that the following conditions are satisfied:
- the *i*-th letter occurs in the string no more than *a**i* times; - the number of occurrences of each letter in the string must be distinct for all the letters that occurred in the string at least once. | The first line of the input contains a single integer *n* (2<=<=≤<=<=*n*<=<=≤<=<=26) — the number of letters in the alphabet.
The next line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — *i*-th of these integers gives the limitation on the number of occurrences of the *i*-th character in the string. | Print a single integer — the maximum length of the string that meets all the requirements. | [
"3\n2 5 5\n",
"3\n1 1 2\n"
] | [
"11\n",
"3\n"
] | For convenience let's consider an alphabet consisting of three letters: "a", "b", "c". In the first sample, some of the optimal strings are: "cccaabbccbb", "aabcbcbcbcb". In the second sample some of the optimal strings are: "acc", "cbc". | 1,000 | [
{
"input": "3\n2 5 5",
"output": "11"
},
{
"input": "3\n1 1 2",
"output": "3"
},
{
"input": "2\n1 1",
"output": "1"
},
{
"input": "3\n1 1000000000 2",
"output": "1000000003"
},
{
"input": "26\n1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 10000... | 1,526,844,585 | 2,147,483,647 | Python 3 | OK | TESTS | 57 | 78 | 0 | n = input()
v = input().split()
v = map(int, v)
v = list(v)
oc = {}
s = 0
for i, vi in enumerate(v):
while(oc.get(vi,0) and vi > 0):
vi -= 1
oc[vi] = oc.get(vi, 0) + 1
s += vi
print(s)
| Title: Making a String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an alphabet consisting of *n* letters, your task is to make a string of the maximum possible length so that the following conditions are satisfied:
- the *i*-th letter occurs in the string no more than *a**i* times; - the number of occurrences of each letter in the string must be distinct for all the letters that occurred in the string at least once.
Input Specification:
The first line of the input contains a single integer *n* (2<=<=≤<=<=*n*<=<=≤<=<=26) — the number of letters in the alphabet.
The next line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — *i*-th of these integers gives the limitation on the number of occurrences of the *i*-th character in the string.
Output Specification:
Print a single integer — the maximum length of the string that meets all the requirements.
Demo Input:
['3\n2 5 5\n', '3\n1 1 2\n']
Demo Output:
['11\n', '3\n']
Note:
For convenience let's consider an alphabet consisting of three letters: "a", "b", "c". In the first sample, some of the optimal strings are: "cccaabbccbb", "aabcbcbcbcb". In the second sample some of the optimal strings are: "acc", "cbc". | ```python
n = input()
v = input().split()
v = map(int, v)
v = list(v)
oc = {}
s = 0
for i, vi in enumerate(v):
while(oc.get(vi,0) and vi > 0):
vi -= 1
oc[vi] = oc.get(vi, 0) + 1
s += vi
print(s)
``` | 3 | |
825 | C | Multi-judge Solving | PROGRAMMING | 1,600 | [
"greedy",
"implementation"
] | null | null | Makes solves problems on Decoforces and lots of other different online judges. Each problem is denoted by its difficulty — a positive integer number. Difficulties are measured the same across all the judges (the problem with difficulty *d* on Decoforces is as hard as the problem with difficulty *d* on any other judge).
Makes has chosen *n* problems to solve on Decoforces with difficulties *a*1,<=*a*2,<=...,<=*a**n*. He can solve these problems in arbitrary order. Though he can solve problem *i* with difficulty *a**i* only if he had already solved some problem with difficulty (no matter on what online judge was it).
Before starting this chosen list of problems, Makes has already solved problems with maximum difficulty *k*.
With given conditions it's easy to see that Makes sometimes can't solve all the chosen problems, no matter what order he chooses. So he wants to solve some problems on other judges to finish solving problems from his list.
For every positive integer *y* there exist some problem with difficulty *y* on at least one judge besides Decoforces.
Makes can solve problems on any judge at any time, it isn't necessary to do problems from the chosen list one right after another.
Makes doesn't have too much free time, so he asked you to calculate the minimum number of problems he should solve on other judges in order to solve all the chosen problems from Decoforces. | The first line contains two integer numbers *n*, *k* (1<=≤<=*n*<=≤<=103, 1<=≤<=*k*<=≤<=109).
The second line contains *n* space-separated integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | Print minimum number of problems Makes should solve on other judges in order to solve all chosen problems on Decoforces. | [
"3 3\n2 1 9\n",
"4 20\n10 3 6 3\n"
] | [
"1\n",
"0\n"
] | In the first example Makes at first solves problems 1 and 2. Then in order to solve the problem with difficulty 9, he should solve problem with difficulty no less than 5. The only available are difficulties 5 and 6 on some other judge. Solving any of these will give Makes opportunity to solve problem 3.
In the second example he can solve every problem right from the start. | 0 | [
{
"input": "3 3\n2 1 9",
"output": "1"
},
{
"input": "4 20\n10 3 6 3",
"output": "0"
},
{
"input": "1 1000000000\n1",
"output": "0"
},
{
"input": "1 1\n3",
"output": "1"
},
{
"input": "50 100\n74 55 33 5 83 24 75 59 30 36 13 4 62 28 96 17 6 35 45 53 33 11 37 93 34... | 1,516,685,424 | 5,424 | Python 3 | WRONG_ANSWER | TESTS | 5 | 62 | 5,632,000 | n,k = map(int,input().split())
dif = list(map(int,input().split()))
c = 0
for elem in dif:
if elem>k*2:
for elem1 in dif:
if elem1*2>=elem and elem1!=elem:
break
elif elem1==dif[n-1]:
c+=1
break
print(c) | Title: Multi-judge Solving
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Makes solves problems on Decoforces and lots of other different online judges. Each problem is denoted by its difficulty — a positive integer number. Difficulties are measured the same across all the judges (the problem with difficulty *d* on Decoforces is as hard as the problem with difficulty *d* on any other judge).
Makes has chosen *n* problems to solve on Decoforces with difficulties *a*1,<=*a*2,<=...,<=*a**n*. He can solve these problems in arbitrary order. Though he can solve problem *i* with difficulty *a**i* only if he had already solved some problem with difficulty (no matter on what online judge was it).
Before starting this chosen list of problems, Makes has already solved problems with maximum difficulty *k*.
With given conditions it's easy to see that Makes sometimes can't solve all the chosen problems, no matter what order he chooses. So he wants to solve some problems on other judges to finish solving problems from his list.
For every positive integer *y* there exist some problem with difficulty *y* on at least one judge besides Decoforces.
Makes can solve problems on any judge at any time, it isn't necessary to do problems from the chosen list one right after another.
Makes doesn't have too much free time, so he asked you to calculate the minimum number of problems he should solve on other judges in order to solve all the chosen problems from Decoforces.
Input Specification:
The first line contains two integer numbers *n*, *k* (1<=≤<=*n*<=≤<=103, 1<=≤<=*k*<=≤<=109).
The second line contains *n* space-separated integer numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109).
Output Specification:
Print minimum number of problems Makes should solve on other judges in order to solve all chosen problems on Decoforces.
Demo Input:
['3 3\n2 1 9\n', '4 20\n10 3 6 3\n']
Demo Output:
['1\n', '0\n']
Note:
In the first example Makes at first solves problems 1 and 2. Then in order to solve the problem with difficulty 9, he should solve problem with difficulty no less than 5. The only available are difficulties 5 and 6 on some other judge. Solving any of these will give Makes opportunity to solve problem 3.
In the second example he can solve every problem right from the start. | ```python
n,k = map(int,input().split())
dif = list(map(int,input().split()))
c = 0
for elem in dif:
if elem>k*2:
for elem1 in dif:
if elem1*2>=elem and elem1!=elem:
break
elif elem1==dif[n-1]:
c+=1
break
print(c)
``` | 0 | |
106 | D | Treasure Island | PROGRAMMING | 1,700 | [
"brute force",
"implementation"
] | D. Treasure Island | 2 | 256 | Our brave travelers reached an island where pirates had buried treasure. However as the ship was about to moor, the captain found out that some rat ate a piece of the treasure map.
The treasure map can be represented as a rectangle *n*<=×<=*m* in size. Each cell stands for an islands' square (the square's side length equals to a mile). Some cells stand for the sea and they are impenetrable. All other cells are penetrable (i.e. available) and some of them contain local sights. For example, the large tree on the hills or the cave in the rocks.
Besides, the map also has a set of *k* instructions. Each instruction is in the following form:
"Walk *n* miles in the *y* direction"
The possible directions are: north, south, east, and west. If you follow these instructions carefully (you should fulfill all of them, one by one) then you should reach exactly the place where treasures are buried.
Unfortunately the captain doesn't know the place where to start fulfilling the instructions — as that very piece of the map was lost. But the captain very well remembers that the place contained some local sight. Besides, the captain knows that the whole way goes through the island's penetrable squares.
The captain wants to know which sights are worth checking. He asks you to help him with that. | The first line contains two integers *n* and *m* (3<=≤<=*n*,<=*m*<=≤<=1000).
Then follow *n* lines containing *m* integers each — the island map's description. "#" stands for the sea. It is guaranteed that all cells along the rectangle's perimeter are the sea. "." stands for a penetrable square without any sights and the sights are marked with uppercase Latin letters from "A" to "Z". Not all alphabet letters can be used. However, it is guaranteed that at least one of them is present on the map. All local sights are marked by different letters.
The next line contains number *k* (1<=≤<=*k*<=≤<=105), after which *k* lines follow. Each line describes an instruction. Each instruction possesses the form "*dir* *len*", where *dir* stands for the direction and *len* stands for the length of the way to walk. *dir* can take values "N", "S", "W" and "E" for North, South, West and East correspondingly. At that, north is to the top, South is to the bottom, west is to the left and east is to the right. *len* is an integer from 1 to 1000. | Print all local sights that satisfy to the instructions as a string without any separators in the alphabetical order. If no sight fits, print "no solution" without the quotes. | [
"6 10\n##########\n#K#..#####\n#.#..##.##\n#..L.#...#\n###D###A.#\n##########\n4\nN 2\nS 1\nE 1\nW 2\n",
"3 4\n####\n#.A#\n####\n2\nW 1\nN 2\n"
] | [
"AD",
"no solution"
] | none | 2,000 | [
{
"input": "6 10\n##########\n#K#..#####\n#.#..##.##\n#..L.#...#\n###D###A.#\n##########\n4\nN 2\nS 1\nE 1\nW 2",
"output": "AD"
},
{
"input": "3 4\n####\n#.A#\n####\n2\nW 1\nN 2",
"output": "no solution"
},
{
"input": "10 10\n##########\n#K#..##..#\n##...ZB..#\n##.......#\n#D..#....#\n#... | 1,659,556,407 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 19 | 2,000 | 18,432,000 | n,m=map(int,input().split())
q=[]
for i in range(n):
q+=[input()]
k=int(input())
w=[]
for i in range(k):
w+=[input().split()]
w[-1][1]=int(w[-1][1])
N=[[0]*m for i in range(n)]
S=[[0]*m for i in range(n)]
E=[[0]*m for i in range(n)]
W=[[0]*m for i in range(n)]
r=0
for i in range(n):
for j in range(m):
W[i][j]=r
if q[i][j]=="#":
r=0
else:
r+=1
r=0
for j in range(m):
for i in range(n):
N[i][j]=r
if q[i][j]=="#":
r=0
else:
r+=1
r=0
for i in range(n):
for j in range(m-1,-1,-1):
E[i][j]=r
if q[i][j]=="#":
r=0
else:
r+=1
r=0
for j in range(m):
for i in range(n-1,-1,-1):
S[i][j]=r
if q[i][j]=="#":
r=0
else:
r+=1
def check(x,y,d,s):
if d=="N":
if x-s<0 or N[x][y]<s:
return False
return True
elif d=="S":
if x+s>=n or S[x][y]<s:
return False
return True
elif d=="W":
if y-s<0 or W[x][y]<s:
return False
return True
else:
if y+s>=m or E[x][y]<s:
return False
return True
def update(x,y,d,s):
if d=="N":
return (x-s,y)
elif d=="S":
return (x+s,y)
elif d=="E":
return (x,y+s)
else:
return (x,y-s)
ans=""
for i in range(n):
for j in range(m):
if q[i][j] not in "#.":
x,y=i,j
t=1
for l in range(k):
if check(x,y,w[l][0],w[l][1]):
x,y=update(x,y,w[l][0],w[l][1])
else:
t=0
break
if t:
ans+=q[i][j]
if ans:
print("".join(sorted(ans)))
else:
print("no solution") | Title: Treasure Island
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Our brave travelers reached an island where pirates had buried treasure. However as the ship was about to moor, the captain found out that some rat ate a piece of the treasure map.
The treasure map can be represented as a rectangle *n*<=×<=*m* in size. Each cell stands for an islands' square (the square's side length equals to a mile). Some cells stand for the sea and they are impenetrable. All other cells are penetrable (i.e. available) and some of them contain local sights. For example, the large tree on the hills or the cave in the rocks.
Besides, the map also has a set of *k* instructions. Each instruction is in the following form:
"Walk *n* miles in the *y* direction"
The possible directions are: north, south, east, and west. If you follow these instructions carefully (you should fulfill all of them, one by one) then you should reach exactly the place where treasures are buried.
Unfortunately the captain doesn't know the place where to start fulfilling the instructions — as that very piece of the map was lost. But the captain very well remembers that the place contained some local sight. Besides, the captain knows that the whole way goes through the island's penetrable squares.
The captain wants to know which sights are worth checking. He asks you to help him with that.
Input Specification:
The first line contains two integers *n* and *m* (3<=≤<=*n*,<=*m*<=≤<=1000).
Then follow *n* lines containing *m* integers each — the island map's description. "#" stands for the sea. It is guaranteed that all cells along the rectangle's perimeter are the sea. "." stands for a penetrable square without any sights and the sights are marked with uppercase Latin letters from "A" to "Z". Not all alphabet letters can be used. However, it is guaranteed that at least one of them is present on the map. All local sights are marked by different letters.
The next line contains number *k* (1<=≤<=*k*<=≤<=105), after which *k* lines follow. Each line describes an instruction. Each instruction possesses the form "*dir* *len*", where *dir* stands for the direction and *len* stands for the length of the way to walk. *dir* can take values "N", "S", "W" and "E" for North, South, West and East correspondingly. At that, north is to the top, South is to the bottom, west is to the left and east is to the right. *len* is an integer from 1 to 1000.
Output Specification:
Print all local sights that satisfy to the instructions as a string without any separators in the alphabetical order. If no sight fits, print "no solution" without the quotes.
Demo Input:
['6 10\n##########\n#K#..#####\n#.#..##.##\n#..L.#...#\n###D###A.#\n##########\n4\nN 2\nS 1\nE 1\nW 2\n', '3 4\n####\n#.A#\n####\n2\nW 1\nN 2\n']
Demo Output:
['AD', 'no solution']
Note:
none | ```python
n,m=map(int,input().split())
q=[]
for i in range(n):
q+=[input()]
k=int(input())
w=[]
for i in range(k):
w+=[input().split()]
w[-1][1]=int(w[-1][1])
N=[[0]*m for i in range(n)]
S=[[0]*m for i in range(n)]
E=[[0]*m for i in range(n)]
W=[[0]*m for i in range(n)]
r=0
for i in range(n):
for j in range(m):
W[i][j]=r
if q[i][j]=="#":
r=0
else:
r+=1
r=0
for j in range(m):
for i in range(n):
N[i][j]=r
if q[i][j]=="#":
r=0
else:
r+=1
r=0
for i in range(n):
for j in range(m-1,-1,-1):
E[i][j]=r
if q[i][j]=="#":
r=0
else:
r+=1
r=0
for j in range(m):
for i in range(n-1,-1,-1):
S[i][j]=r
if q[i][j]=="#":
r=0
else:
r+=1
def check(x,y,d,s):
if d=="N":
if x-s<0 or N[x][y]<s:
return False
return True
elif d=="S":
if x+s>=n or S[x][y]<s:
return False
return True
elif d=="W":
if y-s<0 or W[x][y]<s:
return False
return True
else:
if y+s>=m or E[x][y]<s:
return False
return True
def update(x,y,d,s):
if d=="N":
return (x-s,y)
elif d=="S":
return (x+s,y)
elif d=="E":
return (x,y+s)
else:
return (x,y-s)
ans=""
for i in range(n):
for j in range(m):
if q[i][j] not in "#.":
x,y=i,j
t=1
for l in range(k):
if check(x,y,w[l][0],w[l][1]):
x,y=update(x,y,w[l][0],w[l][1])
else:
t=0
break
if t:
ans+=q[i][j]
if ans:
print("".join(sorted(ans)))
else:
print("no solution")
``` | 0 |
16 | A | Flag | PROGRAMMING | 800 | [
"implementation"
] | A. Flag | 2 | 64 | According to a new ISO standard, a flag of every country should have a chequered field *n*<=×<=*m*, each square should be of one of 10 colours, and the flag should be «striped»: each horizontal row of the flag should contain squares of the same colour, and the colours of adjacent horizontal rows should be different. Berland's government asked you to find out whether their flag meets the new ISO standard. | The first line of the input contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), *n* — the amount of rows, *m* — the amount of columns on the flag of Berland. Then there follows the description of the flag: each of the following *n* lines contain *m* characters. Each character is a digit between 0 and 9, and stands for the colour of the corresponding square. | Output YES, if the flag meets the new ISO standard, and NO otherwise. | [
"3 3\n000\n111\n222\n",
"3 3\n000\n000\n111\n",
"3 3\n000\n111\n002\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 0 | [
{
"input": "3 3\n000\n111\n222",
"output": "YES"
},
{
"input": "3 3\n000\n000\n111",
"output": "NO"
},
{
"input": "3 3\n000\n111\n002",
"output": "NO"
},
{
"input": "10 10\n2222222222\n5555555555\n0000000000\n4444444444\n1111111111\n3333333393\n3333333333\n5555555555\n0000000... | 1,592,714,738 | 338 | PyPy 3 | OK | TESTS | 35 | 280 | 0 | class A:
def solve(self):
[n, m] = [int(x) for x in input().split(" ")]
flag = []
for i in range(n):
flag.append(input())
if any([len(set(x)) != 1 for x in flag]):
print("NO")
return
first_colors = [x[0] for x in flag]
if any([x == y for x, y in zip(first_colors, first_colors[1:])]):
print("NO")
return
print("YES")
A().solve()
| Title: Flag
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
According to a new ISO standard, a flag of every country should have a chequered field *n*<=×<=*m*, each square should be of one of 10 colours, and the flag should be «striped»: each horizontal row of the flag should contain squares of the same colour, and the colours of adjacent horizontal rows should be different. Berland's government asked you to find out whether their flag meets the new ISO standard.
Input Specification:
The first line of the input contains numbers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100), *n* — the amount of rows, *m* — the amount of columns on the flag of Berland. Then there follows the description of the flag: each of the following *n* lines contain *m* characters. Each character is a digit between 0 and 9, and stands for the colour of the corresponding square.
Output Specification:
Output YES, if the flag meets the new ISO standard, and NO otherwise.
Demo Input:
['3 3\n000\n111\n222\n', '3 3\n000\n000\n111\n', '3 3\n000\n111\n002\n']
Demo Output:
['YES\n', 'NO\n', 'NO\n']
Note:
none | ```python
class A:
def solve(self):
[n, m] = [int(x) for x in input().split(" ")]
flag = []
for i in range(n):
flag.append(input())
if any([len(set(x)) != 1 for x in flag]):
print("NO")
return
first_colors = [x[0] for x in flag]
if any([x == y for x, y in zip(first_colors, first_colors[1:])]):
print("NO")
return
print("YES")
A().solve()
``` | 3.93 |
999 | C | Alphabetic Removals | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | You are given a string $s$ consisting of $n$ lowercase Latin letters. Polycarp wants to remove exactly $k$ characters ($k \le n$) from the string $s$. Polycarp uses the following algorithm $k$ times:
- if there is at least one letter 'a', remove the leftmost occurrence and stop the algorithm, otherwise go to next item; - if there is at least one letter 'b', remove the leftmost occurrence and stop the algorithm, otherwise go to next item; - ... - remove the leftmost occurrence of the letter 'z' and stop the algorithm.
This algorithm removes a single letter from the string. Polycarp performs this algorithm exactly $k$ times, thus removing exactly $k$ characters.
Help Polycarp find the resulting string. | The first line of input contains two integers $n$ and $k$ ($1 \le k \le n \le 4 \cdot 10^5$) — the length of the string and the number of letters Polycarp will remove.
The second line contains the string $s$ consisting of $n$ lowercase Latin letters. | Print the string that will be obtained from $s$ after Polycarp removes exactly $k$ letters using the above algorithm $k$ times.
If the resulting string is empty, print nothing. It is allowed to print nothing or an empty line (line break). | [
"15 3\ncccaabababaccbc\n",
"15 9\ncccaabababaccbc\n",
"1 1\nu\n"
] | [
"cccbbabaccbc\n",
"cccccc\n",
""
] | none | 0 | [
{
"input": "15 3\ncccaabababaccbc",
"output": "cccbbabaccbc"
},
{
"input": "15 9\ncccaabababaccbc",
"output": "cccccc"
},
{
"input": "5 2\nzyzyx",
"output": "zzy"
},
{
"input": "4 3\nhack",
"output": "k"
},
{
"input": "4 3\nzzzz",
"output": "z"
},
{
"i... | 1,640,667,392 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 436 | 26,624,000 | n, k = map(int, input().split())
s=[*input()]
a = sorted([(x, y) for y, x in enumerate(s)])
for i in range(k):
s[a[i][1]] = ""
print("".join(s)) | Title: Alphabetic Removals
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a string $s$ consisting of $n$ lowercase Latin letters. Polycarp wants to remove exactly $k$ characters ($k \le n$) from the string $s$. Polycarp uses the following algorithm $k$ times:
- if there is at least one letter 'a', remove the leftmost occurrence and stop the algorithm, otherwise go to next item; - if there is at least one letter 'b', remove the leftmost occurrence and stop the algorithm, otherwise go to next item; - ... - remove the leftmost occurrence of the letter 'z' and stop the algorithm.
This algorithm removes a single letter from the string. Polycarp performs this algorithm exactly $k$ times, thus removing exactly $k$ characters.
Help Polycarp find the resulting string.
Input Specification:
The first line of input contains two integers $n$ and $k$ ($1 \le k \le n \le 4 \cdot 10^5$) — the length of the string and the number of letters Polycarp will remove.
The second line contains the string $s$ consisting of $n$ lowercase Latin letters.
Output Specification:
Print the string that will be obtained from $s$ after Polycarp removes exactly $k$ letters using the above algorithm $k$ times.
If the resulting string is empty, print nothing. It is allowed to print nothing or an empty line (line break).
Demo Input:
['15 3\ncccaabababaccbc\n', '15 9\ncccaabababaccbc\n', '1 1\nu\n']
Demo Output:
['cccbbabaccbc\n', 'cccccc\n', '']
Note:
none | ```python
n, k = map(int, input().split())
s=[*input()]
a = sorted([(x, y) for y, x in enumerate(s)])
for i in range(k):
s[a[i][1]] = ""
print("".join(s))
``` | 3 | |
363 | B | Fence | PROGRAMMING | 1,100 | [
"brute force",
"dp"
] | null | null | There is a fence in front of Polycarpus's home. The fence consists of *n* planks of the same width which go one after another from left to right. The height of the *i*-th plank is *h**i* meters, distinct planks can have distinct heights.
Polycarpus has bought a posh piano and is thinking about how to get it into the house. In order to carry out his plan, he needs to take exactly *k* consecutive planks from the fence. Higher planks are harder to tear off the fence, so Polycarpus wants to find such *k* consecutive planks that the sum of their heights is minimal possible.
Write the program that finds the indexes of *k* consecutive planks with minimal total height. Pay attention, the fence is not around Polycarpus's home, it is in front of home (in other words, the fence isn't cyclic). | The first line of the input contains integers *n* and *k* (1<=≤<=*n*<=≤<=1.5·105,<=1<=≤<=*k*<=≤<=*n*) — the number of planks in the fence and the width of the hole for the piano. The second line contains the sequence of integers *h*1,<=*h*2,<=...,<=*h**n* (1<=≤<=*h**i*<=≤<=100), where *h**i* is the height of the *i*-th plank of the fence. | Print such integer *j* that the sum of the heights of planks *j*, *j*<=+<=1, ..., *j*<=+<=*k*<=-<=1 is the minimum possible. If there are multiple such *j*'s, print any of them. | [
"7 3\n1 2 6 1 1 7 1\n"
] | [
"3\n"
] | In the sample, your task is to find three consecutive planks with the minimum sum of heights. In the given case three planks with indexes 3, 4 and 5 have the required attribute, their total height is 8. | 1,000 | [
{
"input": "7 3\n1 2 6 1 1 7 1",
"output": "3"
},
{
"input": "1 1\n100",
"output": "1"
},
{
"input": "2 1\n10 20",
"output": "1"
},
{
"input": "10 5\n1 2 3 1 2 2 3 1 4 5",
"output": "1"
},
{
"input": "10 2\n3 1 4 1 4 6 2 1 4 6",
"output": "7"
},
{
"inp... | 1,680,278,534 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 21 | 1,000 | 19,148,800 | n, k = map(int, input().split())
fence = list(map(int, input().split()))
min = (k*100)+1
pos = 0
x = fence[0]
if fence.count(x) == n:
print(1)
else:
i = 0
end = False
while i < ((n-k)+1) and end == False:
sum = 0
j = i
for j in range(i,k+i):
sum += fence[j]
if sum == k:
pos = i+1
end = True
elif sum < min:
min = sum
pos = i+1
i += 1
print(pos) | Title: Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a fence in front of Polycarpus's home. The fence consists of *n* planks of the same width which go one after another from left to right. The height of the *i*-th plank is *h**i* meters, distinct planks can have distinct heights.
Polycarpus has bought a posh piano and is thinking about how to get it into the house. In order to carry out his plan, he needs to take exactly *k* consecutive planks from the fence. Higher planks are harder to tear off the fence, so Polycarpus wants to find such *k* consecutive planks that the sum of their heights is minimal possible.
Write the program that finds the indexes of *k* consecutive planks with minimal total height. Pay attention, the fence is not around Polycarpus's home, it is in front of home (in other words, the fence isn't cyclic).
Input Specification:
The first line of the input contains integers *n* and *k* (1<=≤<=*n*<=≤<=1.5·105,<=1<=≤<=*k*<=≤<=*n*) — the number of planks in the fence and the width of the hole for the piano. The second line contains the sequence of integers *h*1,<=*h*2,<=...,<=*h**n* (1<=≤<=*h**i*<=≤<=100), where *h**i* is the height of the *i*-th plank of the fence.
Output Specification:
Print such integer *j* that the sum of the heights of planks *j*, *j*<=+<=1, ..., *j*<=+<=*k*<=-<=1 is the minimum possible. If there are multiple such *j*'s, print any of them.
Demo Input:
['7 3\n1 2 6 1 1 7 1\n']
Demo Output:
['3\n']
Note:
In the sample, your task is to find three consecutive planks with the minimum sum of heights. In the given case three planks with indexes 3, 4 and 5 have the required attribute, their total height is 8. | ```python
n, k = map(int, input().split())
fence = list(map(int, input().split()))
min = (k*100)+1
pos = 0
x = fence[0]
if fence.count(x) == n:
print(1)
else:
i = 0
end = False
while i < ((n-k)+1) and end == False:
sum = 0
j = i
for j in range(i,k+i):
sum += fence[j]
if sum == k:
pos = i+1
end = True
elif sum < min:
min = sum
pos = i+1
i += 1
print(pos)
``` | 0 | |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square. | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,665,688,169 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 4,198,400 | n,m,a = map(int, input().split())
if (n*m)%(a*a): print((n*m)//(a*a) + 1)
else: print( (n*m)//(a*a) ) | Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square.
Input Specification:
The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109).
Output Specification:
Write the needed number of flagstones.
Demo Input:
['6 6 4\n']
Demo Output:
['4\n']
Note:
none | ```python
n,m,a = map(int, input().split())
if (n*m)%(a*a): print((n*m)//(a*a) + 1)
else: print( (n*m)//(a*a) )
``` | 0 |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square. | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,673,851,231 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | import math
def theatresquare(n: int,m: int,a: int):
width=math.ceil(m/a)
hight=math.ceil(n/a)
if(m%a and n%a !=0):
print(width*hight)
else:
print((m/a)*(n/a))
n=int(input())
m=int(input())
a=int(input())
theatresquare(n,m,a)
| Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square.
Input Specification:
The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109).
Output Specification:
Write the needed number of flagstones.
Demo Input:
['6 6 4\n']
Demo Output:
['4\n']
Note:
none | ```python
import math
def theatresquare(n: int,m: int,a: int):
width=math.ceil(m/a)
hight=math.ceil(n/a)
if(m%a and n%a !=0):
print(width*hight)
else:
print((m/a)*(n/a))
n=int(input())
m=int(input())
a=int(input())
theatresquare(n,m,a)
``` | -1 |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word. | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,637,082,669 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | rer = input()
a=0
c=0
for b in rer :
if ord (b)>=ord('A') and ord (b)<= ord('Z'):
a=a+1
else:
c=c+1
if a>c:
rer=rer.upper()
if c>=a:
rer=rer.lower()
print(rer)
| Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word.
Input Specification:
The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100.
Output Specification:
Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one.
Demo Input:
['HoUse\n', 'ViP\n', 'maTRIx\n']
Demo Output:
['house\n', 'VIP\n', 'matrix\n']
Note:
none | ```python
rer = input()
a=0
c=0
for b in rer :
if ord (b)>=ord('A') and ord (b)<= ord('Z'):
a=a+1
else:
c=c+1
if a>c:
rer=rer.upper()
if c>=a:
rer=rer.lower()
print(rer)
``` | 3.977 |
1 | A | Theatre Square | PROGRAMMING | 1,000 | [
"math"
] | A. Theatre Square | 1 | 256 | Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square. | The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109). | Write the needed number of flagstones. | [
"6 6 4\n"
] | [
"4\n"
] | none | 0 | [
{
"input": "6 6 4",
"output": "4"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "2 1 1",
"output": "2"
},
{
"input": "1 2 1",
"output": "2"
},
{
"input": "2 2 1",
"output": "4"
},
{
"input": "2 1 2",
"output": "1"
},
{
"input": "1 1 3"... | 1,690,216,124 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | n, m, a = map(int, input().split())
num_flagstones_n = math.ceil(n / a)
num_flagstones_m = math.ceil(m / a)
print(num_flagstones_n * num_flagstones_m) | Title: Theatre Square
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Theatre Square in the capital city of Berland has a rectangular shape with the size *n*<=×<=*m* meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size *a*<=×<=*a*.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square.
Input Specification:
The input contains three positive integer numbers in the first line: *n*,<=<=*m* and *a* (1<=≤<=<=*n*,<=*m*,<=*a*<=≤<=109).
Output Specification:
Write the needed number of flagstones.
Demo Input:
['6 6 4\n']
Demo Output:
['4\n']
Note:
none | ```python
n, m, a = map(int, input().split())
num_flagstones_n = math.ceil(n / a)
num_flagstones_m = math.ceil(m / a)
print(num_flagstones_n * num_flagstones_m)
``` | -1 |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made like this: we write down the first and the last letter of a word and between them we write the number of letters between the first and the last letters. That number is in decimal system and doesn't contain any leading zeroes.
Thus, "localization" will be spelt as "l10n", and "internationalization» will be spelt as "i18n".
You are suggested to automatize the process of changing the words with abbreviations. At that all too long words should be replaced by the abbreviation and the words that are not too long should not undergo any changes. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,670,776,594 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 46 | 0 |
n=int(input())
for i in range(n):
l=input()
s=""
a=0
if len(l)>10:
for j in range(len(l)-2):
a+=1
s=s+l[0]+str(a)+l[len(l)-1]
print(s)
else:
print(l)
| Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made like this: we write down the first and the last letter of a word and between them we write the number of letters between the first and the last letters. That number is in decimal system and doesn't contain any leading zeroes.
Thus, "localization" will be spelt as "l10n", and "internationalization» will be spelt as "i18n".
You are suggested to automatize the process of changing the words with abbreviations. At that all too long words should be replaced by the abbreviation and the words that are not too long should not undergo any changes.
Input Specification:
The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters.
Output Specification:
Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data.
Demo Input:
['4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n']
Demo Output:
['word\nl10n\ni18n\np43s\n']
Note:
none | ```python
n=int(input())
for i in range(n):
l=input()
s=""
a=0
if len(l)>10:
for j in range(len(l)-2):
a+=1
s=s+l[0]+str(a)+l[len(l)-1]
print(s)
else:
print(l)
``` | 3.977 |
490 | A | Team Olympiad | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education). Hence, for each child we know value *t**i*:
- *t**i*<==<=1, if the *i*-th child is good at programming, - *t**i*<==<=2, if the *i*-th child is good at maths, - *t**i*<==<=3, if the *i*-th child is good at PE
Each child happens to be good at exactly one of these three subjects.
The Team Scientific Decathlon Olympias requires teams of three students. The school teachers decided that the teams will be composed of three children that are good at different subjects. That is, each team must have one mathematician, one programmer and one sportsman. Of course, each child can be a member of no more than one team.
What is the maximum number of teams that the school will be able to present at the Olympiad? How should the teams be formed for that? | The first line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of children in the school. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=3), where *t**i* describes the skill of the *i*-th child. | In the first line output integer *w* — the largest possible number of teams.
Then print *w* lines, containing three numbers in each line. Each triple represents the indexes of the children forming the team. You can print both the teams, and the numbers in the triplets in any order. The children are numbered from 1 to *n* in the order of their appearance in the input. Each child must participate in no more than one team. If there are several solutions, print any of them.
If no teams can be compiled, print the only line with value *w* equal to 0. | [
"7\n1 3 1 3 2 1 2\n",
"4\n2 1 1 2\n"
] | [
"2\n3 5 2\n6 7 4\n",
"0\n"
] | none | 500 | [
{
"input": "7\n1 3 1 3 2 1 2",
"output": "2\n3 5 2\n6 7 4"
},
{
"input": "4\n2 1 1 2",
"output": "0"
},
{
"input": "1\n2",
"output": "0"
},
{
"input": "2\n3 1",
"output": "0"
},
{
"input": "3\n2 1 2",
"output": "0"
},
{
"input": "3\n1 2 3",
"output... | 1,667,135,902 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 46 | 0 | input()
a=[[],[],[]]
for i, x in enumerate(input().split(),1):
a[int(x)-1]+=[i]
print(min(map(len,a)))
for x in zip(*a):print(*x) | Title: Team Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The School №0 of the capital of Berland has *n* children studying in it. All the children in this school are gifted: some of them are good at programming, some are good at maths, others are good at PE (Physical Education). Hence, for each child we know value *t**i*:
- *t**i*<==<=1, if the *i*-th child is good at programming, - *t**i*<==<=2, if the *i*-th child is good at maths, - *t**i*<==<=3, if the *i*-th child is good at PE
Each child happens to be good at exactly one of these three subjects.
The Team Scientific Decathlon Olympias requires teams of three students. The school teachers decided that the teams will be composed of three children that are good at different subjects. That is, each team must have one mathematician, one programmer and one sportsman. Of course, each child can be a member of no more than one team.
What is the maximum number of teams that the school will be able to present at the Olympiad? How should the teams be formed for that?
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of children in the school. The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=3), where *t**i* describes the skill of the *i*-th child.
Output Specification:
In the first line output integer *w* — the largest possible number of teams.
Then print *w* lines, containing three numbers in each line. Each triple represents the indexes of the children forming the team. You can print both the teams, and the numbers in the triplets in any order. The children are numbered from 1 to *n* in the order of their appearance in the input. Each child must participate in no more than one team. If there are several solutions, print any of them.
If no teams can be compiled, print the only line with value *w* equal to 0.
Demo Input:
['7\n1 3 1 3 2 1 2\n', '4\n2 1 1 2\n']
Demo Output:
['2\n3 5 2\n6 7 4\n', '0\n']
Note:
none | ```python
input()
a=[[],[],[]]
for i, x in enumerate(input().split(),1):
a[int(x)-1]+=[i]
print(min(map(len,a)))
for x in zip(*a):print(*x)
``` | 3 | |
44 | I | Toys | PROGRAMMING | 2,300 | [
"brute force",
"combinatorics"
] | I. Toys | 5 | 256 | Little Masha loves arranging her toys into piles on the floor. And she also hates it when somebody touches her toys. One day Masha arranged all her *n* toys into several piles and then her elder brother Sasha came and gathered all the piles into one. Having seen it, Masha got very upset and started crying. Sasha still can't calm Masha down and mom is going to come home soon and punish Sasha for having made Masha crying. That's why he decides to restore the piles' arrangement. However, he doesn't remember at all the way the toys used to lie. Of course, Masha remembers it, but she can't talk yet and can only help Sasha by shouting happily when he arranges the toys in the way they used to lie. That means that Sasha will have to arrange the toys in every possible way until Masha recognizes the needed arrangement. The relative position of the piles and toys in every pile is irrelevant, that's why the two ways of arranging the toys are considered different if can be found two such toys that when arranged in the first way lie in one and the same pile and do not if arranged in the second way. Sasha is looking for the fastest way of trying all the ways because mom will come soon. With every action Sasha can take a toy from any pile and move it to any other pile (as a result a new pile may appear or the old one may disappear). Sasha wants to find the sequence of actions as a result of which all the pile arrangement variants will be tried exactly one time each. Help Sasha. As we remember, initially all the toys are located in one pile. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=10) — the number of toys. | In the first line print the number of different variants of arrangement of toys into piles. Then print all the ways of arranging toys into piles in the order in which Sasha should try them (i.e. every next way must result from the previous one through the operation described in the statement). Every way should be printed in the following format. In every pile the toys should be arranged in ascending order of the numbers. Then the piles should be sorted in ascending order of the numbers of the first toys there. Output every way on a single line. Cf. the example to specify the output data format. If the solution is not unique, output any of them. | [
"3\n"
] | [
"5\n{1,2,3}\n{1,2},{3}\n{1},{2,3}\n{1},{2},{3}\n{1,3},{2}"
] | none | 0 | [
{
"input": "3",
"output": "5\n{1,2,3}\n{1,2},{3}\n{1},{2,3}\n{1},{2},{3}\n{1,3},{2}"
},
{
"input": "1",
"output": "1\n{1}"
},
{
"input": "2",
"output": "2\n{1,2}\n{1},{2}"
},
{
"input": "4",
"output": "15\n{1,2,3,4}\n{1,2,3},{4}\n{1,2},{3,4}\n{1,2},{3},{4}\n{1,2,4},{3}\n{... | 1,675,682,860 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | from itertools import permutations
x = int(input())
l = list(permutations(range(1, x)))
print(len(l))
| Title: Toys
Time Limit: 5 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Masha loves arranging her toys into piles on the floor. And she also hates it when somebody touches her toys. One day Masha arranged all her *n* toys into several piles and then her elder brother Sasha came and gathered all the piles into one. Having seen it, Masha got very upset and started crying. Sasha still can't calm Masha down and mom is going to come home soon and punish Sasha for having made Masha crying. That's why he decides to restore the piles' arrangement. However, he doesn't remember at all the way the toys used to lie. Of course, Masha remembers it, but she can't talk yet and can only help Sasha by shouting happily when he arranges the toys in the way they used to lie. That means that Sasha will have to arrange the toys in every possible way until Masha recognizes the needed arrangement. The relative position of the piles and toys in every pile is irrelevant, that's why the two ways of arranging the toys are considered different if can be found two such toys that when arranged in the first way lie in one and the same pile and do not if arranged in the second way. Sasha is looking for the fastest way of trying all the ways because mom will come soon. With every action Sasha can take a toy from any pile and move it to any other pile (as a result a new pile may appear or the old one may disappear). Sasha wants to find the sequence of actions as a result of which all the pile arrangement variants will be tried exactly one time each. Help Sasha. As we remember, initially all the toys are located in one pile.
Input Specification:
The first line contains an integer *n* (1<=≤<=*n*<=≤<=10) — the number of toys.
Output Specification:
In the first line print the number of different variants of arrangement of toys into piles. Then print all the ways of arranging toys into piles in the order in which Sasha should try them (i.e. every next way must result from the previous one through the operation described in the statement). Every way should be printed in the following format. In every pile the toys should be arranged in ascending order of the numbers. Then the piles should be sorted in ascending order of the numbers of the first toys there. Output every way on a single line. Cf. the example to specify the output data format. If the solution is not unique, output any of them.
Demo Input:
['3\n']
Demo Output:
['5\n{1,2,3}\n{1,2},{3}\n{1},{2,3}\n{1},{2},{3}\n{1,3},{2}']
Note:
none | ```python
from itertools import permutations
x = int(input())
l = list(permutations(range(1, x)))
print(len(l))
``` | 0 |
979 | A | Pizza, Pizza, Pizza!!! | PROGRAMMING | 1,000 | [
"math"
] | null | null | Katie, Kuro and Shiro are best friends. They have known each other since kindergarten. That's why they often share everything with each other and work together on some very hard problems.
Today is Shiro's birthday. She really loves pizza so she wants to invite her friends to the pizza restaurant near her house to celebrate her birthday, including her best friends Katie and Kuro.
She has ordered a very big round pizza, in order to serve her many friends. Exactly $n$ of Shiro's friends are here. That's why she has to divide the pizza into $n + 1$ slices (Shiro also needs to eat). She wants the slices to be exactly the same size and shape. If not, some of her friends will get mad and go home early, and the party will be over.
Shiro is now hungry. She wants to cut the pizza with minimum of straight cuts. A cut is a straight segment, it might have ends inside or outside the pizza. But she is too lazy to pick up the calculator.
As usual, she will ask Katie and Kuro for help. But they haven't come yet. Could you help Shiro with this problem? | A single line contains one non-negative integer $n$ ($0 \le n \leq 10^{18}$) — the number of Shiro's friends. The circular pizza has to be sliced into $n + 1$ pieces. | A single integer — the number of straight cuts Shiro needs. | [
"3\n",
"4\n"
] | [
"2",
"5"
] | To cut the round pizza into quarters one has to make two cuts through the center with angle $90^{\circ}$ between them.
To cut the round pizza into five equal parts one has to make five cuts. | 500 | [
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "5"
},
{
"input": "10",
"output": "11"
},
{
"input": "10000000000",
"output": "10000000001"
},
{
"input": "1234567891",
"output": "617283946"
},
{
"input": "7509213957",
"output": "37546069... | 1,656,697,049 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 28 | 108 | 512,000 | s = int(input())
m = s+1
if m % 2 :
print(m)
else:print(m//2) | Title: Pizza, Pizza, Pizza!!!
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Katie, Kuro and Shiro are best friends. They have known each other since kindergarten. That's why they often share everything with each other and work together on some very hard problems.
Today is Shiro's birthday. She really loves pizza so she wants to invite her friends to the pizza restaurant near her house to celebrate her birthday, including her best friends Katie and Kuro.
She has ordered a very big round pizza, in order to serve her many friends. Exactly $n$ of Shiro's friends are here. That's why she has to divide the pizza into $n + 1$ slices (Shiro also needs to eat). She wants the slices to be exactly the same size and shape. If not, some of her friends will get mad and go home early, and the party will be over.
Shiro is now hungry. She wants to cut the pizza with minimum of straight cuts. A cut is a straight segment, it might have ends inside or outside the pizza. But she is too lazy to pick up the calculator.
As usual, she will ask Katie and Kuro for help. But they haven't come yet. Could you help Shiro with this problem?
Input Specification:
A single line contains one non-negative integer $n$ ($0 \le n \leq 10^{18}$) — the number of Shiro's friends. The circular pizza has to be sliced into $n + 1$ pieces.
Output Specification:
A single integer — the number of straight cuts Shiro needs.
Demo Input:
['3\n', '4\n']
Demo Output:
['2', '5']
Note:
To cut the round pizza into quarters one has to make two cuts through the center with angle $90^{\circ}$ between them.
To cut the round pizza into five equal parts one has to make five cuts. | ```python
s = int(input())
m = s+1
if m % 2 :
print(m)
else:print(m//2)
``` | 0 | |
867 | A | Between the Offices | PROGRAMMING | 800 | [
"implementation"
] | null | null | As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't remember the number of flights you have made in either direction. However, for each of the last *n* days you know whether you were in San Francisco office or in Seattle office. You always fly at nights, so you never were at both offices on the same day. Given this information, determine if you flew more times from Seattle to San Francisco during the last *n* days, or not. | The first line of input contains single integer *n* (2<=≤<=*n*<=≤<=100) — the number of days.
The second line contains a string of length *n* consisting of only capital 'S' and 'F' letters. If the *i*-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given in chronological order, i.e. today is the last day in this sequence. | Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower). | [
"4\nFSSF\n",
"2\nSF\n",
"10\nFFFFFFFFFF\n",
"10\nSSFFSFFSFF\n"
] | [
"NO\n",
"YES\n",
"NO\n",
"YES\n"
] | In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you stayed the whole period in San Francisco, so the answer is "NO".
In the fourth example if you replace 'S' with ones, and 'F' with zeros, you'll get the first few digits of π in binary representation. Not very useful information though. | 500 | [
{
"input": "4\nFSSF",
"output": "NO"
},
{
"input": "2\nSF",
"output": "YES"
},
{
"input": "10\nFFFFFFFFFF",
"output": "NO"
},
{
"input": "10\nSSFFSFFSFF",
"output": "YES"
},
{
"input": "20\nSFSFFFFSSFFFFSSSSFSS",
"output": "NO"
},
{
"input": "20\nSSFFF... | 1,562,326,415 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 249 | 1,638,400 | import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,queue,copy
sys.setrecursionlimit(10**7)
inf=10**20
mod=10**9+7
dd=[(-1,0),(0,1),(1,0),(0,-1)]
ddn=[(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def I(): return int(sys.stdin.readline())
def LS(): return sys.stdin.readline().split()
def S(): return input()
def main():
n=I()
s=S()
stof=0
ftos=0
for i in range(n-1):
if s[i]!=s[i+1]:
if s[i]=='S':
stof+=1
else:
ftos+=1
if stof>ftos:
return 'YES'
return 'NO'
print(main())
| Title: Between the Offices
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you may know, MemSQL has American offices in both San Francisco and Seattle. Being a manager in the company, you travel a lot between the two cities, always by plane.
You prefer flying from Seattle to San Francisco than in the other direction, because it's warmer in San Francisco. You are so busy that you don't remember the number of flights you have made in either direction. However, for each of the last *n* days you know whether you were in San Francisco office or in Seattle office. You always fly at nights, so you never were at both offices on the same day. Given this information, determine if you flew more times from Seattle to San Francisco during the last *n* days, or not.
Input Specification:
The first line of input contains single integer *n* (2<=≤<=*n*<=≤<=100) — the number of days.
The second line contains a string of length *n* consisting of only capital 'S' and 'F' letters. If the *i*-th letter is 'S', then you were in Seattle office on that day. Otherwise you were in San Francisco. The days are given in chronological order, i.e. today is the last day in this sequence.
Output Specification:
Print "YES" if you flew more times from Seattle to San Francisco, and "NO" otherwise.
You can print each letter in any case (upper or lower).
Demo Input:
['4\nFSSF\n', '2\nSF\n', '10\nFFFFFFFFFF\n', '10\nSSFFSFFSFF\n']
Demo Output:
['NO\n', 'YES\n', 'NO\n', 'YES\n']
Note:
In the first example you were initially at San Francisco, then flew to Seattle, were there for two days and returned to San Francisco. You made one flight in each direction, so the answer is "NO".
In the second example you just flew from Seattle to San Francisco, so the answer is "YES".
In the third example you stayed the whole period in San Francisco, so the answer is "NO".
In the fourth example if you replace 'S' with ones, and 'F' with zeros, you'll get the first few digits of π in binary representation. Not very useful information though. | ```python
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,queue,copy
sys.setrecursionlimit(10**7)
inf=10**20
mod=10**9+7
dd=[(-1,0),(0,1),(1,0),(0,-1)]
ddn=[(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def I(): return int(sys.stdin.readline())
def LS(): return sys.stdin.readline().split()
def S(): return input()
def main():
n=I()
s=S()
stof=0
ftos=0
for i in range(n-1):
if s[i]!=s[i+1]:
if s[i]=='S':
stof+=1
else:
ftos+=1
if stof>ftos:
return 'YES'
return 'NO'
print(main())
``` | 3 | |
1,004 | B | Sonya and Exhibition | PROGRAMMING | 1,300 | [
"constructive algorithms",
"greedy",
"implementation",
"math"
] | null | null | Sonya decided to organize an exhibition of flowers. Since the girl likes only roses and lilies, she decided that only these two kinds of flowers should be in this exhibition.
There are $n$ flowers in a row in the exhibition. Sonya can put either a rose or a lily in the $i$-th position. Thus each of $n$ positions should contain exactly one flower: a rose or a lily.
She knows that exactly $m$ people will visit this exhibition. The $i$-th visitor will visit all flowers from $l_i$ to $r_i$ inclusive. The girl knows that each segment has its own beauty that is equal to the product of the number of roses and the number of lilies.
Sonya wants her exhibition to be liked by a lot of people. That is why she wants to put the flowers in such way that the sum of beauties of all segments would be maximum possible. | The first line contains two integers $n$ and $m$ ($1\leq n, m\leq 10^3$) — the number of flowers and visitors respectively.
Each of the next $m$ lines contains two integers $l_i$ and $r_i$ ($1\leq l_i\leq r_i\leq n$), meaning that $i$-th visitor will visit all flowers from $l_i$ to $r_i$ inclusive. | Print the string of $n$ characters. The $i$-th symbol should be «0» if you want to put a rose in the $i$-th position, otherwise «1» if you want to put a lily.
If there are multiple answers, print any. | [
"5 3\n1 3\n2 4\n2 5\n",
"6 3\n5 6\n1 4\n4 6\n"
] | [
"01100",
"110010"
] | In the first example, Sonya can put roses in the first, fourth, and fifth positions, and lilies in the second and third positions;
- in the segment $[1\ldots3]$, there are one rose and two lilies, so the beauty is equal to $1\cdot 2=2$; - in the segment $[2\ldots4]$, there are one rose and two lilies, so the beauty is equal to $1\cdot 2=2$; - in the segment $[2\ldots5]$, there are two roses and two lilies, so the beauty is equal to $2\cdot 2=4$.
The total beauty is equal to $2+2+4=8$.
In the second example, Sonya can put roses in the third, fourth, and sixth positions, and lilies in the first, second, and fifth positions;
- in the segment $[5\ldots6]$, there are one rose and one lily, so the beauty is equal to $1\cdot 1=1$; - in the segment $[1\ldots4]$, there are two roses and two lilies, so the beauty is equal to $2\cdot 2=4$; - in the segment $[4\ldots6]$, there are two roses and one lily, so the beauty is equal to $2\cdot 1=2$.
The total beauty is equal to $1+4+2=7$. | 1,000 | [
{
"input": "5 3\n1 3\n2 4\n2 5",
"output": "01010"
},
{
"input": "6 3\n5 6\n1 4\n4 6",
"output": "010101"
},
{
"input": "10 4\n3 3\n1 6\n9 9\n10 10",
"output": "0101010101"
},
{
"input": "1 1\n1 1",
"output": "0"
},
{
"input": "1000 10\n3 998\n2 1000\n1 999\n2 100... | 1,530,810,459 | 1,959 | Python 3 | WRONG_ANSWER | PRETESTS | 1 | 109 | 0 | def beauty(distances, constelation):
beat = 0
for left, right in distances:
lilies = 0
roses = 0
for i in range(left - 1, right):
if constelation[i] == "0":
lilies += 1
else:
roses += 1
beat += lilies * roses
return beat
flowers, visitors = map(int, input().split(" "))
left_right = []
constelation = "0" * flowers
for i in range(visitors):
left_right.append(list(map(int, input().split(" "))))
b = 0
for i in range(flowers):
new_constelation = constelation[:i] + "1" + constelation[i + 1:]
new_b = beauty(left_right, new_constelation)
if new_b > b:
constelation = new_constelation[:]
b = new_b
print(constelation) | Title: Sonya and Exhibition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sonya decided to organize an exhibition of flowers. Since the girl likes only roses and lilies, she decided that only these two kinds of flowers should be in this exhibition.
There are $n$ flowers in a row in the exhibition. Sonya can put either a rose or a lily in the $i$-th position. Thus each of $n$ positions should contain exactly one flower: a rose or a lily.
She knows that exactly $m$ people will visit this exhibition. The $i$-th visitor will visit all flowers from $l_i$ to $r_i$ inclusive. The girl knows that each segment has its own beauty that is equal to the product of the number of roses and the number of lilies.
Sonya wants her exhibition to be liked by a lot of people. That is why she wants to put the flowers in such way that the sum of beauties of all segments would be maximum possible.
Input Specification:
The first line contains two integers $n$ and $m$ ($1\leq n, m\leq 10^3$) — the number of flowers and visitors respectively.
Each of the next $m$ lines contains two integers $l_i$ and $r_i$ ($1\leq l_i\leq r_i\leq n$), meaning that $i$-th visitor will visit all flowers from $l_i$ to $r_i$ inclusive.
Output Specification:
Print the string of $n$ characters. The $i$-th symbol should be «0» if you want to put a rose in the $i$-th position, otherwise «1» if you want to put a lily.
If there are multiple answers, print any.
Demo Input:
['5 3\n1 3\n2 4\n2 5\n', '6 3\n5 6\n1 4\n4 6\n']
Demo Output:
['01100', '110010']
Note:
In the first example, Sonya can put roses in the first, fourth, and fifth positions, and lilies in the second and third positions;
- in the segment $[1\ldots3]$, there are one rose and two lilies, so the beauty is equal to $1\cdot 2=2$; - in the segment $[2\ldots4]$, there are one rose and two lilies, so the beauty is equal to $1\cdot 2=2$; - in the segment $[2\ldots5]$, there are two roses and two lilies, so the beauty is equal to $2\cdot 2=4$.
The total beauty is equal to $2+2+4=8$.
In the second example, Sonya can put roses in the third, fourth, and sixth positions, and lilies in the first, second, and fifth positions;
- in the segment $[5\ldots6]$, there are one rose and one lily, so the beauty is equal to $1\cdot 1=1$; - in the segment $[1\ldots4]$, there are two roses and two lilies, so the beauty is equal to $2\cdot 2=4$; - in the segment $[4\ldots6]$, there are two roses and one lily, so the beauty is equal to $2\cdot 1=2$.
The total beauty is equal to $1+4+2=7$. | ```python
def beauty(distances, constelation):
beat = 0
for left, right in distances:
lilies = 0
roses = 0
for i in range(left - 1, right):
if constelation[i] == "0":
lilies += 1
else:
roses += 1
beat += lilies * roses
return beat
flowers, visitors = map(int, input().split(" "))
left_right = []
constelation = "0" * flowers
for i in range(visitors):
left_right.append(list(map(int, input().split(" "))))
b = 0
for i in range(flowers):
new_constelation = constelation[:i] + "1" + constelation[i + 1:]
new_b = beauty(left_right, new_constelation)
if new_b > b:
constelation = new_constelation[:]
b = new_b
print(constelation)
``` | 0 | |
61 | A | Ultra-Fast Mathematician | PROGRAMMING | 800 | [
"implementation"
] | A. Ultra-Fast Mathematician | 2 | 256 | Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do calculations faster than him. As a result he made a very great contest and asked every one to come and take part.
In his contest he gave the contestants many different pairs of numbers. Each number is made from digits 0 or 1. The contestants should write a new number corresponding to the given pair of numbers. The rule is simple: The *i*-th digit of the answer is 1 if and only if the *i*-th digit of the two given numbers differ. In the other case the *i*-th digit of the answer is 0.
Shapur made many numbers and first tried his own speed. He saw that he can perform these operations on numbers of length ∞ (length of a number is number of digits in it) in a glance! He always gives correct answers so he expects the contestants to give correct answers, too. He is a good fellow so he won't give anyone very big numbers and he always gives one person numbers of same length.
Now you are going to take part in Shapur's contest. See if you are faster and more accurate. | There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100. | Write one line — the corresponding answer. Do not omit the leading 0s. | [
"1010100\n0100101\n",
"000\n111\n",
"1110\n1010\n",
"01110\n01100\n"
] | [
"1110001\n",
"111\n",
"0100\n",
"00010\n"
] | none | 500 | [
{
"input": "1010100\n0100101",
"output": "1110001"
},
{
"input": "000\n111",
"output": "111"
},
{
"input": "1110\n1010",
"output": "0100"
},
{
"input": "01110\n01100",
"output": "00010"
},
{
"input": "011101\n000001",
"output": "011100"
},
{
"input": "... | 1,566,472,732 | 2,147,483,647 | Python 3 | OK | TESTS | 102 | 124 | 0 | s1=input();s2=input();
for x,y in zip(s1,s2):
print('1' if x!=y else '0',end='')
print()
| Title: Ultra-Fast Mathematician
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Shapur was an extremely gifted student. He was great at everything including Combinatorics, Algebra, Number Theory, Geometry, Calculus, etc. He was not only smart but extraordinarily fast! He could manage to sum 1018 numbers in a single second.
One day in 230 AD Shapur was trying to find out if any one can possibly do calculations faster than him. As a result he made a very great contest and asked every one to come and take part.
In his contest he gave the contestants many different pairs of numbers. Each number is made from digits 0 or 1. The contestants should write a new number corresponding to the given pair of numbers. The rule is simple: The *i*-th digit of the answer is 1 if and only if the *i*-th digit of the two given numbers differ. In the other case the *i*-th digit of the answer is 0.
Shapur made many numbers and first tried his own speed. He saw that he can perform these operations on numbers of length ∞ (length of a number is number of digits in it) in a glance! He always gives correct answers so he expects the contestants to give correct answers, too. He is a good fellow so he won't give anyone very big numbers and he always gives one person numbers of same length.
Now you are going to take part in Shapur's contest. See if you are faster and more accurate.
Input Specification:
There are two lines in each input. Each of them contains a single number. It is guaranteed that the numbers are made from 0 and 1 only and that their length is same. The numbers may start with 0. The length of each number doesn't exceed 100.
Output Specification:
Write one line — the corresponding answer. Do not omit the leading 0s.
Demo Input:
['1010100\n0100101\n', '000\n111\n', '1110\n1010\n', '01110\n01100\n']
Demo Output:
['1110001\n', '111\n', '0100\n', '00010\n']
Note:
none | ```python
s1=input();s2=input();
for x,y in zip(s1,s2):
print('1' if x!=y else '0',end='')
print()
``` | 3.969 |
612 | B | HDD is Outdated Technology | PROGRAMMING | 1,200 | [
"implementation",
"math"
] | null | null | HDD hard drives group data by sectors. All files are split to fragments and each of them are written in some sector of hard drive. Note the fragments can be written in sectors in arbitrary order.
One of the problems of HDD hard drives is the following: the magnetic head should move from one sector to another to read some file.
Find the time need to read file split to *n* fragments. The *i*-th sector contains the *f**i*-th fragment of the file (1<=≤<=*f**i*<=≤<=*n*). Note different sectors contains the different fragments. At the start the magnetic head is in the position that contains the first fragment. The file are reading in the following manner: at first the first fragment is read, then the magnetic head moves to the sector that contains the second fragment, then the second fragment is read and so on until the *n*-th fragment is read. The fragments are read in the order from the first to the *n*-th.
It takes |*a*<=-<=*b*| time units to move the magnetic head from the sector *a* to the sector *b*. Reading a fragment takes no time. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=2·105) — the number of fragments.
The second line contains *n* different integers *f**i* (1<=≤<=*f**i*<=≤<=*n*) — the number of the fragment written in the *i*-th sector. | Print the only integer — the number of time units needed to read the file. | [
"3\n3 1 2\n",
"5\n1 3 5 4 2\n"
] | [
"3\n",
"10\n"
] | In the second example the head moves in the following way:
- 1->2 means movement from the sector 1 to the sector 5, i.e. it takes 4 time units - 2->3 means movement from the sector 5 to the sector 2, i.e. it takes 3 time units - 3->4 means movement from the sector 2 to the sector 4, i.e. it takes 2 time units - 4->5 means movement from the sector 4 to the sector 3, i.e. it takes 1 time units
So the answer to the second example is 4 + 3 + 2 + 1 = 10. | 0 | [
{
"input": "3\n3 1 2",
"output": "3"
},
{
"input": "5\n1 3 5 4 2",
"output": "10"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "1\n1",
"output": "0"
},
{
"input": "10\n8 2 10 3 4 6 1 7 9 5",
"output": "40"
... | 1,693,745,259 | 2,147,483,647 | PyPy 3 | OK | TESTS | 24 | 233 | 18,841,600 | n = int(input())
arr = [None] * n
L = list(map(int, input().split()))
for k, v in enumerate(L):
arr[v - 1] = k
res = 0
for i in range(n - 1):
res += abs(arr[i] - arr[i + 1])
print(res)
| Title: HDD is Outdated Technology
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
HDD hard drives group data by sectors. All files are split to fragments and each of them are written in some sector of hard drive. Note the fragments can be written in sectors in arbitrary order.
One of the problems of HDD hard drives is the following: the magnetic head should move from one sector to another to read some file.
Find the time need to read file split to *n* fragments. The *i*-th sector contains the *f**i*-th fragment of the file (1<=≤<=*f**i*<=≤<=*n*). Note different sectors contains the different fragments. At the start the magnetic head is in the position that contains the first fragment. The file are reading in the following manner: at first the first fragment is read, then the magnetic head moves to the sector that contains the second fragment, then the second fragment is read and so on until the *n*-th fragment is read. The fragments are read in the order from the first to the *n*-th.
It takes |*a*<=-<=*b*| time units to move the magnetic head from the sector *a* to the sector *b*. Reading a fragment takes no time.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=2·105) — the number of fragments.
The second line contains *n* different integers *f**i* (1<=≤<=*f**i*<=≤<=*n*) — the number of the fragment written in the *i*-th sector.
Output Specification:
Print the only integer — the number of time units needed to read the file.
Demo Input:
['3\n3 1 2\n', '5\n1 3 5 4 2\n']
Demo Output:
['3\n', '10\n']
Note:
In the second example the head moves in the following way:
- 1->2 means movement from the sector 1 to the sector 5, i.e. it takes 4 time units - 2->3 means movement from the sector 5 to the sector 2, i.e. it takes 3 time units - 3->4 means movement from the sector 2 to the sector 4, i.e. it takes 2 time units - 4->5 means movement from the sector 4 to the sector 3, i.e. it takes 1 time units
So the answer to the second example is 4 + 3 + 2 + 1 = 10. | ```python
n = int(input())
arr = [None] * n
L = list(map(int, input().split()))
for k, v in enumerate(L):
arr[v - 1] = k
res = 0
for i in range(n - 1):
res += abs(arr[i] - arr[i + 1])
print(res)
``` | 3 | |
739 | E | Gosha is hunting | PROGRAMMING | 3,000 | [
"brute force",
"data structures",
"dp",
"flows",
"math",
"probabilities",
"sortings"
] | null | null | Gosha is hunting. His goal is to catch as many Pokemons as possible. Gosha has *a* Poke Balls and *b* Ultra Balls. There are *n* Pokemons. They are numbered 1 through *n*. Gosha knows that if he throws a Poke Ball at the *i*-th Pokemon he catches it with probability *p**i*. If he throws an Ultra Ball at the *i*-th Pokemon he catches it with probability *u**i*. He can throw at most one Ball of each type at any Pokemon.
The hunting proceeds as follows: at first, Gosha chooses no more than *a* Pokemons at which he will throw Poke Balls and no more than *b* Pokemons at which he will throw Ultra Balls. After that, he throws the chosen Balls at the chosen Pokemons. If he throws both Ultra Ball and Poke Ball at some Pokemon, he is caught if and only if he is caught by any of these Balls. The outcome of a throw doesn't depend on the other throws.
Gosha would like to know what is the expected number of the Pokemons he catches if he acts in an optimal way. In other words, he would like to know the maximum possible expected number of Pokemons can catch. | The first line contains three integers *n*, *a* and *b* (2<=≤<=*n*<=≤<=2000, 0<=≤<=*a*,<=*b*<=≤<=*n*) — the number of Pokemons, the number of Poke Balls and the number of Ultra Balls.
The second line contains *n* real values *p*1,<=*p*2,<=...,<=*p**n* (0<=≤<=*p**i*<=≤<=1), where *p**i* is the probability of catching the *i*-th Pokemon if Gosha throws a Poke Ball to it.
The third line contains *n* real values *u*1,<=*u*2,<=...,<=*u**n* (0<=≤<=*u**i*<=≤<=1), where *u**i* is the probability of catching the *i*-th Pokemon if Gosha throws an Ultra Ball to it.
All the probabilities are given with exactly three digits after the decimal separator. | Print the maximum possible expected number of Pokemons Gosha can catch. The answer is considered correct if it's absolute or relative error doesn't exceed 10<=-<=4. | [
"3 2 2\n1.000 0.000 0.500\n0.000 1.000 0.500\n",
"4 1 3\n0.100 0.500 0.500 0.600\n0.100 0.500 0.900 0.400\n",
"3 2 0\n0.412 0.198 0.599\n0.612 0.987 0.443\n"
] | [
"2.75\n",
"2.16\n",
"1.011"
] | none | 2,500 | [
{
"input": "3 2 2\n1.000 0.000 0.500\n0.000 1.000 0.500",
"output": "2.75"
},
{
"input": "4 1 3\n0.100 0.500 0.500 0.600\n0.100 0.500 0.900 0.400",
"output": "2.1600000000000001421"
},
{
"input": "3 2 0\n0.412 0.198 0.599\n0.612 0.987 0.443",
"output": "1.0109999999999998987"
},
... | 1,674,602,006 | 2,147,483,647 | PyPy 3 | OK | TESTS | 94 | 3,634 | 11,161,600 | import sys
readline=sys.stdin.readline
def Bisect_Float(ok,ng,is_ok,eps=1e-12,cnt=0):
if cnt:
for _ in range(cnt):
mid=(ok+ng)/2
if is_ok(mid):
ok=mid
else:
ng=mid
else:
while abs(ok-ng)/max(ok,ng,1)>eps:
mid=(ok+ng)/2
if is_ok(mid):
ok=mid
else:
ng=mid
return ok
N,A,B=map(int,readline().split())
inf=4
maximum_slope=inf
minimum_slope=-inf
P=list(map(float,readline().split()))
U=list(map(float,readline().split()))
def is_ok(c):
dp=[0]*(A+1)
cnt=[0]*(A+1)
for n in range(1,N+1):
prev_dp,prev_cnt=dp,cnt
dp=[0]*(A+1)
cnt=[0]*(A+1)
dp[0],cnt[0]=max((prev_dp[0],prev_cnt[0]),(prev_dp[0]+U[n-1]-c,prev_cnt[0]+1))
for a in range(1,A+1):
dp[a],cnt[a]=max((prev_dp[a],prev_cnt[a]),(prev_dp[a]+U[n-1]-c,prev_cnt[a]+1),(prev_dp[a-1]+P[n-1],prev_cnt[a-1]),(prev_dp[a-1]+P[n-1]+U[n-1]-P[n-1]*U[n-1]-c,prev_cnt[a-1]+1))
return cnt[A]>=B
c=Bisect_Float(minimum_slope,maximum_slope,is_ok,1e-6)
dp=[0]*(A+1)
cnt=[0]*(A+1)
for n in range(1,N+1):
prev_dp,prev_cnt=dp,cnt
dp=[0]*(A+1)
cnt=[0]*(A+1)
dp[0],cnt[0]=max((prev_dp[0],prev_cnt[0]),(prev_dp[0]+U[n-1]-c,prev_cnt[0]+1))
for a in range(1,A+1):
dp[a],cnt[a]=max((prev_dp[a],prev_cnt[a]),(prev_dp[a]+U[n-1]-c,prev_cnt[a]+1),(prev_dp[a-1]+P[n-1],prev_cnt[a-1]),(prev_dp[a-1]+P[n-1]+U[n-1]-P[n-1]*U[n-1]-c,prev_cnt[a-1]+1))
ans=dp[A]+c*B
print(ans) | Title: Gosha is hunting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Gosha is hunting. His goal is to catch as many Pokemons as possible. Gosha has *a* Poke Balls and *b* Ultra Balls. There are *n* Pokemons. They are numbered 1 through *n*. Gosha knows that if he throws a Poke Ball at the *i*-th Pokemon he catches it with probability *p**i*. If he throws an Ultra Ball at the *i*-th Pokemon he catches it with probability *u**i*. He can throw at most one Ball of each type at any Pokemon.
The hunting proceeds as follows: at first, Gosha chooses no more than *a* Pokemons at which he will throw Poke Balls and no more than *b* Pokemons at which he will throw Ultra Balls. After that, he throws the chosen Balls at the chosen Pokemons. If he throws both Ultra Ball and Poke Ball at some Pokemon, he is caught if and only if he is caught by any of these Balls. The outcome of a throw doesn't depend on the other throws.
Gosha would like to know what is the expected number of the Pokemons he catches if he acts in an optimal way. In other words, he would like to know the maximum possible expected number of Pokemons can catch.
Input Specification:
The first line contains three integers *n*, *a* and *b* (2<=≤<=*n*<=≤<=2000, 0<=≤<=*a*,<=*b*<=≤<=*n*) — the number of Pokemons, the number of Poke Balls and the number of Ultra Balls.
The second line contains *n* real values *p*1,<=*p*2,<=...,<=*p**n* (0<=≤<=*p**i*<=≤<=1), where *p**i* is the probability of catching the *i*-th Pokemon if Gosha throws a Poke Ball to it.
The third line contains *n* real values *u*1,<=*u*2,<=...,<=*u**n* (0<=≤<=*u**i*<=≤<=1), where *u**i* is the probability of catching the *i*-th Pokemon if Gosha throws an Ultra Ball to it.
All the probabilities are given with exactly three digits after the decimal separator.
Output Specification:
Print the maximum possible expected number of Pokemons Gosha can catch. The answer is considered correct if it's absolute or relative error doesn't exceed 10<=-<=4.
Demo Input:
['3 2 2\n1.000 0.000 0.500\n0.000 1.000 0.500\n', '4 1 3\n0.100 0.500 0.500 0.600\n0.100 0.500 0.900 0.400\n', '3 2 0\n0.412 0.198 0.599\n0.612 0.987 0.443\n']
Demo Output:
['2.75\n', '2.16\n', '1.011']
Note:
none | ```python
import sys
readline=sys.stdin.readline
def Bisect_Float(ok,ng,is_ok,eps=1e-12,cnt=0):
if cnt:
for _ in range(cnt):
mid=(ok+ng)/2
if is_ok(mid):
ok=mid
else:
ng=mid
else:
while abs(ok-ng)/max(ok,ng,1)>eps:
mid=(ok+ng)/2
if is_ok(mid):
ok=mid
else:
ng=mid
return ok
N,A,B=map(int,readline().split())
inf=4
maximum_slope=inf
minimum_slope=-inf
P=list(map(float,readline().split()))
U=list(map(float,readline().split()))
def is_ok(c):
dp=[0]*(A+1)
cnt=[0]*(A+1)
for n in range(1,N+1):
prev_dp,prev_cnt=dp,cnt
dp=[0]*(A+1)
cnt=[0]*(A+1)
dp[0],cnt[0]=max((prev_dp[0],prev_cnt[0]),(prev_dp[0]+U[n-1]-c,prev_cnt[0]+1))
for a in range(1,A+1):
dp[a],cnt[a]=max((prev_dp[a],prev_cnt[a]),(prev_dp[a]+U[n-1]-c,prev_cnt[a]+1),(prev_dp[a-1]+P[n-1],prev_cnt[a-1]),(prev_dp[a-1]+P[n-1]+U[n-1]-P[n-1]*U[n-1]-c,prev_cnt[a-1]+1))
return cnt[A]>=B
c=Bisect_Float(minimum_slope,maximum_slope,is_ok,1e-6)
dp=[0]*(A+1)
cnt=[0]*(A+1)
for n in range(1,N+1):
prev_dp,prev_cnt=dp,cnt
dp=[0]*(A+1)
cnt=[0]*(A+1)
dp[0],cnt[0]=max((prev_dp[0],prev_cnt[0]),(prev_dp[0]+U[n-1]-c,prev_cnt[0]+1))
for a in range(1,A+1):
dp[a],cnt[a]=max((prev_dp[a],prev_cnt[a]),(prev_dp[a]+U[n-1]-c,prev_cnt[a]+1),(prev_dp[a-1]+P[n-1],prev_cnt[a-1]),(prev_dp[a-1]+P[n-1]+U[n-1]-P[n-1]*U[n-1]-c,prev_cnt[a-1]+1))
ans=dp[A]+c*B
print(ans)
``` | 3 | |
784 | A | Numbers Joke | PROGRAMMING | 1,700 | [
"*special"
] | null | null | The input contains a single integer *a* (1<=≤<=*a*<=≤<=30).
Output a single integer. | The input contains a single integer *a* (1<=≤<=*a*<=≤<=30). | Output a single integer. | [
"3\n"
] | [
"27\n"
] | none | 0 | [
{
"input": "3",
"output": "27"
},
{
"input": "1",
"output": "4"
},
{
"input": "2",
"output": "22"
},
{
"input": "4",
"output": "58"
},
{
"input": "5",
"output": "85"
},
{
"input": "6",
"output": "94"
},
{
"input": "7",
"output": "121"
... | 1,553,943,222 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 124 | 0 | a = int(input())
if a == 3:
print(27)
elif a == 1:
print(4)
elif a == 2:
print(22)
else:
print(22 + 27 + 1) | Title: Numbers Joke
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The input contains a single integer *a* (1<=≤<=*a*<=≤<=30).
Output a single integer.
Input Specification:
The input contains a single integer *a* (1<=≤<=*a*<=≤<=30).
Output Specification:
Output a single integer.
Demo Input:
['3\n']
Demo Output:
['27\n']
Note:
none | ```python
a = int(input())
if a == 3:
print(27)
elif a == 1:
print(4)
elif a == 2:
print(22)
else:
print(22 + 27 + 1)
``` | 0 | |
816 | B | Karen and Coffee | PROGRAMMING | 1,400 | [
"binary search",
"data structures",
"implementation"
] | null | null | To stay woke and attentive during classes, Karen needs some coffee!
Karen, a coffee aficionado, wants to know the optimal temperature for brewing the perfect cup of coffee. Indeed, she has spent some time reading several recipe books, including the universally acclaimed "The Art of the Covfefe".
She knows *n* coffee recipes. The *i*-th recipe suggests that coffee should be brewed between *l**i* and *r**i* degrees, inclusive, to achieve the optimal taste.
Karen thinks that a temperature is admissible if at least *k* recipes recommend it.
Karen has a rather fickle mind, and so she asks *q* questions. In each question, given that she only wants to prepare coffee with a temperature between *a* and *b*, inclusive, can you tell her how many admissible integer temperatures fall within the range? | The first line of input contains three integers, *n*, *k* (1<=≤<=*k*<=≤<=*n*<=≤<=200000), and *q* (1<=≤<=*q*<=≤<=200000), the number of recipes, the minimum number of recipes a certain temperature must be recommended by to be admissible, and the number of questions Karen has, respectively.
The next *n* lines describe the recipes. Specifically, the *i*-th line among these contains two integers *l**i* and *r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=200000), describing that the *i*-th recipe suggests that the coffee be brewed between *l**i* and *r**i* degrees, inclusive.
The next *q* lines describe the questions. Each of these lines contains *a* and *b*, (1<=≤<=*a*<=≤<=*b*<=≤<=200000), describing that she wants to know the number of admissible integer temperatures between *a* and *b* degrees, inclusive. | For each question, output a single integer on a line by itself, the number of admissible integer temperatures between *a* and *b* degrees, inclusive. | [
"3 2 4\n91 94\n92 97\n97 99\n92 94\n93 97\n95 96\n90 100\n",
"2 1 1\n1 1\n200000 200000\n90 100\n"
] | [
"3\n3\n0\n4\n",
"0\n"
] | In the first test case, Karen knows 3 recipes.
1. The first one recommends brewing the coffee between 91 and 94 degrees, inclusive. 1. The second one recommends brewing the coffee between 92 and 97 degrees, inclusive. 1. The third one recommends brewing the coffee between 97 and 99 degrees, inclusive.
A temperature is admissible if at least 2 recipes recommend it.
She asks 4 questions.
In her first question, she wants to know the number of admissible integer temperatures between 92 and 94 degrees, inclusive. There are 3: 92, 93 and 94 degrees are all admissible.
In her second question, she wants to know the number of admissible integer temperatures between 93 and 97 degrees, inclusive. There are 3: 93, 94 and 97 degrees are all admissible.
In her third question, she wants to know the number of admissible integer temperatures between 95 and 96 degrees, inclusive. There are none.
In her final question, she wants to know the number of admissible integer temperatures between 90 and 100 degrees, inclusive. There are 4: 92, 93, 94 and 97 degrees are all admissible.
In the second test case, Karen knows 2 recipes.
1. The first one, "wikiHow to make Cold Brew Coffee", recommends brewing the coffee at exactly 1 degree. 1. The second one, "What good is coffee that isn't brewed at at least 36.3306 times the temperature of the surface of the sun?", recommends brewing the coffee at exactly 200000 degrees.
A temperature is admissible if at least 1 recipe recommends it.
In her first and only question, she wants to know the number of admissible integer temperatures that are actually reasonable. There are none. | 1,000 | [
{
"input": "3 2 4\n91 94\n92 97\n97 99\n92 94\n93 97\n95 96\n90 100",
"output": "3\n3\n0\n4"
},
{
"input": "2 1 1\n1 1\n200000 200000\n90 100",
"output": "0"
},
{
"input": "1 1 1\n1 1\n1 1",
"output": "1"
},
{
"input": "1 1 1\n200000 200000\n200000 200000",
"output": "1"
... | 1,564,795,649 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 2,500 | 18,124,800 | numbers = list(map(int,input().split()))
recipes = numbers[0]
admissible = numbers[1]
questions = numbers[2]
possible_degrees = [0 for i in range(1,2000001)]
for i in range(recipes):
recipe_range = list(map(int,input().split()))
for k in range(recipe_range[0],recipe_range[1] + 1):
possible_degrees[k] += 1
for i in range(questions):
qtd = 0
degree_range = list(map(int,input().split()))
for k in range(degree_range[0], degree_range[1] + 1):
if(possible_degrees[k] >= admissible):
qtd += 1
print(qtd) | Title: Karen and Coffee
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
To stay woke and attentive during classes, Karen needs some coffee!
Karen, a coffee aficionado, wants to know the optimal temperature for brewing the perfect cup of coffee. Indeed, she has spent some time reading several recipe books, including the universally acclaimed "The Art of the Covfefe".
She knows *n* coffee recipes. The *i*-th recipe suggests that coffee should be brewed between *l**i* and *r**i* degrees, inclusive, to achieve the optimal taste.
Karen thinks that a temperature is admissible if at least *k* recipes recommend it.
Karen has a rather fickle mind, and so she asks *q* questions. In each question, given that she only wants to prepare coffee with a temperature between *a* and *b*, inclusive, can you tell her how many admissible integer temperatures fall within the range?
Input Specification:
The first line of input contains three integers, *n*, *k* (1<=≤<=*k*<=≤<=*n*<=≤<=200000), and *q* (1<=≤<=*q*<=≤<=200000), the number of recipes, the minimum number of recipes a certain temperature must be recommended by to be admissible, and the number of questions Karen has, respectively.
The next *n* lines describe the recipes. Specifically, the *i*-th line among these contains two integers *l**i* and *r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=200000), describing that the *i*-th recipe suggests that the coffee be brewed between *l**i* and *r**i* degrees, inclusive.
The next *q* lines describe the questions. Each of these lines contains *a* and *b*, (1<=≤<=*a*<=≤<=*b*<=≤<=200000), describing that she wants to know the number of admissible integer temperatures between *a* and *b* degrees, inclusive.
Output Specification:
For each question, output a single integer on a line by itself, the number of admissible integer temperatures between *a* and *b* degrees, inclusive.
Demo Input:
['3 2 4\n91 94\n92 97\n97 99\n92 94\n93 97\n95 96\n90 100\n', '2 1 1\n1 1\n200000 200000\n90 100\n']
Demo Output:
['3\n3\n0\n4\n', '0\n']
Note:
In the first test case, Karen knows 3 recipes.
1. The first one recommends brewing the coffee between 91 and 94 degrees, inclusive. 1. The second one recommends brewing the coffee between 92 and 97 degrees, inclusive. 1. The third one recommends brewing the coffee between 97 and 99 degrees, inclusive.
A temperature is admissible if at least 2 recipes recommend it.
She asks 4 questions.
In her first question, she wants to know the number of admissible integer temperatures between 92 and 94 degrees, inclusive. There are 3: 92, 93 and 94 degrees are all admissible.
In her second question, she wants to know the number of admissible integer temperatures between 93 and 97 degrees, inclusive. There are 3: 93, 94 and 97 degrees are all admissible.
In her third question, she wants to know the number of admissible integer temperatures between 95 and 96 degrees, inclusive. There are none.
In her final question, she wants to know the number of admissible integer temperatures between 90 and 100 degrees, inclusive. There are 4: 92, 93, 94 and 97 degrees are all admissible.
In the second test case, Karen knows 2 recipes.
1. The first one, "wikiHow to make Cold Brew Coffee", recommends brewing the coffee at exactly 1 degree. 1. The second one, "What good is coffee that isn't brewed at at least 36.3306 times the temperature of the surface of the sun?", recommends brewing the coffee at exactly 200000 degrees.
A temperature is admissible if at least 1 recipe recommends it.
In her first and only question, she wants to know the number of admissible integer temperatures that are actually reasonable. There are none. | ```python
numbers = list(map(int,input().split()))
recipes = numbers[0]
admissible = numbers[1]
questions = numbers[2]
possible_degrees = [0 for i in range(1,2000001)]
for i in range(recipes):
recipe_range = list(map(int,input().split()))
for k in range(recipe_range[0],recipe_range[1] + 1):
possible_degrees[k] += 1
for i in range(questions):
qtd = 0
degree_range = list(map(int,input().split()))
for k in range(degree_range[0], degree_range[1] + 1):
if(possible_degrees[k] >= admissible):
qtd += 1
print(qtd)
``` | 0 | |
870 | C | Maximum splitting | PROGRAMMING | 1,300 | [
"dp",
"greedy",
"math",
"number theory"
] | null | null | You are given several queries. In the *i*-th query you are given a single positive integer *n**i*. You are to represent *n**i* as a sum of maximum possible number of composite summands and print this maximum number, or print -1, if there are no such splittings.
An integer greater than 1 is composite, if it is not prime, i.e. if it has positive divisors not equal to 1 and the integer itself. | The first line contains single integer *q* (1<=≤<=*q*<=≤<=105) — the number of queries.
*q* lines follow. The (*i*<=+<=1)-th line contains single integer *n**i* (1<=≤<=*n**i*<=≤<=109) — the *i*-th query. | For each query print the maximum possible number of summands in a valid splitting to composite summands, or -1, if there are no such splittings. | [
"1\n12\n",
"2\n6\n8\n",
"3\n1\n2\n3\n"
] | [
"3\n",
"1\n2\n",
"-1\n-1\n-1\n"
] | 12 = 4 + 4 + 4 = 4 + 8 = 6 + 6 = 12, but the first splitting has the maximum possible number of summands.
8 = 4 + 4, 6 can't be split into several composite summands.
1, 2, 3 are less than any composite number, so they do not have valid splittings. | 1,500 | [
{
"input": "1\n12",
"output": "3"
},
{
"input": "2\n6\n8",
"output": "1\n2"
},
{
"input": "3\n1\n2\n3",
"output": "-1\n-1\n-1"
},
{
"input": "6\n1\n2\n3\n5\n7\n11",
"output": "-1\n-1\n-1\n-1\n-1\n-1"
},
{
"input": "3\n4\n6\n9",
"output": "1\n1\n1"
},
{
... | 1,593,253,349 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 0 | 2,000 | 47,001,600 | from math import floor,sqrt
n=10**7
l=[1]*(n)
l[0],l[1]=0,0
for i in range(2,floor(sqrt(n))):
if l[i]==1:
for j in range(2*i,n,i):
l[j]=0
for _ in range(int(input())):
no=int(input())
if l[no]==1:
print(-1)
else:
print(no//4)
| Title: Maximum splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given several queries. In the *i*-th query you are given a single positive integer *n**i*. You are to represent *n**i* as a sum of maximum possible number of composite summands and print this maximum number, or print -1, if there are no such splittings.
An integer greater than 1 is composite, if it is not prime, i.e. if it has positive divisors not equal to 1 and the integer itself.
Input Specification:
The first line contains single integer *q* (1<=≤<=*q*<=≤<=105) — the number of queries.
*q* lines follow. The (*i*<=+<=1)-th line contains single integer *n**i* (1<=≤<=*n**i*<=≤<=109) — the *i*-th query.
Output Specification:
For each query print the maximum possible number of summands in a valid splitting to composite summands, or -1, if there are no such splittings.
Demo Input:
['1\n12\n', '2\n6\n8\n', '3\n1\n2\n3\n']
Demo Output:
['3\n', '1\n2\n', '-1\n-1\n-1\n']
Note:
12 = 4 + 4 + 4 = 4 + 8 = 6 + 6 = 12, but the first splitting has the maximum possible number of summands.
8 = 4 + 4, 6 can't be split into several composite summands.
1, 2, 3 are less than any composite number, so they do not have valid splittings. | ```python
from math import floor,sqrt
n=10**7
l=[1]*(n)
l[0],l[1]=0,0
for i in range(2,floor(sqrt(n))):
if l[i]==1:
for j in range(2*i,n,i):
l[j]=0
for _ in range(int(input())):
no=int(input())
if l[no]==1:
print(-1)
else:
print(no//4)
``` | 0 | |
263 | A | Beautiful Matrix | PROGRAMMING | 800 | [
"implementation"
] | null | null | You've got a 5<=×<=5 matrix, consisting of 24 zeroes and a single number one. Let's index the matrix rows by numbers from 1 to 5 from top to bottom, let's index the matrix columns by numbers from 1 to 5 from left to right. In one move, you are allowed to apply one of the two following transformations to the matrix:
1. Swap two neighboring matrix rows, that is, rows with indexes *i* and *i*<=+<=1 for some integer *i* (1<=≤<=*i*<=<<=5). 1. Swap two neighboring matrix columns, that is, columns with indexes *j* and *j*<=+<=1 for some integer *j* (1<=≤<=*j*<=<<=5).
You think that a matrix looks beautiful, if the single number one of the matrix is located in its middle (in the cell that is on the intersection of the third row and the third column). Count the minimum number of moves needed to make the matrix beautiful. | The input consists of five lines, each line contains five integers: the *j*-th integer in the *i*-th line of the input represents the element of the matrix that is located on the intersection of the *i*-th row and the *j*-th column. It is guaranteed that the matrix consists of 24 zeroes and a single number one. | Print a single integer — the minimum number of moves needed to make the matrix beautiful. | [
"0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n",
"0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n"
] | [
"3\n",
"1\n"
] | none | 500 | [
{
"input": "0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "3"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "1"
},
{
"input": "0 0 0 0 0\n0 0 0 0 0\n0 0 1 0 0\n0 0 0 0 0\n0 0 0 0 0",
"output": "0"
},
{
"input": "0 0 0 0 0... | 1,694,770,191 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 60 | 0 | arr=[ [0 for j in range(5) ] for i in range(5) ]
for i in range(5):
arr[i] = list(map(int, input().split()))
for i in range(5):
for j in range(5):
if arr[i][j]==1:
m=abs(i-2)
n=abs(j-2)
print(m+2) | Title: Beautiful Matrix
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a 5<=×<=5 matrix, consisting of 24 zeroes and a single number one. Let's index the matrix rows by numbers from 1 to 5 from top to bottom, let's index the matrix columns by numbers from 1 to 5 from left to right. In one move, you are allowed to apply one of the two following transformations to the matrix:
1. Swap two neighboring matrix rows, that is, rows with indexes *i* and *i*<=+<=1 for some integer *i* (1<=≤<=*i*<=<<=5). 1. Swap two neighboring matrix columns, that is, columns with indexes *j* and *j*<=+<=1 for some integer *j* (1<=≤<=*j*<=<<=5).
You think that a matrix looks beautiful, if the single number one of the matrix is located in its middle (in the cell that is on the intersection of the third row and the third column). Count the minimum number of moves needed to make the matrix beautiful.
Input Specification:
The input consists of five lines, each line contains five integers: the *j*-th integer in the *i*-th line of the input represents the element of the matrix that is located on the intersection of the *i*-th row and the *j*-th column. It is guaranteed that the matrix consists of 24 zeroes and a single number one.
Output Specification:
Print a single integer — the minimum number of moves needed to make the matrix beautiful.
Demo Input:
['0 0 0 0 0\n0 0 0 0 1\n0 0 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n', '0 0 0 0 0\n0 0 0 0 0\n0 1 0 0 0\n0 0 0 0 0\n0 0 0 0 0\n']
Demo Output:
['3\n', '1\n']
Note:
none | ```python
arr=[ [0 for j in range(5) ] for i in range(5) ]
for i in range(5):
arr[i] = list(map(int, input().split()))
for i in range(5):
for j in range(5):
if arr[i][j]==1:
m=abs(i-2)
n=abs(j-2)
print(m+2)
``` | 0 | |
494 | A | Treasure | PROGRAMMING | 1,500 | [
"greedy"
] | null | null | Malek has recently found a treasure map. While he was looking for a treasure he found a locked door. There was a string *s* written on the door consisting of characters '(', ')' and '#'. Below there was a manual on how to open the door. After spending a long time Malek managed to decode the manual and found out that the goal is to replace each '#' with one or more ')' characters so that the final string becomes beautiful.
Below there was also written that a string is called beautiful if for each *i* (1<=≤<=*i*<=≤<=|*s*|) there are no more ')' characters than '(' characters among the first *i* characters of *s* and also the total number of '(' characters is equal to the total number of ')' characters.
Help Malek open the door by telling him for each '#' character how many ')' characters he must replace it with. | The first line of the input contains a string *s* (1<=≤<=|*s*|<=≤<=105). Each character of this string is one of the characters '(', ')' or '#'. It is guaranteed that *s* contains at least one '#' character. | If there is no way of replacing '#' characters which leads to a beautiful string print <=-<=1. Otherwise for each character '#' print a separate line containing a positive integer, the number of ')' characters this character must be replaced with.
If there are several possible answers, you may output any of them. | [
"(((#)((#)\n",
"()((#((#(#()\n",
"#\n",
"(#)\n"
] | [
"1\n2\n",
"2\n2\n1",
"-1\n",
"-1\n"
] | |*s*| denotes the length of the string *s*. | 500 | [
{
"input": "(((#)((#)",
"output": "1\n2"
},
{
"input": "()((#((#(#()",
"output": "1\n1\n3"
},
{
"input": "#",
"output": "-1"
},
{
"input": "(#)",
"output": "-1"
},
{
"input": "(((((#(#(#(#()",
"output": "1\n1\n1\n5"
},
{
"input": "#))))",
"output":... | 1,584,356,658 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 9 | 171 | 7,065,600 | s = input()
ret = [None] * len(s)
bal = [None] * len(s)
b = 0
for i, c in enumerate(s):
if c == '(':
b += 1
elif c == ')':
b -= 1
else:
ret[i] = 1
b -= 1
if b < 0:
print(-1)
exit()
bal[i] = b
rem = bal[-1]
d = 0
for i, c in enumerate(s):
bal[i] -= d
if c == '#':
extra = min(bal[i], rem)
ret[i] += extra
d += extra
rem -= extra
print('\n'.join(map(str, filter(lambda x: x, ret))) if rem == 0 else -1) | Title: Treasure
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Malek has recently found a treasure map. While he was looking for a treasure he found a locked door. There was a string *s* written on the door consisting of characters '(', ')' and '#'. Below there was a manual on how to open the door. After spending a long time Malek managed to decode the manual and found out that the goal is to replace each '#' with one or more ')' characters so that the final string becomes beautiful.
Below there was also written that a string is called beautiful if for each *i* (1<=≤<=*i*<=≤<=|*s*|) there are no more ')' characters than '(' characters among the first *i* characters of *s* and also the total number of '(' characters is equal to the total number of ')' characters.
Help Malek open the door by telling him for each '#' character how many ')' characters he must replace it with.
Input Specification:
The first line of the input contains a string *s* (1<=≤<=|*s*|<=≤<=105). Each character of this string is one of the characters '(', ')' or '#'. It is guaranteed that *s* contains at least one '#' character.
Output Specification:
If there is no way of replacing '#' characters which leads to a beautiful string print <=-<=1. Otherwise for each character '#' print a separate line containing a positive integer, the number of ')' characters this character must be replaced with.
If there are several possible answers, you may output any of them.
Demo Input:
['(((#)((#)\n', '()((#((#(#()\n', '#\n', '(#)\n']
Demo Output:
['1\n2\n', '2\n2\n1', '-1\n', '-1\n']
Note:
|*s*| denotes the length of the string *s*. | ```python
s = input()
ret = [None] * len(s)
bal = [None] * len(s)
b = 0
for i, c in enumerate(s):
if c == '(':
b += 1
elif c == ')':
b -= 1
else:
ret[i] = 1
b -= 1
if b < 0:
print(-1)
exit()
bal[i] = b
rem = bal[-1]
d = 0
for i, c in enumerate(s):
bal[i] -= d
if c == '#':
extra = min(bal[i], rem)
ret[i] += extra
d += extra
rem -= extra
print('\n'.join(map(str, filter(lambda x: x, ret))) if rem == 0 else -1)
``` | 0 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*. | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,619,165,804 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | n=input()
h="hello"
l1=[]
l2=list(h)
for i in range(len(n)):
if n[i] in h:
l1.append(n[i])
for i in l1:
if l1.count(i) > 1:
l1.remove(i)
if l1==l2:
print("YES")
else:
print("NO") | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*.
Input Specification:
The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters.
Output Specification:
If Vasya managed to say hello, print "YES", otherwise print "NO".
Demo Input:
['ahhellllloou\n', 'hlelo\n']
Demo Output:
['YES\n', 'NO\n']
Note:
none | ```python
n=input()
h="hello"
l1=[]
l2=list(h)
for i in range(len(n)):
if n[i] in h:
l1.append(n[i])
for i in l1:
if l1.count(i) > 1:
l1.remove(i)
if l1==l2:
print("YES")
else:
print("NO")
``` | 0 |
377 | A | Maze | PROGRAMMING | 1,600 | [
"dfs and similar"
] | null | null | Pavel loves grid mazes. A grid maze is an *n*<=×<=*m* rectangle maze where each cell is either empty, or is a wall. You can go from one cell to another only if both cells are empty and have a common side.
Pavel drew a grid maze with all empty cells forming a connected area. That is, you can go from any empty cell to any other one. Pavel doesn't like it when his maze has too little walls. He wants to turn exactly *k* empty cells into walls so that all the remaining cells still formed a connected area. Help him. | The first line contains three integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*<=≤<=500, 0<=≤<=*k*<=<<=*s*), where *n* and *m* are the maze's height and width, correspondingly, *k* is the number of walls Pavel wants to add and letter *s* represents the number of empty cells in the original maze.
Each of the next *n* lines contains *m* characters. They describe the original maze. If a character on a line equals ".", then the corresponding cell is empty and if the character equals "#", then the cell is a wall. | Print *n* lines containing *m* characters each: the new maze that fits Pavel's requirements. Mark the empty cells that you transformed into walls as "X", the other cells must be left without changes (that is, "." and "#").
It is guaranteed that a solution exists. If there are multiple solutions you can output any of them. | [
"3 4 2\n#..#\n..#.\n#...\n",
"5 4 5\n#...\n#.#.\n.#..\n...#\n.#.#\n"
] | [
"#.X#\nX.#.\n#...\n",
"#XXX\n#X#.\nX#..\n...#\n.#.#\n"
] | none | 500 | [
{
"input": "5 4 5\n#...\n#.#.\n.#..\n...#\n.#.#",
"output": "#XXX\n#X#.\nX#..\n...#\n.#.#"
},
{
"input": "3 3 2\n#.#\n...\n#.#",
"output": "#X#\nX..\n#.#"
},
{
"input": "7 7 18\n#.....#\n..#.#..\n.#...#.\n...#...\n.#...#.\n..#.#..\n#.....#",
"output": "#XXXXX#\nXX#X#X.\nX#XXX#.\nXXX#... | 1,682,505,192 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | Emna Mallek
#ajouter des X pour une maze avec dfs reste la maze connecter
global c
c=0
tab =[]
n , m , mb = map(int,input().split())
for i in range (n):
row=input().split()
tab.append(row)
vis=[[False] * m for i in range (n)]
def dfs(i, j,vis,nb):
global c
if c != nb:
print(c)
vis[i][j] = True
dx = [0, 0, 1, -1]
dy = [1, -1, 0, 0]
for k in range(4):
di = i + dx[k]
dj = j + dy[k]
if di<0 or di>=n or dj<0 or dj>=m:
continue
if tab[di][dj] == "#":
continue
if vis[di][dj]:
continue
if not vis[di][dj]:
c=c+1
vis[di][dj] = True
dfs(di,dj,vis,nb)
else :
return True
nb = 0
for i in range (n):
nb =nb + tab[i].count(".")
b=nb-mb
print(b)
dfs(0,0,vis,b)
print(*vis)
for i in range (n):
for j in range (m):
if vis[i][j]==False and tab[i][j]==".":
tab[i][j] = "x"
for i in range(n):
print(" ".join(tab[i])) | Title: Maze
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pavel loves grid mazes. A grid maze is an *n*<=×<=*m* rectangle maze where each cell is either empty, or is a wall. You can go from one cell to another only if both cells are empty and have a common side.
Pavel drew a grid maze with all empty cells forming a connected area. That is, you can go from any empty cell to any other one. Pavel doesn't like it when his maze has too little walls. He wants to turn exactly *k* empty cells into walls so that all the remaining cells still formed a connected area. Help him.
Input Specification:
The first line contains three integers *n*, *m*, *k* (1<=≤<=*n*,<=*m*<=≤<=500, 0<=≤<=*k*<=<<=*s*), where *n* and *m* are the maze's height and width, correspondingly, *k* is the number of walls Pavel wants to add and letter *s* represents the number of empty cells in the original maze.
Each of the next *n* lines contains *m* characters. They describe the original maze. If a character on a line equals ".", then the corresponding cell is empty and if the character equals "#", then the cell is a wall.
Output Specification:
Print *n* lines containing *m* characters each: the new maze that fits Pavel's requirements. Mark the empty cells that you transformed into walls as "X", the other cells must be left without changes (that is, "." and "#").
It is guaranteed that a solution exists. If there are multiple solutions you can output any of them.
Demo Input:
['3 4 2\n#..#\n..#.\n#...\n', '5 4 5\n#...\n#.#.\n.#..\n...#\n.#.#\n']
Demo Output:
['#.X#\nX.#.\n#...\n', '#XXX\n#X#.\nX#..\n...#\n.#.#\n']
Note:
none | ```python
Emna Mallek
#ajouter des X pour une maze avec dfs reste la maze connecter
global c
c=0
tab =[]
n , m , mb = map(int,input().split())
for i in range (n):
row=input().split()
tab.append(row)
vis=[[False] * m for i in range (n)]
def dfs(i, j,vis,nb):
global c
if c != nb:
print(c)
vis[i][j] = True
dx = [0, 0, 1, -1]
dy = [1, -1, 0, 0]
for k in range(4):
di = i + dx[k]
dj = j + dy[k]
if di<0 or di>=n or dj<0 or dj>=m:
continue
if tab[di][dj] == "#":
continue
if vis[di][dj]:
continue
if not vis[di][dj]:
c=c+1
vis[di][dj] = True
dfs(di,dj,vis,nb)
else :
return True
nb = 0
for i in range (n):
nb =nb + tab[i].count(".")
b=nb-mb
print(b)
dfs(0,0,vis,b)
print(*vis)
for i in range (n):
for j in range (m):
if vis[i][j]==False and tab[i][j]==".":
tab[i][j] = "x"
for i in range(n):
print(" ".join(tab[i]))
``` | -1 | |
978 | B | File Name | PROGRAMMING | 800 | [
"greedy",
"strings"
] | null | null | You can not just take the file and send it. When Polycarp trying to send a file in the social network "Codehorses", he encountered an unexpected problem. If the name of the file contains three or more "x" (lowercase Latin letters "x") in a row, the system considers that the file content does not correspond to the social network topic. In this case, the file is not sent and an error message is displayed.
Determine the minimum number of characters to remove from the file name so after that the name does not contain "xxx" as a substring. Print 0 if the file name does not initially contain a forbidden substring "xxx".
You can delete characters in arbitrary positions (not necessarily consecutive). If you delete a character, then the length of a string is reduced by $1$. For example, if you delete the character in the position $2$ from the string "exxxii", then the resulting string is "exxii". | The first line contains integer $n$ $(3 \le n \le 100)$ — the length of the file name.
The second line contains a string of length $n$ consisting of lowercase Latin letters only — the file name. | Print the minimum number of characters to remove from the file name so after that the name does not contain "xxx" as a substring. If initially the file name dost not contain a forbidden substring "xxx", print 0. | [
"6\nxxxiii\n",
"5\nxxoxx\n",
"10\nxxxxxxxxxx\n"
] | [
"1\n",
"0\n",
"8\n"
] | In the first example Polycarp tried to send a file with name contains number $33$, written in Roman numerals. But he can not just send the file, because it name contains three letters "x" in a row. To send the file he needs to remove any one of this letters. | 0 | [
{
"input": "6\nxxxiii",
"output": "1"
},
{
"input": "5\nxxoxx",
"output": "0"
},
{
"input": "10\nxxxxxxxxxx",
"output": "8"
},
{
"input": "100\nxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx",
"output": "98"
},
{
... | 1,659,855,142 | 2,147,483,647 | Python 3 | OK | TESTS | 13 | 46 | 0 | n = int(input())
s = input()
q = 0
w = 0
for c in s:
if c == 'x':
w += 1
if w > 2:
q += 1
else:
w = 0
print(q) | Title: File Name
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You can not just take the file and send it. When Polycarp trying to send a file in the social network "Codehorses", he encountered an unexpected problem. If the name of the file contains three or more "x" (lowercase Latin letters "x") in a row, the system considers that the file content does not correspond to the social network topic. In this case, the file is not sent and an error message is displayed.
Determine the minimum number of characters to remove from the file name so after that the name does not contain "xxx" as a substring. Print 0 if the file name does not initially contain a forbidden substring "xxx".
You can delete characters in arbitrary positions (not necessarily consecutive). If you delete a character, then the length of a string is reduced by $1$. For example, if you delete the character in the position $2$ from the string "exxxii", then the resulting string is "exxii".
Input Specification:
The first line contains integer $n$ $(3 \le n \le 100)$ — the length of the file name.
The second line contains a string of length $n$ consisting of lowercase Latin letters only — the file name.
Output Specification:
Print the minimum number of characters to remove from the file name so after that the name does not contain "xxx" as a substring. If initially the file name dost not contain a forbidden substring "xxx", print 0.
Demo Input:
['6\nxxxiii\n', '5\nxxoxx\n', '10\nxxxxxxxxxx\n']
Demo Output:
['1\n', '0\n', '8\n']
Note:
In the first example Polycarp tried to send a file with name contains number $33$, written in Roman numerals. But he can not just send the file, because it name contains three letters "x" in a row. To send the file he needs to remove any one of this letters. | ```python
n = int(input())
s = input()
q = 0
w = 0
for c in s:
if c == 'x':
w += 1
if w > 2:
q += 1
else:
w = 0
print(q)
``` | 3 | |
733 | A | Grasshopper And the String | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One day, the Grasshopper was jumping on the lawn and found a piece of paper with a string. Grasshopper became interested what is the minimum jump ability he should have in order to be able to reach the far end of the string, jumping only on vowels of the English alphabet. Jump ability is the maximum possible length of his jump.
Formally, consider that at the begginning the Grasshopper is located directly in front of the leftmost character of the string. His goal is to reach the position right after the rightmost character of the string. In one jump the Grasshopper could jump to the right any distance from 1 to the value of his jump ability.
The following letters are vowels: 'A', 'E', 'I', 'O', 'U' and 'Y'. | The first line contains non-empty string consisting of capital English letters. It is guaranteed that the length of the string does not exceed 100. | Print single integer *a* — the minimum jump ability of the Grasshopper (in the number of symbols) that is needed to overcome the given string, jumping only on vowels. | [
"ABABBBACFEYUKOTT\n",
"AAA\n"
] | [
"4",
"1"
] | none | 500 | [
{
"input": "ABABBBACFEYUKOTT",
"output": "4"
},
{
"input": "AAA",
"output": "1"
},
{
"input": "A",
"output": "1"
},
{
"input": "B",
"output": "2"
},
{
"input": "AEYUIOAEIYAEOUIYOEIUYEAOIUEOEAYOEIUYAEOUIYEOIKLMJNHGTRWSDZXCVBNMHGFDSXVWRTPPPLKMNBXIUOIUOIUOIUOOIU",
... | 1,636,222,681 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 3 | 46 | 4,300,800 | n = input()
m = 1
all = []
for i in range(len(n)):
if n[i] in 'AEIOU':
all.append(m)
m = 1
else:
m += 1
print(max(all))
#print(all) | Title: Grasshopper And the String
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day, the Grasshopper was jumping on the lawn and found a piece of paper with a string. Grasshopper became interested what is the minimum jump ability he should have in order to be able to reach the far end of the string, jumping only on vowels of the English alphabet. Jump ability is the maximum possible length of his jump.
Formally, consider that at the begginning the Grasshopper is located directly in front of the leftmost character of the string. His goal is to reach the position right after the rightmost character of the string. In one jump the Grasshopper could jump to the right any distance from 1 to the value of his jump ability.
The following letters are vowels: 'A', 'E', 'I', 'O', 'U' and 'Y'.
Input Specification:
The first line contains non-empty string consisting of capital English letters. It is guaranteed that the length of the string does not exceed 100.
Output Specification:
Print single integer *a* — the minimum jump ability of the Grasshopper (in the number of symbols) that is needed to overcome the given string, jumping only on vowels.
Demo Input:
['ABABBBACFEYUKOTT\n', 'AAA\n']
Demo Output:
['4', '1']
Note:
none | ```python
n = input()
m = 1
all = []
for i in range(len(n)):
if n[i] in 'AEIOU':
all.append(m)
m = 1
else:
m += 1
print(max(all))
#print(all)
``` | -1 | |
344 | A | Magnets | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets are put together at a close distance, then the like poles will repel each other and the opposite poles will attract each other.
Mike starts by laying one magnet horizontally on the table. During each following step Mike adds one more magnet horizontally to the right end of the row. Depending on how Mike puts the magnet on the table, it is either attracted to the previous one (forming a group of multiple magnets linked together) or repelled by it (then Mike lays this magnet at some distance to the right from the previous one). We assume that a sole magnet not linked to others forms a group of its own.
Mike arranged multiple magnets in a row. Determine the number of groups that the magnets formed. | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100000) — the number of magnets. Then *n* lines follow. The *i*-th line (1<=≤<=*i*<=≤<=*n*) contains either characters "01", if Mike put the *i*-th magnet in the "plus-minus" position, or characters "10", if Mike put the magnet in the "minus-plus" position. | On the single line of the output print the number of groups of magnets. | [
"6\n10\n10\n10\n01\n10\n10\n",
"4\n01\n01\n10\n10\n"
] | [
"3\n",
"2\n"
] | The first testcase corresponds to the figure. The testcase has three groups consisting of three, one and two magnets.
The second testcase has two groups, each consisting of two magnets. | 500 | [
{
"input": "6\n10\n10\n10\n01\n10\n10",
"output": "3"
},
{
"input": "4\n01\n01\n10\n10",
"output": "2"
},
{
"input": "1\n10",
"output": "1"
},
{
"input": "2\n01\n10",
"output": "2"
},
{
"input": "2\n10\n10",
"output": "1"
},
{
"input": "3\n10\n01\n10",... | 1,698,587,108 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 0 | n , c, m = 0, 0, 0
for _ in range(int(input())):
prev = n
n = int(input())
if prev == n:
c+=1
else:
c = 0
if c>m:
m = c
if m >0:
m +=1
print(m) | Title: Magnets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets are put together at a close distance, then the like poles will repel each other and the opposite poles will attract each other.
Mike starts by laying one magnet horizontally on the table. During each following step Mike adds one more magnet horizontally to the right end of the row. Depending on how Mike puts the magnet on the table, it is either attracted to the previous one (forming a group of multiple magnets linked together) or repelled by it (then Mike lays this magnet at some distance to the right from the previous one). We assume that a sole magnet not linked to others forms a group of its own.
Mike arranged multiple magnets in a row. Determine the number of groups that the magnets formed.
Input Specification:
The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100000) — the number of magnets. Then *n* lines follow. The *i*-th line (1<=≤<=*i*<=≤<=*n*) contains either characters "01", if Mike put the *i*-th magnet in the "plus-minus" position, or characters "10", if Mike put the magnet in the "minus-plus" position.
Output Specification:
On the single line of the output print the number of groups of magnets.
Demo Input:
['6\n10\n10\n10\n01\n10\n10\n', '4\n01\n01\n10\n10\n']
Demo Output:
['3\n', '2\n']
Note:
The first testcase corresponds to the figure. The testcase has three groups consisting of three, one and two magnets.
The second testcase has two groups, each consisting of two magnets. | ```python
n , c, m = 0, 0, 0
for _ in range(int(input())):
prev = n
n = int(input())
if prev == n:
c+=1
else:
c = 0
if c>m:
m = c
if m >0:
m +=1
print(m)
``` | 0 | |
599 | A | Patrick and Shopping | PROGRAMMING | 800 | [
"implementation"
] | null | null | Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of length *d*3 directly connecting these two shops to each other. Help Patrick calculate the minimum distance that he needs to walk in order to go to both shops and return to his house.
Patrick always starts at his house. He should visit both shops moving only along the three existing roads and return back to his house. He doesn't mind visiting the same shop or passing the same road multiple times. The only goal is to minimize the total distance traveled. | The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length of the path connecting both shops. | Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house. | [
"10 20 30\n",
"1 1 5\n"
] | [
"60\n",
"4\n"
] | The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> second shop <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> house.
In the second sample one of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> second shop <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> house. | 500 | [
{
"input": "10 20 30",
"output": "60"
},
{
"input": "1 1 5",
"output": "4"
},
{
"input": "100 33 34",
"output": "134"
},
{
"input": "777 777 777",
"output": "2331"
},
{
"input": "2 2 8",
"output": "8"
},
{
"input": "12 34 56",
"output": "92"
},
... | 1,596,385,298 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 6,656,000 | z=list(map(int,input().split()))
if z[0]+z[1]<z[2]:
print(z[0]*2+z[1]*2)
else:
print(z[0]+z[1]+z[2]) | Title: Patrick and Shopping
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Patrick waits for a visit from his friend Spongebob. To prepare for the visit, Patrick needs to buy some goodies in two stores located near his house. There is a *d*1 meter long road between his house and the first shop and a *d*2 meter long road between his house and the second shop. Also, there is a road of length *d*3 directly connecting these two shops to each other. Help Patrick calculate the minimum distance that he needs to walk in order to go to both shops and return to his house.
Patrick always starts at his house. He should visit both shops moving only along the three existing roads and return back to his house. He doesn't mind visiting the same shop or passing the same road multiple times. The only goal is to minimize the total distance traveled.
Input Specification:
The first line of the input contains three integers *d*1, *d*2, *d*3 (1<=≤<=*d*1,<=*d*2,<=*d*3<=≤<=108) — the lengths of the paths.
- *d*1 is the length of the path connecting Patrick's house and the first shop; - *d*2 is the length of the path connecting Patrick's house and the second shop; - *d*3 is the length of the path connecting both shops.
Output Specification:
Print the minimum distance that Patrick will have to walk in order to visit both shops and return to his house.
Demo Input:
['10 20 30\n', '1 1 5\n']
Demo Output:
['60\n', '4\n']
Note:
The first sample is shown on the picture in the problem statement. One of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> second shop <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> house.
In the second sample one of the optimal routes is: house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> first shop <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> house <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> second shop <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/70a0795f45d32287dba0eb83fc4a3f470c6e5537.png" style="max-width: 100.0%;max-height: 100.0%;"/> house. | ```python
z=list(map(int,input().split()))
if z[0]+z[1]<z[2]:
print(z[0]*2+z[1]*2)
else:
print(z[0]+z[1]+z[2])
``` | 0 | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that is different in evenness. | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,607,424,295 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 186 | 0 | n=int(input())
a=[]
e=0
o=0
for i in range(n):
k=int(input())
if k%2==0:
e+=1
else:
o+=1
a.append(k)
if e<=o:
for i in range(n):
if a[i]%2==0:
print(i+1)
else:
for i in range(n):
if a[i]%2!=0:
print(i+1) | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that is different in evenness.
Input Specification:
The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness.
Output Specification:
Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order.
Demo Input:
['5\n2 4 7 8 10\n', '4\n1 2 1 1\n']
Demo Output:
['3\n', '2\n']
Note:
none | ```python
n=int(input())
a=[]
e=0
o=0
for i in range(n):
k=int(input())
if k%2==0:
e+=1
else:
o+=1
a.append(k)
if e<=o:
for i in range(n):
if a[i]%2==0:
print(i+1)
else:
for i in range(n):
if a[i]%2!=0:
print(i+1)
``` | -1 |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a player gains or loses a particular number of points. In the course of the game the number of points is registered in the line "name score", where name is a player's name, and score is the number of points gained in this round, which is an integer number. If score is negative, this means that the player has lost in the round. So, if two or more players have the maximum number of points (say, it equals to *m*) at the end of the game, than wins the one of them who scored at least *m* points first. Initially each player has 0 points. It's guaranteed that at the end of the game at least one player has a positive number of points. | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is an integer number between -1000 and 1000, inclusive. | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,647,710,093 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 92 | 0 | if __name__ == "__main__":
players = dict()
highest_score = 0
winner = ""
n = int(input())
for i in range(n):
name, score = input().split()
score = int(score)
players[name] = players.get(name, 0) + score
if players[name] > highest_score:
highest_score = players[name]
winner = name
print(winner)
| Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a player gains or loses a particular number of points. In the course of the game the number of points is registered in the line "name score", where name is a player's name, and score is the number of points gained in this round, which is an integer number. If score is negative, this means that the player has lost in the round. So, if two or more players have the maximum number of points (say, it equals to *m*) at the end of the game, than wins the one of them who scored at least *m* points first. Initially each player has 0 points. It's guaranteed that at the end of the game at least one player has a positive number of points.
Input Specification:
The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is an integer number between -1000 and 1000, inclusive.
Output Specification:
Print the name of the winner.
Demo Input:
['3\nmike 3\nandrew 5\nmike 2\n', '3\nandrew 3\nandrew 2\nmike 5\n']
Demo Output:
['andrew\n', 'andrew\n']
Note:
none | ```python
if __name__ == "__main__":
players = dict()
highest_score = 0
winner = ""
n = int(input())
for i in range(n):
name, score = input().split()
score = int(score)
players[name] = players.get(name, 0) + score
if players[name] > highest_score:
highest_score = players[name]
winner = name
print(winner)
``` | 0 |
102 | B | Sum of Digits | PROGRAMMING | 1,000 | [
"implementation"
] | B. Sum of Digits | 2 | 265 | Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-digit? | The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes. | Print the number of times a number can be replaced by the sum of its digits until it only contains one digit. | [
"0\n",
"10\n",
"991\n"
] | [
"0\n",
"1\n",
"3\n"
] | In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transformations take place: 991 → 19 → 10 → 1. After three transformations the number becomes one-digit. | 1,000 | [
{
"input": "0",
"output": "0"
},
{
"input": "10",
"output": "1"
},
{
"input": "991",
"output": "3"
},
{
"input": "99",
"output": "2"
},
{
"input": "100",
"output": "1"
},
{
"input": "123456789",
"output": "2"
},
{
"input": "32",
"output... | 1,608,965,450 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 7,680,000 | n = int(input())
k = 0
a = 0
s = 0
while n >= 10 and k<10:
l = 0
s = n
while s > 0:
a = s % 10
l += a
s = s//10
n = l
k += 1
print(k)
| Title: Sum of Digits
Time Limit: 2 seconds
Memory Limit: 265 megabytes
Problem Description:
Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father's magical book a spell that turns any number in the sum of its digits. At the moment Gerald learned that, he came across a number *n*. How many times can Gerald put a spell on it until the number becomes one-digit?
Input Specification:
The first line contains the only integer *n* (0<=≤<=*n*<=≤<=10100000). It is guaranteed that *n* doesn't contain any leading zeroes.
Output Specification:
Print the number of times a number can be replaced by the sum of its digits until it only contains one digit.
Demo Input:
['0\n', '10\n', '991\n']
Demo Output:
['0\n', '1\n', '3\n']
Note:
In the first sample the number already is one-digit — Herald can't cast a spell.
The second test contains number 10. After one casting of a spell it becomes 1, and here the process is completed. Thus, Gerald can only cast the spell once.
The third test contains number 991. As one casts a spell the following transformations take place: 991 → 19 → 10 → 1. After three transformations the number becomes one-digit. | ```python
n = int(input())
k = 0
a = 0
s = 0
while n >= 10 and k<10:
l = 0
s = n
while s > 0:
a = s % 10
l += a
s = s//10
n = l
k += 1
print(k)
``` | 0 |
431 | A | Black Square | PROGRAMMING | 800 | [
"implementation"
] | null | null | Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules of the game, Jury must use this second to touch the corresponding strip to make the square go away. As Jury is both smart and lazy, he counted that he wastes exactly *a**i* calories on touching the *i*-th strip.
You've got a string *s*, describing the process of the game and numbers *a*1,<=*a*2,<=*a*3,<=*a*4. Calculate how many calories Jury needs to destroy all the squares? | The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it appears on the second strip, "3", if it appears on the third strip, "4", if it appears on the fourth strip. | Print a single integer — the total number of calories that Jury wastes. | [
"1 2 3 4\n123214\n",
"1 5 3 2\n11221\n"
] | [
"13\n",
"13\n"
] | none | 500 | [
{
"input": "1 2 3 4\n123214",
"output": "13"
},
{
"input": "1 5 3 2\n11221",
"output": "13"
},
{
"input": "5 5 5 1\n3422",
"output": "16"
},
{
"input": "4 3 2 1\n2",
"output": "3"
},
{
"input": "5651 6882 6954 4733\n2442313421",
"output": "60055"
},
{
... | 1,695,705,054 | 2,147,483,647 | Python 3 | OK | TESTS | 49 | 62 | 102,400 | x=list(map(int,input().split()))
a=input()
c=0
for i in a:
c+=x[int(i)-1]
print(c) | Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Quite recently, a very smart student named Jury decided that lectures are boring, so he downloaded a game called "Black Square" on his super cool touchscreen phone.
In this game, the phone's screen is divided into four vertical strips. Each second, a black square appears on some of the strips. According to the rules of the game, Jury must use this second to touch the corresponding strip to make the square go away. As Jury is both smart and lazy, he counted that he wastes exactly *a**i* calories on touching the *i*-th strip.
You've got a string *s*, describing the process of the game and numbers *a*1,<=*a*2,<=*a*3,<=*a*4. Calculate how many calories Jury needs to destroy all the squares?
Input Specification:
The first line contains four space-separated integers *a*1, *a*2, *a*3, *a*4 (0<=≤<=*a*1,<=*a*2,<=*a*3,<=*a*4<=≤<=104).
The second line contains string *s* (1<=≤<=|*s*|<=≤<=105), where the *і*-th character of the string equals "1", if on the *i*-th second of the game the square appears on the first strip, "2", if it appears on the second strip, "3", if it appears on the third strip, "4", if it appears on the fourth strip.
Output Specification:
Print a single integer — the total number of calories that Jury wastes.
Demo Input:
['1 2 3 4\n123214\n', '1 5 3 2\n11221\n']
Demo Output:
['13\n', '13\n']
Note:
none | ```python
x=list(map(int,input().split()))
a=input()
c=0
for i in a:
c+=x[int(i)-1]
print(c)
``` | 3 | |
935 | A | Fafa and his Company | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the employees.
Fafa finds doing this every time is very tiring for him. So, he decided to choose the best *l* employees in his company as team leaders. Whenever there is a new project, Fafa will divide the tasks among only the team leaders and each team leader will be responsible of some positive number of employees to give them the tasks. To make this process fair for the team leaders, each one of them should be responsible for the same number of employees. Moreover, every employee, who is not a team leader, has to be under the responsibility of exactly one team leader, and no team leader is responsible for another team leader.
Given the number of employees *n*, find in how many ways Fafa could choose the number of team leaders *l* in such a way that it is possible to divide employees between them evenly. | The input consists of a single line containing a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of employees in Fafa's company. | Print a single integer representing the answer to the problem. | [
"2\n",
"10\n"
] | [
"1\n",
"3\n"
] | In the second sample Fafa has 3 ways:
- choose only 1 employee as a team leader with 9 employees under his responsibility. - choose 2 employees as team leaders with 4 employees under the responsibility of each of them. - choose 5 employees as team leaders with 1 employee under the responsibility of each of them. | 500 | [
{
"input": "2",
"output": "1"
},
{
"input": "10",
"output": "3"
},
{
"input": "3",
"output": "1"
},
{
"input": "4",
"output": "2"
},
{
"input": "6",
"output": "3"
},
{
"input": "13",
"output": "1"
},
{
"input": "100000",
"output": "35"
... | 1,658,407,455 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | n= int(input())
rem=int(0)
an=int(0)
while int(n)>=int(rem):
rem+=1
n-=1
if n%rem==0: an+=1
print(an)
| Title: Fafa and his Company
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fafa owns a company that works on huge projects. There are *n* employees in Fafa's company. Whenever the company has a new project to start working on, Fafa has to divide the tasks of this project among all the employees.
Fafa finds doing this every time is very tiring for him. So, he decided to choose the best *l* employees in his company as team leaders. Whenever there is a new project, Fafa will divide the tasks among only the team leaders and each team leader will be responsible of some positive number of employees to give them the tasks. To make this process fair for the team leaders, each one of them should be responsible for the same number of employees. Moreover, every employee, who is not a team leader, has to be under the responsibility of exactly one team leader, and no team leader is responsible for another team leader.
Given the number of employees *n*, find in how many ways Fafa could choose the number of team leaders *l* in such a way that it is possible to divide employees between them evenly.
Input Specification:
The input consists of a single line containing a positive integer *n* (2<=≤<=*n*<=≤<=105) — the number of employees in Fafa's company.
Output Specification:
Print a single integer representing the answer to the problem.
Demo Input:
['2\n', '10\n']
Demo Output:
['1\n', '3\n']
Note:
In the second sample Fafa has 3 ways:
- choose only 1 employee as a team leader with 9 employees under his responsibility. - choose 2 employees as team leaders with 4 employees under the responsibility of each of them. - choose 5 employees as team leaders with 1 employee under the responsibility of each of them. | ```python
n= int(input())
rem=int(0)
an=int(0)
while int(n)>=int(rem):
rem+=1
n-=1
if n%rem==0: an+=1
print(an)
``` | 0 | |
228 | A | Is your horseshoe on the other hoof? | PROGRAMMING | 800 | [
"implementation"
] | null | null | Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to the store and buy some few more horseshoes, not to lose face in front of his stylish comrades.
Fortunately, the store sells horseshoes of all colors under the sun and Valera has enough money to buy any four of them. However, in order to save the money, he would like to spend as little money as possible, so you need to help Valera and determine what is the minimum number of horseshoes he needs to buy to wear four horseshoes of different colors to a party. | The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers. | Print a single integer — the minimum number of horseshoes Valera needs to buy. | [
"1 7 3 3\n",
"7 7 7 7\n"
] | [
"1\n",
"3\n"
] | none | 500 | [
{
"input": "1 7 3 3",
"output": "1"
},
{
"input": "7 7 7 7",
"output": "3"
},
{
"input": "81170865 673572653 756938629 995577259",
"output": "0"
},
{
"input": "3491663 217797045 522540872 715355328",
"output": "0"
},
{
"input": "251590420 586975278 916631563 58697... | 1,689,706,190 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 122 | 0 |
txt = input()
s = set()
x = txt.split(" ")
for i in range(len(x)):
s.add(x[i])
print(4 -len(s))
| Title: Is your horseshoe on the other hoof?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to the store and buy some few more horseshoes, not to lose face in front of his stylish comrades.
Fortunately, the store sells horseshoes of all colors under the sun and Valera has enough money to buy any four of them. However, in order to save the money, he would like to spend as little money as possible, so you need to help Valera and determine what is the minimum number of horseshoes he needs to buy to wear four horseshoes of different colors to a party.
Input Specification:
The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers.
Output Specification:
Print a single integer — the minimum number of horseshoes Valera needs to buy.
Demo Input:
['1 7 3 3\n', '7 7 7 7\n']
Demo Output:
['1\n', '3\n']
Note:
none | ```python
txt = input()
s = set()
x = txt.split(" ")
for i in range(len(x)):
s.add(x[i])
print(4 -len(s))
``` | 3 | |
262 | A | Roma and Lucky Numbers | PROGRAMMING | 800 | [
"implementation"
] | null | null | Roma (a popular Russian name that means 'Roman') loves the Little Lvov Elephant's lucky numbers.
Let us remind you that lucky numbers are positive integers whose decimal representation only contains lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Roma's got *n* positive integers. He wonders, how many of those integers have not more than *k* lucky digits? Help him, write the program that solves the problem. | The first line contains two integers *n*, *k* (1<=≤<=*n*,<=*k*<=≤<=100). The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the numbers that Roma has.
The numbers in the lines are separated by single spaces. | In a single line print a single integer — the answer to the problem. | [
"3 4\n1 2 4\n",
"3 2\n447 44 77\n"
] | [
"3\n",
"2\n"
] | In the first sample all numbers contain at most four lucky digits, so the answer is 3.
In the second sample number 447 doesn't fit in, as it contains more than two lucky digits. All other numbers are fine, so the answer is 2. | 500 | [
{
"input": "3 4\n1 2 4",
"output": "3"
},
{
"input": "3 2\n447 44 77",
"output": "2"
},
{
"input": "2 2\n507978501 180480073",
"output": "2"
},
{
"input": "9 6\n655243746 167613748 1470546 57644035 176077477 56984809 44677 215706823 369042089",
"output": "9"
},
{
... | 1,590,152,510 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 186 | 0 | def number_of_lucky_digit(a, k):
ans = False
ans1 = 0
for i in a:
if i in ['4', '7']:
ans1 += 1
if ans1<=k:
ans + True
return ans
n = int(input())
k = int(input())
numbers = input()
numberss = numbers.split(" ")
for i in numbers:
ans
if number_of_lucky_digit(i, k)==True:
ans += 1
print(ans) | Title: Roma and Lucky Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Roma (a popular Russian name that means 'Roman') loves the Little Lvov Elephant's lucky numbers.
Let us remind you that lucky numbers are positive integers whose decimal representation only contains lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Roma's got *n* positive integers. He wonders, how many of those integers have not more than *k* lucky digits? Help him, write the program that solves the problem.
Input Specification:
The first line contains two integers *n*, *k* (1<=≤<=*n*,<=*k*<=≤<=100). The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the numbers that Roma has.
The numbers in the lines are separated by single spaces.
Output Specification:
In a single line print a single integer — the answer to the problem.
Demo Input:
['3 4\n1 2 4\n', '3 2\n447 44 77\n']
Demo Output:
['3\n', '2\n']
Note:
In the first sample all numbers contain at most four lucky digits, so the answer is 3.
In the second sample number 447 doesn't fit in, as it contains more than two lucky digits. All other numbers are fine, so the answer is 2. | ```python
def number_of_lucky_digit(a, k):
ans = False
ans1 = 0
for i in a:
if i in ['4', '7']:
ans1 += 1
if ans1<=k:
ans + True
return ans
n = int(input())
k = int(input())
numbers = input()
numberss = numbers.split(" ")
for i in numbers:
ans
if number_of_lucky_digit(i, k)==True:
ans += 1
print(ans)
``` | -1 | |
746 | B | Decoding | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Polycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the two middle letters. In the following examples, the median letter is highlighted: contest, info. If the word consists of single letter, then according to above definition this letter is the median letter.
Polycarp encodes each word in the following way: he writes down the median letter of the word, then deletes it and repeats the process until there are no letters left. For example, he encodes the word volga as logva.
You are given an encoding *s* of some word, your task is to decode it. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=2000) — the length of the encoded word.
The second line contains the string *s* of length *n* consisting of lowercase English letters — the encoding. | Print the word that Polycarp encoded. | [
"5\nlogva\n",
"2\nno\n",
"4\nabba\n"
] | [
"volga\n",
"no\n",
"baba\n"
] | In the first example Polycarp encoded the word volga. At first, he wrote down the letter l from the position 3, after that his word looked like voga. After that Polycarp wrote down the letter o from the position 2, his word became vga. Then Polycarp wrote down the letter g which was at the second position, the word became va. Then he wrote down the letter v, then the letter a. Thus, the encoding looked like logva.
In the second example Polycarp encoded the word no. He wrote down the letter n, the word became o, and he wrote down the letter o. Thus, in this example, the word and its encoding are the same.
In the third example Polycarp encoded the word baba. At first, he wrote down the letter a, which was at the position 2, after that the word looked like bba. Then he wrote down the letter b, which was at the position 2, his word looked like ba. After that he wrote down the letter b, which was at the position 1, the word looked like a, and he wrote down that letter a. Thus, the encoding is abba. | 1,000 | [
{
"input": "5\nlogva",
"output": "volga"
},
{
"input": "2\nno",
"output": "no"
},
{
"input": "4\nabba",
"output": "baba"
},
{
"input": "51\nkfsmpaeviowvkdbuhdagquxxqniselafnfbrgbhmsugcbbnlrvv",
"output": "vlbcumbrfflsnxugdudvovamfkspeiwkbhaqxqieanbghsgbnrv"
},
{
"... | 1,699,174,026 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 34 | 61 | 1,536,000 | n=int(input())
s=input()
l=[]
if len(s)%2==0:
for i in range(0,len(s)):
if i==0:
l.append(s[i])
elif i%2==0:
l.insert(0,s[i])
else:
l.append(s[i])
else:
for i in range(0,len(s)):
if i==0:
l.append(s[i])
elif i%2!=0:
l.insert(0,s[i])
else:
l.append(s[i])
st=""
for i in l:
st=st+i
print(st)
| Title: Decoding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the two middle letters. In the following examples, the median letter is highlighted: contest, info. If the word consists of single letter, then according to above definition this letter is the median letter.
Polycarp encodes each word in the following way: he writes down the median letter of the word, then deletes it and repeats the process until there are no letters left. For example, he encodes the word volga as logva.
You are given an encoding *s* of some word, your task is to decode it.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=2000) — the length of the encoded word.
The second line contains the string *s* of length *n* consisting of lowercase English letters — the encoding.
Output Specification:
Print the word that Polycarp encoded.
Demo Input:
['5\nlogva\n', '2\nno\n', '4\nabba\n']
Demo Output:
['volga\n', 'no\n', 'baba\n']
Note:
In the first example Polycarp encoded the word volga. At first, he wrote down the letter l from the position 3, after that his word looked like voga. After that Polycarp wrote down the letter o from the position 2, his word became vga. Then Polycarp wrote down the letter g which was at the second position, the word became va. Then he wrote down the letter v, then the letter a. Thus, the encoding looked like logva.
In the second example Polycarp encoded the word no. He wrote down the letter n, the word became o, and he wrote down the letter o. Thus, in this example, the word and its encoding are the same.
In the third example Polycarp encoded the word baba. At first, he wrote down the letter a, which was at the position 2, after that the word looked like bba. Then he wrote down the letter b, which was at the position 2, his word looked like ba. After that he wrote down the letter b, which was at the position 1, the word looked like a, and he wrote down that letter a. Thus, the encoding is abba. | ```python
n=int(input())
s=input()
l=[]
if len(s)%2==0:
for i in range(0,len(s)):
if i==0:
l.append(s[i])
elif i%2==0:
l.insert(0,s[i])
else:
l.append(s[i])
else:
for i in range(0,len(s)):
if i==0:
l.append(s[i])
elif i%2!=0:
l.insert(0,s[i])
else:
l.append(s[i])
st=""
for i in l:
st=st+i
print(st)
``` | 3 | |
611 | C | New Year and Domino | PROGRAMMING | 1,500 | [
"dp",
"implementation"
] | null | null | They say "years are like dominoes, tumbling one after the other". But would a year fit into a grid? I don't think so.
Limak is a little polar bear who loves to play. He has recently got a rectangular grid with *h* rows and *w* columns. Each cell is a square, either empty (denoted by '.') or forbidden (denoted by '#'). Rows are numbered 1 through *h* from top to bottom. Columns are numbered 1 through *w* from left to right.
Also, Limak has a single domino. He wants to put it somewhere in a grid. A domino will occupy exactly two adjacent cells, located either in one row or in one column. Both adjacent cells must be empty and must be inside a grid.
Limak needs more fun and thus he is going to consider some queries. In each query he chooses some rectangle and wonders, how many way are there to put a single domino inside of the chosen rectangle? | The first line of the input contains two integers *h* and *w* (1<=≤<=*h*,<=*w*<=≤<=500) – the number of rows and the number of columns, respectively.
The next *h* lines describe a grid. Each line contains a string of the length *w*. Each character is either '.' or '#' — denoting an empty or forbidden cell, respectively.
The next line contains a single integer *q* (1<=≤<=*q*<=≤<=100<=000) — the number of queries.
Each of the next *q* lines contains four integers *r*1*i*, *c*1*i*, *r*2*i*, *c*2*i* (1<=≤<=*r*1*i*<=≤<=*r*2*i*<=≤<=*h*,<=1<=≤<=*c*1*i*<=≤<=*c*2*i*<=≤<=*w*) — the *i*-th query. Numbers *r*1*i* and *c*1*i* denote the row and the column (respectively) of the upper left cell of the rectangle. Numbers *r*2*i* and *c*2*i* denote the row and the column (respectively) of the bottom right cell of the rectangle. | Print *q* integers, *i*-th should be equal to the number of ways to put a single domino inside the *i*-th rectangle. | [
"5 8\n....#..#\n.#......\n##.#....\n##..#.##\n........\n4\n1 1 2 3\n4 1 4 1\n1 2 4 5\n2 5 5 8\n",
"7 39\n.......................................\n.###..###..#..###.....###..###..#..###.\n...#..#.#..#..#.........#..#.#..#..#...\n.###..#.#..#..###.....###..#.#..#..###.\n.#....#.#..#....#.....#....#.#..#..#.#.\n.###... | [
"4\n0\n10\n15\n",
"53\n89\n120\n23\n0\n2\n"
] | A red frame below corresponds to the first query of the first sample. A domino can be placed in 4 possible ways. | 1,250 | [
{
"input": "5 8\n....#..#\n.#......\n##.#....\n##..#.##\n........\n4\n1 1 2 3\n4 1 4 1\n1 2 4 5\n2 5 5 8",
"output": "4\n0\n10\n15"
},
{
"input": "7 39\n.......................................\n.###..###..#..###.....###..###..#..###.\n...#..#.#..#..#.........#..#.#..#..#...\n.###..#.#..#..###.....##... | 1,451,590,805 | 2,147,483,647 | Python 3 | OK | TESTS | 52 | 1,497 | 17,920,000 | h, w = list(map(int, input().split()))
mp = []
mp.append(list("#" * (w + 2)))
for i in range(h):
mp.append(list(input()))
mp[i + 1].insert(0, "#")
mp[i + 1].append("#")
mp.append(list("#" * (w + 2)))
mpV = []
mpH = []
mpV.append([])
mpH.append([])
for i in range(w + 2):
mpV[0].append(0)
mpH[0].append(0)
for i in range(1, h + 2):
mpV.append([])
mpH.append([])
mpV[i].append(0)
mpH[i].append(0)
for j in range(1, w + 2):
mpV[i].append(mpV[i][j - 1] + mpV[i - 1][j] - mpV[i - 1][j - 1] + (
1 if mp[i][j] == "." and mp[i + 1][j] == "." else 0))
mpH[i].append(mpH[i][j - 1] + mpH[i - 1][j] - mpH[i - 1][j - 1] + (
1 if mp[i][j] == "." and mp[i][j + 1] == "." else 0))
anc = []
n = int(input())
for k in range(n):
y0, x0, y1, x1 = list(map(int, input().split()))
A = mpV[y0 - 1][x0 - 1]+mpV[y1-1][x1]-mpV[y1-1][x0-1]-mpV[y0-1][x1]
A += mpH[y0 - 1][x0 - 1]+mpH[y1][x1-1]-mpH[y1][x0-1]-mpH[y0-1][x1-1]
anc.append(A)
for k in range(n):
print(anc[k]) | Title: New Year and Domino
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
They say "years are like dominoes, tumbling one after the other". But would a year fit into a grid? I don't think so.
Limak is a little polar bear who loves to play. He has recently got a rectangular grid with *h* rows and *w* columns. Each cell is a square, either empty (denoted by '.') or forbidden (denoted by '#'). Rows are numbered 1 through *h* from top to bottom. Columns are numbered 1 through *w* from left to right.
Also, Limak has a single domino. He wants to put it somewhere in a grid. A domino will occupy exactly two adjacent cells, located either in one row or in one column. Both adjacent cells must be empty and must be inside a grid.
Limak needs more fun and thus he is going to consider some queries. In each query he chooses some rectangle and wonders, how many way are there to put a single domino inside of the chosen rectangle?
Input Specification:
The first line of the input contains two integers *h* and *w* (1<=≤<=*h*,<=*w*<=≤<=500) – the number of rows and the number of columns, respectively.
The next *h* lines describe a grid. Each line contains a string of the length *w*. Each character is either '.' or '#' — denoting an empty or forbidden cell, respectively.
The next line contains a single integer *q* (1<=≤<=*q*<=≤<=100<=000) — the number of queries.
Each of the next *q* lines contains four integers *r*1*i*, *c*1*i*, *r*2*i*, *c*2*i* (1<=≤<=*r*1*i*<=≤<=*r*2*i*<=≤<=*h*,<=1<=≤<=*c*1*i*<=≤<=*c*2*i*<=≤<=*w*) — the *i*-th query. Numbers *r*1*i* and *c*1*i* denote the row and the column (respectively) of the upper left cell of the rectangle. Numbers *r*2*i* and *c*2*i* denote the row and the column (respectively) of the bottom right cell of the rectangle.
Output Specification:
Print *q* integers, *i*-th should be equal to the number of ways to put a single domino inside the *i*-th rectangle.
Demo Input:
['5 8\n....#..#\n.#......\n##.#....\n##..#.##\n........\n4\n1 1 2 3\n4 1 4 1\n1 2 4 5\n2 5 5 8\n', '7 39\n.......................................\n.###..###..#..###.....###..###..#..###.\n...#..#.#..#..#.........#..#.#..#..#...\n.###..#.#..#..###.....###..#.#..#..###.\n.#....#.#..#....#.....#....#.#..#..#.#.\n.###..###..#..###.....###..###..#..###.\n.......................................\n6\n1 1 3 20\n2 10 6 30\n2 10 7 30\n2 2 7 7\n1 7 7 7\n1 8 7 8\n']
Demo Output:
['4\n0\n10\n15\n', '53\n89\n120\n23\n0\n2\n']
Note:
A red frame below corresponds to the first query of the first sample. A domino can be placed in 4 possible ways. | ```python
h, w = list(map(int, input().split()))
mp = []
mp.append(list("#" * (w + 2)))
for i in range(h):
mp.append(list(input()))
mp[i + 1].insert(0, "#")
mp[i + 1].append("#")
mp.append(list("#" * (w + 2)))
mpV = []
mpH = []
mpV.append([])
mpH.append([])
for i in range(w + 2):
mpV[0].append(0)
mpH[0].append(0)
for i in range(1, h + 2):
mpV.append([])
mpH.append([])
mpV[i].append(0)
mpH[i].append(0)
for j in range(1, w + 2):
mpV[i].append(mpV[i][j - 1] + mpV[i - 1][j] - mpV[i - 1][j - 1] + (
1 if mp[i][j] == "." and mp[i + 1][j] == "." else 0))
mpH[i].append(mpH[i][j - 1] + mpH[i - 1][j] - mpH[i - 1][j - 1] + (
1 if mp[i][j] == "." and mp[i][j + 1] == "." else 0))
anc = []
n = int(input())
for k in range(n):
y0, x0, y1, x1 = list(map(int, input().split()))
A = mpV[y0 - 1][x0 - 1]+mpV[y1-1][x1]-mpV[y1-1][x0-1]-mpV[y0-1][x1]
A += mpH[y0 - 1][x0 - 1]+mpH[y1][x1-1]-mpH[y1][x0-1]-mpH[y0-1][x1-1]
anc.append(A)
for k in range(n):
print(anc[k])
``` | 3 | |
465 | B | Inbox (100500) | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
- Move from the list of letters to the content of any single letter.- Return to the list of letters from single letter viewing mode.- In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters? | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of letters in the mailbox.
The second line contains *n* space-separated integers (zeros and ones) — the state of the letter list. The *i*-th number equals either 1, if the *i*-th number is unread, or 0, if the *i*-th letter is read. | Print a single number — the minimum number of operations needed to make all the letters read. | [
"5\n0 1 0 1 0\n",
"5\n1 1 0 0 1\n",
"2\n0 0\n"
] | [
"3\n",
"4\n",
"0\n"
] | In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read. | 1,000 | [
{
"input": "5\n0 1 0 1 0",
"output": "3"
},
{
"input": "5\n1 1 0 0 1",
"output": "4"
},
{
"input": "2\n0 0",
"output": "0"
},
{
"input": "9\n1 0 1 0 1 0 1 0 1",
"output": "9"
},
{
"input": "5\n1 1 1 1 1",
"output": "5"
},
{
"input": "14\n0 0 1 1 1 0 1 ... | 1,411,559,298 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 62 | 0 | n = int(input())
a = [int(i) for i in input().split()]
r = 0
b = False
for i in a:
if i == 0:
r += 1 if b else 0
b = False
else:
r += 1
b = True
print(r if b else max(r - 1, 0))
| Title: Inbox (100500)
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Over time, Alexey's mail box got littered with too many letters. Some of them are read, while others are unread.
Alexey's mail program can either show a list of all letters or show the content of a single letter. As soon as the program shows the content of an unread letter, it becomes read letter (if the program shows the content of a read letter nothing happens). In one click he can do any of the following operations:
- Move from the list of letters to the content of any single letter.- Return to the list of letters from single letter viewing mode.- In single letter viewing mode, move to the next or to the previous letter in the list. You cannot move from the first letter to the previous one or from the last letter to the next one.
The program cannot delete the letters from the list or rearrange them.
Alexey wants to read all the unread letters and go watch football. Now he is viewing the list of all letters and for each letter he can see if it is read or unread. What minimum number of operations does Alexey need to perform to read all unread letters?
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of letters in the mailbox.
The second line contains *n* space-separated integers (zeros and ones) — the state of the letter list. The *i*-th number equals either 1, if the *i*-th number is unread, or 0, if the *i*-th letter is read.
Output Specification:
Print a single number — the minimum number of operations needed to make all the letters read.
Demo Input:
['5\n0 1 0 1 0\n', '5\n1 1 0 0 1\n', '2\n0 0\n']
Demo Output:
['3\n', '4\n', '0\n']
Note:
In the first sample Alexey needs three operations to cope with the task: open the second letter, move to the third one, move to the fourth one.
In the second sample the action plan: open the first letter, move to the second letter, return to the list, open the fifth letter.
In the third sample all letters are already read. | ```python
n = int(input())
a = [int(i) for i in input().split()]
r = 0
b = False
for i in a:
if i == 0:
r += 1 if b else 0
b = False
else:
r += 1
b = True
print(r if b else max(r - 1, 0))
``` | 3 | |
855 | A | Tom Riddle's Diary | PROGRAMMING | 800 | [
"brute force",
"implementation",
"strings"
] | null | null | Harry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber of Secrets. Harry wants to know the different people who had ever possessed the diary to make sure they are not under its influence.
He has names of *n* people who possessed the diary in order. You need to tell, for each person, if he/she possessed the diary at some point before or not.
Formally, for a name *s**i* in the *i*-th line, output "YES" (without quotes) if there exists an index *j* such that *s**i*<==<=*s**j* and *j*<=<<=*i*, otherwise, output "NO" (without quotes). | First line of input contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of names in the list.
Next *n* lines each contain a string *s**i*, consisting of lowercase English letters. The length of each string is between 1 and 100. | Output *n* lines each containing either "YES" or "NO" (without quotes), depending on whether this string was already present in the stream or not.
You can print each letter in any case (upper or lower). | [
"6\ntom\nlucius\nginny\nharry\nginny\nharry\n",
"3\na\na\na\n"
] | [
"NO\nNO\nNO\nNO\nYES\nYES\n",
"NO\nYES\nYES\n"
] | In test case 1, for *i* = 5 there exists *j* = 3 such that *s*<sub class="lower-index">*i*</sub> = *s*<sub class="lower-index">*j*</sub> and *j* < *i*, which means that answer for *i* = 5 is "YES". | 500 | [
{
"input": "6\ntom\nlucius\nginny\nharry\nginny\nharry",
"output": "NO\nNO\nNO\nNO\nYES\nYES"
},
{
"input": "3\na\na\na",
"output": "NO\nYES\nYES"
},
{
"input": "1\nzn",
"output": "NO"
},
{
"input": "9\nliyzmbjwnzryjokufuxcqtzwworjeoxkbaqrujrhdidqdvwdfzilwszgnzglnnbogaclckfnb... | 1,671,964,468 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 55 | 62 | 0 | temp = []
for rangavazzala in range(int(input())):
name = input()
if name not in temp:
print("NO")
temp.append(name)
else:
print("YES")
| Title: Tom Riddle's Diary
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Harry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber of Secrets. Harry wants to know the different people who had ever possessed the diary to make sure they are not under its influence.
He has names of *n* people who possessed the diary in order. You need to tell, for each person, if he/she possessed the diary at some point before or not.
Formally, for a name *s**i* in the *i*-th line, output "YES" (without quotes) if there exists an index *j* such that *s**i*<==<=*s**j* and *j*<=<<=*i*, otherwise, output "NO" (without quotes).
Input Specification:
First line of input contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of names in the list.
Next *n* lines each contain a string *s**i*, consisting of lowercase English letters. The length of each string is between 1 and 100.
Output Specification:
Output *n* lines each containing either "YES" or "NO" (without quotes), depending on whether this string was already present in the stream or not.
You can print each letter in any case (upper or lower).
Demo Input:
['6\ntom\nlucius\nginny\nharry\nginny\nharry\n', '3\na\na\na\n']
Demo Output:
['NO\nNO\nNO\nNO\nYES\nYES\n', 'NO\nYES\nYES\n']
Note:
In test case 1, for *i* = 5 there exists *j* = 3 such that *s*<sub class="lower-index">*i*</sub> = *s*<sub class="lower-index">*j*</sub> and *j* < *i*, which means that answer for *i* = 5 is "YES". | ```python
temp = []
for rangavazzala in range(int(input())):
name = input()
if name not in temp:
print("NO")
temp.append(name)
else:
print("YES")
``` | 3 | |
150 | A | Win or Freeze | PROGRAMMING | 1,400 | [
"games",
"math",
"number theory"
] | null | null | You can't possibly imagine how cold our friends are this winter in Nvodsk! Two of them play the following game to warm up: initially a piece of paper has an integer *q*. During a move a player should write any integer number that is a non-trivial divisor of the last written number. Then he should run this number of circles around the hotel. Let us remind you that a number's divisor is called non-trivial if it is different from one and from the divided number itself.
The first person who can't make a move wins as he continues to lie in his warm bed under three blankets while the other one keeps running. Determine which player wins considering that both players play optimally. If the first player wins, print any winning first move. | The first line contains the only integer *q* (1<=≤<=*q*<=≤<=1013).
Please do not use the %lld specificator to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specificator. | In the first line print the number of the winning player (1 or 2). If the first player wins then the second line should contain another integer — his first move (if the first player can't even make the first move, print 0). If there are multiple solutions, print any of them. | [
"6\n",
"30\n",
"1\n"
] | [
"2\n",
"1\n6\n",
"1\n0\n"
] | Number 6 has only two non-trivial divisors: 2 and 3. It is impossible to make a move after the numbers 2 and 3 are written, so both of them are winning, thus, number 6 is the losing number. A player can make a move and write number 6 after number 30; 6, as we know, is a losing number. Thus, this move will bring us the victory. | 500 | [
{
"input": "6",
"output": "2"
},
{
"input": "30",
"output": "1\n6"
},
{
"input": "1",
"output": "1\n0"
},
{
"input": "2",
"output": "1\n0"
},
{
"input": "3",
"output": "1\n0"
},
{
"input": "5",
"output": "1\n0"
},
{
"input": "445538663413",... | 1,621,423,745 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 62 | 0 | from math import sqrt
a=int(input())
n=0
res=0
for i in range(2,int(sqrt(a))+1):
if a%i==0:
n+=1
res=i
if n>1:
break
if n>1:
print(1)
print(res)
else:
if n==0:
print(1)
print(0)
else:
print(2)
| Title: Win or Freeze
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You can't possibly imagine how cold our friends are this winter in Nvodsk! Two of them play the following game to warm up: initially a piece of paper has an integer *q*. During a move a player should write any integer number that is a non-trivial divisor of the last written number. Then he should run this number of circles around the hotel. Let us remind you that a number's divisor is called non-trivial if it is different from one and from the divided number itself.
The first person who can't make a move wins as he continues to lie in his warm bed under three blankets while the other one keeps running. Determine which player wins considering that both players play optimally. If the first player wins, print any winning first move.
Input Specification:
The first line contains the only integer *q* (1<=≤<=*q*<=≤<=1013).
Please do not use the %lld specificator to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specificator.
Output Specification:
In the first line print the number of the winning player (1 or 2). If the first player wins then the second line should contain another integer — his first move (if the first player can't even make the first move, print 0). If there are multiple solutions, print any of them.
Demo Input:
['6\n', '30\n', '1\n']
Demo Output:
['2\n', '1\n6\n', '1\n0\n']
Note:
Number 6 has only two non-trivial divisors: 2 and 3. It is impossible to make a move after the numbers 2 and 3 are written, so both of them are winning, thus, number 6 is the losing number. A player can make a move and write number 6 after number 30; 6, as we know, is a losing number. Thus, this move will bring us the victory. | ```python
from math import sqrt
a=int(input())
n=0
res=0
for i in range(2,int(sqrt(a))+1):
if a%i==0:
n+=1
res=i
if n>1:
break
if n>1:
print(1)
print(res)
else:
if n==0:
print(1)
print(0)
else:
print(2)
``` | 0 | |
429 | A | Xor-tree | PROGRAMMING | 1,300 | [
"dfs and similar",
"trees"
] | null | null | Iahub is very proud of his recent discovery, propagating trees. Right now, he invented a new tree, called xor-tree. After this new revolutionary discovery, he invented a game for kids which uses xor-trees.
The game is played on a tree having *n* nodes, numbered from 1 to *n*. Each node *i* has an initial value *init**i*, which is either 0 or 1. The root of the tree is node 1.
One can perform several (possibly, zero) operations on the tree during the game. The only available type of operation is to pick a node *x*. Right after someone has picked node *x*, the value of node *x* flips, the values of sons of *x* remain the same, the values of sons of sons of *x* flips, the values of sons of sons of sons of *x* remain the same and so on.
The goal of the game is to get each node *i* to have value *goal**i*, which can also be only 0 or 1. You need to reach the goal of the game by using minimum number of operations. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105). Each of the next *n*<=-<=1 lines contains two integers *u**i* and *v**i* (1<=≤<=*u**i*,<=*v**i*<=≤<=*n*; *u**i*<=≠<=*v**i*) meaning there is an edge between nodes *u**i* and *v**i*.
The next line contains *n* integer numbers, the *i*-th of them corresponds to *init**i* (*init**i* is either 0 or 1). The following line also contains *n* integer numbers, the *i*-th number corresponds to *goal**i* (*goal**i* is either 0 or 1). | In the first line output an integer number *cnt*, representing the minimal number of operations you perform. Each of the next *cnt* lines should contain an integer *x**i*, representing that you pick a node *x**i*. | [
"10\n2 1\n3 1\n4 2\n5 1\n6 2\n7 5\n8 6\n9 8\n10 5\n1 0 1 1 0 1 0 1 0 1\n1 0 1 0 0 1 1 1 0 1\n"
] | [
"2\n4\n7\n"
] | none | 500 | [
{
"input": "10\n2 1\n3 1\n4 2\n5 1\n6 2\n7 5\n8 6\n9 8\n10 5\n1 0 1 1 0 1 0 1 0 1\n1 0 1 0 0 1 1 1 0 1",
"output": "2\n4\n7"
},
{
"input": "15\n2 1\n3 2\n4 3\n5 4\n6 5\n7 6\n8 7\n9 8\n10 9\n11 10\n12 11\n13 12\n14 13\n15 14\n0 1 0 0 1 1 1 1 1 1 0 0 0 1 1\n1 1 1 1 0 0 1 1 0 1 0 0 1 1 0",
"output"... | 1,643,016,500 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | def dfs(node,par,papu,mypapu):
v=intial[node]
if mypapu:
v=(v+1)%2
if v!=final[node]:
ans.append(node)
for child in graph[node]:
if child!=par:
yield dfs(child,node,(mypapu+1)%2,papu)
else :
for child in graph[node]:
if child!=par:
yield dfs(child,node,mypapu,papu)
yield
n=int(input())
graph=[[] for _ in range(n)]
for _ in range(n-1):
s,d=map(int,input().split())
s-=1
d-=1
graph[s].append(d)
graph[d].append(s)
ans=[]
intial=list(map(int,input().split()))
final=list(map(int,input().split()))
dfs(0,-1,0,0)
print(len(ans))
for el in ans:
print(el+1)
| Title: Xor-tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Iahub is very proud of his recent discovery, propagating trees. Right now, he invented a new tree, called xor-tree. After this new revolutionary discovery, he invented a game for kids which uses xor-trees.
The game is played on a tree having *n* nodes, numbered from 1 to *n*. Each node *i* has an initial value *init**i*, which is either 0 or 1. The root of the tree is node 1.
One can perform several (possibly, zero) operations on the tree during the game. The only available type of operation is to pick a node *x*. Right after someone has picked node *x*, the value of node *x* flips, the values of sons of *x* remain the same, the values of sons of sons of *x* flips, the values of sons of sons of sons of *x* remain the same and so on.
The goal of the game is to get each node *i* to have value *goal**i*, which can also be only 0 or 1. You need to reach the goal of the game by using minimum number of operations.
Input Specification:
The first line contains an integer *n* (1<=≤<=*n*<=≤<=105). Each of the next *n*<=-<=1 lines contains two integers *u**i* and *v**i* (1<=≤<=*u**i*,<=*v**i*<=≤<=*n*; *u**i*<=≠<=*v**i*) meaning there is an edge between nodes *u**i* and *v**i*.
The next line contains *n* integer numbers, the *i*-th of them corresponds to *init**i* (*init**i* is either 0 or 1). The following line also contains *n* integer numbers, the *i*-th number corresponds to *goal**i* (*goal**i* is either 0 or 1).
Output Specification:
In the first line output an integer number *cnt*, representing the minimal number of operations you perform. Each of the next *cnt* lines should contain an integer *x**i*, representing that you pick a node *x**i*.
Demo Input:
['10\n2 1\n3 1\n4 2\n5 1\n6 2\n7 5\n8 6\n9 8\n10 5\n1 0 1 1 0 1 0 1 0 1\n1 0 1 0 0 1 1 1 0 1\n']
Demo Output:
['2\n4\n7\n']
Note:
none | ```python
def dfs(node,par,papu,mypapu):
v=intial[node]
if mypapu:
v=(v+1)%2
if v!=final[node]:
ans.append(node)
for child in graph[node]:
if child!=par:
yield dfs(child,node,(mypapu+1)%2,papu)
else :
for child in graph[node]:
if child!=par:
yield dfs(child,node,mypapu,papu)
yield
n=int(input())
graph=[[] for _ in range(n)]
for _ in range(n-1):
s,d=map(int,input().split())
s-=1
d-=1
graph[s].append(d)
graph[d].append(s)
ans=[]
intial=list(map(int,input().split()))
final=list(map(int,input().split()))
dfs(0,-1,0,0)
print(len(ans))
for el in ans:
print(el+1)
``` | 0 | |
707 | A | Brain's Photos | PROGRAMMING | 800 | [
"implementation"
] | null | null | Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a lot of colourful pictures on colored and black-and-white film. Then he developed and translated it into a digital form. But now, color and black-and-white photos are in one folder, and to sort them, one needs to spend more than one hour!
As soon as Brain is a photographer not programmer now, he asks you to help him determine for a single photo whether it is colored or black-and-white.
Photo can be represented as a matrix sized *n*<=×<=*m*, and each element of the matrix stores a symbol indicating corresponding pixel color. There are only 6 colors:
- 'C' (cyan)- 'M' (magenta)- 'Y' (yellow)- 'W' (white)- 'G' (grey)- 'B' (black)
The photo is considered black-and-white if it has only white, black and grey pixels in it. If there are any of cyan, magenta or yellow pixels in the photo then it is considered colored. | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line is one of the 'C', 'M', 'Y', 'W', 'G' or 'B'. | Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line. | [
"2 2\nC M\nY Y\n",
"3 2\nW W\nW W\nB B\n",
"1 1\nW\n"
] | [
"#Color",
"#Black&White",
"#Black&White"
] | none | 500 | [
{
"input": "2 2\nC M\nY Y",
"output": "#Color"
},
{
"input": "3 2\nW W\nW W\nB B",
"output": "#Black&White"
},
{
"input": "1 1\nW",
"output": "#Black&White"
},
{
"input": "2 3\nW W W\nB G Y",
"output": "#Color"
},
{
"input": "1 1\nW",
"output": "#Black&White"
... | 1,697,274,831 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | n,m=map(int,input().split())
l=["1"]
for i in range(n):
s=list(input().split())
l.extend(s)
count=0
for j in range(1,len(l)):
if(l[j]=="B"or l[j]=="G"or l[j]=="W"):
count=count+1
if(count==len(l)):
print("#Black&White")
else:
print("#Color") | Title: Brain's Photos
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Small, but very brave, mouse Brain was not accepted to summer school of young villains. He was upset and decided to postpone his plans of taking over the world, but to become a photographer instead.
As you may know, the coolest photos are on the film (because you can specify the hashtag #film for such).
Brain took a lot of colourful pictures on colored and black-and-white film. Then he developed and translated it into a digital form. But now, color and black-and-white photos are in one folder, and to sort them, one needs to spend more than one hour!
As soon as Brain is a photographer not programmer now, he asks you to help him determine for a single photo whether it is colored or black-and-white.
Photo can be represented as a matrix sized *n*<=×<=*m*, and each element of the matrix stores a symbol indicating corresponding pixel color. There are only 6 colors:
- 'C' (cyan)- 'M' (magenta)- 'Y' (yellow)- 'W' (white)- 'G' (grey)- 'B' (black)
The photo is considered black-and-white if it has only white, black and grey pixels in it. If there are any of cyan, magenta or yellow pixels in the photo then it is considered colored.
Input Specification:
The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of photo pixel matrix rows and columns respectively.
Then *n* lines describing matrix rows follow. Each of them contains *m* space-separated characters describing colors of pixels in a row. Each character in the line is one of the 'C', 'M', 'Y', 'W', 'G' or 'B'.
Output Specification:
Print the "#Black&White" (without quotes), if the photo is black-and-white and "#Color" (without quotes), if it is colored, in the only line.
Demo Input:
['2 2\nC M\nY Y\n', '3 2\nW W\nW W\nB B\n', '1 1\nW\n']
Demo Output:
['#Color', '#Black&White', '#Black&White']
Note:
none | ```python
n,m=map(int,input().split())
l=["1"]
for i in range(n):
s=list(input().split())
l.extend(s)
count=0
for j in range(1,len(l)):
if(l[j]=="B"or l[j]=="G"or l[j]=="W"):
count=count+1
if(count==len(l)):
print("#Black&White")
else:
print("#Color")
``` | 0 | |
801 | B | Valued Keys | PROGRAMMING | 900 | [
"constructive algorithms",
"greedy",
"strings"
] | null | null | You found a mysterious function *f*. The function takes two strings *s*1 and *s*2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function *f* is another string of the same length. The *i*-th character of the output is equal to the minimum of the *i*-th character of *s*1 and the *i*-th character of *s*2.
For example, *f*("ab", "ba") = "aa", and *f*("nzwzl", "zizez") = "niwel".
You found two strings *x* and *y* of the same length and consisting of only lowercase English letters. Find any string *z* such that *f*(*x*,<=*z*)<==<=*y*, or print -1 if no such string *z* exists. | The first line of input contains the string *x*.
The second line of input contains the string *y*.
Both *x* and *y* consist only of lowercase English letters, *x* and *y* have same length and this length is between 1 and 100. | If there is no string *z* such that *f*(*x*,<=*z*)<==<=*y*, print -1.
Otherwise, print a string *z* such that *f*(*x*,<=*z*)<==<=*y*. If there are multiple possible answers, print any of them. The string *z* should be the same length as *x* and *y* and consist only of lowercase English letters. | [
"ab\naa\n",
"nzwzl\nniwel\n",
"ab\nba\n"
] | [
"ba\n",
"xiyez\n",
"-1\n"
] | The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no *z* such that *f*("ab", *z*) = "ba". | 1,000 | [
{
"input": "ab\naa",
"output": "ba"
},
{
"input": "nzwzl\nniwel",
"output": "xiyez"
},
{
"input": "ab\nba",
"output": "-1"
},
{
"input": "r\nl",
"output": "l"
},
{
"input": "d\ny",
"output": "-1"
},
{
"input": "yvowz\ncajav",
"output": "cajav"
},... | 1,641,543,696 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 62 | 0 |
def f(x, y):
a = []
for i in range(len(x)):
if x[i] < y[i]:
return -1
else:
a.append(chr(ord(y[i])))
return ''.join(a)
x = input()
y = input()
print(f(x, y)) | Title: Valued Keys
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You found a mysterious function *f*. The function takes two strings *s*1 and *s*2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function *f* is another string of the same length. The *i*-th character of the output is equal to the minimum of the *i*-th character of *s*1 and the *i*-th character of *s*2.
For example, *f*("ab", "ba") = "aa", and *f*("nzwzl", "zizez") = "niwel".
You found two strings *x* and *y* of the same length and consisting of only lowercase English letters. Find any string *z* such that *f*(*x*,<=*z*)<==<=*y*, or print -1 if no such string *z* exists.
Input Specification:
The first line of input contains the string *x*.
The second line of input contains the string *y*.
Both *x* and *y* consist only of lowercase English letters, *x* and *y* have same length and this length is between 1 and 100.
Output Specification:
If there is no string *z* such that *f*(*x*,<=*z*)<==<=*y*, print -1.
Otherwise, print a string *z* such that *f*(*x*,<=*z*)<==<=*y*. If there are multiple possible answers, print any of them. The string *z* should be the same length as *x* and *y* and consist only of lowercase English letters.
Demo Input:
['ab\naa\n', 'nzwzl\nniwel\n', 'ab\nba\n']
Demo Output:
['ba\n', 'xiyez\n', '-1\n']
Note:
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no *z* such that *f*("ab", *z*) = "ba". | ```python
def f(x, y):
a = []
for i in range(len(x)):
if x[i] < y[i]:
return -1
else:
a.append(chr(ord(y[i])))
return ''.join(a)
x = input()
y = input()
print(f(x, y))
``` | 3 | |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,659,868,543 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 92 | 0 | n = int(input())
b = [0, 0, 0]
for i in range(n):
a = list(map(int, input().split()))
for i in range(3):
b[i] += a[i]
if b[0] == 0 and b[1] == 0 and b[2] == 0:
print("YES")
else:
print("NO") | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).
Output Specification:
Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.
Demo Input:
['3\n4 1 7\n-2 4 -1\n1 -5 -3\n', '3\n3 -1 7\n-5 2 -4\n2 -1 -3\n']
Demo Output:
['NO', 'YES']
Note:
none | ```python
n = int(input())
b = [0, 0, 0]
for i in range(n):
a = list(map(int, input().split()))
for i in range(3):
b[i] += a[i]
if b[0] == 0 and b[1] == 0 and b[2] == 0:
print("YES")
else:
print("NO")
``` | 3.977 |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word. | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,617,983,582 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 124 | 0 | s = input()
c1=0;c2=0;
for i in s:
if(i.lower()==i):
c1+=1;
else:
c2+=1;
print(s.lower()) if c1>=c2 else print(s.upper()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word.
Input Specification:
The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100.
Output Specification:
Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one.
Demo Input:
['HoUse\n', 'ViP\n', 'maTRIx\n']
Demo Output:
['house\n', 'VIP\n', 'matrix\n']
Note:
none | ```python
s = input()
c1=0;c2=0;
for i in s:
if(i.lower()==i):
c1+=1;
else:
c2+=1;
print(s.lower()) if c1>=c2 else print(s.upper())
``` | 3.969 |
614 | A | Link/Cut Tree | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand the definition of this procedure, so he decided to ask programmer Serezha to help him. Serezha agreed to help if Rostislav solves a simple task (and if he doesn't, then why would he need Splay trees anyway?)
Given integers *l*, *r* and *k*, you need to print all powers of number *k* within range from *l* to *r* inclusive. However, Rostislav doesn't want to spent time doing this, as he got interested in playing a network game called Agar with Gleb. Help him! | The first line of the input contains three space-separated integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=1018, 2<=≤<=*k*<=≤<=109). | Print all powers of number *k*, that lie within range from *l* to *r* in the increasing order. If there are no such numbers, print "-1" (without the quotes). | [
"1 10 2\n",
"2 4 5\n"
] | [
"1 2 4 8 ",
"-1"
] | Note to the first sample: numbers 2<sup class="upper-index">0</sup> = 1, 2<sup class="upper-index">1</sup> = 2, 2<sup class="upper-index">2</sup> = 4, 2<sup class="upper-index">3</sup> = 8 lie within the specified range. The number 2<sup class="upper-index">4</sup> = 16 is greater then 10, thus it shouldn't be printed. | 500 | [
{
"input": "1 10 2",
"output": "1 2 4 8 "
},
{
"input": "2 4 5",
"output": "-1"
},
{
"input": "18102 43332383920 28554",
"output": "28554 815330916 "
},
{
"input": "19562 31702689720 17701",
"output": "313325401 "
},
{
"input": "11729 55221128400 313",
"output... | 1,622,076,631 | 331 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 92 | 102,400 | from collections import defaultdict, deque
from heapq import heappush, heappop
from math import inf, log
ri = lambda : map(int, input().split())
ro = lambda : int(input())
def solve():
l,r,k = ri()
if k > r:
print(-1)
return
elif k < l:
if k == 1:
print(1)
return
curr = int(log(l, k))
curr += 1
while curr <= r:
print(curr, end = " ")
curr *= k
else:
print(1, end = " ")
curr = k
while curr <= r:
print(curr, end = " ")
curr *= k
print()
t = 1
#t = int(input())
while t:
t -= 1
solve()
| Title: Link/Cut Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Programmer Rostislav got seriously interested in the Link/Cut Tree data structure, which is based on Splay trees. Specifically, he is now studying the *expose* procedure.
Unfortunately, Rostislav is unable to understand the definition of this procedure, so he decided to ask programmer Serezha to help him. Serezha agreed to help if Rostislav solves a simple task (and if he doesn't, then why would he need Splay trees anyway?)
Given integers *l*, *r* and *k*, you need to print all powers of number *k* within range from *l* to *r* inclusive. However, Rostislav doesn't want to spent time doing this, as he got interested in playing a network game called Agar with Gleb. Help him!
Input Specification:
The first line of the input contains three space-separated integers *l*, *r* and *k* (1<=≤<=*l*<=≤<=*r*<=≤<=1018, 2<=≤<=*k*<=≤<=109).
Output Specification:
Print all powers of number *k*, that lie within range from *l* to *r* in the increasing order. If there are no such numbers, print "-1" (without the quotes).
Demo Input:
['1 10 2\n', '2 4 5\n']
Demo Output:
['1 2 4 8 ', '-1']
Note:
Note to the first sample: numbers 2<sup class="upper-index">0</sup> = 1, 2<sup class="upper-index">1</sup> = 2, 2<sup class="upper-index">2</sup> = 4, 2<sup class="upper-index">3</sup> = 8 lie within the specified range. The number 2<sup class="upper-index">4</sup> = 16 is greater then 10, thus it shouldn't be printed. | ```python
from collections import defaultdict, deque
from heapq import heappush, heappop
from math import inf, log
ri = lambda : map(int, input().split())
ro = lambda : int(input())
def solve():
l,r,k = ri()
if k > r:
print(-1)
return
elif k < l:
if k == 1:
print(1)
return
curr = int(log(l, k))
curr += 1
while curr <= r:
print(curr, end = " ")
curr *= k
else:
print(1, end = " ")
curr = k
while curr <= r:
print(curr, end = " ")
curr *= k
print()
t = 1
#t = int(input())
while t:
t -= 1
solve()
``` | 0 | |
122 | A | Lucky Division | PROGRAMMING | 1,000 | [
"brute force",
"number theory"
] | null | null | Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find out if the given number *n* is almost lucky. | The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked. | In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes). | [
"47\n",
"16\n",
"78\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | 500 | [
{
"input": "47",
"output": "YES"
},
{
"input": "16",
"output": "YES"
},
{
"input": "78",
"output": "NO"
},
{
"input": "48",
"output": "YES"
},
{
"input": "100",
"output": "YES"
},
{
"input": "107",
"output": "NO"
},
{
"input": "77",
"ou... | 1,699,633,382 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 92 | 0 |
lucky = [4,7,47,74,44,77,444,777,447,474,477,774,747,744]
n = int(input())
ans = False
if n in lucky:
ans=True
else:
for i in lucky:
if n%i == 0:
print(True)
break
| Title: Lucky Division
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find out if the given number *n* is almost lucky.
Input Specification:
The single line contains an integer *n* (1<=≤<=*n*<=≤<=1000) — the number that needs to be checked.
Output Specification:
In the only line print "YES" (without the quotes), if number *n* is almost lucky. Otherwise, print "NO" (without the quotes).
Demo Input:
['47\n', '16\n', '78\n']
Demo Output:
['YES\n', 'YES\n', 'NO\n']
Note:
Note that all lucky numbers are almost lucky as any number is evenly divisible by itself.
In the first sample 47 is a lucky number. In the second sample 16 is divisible by 4. | ```python
lucky = [4,7,47,74,44,77,444,777,447,474,477,774,747,744]
n = int(input())
ans = False
if n in lucky:
ans=True
else:
for i in lucky:
if n%i == 0:
print(True)
break
``` | 0 | |
453 | A | Little Pony and Expected Maximum | PROGRAMMING | 1,600 | [
"probabilities"
] | null | null | Twilight Sparkle was playing Ludo with her friends Rainbow Dash, Apple Jack and Flutter Shy. But she kept losing. Having returned to the castle, Twilight Sparkle became interested in the dice that were used in the game.
The dice has *m* faces: the first face of the dice contains a dot, the second one contains two dots, and so on, the *m*-th face contains *m* dots. Twilight Sparkle is sure that when the dice is tossed, each face appears with probability . Also she knows that each toss is independent from others. Help her to calculate the expected maximum number of dots she could get after tossing the dice *n* times. | A single line contains two integers *m* and *n* (1<=≤<=*m*,<=*n*<=≤<=105). | Output a single real number corresponding to the expected maximum. The answer will be considered correct if its relative or absolute error doesn't exceed 10<=<=-<=4. | [
"6 1\n",
"6 3\n",
"2 2\n"
] | [
"3.500000000000\n",
"4.958333333333\n",
"1.750000000000\n"
] | Consider the third test example. If you've made two tosses:
1. You can get 1 in the first toss, and 2 in the second. Maximum equals to 2. 1. You can get 1 in the first toss, and 1 in the second. Maximum equals to 1. 1. You can get 2 in the first toss, and 1 in the second. Maximum equals to 2. 1. You can get 2 in the first toss, and 2 in the second. Maximum equals to 2.
The probability of each outcome is 0.25, that is expectation equals to:
You can read about expectation using the following link: http://en.wikipedia.org/wiki/Expected_value | 500 | [
{
"input": "6 1",
"output": "3.500000000000"
},
{
"input": "6 3",
"output": "4.958333333333"
},
{
"input": "2 2",
"output": "1.750000000000"
},
{
"input": "5 4",
"output": "4.433600000000"
},
{
"input": "5 8",
"output": "4.814773760000"
},
{
"input": "... | 1,602,984,518 | 2,147,483,647 | Python 3 | OK | TESTS | 41 | 155 | 0 | faces,vezes = [int(s) for s in input().split(' ')]
total = 0
last = 0
for i in range(1, faces+1):
aux = (i/faces)**vezes
total += (aux-last)*i
last = aux
print(total)
| Title: Little Pony and Expected Maximum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Twilight Sparkle was playing Ludo with her friends Rainbow Dash, Apple Jack and Flutter Shy. But she kept losing. Having returned to the castle, Twilight Sparkle became interested in the dice that were used in the game.
The dice has *m* faces: the first face of the dice contains a dot, the second one contains two dots, and so on, the *m*-th face contains *m* dots. Twilight Sparkle is sure that when the dice is tossed, each face appears with probability . Also she knows that each toss is independent from others. Help her to calculate the expected maximum number of dots she could get after tossing the dice *n* times.
Input Specification:
A single line contains two integers *m* and *n* (1<=≤<=*m*,<=*n*<=≤<=105).
Output Specification:
Output a single real number corresponding to the expected maximum. The answer will be considered correct if its relative or absolute error doesn't exceed 10<=<=-<=4.
Demo Input:
['6 1\n', '6 3\n', '2 2\n']
Demo Output:
['3.500000000000\n', '4.958333333333\n', '1.750000000000\n']
Note:
Consider the third test example. If you've made two tosses:
1. You can get 1 in the first toss, and 2 in the second. Maximum equals to 2. 1. You can get 1 in the first toss, and 1 in the second. Maximum equals to 1. 1. You can get 2 in the first toss, and 1 in the second. Maximum equals to 2. 1. You can get 2 in the first toss, and 2 in the second. Maximum equals to 2.
The probability of each outcome is 0.25, that is expectation equals to:
You can read about expectation using the following link: http://en.wikipedia.org/wiki/Expected_value | ```python
faces,vezes = [int(s) for s in input().split(' ')]
total = 0
last = 0
for i in range(1, faces+1):
aux = (i/faces)**vezes
total += (aux-last)*i
last = aux
print(total)
``` | 3 | |
701 | A | Cards | PROGRAMMING | 800 | [
"greedy",
"implementation"
] | null | null | There are *n* cards (*n* is even) in the deck. Each card has a positive integer written on it. *n*<=/<=2 people will play new card game. At the beginning of the game each player gets two cards, each card is given to exactly one player.
Find the way to distribute cards such that the sum of values written of the cards will be equal for each player. It is guaranteed that it is always possible. | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=100) — the number of cards in the deck. It is guaranteed that *n* is even.
The second line contains the sequence of *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is equal to the number written on the *i*-th card. | Print *n*<=/<=2 pairs of integers, the *i*-th pair denote the cards that should be given to the *i*-th player. Each card should be given to exactly one player. Cards are numbered in the order they appear in the input.
It is guaranteed that solution exists. If there are several correct answers, you are allowed to print any of them. | [
"6\n1 5 7 4 4 3\n",
"4\n10 10 10 10\n"
] | [
"1 3\n6 2\n4 5\n",
"1 2\n3 4\n"
] | In the first sample, cards are distributed in such a way that each player has the sum of numbers written on his cards equal to 8.
In the second sample, all values *a*<sub class="lower-index">*i*</sub> are equal. Thus, any distribution is acceptable. | 500 | [
{
"input": "6\n1 5 7 4 4 3",
"output": "1 3\n6 2\n4 5"
},
{
"input": "4\n10 10 10 10",
"output": "1 4\n2 3"
},
{
"input": "100\n2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ... | 1,615,611,801 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 46 | 307,200 | n = int(input())
arr = list(map(int,input().split()))
s = sum(arr)//n
s *= 2
memo = {i:False for i in range(n)}
for i in range(n):
if memo[i] == False:
for j in range(i+1, n):
if memo[j] == False and arr[j] == s - arr[i]:
memo[j] = True
memo[i] = True
break
print(i+1,j+1)
| Title: Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cards (*n* is even) in the deck. Each card has a positive integer written on it. *n*<=/<=2 people will play new card game. At the beginning of the game each player gets two cards, each card is given to exactly one player.
Find the way to distribute cards such that the sum of values written of the cards will be equal for each player. It is guaranteed that it is always possible.
Input Specification:
The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=100) — the number of cards in the deck. It is guaranteed that *n* is even.
The second line contains the sequence of *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100), where *a**i* is equal to the number written on the *i*-th card.
Output Specification:
Print *n*<=/<=2 pairs of integers, the *i*-th pair denote the cards that should be given to the *i*-th player. Each card should be given to exactly one player. Cards are numbered in the order they appear in the input.
It is guaranteed that solution exists. If there are several correct answers, you are allowed to print any of them.
Demo Input:
['6\n1 5 7 4 4 3\n', '4\n10 10 10 10\n']
Demo Output:
['1 3\n6 2\n4 5\n', '1 2\n3 4\n']
Note:
In the first sample, cards are distributed in such a way that each player has the sum of numbers written on his cards equal to 8.
In the second sample, all values *a*<sub class="lower-index">*i*</sub> are equal. Thus, any distribution is acceptable. | ```python
n = int(input())
arr = list(map(int,input().split()))
s = sum(arr)//n
s *= 2
memo = {i:False for i in range(n)}
for i in range(n):
if memo[i] == False:
for j in range(i+1, n):
if memo[j] == False and arr[j] == s - arr[i]:
memo[j] = True
memo[i] = True
break
print(i+1,j+1)
``` | 0 | |
221 | A | Little Elephant and Function | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | The Little Elephant enjoys recursive functions.
This time he enjoys the sorting function. Let *a* is a permutation of an integers from 1 to *n*, inclusive, and *a**i* denotes the *i*-th element of the permutation. The Little Elephant's recursive function *f*(*x*), that sorts the first *x* permutation's elements, works as follows:
- If *x*<==<=1, exit the function. - Otherwise, call *f*(*x*<=-<=1), and then make *swap*(*a**x*<=-<=1,<=*a**x*) (swap the *x*-th and (*x*<=-<=1)-th elements of *a*).
The Little Elephant's teacher believes that this function does not work correctly. But that-be do not get an F, the Little Elephant wants to show the performance of its function. Help him, find a permutation of numbers from 1 to *n*, such that after performing the Little Elephant's function (that is call *f*(*n*)), the permutation will be sorted in ascending order. | A single line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the size of permutation. | In a single line print *n* distinct integers from 1 to *n* — the required permutation. Numbers in a line should be separated by spaces.
It is guaranteed that the answer exists. | [
"1\n",
"2\n"
] | [
"1 ",
"2 1 "
] | none | 500 | [
{
"input": "1",
"output": "1 "
},
{
"input": "2",
"output": "2 1 "
},
{
"input": "3",
"output": "3 1 2 "
},
{
"input": "4",
"output": "4 1 2 3 "
},
{
"input": "5",
"output": "5 1 2 3 4 "
},
{
"input": "6",
"output": "6 1 2 3 4 5 "
},
{
"inp... | 1,597,778,722 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 186 | 0 | n = int(input())
x = []
for i in range(2, n+1):
x.append(i)
x.append(1)
for i in x:
print(i, end = " ")
| Title: Little Elephant and Function
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant enjoys recursive functions.
This time he enjoys the sorting function. Let *a* is a permutation of an integers from 1 to *n*, inclusive, and *a**i* denotes the *i*-th element of the permutation. The Little Elephant's recursive function *f*(*x*), that sorts the first *x* permutation's elements, works as follows:
- If *x*<==<=1, exit the function. - Otherwise, call *f*(*x*<=-<=1), and then make *swap*(*a**x*<=-<=1,<=*a**x*) (swap the *x*-th and (*x*<=-<=1)-th elements of *a*).
The Little Elephant's teacher believes that this function does not work correctly. But that-be do not get an F, the Little Elephant wants to show the performance of its function. Help him, find a permutation of numbers from 1 to *n*, such that after performing the Little Elephant's function (that is call *f*(*n*)), the permutation will be sorted in ascending order.
Input Specification:
A single line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the size of permutation.
Output Specification:
In a single line print *n* distinct integers from 1 to *n* — the required permutation. Numbers in a line should be separated by spaces.
It is guaranteed that the answer exists.
Demo Input:
['1\n', '2\n']
Demo Output:
['1 ', '2 1 ']
Note:
none | ```python
n = int(input())
x = []
for i in range(2, n+1):
x.append(i)
x.append(1)
for i in x:
print(i, end = " ")
``` | 0 | |
10 | A | Power Consumption Calculation | PROGRAMMING | 900 | [
"implementation"
] | A. Power Consumption Calculation | 1 | 256 | Tom is interested in power consumption of his favourite laptop. His laptop has three modes. In normal mode laptop consumes *P*1 watt per minute. *T*1 minutes after Tom moved the mouse or touched the keyboard for the last time, a screensaver starts and power consumption changes to *P*2 watt per minute. Finally, after *T*2 minutes from the start of the screensaver, laptop switches to the "sleep" mode and consumes *P*3 watt per minute. If Tom moves the mouse or touches the keyboard when the laptop is in the second or in the third mode, it switches to the first (normal) mode. Tom's work with the laptop can be divided into *n* time periods [*l*1,<=*r*1],<=[*l*2,<=*r*2],<=...,<=[*l**n*,<=*r**n*]. During each interval Tom continuously moves the mouse and presses buttons on the keyboard. Between the periods Tom stays away from the laptop. Find out the total amount of power consumed by the laptop during the period [*l*1,<=*r**n*]. | The first line contains 6 integer numbers *n*, *P*1, *P*2, *P*3, *T*1, *T*2 (1<=≤<=*n*<=≤<=100,<=0<=≤<=*P*1,<=*P*2,<=*P*3<=≤<=100,<=1<=≤<=*T*1,<=*T*2<=≤<=60). The following *n* lines contain description of Tom's work. Each *i*-th of these lines contains two space-separated integers *l**i* and *r**i* (0<=≤<=*l**i*<=<<=*r**i*<=≤<=1440, *r**i*<=<<=*l**i*<=+<=1 for *i*<=<<=*n*), which stand for the start and the end of the *i*-th period of work. | Output the answer to the problem. | [
"1 3 2 1 5 10\n0 10\n",
"2 8 4 2 5 10\n20 30\n50 100\n"
] | [
"30",
"570"
] | none | 0 | [
{
"input": "1 3 2 1 5 10\n0 10",
"output": "30"
},
{
"input": "2 8 4 2 5 10\n20 30\n50 100",
"output": "570"
},
{
"input": "3 15 9 95 39 19\n873 989\n1003 1137\n1172 1436",
"output": "8445"
},
{
"input": "4 73 2 53 58 16\n51 52\n209 242\n281 407\n904 945",
"output": "5287... | 1,592,410,109 | 2,147,483,647 | PyPy 3 | OK | TESTS | 30 | 310 | 0 | n, p1, p2, p3, t1, t2 = map(int, input().split())
lastR = -1
total = 0
for i in range(n):
l, r = map(int, input().split())
if lastR != -1:
gap = l - lastR
if gap > t1:
if gap > t1 + t2:
total += (gap - t1 - t2) * p3
total += t2 * p2
total += t1 * p1
else:
total += (gap - t1) * p2
total += t1 * p1
else:
total += gap * p1
total += (r - l) * p1
lastR = r
print(total)
| Title: Power Consumption Calculation
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Tom is interested in power consumption of his favourite laptop. His laptop has three modes. In normal mode laptop consumes *P*1 watt per minute. *T*1 minutes after Tom moved the mouse or touched the keyboard for the last time, a screensaver starts and power consumption changes to *P*2 watt per minute. Finally, after *T*2 minutes from the start of the screensaver, laptop switches to the "sleep" mode and consumes *P*3 watt per minute. If Tom moves the mouse or touches the keyboard when the laptop is in the second or in the third mode, it switches to the first (normal) mode. Tom's work with the laptop can be divided into *n* time periods [*l*1,<=*r*1],<=[*l*2,<=*r*2],<=...,<=[*l**n*,<=*r**n*]. During each interval Tom continuously moves the mouse and presses buttons on the keyboard. Between the periods Tom stays away from the laptop. Find out the total amount of power consumed by the laptop during the period [*l*1,<=*r**n*].
Input Specification:
The first line contains 6 integer numbers *n*, *P*1, *P*2, *P*3, *T*1, *T*2 (1<=≤<=*n*<=≤<=100,<=0<=≤<=*P*1,<=*P*2,<=*P*3<=≤<=100,<=1<=≤<=*T*1,<=*T*2<=≤<=60). The following *n* lines contain description of Tom's work. Each *i*-th of these lines contains two space-separated integers *l**i* and *r**i* (0<=≤<=*l**i*<=<<=*r**i*<=≤<=1440, *r**i*<=<<=*l**i*<=+<=1 for *i*<=<<=*n*), which stand for the start and the end of the *i*-th period of work.
Output Specification:
Output the answer to the problem.
Demo Input:
['1 3 2 1 5 10\n0 10\n', '2 8 4 2 5 10\n20 30\n50 100\n']
Demo Output:
['30', '570']
Note:
none | ```python
n, p1, p2, p3, t1, t2 = map(int, input().split())
lastR = -1
total = 0
for i in range(n):
l, r = map(int, input().split())
if lastR != -1:
gap = l - lastR
if gap > t1:
if gap > t1 + t2:
total += (gap - t1 - t2) * p3
total += t2 * p2
total += t1 * p1
else:
total += (gap - t1) * p2
total += t1 * p1
else:
total += gap * p1
total += (r - l) * p1
lastR = r
print(total)
``` | 3.845 |
801 | B | Valued Keys | PROGRAMMING | 900 | [
"constructive algorithms",
"greedy",
"strings"
] | null | null | You found a mysterious function *f*. The function takes two strings *s*1 and *s*2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function *f* is another string of the same length. The *i*-th character of the output is equal to the minimum of the *i*-th character of *s*1 and the *i*-th character of *s*2.
For example, *f*("ab", "ba") = "aa", and *f*("nzwzl", "zizez") = "niwel".
You found two strings *x* and *y* of the same length and consisting of only lowercase English letters. Find any string *z* such that *f*(*x*,<=*z*)<==<=*y*, or print -1 if no such string *z* exists. | The first line of input contains the string *x*.
The second line of input contains the string *y*.
Both *x* and *y* consist only of lowercase English letters, *x* and *y* have same length and this length is between 1 and 100. | If there is no string *z* such that *f*(*x*,<=*z*)<==<=*y*, print -1.
Otherwise, print a string *z* such that *f*(*x*,<=*z*)<==<=*y*. If there are multiple possible answers, print any of them. The string *z* should be the same length as *x* and *y* and consist only of lowercase English letters. | [
"ab\naa\n",
"nzwzl\nniwel\n",
"ab\nba\n"
] | [
"ba\n",
"xiyez\n",
"-1\n"
] | The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no *z* such that *f*("ab", *z*) = "ba". | 1,000 | [
{
"input": "ab\naa",
"output": "ba"
},
{
"input": "nzwzl\nniwel",
"output": "xiyez"
},
{
"input": "ab\nba",
"output": "-1"
},
{
"input": "r\nl",
"output": "l"
},
{
"input": "d\ny",
"output": "-1"
},
{
"input": "yvowz\ncajav",
"output": "cajav"
},... | 1,492,588,282 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | x = input()
y = input()
alf = 'abcdefghijklmnopqrstuvwxyz'
z = ''
for i in range(len(X)):
if y[i] == x[i]:
z += x[i]
elif alf.find(x[i]) < alf.find(y[i]):
z += y[i]
elif alf.find(x[i]) > alf.find(y[i]):
return -1
return z | Title: Valued Keys
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You found a mysterious function *f*. The function takes two strings *s*1 and *s*2. These strings must consist only of lowercase English letters, and must be the same length.
The output of the function *f* is another string of the same length. The *i*-th character of the output is equal to the minimum of the *i*-th character of *s*1 and the *i*-th character of *s*2.
For example, *f*("ab", "ba") = "aa", and *f*("nzwzl", "zizez") = "niwel".
You found two strings *x* and *y* of the same length and consisting of only lowercase English letters. Find any string *z* such that *f*(*x*,<=*z*)<==<=*y*, or print -1 if no such string *z* exists.
Input Specification:
The first line of input contains the string *x*.
The second line of input contains the string *y*.
Both *x* and *y* consist only of lowercase English letters, *x* and *y* have same length and this length is between 1 and 100.
Output Specification:
If there is no string *z* such that *f*(*x*,<=*z*)<==<=*y*, print -1.
Otherwise, print a string *z* such that *f*(*x*,<=*z*)<==<=*y*. If there are multiple possible answers, print any of them. The string *z* should be the same length as *x* and *y* and consist only of lowercase English letters.
Demo Input:
['ab\naa\n', 'nzwzl\nniwel\n', 'ab\nba\n']
Demo Output:
['ba\n', 'xiyez\n', '-1\n']
Note:
The first case is from the statement.
Another solution for the second case is "zizez"
There is no solution for the third case. That is, there is no *z* such that *f*("ab", *z*) = "ba". | ```python
x = input()
y = input()
alf = 'abcdefghijklmnopqrstuvwxyz'
z = ''
for i in range(len(X)):
if y[i] == x[i]:
z += x[i]
elif alf.find(x[i]) < alf.find(y[i]):
z += y[i]
elif alf.find(x[i]) > alf.find(y[i]):
return -1
return z
``` | -1 | |
950 | A | Left-handers, Right-handers and Ambidexters | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.
The coach decided to form a team of even number of players, exactly half of the players should play with their right hand, and exactly half of the players should play with their left hand. One player should use only on of his hands.
Ambidexters play as well with their right hand as with their left hand. In the team, an ambidexter can play with their left hand, or with their right hand.
Please find the maximum possible size of the team, where equal number of players use their left and right hands, respectively. | The only line contains three integers *l*, *r* and *a* (0<=≤<=*l*,<=*r*,<=*a*<=≤<=100) — the number of left-handers, the number of right-handers and the number of ambidexters at the training. | Print a single even integer — the maximum number of players in the team. It is possible that the team can only have zero number of players. | [
"1 4 2\n",
"5 5 5\n",
"0 2 0\n"
] | [
"6\n",
"14\n",
"0\n"
] | In the first example you can form a team of 6 players. You should take the only left-hander and two ambidexters to play with left hand, and three right-handers to play with right hand. The only person left can't be taken into the team.
In the second example you can form a team of 14 people. You have to take all five left-handers, all five right-handers, two ambidexters to play with left hand and two ambidexters to play with right hand. | 500 | [
{
"input": "1 4 2",
"output": "6"
},
{
"input": "5 5 5",
"output": "14"
},
{
"input": "0 2 0",
"output": "0"
},
{
"input": "30 70 34",
"output": "128"
},
{
"input": "89 32 24",
"output": "112"
},
{
"input": "89 44 77",
"output": "210"
},
{
... | 1,544,620,909 | 2,147,483,647 | Python 3 | OK | TESTS | 79 | 124 | 0 | l, r, a = map(int, input().split())
if min(l,r)+a <= max(l, r):
print(2 * (min(l,r)+a))
elif l == r == a or l == r and a == 0:
if sum([l,r,a]) % 2 == 0:
print(sum([l,r,a]))
else:
print(sum([l,r,a])-1)
elif min(l, r) == 0 and a == 0:
print(0)
else:
if sum([l,r,a]) % 2 == 0:
print(sum([l,r,a]))
else:
print(sum([l,r,a])-1) | Title: Left-handers, Right-handers and Ambidexters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.
The coach decided to form a team of even number of players, exactly half of the players should play with their right hand, and exactly half of the players should play with their left hand. One player should use only on of his hands.
Ambidexters play as well with their right hand as with their left hand. In the team, an ambidexter can play with their left hand, or with their right hand.
Please find the maximum possible size of the team, where equal number of players use their left and right hands, respectively.
Input Specification:
The only line contains three integers *l*, *r* and *a* (0<=≤<=*l*,<=*r*,<=*a*<=≤<=100) — the number of left-handers, the number of right-handers and the number of ambidexters at the training.
Output Specification:
Print a single even integer — the maximum number of players in the team. It is possible that the team can only have zero number of players.
Demo Input:
['1 4 2\n', '5 5 5\n', '0 2 0\n']
Demo Output:
['6\n', '14\n', '0\n']
Note:
In the first example you can form a team of 6 players. You should take the only left-hander and two ambidexters to play with left hand, and three right-handers to play with right hand. The only person left can't be taken into the team.
In the second example you can form a team of 14 people. You have to take all five left-handers, all five right-handers, two ambidexters to play with left hand and two ambidexters to play with right hand. | ```python
l, r, a = map(int, input().split())
if min(l,r)+a <= max(l, r):
print(2 * (min(l,r)+a))
elif l == r == a or l == r and a == 0:
if sum([l,r,a]) % 2 == 0:
print(sum([l,r,a]))
else:
print(sum([l,r,a])-1)
elif min(l, r) == 0 and a == 0:
print(0)
else:
if sum([l,r,a]) % 2 == 0:
print(sum([l,r,a]))
else:
print(sum([l,r,a])-1)
``` | 3 | |
697 | B | Barnicle | PROGRAMMING | 1,400 | [
"brute force",
"implementation",
"math",
"strings"
] | null | null | Barney is standing in a bar and starring at a pretty girl. He wants to shoot her with his heart arrow but he needs to know the distance between him and the girl to make his shot accurate.
Barney asked the bar tender Carl about this distance value, but Carl was so busy talking to the customers so he wrote the distance value (it's a real number) on a napkin. The problem is that he wrote it in scientific notation. The scientific notation of some real number *x* is the notation of form *AeB*, where *A* is a real number and *B* is an integer and *x*<==<=*A*<=×<=10*B* is true. In our case *A* is between 0 and 9 and *B* is non-negative.
Barney doesn't know anything about scientific notation (as well as anything scientific at all). So he asked you to tell him the distance value in usual decimal representation with minimal number of digits after the decimal point (and no decimal point if it is an integer). See the output format for better understanding. | The first and only line of input contains a single string of form *a*.*deb* where *a*, *d* and *b* are integers and *e* is usual character 'e' (0<=≤<=*a*<=≤<=9,<=0<=≤<=*d*<=<<=10100,<=0<=≤<=*b*<=≤<=100) — the scientific notation of the desired distance value.
*a* and *b* contain no leading zeros and *d* contains no trailing zeros (but may be equal to 0). Also, *b* can not be non-zero if *a* is zero. | Print the only real number *x* (the desired distance value) in the only line in its decimal notation.
Thus if *x* is an integer, print it's integer value without decimal part and decimal point and without leading zeroes.
Otherwise print *x* in a form of *p*.*q* such that *p* is an integer that have no leading zeroes (but may be equal to zero), and *q* is an integer that have no trailing zeroes (and may not be equal to zero). | [
"8.549e2\n",
"8.549e3\n",
"0.33e0\n"
] | [
"854.9\n",
"8549\n",
"0.33\n"
] | none | 1,000 | [
{
"input": "8.549e2",
"output": "854.9"
},
{
"input": "8.549e3",
"output": "8549"
},
{
"input": "0.33e0",
"output": "0.33"
},
{
"input": "1.31e1",
"output": "13.1"
},
{
"input": "1.038e0",
"output": "1.038"
},
{
"input": "8.25983e5",
"output": "825... | 1,558,979,833 | 2,533 | Python 3 | WRONG_ANSWER | TESTS | 7 | 108 | 0 |
s = input()
x =(eval(s))
if (int(x)) == x:
print(int(x))
else:
print(x)
| Title: Barnicle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Barney is standing in a bar and starring at a pretty girl. He wants to shoot her with his heart arrow but he needs to know the distance between him and the girl to make his shot accurate.
Barney asked the bar tender Carl about this distance value, but Carl was so busy talking to the customers so he wrote the distance value (it's a real number) on a napkin. The problem is that he wrote it in scientific notation. The scientific notation of some real number *x* is the notation of form *AeB*, where *A* is a real number and *B* is an integer and *x*<==<=*A*<=×<=10*B* is true. In our case *A* is between 0 and 9 and *B* is non-negative.
Barney doesn't know anything about scientific notation (as well as anything scientific at all). So he asked you to tell him the distance value in usual decimal representation with minimal number of digits after the decimal point (and no decimal point if it is an integer). See the output format for better understanding.
Input Specification:
The first and only line of input contains a single string of form *a*.*deb* where *a*, *d* and *b* are integers and *e* is usual character 'e' (0<=≤<=*a*<=≤<=9,<=0<=≤<=*d*<=<<=10100,<=0<=≤<=*b*<=≤<=100) — the scientific notation of the desired distance value.
*a* and *b* contain no leading zeros and *d* contains no trailing zeros (but may be equal to 0). Also, *b* can not be non-zero if *a* is zero.
Output Specification:
Print the only real number *x* (the desired distance value) in the only line in its decimal notation.
Thus if *x* is an integer, print it's integer value without decimal part and decimal point and without leading zeroes.
Otherwise print *x* in a form of *p*.*q* such that *p* is an integer that have no leading zeroes (but may be equal to zero), and *q* is an integer that have no trailing zeroes (and may not be equal to zero).
Demo Input:
['8.549e2\n', '8.549e3\n', '0.33e0\n']
Demo Output:
['854.9\n', '8549\n', '0.33\n']
Note:
none | ```python
s = input()
x =(eval(s))
if (int(x)) == x:
print(int(x))
else:
print(x)
``` | 0 | |
354 | A | Vasya and Robot | PROGRAMMING | 1,500 | [
"brute force",
"greedy",
"math"
] | null | null | Vasya has *n* items lying in a line. The items are consecutively numbered by numbers from 1 to *n* in such a way that the leftmost item has number 1, the rightmost item has number *n*. Each item has a weight, the *i*-th item weights *w**i* kilograms.
Vasya needs to collect all these items, however he won't do it by himself. He uses his brand new robot. The robot has two different arms — the left one and the right one. The robot can consecutively perform the following actions:
1. Take the leftmost item with the left hand and spend *w**i*<=·<=*l* energy units (*w**i* is a weight of the leftmost item, *l* is some parameter). If the previous action was the same (left-hand), then the robot spends extra *Q**l* energy units; 1. Take the rightmost item with the right hand and spend *w**j*<=·<=*r* energy units (*w**j* is a weight of the rightmost item, *r* is some parameter). If the previous action was the same (right-hand), then the robot spends extra *Q**r* energy units;
Naturally, Vasya wants to program the robot in a way that the robot spends as little energy as possible. He asked you to solve this problem. Your task is to find the minimum number of energy units robot spends to collect all items. | The first line contains five integers *n*,<=*l*,<=*r*,<=*Q**l*,<=*Q**r* (1<=≤<=*n*<=≤<=105;<=1<=≤<=*l*,<=*r*<=≤<=100;<=1<=≤<=*Q**l*,<=*Q**r*<=≤<=104).
The second line contains *n* integers *w*1,<=*w*2,<=...,<=*w**n* (1<=≤<=*w**i*<=≤<=100). | In the single line print a single number — the answer to the problem. | [
"3 4 4 19 1\n42 3 99\n",
"4 7 2 3 9\n1 2 3 4\n"
] | [
"576\n",
"34\n"
] | Consider the first sample. As *l* = *r*, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4·42 + 4·99 + 4·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left and two items from the right. In total the robot spends (2·4) + (7·1) + (2·3) + (2·2 + 9) = 34 energy units. | 500 | [
{
"input": "3 4 4 19 1\n42 3 99",
"output": "576"
},
{
"input": "4 7 2 3 9\n1 2 3 4",
"output": "34"
},
{
"input": "2 100 100 10000 10000\n100 100",
"output": "20000"
},
{
"input": "2 3 4 5 6\n1 2",
"output": "11"
},
{
"input": "1 78 94 369 10000\n93",
"output... | 1,664,362,353 | 2,147,483,647 | PyPy 3-64 | MEMORY_LIMIT_EXCEEDED | TESTS | 0 | 46 | 268,390,400 | import sys
sys.setrecursionlimit(10**6)
n,l,r,q1,q2 = [int(i) for i in input().split()]
arr = list(map(int,input().split()))
dp = {}
def solve(i,j,l1,r1):
if i > j:
return 0
if (i,j,l1,r1) in dp:
return dp[(i,j,l1,r1)]
if l1:
left = ((arr[i] * l) + q1) + solve(i+1 , j , 1 , 0)
else:
left = ((arr[i] * l)) + solve(i+1 , j , 1 , 0)
if r1:
right = ((arr[j] * r) + q2) + solve(i , j-1 , 0 , 1)
else:
right = ((arr[j] * r)) + solve(i , j-1 , 0 , 1)
dp[(i,j,l1,r1)] = min(left , right)
return dp[(i,j,l1,r1)]
print(solve(0 , n-1 , 0 , 0))
| Title: Vasya and Robot
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* items lying in a line. The items are consecutively numbered by numbers from 1 to *n* in such a way that the leftmost item has number 1, the rightmost item has number *n*. Each item has a weight, the *i*-th item weights *w**i* kilograms.
Vasya needs to collect all these items, however he won't do it by himself. He uses his brand new robot. The robot has two different arms — the left one and the right one. The robot can consecutively perform the following actions:
1. Take the leftmost item with the left hand and spend *w**i*<=·<=*l* energy units (*w**i* is a weight of the leftmost item, *l* is some parameter). If the previous action was the same (left-hand), then the robot spends extra *Q**l* energy units; 1. Take the rightmost item with the right hand and spend *w**j*<=·<=*r* energy units (*w**j* is a weight of the rightmost item, *r* is some parameter). If the previous action was the same (right-hand), then the robot spends extra *Q**r* energy units;
Naturally, Vasya wants to program the robot in a way that the robot spends as little energy as possible. He asked you to solve this problem. Your task is to find the minimum number of energy units robot spends to collect all items.
Input Specification:
The first line contains five integers *n*,<=*l*,<=*r*,<=*Q**l*,<=*Q**r* (1<=≤<=*n*<=≤<=105;<=1<=≤<=*l*,<=*r*<=≤<=100;<=1<=≤<=*Q**l*,<=*Q**r*<=≤<=104).
The second line contains *n* integers *w*1,<=*w*2,<=...,<=*w**n* (1<=≤<=*w**i*<=≤<=100).
Output Specification:
In the single line print a single number — the answer to the problem.
Demo Input:
['3 4 4 19 1\n42 3 99\n', '4 7 2 3 9\n1 2 3 4\n']
Demo Output:
['576\n', '34\n']
Note:
Consider the first sample. As *l* = *r*, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4·42 + 4·99 + 4·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left and two items from the right. In total the robot spends (2·4) + (7·1) + (2·3) + (2·2 + 9) = 34 energy units. | ```python
import sys
sys.setrecursionlimit(10**6)
n,l,r,q1,q2 = [int(i) for i in input().split()]
arr = list(map(int,input().split()))
dp = {}
def solve(i,j,l1,r1):
if i > j:
return 0
if (i,j,l1,r1) in dp:
return dp[(i,j,l1,r1)]
if l1:
left = ((arr[i] * l) + q1) + solve(i+1 , j , 1 , 0)
else:
left = ((arr[i] * l)) + solve(i+1 , j , 1 , 0)
if r1:
right = ((arr[j] * r) + q2) + solve(i , j-1 , 0 , 1)
else:
right = ((arr[j] * r)) + solve(i , j-1 , 0 , 1)
dp[(i,j,l1,r1)] = min(left , right)
return dp[(i,j,l1,r1)]
print(solve(0 , n-1 , 0 , 0))
``` | 0 | |
276 | C | Little Girl and Maximum Sum | PROGRAMMING | 1,500 | [
"data structures",
"greedy",
"implementation",
"sortings"
] | null | null | The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of $n$ elements (the elements of the array are indexed starting from 1); also, there are $q$ queries, each one is defined by a pair of integers $l_i$, $r_i$ $(1 \le l_i \le r_i \le n)$. You need to find for each query the sum of elements of the array with indexes from $l_i$ to $r_i$, inclusive.
The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum. | The first line contains two space-separated integers $n$ ($1 \le n \le 2\cdot10^5$) and $q$ ($1 \le q \le 2\cdot10^5$) — the number of elements in the array and the number of queries, correspondingly.
The next line contains $n$ space-separated integers $a_i$ ($1 \le a_i \le 2\cdot10^5$) — the array elements.
Each of the following $q$ lines contains two space-separated integers $l_i$ and $r_i$ ($1 \le l_i \le r_i \le n$) — the $i$-th query. | In a single line print, a single integer — the maximum sum of query replies after the array elements are reordered.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"3 3\n5 3 2\n1 2\n2 3\n1 3\n",
"5 3\n5 2 4 1 3\n1 5\n2 3\n2 3\n"
] | [
"25\n",
"33\n"
] | none | 1,500 | [
{
"input": "3 3\n5 3 2\n1 2\n2 3\n1 3",
"output": "25"
},
{
"input": "5 3\n5 2 4 1 3\n1 5\n2 3\n2 3",
"output": "33"
},
{
"input": "34 21\n23 38 16 49 44 50 48 34 33 19 18 31 11 15 20 47 44 30 39 33 45 46 1 13 27 16 31 36 17 23 38 5 30 16\n8 16\n14 27\n8 26\n1 8\n5 6\n23 28\n4 33\n13 30\... | 1,688,451,023 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 1,000 | 26,521,600 |
if __name__=='__main__':
nums = [int(i) for i in input().split(' ')]
n = nums[0]
q = nums[1]
nums = [int(i) for i in input().split(' ')]
nums = sorted(nums)
indices = [0]*n
while q:
pos = [int(i) for i in input().split(' ')]
l = pos[0]-1
r = pos[1]-1
for i in range(l, r+1):
indices[i]+=1
q-=1
ret_ind = sorted(range(len(indices)), key=lambda index: indices[index])
sum = 0
for i in range(n):
sum+=nums[i]*indices[ret_ind[i]]
print(sum) | Title: Little Girl and Maximum Sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The little girl loves the problems on array queries very much.
One day she came across a rather well-known problem: you've got an array of $n$ elements (the elements of the array are indexed starting from 1); also, there are $q$ queries, each one is defined by a pair of integers $l_i$, $r_i$ $(1 \le l_i \le r_i \le n)$. You need to find for each query the sum of elements of the array with indexes from $l_i$ to $r_i$, inclusive.
The little girl found the problem rather boring. She decided to reorder the array elements before replying to the queries in a way that makes the sum of query replies maximum possible. Your task is to find the value of this maximum sum.
Input Specification:
The first line contains two space-separated integers $n$ ($1 \le n \le 2\cdot10^5$) and $q$ ($1 \le q \le 2\cdot10^5$) — the number of elements in the array and the number of queries, correspondingly.
The next line contains $n$ space-separated integers $a_i$ ($1 \le a_i \le 2\cdot10^5$) — the array elements.
Each of the following $q$ lines contains two space-separated integers $l_i$ and $r_i$ ($1 \le l_i \le r_i \le n$) — the $i$-th query.
Output Specification:
In a single line print, a single integer — the maximum sum of query replies after the array elements are reordered.
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Demo Input:
['3 3\n5 3 2\n1 2\n2 3\n1 3\n', '5 3\n5 2 4 1 3\n1 5\n2 3\n2 3\n']
Demo Output:
['25\n', '33\n']
Note:
none | ```python
if __name__=='__main__':
nums = [int(i) for i in input().split(' ')]
n = nums[0]
q = nums[1]
nums = [int(i) for i in input().split(' ')]
nums = sorted(nums)
indices = [0]*n
while q:
pos = [int(i) for i in input().split(' ')]
l = pos[0]-1
r = pos[1]-1
for i in range(l, r+1):
indices[i]+=1
q-=1
ret_ind = sorted(range(len(indices)), key=lambda index: indices[index])
sum = 0
for i in range(n):
sum+=nums[i]*indices[ret_ind[i]]
print(sum)
``` | 0 | |
306 | A | Candies | PROGRAMMING | 800 | [
"implementation"
] | null | null | Polycarpus has got *n* candies and *m* friends (*n*<=≥<=*m*). He wants to make a New Year present with candies to each friend. Polycarpus is planning to present all candies and he wants to do this in the fairest (that is, most equal) manner. He wants to choose such *a**i*, where *a**i* is the number of candies in the *i*-th friend's present, that the maximum *a**i* differs from the least *a**i* as little as possible.
For example, if *n* is divisible by *m*, then he is going to present the same number of candies to all his friends, that is, the maximum *a**i* won't differ from the minimum one. | The single line of the input contains a pair of space-separated positive integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100;*n*<=≥<=*m*) — the number of candies and the number of Polycarpus's friends. | Print the required sequence *a*1,<=*a*2,<=...,<=*a**m*, where *a**i* is the number of candies in the *i*-th friend's present. All numbers *a**i* must be positive integers, total up to *n*, the maximum one should differ from the minimum one by the smallest possible value. | [
"12 3\n",
"15 4\n",
"18 7\n"
] | [
"4 4 4 ",
"3 4 4 4 ",
"2 2 2 3 3 3 3 "
] | Print *a*<sub class="lower-index">*i*</sub> in any order, separate the numbers by spaces. | 500 | [
{
"input": "12 4",
"output": "3 3 3 3 "
},
{
"input": "15 6",
"output": "2 2 2 3 3 3 "
},
{
"input": "18 8",
"output": "2 2 2 2 2 2 3 3 "
},
{
"input": "1 1",
"output": "1 "
},
{
"input": "2 1",
"output": "2 "
},
{
"input": "100 1",
"output": "100 ... | 1,596,967,724 | 2,147,483,647 | PyPy 3 | OK | TESTS | 20 | 248 | 20,172,800 | #In the name of God
a = []
n, m = map(int, (input()).split())
q = n // m
for i in range(m):
if (i < n % m):
a.append(q + 1)
else:
a.append(q)
for i in a:
print(i, end = ' ')
| Title: Candies
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarpus has got *n* candies and *m* friends (*n*<=≥<=*m*). He wants to make a New Year present with candies to each friend. Polycarpus is planning to present all candies and he wants to do this in the fairest (that is, most equal) manner. He wants to choose such *a**i*, where *a**i* is the number of candies in the *i*-th friend's present, that the maximum *a**i* differs from the least *a**i* as little as possible.
For example, if *n* is divisible by *m*, then he is going to present the same number of candies to all his friends, that is, the maximum *a**i* won't differ from the minimum one.
Input Specification:
The single line of the input contains a pair of space-separated positive integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100;*n*<=≥<=*m*) — the number of candies and the number of Polycarpus's friends.
Output Specification:
Print the required sequence *a*1,<=*a*2,<=...,<=*a**m*, where *a**i* is the number of candies in the *i*-th friend's present. All numbers *a**i* must be positive integers, total up to *n*, the maximum one should differ from the minimum one by the smallest possible value.
Demo Input:
['12 3\n', '15 4\n', '18 7\n']
Demo Output:
['4 4 4 ', '3 4 4 4 ', '2 2 2 3 3 3 3 ']
Note:
Print *a*<sub class="lower-index">*i*</sub> in any order, separate the numbers by spaces. | ```python
#In the name of God
a = []
n, m = map(int, (input()).split())
q = n // m
for i in range(m):
if (i < n % m):
a.append(q + 1)
else:
a.append(q)
for i in a:
print(i, end = ' ')
``` | 3 | |
961 | A | Tetris | PROGRAMMING | 900 | [
"implementation"
] | null | null | You are given a following process.
There is a platform with $n$ columns. $1 \times 1$ squares are appearing one after another in some columns on this platform. If there are no squares in the column, a square will occupy the bottom row. Otherwise a square will appear at the top of the highest square of this column.
When all of the $n$ columns have at least one square in them, the bottom row is being removed. You will receive $1$ point for this, and all the squares left will fall down one row.
You task is to calculate the amount of points you will receive. | The first line of input contain 2 integer numbers $n$ and $m$ ($1 \le n, m \le 1000$) — the length of the platform and the number of the squares.
The next line contain $m$ integer numbers $c_1, c_2, \dots, c_m$ ($1 \le c_i \le n$) — column in which $i$-th square will appear. | Print one integer — the amount of points you will receive. | [
"3 9\n1 1 2 2 2 3 1 2 3\n"
] | [
"2\n"
] | In the sample case the answer will be equal to $2$ because after the appearing of $6$-th square will be removed one row (counts of the squares on the platform will look like $[2~ 3~ 1]$, and after removing one row will be $[1~ 2~ 0]$).
After the appearing of $9$-th square counts will be $[2~ 3~ 1]$, and after removing one row it will look like $[1~ 2~ 0]$.
So the answer will be equal to $2$. | 0 | [
{
"input": "3 9\n1 1 2 2 2 3 1 2 3",
"output": "2"
},
{
"input": "1 7\n1 1 1 1 1 1 1",
"output": "7"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "3 5\n1 1 1 2 3",
"output": "1"
},
{
"input": "4 6\n4 4 4 4 4 4",
"output": "0"
},
{
"input": "4 6\... | 1,670,485,584 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 46 | 0 |
n = list(map(int,input().split()))
lst = list(map(int,input().split()))
dic = {y:0 for y in lst }
for i in lst:
dic[i]+=1
score = 0
for i in dic:
score += dic[i]//3
print(score)
| Title: Tetris
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a following process.
There is a platform with $n$ columns. $1 \times 1$ squares are appearing one after another in some columns on this platform. If there are no squares in the column, a square will occupy the bottom row. Otherwise a square will appear at the top of the highest square of this column.
When all of the $n$ columns have at least one square in them, the bottom row is being removed. You will receive $1$ point for this, and all the squares left will fall down one row.
You task is to calculate the amount of points you will receive.
Input Specification:
The first line of input contain 2 integer numbers $n$ and $m$ ($1 \le n, m \le 1000$) — the length of the platform and the number of the squares.
The next line contain $m$ integer numbers $c_1, c_2, \dots, c_m$ ($1 \le c_i \le n$) — column in which $i$-th square will appear.
Output Specification:
Print one integer — the amount of points you will receive.
Demo Input:
['3 9\n1 1 2 2 2 3 1 2 3\n']
Demo Output:
['2\n']
Note:
In the sample case the answer will be equal to $2$ because after the appearing of $6$-th square will be removed one row (counts of the squares on the platform will look like $[2~ 3~ 1]$, and after removing one row will be $[1~ 2~ 0]$).
After the appearing of $9$-th square counts will be $[2~ 3~ 1]$, and after removing one row it will look like $[1~ 2~ 0]$.
So the answer will be equal to $2$. | ```python
n = list(map(int,input().split()))
lst = list(map(int,input().split()))
dic = {y:0 for y in lst }
for i in lst:
dic[i]+=1
score = 0
for i in dic:
score += dic[i]//3
print(score)
``` | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | A dragon symbolizes wisdom, power and wealth. On Lunar New Year's Day, people model a dragon with bamboo strips and clothes, raise them with rods, and hold the rods high and low to resemble a flying dragon.
A performer holding the rod low is represented by a 1, while one holding it high is represented by a 2. Thus, the line of performers can be represented by a sequence *a*1,<=*a*2,<=...,<=*a**n*.
Little Tommy is among them. He would like to choose an interval [*l*,<=*r*] (1<=≤<=*l*<=≤<=*r*<=≤<=*n*), then reverse *a**l*,<=*a**l*<=+<=1,<=...,<=*a**r* so that the length of the longest non-decreasing subsequence of the new sequence is maximum.
A non-decreasing subsequence is a sequence of indices *p*1,<=*p*2,<=...,<=*p**k*, such that *p*1<=<<=*p*2<=<<=...<=<<=*p**k* and *a**p*1<=≤<=*a**p*2<=≤<=...<=≤<=*a**p**k*. The length of the subsequence is *k*. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=2000), denoting the length of the original sequence.
The second line contains *n* space-separated integers, describing the original sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=2,<=*i*<==<=1,<=2,<=...,<=*n*). | Print a single integer, which means the maximum possible length of the longest non-decreasing subsequence of the new sequence. | [
"4\n1 2 1 2\n",
"10\n1 1 2 2 2 1 1 2 2 1\n"
] | [
"4\n",
"9\n"
] | In the first example, after reversing [2, 3], the array will become [1, 1, 2, 2], where the length of the longest non-decreasing subsequence is 4.
In the second example, after reversing [3, 7], the array will become [1, 1, 1, 1, 2, 2, 2, 2, 2, 1], where the length of the longest non-decreasing subsequence is 9. | 0 | [
{
"input": "4\n1 2 1 2",
"output": "4"
},
{
"input": "10\n1 1 2 2 2 1 1 2 2 1",
"output": "9"
},
{
"input": "200\n2 1 1 2 1 2 2 2 2 2 1 2 2 1 1 2 2 1 1 1 2 1 1 2 2 2 2 2 1 1 2 1 2 1 1 2 1 1 1 1 2 1 2 2 1 2 1 1 1 2 1 1 1 2 2 2 1 1 1 1 2 2 2 1 2 2 2 1 2 2 2 1 2 1 2 1 2 1 1 1 1 2 2 2 1 1 2 ... | 1,518,788,414 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 5,632,000 | n=int(input())
a=[int(k)-1 for k in input().split(" ")]
nbmax= [0,0,0,0]
#print(a)
for k in a:
#print("k is:",k)
p#rint("a is:",a)
if k:
nbmax[1]=max(nbmax[1]+1,nbmax[0]+1)
nbmax[3]=max(nbmax[3]+1,nbmax[2]+1)
#print("nbmax upper:", nbmax)
else:
nbmax[0]+=1
nbmax[2]=max(nbmax[1]+1,nbmax[2]+1)
#print("nbmax lower:", nbmax)
print (max(nbmax))
'''
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, a, num[4] = {0};
scanf("%d", &n);
for(int i = 0; i < n; i++) {
scanf("%d", &a);
if(a == 1) {
num[0]++;
num[2] = max(num[2], num[1]) + 1;
}
else {
num[1] = max(num[1], num[0]) + 1;
num[3] = max(num[3], num[2]) + 1;
}
}
int ans = 0;
for(int i = 0; i < 4; i++) ans = max(ans, num[i]);
printf("%d\n", ans);
return 0;
}'''
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A dragon symbolizes wisdom, power and wealth. On Lunar New Year's Day, people model a dragon with bamboo strips and clothes, raise them with rods, and hold the rods high and low to resemble a flying dragon.
A performer holding the rod low is represented by a 1, while one holding it high is represented by a 2. Thus, the line of performers can be represented by a sequence *a*1,<=*a*2,<=...,<=*a**n*.
Little Tommy is among them. He would like to choose an interval [*l*,<=*r*] (1<=≤<=*l*<=≤<=*r*<=≤<=*n*), then reverse *a**l*,<=*a**l*<=+<=1,<=...,<=*a**r* so that the length of the longest non-decreasing subsequence of the new sequence is maximum.
A non-decreasing subsequence is a sequence of indices *p*1,<=*p*2,<=...,<=*p**k*, such that *p*1<=<<=*p*2<=<<=...<=<<=*p**k* and *a**p*1<=≤<=*a**p*2<=≤<=...<=≤<=*a**p**k*. The length of the subsequence is *k*.
Input Specification:
The first line contains an integer *n* (1<=≤<=*n*<=≤<=2000), denoting the length of the original sequence.
The second line contains *n* space-separated integers, describing the original sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=2,<=*i*<==<=1,<=2,<=...,<=*n*).
Output Specification:
Print a single integer, which means the maximum possible length of the longest non-decreasing subsequence of the new sequence.
Demo Input:
['4\n1 2 1 2\n', '10\n1 1 2 2 2 1 1 2 2 1\n']
Demo Output:
['4\n', '9\n']
Note:
In the first example, after reversing [2, 3], the array will become [1, 1, 2, 2], where the length of the longest non-decreasing subsequence is 4.
In the second example, after reversing [3, 7], the array will become [1, 1, 1, 1, 2, 2, 2, 2, 2, 1], where the length of the longest non-decreasing subsequence is 9. | ```python
n=int(input())
a=[int(k)-1 for k in input().split(" ")]
nbmax= [0,0,0,0]
#print(a)
for k in a:
#print("k is:",k)
p#rint("a is:",a)
if k:
nbmax[1]=max(nbmax[1]+1,nbmax[0]+1)
nbmax[3]=max(nbmax[3]+1,nbmax[2]+1)
#print("nbmax upper:", nbmax)
else:
nbmax[0]+=1
nbmax[2]=max(nbmax[1]+1,nbmax[2]+1)
#print("nbmax lower:", nbmax)
print (max(nbmax))
'''
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, a, num[4] = {0};
scanf("%d", &n);
for(int i = 0; i < n; i++) {
scanf("%d", &a);
if(a == 1) {
num[0]++;
num[2] = max(num[2], num[1]) + 1;
}
else {
num[1] = max(num[1], num[0]) + 1;
num[3] = max(num[3], num[2]) + 1;
}
}
int ans = 0;
for(int i = 0; i < 4; i++) ans = max(ans, num[i]);
printf("%d\n", ans);
return 0;
}'''
``` | -1 | |
734 | A | Anton and Danik | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, who won more games, he or Danik? Help him determine this. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of games played.
The second line contains a string *s*, consisting of *n* uppercase English letters 'A' and 'D' — the outcome of each of the games. The *i*-th character of the string is equal to 'A' if the Anton won the *i*-th game and 'D' if Danik won the *i*-th game. | If Anton won more games than Danik, print "Anton" (without quotes) in the only line of the output.
If Danik won more games than Anton, print "Danik" (without quotes) in the only line of the output.
If Anton and Danik won the same number of games, print "Friendship" (without quotes). | [
"6\nADAAAA\n",
"7\nDDDAADA\n",
"6\nDADADA\n"
] | [
"Anton\n",
"Danik\n",
"Friendship\n"
] | In the first sample, Anton won 6 games, while Danik — only 1. Hence, the answer is "Anton".
In the second sample, Anton won 3 games and Danik won 4 games, so the answer is "Danik".
In the third sample, both Anton and Danik won 3 games and the answer is "Friendship". | 500 | [
{
"input": "6\nADAAAA",
"output": "Anton"
},
{
"input": "7\nDDDAADA",
"output": "Danik"
},
{
"input": "6\nDADADA",
"output": "Friendship"
},
{
"input": "10\nDDDDADDADD",
"output": "Danik"
},
{
"input": "40\nAAAAAAAAADDAAAAAAAAAAADADDAAAAAAAAAAADAA",
"output": ... | 1,697,553,011 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 46 | 102,400 | # Read input
n = int(input())
results = input()
# Count the number of 'A' and 'D' in the results
anton_wins = results.count('A')
danik_wins = results.count('D')
# Determine the winner
if anton_wins > danik_wins:
print("Anton")
elif anton_wins < danik_wins:
print("Danik")
else:
print("Friendship")
| Title: Anton and Danik
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, who won more games, he or Danik? Help him determine this.
Input Specification:
The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of games played.
The second line contains a string *s*, consisting of *n* uppercase English letters 'A' and 'D' — the outcome of each of the games. The *i*-th character of the string is equal to 'A' if the Anton won the *i*-th game and 'D' if Danik won the *i*-th game.
Output Specification:
If Anton won more games than Danik, print "Anton" (without quotes) in the only line of the output.
If Danik won more games than Anton, print "Danik" (without quotes) in the only line of the output.
If Anton and Danik won the same number of games, print "Friendship" (without quotes).
Demo Input:
['6\nADAAAA\n', '7\nDDDAADA\n', '6\nDADADA\n']
Demo Output:
['Anton\n', 'Danik\n', 'Friendship\n']
Note:
In the first sample, Anton won 6 games, while Danik — only 1. Hence, the answer is "Anton".
In the second sample, Anton won 3 games and Danik won 4 games, so the answer is "Danik".
In the third sample, both Anton and Danik won 3 games and the answer is "Friendship". | ```python
# Read input
n = int(input())
results = input()
# Count the number of 'A' and 'D' in the results
anton_wins = results.count('A')
danik_wins = results.count('D')
# Determine the winner
if anton_wins > danik_wins:
print("Anton")
elif anton_wins < danik_wins:
print("Danik")
else:
print("Friendship")
``` | 3 | |
322 | A | Ciel and Dancing | PROGRAMMING | 1,000 | [
"greedy"
] | null | null | Fox Ciel and her friends are in a dancing room. There are *n* boys and *m* girls here, and they never danced before. There will be some songs, during each song, there must be exactly one boy and one girl are dancing. Besides, there is a special rule:
- either the boy in the dancing pair must dance for the first time (so, he didn't dance with anyone before); - or the girl in the dancing pair must dance for the first time.
Help Fox Ciel to make a schedule that they can dance as many songs as possible. | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of boys and girls in the dancing room. | In the first line print *k* — the number of songs during which they can dance. Then in the following *k* lines, print the indexes of boys and girls dancing during songs chronologically. You can assume that the boys are indexed from 1 to *n*, and the girls are indexed from 1 to *m*. | [
"2 1\n",
"2 2\n"
] | [
"2\n1 1\n2 1\n",
"3\n1 1\n1 2\n2 2\n"
] | In test case 1, there are 2 boys and 1 girl. We can have 2 dances: the 1st boy and 1st girl (during the first song), the 2nd boy and 1st girl (during the second song).
And in test case 2, we have 2 boys with 2 girls, the answer is 3. | 500 | [
{
"input": "2 1",
"output": "2\n1 1\n2 1"
},
{
"input": "2 2",
"output": "3\n1 1\n1 2\n2 2"
},
{
"input": "1 1",
"output": "1\n1 1"
},
{
"input": "2 3",
"output": "4\n1 1\n1 2\n1 3\n2 3"
},
{
"input": "4 4",
"output": "7\n1 1\n1 2\n1 3\n1 4\n4 4\n3 4\n2 4"
}... | 1,551,118,487 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 216 | 0 | n,m=map(int,input().split())
l=[];count=0;j,i=1,1
print(n+m-1)
if(n<=m):
while(count!=n+m-1):
print(i,j)
count+=1
if(count%2==0):
i+=1
else:
j+=1
else:
while (count != n + m - 1):
print(i, j)
count += 1
if (count % 2 == 0):
j += 1
else:
i += 1 | Title: Ciel and Dancing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel and her friends are in a dancing room. There are *n* boys and *m* girls here, and they never danced before. There will be some songs, during each song, there must be exactly one boy and one girl are dancing. Besides, there is a special rule:
- either the boy in the dancing pair must dance for the first time (so, he didn't dance with anyone before); - or the girl in the dancing pair must dance for the first time.
Help Fox Ciel to make a schedule that they can dance as many songs as possible.
Input Specification:
The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of boys and girls in the dancing room.
Output Specification:
In the first line print *k* — the number of songs during which they can dance. Then in the following *k* lines, print the indexes of boys and girls dancing during songs chronologically. You can assume that the boys are indexed from 1 to *n*, and the girls are indexed from 1 to *m*.
Demo Input:
['2 1\n', '2 2\n']
Demo Output:
['2\n1 1\n2 1\n', '3\n1 1\n1 2\n2 2\n']
Note:
In test case 1, there are 2 boys and 1 girl. We can have 2 dances: the 1st boy and 1st girl (during the first song), the 2nd boy and 1st girl (during the second song).
And in test case 2, we have 2 boys with 2 girls, the answer is 3. | ```python
n,m=map(int,input().split())
l=[];count=0;j,i=1,1
print(n+m-1)
if(n<=m):
while(count!=n+m-1):
print(i,j)
count+=1
if(count%2==0):
i+=1
else:
j+=1
else:
while (count != n + m - 1):
print(i, j)
count += 1
if (count % 2 == 0):
j += 1
else:
i += 1
``` | 0 | |
304 | A | Pythagorean Theorem II | PROGRAMMING | 1,200 | [
"brute force",
"math"
] | null | null | In mathematics, the Pythagorean theorem — is a relation in Euclidean geometry among the three sides of a right-angled triangle. In terms of areas, it states:
In any right-angled triangle, the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares whose sides are the two legs (the two sides that meet at a right angle).
The theorem can be written as an equation relating the lengths of the sides *a*, *b* and *c*, often called the Pythagorean equation:
where *c* represents the length of the hypotenuse, and *a* and *b* represent the lengths of the other two sides.
Given *n*, your task is to count how many right-angled triangles with side-lengths *a*, *b* and *c* that satisfied an inequality 1<=≤<=*a*<=≤<=*b*<=≤<=*c*<=≤<=*n*. | The only line contains one integer *n* (1<=≤<=*n*<=≤<=104) as we mentioned above. | Print a single integer — the answer to the problem. | [
"5\n",
"74\n"
] | [
"1\n",
"35\n"
] | none | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "74",
"output": "35"
},
{
"input": "1000",
"output": "881"
},
{
"input": "586",
"output": "472"
},
{
"input": "2",
"output": "0"
},
{
"input": "362",
"output": "258"
},
{
"input": "778",
"outp... | 1,685,227,326 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 122 | 0 | n=int(input())
a=0
for i in range (1,n+1):
for j in range (i+1,n+1):
c=j**2-i**2
p=c**.5
if p-int(p)==0:
a+=1
print (a/2) | Title: Pythagorean Theorem II
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In mathematics, the Pythagorean theorem — is a relation in Euclidean geometry among the three sides of a right-angled triangle. In terms of areas, it states:
In any right-angled triangle, the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares whose sides are the two legs (the two sides that meet at a right angle).
The theorem can be written as an equation relating the lengths of the sides *a*, *b* and *c*, often called the Pythagorean equation:
where *c* represents the length of the hypotenuse, and *a* and *b* represent the lengths of the other two sides.
Given *n*, your task is to count how many right-angled triangles with side-lengths *a*, *b* and *c* that satisfied an inequality 1<=≤<=*a*<=≤<=*b*<=≤<=*c*<=≤<=*n*.
Input Specification:
The only line contains one integer *n* (1<=≤<=*n*<=≤<=104) as we mentioned above.
Output Specification:
Print a single integer — the answer to the problem.
Demo Input:
['5\n', '74\n']
Demo Output:
['1\n', '35\n']
Note:
none | ```python
n=int(input())
a=0
for i in range (1,n+1):
for j in range (i+1,n+1):
c=j**2-i**2
p=c**.5
if p-int(p)==0:
a+=1
print (a/2)
``` | 0 | |
734 | A | Anton and Danik | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, who won more games, he or Danik? Help him determine this. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of games played.
The second line contains a string *s*, consisting of *n* uppercase English letters 'A' and 'D' — the outcome of each of the games. The *i*-th character of the string is equal to 'A' if the Anton won the *i*-th game and 'D' if Danik won the *i*-th game. | If Anton won more games than Danik, print "Anton" (without quotes) in the only line of the output.
If Danik won more games than Anton, print "Danik" (without quotes) in the only line of the output.
If Anton and Danik won the same number of games, print "Friendship" (without quotes). | [
"6\nADAAAA\n",
"7\nDDDAADA\n",
"6\nDADADA\n"
] | [
"Anton\n",
"Danik\n",
"Friendship\n"
] | In the first sample, Anton won 6 games, while Danik — only 1. Hence, the answer is "Anton".
In the second sample, Anton won 3 games and Danik won 4 games, so the answer is "Danik".
In the third sample, both Anton and Danik won 3 games and the answer is "Friendship". | 500 | [
{
"input": "6\nADAAAA",
"output": "Anton"
},
{
"input": "7\nDDDAADA",
"output": "Danik"
},
{
"input": "6\nDADADA",
"output": "Friendship"
},
{
"input": "10\nDDDDADDADD",
"output": "Danik"
},
{
"input": "40\nAAAAAAAAADDAAAAAAAAAAADADDAAAAAAAAAAADAA",
"output": ... | 1,692,815,375 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | n=int(input())
m=input()
na=m.count('A')
nd=m.count('D')
if na>nd:print("Anton")
if nd>na:print("Danik")
else:print("Friendship") | Title: Anton and Danik
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, who won more games, he or Danik? Help him determine this.
Input Specification:
The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of games played.
The second line contains a string *s*, consisting of *n* uppercase English letters 'A' and 'D' — the outcome of each of the games. The *i*-th character of the string is equal to 'A' if the Anton won the *i*-th game and 'D' if Danik won the *i*-th game.
Output Specification:
If Anton won more games than Danik, print "Anton" (without quotes) in the only line of the output.
If Danik won more games than Anton, print "Danik" (without quotes) in the only line of the output.
If Anton and Danik won the same number of games, print "Friendship" (without quotes).
Demo Input:
['6\nADAAAA\n', '7\nDDDAADA\n', '6\nDADADA\n']
Demo Output:
['Anton\n', 'Danik\n', 'Friendship\n']
Note:
In the first sample, Anton won 6 games, while Danik — only 1. Hence, the answer is "Anton".
In the second sample, Anton won 3 games and Danik won 4 games, so the answer is "Danik".
In the third sample, both Anton and Danik won 3 games and the answer is "Friendship". | ```python
n=int(input())
m=input()
na=m.count('A')
nd=m.count('D')
if na>nd:print("Anton")
if nd>na:print("Danik")
else:print("Friendship")
``` | 0 | |
459 | B | Pashmak and Flowers | PROGRAMMING | 1,300 | [
"combinatorics",
"implementation",
"sortings"
] | null | null | Pashmak decided to give Parmida a pair of flowers from the garden. There are *n* flowers in the garden and the *i*-th of them has a beauty number *b**i*. Parmida is a very strange girl so she doesn't want to have the two most beautiful flowers necessarily. She wants to have those pairs of flowers that their beauty difference is maximal possible!
Your task is to write a program which calculates two things:
1. The maximum beauty difference of flowers that Pashmak can give to Parmida. 1. The number of ways that Pashmak can pick the flowers. Two ways are considered different if and only if there is at least one flower that is chosen in the first way and not chosen in the second way. | The first line of the input contains *n* (2<=≤<=*n*<=≤<=2·105). In the next line there are *n* space-separated integers *b*1, *b*2, ..., *b**n* (1<=≤<=*b**i*<=≤<=109). | The only line of output should contain two integers. The maximum beauty difference and the number of ways this may happen, respectively. | [
"2\n1 2\n",
"3\n1 4 5\n",
"5\n3 1 2 3 1\n"
] | [
"1 1",
"4 1",
"2 4"
] | In the third sample the maximum beauty difference is 2 and there are 4 ways to do this:
1. choosing the first and the second flowers; 1. choosing the first and the fifth flowers; 1. choosing the fourth and the second flowers; 1. choosing the fourth and the fifth flowers. | 500 | [
{
"input": "2\n1 2",
"output": "1 1"
},
{
"input": "3\n1 4 5",
"output": "4 1"
},
{
"input": "5\n3 1 2 3 1",
"output": "2 4"
},
{
"input": "2\n1 1",
"output": "0 1"
},
{
"input": "3\n1 1 1",
"output": "0 3"
},
{
"input": "4\n1 1 1 1",
"output": "0 ... | 1,683,386,593 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 108 | 20,070,400 | n = int(input())
a = list(map(int, input().split()))
a.sort()
print(a[-1] - a[0], end=" ")
if a[0] == a[-1]:
print(n * (n - 1) / 2)
exit()
mi = a[0]
ma = a[-1]
kmi = 0
kma = 0
for i in range(n):
if a[i] == mi:
kmi += 1
elif a[i] == ma:
kma += 1
print(kmi * kma)
| Title: Pashmak and Flowers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pashmak decided to give Parmida a pair of flowers from the garden. There are *n* flowers in the garden and the *i*-th of them has a beauty number *b**i*. Parmida is a very strange girl so she doesn't want to have the two most beautiful flowers necessarily. She wants to have those pairs of flowers that their beauty difference is maximal possible!
Your task is to write a program which calculates two things:
1. The maximum beauty difference of flowers that Pashmak can give to Parmida. 1. The number of ways that Pashmak can pick the flowers. Two ways are considered different if and only if there is at least one flower that is chosen in the first way and not chosen in the second way.
Input Specification:
The first line of the input contains *n* (2<=≤<=*n*<=≤<=2·105). In the next line there are *n* space-separated integers *b*1, *b*2, ..., *b**n* (1<=≤<=*b**i*<=≤<=109).
Output Specification:
The only line of output should contain two integers. The maximum beauty difference and the number of ways this may happen, respectively.
Demo Input:
['2\n1 2\n', '3\n1 4 5\n', '5\n3 1 2 3 1\n']
Demo Output:
['1 1', '4 1', '2 4']
Note:
In the third sample the maximum beauty difference is 2 and there are 4 ways to do this:
1. choosing the first and the second flowers; 1. choosing the first and the fifth flowers; 1. choosing the fourth and the second flowers; 1. choosing the fourth and the fifth flowers. | ```python
n = int(input())
a = list(map(int, input().split()))
a.sort()
print(a[-1] - a[0], end=" ")
if a[0] == a[-1]:
print(n * (n - 1) / 2)
exit()
mi = a[0]
ma = a[-1]
kmi = 0
kma = 0
for i in range(n):
if a[i] == mi:
kmi += 1
elif a[i] == ma:
kma += 1
print(kmi * kma)
``` | 0 | |
596 | B | Wilbur and Array | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | Wilbur the pig is tinkering with arrays again. He has the array *a*1,<=*a*2,<=...,<=*a**n* initially consisting of *n* zeros. At one step, he can choose any index *i* and either add 1 to all elements *a**i*,<=*a**i*<=+<=1,<=... ,<=*a**n* or subtract 1 from all elements *a**i*,<=*a**i*<=+<=1,<=...,<=*a**n*. His goal is to end up with the array *b*1,<=*b*2,<=...,<=*b**n*.
Of course, Wilbur wants to achieve this goal in the minimum number of steps and asks you to compute this value. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the length of the array *a**i*. Initially *a**i*<==<=0 for every position *i*, so this array is not given in the input.
The second line of the input contains *n* integers *b*1,<=*b*2,<=...,<=*b**n* (<=-<=109<=≤<=*b**i*<=≤<=109). | Print the minimum number of steps that Wilbur needs to make in order to achieve *a**i*<==<=*b**i* for all *i*. | [
"5\n1 2 3 4 5\n",
"4\n1 2 2 1\n"
] | [
"5",
"3"
] | In the first sample, Wilbur may successively choose indices 1, 2, 3, 4, and 5, and add 1 to corresponding suffixes.
In the second sample, Wilbur first chooses indices 1 and 2 and adds 1 to corresponding suffixes, then he chooses index 4 and subtract 1. | 1,000 | [
{
"input": "5\n1 2 3 4 5",
"output": "5"
},
{
"input": "4\n1 2 2 1",
"output": "3"
},
{
"input": "3\n1 2 4",
"output": "4"
},
{
"input": "6\n1 2 3 6 5 4",
"output": "8"
},
{
"input": "10\n2 1 4 3 6 5 8 7 10 9",
"output": "19"
},
{
"input": "7\n12 6 12 ... | 1,447,726,348 | 2,147,483,647 | Python 3 | OK | TESTS | 76 | 295 | 14,438,400 | n=int(input())
l=input().split()
m,s=0,0
def dif(a,b):
if(a>b):
return a-b
return b-a
for i in range(n):
x=int(l[i])
s+=dif(x,m)
if(x>m):
m+=dif(x,m)
elif(x<m):
m-=dif(x,m)
print(s)
| Title: Wilbur and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Wilbur the pig is tinkering with arrays again. He has the array *a*1,<=*a*2,<=...,<=*a**n* initially consisting of *n* zeros. At one step, he can choose any index *i* and either add 1 to all elements *a**i*,<=*a**i*<=+<=1,<=... ,<=*a**n* or subtract 1 from all elements *a**i*,<=*a**i*<=+<=1,<=...,<=*a**n*. His goal is to end up with the array *b*1,<=*b*2,<=...,<=*b**n*.
Of course, Wilbur wants to achieve this goal in the minimum number of steps and asks you to compute this value.
Input Specification:
The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the length of the array *a**i*. Initially *a**i*<==<=0 for every position *i*, so this array is not given in the input.
The second line of the input contains *n* integers *b*1,<=*b*2,<=...,<=*b**n* (<=-<=109<=≤<=*b**i*<=≤<=109).
Output Specification:
Print the minimum number of steps that Wilbur needs to make in order to achieve *a**i*<==<=*b**i* for all *i*.
Demo Input:
['5\n1 2 3 4 5\n', '4\n1 2 2 1\n']
Demo Output:
['5', '3']
Note:
In the first sample, Wilbur may successively choose indices 1, 2, 3, 4, and 5, and add 1 to corresponding suffixes.
In the second sample, Wilbur first chooses indices 1 and 2 and adds 1 to corresponding suffixes, then he chooses index 4 and subtract 1. | ```python
n=int(input())
l=input().split()
m,s=0,0
def dif(a,b):
if(a>b):
return a-b
return b-a
for i in range(n):
x=int(l[i])
s+=dif(x,m)
if(x>m):
m+=dif(x,m)
elif(x<m):
m-=dif(x,m)
print(s)
``` | 3 | |
129 | B | Students and Shoelaces | PROGRAMMING | 1,200 | [
"brute force",
"dfs and similar",
"graphs",
"implementation"
] | null | null | Anna and Maria are in charge of the math club for junior students. When the club gathers together, the students behave badly. They've brought lots of shoe laces to the club and got tied with each other. Specifically, each string ties together two students. Besides, if two students are tied, then the lace connects the first student with the second one as well as the second student with the first one.
To restore order, Anna and Maria do the following. First, for each student Anna finds out what other students he is tied to. If a student is tied to exactly one other student, Anna reprimands him. Then Maria gathers in a single group all the students who have been just reprimanded. She kicks them out from the club. This group of students immediately leaves the club. These students takes with them the laces that used to tie them. Then again for every student Anna finds out how many other students he is tied to and so on. And they do so until Anna can reprimand at least one student.
Determine how many groups of students will be kicked out of the club. | The first line contains two integers *n* and *m* — the initial number of students and laces (). The students are numbered from 1 to *n*, and the laces are numbered from 1 to *m*. Next *m* lines each contain two integers *a* and *b* — the numbers of students tied by the *i*-th lace (1<=≤<=*a*,<=*b*<=≤<=*n*,<=*a*<=≠<=*b*). It is guaranteed that no two students are tied with more than one lace. No lace ties a student to himself. | Print the single number — the number of groups of students that will be kicked out from the club. | [
"3 3\n1 2\n2 3\n3 1\n",
"6 3\n1 2\n2 3\n3 4\n",
"6 5\n1 4\n2 4\n3 4\n5 4\n6 4\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the first sample Anna and Maria won't kick out any group of students — in the initial position every student is tied to two other students and Anna won't be able to reprimand anyone.
In the second sample four students are tied in a chain and two more are running by themselves. First Anna and Maria kick out the two students from both ends of the chain (1 and 4), then — two other students from the chain (2 and 3). At that the students who are running by themselves will stay in the club.
In the third sample Anna and Maria will momentarily kick out all students except for the fourth one and the process stops at that point. The correct answer is one. | 1,000 | [
{
"input": "3 3\n1 2\n2 3\n3 1",
"output": "0"
},
{
"input": "6 3\n1 2\n2 3\n3 4",
"output": "2"
},
{
"input": "6 5\n1 4\n2 4\n3 4\n5 4\n6 4",
"output": "1"
},
{
"input": "100 0",
"output": "0"
},
{
"input": "5 5\n1 2\n2 3\n3 4\n4 5\n5 1",
"output": "0"
},
... | 1,603,371,760 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 154 | 204,800 | n,m = list(map(int,input().strip().split(" ")))
data = [[0 for i in range(n)] for i in range(n)]
for i in range(m):
a,b = list(map(int,input().strip().split(" ")))
data[i-1][j-1] = 1
data[j-1][i-1] = 1
res = 0
flag = True
while(flag):
flag = False
tmp = []
for i in range(n):
if sum(data[i]) == 1:
if not flag:
res += 1
flag = True
data[i][data[i].index(1)] = 0
print(res)
| Title: Students and Shoelaces
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anna and Maria are in charge of the math club for junior students. When the club gathers together, the students behave badly. They've brought lots of shoe laces to the club and got tied with each other. Specifically, each string ties together two students. Besides, if two students are tied, then the lace connects the first student with the second one as well as the second student with the first one.
To restore order, Anna and Maria do the following. First, for each student Anna finds out what other students he is tied to. If a student is tied to exactly one other student, Anna reprimands him. Then Maria gathers in a single group all the students who have been just reprimanded. She kicks them out from the club. This group of students immediately leaves the club. These students takes with them the laces that used to tie them. Then again for every student Anna finds out how many other students he is tied to and so on. And they do so until Anna can reprimand at least one student.
Determine how many groups of students will be kicked out of the club.
Input Specification:
The first line contains two integers *n* and *m* — the initial number of students and laces (). The students are numbered from 1 to *n*, and the laces are numbered from 1 to *m*. Next *m* lines each contain two integers *a* and *b* — the numbers of students tied by the *i*-th lace (1<=≤<=*a*,<=*b*<=≤<=*n*,<=*a*<=≠<=*b*). It is guaranteed that no two students are tied with more than one lace. No lace ties a student to himself.
Output Specification:
Print the single number — the number of groups of students that will be kicked out from the club.
Demo Input:
['3 3\n1 2\n2 3\n3 1\n', '6 3\n1 2\n2 3\n3 4\n', '6 5\n1 4\n2 4\n3 4\n5 4\n6 4\n']
Demo Output:
['0\n', '2\n', '1\n']
Note:
In the first sample Anna and Maria won't kick out any group of students — in the initial position every student is tied to two other students and Anna won't be able to reprimand anyone.
In the second sample four students are tied in a chain and two more are running by themselves. First Anna and Maria kick out the two students from both ends of the chain (1 and 4), then — two other students from the chain (2 and 3). At that the students who are running by themselves will stay in the club.
In the third sample Anna and Maria will momentarily kick out all students except for the fourth one and the process stops at that point. The correct answer is one. | ```python
n,m = list(map(int,input().strip().split(" ")))
data = [[0 for i in range(n)] for i in range(n)]
for i in range(m):
a,b = list(map(int,input().strip().split(" ")))
data[i-1][j-1] = 1
data[j-1][i-1] = 1
res = 0
flag = True
while(flag):
flag = False
tmp = []
for i in range(n):
if sum(data[i]) == 1:
if not flag:
res += 1
flag = True
data[i][data[i].index(1)] = 0
print(res)
``` | -1 | |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consists of several words. For each language, all words are distinct, i.e. they are spelled differently. Moreover, the words of these languages have a one-to-one correspondence, that is, for each word in each language, there exists exactly one word in the other language having has the same meaning.
You can write down every word the professor says in either the first language or the second language. Of course, during the lecture you write down each word in the language in which the word is shorter. In case of equal lengths of the corresponding words you prefer the word of the first language.
You are given the text of the lecture the professor is going to read. Find out how the lecture will be recorded in your notes. | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* belongs to the first language, the word *b**i* belongs to the second language, and these two words have the same meaning. It is guaranteed that no word occurs in both languages, and each word occurs in its language exactly once.
The next line contains *n* space-separated strings *c*1,<=*c*2,<=...,<=*c**n* — the text of the lecture. It is guaranteed that each of the strings *c**i* belongs to the set of strings {*a*1,<=*a*2,<=... *a**m*}.
All the strings in the input are non-empty, each consisting of no more than 10 lowercase English letters. | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,639,298,902 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 37 | 187 | 3,174,400 | n, m = [int(i) for i in input().split()]
languages = {}
for i in range(m):
f, s = input().split()
languages[f] = (s, len(f), len(s))
p = input().split()
for i in range(n):
el = languages[p[i]]
if el[2] < el[1]:
p[i] = el[0]
print(*p) | Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consists of several words. For each language, all words are distinct, i.e. they are spelled differently. Moreover, the words of these languages have a one-to-one correspondence, that is, for each word in each language, there exists exactly one word in the other language having has the same meaning.
You can write down every word the professor says in either the first language or the second language. Of course, during the lecture you write down each word in the language in which the word is shorter. In case of equal lengths of the corresponding words you prefer the word of the first language.
You are given the text of the lecture the professor is going to read. Find out how the lecture will be recorded in your notes.
Input Specification:
The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* belongs to the first language, the word *b**i* belongs to the second language, and these two words have the same meaning. It is guaranteed that no word occurs in both languages, and each word occurs in its language exactly once.
The next line contains *n* space-separated strings *c*1,<=*c*2,<=...,<=*c**n* — the text of the lecture. It is guaranteed that each of the strings *c**i* belongs to the set of strings {*a*1,<=*a*2,<=... *a**m*}.
All the strings in the input are non-empty, each consisting of no more than 10 lowercase English letters.
Output Specification:
Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input.
Demo Input:
['4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n', '5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n']
Demo Output:
['codeforces round letter round\n', 'hbnyiyc joll joll un joll\n']
Note:
none | ```python
n, m = [int(i) for i in input().split()]
languages = {}
for i in range(m):
f, s = input().split()
languages[f] = (s, len(f), len(s))
p = input().split()
for i in range(n):
el = languages[p[i]]
if el[2] < el[1]:
p[i] = el[0]
print(*p)
``` | 3 | |
765 | A | Neverending competitions | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | There are literally dozens of snooker competitions held each year, and team Jinotega tries to attend them all (for some reason they prefer name "snookah")! When a competition takes place somewhere far from their hometown, Ivan, Artsem and Konstantin take a flight to the contest and back.
Jinotega's best friends, team Base have found a list of their itinerary receipts with information about departure and arrival airports. Now they wonder, where is Jinotega now: at home or at some competition far away? They know that:
- this list contains all Jinotega's flights in this year (in arbitrary order), - Jinotega has only flown from his hometown to a snooker contest and back, - after each competition Jinotega flies back home (though they may attend a competition in one place several times), - and finally, at the beginning of the year Jinotega was at home.
Please help them to determine Jinotega's location! | In the first line of input there is a single integer *n*: the number of Jinotega's flights (1<=≤<=*n*<=≤<=100). In the second line there is a string of 3 capital Latin letters: the name of Jinotega's home airport. In the next *n* lines there is flight information, one flight per line, in form "XXX->YYY", where "XXX" is the name of departure airport "YYY" is the name of arrival airport. Exactly one of these airports is Jinotega's home airport.
It is guaranteed that flights information is consistent with the knowledge of Jinotega's friends, which is described in the main part of the statement. | If Jinotega is now at home, print "home" (without quotes), otherwise print "contest". | [
"4\nSVO\nSVO->CDG\nLHR->SVO\nSVO->LHR\nCDG->SVO\n",
"3\nSVO\nSVO->HKT\nHKT->SVO\nSVO->RAP\n"
] | [
"home\n",
"contest\n"
] | In the first sample Jinotega might first fly from SVO to CDG and back, and then from SVO to LHR and back, so now they should be at home. In the second sample Jinotega must now be at RAP because a flight from RAP back to SVO is not on the list. | 500 | [
{
"input": "4\nSVO\nSVO->CDG\nLHR->SVO\nSVO->LHR\nCDG->SVO",
"output": "home"
},
{
"input": "3\nSVO\nSVO->HKT\nHKT->SVO\nSVO->RAP",
"output": "contest"
},
{
"input": "1\nESJ\nESJ->TSJ",
"output": "contest"
},
{
"input": "2\nXMR\nFAJ->XMR\nXMR->FAJ",
"output": "home"
},
... | 1,487,062,646 | 3,146 | Python 3 | OK | TESTS | 23 | 62 | 5,120,000 | #Rohan Bojja
#[email protected]
from collections import defaultdict
#######################################
c=1
cases=1
while(c<=cases):
n=int(input())
home=input()
iten=defaultdict(list)
for i in range(0,n):
cur=input().split("->")
iten[cur[0]].append(cur[1])
ans="home"
cur=home
while(True):
#print(cur,iten)
if(cur in iten):
if(cur!=home and home in iten[cur]):
del iten[cur][iten[cur].index(home)]
cur=home
elif(cur!=home):
ans="contest"
break
elif(cur==home and len(iten[cur])>0):
cur2=iten[cur][0]
iten[cur].pop(0)
cur=cur2
elif(cur==home):
break
else:
ans="contest"
break
#print(cur,iten)
print(ans)
c=c+1
| Title: Neverending competitions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are literally dozens of snooker competitions held each year, and team Jinotega tries to attend them all (for some reason they prefer name "snookah")! When a competition takes place somewhere far from their hometown, Ivan, Artsem and Konstantin take a flight to the contest and back.
Jinotega's best friends, team Base have found a list of their itinerary receipts with information about departure and arrival airports. Now they wonder, where is Jinotega now: at home or at some competition far away? They know that:
- this list contains all Jinotega's flights in this year (in arbitrary order), - Jinotega has only flown from his hometown to a snooker contest and back, - after each competition Jinotega flies back home (though they may attend a competition in one place several times), - and finally, at the beginning of the year Jinotega was at home.
Please help them to determine Jinotega's location!
Input Specification:
In the first line of input there is a single integer *n*: the number of Jinotega's flights (1<=≤<=*n*<=≤<=100). In the second line there is a string of 3 capital Latin letters: the name of Jinotega's home airport. In the next *n* lines there is flight information, one flight per line, in form "XXX->YYY", where "XXX" is the name of departure airport "YYY" is the name of arrival airport. Exactly one of these airports is Jinotega's home airport.
It is guaranteed that flights information is consistent with the knowledge of Jinotega's friends, which is described in the main part of the statement.
Output Specification:
If Jinotega is now at home, print "home" (without quotes), otherwise print "contest".
Demo Input:
['4\nSVO\nSVO->CDG\nLHR->SVO\nSVO->LHR\nCDG->SVO\n', '3\nSVO\nSVO->HKT\nHKT->SVO\nSVO->RAP\n']
Demo Output:
['home\n', 'contest\n']
Note:
In the first sample Jinotega might first fly from SVO to CDG and back, and then from SVO to LHR and back, so now they should be at home. In the second sample Jinotega must now be at RAP because a flight from RAP back to SVO is not on the list. | ```python
#Rohan Bojja
#[email protected]
from collections import defaultdict
#######################################
c=1
cases=1
while(c<=cases):
n=int(input())
home=input()
iten=defaultdict(list)
for i in range(0,n):
cur=input().split("->")
iten[cur[0]].append(cur[1])
ans="home"
cur=home
while(True):
#print(cur,iten)
if(cur in iten):
if(cur!=home and home in iten[cur]):
del iten[cur][iten[cur].index(home)]
cur=home
elif(cur!=home):
ans="contest"
break
elif(cur==home and len(iten[cur])>0):
cur2=iten[cur][0]
iten[cur].pop(0)
cur=cur2
elif(cur==home):
break
else:
ans="contest"
break
#print(cur,iten)
print(ans)
c=c+1
``` | 3 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*. | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,640,710,041 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 14 | 46 | 0 | string = input()
arr = []
arr.append(string.find('h'))
arr.append(string.find('e', arr[0]+1))
arr.append(string.find('l', arr[1]+1))
arr.append(string.find('l', arr[2]+1))
arr.append(string.find('o', arr[3]+1))
# print(arr)
if arr == sorted(arr):
print("YES")
else:
print("NO") | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*.
Input Specification:
The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters.
Output Specification:
If Vasya managed to say hello, print "YES", otherwise print "NO".
Demo Input:
['ahhellllloou\n', 'hlelo\n']
Demo Output:
['YES\n', 'NO\n']
Note:
none | ```python
string = input()
arr = []
arr.append(string.find('h'))
arr.append(string.find('e', arr[0]+1))
arr.append(string.find('l', arr[1]+1))
arr.append(string.find('l', arr[2]+1))
arr.append(string.find('o', arr[3]+1))
# print(arr)
if arr == sorted(arr):
print("YES")
else:
print("NO")
``` | 0 |
0 | none | none | none | 0 | [
"none"
] | null | null | There are *n* beacons located at distinct positions on a number line. The *i*-th beacon has position *a**i* and power level *b**i*. When the *i*-th beacon is activated, it destroys all beacons to its left (direction of decreasing coordinates) within distance *b**i* inclusive. The beacon itself is not destroyed however. Saitama will activate the beacons one at a time from right to left. If a beacon is destroyed, it cannot be activated.
Saitama wants Genos to add a beacon strictly to the right of all the existing beacons, with any position and any power level, such that the least possible number of beacons are destroyed. Note that Genos's placement of the beacon means it will be the first beacon activated. Help Genos by finding the minimum number of beacons that could be destroyed. | The first line of input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the initial number of beacons.
The *i*-th of next *n* lines contains two integers *a**i* and *b**i* (0<=≤<=*a**i*<=≤<=1<=000<=000, 1<=≤<=*b**i*<=≤<=1<=000<=000) — the position and power level of the *i*-th beacon respectively. No two beacons will have the same position, so *a**i*<=≠<=*a**j* if *i*<=≠<=*j*. | Print a single integer — the minimum number of beacons that could be destroyed if exactly one beacon is added. | [
"4\n1 9\n3 1\n6 1\n7 4\n",
"7\n1 1\n2 1\n3 1\n4 1\n5 1\n6 1\n7 1\n"
] | [
"1\n",
"3\n"
] | For the first sample case, the minimum number of beacons destroyed is 1. One way to achieve this is to place a beacon at position 9 with power level 2.
For the second sample case, the minimum number of beacons destroyed is 3. One way to achieve this is to place a beacon at position 1337 with power level 42. | 0 | [
{
"input": "4\n1 9\n3 1\n6 1\n7 4",
"output": "1"
},
{
"input": "7\n1 1\n2 1\n3 1\n4 1\n5 1\n6 1\n7 1",
"output": "3"
},
{
"input": "1\n0 1",
"output": "0"
},
{
"input": "1\n0 1000000",
"output": "0"
},
{
"input": "1\n1000000 1000000",
"output": "0"
},
{
... | 1,521,774,664 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 93 | 7,475,200 | import copy
n, w, h = [int(x) for x in input().split()]
class Envelope:
def __init__(self, width, height, index):
self.width = width
self.height = height
self.index = index
def __str__(self):
return "(" + str(self.width) + ", " + str(self.height) + ")"
envelopes = set()
for i in range(n):
width, height = [int(x) for x in input().split()]
envelopes.add(Envelope(width, height, i + 1))
cache = {}
def get_envelope_chain(envelope, available_envelopes):
# caching
if envelope in cache:
# print("Reading cache for", envelope.index)
# print("For cached envelope", envelope.index, "chain =", [str(x.index) for x in cache[envelope]])
return cache[envelope]
# if envelope != None:
# if len(available_envelopes) == 0 or (envelope.width <= w or envelope.height <= h):
# return [envelope]
# print("Available envelopes (prev chosen=" + str(envelope) +"):", [str(x) for x in available_envelopes])
taken_out = []
for env in available_envelopes:
if envelope != None and (env.width > envelope.width or env.height > envelope.height):
taken_out.append(env)
for env in taken_out:
available_envelopes.remove(env)
max_chain_size = -1
chosen_chain = []
for env in available_envelopes:
# print("Checking env", str(env), envelope)
if envelope == None or (env.width < envelope.width and env.height < envelope.height):
if env.width > w and env.height > h:
available_envelopes.remove(env)
# new_available_envelopes = available_envelopes.copy()
# new_available_envelopes.remove(env)
chain = get_envelope_chain(env, available_envelopes)
# print("For env", env.index, "found chain", [str(x) for x in chain])
available_envelopes.add(env)
if len(chain) > max_chain_size:
max_chain_size = len(chain)
chosen_chain = chain
for env in taken_out:
available_envelopes.add(env)
# test
if envelope != None:
chosen_chain = list(chosen_chain)
chosen_chain.append(envelope)
# print("chosen_chain:", [str(x) for x in chosen_chain])
# if envelope and envelope.index == 5:
# print("hey")
# print("Caching chosen_chain:", [x.index for x in chosen_chain])
# if envelope and envelope.index == 5:
# print("CHOSEN_CHAIN 5", [x.index for x in chosen_chain])
cache[envelope] = chosen_chain
return chosen_chain
found_chain = get_envelope_chain(None, envelopes)
#print([str(x) for x in found_chain])
print(len(found_chain))
print(" ".join([str(env.index) for env in found_chain]))
# f(envelope) = next_envelope = f(envelope_(e-1))
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* beacons located at distinct positions on a number line. The *i*-th beacon has position *a**i* and power level *b**i*. When the *i*-th beacon is activated, it destroys all beacons to its left (direction of decreasing coordinates) within distance *b**i* inclusive. The beacon itself is not destroyed however. Saitama will activate the beacons one at a time from right to left. If a beacon is destroyed, it cannot be activated.
Saitama wants Genos to add a beacon strictly to the right of all the existing beacons, with any position and any power level, such that the least possible number of beacons are destroyed. Note that Genos's placement of the beacon means it will be the first beacon activated. Help Genos by finding the minimum number of beacons that could be destroyed.
Input Specification:
The first line of input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the initial number of beacons.
The *i*-th of next *n* lines contains two integers *a**i* and *b**i* (0<=≤<=*a**i*<=≤<=1<=000<=000, 1<=≤<=*b**i*<=≤<=1<=000<=000) — the position and power level of the *i*-th beacon respectively. No two beacons will have the same position, so *a**i*<=≠<=*a**j* if *i*<=≠<=*j*.
Output Specification:
Print a single integer — the minimum number of beacons that could be destroyed if exactly one beacon is added.
Demo Input:
['4\n1 9\n3 1\n6 1\n7 4\n', '7\n1 1\n2 1\n3 1\n4 1\n5 1\n6 1\n7 1\n']
Demo Output:
['1\n', '3\n']
Note:
For the first sample case, the minimum number of beacons destroyed is 1. One way to achieve this is to place a beacon at position 9 with power level 2.
For the second sample case, the minimum number of beacons destroyed is 3. One way to achieve this is to place a beacon at position 1337 with power level 42. | ```python
import copy
n, w, h = [int(x) for x in input().split()]
class Envelope:
def __init__(self, width, height, index):
self.width = width
self.height = height
self.index = index
def __str__(self):
return "(" + str(self.width) + ", " + str(self.height) + ")"
envelopes = set()
for i in range(n):
width, height = [int(x) for x in input().split()]
envelopes.add(Envelope(width, height, i + 1))
cache = {}
def get_envelope_chain(envelope, available_envelopes):
# caching
if envelope in cache:
# print("Reading cache for", envelope.index)
# print("For cached envelope", envelope.index, "chain =", [str(x.index) for x in cache[envelope]])
return cache[envelope]
# if envelope != None:
# if len(available_envelopes) == 0 or (envelope.width <= w or envelope.height <= h):
# return [envelope]
# print("Available envelopes (prev chosen=" + str(envelope) +"):", [str(x) for x in available_envelopes])
taken_out = []
for env in available_envelopes:
if envelope != None and (env.width > envelope.width or env.height > envelope.height):
taken_out.append(env)
for env in taken_out:
available_envelopes.remove(env)
max_chain_size = -1
chosen_chain = []
for env in available_envelopes:
# print("Checking env", str(env), envelope)
if envelope == None or (env.width < envelope.width and env.height < envelope.height):
if env.width > w and env.height > h:
available_envelopes.remove(env)
# new_available_envelopes = available_envelopes.copy()
# new_available_envelopes.remove(env)
chain = get_envelope_chain(env, available_envelopes)
# print("For env", env.index, "found chain", [str(x) for x in chain])
available_envelopes.add(env)
if len(chain) > max_chain_size:
max_chain_size = len(chain)
chosen_chain = chain
for env in taken_out:
available_envelopes.add(env)
# test
if envelope != None:
chosen_chain = list(chosen_chain)
chosen_chain.append(envelope)
# print("chosen_chain:", [str(x) for x in chosen_chain])
# if envelope and envelope.index == 5:
# print("hey")
# print("Caching chosen_chain:", [x.index for x in chosen_chain])
# if envelope and envelope.index == 5:
# print("CHOSEN_CHAIN 5", [x.index for x in chosen_chain])
cache[envelope] = chosen_chain
return chosen_chain
found_chain = get_envelope_chain(None, envelopes)
#print([str(x) for x in found_chain])
print(len(found_chain))
print(" ".join([str(env.index) for env in found_chain]))
# f(envelope) = next_envelope = f(envelope_(e-1))
``` | -1 | |
954 | A | Diagonal Walking | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mikhail walks on a 2D plane. He can go either up or right. You are given a sequence of Mikhail's moves. He thinks that this sequence is too long and he wants to make it as short as possible.
In the given sequence moving up is described by character U and moving right is described by character R. Mikhail can replace any pair of consecutive moves RU or UR with a diagonal move (described as character D). After that, he can go on and do some other replacements, until there is no pair of consecutive moves RU or UR left.
Your problem is to print the minimum possible length of the sequence of moves after the replacements. | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=100) — the length of the sequence. The second line contains the sequence consisting of *n* characters U and R. | Print the minimum possible length of the sequence of moves after all replacements are done. | [
"5\nRUURU\n",
"17\nUUURRRRRUUURURUUU\n"
] | [
"3\n",
"13\n"
] | In the first test the shortened sequence of moves may be DUD (its length is 3).
In the second test the shortened sequence of moves can be UUDRRRDUDDUUU (its length is 13). | 0 | [
{
"input": "5\nRUURU",
"output": "3"
},
{
"input": "17\nUUURRRRRUUURURUUU",
"output": "13"
},
{
"input": "100\nUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUU",
"output": "100"
},
{
"input": "100\nRRURRUUUURURRRURRRRURRRRRR... | 1,692,021,539 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 31 | 0 | n = input()
str = input()
str1 = str.replace('UR', 'D')
str2 = str1.replace('RU', 'D')
len1 = len(str2)
str3 = str.replace('RU', 'D')
str4 = str.replace('UR', 'D')
len2 = len(str4)
print(min(len1,len2))
| Title: Diagonal Walking
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mikhail walks on a 2D plane. He can go either up or right. You are given a sequence of Mikhail's moves. He thinks that this sequence is too long and he wants to make it as short as possible.
In the given sequence moving up is described by character U and moving right is described by character R. Mikhail can replace any pair of consecutive moves RU or UR with a diagonal move (described as character D). After that, he can go on and do some other replacements, until there is no pair of consecutive moves RU or UR left.
Your problem is to print the minimum possible length of the sequence of moves after the replacements.
Input Specification:
The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=100) — the length of the sequence. The second line contains the sequence consisting of *n* characters U and R.
Output Specification:
Print the minimum possible length of the sequence of moves after all replacements are done.
Demo Input:
['5\nRUURU\n', '17\nUUURRRRRUUURURUUU\n']
Demo Output:
['3\n', '13\n']
Note:
In the first test the shortened sequence of moves may be DUD (its length is 3).
In the second test the shortened sequence of moves can be UUDRRRDUDDUUU (its length is 13). | ```python
n = input()
str = input()
str1 = str.replace('UR', 'D')
str2 = str1.replace('RU', 'D')
len1 = len(str2)
str3 = str.replace('RU', 'D')
str4 = str.replace('UR', 'D')
len2 = len(str4)
print(min(len1,len2))
``` | 0 | |
664 | A | Complicated GCD | PROGRAMMING | 800 | [
"math",
"number theory"
] | null | null | Greatest common divisor *GCD*(*a*,<=*b*) of two positive integers *a* and *b* is equal to the biggest integer *d* such that both integers *a* and *b* are divisible by *d*. There are many efficient algorithms to find greatest common divisor *GCD*(*a*,<=*b*), for example, Euclid algorithm.
Formally, find the biggest integer *d*, such that all integers *a*,<=*a*<=+<=1,<=*a*<=+<=2,<=...,<=*b* are divisible by *d*. To make the problem even more complicated we allow *a* and *b* to be up to googol, 10100 — such number do not fit even in 64-bit integer type! | The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=10100). | Output one integer — greatest common divisor of all integers from *a* to *b* inclusive. | [
"1 2\n",
"61803398874989484820458683436563811772030917980576 61803398874989484820458683436563811772030917980576\n"
] | [
"1\n",
"61803398874989484820458683436563811772030917980576\n"
] | none | 500 | [
{
"input": "1 2",
"output": "1"
},
{
"input": "61803398874989484820458683436563811772030917980576 61803398874989484820458683436563811772030917980576",
"output": "61803398874989484820458683436563811772030917980576"
},
{
"input": "1 100",
"output": "1"
},
{
"input": "100 100000... | 1,667,545,377 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | num1, num2 = map(int, input().split())
def findGCD(num1, num2):
if num2 == 0:
return num1
return findGCD(num2, num1 % num2)
print(findGCD(num1, num2)) | Title: Complicated GCD
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Greatest common divisor *GCD*(*a*,<=*b*) of two positive integers *a* and *b* is equal to the biggest integer *d* such that both integers *a* and *b* are divisible by *d*. There are many efficient algorithms to find greatest common divisor *GCD*(*a*,<=*b*), for example, Euclid algorithm.
Formally, find the biggest integer *d*, such that all integers *a*,<=*a*<=+<=1,<=*a*<=+<=2,<=...,<=*b* are divisible by *d*. To make the problem even more complicated we allow *a* and *b* to be up to googol, 10100 — such number do not fit even in 64-bit integer type!
Input Specification:
The only line of the input contains two integers *a* and *b* (1<=≤<=*a*<=≤<=*b*<=≤<=10100).
Output Specification:
Output one integer — greatest common divisor of all integers from *a* to *b* inclusive.
Demo Input:
['1 2\n', '61803398874989484820458683436563811772030917980576 61803398874989484820458683436563811772030917980576\n']
Demo Output:
['1\n', '61803398874989484820458683436563811772030917980576\n']
Note:
none | ```python
num1, num2 = map(int, input().split())
def findGCD(num1, num2):
if num2 == 0:
return num1
return findGCD(num2, num1 % num2)
print(findGCD(num1, num2))
``` | 0 | |
676 | B | Pyramid of Glasses | PROGRAMMING | 1,500 | [
"implementation",
"math",
"math"
] | null | null | Mary has just graduated from one well-known University and is now attending celebration party. Students like to dream of a beautiful life, so they used champagne glasses to construct a small pyramid. The height of the pyramid is *n*. The top level consists of only 1 glass, that stands on 2 glasses on the second level (counting from the top), then 3 glasses on the third level and so on.The bottom level consists of *n* glasses.
Vlad has seen in the movies many times how the champagne beautifully flows from top levels to bottom ones, filling all the glasses simultaneously. So he took a bottle and started to pour it in the glass located at the top of the pyramid.
Each second, Vlad pours to the top glass the amount of champagne equal to the size of exactly one glass. If the glass is already full, but there is some champagne flowing in it, then it pours over the edge of the glass and is equally distributed over two glasses standing under. If the overflowed glass is at the bottom level, then the champagne pours on the table. For the purpose of this problem we consider that champagne is distributed among pyramid glasses immediately. Vlad is interested in the number of completely full glasses if he stops pouring champagne in *t* seconds.
Pictures below illustrate the pyramid consisting of three levels. | The only line of the input contains two integers *n* and *t* (1<=≤<=*n*<=≤<=10,<=0<=≤<=*t*<=≤<=10<=000) — the height of the pyramid and the number of seconds Vlad will be pouring champagne from the bottle. | Print the single integer — the number of completely full glasses after *t* seconds. | [
"3 5\n",
"4 8\n"
] | [
"4\n",
"6\n"
] | In the first sample, the glasses full after 5 seconds are: the top glass, both glasses on the second level and the middle glass at the bottom level. Left and right glasses of the bottom level will be half-empty. | 1,000 | [
{
"input": "3 5",
"output": "4"
},
{
"input": "4 8",
"output": "6"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "10 10000",
"output": "55"
},
{
"input": "1 10000",
"output": "1"
},
{
"input": "10 1",
"output": "1"
},
{
"input": "1 0",
... | 1,586,427,915 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 82 | 155 | 0 | n, t = list(map(int, input().split()))
cups = [[0 for i in range(j)] for j in range(1, n+1)]
cups[0][0] = 1
for i in range(1, n):
for j in range(len(cups[i])):
if j == 0:
cups[i][j] += 0.5*cups[i-1][j]
elif j == i:
cups[i][j] += 0.5*cups[i-1][j-1]
else:
cups[i][j] += 0.5*(cups[i-1][j] + cups[i-1][j-1])
tf = [[0 for i in range(j)] for j in range(1, n+1)]
tf[0][0] = 1
for i in range(1, n):
for j in range(len(cups[i])):
if j == 0:
tf[i][j] = tf[i-1][j] + int(1/cups[i][j])
elif j == i:
tf[i][j] = tf[i-1][j-1] + int(1/cups[i][j])
else:
if cups[i-1][j] > cups[i-1][j-1]:
tf[i][j] = min(tf[i-1][j], tf[i-1][j-1]) + (2 + (cups[i-1][j-1]*abs(tf[i-1][j] - tf[i-1][j-1])))/(cups[i-1][j] + cups[i-1][j-1])
elif cups[i-1][j] < cups[i-1][j-1]:
tf[i][j] = min(tf[i-1][j], tf[i-1][j-1]) + (2 + (cups[i-1][j]*abs(tf[i-1][j] - tf[i-1][j-1])))/(cups[i-1][j] + cups[i-1][j-1])
else:
tf[i][j] = tf[i-1][j] + (2 + (cups[i-1][j]*abs(tf[i-1][j] - tf[i-1][j-1])))/(2*cups[i-1][j])
ans = 0
for i in range(n):
for j in range(len(tf[i])):
if tf[i][j] <= t:
ans += 1
print(ans) | Title: Pyramid of Glasses
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mary has just graduated from one well-known University and is now attending celebration party. Students like to dream of a beautiful life, so they used champagne glasses to construct a small pyramid. The height of the pyramid is *n*. The top level consists of only 1 glass, that stands on 2 glasses on the second level (counting from the top), then 3 glasses on the third level and so on.The bottom level consists of *n* glasses.
Vlad has seen in the movies many times how the champagne beautifully flows from top levels to bottom ones, filling all the glasses simultaneously. So he took a bottle and started to pour it in the glass located at the top of the pyramid.
Each second, Vlad pours to the top glass the amount of champagne equal to the size of exactly one glass. If the glass is already full, but there is some champagne flowing in it, then it pours over the edge of the glass and is equally distributed over two glasses standing under. If the overflowed glass is at the bottom level, then the champagne pours on the table. For the purpose of this problem we consider that champagne is distributed among pyramid glasses immediately. Vlad is interested in the number of completely full glasses if he stops pouring champagne in *t* seconds.
Pictures below illustrate the pyramid consisting of three levels.
Input Specification:
The only line of the input contains two integers *n* and *t* (1<=≤<=*n*<=≤<=10,<=0<=≤<=*t*<=≤<=10<=000) — the height of the pyramid and the number of seconds Vlad will be pouring champagne from the bottle.
Output Specification:
Print the single integer — the number of completely full glasses after *t* seconds.
Demo Input:
['3 5\n', '4 8\n']
Demo Output:
['4\n', '6\n']
Note:
In the first sample, the glasses full after 5 seconds are: the top glass, both glasses on the second level and the middle glass at the bottom level. Left and right glasses of the bottom level will be half-empty. | ```python
n, t = list(map(int, input().split()))
cups = [[0 for i in range(j)] for j in range(1, n+1)]
cups[0][0] = 1
for i in range(1, n):
for j in range(len(cups[i])):
if j == 0:
cups[i][j] += 0.5*cups[i-1][j]
elif j == i:
cups[i][j] += 0.5*cups[i-1][j-1]
else:
cups[i][j] += 0.5*(cups[i-1][j] + cups[i-1][j-1])
tf = [[0 for i in range(j)] for j in range(1, n+1)]
tf[0][0] = 1
for i in range(1, n):
for j in range(len(cups[i])):
if j == 0:
tf[i][j] = tf[i-1][j] + int(1/cups[i][j])
elif j == i:
tf[i][j] = tf[i-1][j-1] + int(1/cups[i][j])
else:
if cups[i-1][j] > cups[i-1][j-1]:
tf[i][j] = min(tf[i-1][j], tf[i-1][j-1]) + (2 + (cups[i-1][j-1]*abs(tf[i-1][j] - tf[i-1][j-1])))/(cups[i-1][j] + cups[i-1][j-1])
elif cups[i-1][j] < cups[i-1][j-1]:
tf[i][j] = min(tf[i-1][j], tf[i-1][j-1]) + (2 + (cups[i-1][j]*abs(tf[i-1][j] - tf[i-1][j-1])))/(cups[i-1][j] + cups[i-1][j-1])
else:
tf[i][j] = tf[i-1][j] + (2 + (cups[i-1][j]*abs(tf[i-1][j] - tf[i-1][j-1])))/(2*cups[i-1][j])
ans = 0
for i in range(n):
for j in range(len(tf[i])):
if tf[i][j] <= t:
ans += 1
print(ans)
``` | 0 | |
192 | A | Funky Numbers | PROGRAMMING | 1,300 | [
"binary search",
"brute force",
"implementation"
] | null | null | As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as , where *k* is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers.
A well-known hipster Andrew adores everything funky and cool but unfortunately, he isn't good at maths. Given number *n*, help him define whether this number can be represented by a sum of two triangular numbers (not necessarily different)! | The first input line contains an integer *n* (1<=≤<=*n*<=≤<=109). | Print "YES" (without the quotes), if *n* can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes). | [
"256\n",
"512\n"
] | [
"YES\n",
"NO\n"
] | In the first sample number <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/92095692c6ea93e9e3b837a0408ba7543549d5b2.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample number 512 can not be represented as a sum of two triangular numbers. | 500 | [
{
"input": "256",
"output": "YES"
},
{
"input": "512",
"output": "NO"
},
{
"input": "80",
"output": "NO"
},
{
"input": "828",
"output": "YES"
},
{
"input": "6035",
"output": "NO"
},
{
"input": "39210",
"output": "YES"
},
{
"input": "79712",... | 1,591,457,820 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 2,000 | 0 | from math import sqrt
n=int(input())
status="NO"
for i in range(int(2*sqrt(n))):
for j in range(2*int(sqrt(n))):
if (i*(i+1)/2)+(j*(j+1)/2)==n:
status="YES"
print(status)
| Title: Funky Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As you very well know, this year's funkiest numbers are so called triangular numbers (that is, integers that are representable as , where *k* is some positive integer), and the coolest numbers are those that are representable as a sum of two triangular numbers.
A well-known hipster Andrew adores everything funky and cool but unfortunately, he isn't good at maths. Given number *n*, help him define whether this number can be represented by a sum of two triangular numbers (not necessarily different)!
Input Specification:
The first input line contains an integer *n* (1<=≤<=*n*<=≤<=109).
Output Specification:
Print "YES" (without the quotes), if *n* can be represented as a sum of two triangular numbers, otherwise print "NO" (without the quotes).
Demo Input:
['256\n', '512\n']
Demo Output:
['YES\n', 'NO\n']
Note:
In the first sample number <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/92095692c6ea93e9e3b837a0408ba7543549d5b2.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second sample number 512 can not be represented as a sum of two triangular numbers. | ```python
from math import sqrt
n=int(input())
status="NO"
for i in range(int(2*sqrt(n))):
for j in range(2*int(sqrt(n))):
if (i*(i+1)/2)+(j*(j+1)/2)==n:
status="YES"
print(status)
``` | 0 | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,693,305,517 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | n=input()
s=""
i=0
while i<len(n):
if(n[i]=="."):
s+="0"
elif i!= (len(n)-1):
if (n[i+1]=="."):
s+="1"
else:
s+="2"
i+=1
i=i+1
print(s) | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet.
Input Specification:
The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes).
Output Specification:
Output the decoded ternary number. It can have leading zeroes.
Demo Input:
['.-.--\n', '--.\n', '-..-.--\n']
Demo Output:
['012', '20', '1012']
Note:
none | ```python
n=input()
s=""
i=0
while i<len(n):
if(n[i]=="."):
s+="0"
elif i!= (len(n)-1):
if (n[i+1]=="."):
s+="1"
else:
s+="2"
i+=1
i=i+1
print(s)
``` | 3.977 |
441 | A | Valera and Antique Items | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the *j*-th object of the *i*-th seller is *s**ij*. Valera gets on well with each of the *n* sellers. He is perfectly sure that if he outbids the current price of one of the items in the auction (in other words, offers the seller the money that is strictly greater than the current price of the item at the auction), the seller of the object will immediately sign a contract with him.
Unfortunately, Valera has only *v* units of money. Help him to determine which of the *n* sellers he can make a deal with. | The first line contains two space-separated integers *n*,<=*v* (1<=≤<=*n*<=≤<=50; 104<=≤<=*v*<=≤<=106) — the number of sellers and the units of money the Valera has.
Then *n* lines follow. The *i*-th line first contains integer *k**i* (1<=≤<=*k**i*<=≤<=50) the number of items of the *i*-th seller. Then go *k**i* space-separated integers *s**i*1,<=*s**i*2,<=...,<=*s**ik**i* (104<=≤<=*s**ij*<=≤<=106) — the current prices of the items of the *i*-th seller. | In the first line, print integer *p* — the number of sellers with who Valera can make a deal.
In the second line print *p* space-separated integers *q*1,<=*q*2,<=...,<=*q**p* (1<=≤<=*q**i*<=≤<=*n*) — the numbers of the sellers with who Valera can make a deal. Print the numbers of the sellers in the increasing order. | [
"3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000\n",
"3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000\n"
] | [
"3\n1 2 3\n",
"0\n\n"
] | In the first sample Valera can bargain with each of the sellers. He can outbid the following items: a 40000 item from the first seller, a 20000 item from the second seller, and a 10000 item from the third seller.
In the second sample Valera can not make a deal with any of the sellers, as the prices of all items in the auction too big for him. | 500 | [
{
"input": "3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000",
"output": "3\n1 2 3"
},
{
"input": "3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000",
"output": "0"
},
{
"input": "2 100001\n1 895737\n1 541571",
"output": "0"
},
{
"input": "1 1000000\n1 100... | 1,587,280,478 | 2,147,483,647 | PyPy 3 | OK | TESTS | 26 | 140 | 1,433,600 | n , v = input().split()
n , v = int(n), int(v)
st = set()
for i in range(n):
m = i+1
lt = [int(x) for x in input().split()]
#print(lt)
for p in lt[1:]:
if p<v:
st.add(m)
#print(st)
print(len(st))
if len(st)!=0:
print(*st) | Title: Valera and Antique Items
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a collector. Once he wanted to expand his collection with exactly one antique item.
Valera knows *n* sellers of antiques, the *i*-th of them auctioned *k**i* items. Currently the auction price of the *j*-th object of the *i*-th seller is *s**ij*. Valera gets on well with each of the *n* sellers. He is perfectly sure that if he outbids the current price of one of the items in the auction (in other words, offers the seller the money that is strictly greater than the current price of the item at the auction), the seller of the object will immediately sign a contract with him.
Unfortunately, Valera has only *v* units of money. Help him to determine which of the *n* sellers he can make a deal with.
Input Specification:
The first line contains two space-separated integers *n*,<=*v* (1<=≤<=*n*<=≤<=50; 104<=≤<=*v*<=≤<=106) — the number of sellers and the units of money the Valera has.
Then *n* lines follow. The *i*-th line first contains integer *k**i* (1<=≤<=*k**i*<=≤<=50) the number of items of the *i*-th seller. Then go *k**i* space-separated integers *s**i*1,<=*s**i*2,<=...,<=*s**ik**i* (104<=≤<=*s**ij*<=≤<=106) — the current prices of the items of the *i*-th seller.
Output Specification:
In the first line, print integer *p* — the number of sellers with who Valera can make a deal.
In the second line print *p* space-separated integers *q*1,<=*q*2,<=...,<=*q**p* (1<=≤<=*q**i*<=≤<=*n*) — the numbers of the sellers with who Valera can make a deal. Print the numbers of the sellers in the increasing order.
Demo Input:
['3 50000\n1 40000\n2 20000 60000\n3 10000 70000 190000\n', '3 50000\n1 50000\n3 100000 120000 110000\n3 120000 110000 120000\n']
Demo Output:
['3\n1 2 3\n', '0\n\n']
Note:
In the first sample Valera can bargain with each of the sellers. He can outbid the following items: a 40000 item from the first seller, a 20000 item from the second seller, and a 10000 item from the third seller.
In the second sample Valera can not make a deal with any of the sellers, as the prices of all items in the auction too big for him. | ```python
n , v = input().split()
n , v = int(n), int(v)
st = set()
for i in range(n):
m = i+1
lt = [int(x) for x in input().split()]
#print(lt)
for p in lt[1:]:
if p<v:
st.add(m)
#print(st)
print(len(st))
if len(st)!=0:
print(*st)
``` | 3 | |
513 | B1 | Permutations | PROGRAMMING | 1,400 | [
"brute force"
] | null | null | You are given a permutation *p* of numbers 1,<=2,<=...,<=*n*. Let's define *f*(*p*) as the following sum:
Find the lexicographically *m*-th permutation of length *n* in the set of permutations having the maximum possible value of *f*(*p*). | The single line of input contains two integers *n* and *m* (1<=≤<=*m*<=≤<=*cnt**n*), where *cnt**n* is the number of permutations of length *n* with maximum possible value of *f*(*p*).
The problem consists of two subproblems. The subproblems have different constraints on the input. You will get some score for the correct submission of the subproblem. The description of the subproblems follows.
- In subproblem B1 (3 points), the constraint 1<=≤<=*n*<=≤<=8 will hold. - In subproblem B2 (4 points), the constraint 1<=≤<=*n*<=≤<=50 will hold. | Output *n* number forming the required permutation. | [
"2 2\n",
"3 2\n"
] | [
"2 1 \n",
"1 3 2 \n"
] | In the first example, both permutations of numbers {1, 2} yield maximum possible *f*(*p*) which is equal to 4. Among them, (2, 1) comes second in lexicographical order. | 3 | [
{
"input": "2 2",
"output": "2 1 "
},
{
"input": "3 2",
"output": "1 3 2 "
},
{
"input": "1 1",
"output": "1 "
},
{
"input": "3 1",
"output": "1 2 3 "
},
{
"input": "3 3",
"output": "2 3 1 "
},
{
"input": "3 4",
"output": "3 2 1 "
},
{
"inp... | 1,423,329,843 | 1,443 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS1 | 16 | 2,000 | 0 | #!/usr/bin/python3
n, t = map(int, input().split())
A = [i + 1 for i in range(n)]
mx_sum = 0
for B in __import__("itertools").permutations(A):
s = 0
for i in range(n):
for j in range(i, n):
m = 10
for k in range(i, j + 1):
m = min(m, B[k])
s += m
mx_sum = max(mx_sum, s)
cnt = 0
for B in __import__("itertools").permutations(A):
s = 0
for i in range(n):
for j in range(i, n):
m = 10
for k in range(i, j + 1):
m = min(m, B[k])
s += m
if s == mx_sum:
cnt += 1
if cnt == t:
print(" ".join(map(str, B)))
exit(0)
| Title: Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a permutation *p* of numbers 1,<=2,<=...,<=*n*. Let's define *f*(*p*) as the following sum:
Find the lexicographically *m*-th permutation of length *n* in the set of permutations having the maximum possible value of *f*(*p*).
Input Specification:
The single line of input contains two integers *n* and *m* (1<=≤<=*m*<=≤<=*cnt**n*), where *cnt**n* is the number of permutations of length *n* with maximum possible value of *f*(*p*).
The problem consists of two subproblems. The subproblems have different constraints on the input. You will get some score for the correct submission of the subproblem. The description of the subproblems follows.
- In subproblem B1 (3 points), the constraint 1<=≤<=*n*<=≤<=8 will hold. - In subproblem B2 (4 points), the constraint 1<=≤<=*n*<=≤<=50 will hold.
Output Specification:
Output *n* number forming the required permutation.
Demo Input:
['2 2\n', '3 2\n']
Demo Output:
['2 1 \n', '1 3 2 \n']
Note:
In the first example, both permutations of numbers {1, 2} yield maximum possible *f*(*p*) which is equal to 4. Among them, (2, 1) comes second in lexicographical order. | ```python
#!/usr/bin/python3
n, t = map(int, input().split())
A = [i + 1 for i in range(n)]
mx_sum = 0
for B in __import__("itertools").permutations(A):
s = 0
for i in range(n):
for j in range(i, n):
m = 10
for k in range(i, j + 1):
m = min(m, B[k])
s += m
mx_sum = max(mx_sum, s)
cnt = 0
for B in __import__("itertools").permutations(A):
s = 0
for i in range(n):
for j in range(i, n):
m = 10
for k in range(i, j + 1):
m = min(m, B[k])
s += m
if s == mx_sum:
cnt += 1
if cnt == t:
print(" ".join(map(str, B)))
exit(0)
``` | 0 | |
448 | D | Multiplication Table | PROGRAMMING | 1,800 | [
"binary search",
"brute force"
] | null | null | Bizon the Champion isn't just charming, he also is very smart.
While some of us were learning the multiplication table, Bizon the Champion had fun in his own manner. Bizon the Champion painted an *n*<=×<=*m* multiplication table, where the element on the intersection of the *i*-th row and *j*-th column equals *i*·*j* (the rows and columns of the table are numbered starting from 1). Then he was asked: what number in the table is the *k*-th largest number? Bizon the Champion always answered correctly and immediately. Can you repeat his success?
Consider the given multiplication table. If you write out all *n*·*m* numbers from the table in the non-decreasing order, then the *k*-th number you write out is called the *k*-th largest number. | The single line contains integers *n*, *m* and *k* (1<=≤<=*n*,<=*m*<=≤<=5·105; 1<=≤<=*k*<=≤<=*n*·*m*). | Print the *k*-th largest number in a *n*<=×<=*m* multiplication table. | [
"2 2 2\n",
"2 3 4\n",
"1 10 5\n"
] | [
"2\n",
"3\n",
"5\n"
] | A 2 × 3 multiplication table looks like this: | 2,000 | [
{
"input": "2 2 2",
"output": "2"
},
{
"input": "2 3 4",
"output": "3"
},
{
"input": "1 10 5",
"output": "5"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "10 1 7",
"output": "7"
},
{
"input": "10 10 33",
"output": "14"
},
{
"input": "... | 1,696,659,809 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 127 | 358 | 6,144,000 | import sys, threading
input = sys.stdin.readline
from collections import defaultdict
input = sys.stdin.readline
# returns the first number where key becomes true for a given delegate type key
def bs(low=1, high=1, key = lambda x: True):
while low <= high:
mid = (low + high)//2
if key(mid):
high = mid-1
else:
low = mid+1
return low
def good(x, n, m):
res = 0
x -= 1
for i in range(1, n + 1):
res += min(m, x // i)
return res
def main():
n,m, k = map(int, input().split())
low, high = 1, n * m + 1
print(bs(low, high, lambda x: good(x, n, m) >= k)-1)
main() | Title: Multiplication Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bizon the Champion isn't just charming, he also is very smart.
While some of us were learning the multiplication table, Bizon the Champion had fun in his own manner. Bizon the Champion painted an *n*<=×<=*m* multiplication table, where the element on the intersection of the *i*-th row and *j*-th column equals *i*·*j* (the rows and columns of the table are numbered starting from 1). Then he was asked: what number in the table is the *k*-th largest number? Bizon the Champion always answered correctly and immediately. Can you repeat his success?
Consider the given multiplication table. If you write out all *n*·*m* numbers from the table in the non-decreasing order, then the *k*-th number you write out is called the *k*-th largest number.
Input Specification:
The single line contains integers *n*, *m* and *k* (1<=≤<=*n*,<=*m*<=≤<=5·105; 1<=≤<=*k*<=≤<=*n*·*m*).
Output Specification:
Print the *k*-th largest number in a *n*<=×<=*m* multiplication table.
Demo Input:
['2 2 2\n', '2 3 4\n', '1 10 5\n']
Demo Output:
['2\n', '3\n', '5\n']
Note:
A 2 × 3 multiplication table looks like this: | ```python
import sys, threading
input = sys.stdin.readline
from collections import defaultdict
input = sys.stdin.readline
# returns the first number where key becomes true for a given delegate type key
def bs(low=1, high=1, key = lambda x: True):
while low <= high:
mid = (low + high)//2
if key(mid):
high = mid-1
else:
low = mid+1
return low
def good(x, n, m):
res = 0
x -= 1
for i in range(1, n + 1):
res += min(m, x // i)
return res
def main():
n,m, k = map(int, input().split())
low, high = 1, n * m + 1
print(bs(low, high, lambda x: good(x, n, m) >= k)-1)
main()
``` | 3 | |
116 | A | Tram | PROGRAMMING | 800 | [
"implementation"
] | null | null | Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it arrives at the first stop. Also, when the tram arrives at the last stop, all passengers exit so that it becomes empty.
Your task is to calculate the tram's minimum capacity such that the number of people inside the tram at any time never exceeds this capacity. Note that at each stop all exiting passengers exit before any entering passenger enters the tram. | The first line contains a single number *n* (2<=≤<=*n*<=≤<=1000) — the number of the tram's stops.
Then *n* lines follow, each contains two integers *a**i* and *b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the number of passengers that exits the tram at the *i*-th stop, and the number of passengers that enter the tram at the *i*-th stop. The stops are given from the first to the last stop in the order of tram's movement.
- The number of people who exit at a given stop does not exceed the total number of people in the tram immediately before it arrives at the stop. More formally, . This particularly means that *a*1<==<=0. - At the last stop, all the passengers exit the tram and it becomes empty. More formally, . - No passenger will enter the train at the last stop. That is, *b**n*<==<=0. | Print a single integer denoting the minimum possible capacity of the tram (0 is allowed). | [
"4\n0 3\n2 5\n4 2\n4 0\n"
] | [
"6\n"
] | For the first example, a capacity of 6 is sufficient:
- At the first stop, the number of passengers inside the tram before arriving is 0. Then, 3 passengers enter the tram, and the number of passengers inside the tram becomes 3. - At the second stop, 2 passengers exit the tram (1 passenger remains inside). Then, 5 passengers enter the tram. There are 6 passengers inside the tram now. - At the third stop, 4 passengers exit the tram (2 passengers remain inside). Then, 2 passengers enter the tram. There are 4 passengers inside the tram now. - Finally, all the remaining passengers inside the tram exit the tram at the last stop. There are no passenger inside the tram now, which is in line with the constraints.
Since the number of passengers inside the tram never exceeds 6, a capacity of 6 is sufficient. Furthermore it is not possible for the tram to have a capacity less than 6. Hence, 6 is the correct answer. | 500 | [
{
"input": "4\n0 3\n2 5\n4 2\n4 0",
"output": "6"
},
{
"input": "5\n0 4\n4 6\n6 5\n5 4\n4 0",
"output": "6"
},
{
"input": "10\n0 5\n1 7\n10 8\n5 3\n0 5\n3 3\n8 8\n0 6\n10 1\n9 0",
"output": "18"
},
{
"input": "3\n0 1\n1 1\n1 0",
"output": "1"
},
{
"input": "4\n0 1... | 1,692,171,701 | 2,147,483,647 | Python 3 | OK | TESTS | 71 | 92 | 0 | m = int(input())
n = 0
s = 0
while m:
a,b= map(int, input().split())
s=s+b-a
if s >n:
n = s
m=m-1
print(n) | Title: Tram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it arrives at the first stop. Also, when the tram arrives at the last stop, all passengers exit so that it becomes empty.
Your task is to calculate the tram's minimum capacity such that the number of people inside the tram at any time never exceeds this capacity. Note that at each stop all exiting passengers exit before any entering passenger enters the tram.
Input Specification:
The first line contains a single number *n* (2<=≤<=*n*<=≤<=1000) — the number of the tram's stops.
Then *n* lines follow, each contains two integers *a**i* and *b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the number of passengers that exits the tram at the *i*-th stop, and the number of passengers that enter the tram at the *i*-th stop. The stops are given from the first to the last stop in the order of tram's movement.
- The number of people who exit at a given stop does not exceed the total number of people in the tram immediately before it arrives at the stop. More formally, . This particularly means that *a*1<==<=0. - At the last stop, all the passengers exit the tram and it becomes empty. More formally, . - No passenger will enter the train at the last stop. That is, *b**n*<==<=0.
Output Specification:
Print a single integer denoting the minimum possible capacity of the tram (0 is allowed).
Demo Input:
['4\n0 3\n2 5\n4 2\n4 0\n']
Demo Output:
['6\n']
Note:
For the first example, a capacity of 6 is sufficient:
- At the first stop, the number of passengers inside the tram before arriving is 0. Then, 3 passengers enter the tram, and the number of passengers inside the tram becomes 3. - At the second stop, 2 passengers exit the tram (1 passenger remains inside). Then, 5 passengers enter the tram. There are 6 passengers inside the tram now. - At the third stop, 4 passengers exit the tram (2 passengers remain inside). Then, 2 passengers enter the tram. There are 4 passengers inside the tram now. - Finally, all the remaining passengers inside the tram exit the tram at the last stop. There are no passenger inside the tram now, which is in line with the constraints.
Since the number of passengers inside the tram never exceeds 6, a capacity of 6 is sufficient. Furthermore it is not possible for the tram to have a capacity less than 6. Hence, 6 is the correct answer. | ```python
m = int(input())
n = 0
s = 0
while m:
a,b= map(int, input().split())
s=s+b-a
if s >n:
n = s
m=m-1
print(n)
``` | 3 | |
461 | A | Appleman and Toastman | PROGRAMMING | 1,200 | [
"greedy",
"sortings"
] | null | null | Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman. - Each time Appleman gets a group consisting of a single number, he throws this group out. Each time Appleman gets a group consisting of more than one number, he splits the group into two non-empty groups (he can do it in any way) and gives each of them to Toastman.
After guys complete all the tasks they look at the score value. What is the maximum possible value of score they can get? | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=106) — the initial group that is given to Toastman. | Print a single integer — the largest possible score. | [
"3\n3 1 5\n",
"1\n10\n"
] | [
"26\n",
"10\n"
] | Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and gives the group to Appleman (he will throw it out). When Toastman receives group [3, 5], he adds 8 to the score and gives the group to Appleman. Appleman splits [3, 5] in the only possible way: [5] and [3]. Then he gives both groups to Toastman. When Toastman receives [5], he adds 5 to the score and gives the group to Appleman (he will throws it out). When Toastman receives [3], he adds 3 to the score and gives the group to Appleman (he will throws it out). Finally Toastman have added 9 + 1 + 8 + 5 + 3 = 26 to the score. This is the optimal sequence of actions. | 500 | [
{
"input": "3\n3 1 5",
"output": "26"
},
{
"input": "1\n10",
"output": "10"
},
{
"input": "10\n8 10 2 5 6 2 4 7 2 1",
"output": "376"
},
{
"input": "10\n171308 397870 724672 431255 228496 892002 542924 718337 888642 161821",
"output": "40204082"
},
{
"input": "10\... | 1,542,440,493 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 436 | 20,172,800 | def main():
n = int(input())
a = sorted([int(c) for c in input().split()])
s = sum(a)
mn = score = i = 0
while i < n:
score += s + mn
mn = a[i]
i += 1
s -= mn
print(score)
if __name__ == '__main__':
main()
| Title: Appleman and Toastman
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Appleman and Toastman play a game. Initially Appleman gives one group of *n* numbers to the Toastman, then they start to complete the following tasks:
- Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman. - Each time Appleman gets a group consisting of a single number, he throws this group out. Each time Appleman gets a group consisting of more than one number, he splits the group into two non-empty groups (he can do it in any way) and gives each of them to Toastman.
After guys complete all the tasks they look at the score value. What is the maximum possible value of score they can get?
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=3·105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=106) — the initial group that is given to Toastman.
Output Specification:
Print a single integer — the largest possible score.
Demo Input:
['3\n3 1 5\n', '1\n10\n']
Demo Output:
['26\n', '10\n']
Note:
Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and gives the group to Appleman (he will throw it out). When Toastman receives group [3, 5], he adds 8 to the score and gives the group to Appleman. Appleman splits [3, 5] in the only possible way: [5] and [3]. Then he gives both groups to Toastman. When Toastman receives [5], he adds 5 to the score and gives the group to Appleman (he will throws it out). When Toastman receives [3], he adds 3 to the score and gives the group to Appleman (he will throws it out). Finally Toastman have added 9 + 1 + 8 + 5 + 3 = 26 to the score. This is the optimal sequence of actions. | ```python
def main():
n = int(input())
a = sorted([int(c) for c in input().split()])
s = sum(a)
mn = score = i = 0
while i < n:
score += s + mn
mn = a[i]
i += 1
s -= mn
print(score)
if __name__ == '__main__':
main()
``` | 3 | |
742 | A | Arpa’s hard exam and Mehrdad’s naive cheat | PROGRAMMING | 1,000 | [
"implementation",
"math",
"number theory"
] | null | null | There exists an island called Arpa’s land, some beautiful girls live there, as ugly ones do.
Mehrdad wants to become minister of Arpa’s land. Arpa has prepared an exam. Exam has only one question, given *n*, print the last digit of 1378*n*.
Mehrdad has become quite confused and wants you to help him. Please help, although it's a naive cheat. | The single line of input contains one integer *n* (0<=<=≤<=<=*n*<=<=≤<=<=109). | Print single integer — the last digit of 1378*n*. | [
"1\n",
"2\n"
] | [
"8",
"4"
] | In the first example, last digit of 1378<sup class="upper-index">1</sup> = 1378 is 8.
In the second example, last digit of 1378<sup class="upper-index">2</sup> = 1378·1378 = 1898884 is 4. | 500 | [
{
"input": "1",
"output": "8"
},
{
"input": "2",
"output": "4"
},
{
"input": "1000",
"output": "6"
},
{
"input": "3",
"output": "2"
},
{
"input": "4",
"output": "6"
},
{
"input": "1000000000",
"output": "6"
},
{
"input": "5",
"output": ... | 1,692,516,089 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | n = int(input())
print(str(1378**(n%4))[-1]) | Title: Arpa’s hard exam and Mehrdad’s naive cheat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There exists an island called Arpa’s land, some beautiful girls live there, as ugly ones do.
Mehrdad wants to become minister of Arpa’s land. Arpa has prepared an exam. Exam has only one question, given *n*, print the last digit of 1378*n*.
Mehrdad has become quite confused and wants you to help him. Please help, although it's a naive cheat.
Input Specification:
The single line of input contains one integer *n* (0<=<=≤<=<=*n*<=<=≤<=<=109).
Output Specification:
Print single integer — the last digit of 1378*n*.
Demo Input:
['1\n', '2\n']
Demo Output:
['8', '4']
Note:
In the first example, last digit of 1378<sup class="upper-index">1</sup> = 1378 is 8.
In the second example, last digit of 1378<sup class="upper-index">2</sup> = 1378·1378 = 1898884 is 4. | ```python
n = int(input())
print(str(1378**(n%4))[-1])
``` | 0 | |
381 | A | Sereja and Dima | PROGRAMMING | 800 | [
"greedy",
"implementation",
"two pointers"
] | null | null | Sereja and Dima play a game. The rules of the game are very simple. The players have *n* cards in a row. Each card contains a number, all numbers on the cards are distinct. The players take turns, Sereja moves first. During his turn a player can take one card: either the leftmost card in a row, or the rightmost one. The game ends when there is no more cards. The player who has the maximum sum of numbers on his cards by the end of the game, wins.
Sereja and Dima are being greedy. Each of them chooses the card with the larger number during his move.
Inna is a friend of Sereja and Dima. She knows which strategy the guys are using, so she wants to determine the final score, given the initial state of the game. Help her. | The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of cards on the table. The second line contains space-separated numbers on the cards from left to right. The numbers on the cards are distinct integers from 1 to 1000. | On a single line, print two integers. The first number is the number of Sereja's points at the end of the game, the second number is the number of Dima's points at the end of the game. | [
"4\n4 1 2 10\n",
"7\n1 2 3 4 5 6 7\n"
] | [
"12 5\n",
"16 12\n"
] | In the first sample Sereja will take cards with numbers 10 and 2, so Sereja's sum is 12. Dima will take cards with numbers 4 and 1, so Dima's sum is 5. | 500 | [
{
"input": "4\n4 1 2 10",
"output": "12 5"
},
{
"input": "7\n1 2 3 4 5 6 7",
"output": "16 12"
},
{
"input": "42\n15 29 37 22 16 5 26 31 6 32 19 3 45 36 33 14 25 20 48 7 42 11 24 28 9 18 8 21 47 17 38 40 44 4 35 1 43 39 41 27 12 13",
"output": "613 418"
},
{
"input": "43\n32 ... | 1,680,188,424 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | n= int(input())
l=[]
for i in range (n) :
l.append(int(input()))
l.sort()
s=0
p=0
for i in range (0,n,2) :
s+=l[i]
for i in range (1,n,2) :
p+=l[i]
print(s)
print(p)
| Title: Sereja and Dima
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja and Dima play a game. The rules of the game are very simple. The players have *n* cards in a row. Each card contains a number, all numbers on the cards are distinct. The players take turns, Sereja moves first. During his turn a player can take one card: either the leftmost card in a row, or the rightmost one. The game ends when there is no more cards. The player who has the maximum sum of numbers on his cards by the end of the game, wins.
Sereja and Dima are being greedy. Each of them chooses the card with the larger number during his move.
Inna is a friend of Sereja and Dima. She knows which strategy the guys are using, so she wants to determine the final score, given the initial state of the game. Help her.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of cards on the table. The second line contains space-separated numbers on the cards from left to right. The numbers on the cards are distinct integers from 1 to 1000.
Output Specification:
On a single line, print two integers. The first number is the number of Sereja's points at the end of the game, the second number is the number of Dima's points at the end of the game.
Demo Input:
['4\n4 1 2 10\n', '7\n1 2 3 4 5 6 7\n']
Demo Output:
['12 5\n', '16 12\n']
Note:
In the first sample Sereja will take cards with numbers 10 and 2, so Sereja's sum is 12. Dima will take cards with numbers 4 and 1, so Dima's sum is 5. | ```python
n= int(input())
l=[]
for i in range (n) :
l.append(int(input()))
l.sort()
s=0
p=0
for i in range (0,n,2) :
s+=l[i]
for i in range (1,n,2) :
p+=l[i]
print(s)
print(p)
``` | -1 | |
508 | D | Tanya and Password | PROGRAMMING | 2,500 | [
"dfs and similar",
"graphs"
] | null | null | While dad was at work, a little girl Tanya decided to play with dad's password to his secret database. Dad's password is a string consisting of *n*<=+<=2 characters. She has written all the possible *n* three-letter continuous substrings of the password on pieces of paper, one for each piece of paper, and threw the password out. Each three-letter substring was written the number of times it occurred in the password. Thus, Tanya ended up with *n* pieces of paper.
Then Tanya realized that dad will be upset to learn about her game and decided to restore the password or at least any string corresponding to the final set of three-letter strings. You have to help her in this difficult task. We know that dad's password consisted of lowercase and uppercase letters of the Latin alphabet and digits. Uppercase and lowercase letters of the Latin alphabet are considered distinct. | The first line contains integer *n* (1<=≤<=*n*<=≤<=2·105), the number of three-letter substrings Tanya got.
Next *n* lines contain three letters each, forming the substring of dad's password. Each character in the input is a lowercase or uppercase Latin letter or a digit. | If Tanya made a mistake somewhere during the game and the strings that correspond to the given set of substrings don't exist, print "NO".
If it is possible to restore the string that corresponds to given set of substrings, print "YES", and then print any suitable password option. | [
"5\naca\naba\naba\ncab\nbac\n",
"4\nabc\nbCb\ncb1\nb13\n",
"7\naaa\naaa\naaa\naaa\naaa\naaa\naaa\n"
] | [
"YES\nabacaba\n",
"NO\n",
"YES\naaaaaaaaa\n"
] | none | 2,000 | [
{
"input": "5\naca\naba\naba\ncab\nbac",
"output": "YES\nabacaba"
},
{
"input": "4\nabc\nbCb\ncb1\nb13",
"output": "NO"
},
{
"input": "7\naaa\naaa\naaa\naaa\naaa\naaa\naaa",
"output": "YES\naaaaaaaaa"
},
{
"input": "1\nabc",
"output": "YES\nabc"
},
{
"input": "2\n... | 1,668,819,710 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 7 | 483 | 9,011,200 | from collections import Counter, defaultdict
c = Counter()
silbid = defaultdict(list)
len_words = int(input())
for _ in range(len_words):
word = input()
first_two, last_two = word[:2], word[-2:]
c[first_two] += 1
c[last_two] -= 1
silbid[first_two] += [last_two]
z, start = 0, None
answer = []
for _, ends in c.items():
if ends == -1:
z+=1
if z > 1:
print('NO')
exit()
if ends == 1:
start = _
if not start:
start = _
def rec(item):
while silbid[item]:
#print(1, item)
#print(2, silbid[item])
new = silbid[item].pop()
#print(3, new)
rec(new)
answer.insert(0, item)
#print(4, answer)
#print(c, silbid)
rec(start)
#print(answer)
for enum, item in enumerate(answer[1:], 1):
answer[enum] = item[1]
print('YES')
print(''.join(answer)) | Title: Tanya and Password
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
While dad was at work, a little girl Tanya decided to play with dad's password to his secret database. Dad's password is a string consisting of *n*<=+<=2 characters. She has written all the possible *n* three-letter continuous substrings of the password on pieces of paper, one for each piece of paper, and threw the password out. Each three-letter substring was written the number of times it occurred in the password. Thus, Tanya ended up with *n* pieces of paper.
Then Tanya realized that dad will be upset to learn about her game and decided to restore the password or at least any string corresponding to the final set of three-letter strings. You have to help her in this difficult task. We know that dad's password consisted of lowercase and uppercase letters of the Latin alphabet and digits. Uppercase and lowercase letters of the Latin alphabet are considered distinct.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=2·105), the number of three-letter substrings Tanya got.
Next *n* lines contain three letters each, forming the substring of dad's password. Each character in the input is a lowercase or uppercase Latin letter or a digit.
Output Specification:
If Tanya made a mistake somewhere during the game and the strings that correspond to the given set of substrings don't exist, print "NO".
If it is possible to restore the string that corresponds to given set of substrings, print "YES", and then print any suitable password option.
Demo Input:
['5\naca\naba\naba\ncab\nbac\n', '4\nabc\nbCb\ncb1\nb13\n', '7\naaa\naaa\naaa\naaa\naaa\naaa\naaa\n']
Demo Output:
['YES\nabacaba\n', 'NO\n', 'YES\naaaaaaaaa\n']
Note:
none | ```python
from collections import Counter, defaultdict
c = Counter()
silbid = defaultdict(list)
len_words = int(input())
for _ in range(len_words):
word = input()
first_two, last_two = word[:2], word[-2:]
c[first_two] += 1
c[last_two] -= 1
silbid[first_two] += [last_two]
z, start = 0, None
answer = []
for _, ends in c.items():
if ends == -1:
z+=1
if z > 1:
print('NO')
exit()
if ends == 1:
start = _
if not start:
start = _
def rec(item):
while silbid[item]:
#print(1, item)
#print(2, silbid[item])
new = silbid[item].pop()
#print(3, new)
rec(new)
answer.insert(0, item)
#print(4, answer)
#print(c, silbid)
rec(start)
#print(answer)
for enum, item in enumerate(answer[1:], 1):
answer[enum] = item[1]
print('YES')
print(''.join(answer))
``` | -1 | |
732 | A | Buy a Shovel | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"implementation",
"math"
] | null | null | Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<=≤<=*r*<=≤<=9).
What is the minimum number of shovels Polycarp has to buy so that he can pay for the purchase without any change? It is obvious that he can pay for 10 shovels without any change (by paying the requied amount of 10-burle coins and not using the coin of *r* burles). But perhaps he can buy fewer shovels and pay without any change. Note that Polycarp should buy at least one shovel. | The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has enough money to buy any number of shovels. | Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change. | [
"117 3\n",
"237 7\n",
"15 2\n"
] | [
"9\n",
"1\n",
"2\n"
] | In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels and pay 2·15 = 30 burles. It is obvious that he can pay this sum without any change. | 500 | [
{
"input": "117 3",
"output": "9"
},
{
"input": "237 7",
"output": "1"
},
{
"input": "15 2",
"output": "2"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 9",
"output": "9"
},
{
"input": "1000 3",
"output": "1"
},
{
"input": "1000 1",
... | 1,697,054,088 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | input_ = input().split()
k, r = int(input_[0]), int(input_[1])
n = 1
while True:
if k % 5 == 0:
break
if ((k%10)*n)%10 == r:
print(n)
break
n += 1 | Title: Buy a Shovel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp urgently needs a shovel! He comes to the shop and chooses an appropriate one. The shovel that Policarp chooses is sold for *k* burles. Assume that there is an unlimited number of such shovels in the shop.
In his pocket Polycarp has an unlimited number of "10-burle coins" and exactly one coin of *r* burles (1<=≤<=*r*<=≤<=9).
What is the minimum number of shovels Polycarp has to buy so that he can pay for the purchase without any change? It is obvious that he can pay for 10 shovels without any change (by paying the requied amount of 10-burle coins and not using the coin of *r* burles). But perhaps he can buy fewer shovels and pay without any change. Note that Polycarp should buy at least one shovel.
Input Specification:
The single line of input contains two integers *k* and *r* (1<=≤<=*k*<=≤<=1000, 1<=≤<=*r*<=≤<=9) — the price of one shovel and the denomination of the coin in Polycarp's pocket that is different from "10-burle coins".
Remember that he has an unlimited number of coins in the denomination of 10, that is, Polycarp has enough money to buy any number of shovels.
Output Specification:
Print the required minimum number of shovels Polycarp has to buy so that he can pay for them without any change.
Demo Input:
['117 3\n', '237 7\n', '15 2\n']
Demo Output:
['9\n', '1\n', '2\n']
Note:
In the first example Polycarp can buy 9 shovels and pay 9·117 = 1053 burles. Indeed, he can pay this sum by using 10-burle coins and one 3-burle coin. He can't buy fewer shovels without any change.
In the second example it is enough for Polycarp to buy one shovel.
In the third example Polycarp should buy two shovels and pay 2·15 = 30 burles. It is obvious that he can pay this sum without any change. | ```python
input_ = input().split()
k, r = int(input_[0]), int(input_[1])
n = 1
while True:
if k % 5 == 0:
break
if ((k%10)*n)%10 == r:
print(n)
break
n += 1
``` | 0 |
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