contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
350 | A | TL | PROGRAMMING | 1,200 | [
"brute force",
"greedy",
"implementation"
] | null | null | Valera wanted to prepare a Codesecrof round. He's already got one problem and he wants to set a time limit (TL) on it.
Valera has written *n* correct solutions. For each correct solution, he knows its running time (in seconds). Valera has also wrote *m* wrong solutions and for each wrong solution he knows its running time (in seconds).
Let's suppose that Valera will set *v* seconds TL in the problem. Then we can say that a solution passes the system testing if its running time is at most *v* seconds. We can also say that a solution passes the system testing with some "extra" time if for its running time, *a* seconds, an inequality 2*a*<=≤<=*v* holds.
As a result, Valera decided to set *v* seconds TL, that the following conditions are met:
1. *v* is a positive integer; 1. all correct solutions pass the system testing; 1. at least one correct solution passes the system testing with some "extra" time; 1. all wrong solutions do not pass the system testing; 1. value *v* is minimum among all TLs, for which points 1, 2, 3, 4 hold.
Help Valera and find the most suitable TL or else state that such TL doesn't exist. | The first line contains two integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100). The second line contains *n* space-separated positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100) — the running time of each of the *n* correct solutions in seconds. The third line contains *m* space-separated positive integers *b*1,<=*b*2,<=...,<=*b**m* (1<=≤<=*b**i*<=≤<=100) — the running time of each of *m* wrong solutions in seconds. | If there is a valid TL value, print it. Otherwise, print -1. | [
"3 6\n4 5 2\n8 9 6 10 7 11\n",
"3 1\n3 4 5\n6\n"
] | [
"5",
"-1\n"
] | none | 500 | [
{
"input": "3 6\n4 5 2\n8 9 6 10 7 11",
"output": "5"
},
{
"input": "3 1\n3 4 5\n6",
"output": "-1"
},
{
"input": "2 5\n45 99\n49 41 77 83 45",
"output": "-1"
},
{
"input": "50 50\n18 13 5 34 10 36 36 12 15 11 16 17 14 36 23 45 32 24 31 18 24 32 7 1 31 3 49 8 16 23 3 39 47 43... | 1,618,272,560 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 122 | 0 | p,f = map(int,input().split())
tl = 0
lp = [int(x) for x in input().split()]
lf = [int(x) for x in input().split()]
ma = max(lp)
if min(lf) <= ma:
tl = -1
else:
if min(lp)*2 <= ma:
if min(lf) > ma:
tl = ma
else:
tl = -1
print(tl) | Title: TL
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera wanted to prepare a Codesecrof round. He's already got one problem and he wants to set a time limit (TL) on it.
Valera has written *n* correct solutions. For each correct solution, he knows its running time (in seconds). Valera has also wrote *m* wrong solutions and for each wrong solution he knows its running time (in seconds).
Let's suppose that Valera will set *v* seconds TL in the problem. Then we can say that a solution passes the system testing if its running time is at most *v* seconds. We can also say that a solution passes the system testing with some "extra" time if for its running time, *a* seconds, an inequality 2*a*<=≤<=*v* holds.
As a result, Valera decided to set *v* seconds TL, that the following conditions are met:
1. *v* is a positive integer; 1. all correct solutions pass the system testing; 1. at least one correct solution passes the system testing with some "extra" time; 1. all wrong solutions do not pass the system testing; 1. value *v* is minimum among all TLs, for which points 1, 2, 3, 4 hold.
Help Valera and find the most suitable TL or else state that such TL doesn't exist.
Input Specification:
The first line contains two integers *n*, *m* (1<=≤<=*n*,<=*m*<=≤<=100). The second line contains *n* space-separated positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100) — the running time of each of the *n* correct solutions in seconds. The third line contains *m* space-separated positive integers *b*1,<=*b*2,<=...,<=*b**m* (1<=≤<=*b**i*<=≤<=100) — the running time of each of *m* wrong solutions in seconds.
Output Specification:
If there is a valid TL value, print it. Otherwise, print -1.
Demo Input:
['3 6\n4 5 2\n8 9 6 10 7 11\n', '3 1\n3 4 5\n6\n']
Demo Output:
['5', '-1\n']
Note:
none | ```python
p,f = map(int,input().split())
tl = 0
lp = [int(x) for x in input().split()]
lf = [int(x) for x in input().split()]
ma = max(lp)
if min(lf) <= ma:
tl = -1
else:
if min(lp)*2 <= ma:
if min(lf) > ma:
tl = ma
else:
tl = -1
print(tl)
``` | 0 | |
977 | A | Wrong Subtraction | PROGRAMMING | 800 | [
"implementation"
] | null | null | Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm:
- if the last digit of the number is non-zero, she decreases the number by one; - if the last digit of the number is zero, she divides the number by 10 (i.e. removes the last digit).
You are given an integer number $n$. Tanya will subtract one from it $k$ times. Your task is to print the result after all $k$ subtractions.
It is guaranteed that the result will be positive integer number. | The first line of the input contains two integer numbers $n$ and $k$ ($2 \le n \le 10^9$, $1 \le k \le 50$) — the number from which Tanya will subtract and the number of subtractions correspondingly. | Print one integer number — the result of the decreasing $n$ by one $k$ times.
It is guaranteed that the result will be positive integer number. | [
"512 4\n",
"1000000000 9\n"
] | [
"50\n",
"1\n"
] | The first example corresponds to the following sequence: $512 \rightarrow 511 \rightarrow 510 \rightarrow 51 \rightarrow 50$. | 0 | [
{
"input": "512 4",
"output": "50"
},
{
"input": "1000000000 9",
"output": "1"
},
{
"input": "131203 11",
"output": "12"
},
{
"input": "999999999 50",
"output": "9999"
},
{
"input": "999999999 49",
"output": "99990"
},
{
"input": "131203 9",
"outpu... | 1,695,483,640 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 30 | 0 | first_line=input().split()
for i in range(int(first_line[1])):
if int(first_line[0])%10==0:
first_line[0]=int(first_line[0])/10
else:
first_line[0] =int(first_line[0])-1
print(first_line[0]) | Title: Wrong Subtraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm:
- if the last digit of the number is non-zero, she decreases the number by one; - if the last digit of the number is zero, she divides the number by 10 (i.e. removes the last digit).
You are given an integer number $n$. Tanya will subtract one from it $k$ times. Your task is to print the result after all $k$ subtractions.
It is guaranteed that the result will be positive integer number.
Input Specification:
The first line of the input contains two integer numbers $n$ and $k$ ($2 \le n \le 10^9$, $1 \le k \le 50$) — the number from which Tanya will subtract and the number of subtractions correspondingly.
Output Specification:
Print one integer number — the result of the decreasing $n$ by one $k$ times.
It is guaranteed that the result will be positive integer number.
Demo Input:
['512 4\n', '1000000000 9\n']
Demo Output:
['50\n', '1\n']
Note:
The first example corresponds to the following sequence: $512 \rightarrow 511 \rightarrow 510 \rightarrow 51 \rightarrow 50$. | ```python
first_line=input().split()
for i in range(int(first_line[1])):
if int(first_line[0])%10==0:
first_line[0]=int(first_line[0])/10
else:
first_line[0] =int(first_line[0])-1
print(first_line[0])
``` | 0 | |
460 | A | Vasya and Socks | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it late in the evening, so that Vasya cannot put on a new pair of socks before the next day. How many consecutive days pass until Vasya runs out of socks? | The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space. | Print a single integer — the answer to the problem. | [
"2 2\n",
"9 3\n"
] | [
"3\n",
"13\n"
] | In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on the third, sixth and ninth days. Than he spends another day wearing the socks that were bought on the twelfth day. | 500 | [
{
"input": "2 2",
"output": "3"
},
{
"input": "9 3",
"output": "13"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 3",
"output": "2"
},
{
"input": "1 99",
"output": "1"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "10 2",
"outp... | 1,696,065,323 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 77 | 2,150,400 | socks, day_bought = map(int, input().split())
total_wear = socks
total_wear = total_wear + socks//day_bought
total_wear = total_wear + total//socks//day_bought
print(total_wear) | Title: Vasya and Socks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it late in the evening, so that Vasya cannot put on a new pair of socks before the next day. How many consecutive days pass until Vasya runs out of socks?
Input Specification:
The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space.
Output Specification:
Print a single integer — the answer to the problem.
Demo Input:
['2 2\n', '9 3\n']
Demo Output:
['3\n', '13\n']
Note:
In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on the third, sixth and ninth days. Than he spends another day wearing the socks that were bought on the twelfth day. | ```python
socks, day_bought = map(int, input().split())
total_wear = socks
total_wear = total_wear + socks//day_bought
total_wear = total_wear + total//socks//day_bought
print(total_wear)
``` | -1 | |
545 | D | Queue | PROGRAMMING | 1,300 | [
"greedy",
"implementation",
"sortings"
] | null | null | Little girl Susie went shopping with her mom and she wondered how to improve service quality.
There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time he waits is more than the time needed to serve him. The time a person waits is the total time when all the people who stand in the queue in front of him are served. Susie thought that if we swap some people in the queue, then we can decrease the number of people who are disappointed.
Help Susie find out what is the maximum number of not disappointed people can be achieved by swapping people in the queue. | The first line contains integer *n* (1<=≤<=*n*<=≤<=105).
The next line contains *n* integers *t**i* (1<=≤<=*t**i*<=≤<=109), separated by spaces. | Print a single number — the maximum number of not disappointed people in the queue. | [
"5\n15 2 1 5 3\n"
] | [
"4\n"
] | Value 4 is achieved at such an arrangement, for example: 1, 2, 3, 5, 15. Thus, you can make everything feel not disappointed except for the person with time 5. | 1,750 | [
{
"input": "5\n15 2 1 5 3",
"output": "4"
},
{
"input": "15\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1",
"output": "2"
},
{
"input": "10\n13 2 5 55 21 34 1 8 1 3",
"output": "6"
},
{
"input": "10\n8 256 16 1 2 1 64 4 128 32",
"output": "10"
},
{
"input": "10\n10000 40000 1000... | 1,697,890,732 | 2,147,483,647 | Python 3 | OK | TESTS | 61 | 93 | 14,233,600 | s=t=0
for i in sorted(map(int,[*open(0)][1].split())):
if i>=s:t+=1;s+=i
print(t) | Title: Queue
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little girl Susie went shopping with her mom and she wondered how to improve service quality.
There are *n* people in the queue. For each person we know time *t**i* needed to serve him. A person will be disappointed if the time he waits is more than the time needed to serve him. The time a person waits is the total time when all the people who stand in the queue in front of him are served. Susie thought that if we swap some people in the queue, then we can decrease the number of people who are disappointed.
Help Susie find out what is the maximum number of not disappointed people can be achieved by swapping people in the queue.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=105).
The next line contains *n* integers *t**i* (1<=≤<=*t**i*<=≤<=109), separated by spaces.
Output Specification:
Print a single number — the maximum number of not disappointed people in the queue.
Demo Input:
['5\n15 2 1 5 3\n']
Demo Output:
['4\n']
Note:
Value 4 is achieved at such an arrangement, for example: 1, 2, 3, 5, 15. Thus, you can make everything feel not disappointed except for the person with time 5. | ```python
s=t=0
for i in sorted(map(int,[*open(0)][1].split())):
if i>=s:t+=1;s+=i
print(t)
``` | 3 | |
355 | A | Vasya and Digital Root | PROGRAMMING | 1,100 | [
"constructive algorithms",
"implementation"
] | null | null | Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that *S*(*n*) is the sum of digits of number *n*, for example, *S*(4098)<==<=4<=+<=0<=+<=9<=+<=8<==<=21. Then the digital root of number *n* equals to:
1. *dr*(*n*)<==<=*S*(*n*), if *S*(*n*)<=<<=10; 1. *dr*(*n*)<==<=*dr*(<=*S*(*n*)<=), if *S*(*n*)<=≥<=10.
For example, *dr*(4098)<=<==<=<=*dr*(21)<=<==<=<=3.
Vasya is afraid of large numbers, so the numbers he works with are at most 101000. For all such numbers, he has proved that *dr*(*n*)<=<==<=<=*S*(<=*S*(<=*S*(<=*S*(*n*)<=)<=)<=) (*n*<=≤<=101000).
Now Vasya wants to quickly find numbers with the given digital root. The problem is, he hasn't learned how to do that and he asked you to help him. You task is, given numbers *k* and *d*, find the number consisting of exactly *k* digits (the leading zeroes are not allowed), with digital root equal to *d*, or else state that such number does not exist. | The first line contains two integers *k* and *d* (1<=≤<=*k*<=≤<=1000; 0<=≤<=*d*<=≤<=9). | In a single line print either any number that meets the requirements (without the leading zeroes) or "No solution" (without the quotes), if the corresponding number does not exist.
The chosen number must consist of exactly *k* digits. We assume that number 0 doesn't contain any leading zeroes. | [
"4 4\n",
"5 1\n",
"1 0\n"
] | [
"5881\n",
"36172\n",
"0\n"
] | For the first test sample *dr*(5881) = *dr*(22) = 4.
For the second test sample *dr*(36172) = *dr*(19) = *dr*(10) = 1. | 500 | [
{
"input": "4 4",
"output": "5881"
},
{
"input": "5 1",
"output": "36172"
},
{
"input": "1 0",
"output": "0"
},
{
"input": "8 7",
"output": "49722154"
},
{
"input": "487 0",
"output": "No solution"
},
{
"input": "1000 5",
"output": "854193955406789... | 1,690,339,736 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 31 | 0 | k,d=map(int,input().split(' '))
if (d==0 and k>1):
print('No solution')
else:
print(str(d)+(k-1)*"0") | Title: Vasya and Digital Root
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that *S*(*n*) is the sum of digits of number *n*, for example, *S*(4098)<==<=4<=+<=0<=+<=9<=+<=8<==<=21. Then the digital root of number *n* equals to:
1. *dr*(*n*)<==<=*S*(*n*), if *S*(*n*)<=<<=10; 1. *dr*(*n*)<==<=*dr*(<=*S*(*n*)<=), if *S*(*n*)<=≥<=10.
For example, *dr*(4098)<=<==<=<=*dr*(21)<=<==<=<=3.
Vasya is afraid of large numbers, so the numbers he works with are at most 101000. For all such numbers, he has proved that *dr*(*n*)<=<==<=<=*S*(<=*S*(<=*S*(<=*S*(*n*)<=)<=)<=) (*n*<=≤<=101000).
Now Vasya wants to quickly find numbers with the given digital root. The problem is, he hasn't learned how to do that and he asked you to help him. You task is, given numbers *k* and *d*, find the number consisting of exactly *k* digits (the leading zeroes are not allowed), with digital root equal to *d*, or else state that such number does not exist.
Input Specification:
The first line contains two integers *k* and *d* (1<=≤<=*k*<=≤<=1000; 0<=≤<=*d*<=≤<=9).
Output Specification:
In a single line print either any number that meets the requirements (without the leading zeroes) or "No solution" (without the quotes), if the corresponding number does not exist.
The chosen number must consist of exactly *k* digits. We assume that number 0 doesn't contain any leading zeroes.
Demo Input:
['4 4\n', '5 1\n', '1 0\n']
Demo Output:
['5881\n', '36172\n', '0\n']
Note:
For the first test sample *dr*(5881) = *dr*(22) = 4.
For the second test sample *dr*(36172) = *dr*(19) = *dr*(10) = 1. | ```python
k,d=map(int,input().split(' '))
if (d==0 and k>1):
print('No solution')
else:
print(str(d)+(k-1)*"0")
``` | 3 | |
764 | A | Taymyr is calling you | PROGRAMMING | 800 | [
"brute force",
"implementation",
"math"
] | null | null | Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists come to the comrade every *m* minutes, i.e. in minutes *m*, 2*m*, 3*m* and so on. The day is *z* minutes long, i.e. the day consists of minutes 1,<=2,<=...,<=*z*. How many artists should be killed so that there are no artists in the room when Ilia calls? Consider that a call and a talk with an artist take exactly one minute. | The only string contains three integers — *n*, *m* and *z* (1<=≤<=*n*,<=*m*,<=*z*<=≤<=104). | Print single integer — the minimum number of artists that should be killed so that there are no artists in the room when Ilia calls. | [
"1 1 10\n",
"1 2 5\n",
"2 3 9\n"
] | [
"10\n",
"2\n",
"1\n"
] | Taymyr is a place in the north of Russia.
In the first test the artists come each minute, as well as the calls, so we need to kill all of them.
In the second test we need to kill artists which come on the second and the fourth minutes.
In the third test — only the artist which comes on the sixth minute. | 500 | [
{
"input": "1 1 10",
"output": "10"
},
{
"input": "1 2 5",
"output": "2"
},
{
"input": "2 3 9",
"output": "1"
},
{
"input": "4 8 9",
"output": "1"
},
{
"input": "7 9 2",
"output": "0"
},
{
"input": "10000 10000 10000",
"output": "1"
},
{
"i... | 1,590,645,840 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 93 | 0 |
n = int(input())
home = input()
flights = []
while n > 0:
s, t = input().split("->")
flights.append(s)
flights.append(t)
n -= 1
count = 0
for flight in flights:
if flight == home:
count += 1
if count % 2 == 0:
print("home")
else:
print("contest") | Title: Taymyr is calling you
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Comrade Dujikov is busy choosing artists for Timofey's birthday and is recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every *n* minutes, i.e. in minutes *n*, 2*n*, 3*n* and so on. Artists come to the comrade every *m* minutes, i.e. in minutes *m*, 2*m*, 3*m* and so on. The day is *z* minutes long, i.e. the day consists of minutes 1,<=2,<=...,<=*z*. How many artists should be killed so that there are no artists in the room when Ilia calls? Consider that a call and a talk with an artist take exactly one minute.
Input Specification:
The only string contains three integers — *n*, *m* and *z* (1<=≤<=*n*,<=*m*,<=*z*<=≤<=104).
Output Specification:
Print single integer — the minimum number of artists that should be killed so that there are no artists in the room when Ilia calls.
Demo Input:
['1 1 10\n', '1 2 5\n', '2 3 9\n']
Demo Output:
['10\n', '2\n', '1\n']
Note:
Taymyr is a place in the north of Russia.
In the first test the artists come each minute, as well as the calls, so we need to kill all of them.
In the second test we need to kill artists which come on the second and the fourth minutes.
In the third test — only the artist which comes on the sixth minute. | ```python
n = int(input())
home = input()
flights = []
while n > 0:
s, t = input().split("->")
flights.append(s)
flights.append(t)
n -= 1
count = 0
for flight in flights:
if flight == home:
count += 1
if count % 2 == 0:
print("home")
else:
print("contest")
``` | -1 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*. | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,667,285,886 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 46 | 0 | a = str(input())
helo = ['h','e','l','l','o']
i = -1
for c in helo:
i = a.find(c, i+1)
if i == -1:
print('NO')
exit()
print('YES') | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*.
Input Specification:
The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters.
Output Specification:
If Vasya managed to say hello, print "YES", otherwise print "NO".
Demo Input:
['ahhellllloou\n', 'hlelo\n']
Demo Output:
['YES\n', 'NO\n']
Note:
none | ```python
a = str(input())
helo = ['h','e','l','l','o']
i = -1
for c in helo:
i = a.find(c, i+1)
if i == -1:
print('NO')
exit()
print('YES')
``` | 3.977 |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions. | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,666,775,048 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | n = int(input())
m = int(input())
print(n * m / 2) | Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions.
Input Specification:
In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16).
Output Specification:
Output one number — the maximal number of dominoes, which can be placed.
Demo Input:
['2 4\n', '3 3\n']
Demo Output:
['4\n', '4\n']
Note:
none | ```python
n = int(input())
m = int(input())
print(n * m / 2)
``` | -1 |
579 | A | Raising Bacteria | PROGRAMMING | 1,000 | [
"bitmasks"
] | null | null | You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the minimum number of bacteria you need to put into the box across those days? | The only line containing one integer *x* (1<=≤<=*x*<=≤<=109). | The only line containing one integer: the answer. | [
"5\n",
"8\n"
] | [
"2\n",
"1\n"
] | For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th morning there will be 8 in the box. So the answer is 1. | 250 | [
{
"input": "5",
"output": "2"
},
{
"input": "8",
"output": "1"
},
{
"input": "536870911",
"output": "29"
},
{
"input": "1",
"output": "1"
},
{
"input": "343000816",
"output": "14"
},
{
"input": "559980448",
"output": "12"
},
{
"input": "697... | 1,679,720,745 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | b = int(input())
x = 1
while x <= b :
x *= 2
x /= 2
print(int((b-x)+1)) | Title: Raising Bacteria
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are a lover of bacteria. You want to raise some bacteria in a box.
Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to see exactly *x* bacteria in the box at some moment.
What is the minimum number of bacteria you need to put into the box across those days?
Input Specification:
The only line containing one integer *x* (1<=≤<=*x*<=≤<=109).
Output Specification:
The only line containing one integer: the answer.
Demo Input:
['5\n', '8\n']
Demo Output:
['2\n', '1\n']
Note:
For the first sample, we can add one bacterium in the box in the first day morning and at the third morning there will be 4 bacteria in the box. Now we put one more resulting 5 in the box. We added 2 bacteria in the process so the answer is 2.
For the second sample, we can put one in the first morning and in the 4-th morning there will be 8 in the box. So the answer is 1. | ```python
b = int(input())
x = 1
while x <= b :
x *= 2
x /= 2
print(int((b-x)+1))
``` | 0 | |
71 | A | Way Too Long Words | PROGRAMMING | 800 | [
"strings"
] | A. Way Too Long Words | 1 | 256 | Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made like this: we write down the first and the last letter of a word and between them we write the number of letters between the first and the last letters. That number is in decimal system and doesn't contain any leading zeroes.
Thus, "localization" will be spelt as "l10n", and "internationalization» will be spelt as "i18n".
You are suggested to automatize the process of changing the words with abbreviations. At that all too long words should be replaced by the abbreviation and the words that are not too long should not undergo any changes. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters. | Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data. | [
"4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n"
] | [
"word\nl10n\ni18n\np43s\n"
] | none | 500 | [
{
"input": "4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis",
"output": "word\nl10n\ni18n\np43s"
},
{
"input": "5\nabcdefgh\nabcdefghi\nabcdefghij\nabcdefghijk\nabcdefghijklm",
"output": "abcdefgh\nabcdefghi\nabcdefghij\na9k\na11m"
},
{
"input":... | 1,693,791,384 | 2,147,483,647 | Python 3 | OK | TESTS | 20 | 46 | 0 | numero = int(input())
for _ in range(numero):
palabra = input() # Lee una palabra
if len(palabra) > 10:
abbreviation = palabra[0] + str(len(palabra) - 2) + palabra[-1]
print(abbreviation)
else:
print(palabra)
| Title: Way Too Long Words
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Sometimes some words like "localization" or "internationalization" are so long that writing them many times in one text is quite tiresome.
Let's consider a word too long, if its length is strictly more than 10 characters. All too long words should be replaced with a special abbreviation.
This abbreviation is made like this: we write down the first and the last letter of a word and between them we write the number of letters between the first and the last letters. That number is in decimal system and doesn't contain any leading zeroes.
Thus, "localization" will be spelt as "l10n", and "internationalization» will be spelt as "i18n".
You are suggested to automatize the process of changing the words with abbreviations. At that all too long words should be replaced by the abbreviation and the words that are not too long should not undergo any changes.
Input Specification:
The first line contains an integer *n* (1<=≤<=*n*<=≤<=100). Each of the following *n* lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters.
Output Specification:
Print *n* lines. The *i*-th line should contain the result of replacing of the *i*-th word from the input data.
Demo Input:
['4\nword\nlocalization\ninternationalization\npneumonoultramicroscopicsilicovolcanoconiosis\n']
Demo Output:
['word\nl10n\ni18n\np43s\n']
Note:
none | ```python
numero = int(input())
for _ in range(numero):
palabra = input() # Lee una palabra
if len(palabra) > 10:
abbreviation = palabra[0] + str(len(palabra) - 2) + palabra[-1]
print(abbreviation)
else:
print(palabra)
``` | 3.977 |
152 | C | Pocket Book | PROGRAMMING | 1,400 | [
"combinatorics"
] | null | null | One day little Vasya found mom's pocket book. The book had *n* names of her friends and unusually enough, each name was exactly *m* letters long. Let's number the names from 1 to *n* in the order in which they are written.
As mom wasn't home, Vasya decided to play with names: he chose three integers *i*, *j*, *k* (1<=≤<=*i*<=<<=*j*<=≤<=*n*, 1<=≤<=*k*<=≤<=*m*), then he took names number *i* and *j* and swapped their prefixes of length *k*. For example, if we take names "CBDAD" and "AABRD" and swap their prefixes with the length of 3, the result will be names "AABAD" and "CBDRD".
You wonder how many different names Vasya can write instead of name number 1, if Vasya is allowed to perform any number of the described actions. As Vasya performs each action, he chooses numbers *i*, *j*, *k* independently from the previous moves and his choice is based entirely on his will. The sought number can be very large, so you should only find it modulo 1000000007 (109<=+<=7). | The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of names and the length of each name, correspondingly. Then *n* lines contain names, each name consists of exactly *m* uppercase Latin letters. | Print the single number — the number of different names that could end up in position number 1 in the pocket book after the applying the procedures described above. Print the number modulo 1000000007 (109<=+<=7). | [
"2 3\nAAB\nBAA\n",
"4 5\nABABA\nBCGDG\nAAAAA\nYABSA\n"
] | [
"4\n",
"216\n"
] | In the first sample Vasya can get the following names in the position number 1: "AAB", "AAA", "BAA" and "BAB". | 1,500 | [
{
"input": "2 3\nAAB\nBAA",
"output": "4"
},
{
"input": "4 5\nABABA\nBCGDG\nAAAAA\nYABSA",
"output": "216"
},
{
"input": "1 1\nE",
"output": "1"
},
{
"input": "2 2\nNS\nPD",
"output": "4"
},
{
"input": "3 4\nPJKD\nNFJX\nFGFK",
"output": "81"
},
{
"inpu... | 1,627,875,836 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 122 | 6,963,200 | n,m=list(map(int,input().split()))
l=[]
for i in range(n):
l.append(input())
ans=1
for j in range(m):
d={}
c=0
for i in range(n):
d[l[i][j]]=d.get(l[i][j],0)+1
if d[l[i][j]]==1:
c=c+1
ans=ans*c
print(ans%(10**9+5))
| Title: Pocket Book
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day little Vasya found mom's pocket book. The book had *n* names of her friends and unusually enough, each name was exactly *m* letters long. Let's number the names from 1 to *n* in the order in which they are written.
As mom wasn't home, Vasya decided to play with names: he chose three integers *i*, *j*, *k* (1<=≤<=*i*<=<<=*j*<=≤<=*n*, 1<=≤<=*k*<=≤<=*m*), then he took names number *i* and *j* and swapped their prefixes of length *k*. For example, if we take names "CBDAD" and "AABRD" and swap their prefixes with the length of 3, the result will be names "AABAD" and "CBDRD".
You wonder how many different names Vasya can write instead of name number 1, if Vasya is allowed to perform any number of the described actions. As Vasya performs each action, he chooses numbers *i*, *j*, *k* independently from the previous moves and his choice is based entirely on his will. The sought number can be very large, so you should only find it modulo 1000000007 (109<=+<=7).
Input Specification:
The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of names and the length of each name, correspondingly. Then *n* lines contain names, each name consists of exactly *m* uppercase Latin letters.
Output Specification:
Print the single number — the number of different names that could end up in position number 1 in the pocket book after the applying the procedures described above. Print the number modulo 1000000007 (109<=+<=7).
Demo Input:
['2 3\nAAB\nBAA\n', '4 5\nABABA\nBCGDG\nAAAAA\nYABSA\n']
Demo Output:
['4\n', '216\n']
Note:
In the first sample Vasya can get the following names in the position number 1: "AAB", "AAA", "BAA" and "BAB". | ```python
n,m=list(map(int,input().split()))
l=[]
for i in range(n):
l.append(input())
ans=1
for j in range(m):
d={}
c=0
for i in range(n):
d[l[i][j]]=d.get(l[i][j],0)+1
if d[l[i][j]]==1:
c=c+1
ans=ans*c
print(ans%(10**9+5))
``` | 0 | |
43 | A | Football | PROGRAMMING | 1,000 | [
"strings"
] | A. Football | 2 | 256 | One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process. On the whole there are *n* lines in that description each of which described one goal. Every goal was marked with the name of the team that had scored it. Help Vasya, learn the name of the team that won the finals. It is guaranteed that the match did not end in a tie. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the description. Then follow *n* lines — for each goal the names of the teams that scored it. The names are non-empty lines consisting of uppercase Latin letters whose lengths do not exceed 10 symbols. It is guaranteed that the match did not end in a tie and the description contains no more than two different teams. | Print the name of the winning team. We remind you that in football the team that scores more goals is considered the winner. | [
"1\nABC\n",
"5\nA\nABA\nABA\nA\nA\n"
] | [
"ABC\n",
"A\n"
] | none | 500 | [
{
"input": "1\nABC",
"output": "ABC"
},
{
"input": "5\nA\nABA\nABA\nA\nA",
"output": "A"
},
{
"input": "2\nXTSJEP\nXTSJEP",
"output": "XTSJEP"
},
{
"input": "3\nXZYDJAEDZ\nXZYDJAEDZ\nXZYDJAEDZ",
"output": "XZYDJAEDZ"
},
{
"input": "3\nQCCYXL\nQCCYXL\nAXGLFQDD",
... | 1,606,058,793 | 2,147,483,647 | PyPy 3 | OK | TESTS | 34 | 280 | 0 | n=int(input())
report=[]
for _ in range(n):
report.append(input())
zero=0
for team in report:
if team==report[0]:
zero+=1
if team!=report[0]:
other=team
if zero>n-zero:
print(report[0])
else:
print(other) | Title: Football
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process. On the whole there are *n* lines in that description each of which described one goal. Every goal was marked with the name of the team that had scored it. Help Vasya, learn the name of the team that won the finals. It is guaranteed that the match did not end in a tie.
Input Specification:
The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the description. Then follow *n* lines — for each goal the names of the teams that scored it. The names are non-empty lines consisting of uppercase Latin letters whose lengths do not exceed 10 symbols. It is guaranteed that the match did not end in a tie and the description contains no more than two different teams.
Output Specification:
Print the name of the winning team. We remind you that in football the team that scores more goals is considered the winner.
Demo Input:
['1\nABC\n', '5\nA\nABA\nABA\nA\nA\n']
Demo Output:
['ABC\n', 'A\n']
Note:
none | ```python
n=int(input())
report=[]
for _ in range(n):
report.append(input())
zero=0
for team in report:
if team==report[0]:
zero+=1
if team!=report[0]:
other=team
if zero>n-zero:
print(report[0])
else:
print(other)
``` | 3.93 |
368 | B | Sereja and Suffixes | PROGRAMMING | 1,100 | [
"data structures",
"dp"
] | null | null | Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*). For each number *l**i* he wants to know how many distinct numbers are staying on the positions *l**i*, *l**i*<=+<=1, ..., *n*. Formally, he want to find the number of distinct numbers among *a**l**i*,<=*a**l**i*<=+<=1,<=...,<=*a**n*.?
Sereja wrote out the necessary array elements but the array was so large and the boy was so pressed for time. Help him, find the answer for the described question for each *l**i*. | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105) — the array elements.
Next *m* lines contain integers *l*1,<=*l*2,<=...,<=*l**m*. The *i*-th line contains integer *l**i* (1<=≤<=*l**i*<=≤<=*n*). | Print *m* lines — on the *i*-th line print the answer to the number *l**i*. | [
"10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n"
] | [
"6\n6\n6\n6\n6\n5\n4\n3\n2\n1\n"
] | none | 1,000 | [
{
"input": "10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "6\n6\n6\n6\n6\n5\n4\n3\n2\n1"
},
{
"input": "8 3\n8 6 4 3 4 2 4 8\n6\n4\n2",
"output": "3\n4\n5"
},
{
"input": "7 10\n1 3 8 6 2 2 7\n4\n2\n6\n3\n4\n4\n6\n2\n7\n4",
"output": "3\n5\n2\n4\n3\n3\... | 1,698,740,263 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 1,000 | 10,649,600 | n,m=map(int,input().split())
a=list(map(int,input().split()))
def control(l):
num=l-1
ls=a[num:]
x=0
for i in range(len(ls)) :
x+=1
if ls[i] in ls[:i] :
x-=1
print(x)
for t in range (m):
l=int(input())
control(l) | Title: Sereja and Suffixes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*). For each number *l**i* he wants to know how many distinct numbers are staying on the positions *l**i*, *l**i*<=+<=1, ..., *n*. Formally, he want to find the number of distinct numbers among *a**l**i*,<=*a**l**i*<=+<=1,<=...,<=*a**n*.?
Sereja wrote out the necessary array elements but the array was so large and the boy was so pressed for time. Help him, find the answer for the described question for each *l**i*.
Input Specification:
The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105) — the array elements.
Next *m* lines contain integers *l*1,<=*l*2,<=...,<=*l**m*. The *i*-th line contains integer *l**i* (1<=≤<=*l**i*<=≤<=*n*).
Output Specification:
Print *m* lines — on the *i*-th line print the answer to the number *l**i*.
Demo Input:
['10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n']
Demo Output:
['6\n6\n6\n6\n6\n5\n4\n3\n2\n1\n']
Note:
none | ```python
n,m=map(int,input().split())
a=list(map(int,input().split()))
def control(l):
num=l-1
ls=a[num:]
x=0
for i in range(len(ls)) :
x+=1
if ls[i] in ls[:i] :
x-=1
print(x)
for t in range (m):
l=int(input())
control(l)
``` | 0 | |
583 | B | Robot's Task | PROGRAMMING | 1,200 | [
"greedy",
"implementation"
] | null | null | Robot Doc is located in the hall, with *n* computers stand in a line, numbered from left to right from 1 to *n*. Each computer contains exactly one piece of information, each of which Doc wants to get eventually. The computers are equipped with a security system, so to crack the *i*-th of them, the robot needs to collect at least *a**i* any pieces of information from the other computers. Doc can hack the computer only if he is right next to it.
The robot is assembled using modern technologies and can move along the line of computers in either of the two possible directions, but the change of direction requires a large amount of resources from Doc. Tell the minimum number of changes of direction, which the robot will have to make to collect all *n* parts of information if initially it is next to computer with number 1.
It is guaranteed that there exists at least one sequence of the robot's actions, which leads to the collection of all information. Initially Doc doesn't have any pieces of information. | The first line contains number *n* (1<=≤<=*n*<=≤<=1000). The second line contains *n* non-negative integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=<<=*n*), separated by a space. It is guaranteed that there exists a way for robot to collect all pieces of the information. | Print a single number — the minimum number of changes in direction that the robot will have to make in order to collect all *n* parts of information. | [
"3\n0 2 0\n",
"5\n4 2 3 0 1\n",
"7\n0 3 1 0 5 2 6\n"
] | [
"1\n",
"3\n",
"2\n"
] | In the first sample you can assemble all the pieces of information in the optimal manner by assembling first the piece of information in the first computer, then in the third one, then change direction and move to the second one, and then, having 2 pieces of information, collect the last piece.
In the second sample to collect all the pieces of information in the optimal manner, Doc can go to the fourth computer and get the piece of information, then go to the fifth computer with one piece and get another one, then go to the second computer in the same manner, then to the third one and finally, to the first one. Changes of direction will take place before moving from the fifth to the second computer, then from the second to the third computer, then from the third to the first computer.
In the third sample the optimal order of collecting parts from computers can look like that: 1->3->4->6->2->5->7. | 1,000 | [
{
"input": "3\n0 2 0",
"output": "1"
},
{
"input": "5\n4 2 3 0 1",
"output": "3"
},
{
"input": "7\n0 3 1 0 5 2 6",
"output": "2"
},
{
"input": "1\n0",
"output": "0"
},
{
"input": "2\n0 1",
"output": "0"
},
{
"input": "10\n0 0 0 0 0 0 0 0 0 0",
"out... | 1,443,966,808 | 2,147,483,647 | Python 3 | OK | TESTS | 56 | 233 | 0 | n=int(input())
arr=list(map(int,input().split()))
found=0
ans=-1
cur=0
while found<n:
if ans%2==1:
for i in range(0,len(arr)):
if arr[i]!=-1 and arr[i]<=found:
found+=1
arr[i]=-1
#print(i+1)
ans+=1
else:
for i in range(len(arr)-1,-1,-1):
if arr[i]!=-1 and arr[i]<=found:
found+=1
arr[i]=-1
#print(i+1)
ans+=1
print(ans) | Title: Robot's Task
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Robot Doc is located in the hall, with *n* computers stand in a line, numbered from left to right from 1 to *n*. Each computer contains exactly one piece of information, each of which Doc wants to get eventually. The computers are equipped with a security system, so to crack the *i*-th of them, the robot needs to collect at least *a**i* any pieces of information from the other computers. Doc can hack the computer only if he is right next to it.
The robot is assembled using modern technologies and can move along the line of computers in either of the two possible directions, but the change of direction requires a large amount of resources from Doc. Tell the minimum number of changes of direction, which the robot will have to make to collect all *n* parts of information if initially it is next to computer with number 1.
It is guaranteed that there exists at least one sequence of the robot's actions, which leads to the collection of all information. Initially Doc doesn't have any pieces of information.
Input Specification:
The first line contains number *n* (1<=≤<=*n*<=≤<=1000). The second line contains *n* non-negative integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=<<=*n*), separated by a space. It is guaranteed that there exists a way for robot to collect all pieces of the information.
Output Specification:
Print a single number — the minimum number of changes in direction that the robot will have to make in order to collect all *n* parts of information.
Demo Input:
['3\n0 2 0\n', '5\n4 2 3 0 1\n', '7\n0 3 1 0 5 2 6\n']
Demo Output:
['1\n', '3\n', '2\n']
Note:
In the first sample you can assemble all the pieces of information in the optimal manner by assembling first the piece of information in the first computer, then in the third one, then change direction and move to the second one, and then, having 2 pieces of information, collect the last piece.
In the second sample to collect all the pieces of information in the optimal manner, Doc can go to the fourth computer and get the piece of information, then go to the fifth computer with one piece and get another one, then go to the second computer in the same manner, then to the third one and finally, to the first one. Changes of direction will take place before moving from the fifth to the second computer, then from the second to the third computer, then from the third to the first computer.
In the third sample the optimal order of collecting parts from computers can look like that: 1->3->4->6->2->5->7. | ```python
n=int(input())
arr=list(map(int,input().split()))
found=0
ans=-1
cur=0
while found<n:
if ans%2==1:
for i in range(0,len(arr)):
if arr[i]!=-1 and arr[i]<=found:
found+=1
arr[i]=-1
#print(i+1)
ans+=1
else:
for i in range(len(arr)-1,-1,-1):
if arr[i]!=-1 and arr[i]<=found:
found+=1
arr[i]=-1
#print(i+1)
ans+=1
print(ans)
``` | 3 | |
734 | A | Anton and Danik | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, who won more games, he or Danik? Help him determine this. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of games played.
The second line contains a string *s*, consisting of *n* uppercase English letters 'A' and 'D' — the outcome of each of the games. The *i*-th character of the string is equal to 'A' if the Anton won the *i*-th game and 'D' if Danik won the *i*-th game. | If Anton won more games than Danik, print "Anton" (without quotes) in the only line of the output.
If Danik won more games than Anton, print "Danik" (without quotes) in the only line of the output.
If Anton and Danik won the same number of games, print "Friendship" (without quotes). | [
"6\nADAAAA\n",
"7\nDDDAADA\n",
"6\nDADADA\n"
] | [
"Anton\n",
"Danik\n",
"Friendship\n"
] | In the first sample, Anton won 6 games, while Danik — only 1. Hence, the answer is "Anton".
In the second sample, Anton won 3 games and Danik won 4 games, so the answer is "Danik".
In the third sample, both Anton and Danik won 3 games and the answer is "Friendship". | 500 | [
{
"input": "6\nADAAAA",
"output": "Anton"
},
{
"input": "7\nDDDAADA",
"output": "Danik"
},
{
"input": "6\nDADADA",
"output": "Friendship"
},
{
"input": "10\nDDDDADDADD",
"output": "Danik"
},
{
"input": "40\nAAAAAAAAADDAAAAAAAAAAADADDAAAAAAAAAAADAA",
"output": ... | 1,699,354,827 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | n = int(input())
lst = list(map(str, input().split()))
a, d = 0, 0
for i in lst:
if i == 'A':
a += 1
else:
d += 1
if a > d:
print('Anton')
elif a == d:
print('Friendship')
else:
print('Danik') | Title: Anton and Danik
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, who won more games, he or Danik? Help him determine this.
Input Specification:
The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of games played.
The second line contains a string *s*, consisting of *n* uppercase English letters 'A' and 'D' — the outcome of each of the games. The *i*-th character of the string is equal to 'A' if the Anton won the *i*-th game and 'D' if Danik won the *i*-th game.
Output Specification:
If Anton won more games than Danik, print "Anton" (without quotes) in the only line of the output.
If Danik won more games than Anton, print "Danik" (without quotes) in the only line of the output.
If Anton and Danik won the same number of games, print "Friendship" (without quotes).
Demo Input:
['6\nADAAAA\n', '7\nDDDAADA\n', '6\nDADADA\n']
Demo Output:
['Anton\n', 'Danik\n', 'Friendship\n']
Note:
In the first sample, Anton won 6 games, while Danik — only 1. Hence, the answer is "Anton".
In the second sample, Anton won 3 games and Danik won 4 games, so the answer is "Danik".
In the third sample, both Anton and Danik won 3 games and the answer is "Friendship". | ```python
n = int(input())
lst = list(map(str, input().split()))
a, d = 0, 0
for i in lst:
if i == 'A':
a += 1
else:
d += 1
if a > d:
print('Anton')
elif a == d:
print('Friendship')
else:
print('Danik')
``` | 0 | |
261 | A | Maxim and Discounts | PROGRAMMING | 1,400 | [
"greedy",
"sortings"
] | null | null | Maxim always goes to the supermarket on Sundays. Today the supermarket has a special offer of discount systems.
There are *m* types of discounts. We assume that the discounts are indexed from 1 to *m*. To use the discount number *i*, the customer takes a special basket, where he puts exactly *q**i* items he buys. Under the terms of the discount system, in addition to the items in the cart the customer can receive at most two items from the supermarket for free. The number of the "free items" (0, 1 or 2) to give is selected by the customer. The only condition imposed on the selected "free items" is as follows: each of them mustn't be more expensive than the cheapest item out of the *q**i* items in the cart.
Maxim now needs to buy *n* items in the shop. Count the minimum sum of money that Maxim needs to buy them, if he use the discount system optimally well.
Please assume that the supermarket has enough carts for any actions. Maxim can use the same discount multiple times. Of course, Maxim can buy items without any discounts. | The first line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of discount types. The second line contains *m* integers: *q*1,<=*q*2,<=...,<=*q**m* (1<=≤<=*q**i*<=≤<=105).
The third line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of items Maxim needs. The fourth line contains *n* integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104) — the items' prices.
The numbers in the lines are separated by single spaces. | In a single line print a single integer — the answer to the problem. | [
"1\n2\n4\n50 50 100 100\n",
"2\n2 3\n5\n50 50 50 50 50\n",
"1\n1\n7\n1 1 1 1 1 1 1\n"
] | [
"200\n",
"150\n",
"3\n"
] | In the first sample Maxim needs to buy two items that cost 100 and get a discount for two free items that cost 50. In that case, Maxim is going to pay 200.
In the second sample the best strategy for Maxim is to buy 3 items and get 2 items for free using the discount. In that case, Maxim is going to pay 150. | 500 | [
{
"input": "1\n2\n4\n50 50 100 100",
"output": "200"
},
{
"input": "2\n2 3\n5\n50 50 50 50 50",
"output": "150"
},
{
"input": "1\n1\n7\n1 1 1 1 1 1 1",
"output": "3"
},
{
"input": "60\n7 4 20 15 17 6 2 2 3 18 13 14 16 11 13 12 6 10 14 1 16 6 4 9 10 8 10 15 16 13 13 9 16 11 5 ... | 1,377,979,516 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | import sys
n_discounts = int(sys.stdin.readline())
discount_values = [int(x) for x in sys.stdin.readline().split()]
n_items = int(sys.stdin.readline())
item_values = [int(x) for x in sys.stdin.readline().split()]
min_discount_req = 10000000
for discount_value in discount_values:
min_discount_req = min(min_discount_req, discount_value)
item_values.sort(reverse=True)
print(item_values)
index = 0
overall_price = 0
while index < n_items:
n_left = min(min_discount_req, n_items - index)
for i in range(n_left):
overall_price += item_values[index+i]
index += n_left + 2
print(overall_price)
| Title: Maxim and Discounts
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Maxim always goes to the supermarket on Sundays. Today the supermarket has a special offer of discount systems.
There are *m* types of discounts. We assume that the discounts are indexed from 1 to *m*. To use the discount number *i*, the customer takes a special basket, where he puts exactly *q**i* items he buys. Under the terms of the discount system, in addition to the items in the cart the customer can receive at most two items from the supermarket for free. The number of the "free items" (0, 1 or 2) to give is selected by the customer. The only condition imposed on the selected "free items" is as follows: each of them mustn't be more expensive than the cheapest item out of the *q**i* items in the cart.
Maxim now needs to buy *n* items in the shop. Count the minimum sum of money that Maxim needs to buy them, if he use the discount system optimally well.
Please assume that the supermarket has enough carts for any actions. Maxim can use the same discount multiple times. Of course, Maxim can buy items without any discounts.
Input Specification:
The first line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of discount types. The second line contains *m* integers: *q*1,<=*q*2,<=...,<=*q**m* (1<=≤<=*q**i*<=≤<=105).
The third line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of items Maxim needs. The fourth line contains *n* integers: *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=104) — the items' prices.
The numbers in the lines are separated by single spaces.
Output Specification:
In a single line print a single integer — the answer to the problem.
Demo Input:
['1\n2\n4\n50 50 100 100\n', '2\n2 3\n5\n50 50 50 50 50\n', '1\n1\n7\n1 1 1 1 1 1 1\n']
Demo Output:
['200\n', '150\n', '3\n']
Note:
In the first sample Maxim needs to buy two items that cost 100 and get a discount for two free items that cost 50. In that case, Maxim is going to pay 200.
In the second sample the best strategy for Maxim is to buy 3 items and get 2 items for free using the discount. In that case, Maxim is going to pay 150. | ```python
import sys
n_discounts = int(sys.stdin.readline())
discount_values = [int(x) for x in sys.stdin.readline().split()]
n_items = int(sys.stdin.readline())
item_values = [int(x) for x in sys.stdin.readline().split()]
min_discount_req = 10000000
for discount_value in discount_values:
min_discount_req = min(min_discount_req, discount_value)
item_values.sort(reverse=True)
print(item_values)
index = 0
overall_price = 0
while index < n_items:
n_left = min(min_discount_req, n_items - index)
for i in range(n_left):
overall_price += item_values[index+i]
index += n_left + 2
print(overall_price)
``` | 0 | |
313 | B | Ilya and Queries | PROGRAMMING | 1,100 | [
"dp",
"implementation"
] | null | null | Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string *s*<==<=*s*1*s*2... *s**n* (*n* is the length of the string), consisting only of characters "." and "#" and *m* queries. Each query is described by a pair of integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=<<=*r**i*<=≤<=*n*). The answer to the query *l**i*,<=*r**i* is the number of such integers *i* (*l**i*<=≤<=*i*<=<<=*r**i*), that *s**i*<==<=*s**i*<=+<=1.
Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem. | The first line contains string *s* of length *n* (2<=≤<=*n*<=≤<=105). It is guaranteed that the given string only consists of characters "." and "#".
The next line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of queries. Each of the next *m* lines contains the description of the corresponding query. The *i*-th line contains integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=<<=*r**i*<=≤<=*n*). | Print *m* integers — the answers to the queries in the order in which they are given in the input. | [
"......\n4\n3 4\n2 3\n1 6\n2 6\n",
"#..###\n5\n1 3\n5 6\n1 5\n3 6\n3 4\n"
] | [
"1\n1\n5\n4\n",
"1\n1\n2\n2\n0\n"
] | none | 1,000 | [
{
"input": "......\n4\n3 4\n2 3\n1 6\n2 6",
"output": "1\n1\n5\n4"
},
{
"input": "#..###\n5\n1 3\n5 6\n1 5\n3 6\n3 4",
"output": "1\n1\n2\n2\n0"
},
{
"input": ".#...#..\n6\n1 5\n2 3\n6 7\n2 4\n2 5\n1 3",
"output": "2\n0\n0\n1\n2\n0"
},
{
"input": "#.#.#..\n5\n3 4\n4 5\n5 7\n5... | 1,698,065,505 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 9 | 2,000 | 3,276,800 | def thing(s, q1,q2):
section = s[q1-1:q2]
c=0
for i in range(len(section) -1):
if section[i] == section[i+1]:
c += 1
return c
s = input()
m = input()
for i in range(int(m)):
a,b = [int(x) for x in input().split()]
print(thing(s,a,b))
| Title: Ilya and Queries
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string *s*<==<=*s*1*s*2... *s**n* (*n* is the length of the string), consisting only of characters "." and "#" and *m* queries. Each query is described by a pair of integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=<<=*r**i*<=≤<=*n*). The answer to the query *l**i*,<=*r**i* is the number of such integers *i* (*l**i*<=≤<=*i*<=<<=*r**i*), that *s**i*<==<=*s**i*<=+<=1.
Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.
Input Specification:
The first line contains string *s* of length *n* (2<=≤<=*n*<=≤<=105). It is guaranteed that the given string only consists of characters "." and "#".
The next line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of queries. Each of the next *m* lines contains the description of the corresponding query. The *i*-th line contains integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=<<=*r**i*<=≤<=*n*).
Output Specification:
Print *m* integers — the answers to the queries in the order in which they are given in the input.
Demo Input:
['......\n4\n3 4\n2 3\n1 6\n2 6\n', '#..###\n5\n1 3\n5 6\n1 5\n3 6\n3 4\n']
Demo Output:
['1\n1\n5\n4\n', '1\n1\n2\n2\n0\n']
Note:
none | ```python
def thing(s, q1,q2):
section = s[q1-1:q2]
c=0
for i in range(len(section) -1):
if section[i] == section[i+1]:
c += 1
return c
s = input()
m = input()
for i in range(int(m)):
a,b = [int(x) for x in input().split()]
print(thing(s,a,b))
``` | 0 | |
873 | A | Chores | PROGRAMMING | 800 | [
"implementation"
] | null | null | Luba has to do *n* chores today. *i*-th chore takes *a**i* units of time to complete. It is guaranteed that for every the condition *a**i*<=≥<=*a**i*<=-<=1 is met, so the sequence is sorted.
Also Luba can work really hard on some chores. She can choose not more than *k* any chores and do each of them in *x* units of time instead of *a**i* ().
Luba is very responsible, so she has to do all *n* chores, and now she wants to know the minimum time she needs to do everything. Luba cannot do two chores simultaneously. | The first line contains three integers *n*,<=*k*,<=*x* (1<=≤<=*k*<=≤<=*n*<=≤<=100,<=1<=≤<=*x*<=≤<=99) — the number of chores Luba has to do, the number of chores she can do in *x* units of time, and the number *x* itself.
The second line contains *n* integer numbers *a**i* (2<=≤<=*a**i*<=≤<=100) — the time Luba has to spend to do *i*-th chore.
It is guaranteed that , and for each *a**i*<=≥<=*a**i*<=-<=1. | Print one number — minimum time Luba needs to do all *n* chores. | [
"4 2 2\n3 6 7 10\n",
"5 2 1\n100 100 100 100 100\n"
] | [
"13\n",
"302\n"
] | In the first example the best option would be to do the third and the fourth chore, spending *x* = 2 time on each instead of *a*<sub class="lower-index">3</sub> and *a*<sub class="lower-index">4</sub>, respectively. Then the answer is 3 + 6 + 2 + 2 = 13.
In the second example Luba can choose any two chores to spend *x* time on them instead of *a*<sub class="lower-index">*i*</sub>. So the answer is 100·3 + 2·1 = 302. | 0 | [
{
"input": "4 2 2\n3 6 7 10",
"output": "13"
},
{
"input": "5 2 1\n100 100 100 100 100",
"output": "302"
},
{
"input": "1 1 1\n100",
"output": "1"
},
{
"input": "100 1 99\n100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 ... | 1,585,902,138 | 2,147,483,647 | PyPy 3 | OK | TESTS | 11 | 140 | 0 | #----Kuzlyaev-Nikita-Codeforces-----
#------------03.04.2020-------------
alph="abcdefghijklmnopqrstuvwxyz"
#-----------------------------------
n,k,x=map(int,input().split())
a=list(map(int,input().split()))
E=sum(a)
for i in range(min(n,k)):
E-=a[-i-1]-x
print(E) | Title: Chores
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luba has to do *n* chores today. *i*-th chore takes *a**i* units of time to complete. It is guaranteed that for every the condition *a**i*<=≥<=*a**i*<=-<=1 is met, so the sequence is sorted.
Also Luba can work really hard on some chores. She can choose not more than *k* any chores and do each of them in *x* units of time instead of *a**i* ().
Luba is very responsible, so she has to do all *n* chores, and now she wants to know the minimum time she needs to do everything. Luba cannot do two chores simultaneously.
Input Specification:
The first line contains three integers *n*,<=*k*,<=*x* (1<=≤<=*k*<=≤<=*n*<=≤<=100,<=1<=≤<=*x*<=≤<=99) — the number of chores Luba has to do, the number of chores she can do in *x* units of time, and the number *x* itself.
The second line contains *n* integer numbers *a**i* (2<=≤<=*a**i*<=≤<=100) — the time Luba has to spend to do *i*-th chore.
It is guaranteed that , and for each *a**i*<=≥<=*a**i*<=-<=1.
Output Specification:
Print one number — minimum time Luba needs to do all *n* chores.
Demo Input:
['4 2 2\n3 6 7 10\n', '5 2 1\n100 100 100 100 100\n']
Demo Output:
['13\n', '302\n']
Note:
In the first example the best option would be to do the third and the fourth chore, spending *x* = 2 time on each instead of *a*<sub class="lower-index">3</sub> and *a*<sub class="lower-index">4</sub>, respectively. Then the answer is 3 + 6 + 2 + 2 = 13.
In the second example Luba can choose any two chores to spend *x* time on them instead of *a*<sub class="lower-index">*i*</sub>. So the answer is 100·3 + 2·1 = 302. | ```python
#----Kuzlyaev-Nikita-Codeforces-----
#------------03.04.2020-------------
alph="abcdefghijklmnopqrstuvwxyz"
#-----------------------------------
n,k,x=map(int,input().split())
a=list(map(int,input().split()))
E=sum(a)
for i in range(min(n,k)):
E-=a[-i-1]-x
print(E)
``` | 3 | |
919 | A | Supermarket | PROGRAMMING | 800 | [
"brute force",
"greedy",
"implementation"
] | null | null | We often go to supermarkets to buy some fruits or vegetables, and on the tag there prints the price for a kilo. But in some supermarkets, when asked how much the items are, the clerk will say that $a$ yuan for $b$ kilos (You don't need to care about what "yuan" is), the same as $a/b$ yuan for a kilo.
Now imagine you'd like to buy $m$ kilos of apples. You've asked $n$ supermarkets and got the prices. Find the minimum cost for those apples.
You can assume that there are enough apples in all supermarkets. | The first line contains two positive integers $n$ and $m$ ($1 \leq n \leq 5\,000$, $1 \leq m \leq 100$), denoting that there are $n$ supermarkets and you want to buy $m$ kilos of apples.
The following $n$ lines describe the information of the supermarkets. Each line contains two positive integers $a, b$ ($1 \leq a, b \leq 100$), denoting that in this supermarket, you are supposed to pay $a$ yuan for $b$ kilos of apples. | The only line, denoting the minimum cost for $m$ kilos of apples. Please make sure that the absolute or relative error between your answer and the correct answer won't exceed $10^{-6}$.
Formally, let your answer be $x$, and the jury's answer be $y$. Your answer is considered correct if $\frac{|x - y|}{\max{(1, |y|)}} \le 10^{-6}$. | [
"3 5\n1 2\n3 4\n1 3\n",
"2 1\n99 100\n98 99\n"
] | [
"1.66666667\n",
"0.98989899\n"
] | In the first sample, you are supposed to buy $5$ kilos of apples in supermarket $3$. The cost is $5/3$ yuan.
In the second sample, you are supposed to buy $1$ kilo of apples in supermarket $2$. The cost is $98/99$ yuan. | 500 | [
{
"input": "3 5\n1 2\n3 4\n1 3",
"output": "1.66666667"
},
{
"input": "2 1\n99 100\n98 99",
"output": "0.98989899"
},
{
"input": "50 37\n78 49\n96 4\n86 62\n28 4\n19 2\n79 43\n79 92\n95 35\n33 60\n54 84\n90 25\n2 25\n53 21\n86 52\n72 25\n6 78\n41 46\n3 68\n42 89\n33 35\n57 43\n99 45\n1 8... | 1,699,697,579 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 15 | 0 | a, b = [int(i) for i in input().split()]
minimum=float('inf')
for i in range(a):
c,d =int(input())
price=c/d
if price<minimum:
minimum=price
print(minimum) | Title: Supermarket
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We often go to supermarkets to buy some fruits or vegetables, and on the tag there prints the price for a kilo. But in some supermarkets, when asked how much the items are, the clerk will say that $a$ yuan for $b$ kilos (You don't need to care about what "yuan" is), the same as $a/b$ yuan for a kilo.
Now imagine you'd like to buy $m$ kilos of apples. You've asked $n$ supermarkets and got the prices. Find the minimum cost for those apples.
You can assume that there are enough apples in all supermarkets.
Input Specification:
The first line contains two positive integers $n$ and $m$ ($1 \leq n \leq 5\,000$, $1 \leq m \leq 100$), denoting that there are $n$ supermarkets and you want to buy $m$ kilos of apples.
The following $n$ lines describe the information of the supermarkets. Each line contains two positive integers $a, b$ ($1 \leq a, b \leq 100$), denoting that in this supermarket, you are supposed to pay $a$ yuan for $b$ kilos of apples.
Output Specification:
The only line, denoting the minimum cost for $m$ kilos of apples. Please make sure that the absolute or relative error between your answer and the correct answer won't exceed $10^{-6}$.
Formally, let your answer be $x$, and the jury's answer be $y$. Your answer is considered correct if $\frac{|x - y|}{\max{(1, |y|)}} \le 10^{-6}$.
Demo Input:
['3 5\n1 2\n3 4\n1 3\n', '2 1\n99 100\n98 99\n']
Demo Output:
['1.66666667\n', '0.98989899\n']
Note:
In the first sample, you are supposed to buy $5$ kilos of apples in supermarket $3$. The cost is $5/3$ yuan.
In the second sample, you are supposed to buy $1$ kilo of apples in supermarket $2$. The cost is $98/99$ yuan. | ```python
a, b = [int(i) for i in input().split()]
minimum=float('inf')
for i in range(a):
c,d =int(input())
price=c/d
if price<minimum:
minimum=price
print(minimum)
``` | -1 | |
884 | D | Boxes And Balls | PROGRAMMING | 2,300 | [
"data structures",
"greedy"
] | null | null | Ivan has *n* different boxes. The first of them contains some balls of *n* different colors.
Ivan wants to play a strange game. He wants to distribute the balls into boxes in such a way that for every *i* (1<=≤<=*i*<=≤<=*n*) *i*-th box will contain all balls with color *i*.
In order to do this, Ivan will make some turns. Each turn he does the following:
1. Ivan chooses any non-empty box and takes all balls from this box; 1. Then Ivan chooses any *k* empty boxes (the box from the first step becomes empty, and Ivan is allowed to choose it), separates the balls he took on the previous step into *k* non-empty groups and puts each group into one of the boxes. He should put each group into a separate box. He can choose either *k*<==<=2 or *k*<==<=3.
The penalty of the turn is the number of balls Ivan takes from the box during the first step of the turn. And penalty of the game is the total penalty of turns made by Ivan until he distributes all balls to corresponding boxes.
Help Ivan to determine the minimum possible penalty of the game! | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=200000) — the number of boxes and colors.
The second line contains *n* integer numbers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=109), where *a**i* is the number of balls with color *i*. | Print one number — the minimum possible penalty of the game. | [
"3\n1 2 3\n",
"4\n2 3 4 5\n"
] | [
"6\n",
"19\n"
] | In the first example you take all the balls from the first box, choose *k* = 3 and sort all colors to corresponding boxes. Penalty is 6.
In the second example you make two turns:
1. Take all the balls from the first box, choose *k* = 3, put balls of color 3 to the third box, of color 4 — to the fourth box and the rest put back into the first box. Penalty is 14; 1. Take all the balls from the first box, choose *k* = 2, put balls of color 1 to the first box, of color 2 — to the second box. Penalty is 5.
Total penalty is 19. | 0 | [
{
"input": "3\n1 2 3",
"output": "6"
},
{
"input": "4\n2 3 4 5",
"output": "19"
},
{
"input": "6\n1 4 4 4 4 4",
"output": "38"
},
{
"input": "8\n821407370 380061316 428719552 90851747 825473738 704702117 845629927 245820158",
"output": "8176373828"
},
{
"input": "... | 1,510,185,241 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 514 | 15,974,400 | import heapq as h
n = int(input())
line2 = input().split()
a = []
for i in range(n):
h.heappush(a,int(line2[i]))
if n == 1:
print(0)
else:
result = 0
if n%2 == 1:
k = n
else:
a.append(0)
k = n + 1
while k > 3:
previous = h.heappop(a) + h.heappop(a)+ h.heappop(a)
result += previous
h.heappush(a, previous)
k -= 2
result += sum(a)
print(result) | Title: Boxes And Balls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ivan has *n* different boxes. The first of them contains some balls of *n* different colors.
Ivan wants to play a strange game. He wants to distribute the balls into boxes in such a way that for every *i* (1<=≤<=*i*<=≤<=*n*) *i*-th box will contain all balls with color *i*.
In order to do this, Ivan will make some turns. Each turn he does the following:
1. Ivan chooses any non-empty box and takes all balls from this box; 1. Then Ivan chooses any *k* empty boxes (the box from the first step becomes empty, and Ivan is allowed to choose it), separates the balls he took on the previous step into *k* non-empty groups and puts each group into one of the boxes. He should put each group into a separate box. He can choose either *k*<==<=2 or *k*<==<=3.
The penalty of the turn is the number of balls Ivan takes from the box during the first step of the turn. And penalty of the game is the total penalty of turns made by Ivan until he distributes all balls to corresponding boxes.
Help Ivan to determine the minimum possible penalty of the game!
Input Specification:
The first line contains one integer number *n* (1<=≤<=*n*<=≤<=200000) — the number of boxes and colors.
The second line contains *n* integer numbers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=109), where *a**i* is the number of balls with color *i*.
Output Specification:
Print one number — the minimum possible penalty of the game.
Demo Input:
['3\n1 2 3\n', '4\n2 3 4 5\n']
Demo Output:
['6\n', '19\n']
Note:
In the first example you take all the balls from the first box, choose *k* = 3 and sort all colors to corresponding boxes. Penalty is 6.
In the second example you make two turns:
1. Take all the balls from the first box, choose *k* = 3, put balls of color 3 to the third box, of color 4 — to the fourth box and the rest put back into the first box. Penalty is 14; 1. Take all the balls from the first box, choose *k* = 2, put balls of color 1 to the first box, of color 2 — to the second box. Penalty is 5.
Total penalty is 19. | ```python
import heapq as h
n = int(input())
line2 = input().split()
a = []
for i in range(n):
h.heappush(a,int(line2[i]))
if n == 1:
print(0)
else:
result = 0
if n%2 == 1:
k = n
else:
a.append(0)
k = n + 1
while k > 3:
previous = h.heappop(a) + h.heappop(a)+ h.heappop(a)
result += previous
h.heappush(a, previous)
k -= 2
result += sum(a)
print(result)
``` | 3 | |
702 | A | Maximum Increase | PROGRAMMING | 800 | [
"dp",
"greedy",
"implementation"
] | null | null | You are given array consisting of *n* integers. Your task is to find the maximum length of an increasing subarray of the given array.
A subarray is the sequence of consecutive elements of the array. Subarray is called increasing if each element of this subarray strictly greater than previous. | The first line contains single positive integer *n* (1<=≤<=*n*<=≤<=105) — the number of integers.
The second line contains *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | Print the maximum length of an increasing subarray of the given array. | [
"5\n1 7 2 11 15\n",
"6\n100 100 100 100 100 100\n",
"3\n1 2 3\n"
] | [
"3\n",
"1\n",
"3\n"
] | none | 0 | [
{
"input": "5\n1 7 2 11 15",
"output": "3"
},
{
"input": "6\n100 100 100 100 100 100",
"output": "1"
},
{
"input": "3\n1 2 3",
"output": "3"
},
{
"input": "1\n1000000000",
"output": "1"
},
{
"input": "10\n802030518 598196518 640274071 983359971 71550121 96204862 7... | 1,654,505,452 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 0 | n, ls, c, res, mx, = int(input()), list(map(int, input().split())), 0, 0, 0
for i in ls:
if i > c: c, res = i, res + 1
else: res, mx = 1, max(res, mx)
print(max(mx, c)) | Title: Maximum Increase
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given array consisting of *n* integers. Your task is to find the maximum length of an increasing subarray of the given array.
A subarray is the sequence of consecutive elements of the array. Subarray is called increasing if each element of this subarray strictly greater than previous.
Input Specification:
The first line contains single positive integer *n* (1<=≤<=*n*<=≤<=105) — the number of integers.
The second line contains *n* positive integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109).
Output Specification:
Print the maximum length of an increasing subarray of the given array.
Demo Input:
['5\n1 7 2 11 15\n', '6\n100 100 100 100 100 100\n', '3\n1 2 3\n']
Demo Output:
['3\n', '1\n', '3\n']
Note:
none | ```python
n, ls, c, res, mx, = int(input()), list(map(int, input().split())), 0, 0, 0
for i in ls:
if i > c: c, res = i, res + 1
else: res, mx = 1, max(res, mx)
print(max(mx, c))
``` | 0 | |
598 | A | Tricky Sum | PROGRAMMING | 900 | [
"math"
] | null | null | In this problem you are to calculate the sum of all integers from 1 to *n*, but you should take all powers of two with minus in the sum.
For example, for *n*<==<=4 the sum is equal to <=-<=1<=-<=2<=+<=3<=-<=4<==<=<=-<=4, because 1, 2 and 4 are 20, 21 and 22 respectively.
Calculate the answer for *t* values of *n*. | The first line of the input contains a single integer *t* (1<=≤<=*t*<=≤<=100) — the number of values of *n* to be processed.
Each of next *t* lines contains a single integer *n* (1<=≤<=*n*<=≤<=109). | Print the requested sum for each of *t* integers *n* given in the input. | [
"2\n4\n1000000000\n"
] | [
"-4\n499999998352516354\n"
] | The answer for the first sample is explained in the statement. | 0 | [
{
"input": "2\n4\n1000000000",
"output": "-4\n499999998352516354"
},
{
"input": "10\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "-1\n-3\n0\n-4\n1\n7\n14\n6\n15\n25"
},
{
"input": "10\n10\n9\n47\n33\n99\n83\n62\n1\n100\n53",
"output": "25\n15\n1002\n435\n4696\n3232\n1827\n-1\n4796\n130... | 1,636,130,652 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 21 | 62 | 30,412,800 | t = int(input())
for i in range(t):
n = int(input())
s = ((n+1)*n)//2
i = 1
while i<=n:
s -= i*2
i*=2
print(s) | Title: Tricky Sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In this problem you are to calculate the sum of all integers from 1 to *n*, but you should take all powers of two with minus in the sum.
For example, for *n*<==<=4 the sum is equal to <=-<=1<=-<=2<=+<=3<=-<=4<==<=<=-<=4, because 1, 2 and 4 are 20, 21 and 22 respectively.
Calculate the answer for *t* values of *n*.
Input Specification:
The first line of the input contains a single integer *t* (1<=≤<=*t*<=≤<=100) — the number of values of *n* to be processed.
Each of next *t* lines contains a single integer *n* (1<=≤<=*n*<=≤<=109).
Output Specification:
Print the requested sum for each of *t* integers *n* given in the input.
Demo Input:
['2\n4\n1000000000\n']
Demo Output:
['-4\n499999998352516354\n']
Note:
The answer for the first sample is explained in the statement. | ```python
t = int(input())
for i in range(t):
n = int(input())
s = ((n+1)*n)//2
i = 1
while i<=n:
s -= i*2
i*=2
print(s)
``` | 3 | |
432 | A | Choosing Teams | PROGRAMMING | 800 | [
"greedy",
"implementation",
"sortings"
] | null | null | The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
The head of the SSU OPTC is recently gathering teams to participate in the world championship. Each team must consist of exactly three people, at that, any person cannot be a member of two or more teams. What maximum number of teams can the head make if he wants each team to participate in the world championship with the same members at least *k* times? | The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship. | Print a single number — the answer to the problem. | [
"5 2\n0 4 5 1 0\n",
"6 4\n0 1 2 3 4 5\n",
"6 5\n0 0 0 0 0 0\n"
] | [
"1\n",
"0\n",
"2\n"
] | In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | 500 | [
{
"input": "5 2\n0 4 5 1 0",
"output": "1"
},
{
"input": "6 4\n0 1 2 3 4 5",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0 0",
"output": "2"
},
{
"input": "3 4\n0 1 0",
"output": "1"
},
{
"input": "3 4\n0 2 0",
"output": "0"
},
{
"input": "6 5\n0 0 0 0 0... | 1,681,262,583 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 46 | 0 | n,k=map(int,input().split())
*a,=map(int,input().split())
print(sum(1 for i in a if i<=5-k)//3) | Title: Choosing Teams
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has *n* students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
The head of the SSU OPTC is recently gathering teams to participate in the world championship. Each team must consist of exactly three people, at that, any person cannot be a member of two or more teams. What maximum number of teams can the head make if he wants each team to participate in the world championship with the same members at least *k* times?
Input Specification:
The first line contains two integers, *n* and *k* (1<=≤<=*n*<=≤<=2000; 1<=≤<=*k*<=≤<=5). The next line contains *n* integers: *y*1,<=*y*2,<=...,<=*y**n* (0<=≤<=*y**i*<=≤<=5), where *y**i* shows the number of times the *i*-th person participated in the ACM ICPC world championship.
Output Specification:
Print a single number — the answer to the problem.
Demo Input:
['5 2\n0 4 5 1 0\n', '6 4\n0 1 2 3 4 5\n', '6 5\n0 0 0 0 0 0\n']
Demo Output:
['1\n', '0\n', '2\n']
Note:
In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits. | ```python
n,k=map(int,input().split())
*a,=map(int,input().split())
print(sum(1 for i in a if i<=5-k)//3)
``` | 3 | |
902 | B | Coloring a Tree | PROGRAMMING | 1,200 | [
"dfs and similar",
"dsu",
"greedy"
] | null | null | You are given a rooted tree with *n* vertices. The vertices are numbered from 1 to *n*, the root is the vertex number 1.
Each vertex has a color, let's denote the color of vertex *v* by *c**v*. Initially *c**v*<==<=0.
You have to color the tree into the given colors using the smallest possible number of steps. On each step you can choose a vertex *v* and a color *x*, and then color all vectices in the subtree of *v* (including *v* itself) in color *x*. In other words, for every vertex *u*, such that the path from root to *u* passes through *v*, set *c**u*<==<=*x*.
It is guaranteed that you have to color each vertex in a color different from 0.
You can learn what a rooted tree is using the link: [https://en.wikipedia.org/wiki/Tree_(graph_theory)](https://en.wikipedia.org/wiki/Tree_(graph_theory)). | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=104) — the number of vertices in the tree.
The second line contains *n*<=-<=1 integers *p*2,<=*p*3,<=...,<=*p**n* (1<=≤<=*p**i*<=<<=*i*), where *p**i* means that there is an edge between vertices *i* and *p**i*.
The third line contains *n* integers *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=*n*), where *c**i* is the color you should color the *i*-th vertex into.
It is guaranteed that the given graph is a tree. | Print a single integer — the minimum number of steps you have to perform to color the tree into given colors. | [
"6\n1 2 2 1 5\n2 1 1 1 1 1\n",
"7\n1 1 2 3 1 4\n3 3 1 1 1 2 3\n"
] | [
"3\n",
"5\n"
] | The tree from the first sample is shown on the picture (numbers are vetices' indices):
<img class="tex-graphics" src="https://espresso.codeforces.com/10324ccdc37f95343acc4f3c6050d8c334334ffa.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On first step we color all vertices in the subtree of vertex 1 into color 2 (numbers are colors):
<img class="tex-graphics" src="https://espresso.codeforces.com/1c7bb267e2c1a006132248a43121400189309e2f.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On seond step we color all vertices in the subtree of vertex 5 into color 1:
<img class="tex-graphics" src="https://espresso.codeforces.com/2201a6d49b89ba850ff0d0bdcbb3f8e9dd3871a8.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On third step we color all vertices in the subtree of vertex 2 into color 1:
<img class="tex-graphics" src="https://espresso.codeforces.com/6fa977fcdebdde94c47695151e0427b33d0102c5.png" style="max-width: 100.0%;max-height: 100.0%;"/>
The tree from the second sample is shown on the picture (numbers are vetices' indices):
<img class="tex-graphics" src="https://espresso.codeforces.com/d70f9ae72a2ed429dd6531cac757e375dd3c953d.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On first step we color all vertices in the subtree of vertex 1 into color 3 (numbers are colors):
<img class="tex-graphics" src="https://espresso.codeforces.com/7289e8895d0dd56c47b6b17969b9cf77b36786b5.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On second step we color all vertices in the subtree of vertex 3 into color 1:
<img class="tex-graphics" src="https://espresso.codeforces.com/819001df7229138db3a407713744d1e3be88b64e.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On third step we color all vertices in the subtree of vertex 6 into color 2:
<img class="tex-graphics" src="https://espresso.codeforces.com/80ebbd870a0a339636a21b9acdaf9de046458b43.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On fourth step we color all vertices in the subtree of vertex 4 into color 1:
<img class="tex-graphics" src="https://espresso.codeforces.com/ed836aa723ac0176abde4e32988e3ac205014e93.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On fith step we color all vertices in the subtree of vertex 7 into color 3:
<img class="tex-graphics" src="https://espresso.codeforces.com/8132909e11b41c27b8df2f0b0c10bc841f35e58a.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "6\n1 2 2 1 5\n2 1 1 1 1 1",
"output": "3"
},
{
"input": "7\n1 1 2 3 1 4\n3 3 1 1 1 2 3",
"output": "5"
},
{
"input": "2\n1\n2 2",
"output": "1"
},
{
"input": "3\n1 1\n2 2 2",
"output": "1"
},
{
"input": "4\n1 2 1\n1 2 3 4",
"output": "4"
},
{
... | 1,540,831,003 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 93 | 0 | n = int(input())
tree = list(map(int,input().split()))
tree2, tree3 = [], []
node_nr, last_nodes = 0, 0
for nodes in tree:
for i in range(nodes):
tree2.append(node_nr)
if nodes >= 2 and last_nodes >= 2:
tree3.append(node_nr - 1)
for i in range(nodes - 1):
tree3.append(node_nr)
else:
for i in range(nodes):
tree3.append(node_nr)
node_nr += nodes
last_nodes = nodes
def a():
print('ambiguous')
print(*tree2)
print(*tree3)
return ''
print('perfect\n' if tree2 == tree3 else a())
| Title: Coloring a Tree
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a rooted tree with *n* vertices. The vertices are numbered from 1 to *n*, the root is the vertex number 1.
Each vertex has a color, let's denote the color of vertex *v* by *c**v*. Initially *c**v*<==<=0.
You have to color the tree into the given colors using the smallest possible number of steps. On each step you can choose a vertex *v* and a color *x*, and then color all vectices in the subtree of *v* (including *v* itself) in color *x*. In other words, for every vertex *u*, such that the path from root to *u* passes through *v*, set *c**u*<==<=*x*.
It is guaranteed that you have to color each vertex in a color different from 0.
You can learn what a rooted tree is using the link: [https://en.wikipedia.org/wiki/Tree_(graph_theory)](https://en.wikipedia.org/wiki/Tree_(graph_theory)).
Input Specification:
The first line contains a single integer *n* (2<=≤<=*n*<=≤<=104) — the number of vertices in the tree.
The second line contains *n*<=-<=1 integers *p*2,<=*p*3,<=...,<=*p**n* (1<=≤<=*p**i*<=<<=*i*), where *p**i* means that there is an edge between vertices *i* and *p**i*.
The third line contains *n* integers *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=*n*), where *c**i* is the color you should color the *i*-th vertex into.
It is guaranteed that the given graph is a tree.
Output Specification:
Print a single integer — the minimum number of steps you have to perform to color the tree into given colors.
Demo Input:
['6\n1 2 2 1 5\n2 1 1 1 1 1\n', '7\n1 1 2 3 1 4\n3 3 1 1 1 2 3\n']
Demo Output:
['3\n', '5\n']
Note:
The tree from the first sample is shown on the picture (numbers are vetices' indices):
<img class="tex-graphics" src="https://espresso.codeforces.com/10324ccdc37f95343acc4f3c6050d8c334334ffa.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On first step we color all vertices in the subtree of vertex 1 into color 2 (numbers are colors):
<img class="tex-graphics" src="https://espresso.codeforces.com/1c7bb267e2c1a006132248a43121400189309e2f.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On seond step we color all vertices in the subtree of vertex 5 into color 1:
<img class="tex-graphics" src="https://espresso.codeforces.com/2201a6d49b89ba850ff0d0bdcbb3f8e9dd3871a8.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On third step we color all vertices in the subtree of vertex 2 into color 1:
<img class="tex-graphics" src="https://espresso.codeforces.com/6fa977fcdebdde94c47695151e0427b33d0102c5.png" style="max-width: 100.0%;max-height: 100.0%;"/>
The tree from the second sample is shown on the picture (numbers are vetices' indices):
<img class="tex-graphics" src="https://espresso.codeforces.com/d70f9ae72a2ed429dd6531cac757e375dd3c953d.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On first step we color all vertices in the subtree of vertex 1 into color 3 (numbers are colors):
<img class="tex-graphics" src="https://espresso.codeforces.com/7289e8895d0dd56c47b6b17969b9cf77b36786b5.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On second step we color all vertices in the subtree of vertex 3 into color 1:
<img class="tex-graphics" src="https://espresso.codeforces.com/819001df7229138db3a407713744d1e3be88b64e.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On third step we color all vertices in the subtree of vertex 6 into color 2:
<img class="tex-graphics" src="https://espresso.codeforces.com/80ebbd870a0a339636a21b9acdaf9de046458b43.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On fourth step we color all vertices in the subtree of vertex 4 into color 1:
<img class="tex-graphics" src="https://espresso.codeforces.com/ed836aa723ac0176abde4e32988e3ac205014e93.png" style="max-width: 100.0%;max-height: 100.0%;"/>
On fith step we color all vertices in the subtree of vertex 7 into color 3:
<img class="tex-graphics" src="https://espresso.codeforces.com/8132909e11b41c27b8df2f0b0c10bc841f35e58a.png" style="max-width: 100.0%;max-height: 100.0%;"/> | ```python
n = int(input())
tree = list(map(int,input().split()))
tree2, tree3 = [], []
node_nr, last_nodes = 0, 0
for nodes in tree:
for i in range(nodes):
tree2.append(node_nr)
if nodes >= 2 and last_nodes >= 2:
tree3.append(node_nr - 1)
for i in range(nodes - 1):
tree3.append(node_nr)
else:
for i in range(nodes):
tree3.append(node_nr)
node_nr += nodes
last_nodes = nodes
def a():
print('ambiguous')
print(*tree2)
print(*tree3)
return ''
print('perfect\n' if tree2 == tree3 else a())
``` | 0 | |
886 | A | ACM ICPC | PROGRAMMING | 1,000 | [
"brute force"
] | null | null | In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build exactly two teams.
After practice competition, participant number *i* got a score of *a**i*. Team score is defined as sum of scores of its participants. High school management is interested if it's possible to build two teams with equal scores. Your task is to answer that question. | The single line contains six integers *a*1,<=...,<=*a*6 (0<=≤<=*a**i*<=≤<=1000) — scores of the participants | Print "YES" (quotes for clarity), if it is possible to build teams with equal score, and "NO" otherwise.
You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES"). | [
"1 3 2 1 2 1\n",
"1 1 1 1 1 99\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, first team can be composed of 1st, 2nd and 6th participant, second — of 3rd, 4th and 5th: team scores are 1 + 3 + 1 = 2 + 1 + 2 = 5.
In the second sample, score of participant number 6 is too high: his team score will be definitely greater. | 500 | [
{
"input": "1 3 2 1 2 1",
"output": "YES"
},
{
"input": "1 1 1 1 1 99",
"output": "NO"
},
{
"input": "1000 1000 1000 1000 1000 1000",
"output": "YES"
},
{
"input": "0 0 0 0 0 0",
"output": "YES"
},
{
"input": "633 609 369 704 573 416",
"output": "NO"
},
{
... | 1,691,597,302 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | for _ in range(int(input())):
l= list(map(int,input().split(" ")))
flag=0
for i in range(len(l)):
for j in range(i+1,len(l)):
if l[i]+l[j] >= 10:
flag=1
if flag==0:
print("No")
else:
print("Yes") | Title: ACM ICPC
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build exactly two teams.
After practice competition, participant number *i* got a score of *a**i*. Team score is defined as sum of scores of its participants. High school management is interested if it's possible to build two teams with equal scores. Your task is to answer that question.
Input Specification:
The single line contains six integers *a*1,<=...,<=*a*6 (0<=≤<=*a**i*<=≤<=1000) — scores of the participants
Output Specification:
Print "YES" (quotes for clarity), if it is possible to build teams with equal score, and "NO" otherwise.
You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES").
Demo Input:
['1 3 2 1 2 1\n', '1 1 1 1 1 99\n']
Demo Output:
['YES\n', 'NO\n']
Note:
In the first sample, first team can be composed of 1st, 2nd and 6th participant, second — of 3rd, 4th and 5th: team scores are 1 + 3 + 1 = 2 + 1 + 2 = 5.
In the second sample, score of participant number 6 is too high: his team score will be definitely greater. | ```python
for _ in range(int(input())):
l= list(map(int,input().split(" ")))
flag=0
for i in range(len(l)):
for j in range(i+1,len(l)):
if l[i]+l[j] >= 10:
flag=1
if flag==0:
print("No")
else:
print("Yes")
``` | -1 | |
218 | B | Airport | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen plane has *x* (*x*<=><=0) empty seats at the given moment, then the ticket for such a plane costs *x* zlotys (units of Polish currency).
The only ticket office of the airport already has a queue of *n* passengers in front of it. Lolek and Bolek have not stood in the queue yet, but they are already wondering what is the maximum and the minimum number of zlotys the airport administration can earn if all *n* passengers buy tickets according to the conditions of this offer?
The passengers buy tickets in turn, the first person in the queue goes first, then goes the second one, and so on up to *n*-th person. | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of passengers in the queue and the number of planes in the airport, correspondingly. The next line contains *m* integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=1000) — *a**i* stands for the number of empty seats in the *i*-th plane before the ticket office starts selling tickets.
The numbers in the lines are separated by a space. It is guaranteed that there are at least *n* empty seats in total. | Print two integers — the maximum and the minimum number of zlotys that the airport administration can earn, correspondingly. | [
"4 3\n2 1 1\n",
"4 3\n2 2 2\n"
] | [
"5 5\n",
"7 6\n"
] | In the first test sample the number of passengers is equal to the number of empty seats, so regardless of the way the planes are chosen, the administration will earn the same sum.
In the second sample the sum is maximized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 2-nd plane, the 3-rd person — to the 3-rd plane, the 4-th person — to the 1-st plane. The sum is minimized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 1-st plane, the 3-rd person — to the 2-nd plane, the 4-th person — to the 2-nd plane. | 500 | [
{
"input": "4 3\n2 1 1",
"output": "5 5"
},
{
"input": "4 3\n2 2 2",
"output": "7 6"
},
{
"input": "10 5\n10 3 3 1 2",
"output": "58 26"
},
{
"input": "10 1\n10",
"output": "55 55"
},
{
"input": "10 1\n100",
"output": "955 955"
},
{
"input": "10 2\n4 7... | 1,589,625,216 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 466 | 6,963,200 | n,m = map(int,input().split())
a = list(map(int,input().split()))
b = [i for i in a]
mx,mn = 0,0
for i in range(n):
mx = mx + max(a)
d = a.index(max(a))
if(a[d]>0):
a[d]-=1
for i in range(n):
mn = mn + min(b)
d = b.index(min(b))
if(b[d]==1):
b[d]=1000000000
elif(b[d]>1):
b[d]-=1
print(mx,mn)
| Title: Airport
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Lolek and Bolek are about to travel abroad by plane. The local airport has a special "Choose Your Plane" offer. The offer's conditions are as follows:
- it is up to a passenger to choose a plane to fly on; - if the chosen plane has *x* (*x*<=><=0) empty seats at the given moment, then the ticket for such a plane costs *x* zlotys (units of Polish currency).
The only ticket office of the airport already has a queue of *n* passengers in front of it. Lolek and Bolek have not stood in the queue yet, but they are already wondering what is the maximum and the minimum number of zlotys the airport administration can earn if all *n* passengers buy tickets according to the conditions of this offer?
The passengers buy tickets in turn, the first person in the queue goes first, then goes the second one, and so on up to *n*-th person.
Input Specification:
The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of passengers in the queue and the number of planes in the airport, correspondingly. The next line contains *m* integers *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=1000) — *a**i* stands for the number of empty seats in the *i*-th plane before the ticket office starts selling tickets.
The numbers in the lines are separated by a space. It is guaranteed that there are at least *n* empty seats in total.
Output Specification:
Print two integers — the maximum and the minimum number of zlotys that the airport administration can earn, correspondingly.
Demo Input:
['4 3\n2 1 1\n', '4 3\n2 2 2\n']
Demo Output:
['5 5\n', '7 6\n']
Note:
In the first test sample the number of passengers is equal to the number of empty seats, so regardless of the way the planes are chosen, the administration will earn the same sum.
In the second sample the sum is maximized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 2-nd plane, the 3-rd person — to the 3-rd plane, the 4-th person — to the 1-st plane. The sum is minimized if the 1-st person in the queue buys a ticket to the 1-st plane, the 2-nd person — to the 1-st plane, the 3-rd person — to the 2-nd plane, the 4-th person — to the 2-nd plane. | ```python
n,m = map(int,input().split())
a = list(map(int,input().split()))
b = [i for i in a]
mx,mn = 0,0
for i in range(n):
mx = mx + max(a)
d = a.index(max(a))
if(a[d]>0):
a[d]-=1
for i in range(n):
mn = mn + min(b)
d = b.index(min(b))
if(b[d]==1):
b[d]=1000000000
elif(b[d]>1):
b[d]-=1
print(mx,mn)
``` | 3 | |
928 | B | Chat | PROGRAMMING | 1,400 | [
"*special",
"dp"
] | null | null | There are times you recall a good old friend and everything you've come through together. Luckily there are social networks — they store all your message history making it easy to know what you argued over 10 years ago.
More formal, your message history is a sequence of messages ordered by time sent numbered from 1 to *n* where *n* is the total number of messages in the chat.
Each message might contain a link to an earlier message which it is a reply to. When opening a message *x* or getting a link to it, the dialogue is shown in such a way that *k* previous messages, message *x* and *k* next messages are visible (with respect to message *x*). In case there are less than *k* messages somewhere, they are yet all shown.
Digging deep into your message history, you always read all visible messages and then go by the link in the current message *x* (if there is one) and continue reading in the same manner.
Determine the number of messages you'll read if your start from message number *t* for all *t* from 1 to *n*. Calculate these numbers independently. If you start with message *x*, the initial configuration is *x* itself, *k* previous and *k* next messages. Messages read multiple times are considered as one. | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105, 0<=≤<=*k*<=≤<=*n*) — the total amount of messages and the number of previous and next messages visible.
The second line features a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=<<=*i*), where *a**i* denotes the *i*-th message link destination or zero, if there's no link from *i*. All messages are listed in chronological order. It's guaranteed that the link from message *x* goes to message with number strictly less than *x*. | Print *n* integers with *i*-th denoting the number of distinct messages you can read starting from message *i* and traversing the links while possible. | [
"6 0\n0 1 1 2 3 2\n",
"10 1\n0 1 0 3 4 5 2 3 7 0\n",
"2 2\n0 1\n"
] | [
"1 2 2 3 3 3 \n",
"2 3 3 4 5 6 6 6 8 2 \n",
"2 2 \n"
] | Consider *i* = 6 in sample case one. You will read message 6, then 2, then 1 and then there will be no link to go.
In the second sample case *i* = 6 gives you messages 5, 6, 7 since *k* = 1, then 4, 5, 6, then 2, 3, 4 and then the link sequence breaks. The number of distinct messages here is equal to 6. | 1,250 | [
{
"input": "6 0\n0 1 1 2 3 2",
"output": "1 2 2 3 3 3 "
},
{
"input": "10 1\n0 1 0 3 4 5 2 3 7 0",
"output": "2 3 3 4 5 6 6 6 8 2 "
},
{
"input": "2 2\n0 1",
"output": "2 2 "
},
{
"input": "1 1\n0",
"output": "1 "
},
{
"input": "5 2\n0 1 2 3 1",
"output": "3 4... | 1,519,561,395 | 74,895 | PyPy 3 | WRONG_ANSWER | TESTS | 21 | 295 | 30,924,800 | s = input().split()
n = int(s[0])
k = int(s[1])
a = [int(i) for i in input().split()]
if n < k+2:
print(str(n)+(' ' + str(n))*(n-1))
else:
twok = k*2+1
counts = []
for i in range(1, k+2):
counts.append(i + k)
for i in range(k+2, n-k):
if a[i-1] == 0:
counts.append(twok)
else:
p = i - a[i-1]
if p < twok:
counts.append(counts[a[i-1]-1]+p)
else:
counts.append(counts[a[i-1]-1]+twok)
for i in range(n-k, n+1):
if a[i-1] == 0:
counts.append(n-i+1+k)
elif n-k < a[i-1]:
counts.append(counts[a[i-1]-1])
else:
p = i - a[i-1]
if p < twok:
counts.append(counts[a[i-1]-1]+n-i-k+p)
else:
counts.append(counts[a[i-1]-1]+n-i+1+k)
print(counts[0], end='')
[print(' ' + str(counts[i]), end='') for i in range(1,n)]
| Title: Chat
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are times you recall a good old friend and everything you've come through together. Luckily there are social networks — they store all your message history making it easy to know what you argued over 10 years ago.
More formal, your message history is a sequence of messages ordered by time sent numbered from 1 to *n* where *n* is the total number of messages in the chat.
Each message might contain a link to an earlier message which it is a reply to. When opening a message *x* or getting a link to it, the dialogue is shown in such a way that *k* previous messages, message *x* and *k* next messages are visible (with respect to message *x*). In case there are less than *k* messages somewhere, they are yet all shown.
Digging deep into your message history, you always read all visible messages and then go by the link in the current message *x* (if there is one) and continue reading in the same manner.
Determine the number of messages you'll read if your start from message number *t* for all *t* from 1 to *n*. Calculate these numbers independently. If you start with message *x*, the initial configuration is *x* itself, *k* previous and *k* next messages. Messages read multiple times are considered as one.
Input Specification:
The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=105, 0<=≤<=*k*<=≤<=*n*) — the total amount of messages and the number of previous and next messages visible.
The second line features a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=<<=*i*), where *a**i* denotes the *i*-th message link destination or zero, if there's no link from *i*. All messages are listed in chronological order. It's guaranteed that the link from message *x* goes to message with number strictly less than *x*.
Output Specification:
Print *n* integers with *i*-th denoting the number of distinct messages you can read starting from message *i* and traversing the links while possible.
Demo Input:
['6 0\n0 1 1 2 3 2\n', '10 1\n0 1 0 3 4 5 2 3 7 0\n', '2 2\n0 1\n']
Demo Output:
['1 2 2 3 3 3 \n', '2 3 3 4 5 6 6 6 8 2 \n', '2 2 \n']
Note:
Consider *i* = 6 in sample case one. You will read message 6, then 2, then 1 and then there will be no link to go.
In the second sample case *i* = 6 gives you messages 5, 6, 7 since *k* = 1, then 4, 5, 6, then 2, 3, 4 and then the link sequence breaks. The number of distinct messages here is equal to 6. | ```python
s = input().split()
n = int(s[0])
k = int(s[1])
a = [int(i) for i in input().split()]
if n < k+2:
print(str(n)+(' ' + str(n))*(n-1))
else:
twok = k*2+1
counts = []
for i in range(1, k+2):
counts.append(i + k)
for i in range(k+2, n-k):
if a[i-1] == 0:
counts.append(twok)
else:
p = i - a[i-1]
if p < twok:
counts.append(counts[a[i-1]-1]+p)
else:
counts.append(counts[a[i-1]-1]+twok)
for i in range(n-k, n+1):
if a[i-1] == 0:
counts.append(n-i+1+k)
elif n-k < a[i-1]:
counts.append(counts[a[i-1]-1])
else:
p = i - a[i-1]
if p < twok:
counts.append(counts[a[i-1]-1]+n-i-k+p)
else:
counts.append(counts[a[i-1]-1]+n-i+1+k)
print(counts[0], end='')
[print(' ' + str(counts[i]), end='') for i in range(1,n)]
``` | 0 | |
228 | A | Is your horseshoe on the other hoof? | PROGRAMMING | 800 | [
"implementation"
] | null | null | Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to the store and buy some few more horseshoes, not to lose face in front of his stylish comrades.
Fortunately, the store sells horseshoes of all colors under the sun and Valera has enough money to buy any four of them. However, in order to save the money, he would like to spend as little money as possible, so you need to help Valera and determine what is the minimum number of horseshoes he needs to buy to wear four horseshoes of different colors to a party. | The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers. | Print a single integer — the minimum number of horseshoes Valera needs to buy. | [
"1 7 3 3\n",
"7 7 7 7\n"
] | [
"1\n",
"3\n"
] | none | 500 | [
{
"input": "1 7 3 3",
"output": "1"
},
{
"input": "7 7 7 7",
"output": "3"
},
{
"input": "81170865 673572653 756938629 995577259",
"output": "0"
},
{
"input": "3491663 217797045 522540872 715355328",
"output": "0"
},
{
"input": "251590420 586975278 916631563 58697... | 1,692,033,810 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 60 | 0 | def valerathehorse(shoes):
shoesNeed = 0
d = {}
for i in range(len(shoes)):
if d.get(shoes[i]):
d[n[i]] = 1
else:
shoesNeed += 1
print(shoesNeed)
if __name__ == "__main__":
shoes = list(map(int, input().split()))
valerathehorse(shoes) | Title: Is your horseshoe on the other hoof?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera the Horse is going to the party with friends. He has been following the fashion trends for a while, and he knows that it is very popular to wear all horseshoes of different color. Valera has got four horseshoes left from the last year, but maybe some of them have the same color. In this case he needs to go to the store and buy some few more horseshoes, not to lose face in front of his stylish comrades.
Fortunately, the store sells horseshoes of all colors under the sun and Valera has enough money to buy any four of them. However, in order to save the money, he would like to spend as little money as possible, so you need to help Valera and determine what is the minimum number of horseshoes he needs to buy to wear four horseshoes of different colors to a party.
Input Specification:
The first line contains four space-separated integers *s*1,<=*s*2,<=*s*3,<=*s*4 (1<=≤<=*s*1,<=*s*2,<=*s*3,<=*s*4<=≤<=109) — the colors of horseshoes Valera has.
Consider all possible colors indexed with integers.
Output Specification:
Print a single integer — the minimum number of horseshoes Valera needs to buy.
Demo Input:
['1 7 3 3\n', '7 7 7 7\n']
Demo Output:
['1\n', '3\n']
Note:
none | ```python
def valerathehorse(shoes):
shoesNeed = 0
d = {}
for i in range(len(shoes)):
if d.get(shoes[i]):
d[n[i]] = 1
else:
shoesNeed += 1
print(shoesNeed)
if __name__ == "__main__":
shoes = list(map(int, input().split()))
valerathehorse(shoes)
``` | 0 | |
855 | B | Marvolo Gaunt's Ring | PROGRAMMING | 1,500 | [
"brute force",
"data structures",
"dp"
] | null | null | Professor Dumbledore is helping Harry destroy the Horcruxes. He went to Gaunt Shack as he suspected a Horcrux to be present there. He saw Marvolo Gaunt's Ring and identified it as a Horcrux. Although he destroyed it, he is still affected by its curse. Professor Snape is helping Dumbledore remove the curse. For this, he wants to give Dumbledore exactly *x* drops of the potion he made.
Value of *x* is calculated as maximum of *p*·*a**i*<=+<=*q*·*a**j*<=+<=*r*·*a**k* for given *p*,<=*q*,<=*r* and array *a*1,<=*a*2,<=... *a**n* such that 1<=≤<=*i*<=≤<=*j*<=≤<=*k*<=≤<=*n*. Help Snape find the value of *x*. Do note that the value of *x* may be negative. | First line of input contains 4 integers *n*,<=*p*,<=*q*,<=*r* (<=-<=109<=≤<=*p*,<=*q*,<=*r*<=≤<=109,<=1<=≤<=*n*<=≤<=105).
Next line of input contains *n* space separated integers *a*1,<=*a*2,<=... *a**n* (<=-<=109<=≤<=*a**i*<=≤<=109). | Output a single integer the maximum value of *p*·*a**i*<=+<=*q*·*a**j*<=+<=*r*·*a**k* that can be obtained provided 1<=≤<=*i*<=≤<=*j*<=≤<=*k*<=≤<=*n*. | [
"5 1 2 3\n1 2 3 4 5\n",
"5 1 2 -3\n-1 -2 -3 -4 -5\n"
] | [
"30\n",
"12\n"
] | In the first sample case, we can take *i* = *j* = *k* = 5, thus making the answer as 1·5 + 2·5 + 3·5 = 30.
In second sample case, selecting *i* = *j* = 1 and *k* = 5 gives the answer 12. | 1,000 | [
{
"input": "5 1 2 3\n1 2 3 4 5",
"output": "30"
},
{
"input": "5 1 2 -3\n-1 -2 -3 -4 -5",
"output": "12"
},
{
"input": "5 886327859 82309257 -68295239\n-731225382 354766539 -48222231 -474691998 360965777",
"output": "376059240645059046"
},
{
"input": "4 -96405765 -495906217 6... | 1,648,179,190 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | def check_x():
params = input().split()
n, p, q, r = int(params[0]), int(params[1]), int(params[2]), int(params[3])
arr = input().split()
arr = [int(x) for x in arr]
x = find_x(p, q, r, arr)
print(x)
def find_x(p, q, r, a):
pqr = [p, q, r]
x = 0
# preprocess
overall_max = None
overall_min = None
has_zero = False
for i in range(len(a)):
# get overall max
if overall_max is None:
overall_max = a[i]
else:
overall_max = max(overall_max, a[i])
# get overall min
if overall_min is None:
overall_min = a[i]
else:
overall_min = min(overall_min, a[i])
# check for 0
if a[i] == 0:
has_zero = True
for num in pqr:
# num is positive
if num > 0:
x += num * overall_max
# num is negative
elif num < 0:
if overall_min < 0 or not has_zero:
x += num * overall_min
return x
check_x()
| Title: Marvolo Gaunt's Ring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor Dumbledore is helping Harry destroy the Horcruxes. He went to Gaunt Shack as he suspected a Horcrux to be present there. He saw Marvolo Gaunt's Ring and identified it as a Horcrux. Although he destroyed it, he is still affected by its curse. Professor Snape is helping Dumbledore remove the curse. For this, he wants to give Dumbledore exactly *x* drops of the potion he made.
Value of *x* is calculated as maximum of *p*·*a**i*<=+<=*q*·*a**j*<=+<=*r*·*a**k* for given *p*,<=*q*,<=*r* and array *a*1,<=*a*2,<=... *a**n* such that 1<=≤<=*i*<=≤<=*j*<=≤<=*k*<=≤<=*n*. Help Snape find the value of *x*. Do note that the value of *x* may be negative.
Input Specification:
First line of input contains 4 integers *n*,<=*p*,<=*q*,<=*r* (<=-<=109<=≤<=*p*,<=*q*,<=*r*<=≤<=109,<=1<=≤<=*n*<=≤<=105).
Next line of input contains *n* space separated integers *a*1,<=*a*2,<=... *a**n* (<=-<=109<=≤<=*a**i*<=≤<=109).
Output Specification:
Output a single integer the maximum value of *p*·*a**i*<=+<=*q*·*a**j*<=+<=*r*·*a**k* that can be obtained provided 1<=≤<=*i*<=≤<=*j*<=≤<=*k*<=≤<=*n*.
Demo Input:
['5 1 2 3\n1 2 3 4 5\n', '5 1 2 -3\n-1 -2 -3 -4 -5\n']
Demo Output:
['30\n', '12\n']
Note:
In the first sample case, we can take *i* = *j* = *k* = 5, thus making the answer as 1·5 + 2·5 + 3·5 = 30.
In second sample case, selecting *i* = *j* = 1 and *k* = 5 gives the answer 12. | ```python
def check_x():
params = input().split()
n, p, q, r = int(params[0]), int(params[1]), int(params[2]), int(params[3])
arr = input().split()
arr = [int(x) for x in arr]
x = find_x(p, q, r, arr)
print(x)
def find_x(p, q, r, a):
pqr = [p, q, r]
x = 0
# preprocess
overall_max = None
overall_min = None
has_zero = False
for i in range(len(a)):
# get overall max
if overall_max is None:
overall_max = a[i]
else:
overall_max = max(overall_max, a[i])
# get overall min
if overall_min is None:
overall_min = a[i]
else:
overall_min = min(overall_min, a[i])
# check for 0
if a[i] == 0:
has_zero = True
for num in pqr:
# num is positive
if num > 0:
x += num * overall_max
# num is negative
elif num < 0:
if overall_min < 0 or not has_zero:
x += num * overall_min
return x
check_x()
``` | 0 | |
682 | B | Alyona and Mex | PROGRAMMING | 1,200 | [
"sortings"
] | null | null | Someone gave Alyona an array containing *n* positive integers *a*1,<=*a*2,<=...,<=*a**n*. In one operation, Alyona can choose any element of the array and decrease it, i.e. replace with any positive integer that is smaller than the current one. Alyona can repeat this operation as many times as she wants. In particular, she may not apply any operation to the array at all.
Formally, after applying some operations Alyona will get an array of *n* positive integers *b*1,<=*b*2,<=...,<=*b**n* such that 1<=≤<=*b**i*<=≤<=*a**i* for every 1<=≤<=*i*<=≤<=*n*. Your task is to determine the maximum possible value of mex of this array.
Mex of an array in this problem is the minimum positive integer that doesn't appear in this array. For example, mex of the array containing 1, 3 and 4 is equal to 2, while mex of the array containing 2, 3 and 2 is equal to 1. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of elements in the Alyona's array.
The second line of the input contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the elements of the array. | Print one positive integer — the maximum possible value of mex of the array after Alyona applies some (possibly none) operations. | [
"5\n1 3 3 3 6\n",
"2\n2 1\n"
] | [
"5\n",
"3\n"
] | In the first sample case if one will decrease the second element value to 2 and the fifth element value to 4 then the mex value of resulting array 1 2 3 3 4 will be equal to 5.
To reach the answer to the second sample case one must not decrease any of the array elements. | 1,000 | [
{
"input": "5\n1 3 3 3 6",
"output": "5"
},
{
"input": "2\n2 1",
"output": "3"
},
{
"input": "1\n1",
"output": "2"
},
{
"input": "1\n1000000000",
"output": "2"
},
{
"input": "1\n2",
"output": "2"
},
{
"input": "2\n1 1",
"output": "2"
},
{
"... | 1,609,868,733 | 2,147,483,647 | PyPy 3 | OK | TESTS | 127 | 264 | 10,956,800 | # RawCoder : https://bit.ly/RCyouTube
# Author : MehulYK
n = int(input())
w = list(map(int,input().split()))
w.sort()
ans = 1
for i in w:
ans += i >= ans
print(ans) | Title: Alyona and Mex
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Someone gave Alyona an array containing *n* positive integers *a*1,<=*a*2,<=...,<=*a**n*. In one operation, Alyona can choose any element of the array and decrease it, i.e. replace with any positive integer that is smaller than the current one. Alyona can repeat this operation as many times as she wants. In particular, she may not apply any operation to the array at all.
Formally, after applying some operations Alyona will get an array of *n* positive integers *b*1,<=*b*2,<=...,<=*b**n* such that 1<=≤<=*b**i*<=≤<=*a**i* for every 1<=≤<=*i*<=≤<=*n*. Your task is to determine the maximum possible value of mex of this array.
Mex of an array in this problem is the minimum positive integer that doesn't appear in this array. For example, mex of the array containing 1, 3 and 4 is equal to 2, while mex of the array containing 2, 3 and 2 is equal to 1.
Input Specification:
The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of elements in the Alyona's array.
The second line of the input contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the elements of the array.
Output Specification:
Print one positive integer — the maximum possible value of mex of the array after Alyona applies some (possibly none) operations.
Demo Input:
['5\n1 3 3 3 6\n', '2\n2 1\n']
Demo Output:
['5\n', '3\n']
Note:
In the first sample case if one will decrease the second element value to 2 and the fifth element value to 4 then the mex value of resulting array 1 2 3 3 4 will be equal to 5.
To reach the answer to the second sample case one must not decrease any of the array elements. | ```python
# RawCoder : https://bit.ly/RCyouTube
# Author : MehulYK
n = int(input())
w = list(map(int,input().split()))
w.sort()
ans = 1
for i in w:
ans += i >= ans
print(ans)
``` | 3 | |
678 | C | Joty and Chocolate | PROGRAMMING | 1,600 | [
"implementation",
"math",
"number theory"
] | null | null | Little Joty has got a task to do. She has a line of *n* tiles indexed from 1 to *n*. She has to paint them in a strange pattern.
An unpainted tile should be painted Red if it's index is divisible by *a* and an unpainted tile should be painted Blue if it's index is divisible by *b*. So the tile with the number divisible by *a* and *b* can be either painted Red or Blue.
After her painting is done, she will get *p* chocolates for each tile that is painted Red and *q* chocolates for each tile that is painted Blue.
Note that she can paint tiles in any order she wants.
Given the required information, find the maximum number of chocolates Joty can get. | The only line contains five integers *n*, *a*, *b*, *p* and *q* (1<=≤<=*n*,<=*a*,<=*b*,<=*p*,<=*q*<=≤<=109). | Print the only integer *s* — the maximum number of chocolates Joty can get.
Note that the answer can be too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type. | [
"5 2 3 12 15\n",
"20 2 3 3 5\n"
] | [
"39\n",
"51\n"
] | none | 0 | [
{
"input": "5 2 3 12 15",
"output": "39"
},
{
"input": "20 2 3 3 5",
"output": "51"
},
{
"input": "1 1 1 1 1",
"output": "1"
},
{
"input": "1 2 2 2 2",
"output": "0"
},
{
"input": "2 1 3 3 3",
"output": "6"
},
{
"input": "3 1 1 3 3",
"output": "9"
... | 1,672,809,168 | 2,147,483,647 | Python 3 | OK | TESTS | 185 | 46 | 0 | from math import gcd
def lcm(a, b):
return a // gcd(a, b) * b
n, a, b, p, q = [int(i) for i in input().split()]
s3 = n // lcm(a, b)
s1 = n // a - s3
s2 = n // b - s3
s = s1 * p + s2 * q + max(p, q) * s3
print(s) | Title: Joty and Chocolate
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Joty has got a task to do. She has a line of *n* tiles indexed from 1 to *n*. She has to paint them in a strange pattern.
An unpainted tile should be painted Red if it's index is divisible by *a* and an unpainted tile should be painted Blue if it's index is divisible by *b*. So the tile with the number divisible by *a* and *b* can be either painted Red or Blue.
After her painting is done, she will get *p* chocolates for each tile that is painted Red and *q* chocolates for each tile that is painted Blue.
Note that she can paint tiles in any order she wants.
Given the required information, find the maximum number of chocolates Joty can get.
Input Specification:
The only line contains five integers *n*, *a*, *b*, *p* and *q* (1<=≤<=*n*,<=*a*,<=*b*,<=*p*,<=*q*<=≤<=109).
Output Specification:
Print the only integer *s* — the maximum number of chocolates Joty can get.
Note that the answer can be too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type.
Demo Input:
['5 2 3 12 15\n', '20 2 3 3 5\n']
Demo Output:
['39\n', '51\n']
Note:
none | ```python
from math import gcd
def lcm(a, b):
return a // gcd(a, b) * b
n, a, b, p, q = [int(i) for i in input().split()]
s3 = n // lcm(a, b)
s1 = n // a - s3
s2 = n // b - s3
s = s1 * p + s2 * q + max(p, q) * s3
print(s)
``` | 3 | |
103 | A | Testing Pants for Sadness | PROGRAMMING | 1,100 | [
"greedy",
"implementation",
"math"
] | A. Testing Pants for Sadness | 2 | 256 | The average miner Vaganych took refresher courses. As soon as a miner completes the courses, he should take exams. The hardest one is a computer test called "Testing Pants for Sadness".
The test consists of *n* questions; the questions are to be answered strictly in the order in which they are given, from question 1 to question *n*. Question *i* contains *a**i* answer variants, exactly one of them is correct.
A click is regarded as selecting any answer in any question. The goal is to select the correct answer for each of the *n* questions. If Vaganych selects a wrong answer for some question, then all selected answers become unselected and the test starts from the very beginning, from question 1 again. But Vaganych remembers everything. The order of answers for each question and the order of questions remain unchanged, as well as the question and answers themselves.
Vaganych is very smart and his memory is superb, yet he is unbelievably unlucky and knows nothing whatsoever about the test's theme. How many clicks will he have to perform in the worst case? | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100). It is the number of questions in the test. The second line contains space-separated *n* positive integers *a**i* (1<=≤<=*a**i*<=≤<=109), the number of answer variants to question *i*. | Print a single number — the minimal number of clicks needed to pass the test it the worst-case scenario.
Please do not use the %lld specificator to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specificator. | [
"2\n1 1\n",
"2\n2 2\n",
"1\n10\n"
] | [
"2",
"5",
"10"
] | Note to the second sample. In the worst-case scenario you will need five clicks:
- the first click selects the first variant to the first question, this answer turns out to be wrong. - the second click selects the second variant to the first question, it proves correct and we move on to the second question; - the third click selects the first variant to the second question, it is wrong and we go back to question 1; - the fourth click selects the second variant to the first question, it proves as correct as it was and we move on to the second question; - the fifth click selects the second variant to the second question, it proves correct, the test is finished. | 500 | [
{
"input": "2\n1 1",
"output": "2"
},
{
"input": "2\n2 2",
"output": "5"
},
{
"input": "1\n10",
"output": "10"
},
{
"input": "3\n2 4 1",
"output": "10"
},
{
"input": "4\n5 5 3 1",
"output": "22"
},
{
"input": "2\n1000000000 1000000000",
"output": "... | 1,595,836,810 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 216 | 6,656,000 | n = int(input())
a = list(map(int,input().split()))
s = 0
for i in range(len(a)):
s += (a[i]-1)*(i+1)+1
print(s)
| Title: Testing Pants for Sadness
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The average miner Vaganych took refresher courses. As soon as a miner completes the courses, he should take exams. The hardest one is a computer test called "Testing Pants for Sadness".
The test consists of *n* questions; the questions are to be answered strictly in the order in which they are given, from question 1 to question *n*. Question *i* contains *a**i* answer variants, exactly one of them is correct.
A click is regarded as selecting any answer in any question. The goal is to select the correct answer for each of the *n* questions. If Vaganych selects a wrong answer for some question, then all selected answers become unselected and the test starts from the very beginning, from question 1 again. But Vaganych remembers everything. The order of answers for each question and the order of questions remain unchanged, as well as the question and answers themselves.
Vaganych is very smart and his memory is superb, yet he is unbelievably unlucky and knows nothing whatsoever about the test's theme. How many clicks will he have to perform in the worst case?
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100). It is the number of questions in the test. The second line contains space-separated *n* positive integers *a**i* (1<=≤<=*a**i*<=≤<=109), the number of answer variants to question *i*.
Output Specification:
Print a single number — the minimal number of clicks needed to pass the test it the worst-case scenario.
Please do not use the %lld specificator to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specificator.
Demo Input:
['2\n1 1\n', '2\n2 2\n', '1\n10\n']
Demo Output:
['2', '5', '10']
Note:
Note to the second sample. In the worst-case scenario you will need five clicks:
- the first click selects the first variant to the first question, this answer turns out to be wrong. - the second click selects the second variant to the first question, it proves correct and we move on to the second question; - the third click selects the first variant to the second question, it is wrong and we go back to question 1; - the fourth click selects the second variant to the first question, it proves as correct as it was and we move on to the second question; - the fifth click selects the second variant to the second question, it proves correct, the test is finished. | ```python
n = int(input())
a = list(map(int,input().split()))
s = 0
for i in range(len(a)):
s += (a[i]-1)*(i+1)+1
print(s)
``` | 3.933602 |
841 | A | Generous Kefa | PROGRAMMING | 900 | [
"brute force",
"implementation"
] | null | null | One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his baloons, such that no one of his friens will be upset — print «YES», if he can, and «NO», otherwise. Note, that Kefa's friend will not upset, if he doesn't get baloons at all. | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends.
Next line contains string *s* — colors of baloons. | Answer to the task — «YES» or «NO» in a single line.
You can choose the case (lower or upper) for each letter arbitrary. | [
"4 2\naabb\n",
"6 3\naacaab\n"
] | [
"YES\n",
"NO\n"
] | In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second.
In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO». | 500 | [
{
"input": "4 2\naabb",
"output": "YES"
},
{
"input": "6 3\naacaab",
"output": "NO"
},
{
"input": "2 2\nlu",
"output": "YES"
},
{
"input": "5 3\novvoo",
"output": "YES"
},
{
"input": "36 13\nbzbzcffczzcbcbzzfzbbfzfzzbfbbcbfccbf",
"output": "YES"
},
{
"... | 1,586,042,559 | 2,147,483,647 | Python 3 | OK | TESTS | 114 | 109 | 0 | n, k = map(int, input().split())
s = input()
count = [0] * 26
for i in s:
nomer = ord(i) - 97
count[nomer] += 1
if max(count) > k:
print('NO')
else:
print('YES') | Title: Generous Kefa
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Kefa found *n* baloons. For convenience, we denote color of *i*-th baloon as *s**i* — lowercase letter of the Latin alphabet. Also Kefa has *k* friends. Friend will be upset, If he get two baloons of the same color. Kefa want to give out all baloons to his friends. Help Kefa to find out, can he give out all his baloons, such that no one of his friens will be upset — print «YES», if he can, and «NO», otherwise. Note, that Kefa's friend will not upset, if he doesn't get baloons at all.
Input Specification:
The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of baloons and friends.
Next line contains string *s* — colors of baloons.
Output Specification:
Answer to the task — «YES» or «NO» in a single line.
You can choose the case (lower or upper) for each letter arbitrary.
Demo Input:
['4 2\naabb\n', '6 3\naacaab\n']
Demo Output:
['YES\n', 'NO\n']
Note:
In the first sample Kefa can give 1-st and 3-rd baloon to the first friend, and 2-nd and 4-th to the second.
In the second sample Kefa needs to give to all his friends baloons of color a, but one baloon will stay, thats why answer is «NO». | ```python
n, k = map(int, input().split())
s = input()
count = [0] * 26
for i in s:
nomer = ord(i) - 97
count[nomer] += 1
if max(count) > k:
print('NO')
else:
print('YES')
``` | 3 | |
950 | A | Left-handers, Right-handers and Ambidexters | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.
The coach decided to form a team of even number of players, exactly half of the players should play with their right hand, and exactly half of the players should play with their left hand. One player should use only on of his hands.
Ambidexters play as well with their right hand as with their left hand. In the team, an ambidexter can play with their left hand, or with their right hand.
Please find the maximum possible size of the team, where equal number of players use their left and right hands, respectively. | The only line contains three integers *l*, *r* and *a* (0<=≤<=*l*,<=*r*,<=*a*<=≤<=100) — the number of left-handers, the number of right-handers and the number of ambidexters at the training. | Print a single even integer — the maximum number of players in the team. It is possible that the team can only have zero number of players. | [
"1 4 2\n",
"5 5 5\n",
"0 2 0\n"
] | [
"6\n",
"14\n",
"0\n"
] | In the first example you can form a team of 6 players. You should take the only left-hander and two ambidexters to play with left hand, and three right-handers to play with right hand. The only person left can't be taken into the team.
In the second example you can form a team of 14 people. You have to take all five left-handers, all five right-handers, two ambidexters to play with left hand and two ambidexters to play with right hand. | 500 | [
{
"input": "1 4 2",
"output": "6"
},
{
"input": "5 5 5",
"output": "14"
},
{
"input": "0 2 0",
"output": "0"
},
{
"input": "30 70 34",
"output": "128"
},
{
"input": "89 32 24",
"output": "112"
},
{
"input": "89 44 77",
"output": "210"
},
{
... | 1,595,625,344 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 124 | 20,172,800 | l, r, a = [int(x) for x in input().split()]
less = min(l, r)
more = max(l, r)
if less + a <= more: print(less + a)
print(more + (a - (more - less)) // 2) | Title: Left-handers, Right-handers and Ambidexters
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are at a water bowling training. There are *l* people who play with their left hand, *r* people, who play with their right hand, and *a* ambidexters, who can play with left or right hand.
The coach decided to form a team of even number of players, exactly half of the players should play with their right hand, and exactly half of the players should play with their left hand. One player should use only on of his hands.
Ambidexters play as well with their right hand as with their left hand. In the team, an ambidexter can play with their left hand, or with their right hand.
Please find the maximum possible size of the team, where equal number of players use their left and right hands, respectively.
Input Specification:
The only line contains three integers *l*, *r* and *a* (0<=≤<=*l*,<=*r*,<=*a*<=≤<=100) — the number of left-handers, the number of right-handers and the number of ambidexters at the training.
Output Specification:
Print a single even integer — the maximum number of players in the team. It is possible that the team can only have zero number of players.
Demo Input:
['1 4 2\n', '5 5 5\n', '0 2 0\n']
Demo Output:
['6\n', '14\n', '0\n']
Note:
In the first example you can form a team of 6 players. You should take the only left-hander and two ambidexters to play with left hand, and three right-handers to play with right hand. The only person left can't be taken into the team.
In the second example you can form a team of 14 people. You have to take all five left-handers, all five right-handers, two ambidexters to play with left hand and two ambidexters to play with right hand. | ```python
l, r, a = [int(x) for x in input().split()]
less = min(l, r)
more = max(l, r)
if less + a <= more: print(less + a)
print(more + (a - (more - less)) // 2)
``` | 0 | |
507 | B | Amr and Pins | PROGRAMMING | 1,400 | [
"geometry",
"math"
] | null | null | Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius *r* and center in point (*x*,<=*y*). He wants the circle center to be in new position (*x*',<=*y*').
In one step Amr can put a pin to the border of the circle in a certain point, then rotate the circle around that pin by any angle and finally remove the pin.
Help Amr to achieve his goal in minimum number of steps. | Input consists of 5 space-separated integers *r*, *x*, *y*, *x*' *y*' (1<=≤<=*r*<=≤<=105, <=-<=105<=≤<=*x*,<=*y*,<=*x*',<=*y*'<=≤<=105), circle radius, coordinates of original center of the circle and coordinates of destination center of the circle respectively. | Output a single integer — minimum number of steps required to move the center of the circle to the destination point. | [
"2 0 0 0 4\n",
"1 1 1 4 4\n",
"4 5 6 5 6\n"
] | [
"1\n",
"3\n",
"0\n"
] | In the first sample test the optimal way is to put a pin at point (0, 2) and rotate the circle by 180 degrees counter-clockwise (or clockwise, no matter).
<img class="tex-graphics" src="https://espresso.codeforces.com/4e40fd4cc24a2050a0488aa131e6244369328039.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "2 0 0 0 4",
"output": "1"
},
{
"input": "1 1 1 4 4",
"output": "3"
},
{
"input": "4 5 6 5 6",
"output": "0"
},
{
"input": "10 20 0 40 0",
"output": "1"
},
{
"input": "9 20 0 40 0",
"output": "2"
},
{
"input": "5 -1 -6 -5 1",
"output": "... | 1,695,393,013 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 46 | 0 | import math
r, x, y, x_, y_ = map(int, input().split())
D = 2*r
d = math.sqrt((x-x_)**2 + (y-y_)**2)
print(math.ceil(d/D)) | Title: Amr and Pins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr loves Geometry. One day he came up with a very interesting problem.
Amr has a circle of radius *r* and center in point (*x*,<=*y*). He wants the circle center to be in new position (*x*',<=*y*').
In one step Amr can put a pin to the border of the circle in a certain point, then rotate the circle around that pin by any angle and finally remove the pin.
Help Amr to achieve his goal in minimum number of steps.
Input Specification:
Input consists of 5 space-separated integers *r*, *x*, *y*, *x*' *y*' (1<=≤<=*r*<=≤<=105, <=-<=105<=≤<=*x*,<=*y*,<=*x*',<=*y*'<=≤<=105), circle radius, coordinates of original center of the circle and coordinates of destination center of the circle respectively.
Output Specification:
Output a single integer — minimum number of steps required to move the center of the circle to the destination point.
Demo Input:
['2 0 0 0 4\n', '1 1 1 4 4\n', '4 5 6 5 6\n']
Demo Output:
['1\n', '3\n', '0\n']
Note:
In the first sample test the optimal way is to put a pin at point (0, 2) and rotate the circle by 180 degrees counter-clockwise (or clockwise, no matter).
<img class="tex-graphics" src="https://espresso.codeforces.com/4e40fd4cc24a2050a0488aa131e6244369328039.png" style="max-width: 100.0%;max-height: 100.0%;"/> | ```python
import math
r, x, y, x_, y_ = map(int, input().split())
D = 2*r
d = math.sqrt((x-x_)**2 + (y-y_)**2)
print(math.ceil(d/D))
``` | 3 | |
1,000 | B | Light It Up | PROGRAMMING | 1,500 | [
"greedy"
] | null | null | Recently, you bought a brand new smart lamp with programming features. At first, you set up a schedule to the lamp. Every day it will turn power on at moment $0$ and turn power off at moment $M$. Moreover, the lamp allows you to set a program of switching its state (states are "lights on" and "lights off"). Unfortunately, some program is already installed into the lamp.
The lamp allows only good programs. Good program can be represented as a non-empty array $a$, where $0 < a_1 < a_2 < \dots < a_{|a|} < M$. All $a_i$ must be integers. Of course, preinstalled program is a good program.
The lamp follows program $a$ in next manner: at moment $0$ turns power and light on. Then at moment $a_i$ the lamp flips its state to opposite (if it was lit, it turns off, and vice versa). The state of the lamp flips instantly: for example, if you turn the light off at moment $1$ and then do nothing, the total time when the lamp is lit will be $1$. Finally, at moment $M$ the lamp is turning its power off regardless of its state.
Since you are not among those people who read instructions, and you don't understand the language it's written in, you realize (after some testing) the only possible way to alter the preinstalled program. You can insert at most one element into the program $a$, so it still should be a good program after alteration. Insertion can be done between any pair of consecutive elements of $a$, or even at the begining or at the end of $a$.
Find such a way to alter the program that the total time when the lamp is lit is maximum possible. Maybe you should leave program untouched. If the lamp is lit from $x$ till moment $y$, then its lit for $y - x$ units of time. Segments of time when the lamp is lit are summed up. | First line contains two space separated integers $n$ and $M$ ($1 \le n \le 10^5$, $2 \le M \le 10^9$) — the length of program $a$ and the moment when power turns off.
Second line contains $n$ space separated integers $a_1, a_2, \dots, a_n$ ($0 < a_1 < a_2 < \dots < a_n < M$) — initially installed program $a$. | Print the only integer — maximum possible total time when the lamp is lit. | [
"3 10\n4 6 7\n",
"2 12\n1 10\n",
"2 7\n3 4\n"
] | [
"8\n",
"9\n",
"6\n"
] | In the first example, one of possible optimal solutions is to insert value $x = 3$ before $a_1$, so program will be $[3, 4, 6, 7]$ and time of lamp being lit equals $(3 - 0) + (6 - 4) + (10 - 7) = 8$. Other possible solution is to insert $x = 5$ in appropriate place.
In the second example, there is only one optimal solution: to insert $x = 2$ between $a_1$ and $a_2$. Program will become $[1, 2, 10]$, and answer will be $(1 - 0) + (10 - 2) = 9$.
In the third example, optimal answer is to leave program untouched, so answer will be $(3 - 0) + (7 - 4) = 6$. | 0 | [
{
"input": "3 10\n4 6 7",
"output": "8"
},
{
"input": "2 12\n1 10",
"output": "9"
},
{
"input": "2 7\n3 4",
"output": "6"
},
{
"input": "1 2\n1",
"output": "1"
},
{
"input": "5 10\n1 3 5 6 8",
"output": "6"
},
{
"input": "7 1000000000\n1 10001 10011 20... | 1,635,408,415 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 155 | 12,902,400 | n, M = map(int, input().split())
a = [int(x) for x in input().split()]
a.append(0)
a.append(M)
a.sort()
on = 0
for i in range(1, len(a), 2):
on += a[i] - a[i-1]
h = on
s = 0
for i in range(2, len(a), 2):
s += a[i-1] - a[i-2]
t = on - s
h = max(h, s + M-a[i-1]-t - 1)
print(h) | Title: Light It Up
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently, you bought a brand new smart lamp with programming features. At first, you set up a schedule to the lamp. Every day it will turn power on at moment $0$ and turn power off at moment $M$. Moreover, the lamp allows you to set a program of switching its state (states are "lights on" and "lights off"). Unfortunately, some program is already installed into the lamp.
The lamp allows only good programs. Good program can be represented as a non-empty array $a$, where $0 < a_1 < a_2 < \dots < a_{|a|} < M$. All $a_i$ must be integers. Of course, preinstalled program is a good program.
The lamp follows program $a$ in next manner: at moment $0$ turns power and light on. Then at moment $a_i$ the lamp flips its state to opposite (if it was lit, it turns off, and vice versa). The state of the lamp flips instantly: for example, if you turn the light off at moment $1$ and then do nothing, the total time when the lamp is lit will be $1$. Finally, at moment $M$ the lamp is turning its power off regardless of its state.
Since you are not among those people who read instructions, and you don't understand the language it's written in, you realize (after some testing) the only possible way to alter the preinstalled program. You can insert at most one element into the program $a$, so it still should be a good program after alteration. Insertion can be done between any pair of consecutive elements of $a$, or even at the begining or at the end of $a$.
Find such a way to alter the program that the total time when the lamp is lit is maximum possible. Maybe you should leave program untouched. If the lamp is lit from $x$ till moment $y$, then its lit for $y - x$ units of time. Segments of time when the lamp is lit are summed up.
Input Specification:
First line contains two space separated integers $n$ and $M$ ($1 \le n \le 10^5$, $2 \le M \le 10^9$) — the length of program $a$ and the moment when power turns off.
Second line contains $n$ space separated integers $a_1, a_2, \dots, a_n$ ($0 < a_1 < a_2 < \dots < a_n < M$) — initially installed program $a$.
Output Specification:
Print the only integer — maximum possible total time when the lamp is lit.
Demo Input:
['3 10\n4 6 7\n', '2 12\n1 10\n', '2 7\n3 4\n']
Demo Output:
['8\n', '9\n', '6\n']
Note:
In the first example, one of possible optimal solutions is to insert value $x = 3$ before $a_1$, so program will be $[3, 4, 6, 7]$ and time of lamp being lit equals $(3 - 0) + (6 - 4) + (10 - 7) = 8$. Other possible solution is to insert $x = 5$ in appropriate place.
In the second example, there is only one optimal solution: to insert $x = 2$ between $a_1$ and $a_2$. Program will become $[1, 2, 10]$, and answer will be $(1 - 0) + (10 - 2) = 9$.
In the third example, optimal answer is to leave program untouched, so answer will be $(3 - 0) + (7 - 4) = 6$. | ```python
n, M = map(int, input().split())
a = [int(x) for x in input().split()]
a.append(0)
a.append(M)
a.sort()
on = 0
for i in range(1, len(a), 2):
on += a[i] - a[i-1]
h = on
s = 0
for i in range(2, len(a), 2):
s += a[i-1] - a[i-2]
t = on - s
h = max(h, s + M-a[i-1]-t - 1)
print(h)
``` | 3 | |
931 | A | Friends Meeting | PROGRAMMING | 800 | [
"brute force",
"greedy",
"implementation",
"math"
] | null | null | Two friends are on the coordinate axis *Ox* in points with integer coordinates. One of them is in the point *x*1<==<=*a*, another one is in the point *x*2<==<=*b*.
Each of the friends can move by one along the line in any direction unlimited number of times. When a friend moves, the tiredness of a friend changes according to the following rules: the first move increases the tiredness by 1, the second move increases the tiredness by 2, the third — by 3 and so on. For example, if a friend moves first to the left, then to the right (returning to the same point), and then again to the left his tiredness becomes equal to 1<=+<=2<=+<=3<==<=6.
The friends want to meet in a integer point. Determine the minimum total tiredness they should gain, if they meet in the same point. | The first line contains a single integer *a* (1<=≤<=*a*<=≤<=1000) — the initial position of the first friend.
The second line contains a single integer *b* (1<=≤<=*b*<=≤<=1000) — the initial position of the second friend.
It is guaranteed that *a*<=≠<=*b*. | Print the minimum possible total tiredness if the friends meet in the same point. | [
"3\n4\n",
"101\n99\n",
"5\n10\n"
] | [
"1\n",
"2\n",
"9\n"
] | In the first example the first friend should move by one to the right (then the meeting happens at point 4), or the second friend should move by one to the left (then the meeting happens at point 3). In both cases, the total tiredness becomes 1.
In the second example the first friend should move by one to the left, and the second friend should move by one to the right. Then they meet in the point 100, and the total tiredness becomes 1 + 1 = 2.
In the third example one of the optimal ways is the following. The first friend should move three times to the right, and the second friend — two times to the left. Thus the friends meet in the point 8, and the total tiredness becomes 1 + 2 + 3 + 1 + 2 = 9. | 500 | [
{
"input": "3\n4",
"output": "1"
},
{
"input": "101\n99",
"output": "2"
},
{
"input": "5\n10",
"output": "9"
},
{
"input": "1\n2",
"output": "1"
},
{
"input": "1\n1000",
"output": "250000"
},
{
"input": "999\n1000",
"output": "1"
},
{
"inpu... | 1,576,020,936 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 124 | 0 | a = int(input())
b = int(input())
d = abs(a - b)
r = d // 2
res = r * (r + 1) // 2 + (r + 1) * (r + 2) //2
print(res) | Title: Friends Meeting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two friends are on the coordinate axis *Ox* in points with integer coordinates. One of them is in the point *x*1<==<=*a*, another one is in the point *x*2<==<=*b*.
Each of the friends can move by one along the line in any direction unlimited number of times. When a friend moves, the tiredness of a friend changes according to the following rules: the first move increases the tiredness by 1, the second move increases the tiredness by 2, the third — by 3 and so on. For example, if a friend moves first to the left, then to the right (returning to the same point), and then again to the left his tiredness becomes equal to 1<=+<=2<=+<=3<==<=6.
The friends want to meet in a integer point. Determine the minimum total tiredness they should gain, if they meet in the same point.
Input Specification:
The first line contains a single integer *a* (1<=≤<=*a*<=≤<=1000) — the initial position of the first friend.
The second line contains a single integer *b* (1<=≤<=*b*<=≤<=1000) — the initial position of the second friend.
It is guaranteed that *a*<=≠<=*b*.
Output Specification:
Print the minimum possible total tiredness if the friends meet in the same point.
Demo Input:
['3\n4\n', '101\n99\n', '5\n10\n']
Demo Output:
['1\n', '2\n', '9\n']
Note:
In the first example the first friend should move by one to the right (then the meeting happens at point 4), or the second friend should move by one to the left (then the meeting happens at point 3). In both cases, the total tiredness becomes 1.
In the second example the first friend should move by one to the left, and the second friend should move by one to the right. Then they meet in the point 100, and the total tiredness becomes 1 + 1 = 2.
In the third example one of the optimal ways is the following. The first friend should move three times to the right, and the second friend — two times to the left. Thus the friends meet in the point 8, and the total tiredness becomes 1 + 2 + 3 + 1 + 2 = 9. | ```python
a = int(input())
b = int(input())
d = abs(a - b)
r = d // 2
res = r * (r + 1) // 2 + (r + 1) * (r + 2) //2
print(res)
``` | 0 | |
116 | A | Tram | PROGRAMMING | 800 | [
"implementation"
] | null | null | Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it arrives at the first stop. Also, when the tram arrives at the last stop, all passengers exit so that it becomes empty.
Your task is to calculate the tram's minimum capacity such that the number of people inside the tram at any time never exceeds this capacity. Note that at each stop all exiting passengers exit before any entering passenger enters the tram. | The first line contains a single number *n* (2<=≤<=*n*<=≤<=1000) — the number of the tram's stops.
Then *n* lines follow, each contains two integers *a**i* and *b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the number of passengers that exits the tram at the *i*-th stop, and the number of passengers that enter the tram at the *i*-th stop. The stops are given from the first to the last stop in the order of tram's movement.
- The number of people who exit at a given stop does not exceed the total number of people in the tram immediately before it arrives at the stop. More formally, . This particularly means that *a*1<==<=0. - At the last stop, all the passengers exit the tram and it becomes empty. More formally, . - No passenger will enter the train at the last stop. That is, *b**n*<==<=0. | Print a single integer denoting the minimum possible capacity of the tram (0 is allowed). | [
"4\n0 3\n2 5\n4 2\n4 0\n"
] | [
"6\n"
] | For the first example, a capacity of 6 is sufficient:
- At the first stop, the number of passengers inside the tram before arriving is 0. Then, 3 passengers enter the tram, and the number of passengers inside the tram becomes 3. - At the second stop, 2 passengers exit the tram (1 passenger remains inside). Then, 5 passengers enter the tram. There are 6 passengers inside the tram now. - At the third stop, 4 passengers exit the tram (2 passengers remain inside). Then, 2 passengers enter the tram. There are 4 passengers inside the tram now. - Finally, all the remaining passengers inside the tram exit the tram at the last stop. There are no passenger inside the tram now, which is in line with the constraints.
Since the number of passengers inside the tram never exceeds 6, a capacity of 6 is sufficient. Furthermore it is not possible for the tram to have a capacity less than 6. Hence, 6 is the correct answer. | 500 | [
{
"input": "4\n0 3\n2 5\n4 2\n4 0",
"output": "6"
},
{
"input": "5\n0 4\n4 6\n6 5\n5 4\n4 0",
"output": "6"
},
{
"input": "10\n0 5\n1 7\n10 8\n5 3\n0 5\n3 3\n8 8\n0 6\n10 1\n9 0",
"output": "18"
},
{
"input": "3\n0 1\n1 1\n1 0",
"output": "1"
},
{
"input": "4\n0 1... | 1,697,985,149 | 2,147,483,647 | PyPy 3 | OK | TESTS | 71 | 278 | 1,536,000 | m = 0
c = 0
for i in range(int(input())):
a,b = [int(x) for x in input().split()]
c += b-a
m = max(m,c)
print(m) | Title: Tram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Linear Kingdom has exactly one tram line. It has *n* stops, numbered from 1 to *n* in the order of tram's movement. At the *i*-th stop *a**i* passengers exit the tram, while *b**i* passengers enter it. The tram is empty before it arrives at the first stop. Also, when the tram arrives at the last stop, all passengers exit so that it becomes empty.
Your task is to calculate the tram's minimum capacity such that the number of people inside the tram at any time never exceeds this capacity. Note that at each stop all exiting passengers exit before any entering passenger enters the tram.
Input Specification:
The first line contains a single number *n* (2<=≤<=*n*<=≤<=1000) — the number of the tram's stops.
Then *n* lines follow, each contains two integers *a**i* and *b**i* (0<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the number of passengers that exits the tram at the *i*-th stop, and the number of passengers that enter the tram at the *i*-th stop. The stops are given from the first to the last stop in the order of tram's movement.
- The number of people who exit at a given stop does not exceed the total number of people in the tram immediately before it arrives at the stop. More formally, . This particularly means that *a*1<==<=0. - At the last stop, all the passengers exit the tram and it becomes empty. More formally, . - No passenger will enter the train at the last stop. That is, *b**n*<==<=0.
Output Specification:
Print a single integer denoting the minimum possible capacity of the tram (0 is allowed).
Demo Input:
['4\n0 3\n2 5\n4 2\n4 0\n']
Demo Output:
['6\n']
Note:
For the first example, a capacity of 6 is sufficient:
- At the first stop, the number of passengers inside the tram before arriving is 0. Then, 3 passengers enter the tram, and the number of passengers inside the tram becomes 3. - At the second stop, 2 passengers exit the tram (1 passenger remains inside). Then, 5 passengers enter the tram. There are 6 passengers inside the tram now. - At the third stop, 4 passengers exit the tram (2 passengers remain inside). Then, 2 passengers enter the tram. There are 4 passengers inside the tram now. - Finally, all the remaining passengers inside the tram exit the tram at the last stop. There are no passenger inside the tram now, which is in line with the constraints.
Since the number of passengers inside the tram never exceeds 6, a capacity of 6 is sufficient. Furthermore it is not possible for the tram to have a capacity less than 6. Hence, 6 is the correct answer. | ```python
m = 0
c = 0
for i in range(int(input())):
a,b = [int(x) for x in input().split()]
c += b-a
m = max(m,c)
print(m)
``` | 3 | |
439 | A | Devu, the Singer and Churu, the Joker | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invited.
Devu has provided organizers a list of the songs and required time for singing them. He will sing *n* songs, *i**th* song will take *t**i* minutes exactly.
The Comedian, Churu will crack jokes. All his jokes are of 5 minutes exactly.
People have mainly come to listen Devu. But you know that he needs rest of 10 minutes after each song. On the other hand, Churu being a very active person, doesn't need any rest.
You as one of the organizers should make an optimal sсhedule for the event. For some reasons you must follow the conditions:
- The duration of the event must be no more than *d* minutes; - Devu must complete all his songs; - With satisfying the two previous conditions the number of jokes cracked by Churu should be as many as possible.
If it is not possible to find a way to conduct all the songs of the Devu, output -1. Otherwise find out maximum number of jokes that Churu can crack in the grand event. | The first line contains two space separated integers *n*, *d* (1<=≤<=*n*<=≤<=100; 1<=≤<=*d*<=≤<=10000). The second line contains *n* space-separated integers: *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=100). | If there is no way to conduct all the songs of Devu, output -1. Otherwise output the maximum number of jokes that Churu can crack in the grand event. | [
"3 30\n2 2 1\n",
"3 20\n2 1 1\n"
] | [
"5\n",
"-1\n"
] | Consider the first example. The duration of the event is 30 minutes. There could be maximum 5 jokes in the following way:
- First Churu cracks a joke in 5 minutes. - Then Devu performs the first song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now Devu performs second song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now finally Devu will perform his last song in 1 minutes.
Total time spent is 5 + 2 + 10 + 2 + 10 + 1 = 30 minutes.
Consider the second example. There is no way of organizing Devu's all songs. Hence the answer is -1. | 500 | [
{
"input": "3 30\n2 2 1",
"output": "5"
},
{
"input": "3 20\n2 1 1",
"output": "-1"
},
{
"input": "50 10000\n5 4 10 9 9 6 7 7 7 3 3 7 7 4 7 4 10 10 1 7 10 3 1 4 5 7 2 10 10 10 2 3 4 7 6 1 8 4 7 3 8 8 4 10 1 1 9 2 6 1",
"output": "1943"
},
{
"input": "50 10000\n4 7 15 9 11 12 ... | 1,605,383,543 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 93 | 307,200 | def solve(d,t):
info1 = d.split()
info2 = t.split()
a = [int(x) for x in info2]
diff = int(info1[1]) - sum(a) - 10*(len(a)-1)
if diff >= 0:
num = diff // 5
num_plus = diff % 5
number_of_jokes = 5*num + num_plus
return number_of_jokes
else:
return -1
d = input()
t = input()
print(solve(d,t)) | Title: Devu, the Singer and Churu, the Joker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invited.
Devu has provided organizers a list of the songs and required time for singing them. He will sing *n* songs, *i**th* song will take *t**i* minutes exactly.
The Comedian, Churu will crack jokes. All his jokes are of 5 minutes exactly.
People have mainly come to listen Devu. But you know that he needs rest of 10 minutes after each song. On the other hand, Churu being a very active person, doesn't need any rest.
You as one of the organizers should make an optimal sсhedule for the event. For some reasons you must follow the conditions:
- The duration of the event must be no more than *d* minutes; - Devu must complete all his songs; - With satisfying the two previous conditions the number of jokes cracked by Churu should be as many as possible.
If it is not possible to find a way to conduct all the songs of the Devu, output -1. Otherwise find out maximum number of jokes that Churu can crack in the grand event.
Input Specification:
The first line contains two space separated integers *n*, *d* (1<=≤<=*n*<=≤<=100; 1<=≤<=*d*<=≤<=10000). The second line contains *n* space-separated integers: *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=100).
Output Specification:
If there is no way to conduct all the songs of Devu, output -1. Otherwise output the maximum number of jokes that Churu can crack in the grand event.
Demo Input:
['3 30\n2 2 1\n', '3 20\n2 1 1\n']
Demo Output:
['5\n', '-1\n']
Note:
Consider the first example. The duration of the event is 30 minutes. There could be maximum 5 jokes in the following way:
- First Churu cracks a joke in 5 minutes. - Then Devu performs the first song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now Devu performs second song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now finally Devu will perform his last song in 1 minutes.
Total time spent is 5 + 2 + 10 + 2 + 10 + 1 = 30 minutes.
Consider the second example. There is no way of organizing Devu's all songs. Hence the answer is -1. | ```python
def solve(d,t):
info1 = d.split()
info2 = t.split()
a = [int(x) for x in info2]
diff = int(info1[1]) - sum(a) - 10*(len(a)-1)
if diff >= 0:
num = diff // 5
num_plus = diff % 5
number_of_jokes = 5*num + num_plus
return number_of_jokes
else:
return -1
d = input()
t = input()
print(solve(d,t))
``` | 0 | |
946 | A | Partition | PROGRAMMING | 800 | [
"greedy"
] | null | null | You are given a sequence *a* consisting of *n* integers. You may partition this sequence into two sequences *b* and *c* in such a way that every element belongs exactly to one of these sequences.
Let *B* be the sum of elements belonging to *b*, and *C* be the sum of elements belonging to *c* (if some of these sequences is empty, then its sum is 0). What is the maximum possible value of *B*<=-<=*C*? | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in *a*.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (<=-<=100<=≤<=*a**i*<=≤<=100) — the elements of sequence *a*. | Print the maximum possible value of *B*<=-<=*C*, where *B* is the sum of elements of sequence *b*, and *C* is the sum of elements of sequence *c*. | [
"3\n1 -2 0\n",
"6\n16 23 16 15 42 8\n"
] | [
"3\n",
"120\n"
] | In the first example we may choose *b* = {1, 0}, *c* = { - 2}. Then *B* = 1, *C* = - 2, *B* - *C* = 3.
In the second example we choose *b* = {16, 23, 16, 15, 42, 8}, *c* = {} (an empty sequence). Then *B* = 120, *C* = 0, *B* - *C* = 120. | 0 | [
{
"input": "3\n1 -2 0",
"output": "3"
},
{
"input": "6\n16 23 16 15 42 8",
"output": "120"
},
{
"input": "1\n-1",
"output": "1"
},
{
"input": "100\n-100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -100 -10... | 1,601,196,895 | 2,147,483,647 | Python 3 | OK | TESTS | 72 | 109 | 0 | n=int(input())
A=input().split()
B,C=[],[]
for i in range(n):
A[i]=int(A[i])
if A[i]>0:
B.append(A[i])
else:
C.append(A[i])
print(sum(B)-sum(C))
| Title: Partition
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a sequence *a* consisting of *n* integers. You may partition this sequence into two sequences *b* and *c* in such a way that every element belongs exactly to one of these sequences.
Let *B* be the sum of elements belonging to *b*, and *C* be the sum of elements belonging to *c* (if some of these sequences is empty, then its sum is 0). What is the maximum possible value of *B*<=-<=*C*?
Input Specification:
The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in *a*.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (<=-<=100<=≤<=*a**i*<=≤<=100) — the elements of sequence *a*.
Output Specification:
Print the maximum possible value of *B*<=-<=*C*, where *B* is the sum of elements of sequence *b*, and *C* is the sum of elements of sequence *c*.
Demo Input:
['3\n1 -2 0\n', '6\n16 23 16 15 42 8\n']
Demo Output:
['3\n', '120\n']
Note:
In the first example we may choose *b* = {1, 0}, *c* = { - 2}. Then *B* = 1, *C* = - 2, *B* - *C* = 3.
In the second example we choose *b* = {16, 23, 16, 15, 42, 8}, *c* = {} (an empty sequence). Then *B* = 120, *C* = 0, *B* - *C* = 120. | ```python
n=int(input())
A=input().split()
B,C=[],[]
for i in range(n):
A[i]=int(A[i])
if A[i]>0:
B.append(A[i])
else:
C.append(A[i])
print(sum(B)-sum(C))
``` | 3 | |
959 | A | Mahmoud and Ehab and the even-odd game | PROGRAMMING | 800 | [
"games",
"math"
] | null | null | Mahmoud and Ehab play a game called the even-odd game. Ehab chooses his favorite integer *n* and then they take turns, starting from Mahmoud. In each player's turn, he has to choose an integer *a* and subtract it from *n* such that:
- 1<=≤<=*a*<=≤<=*n*. - If it's Mahmoud's turn, *a* has to be even, but if it's Ehab's turn, *a* has to be odd.
If the current player can't choose any number satisfying the conditions, he loses. Can you determine the winner if they both play optimally? | The only line contains an integer *n* (1<=≤<=*n*<=≤<=109), the number at the beginning of the game. | Output "Mahmoud" (without quotes) if Mahmoud wins and "Ehab" (without quotes) otherwise. | [
"1\n",
"2\n"
] | [
"Ehab",
"Mahmoud"
] | In the first sample, Mahmoud can't choose any integer *a* initially because there is no positive even integer less than or equal to 1 so Ehab wins.
In the second sample, Mahmoud has to choose *a* = 2 and subtract it from *n*. It's Ehab's turn and *n* = 0. There is no positive odd integer less than or equal to 0 so Mahmoud wins. | 500 | [
{
"input": "1",
"output": "Ehab"
},
{
"input": "2",
"output": "Mahmoud"
},
{
"input": "10000",
"output": "Mahmoud"
},
{
"input": "33333",
"output": "Ehab"
},
{
"input": "5",
"output": "Ehab"
},
{
"input": "1000000000",
"output": "Mahmoud"
},
{
... | 1,656,133,288 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | print'Mahmoud'if input()%2==0 else'Ehab'
| Title: Mahmoud and Ehab and the even-odd game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mahmoud and Ehab play a game called the even-odd game. Ehab chooses his favorite integer *n* and then they take turns, starting from Mahmoud. In each player's turn, he has to choose an integer *a* and subtract it from *n* such that:
- 1<=≤<=*a*<=≤<=*n*. - If it's Mahmoud's turn, *a* has to be even, but if it's Ehab's turn, *a* has to be odd.
If the current player can't choose any number satisfying the conditions, he loses. Can you determine the winner if they both play optimally?
Input Specification:
The only line contains an integer *n* (1<=≤<=*n*<=≤<=109), the number at the beginning of the game.
Output Specification:
Output "Mahmoud" (without quotes) if Mahmoud wins and "Ehab" (without quotes) otherwise.
Demo Input:
['1\n', '2\n']
Demo Output:
['Ehab', 'Mahmoud']
Note:
In the first sample, Mahmoud can't choose any integer *a* initially because there is no positive even integer less than or equal to 1 so Ehab wins.
In the second sample, Mahmoud has to choose *a* = 2 and subtract it from *n*. It's Ehab's turn and *n* = 0. There is no positive odd integer less than or equal to 0 so Mahmoud wins. | ```python
print'Mahmoud'if input()%2==0 else'Ehab'
``` | -1 | |
266 | A | Stones on the Table | PROGRAMMING | 800 | [
"implementation"
] | null | null | There are *n* stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row are considered neighboring if there are no other stones between them. | The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of stones on the table.
The next line contains string *s*, which represents the colors of the stones. We'll consider the stones in the row numbered from 1 to *n* from left to right. Then the *i*-th character *s* equals "R", if the *i*-th stone is red, "G", if it's green and "B", if it's blue. | Print a single integer — the answer to the problem. | [
"3\nRRG\n",
"5\nRRRRR\n",
"4\nBRBG\n"
] | [
"1\n",
"4\n",
"0\n"
] | none | 500 | [
{
"input": "3\nRRG",
"output": "1"
},
{
"input": "5\nRRRRR",
"output": "4"
},
{
"input": "4\nBRBG",
"output": "0"
},
{
"input": "1\nB",
"output": "0"
},
{
"input": "2\nBG",
"output": "0"
},
{
"input": "3\nBGB",
"output": "0"
},
{
"input": "... | 1,698,143,439 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 62 | 0 | san = int(input())
soz = input()
count = 0
for i in range(len(soz)):
if soz[i] == soz[i-1]:
count+=1
print(count) | Title: Stones on the Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row are considered neighboring if there are no other stones between them.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of stones on the table.
The next line contains string *s*, which represents the colors of the stones. We'll consider the stones in the row numbered from 1 to *n* from left to right. Then the *i*-th character *s* equals "R", if the *i*-th stone is red, "G", if it's green and "B", if it's blue.
Output Specification:
Print a single integer — the answer to the problem.
Demo Input:
['3\nRRG\n', '5\nRRRRR\n', '4\nBRBG\n']
Demo Output:
['1\n', '4\n', '0\n']
Note:
none | ```python
san = int(input())
soz = input()
count = 0
for i in range(len(soz)):
if soz[i] == soz[i-1]:
count+=1
print(count)
``` | 0 | |
146 | A | Lucky Ticket | PROGRAMMING | 800 | [
"implementation"
] | null | null | Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya loves tickets very much. As we know, each ticket has a number that is a positive integer. Its length equals *n* (*n* is always even). Petya calls a ticket lucky if the ticket's number is a lucky number and the sum of digits in the first half (the sum of the first *n*<=/<=2 digits) equals the sum of digits in the second half (the sum of the last *n*<=/<=2 digits). Check if the given ticket is lucky. | The first line contains an even integer *n* (2<=≤<=*n*<=≤<=50) — the length of the ticket number that needs to be checked. The second line contains an integer whose length equals exactly *n* — the ticket number. The number may contain leading zeros. | On the first line print "YES" if the given ticket number is lucky. Otherwise, print "NO" (without the quotes). | [
"2\n47\n",
"4\n4738\n",
"4\n4774\n"
] | [
"NO\n",
"NO\n",
"YES\n"
] | In the first sample the sum of digits in the first half does not equal the sum of digits in the second half (4 ≠ 7).
In the second sample the ticket number is not the lucky number. | 500 | [
{
"input": "2\n47",
"output": "NO"
},
{
"input": "4\n4738",
"output": "NO"
},
{
"input": "4\n4774",
"output": "YES"
},
{
"input": "4\n4570",
"output": "NO"
},
{
"input": "6\n477477",
"output": "YES"
},
{
"input": "6\n777777",
"output": "YES"
},
... | 1,470,927,759 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 122 | 4,608,000 | n=int(input())
s=input()
s1=0
s2=0
for i in range(n//2):
if s[i]!=s[n-i-1]:
import sys
print('NO')
sys.exit(0)
print ('YES')
| Title: Lucky Ticket
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya loves tickets very much. As we know, each ticket has a number that is a positive integer. Its length equals *n* (*n* is always even). Petya calls a ticket lucky if the ticket's number is a lucky number and the sum of digits in the first half (the sum of the first *n*<=/<=2 digits) equals the sum of digits in the second half (the sum of the last *n*<=/<=2 digits). Check if the given ticket is lucky.
Input Specification:
The first line contains an even integer *n* (2<=≤<=*n*<=≤<=50) — the length of the ticket number that needs to be checked. The second line contains an integer whose length equals exactly *n* — the ticket number. The number may contain leading zeros.
Output Specification:
On the first line print "YES" if the given ticket number is lucky. Otherwise, print "NO" (without the quotes).
Demo Input:
['2\n47\n', '4\n4738\n', '4\n4774\n']
Demo Output:
['NO\n', 'NO\n', 'YES\n']
Note:
In the first sample the sum of digits in the first half does not equal the sum of digits in the second half (4 ≠ 7).
In the second sample the ticket number is not the lucky number. | ```python
n=int(input())
s=input()
s1=0
s2=0
for i in range(n//2):
if s[i]!=s[n-i-1]:
import sys
print('NO')
sys.exit(0)
print ('YES')
``` | 0 | |
784 | B | Kids' Riddle | PROGRAMMING | 2,000 | [
"*special"
] | null | null | Programmers' kids solve this riddle in 5-10 minutes. How fast can you do it? | The input contains a single integer *n* (0<=≤<=*n*<=≤<=2000000000). | Output a single integer. | [
"11\n",
"14\n",
"61441\n",
"571576\n",
"2128506\n"
] | [
"2\n",
"0\n",
"2\n",
"10\n",
"3\n"
] | none | 0 | [
{
"input": "11",
"output": "2"
},
{
"input": "14",
"output": "0"
},
{
"input": "61441",
"output": "2"
},
{
"input": "571576",
"output": "10"
},
{
"input": "2128506",
"output": "3"
},
{
"input": "0",
"output": "1"
},
{
"input": "2000000000",... | 1,522,576,514 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 78 | 7,065,600 | n=int(input())
sumx=0
if(n==0):
print(1)
else:
while(n>0):
a=n%16
if(a<10):
if(a==0 or a==4 or a==6 or a==9):
sumx+=1
elif(a==8):
sumx+=2
elif(a==10 or a==13):
sumx+=1
elif(a==11):
sumx+=2
n=n//16
print(sumx) | Title: Kids' Riddle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Programmers' kids solve this riddle in 5-10 minutes. How fast can you do it?
Input Specification:
The input contains a single integer *n* (0<=≤<=*n*<=≤<=2000000000).
Output Specification:
Output a single integer.
Demo Input:
['11\n', '14\n', '61441\n', '571576\n', '2128506\n']
Demo Output:
['2\n', '0\n', '2\n', '10\n', '3\n']
Note:
none | ```python
n=int(input())
sumx=0
if(n==0):
print(1)
else:
while(n>0):
a=n%16
if(a<10):
if(a==0 or a==4 or a==6 or a==9):
sumx+=1
elif(a==8):
sumx+=2
elif(a==10 or a==13):
sumx+=1
elif(a==11):
sumx+=2
n=n//16
print(sumx)
``` | 3 | |
460 | A | Vasya and Socks | PROGRAMMING | 900 | [
"brute force",
"implementation",
"math"
] | null | null | Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it late in the evening, so that Vasya cannot put on a new pair of socks before the next day. How many consecutive days pass until Vasya runs out of socks? | The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space. | Print a single integer — the answer to the problem. | [
"2 2\n",
"9 3\n"
] | [
"3\n",
"13\n"
] | In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on the third, sixth and ninth days. Than he spends another day wearing the socks that were bought on the twelfth day. | 500 | [
{
"input": "2 2",
"output": "3"
},
{
"input": "9 3",
"output": "13"
},
{
"input": "1 2",
"output": "1"
},
{
"input": "2 3",
"output": "2"
},
{
"input": "1 99",
"output": "1"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "10 2",
"outp... | 1,690,211,499 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 6 | 62 | 0 | n, m = list(map(int,input().split()))
ans = 0
while n>0:
ans += n
n//=m
print(ans) | Title: Vasya and Socks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has *n* pairs of socks. In the morning of each day Vasya has to put on a pair of socks before he goes to school. When he comes home in the evening, Vasya takes off the used socks and throws them away. Every *m*-th day (at days with numbers *m*,<=2*m*,<=3*m*,<=...) mom buys a pair of socks to Vasya. She does it late in the evening, so that Vasya cannot put on a new pair of socks before the next day. How many consecutive days pass until Vasya runs out of socks?
Input Specification:
The single line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100; 2<=≤<=*m*<=≤<=100), separated by a space.
Output Specification:
Print a single integer — the answer to the problem.
Demo Input:
['2 2\n', '9 3\n']
Demo Output:
['3\n', '13\n']
Note:
In the first sample Vasya spends the first two days wearing the socks that he had initially. Then on day three he puts on the socks that were bought on day two.
In the second sample Vasya spends the first nine days wearing the socks that he had initially. Then he spends three days wearing the socks that were bought on the third, sixth and ninth days. Than he spends another day wearing the socks that were bought on the twelfth day. | ```python
n, m = list(map(int,input().split()))
ans = 0
while n>0:
ans += n
n//=m
print(ans)
``` | 0 | |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note that there is exactly one next prime number after each number. So 5 is not the next prime number for 2.
One cold April morning Panoramix predicted that soon Kakofonix will break free from his straitjacket, and this will be a black day for the residents of the Gallic countryside.
Panoramix's prophecy tells that if some day Asterix and Obelix beat exactly *x* Roman soldiers, where *x* is a prime number, and next day they beat exactly *y* Roman soldiers, where *y* is the next prime number after *x*, then it's time to wait for Armageddon, for nothing can shut Kakofonix up while he sings his infernal song.
Yesterday the Gauls beat *n* Roman soldiers and it turned out that the number *n* was prime! Today their victims were a troop of *m* Romans (*m*<=><=*n*). Determine whether the Gauls should wait for the black day after today's victory of Asterix and Obelix? | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,675,911,870 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 92 | 0 | [n, m] = list(map(int, input().split(" ")))
number = n + 1
isNotPrime = True
while (isNotPrime):
temp = number - 1
isNotPrime = False
while (temp > 1):
if (number % temp == 0):
isNotPrime = True
temp -= 1
number += 1
if (number - 1 == m):
print("YES")
else:
print("NO")
| Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note that there is exactly one next prime number after each number. So 5 is not the next prime number for 2.
One cold April morning Panoramix predicted that soon Kakofonix will break free from his straitjacket, and this will be a black day for the residents of the Gallic countryside.
Panoramix's prophecy tells that if some day Asterix and Obelix beat exactly *x* Roman soldiers, where *x* is a prime number, and next day they beat exactly *y* Roman soldiers, where *y* is the next prime number after *x*, then it's time to wait for Armageddon, for nothing can shut Kakofonix up while he sings his infernal song.
Yesterday the Gauls beat *n* Roman soldiers and it turned out that the number *n* was prime! Today their victims were a troop of *m* Romans (*m*<=><=*n*). Determine whether the Gauls should wait for the black day after today's victory of Asterix and Obelix?
Input Specification:
The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4.
Output Specification:
Print YES, if *m* is the next prime number after *n*, or NO otherwise.
Demo Input:
['3 5\n', '7 11\n', '7 9\n']
Demo Output:
['YES', 'YES', 'NO']
Note:
none | ```python
[n, m] = list(map(int, input().split(" ")))
number = n + 1
isNotPrime = True
while (isNotPrime):
temp = number - 1
isNotPrime = False
while (temp > 1):
if (number % temp == 0):
isNotPrime = True
temp -= 1
number += 1
if (number - 1 == m):
print("YES")
else:
print("NO")
``` | 3.977 |
456 | B | Fedya and Maths | PROGRAMMING | 1,200 | [
"math",
"number theory"
] | null | null | Fedya studies in a gymnasium. Fedya's maths hometask is to calculate the following expression:
for given value of *n*. Fedya managed to complete the task. Can you? Note that given number *n* can be extremely large (e.g. it can exceed any integer type of your programming language). | The single line contains a single integer *n* (0<=≤<=*n*<=≤<=10105). The number doesn't contain any leading zeroes. | Print the value of the expression without leading zeros. | [
"4\n",
"124356983594583453458888889\n"
] | [
"4\n",
"0\n"
] | Operation *x* *mod* *y* means taking remainder after division *x* by *y*.
Note to the first sample:
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/825f244180bb10323db01645118c3cfdb312fa89.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "4",
"output": "4"
},
{
"input": "124356983594583453458888889",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "7854",
"output": "0"
},
{
"input": "584660",
"output": "4"
},
{
"input": "464",
"output": "4"
},
{
"inp... | 1,664,532,341 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | a=input()
print("4")
#111111111111111111111111111111111111111111111111111111111111111111111111
| Title: Fedya and Maths
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fedya studies in a gymnasium. Fedya's maths hometask is to calculate the following expression:
for given value of *n*. Fedya managed to complete the task. Can you? Note that given number *n* can be extremely large (e.g. it can exceed any integer type of your programming language).
Input Specification:
The single line contains a single integer *n* (0<=≤<=*n*<=≤<=10105). The number doesn't contain any leading zeroes.
Output Specification:
Print the value of the expression without leading zeros.
Demo Input:
['4\n', '124356983594583453458888889\n']
Demo Output:
['4\n', '0\n']
Note:
Operation *x* *mod* *y* means taking remainder after division *x* by *y*.
Note to the first sample:
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/825f244180bb10323db01645118c3cfdb312fa89.png" style="max-width: 100.0%;max-height: 100.0%;"/> | ```python
a=input()
print("4")
#111111111111111111111111111111111111111111111111111111111111111111111111
``` | 0 | |
651 | A | Joysticks | PROGRAMMING | 1,100 | [
"dp",
"greedy",
"implementation",
"math"
] | null | null | Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at *a*1 percent and second one is charged at *a*2 percent. You can connect charger to a joystick only at the beginning of each minute. In one minute joystick either discharges by 2 percent (if not connected to a charger) or charges by 1 percent (if connected to a charger).
Game continues while both joysticks have a positive charge. Hence, if at the beginning of minute some joystick is charged by 1 percent, it has to be connected to a charger, otherwise the game stops. If some joystick completely discharges (its charge turns to 0), the game also stops.
Determine the maximum number of minutes that game can last. It is prohibited to pause the game, i. e. at each moment both joysticks should be enabled. It is allowed for joystick to be charged by more than 100 percent. | The first line of the input contains two positive integers *a*1 and *a*2 (1<=≤<=*a*1,<=*a*2<=≤<=100), the initial charge level of first and second joystick respectively. | Output the only integer, the maximum number of minutes that the game can last. Game continues until some joystick is discharged. | [
"3 5\n",
"4 4\n"
] | [
"6\n",
"5\n"
] | In the first sample game lasts for 6 minute by using the following algorithm:
- at the beginning of the first minute connect first joystick to the charger, by the end of this minute first joystick is at 4%, second is at 3%; - continue the game without changing charger, by the end of the second minute the first joystick is at 5%, second is at 1%; - at the beginning of the third minute connect second joystick to the charger, after this minute the first joystick is at 3%, the second one is at 2%; - continue the game without changing charger, by the end of the fourth minute first joystick is at 1%, second one is at 3%; - at the beginning of the fifth minute connect first joystick to the charger, after this minute the first joystick is at 2%, the second one is at 1%; - at the beginning of the sixth minute connect second joystick to the charger, after this minute the first joystick is at 0%, the second one is at 2%.
After that the first joystick is completely discharged and the game is stopped. | 500 | [
{
"input": "3 5",
"output": "6"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "100 100",
"output": "197"
},
{
"input": "1 100",
"output": "98"
},
{
"input": "100 1",
"output": "98"
},
{
"input": "1 4",
"output": "2"
},
{
"input": "1 1",
... | 1,633,235,766 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 46 | 102,400 |
a,b=list(map(int,input().split()))
g={}
def recr(x,y):
if (x,y) in g:
return g[x,y]
if x<=0 or y<=0:
return 0
ans=1+max(recr(x-2,y+1),recr(x+1,y-2))
g[(x,y)]=ans
return ans
print(recr(a,b)) | Title: Joysticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at *a*1 percent and second one is charged at *a*2 percent. You can connect charger to a joystick only at the beginning of each minute. In one minute joystick either discharges by 2 percent (if not connected to a charger) or charges by 1 percent (if connected to a charger).
Game continues while both joysticks have a positive charge. Hence, if at the beginning of minute some joystick is charged by 1 percent, it has to be connected to a charger, otherwise the game stops. If some joystick completely discharges (its charge turns to 0), the game also stops.
Determine the maximum number of minutes that game can last. It is prohibited to pause the game, i. e. at each moment both joysticks should be enabled. It is allowed for joystick to be charged by more than 100 percent.
Input Specification:
The first line of the input contains two positive integers *a*1 and *a*2 (1<=≤<=*a*1,<=*a*2<=≤<=100), the initial charge level of first and second joystick respectively.
Output Specification:
Output the only integer, the maximum number of minutes that the game can last. Game continues until some joystick is discharged.
Demo Input:
['3 5\n', '4 4\n']
Demo Output:
['6\n', '5\n']
Note:
In the first sample game lasts for 6 minute by using the following algorithm:
- at the beginning of the first minute connect first joystick to the charger, by the end of this minute first joystick is at 4%, second is at 3%; - continue the game without changing charger, by the end of the second minute the first joystick is at 5%, second is at 1%; - at the beginning of the third minute connect second joystick to the charger, after this minute the first joystick is at 3%, the second one is at 2%; - continue the game without changing charger, by the end of the fourth minute first joystick is at 1%, second one is at 3%; - at the beginning of the fifth minute connect first joystick to the charger, after this minute the first joystick is at 2%, the second one is at 1%; - at the beginning of the sixth minute connect second joystick to the charger, after this minute the first joystick is at 0%, the second one is at 2%.
After that the first joystick is completely discharged and the game is stopped. | ```python
a,b=list(map(int,input().split()))
g={}
def recr(x,y):
if (x,y) in g:
return g[x,y]
if x<=0 or y<=0:
return 0
ans=1+max(recr(x-2,y+1),recr(x+1,y-2))
g[(x,y)]=ans
return ans
print(recr(a,b))
``` | 0 | |
409 | C | Magnum Opus | PROGRAMMING | 1,700 | [
"*special"
] | null | null | Salve, mi amice.
Et tu quidem de lapis philosophorum. Barba non facit philosophum. Labor omnia vincit. Non potest creatio ex nihilo. Necesse est partibus.
Rp:
I Aqua Fortis
I Aqua Regia
II Amalgama
VII Minium
IV Vitriol
Misce in vitro et æstus, et nil admirari. Festina lente, et nulla tenaci invia est via.
Fac et spera,
Vale,
Nicolas Flamel | The first line of input contains several space-separated integers *a**i* (0<=≤<=*a**i*<=≤<=100). | Print a single integer. | [
"2 4 6 8 10\n"
] | [
"1\n"
] | none | 0 | [
{
"input": "2 4 6 8 10",
"output": "1"
},
{
"input": "50 27 17 31 89",
"output": "4"
},
{
"input": "50 87 29 81 21",
"output": "5"
},
{
"input": "74 21 36 68 80",
"output": "9"
},
{
"input": "75 82 48 95 12",
"output": "3"
},
{
"input": "41 85 14 43 23... | 1,646,284,114 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 46 | 0 | a = [int(i) for i in input().split()]
print(min(a[0], a[1], a[2] // 2, a[3] // 7, a[4] // 4)) | Title: Magnum Opus
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Salve, mi amice.
Et tu quidem de lapis philosophorum. Barba non facit philosophum. Labor omnia vincit. Non potest creatio ex nihilo. Necesse est partibus.
Rp:
I Aqua Fortis
I Aqua Regia
II Amalgama
VII Minium
IV Vitriol
Misce in vitro et æstus, et nil admirari. Festina lente, et nulla tenaci invia est via.
Fac et spera,
Vale,
Nicolas Flamel
Input Specification:
The first line of input contains several space-separated integers *a**i* (0<=≤<=*a**i*<=≤<=100).
Output Specification:
Print a single integer.
Demo Input:
['2 4 6 8 10\n']
Demo Output:
['1\n']
Note:
none | ```python
a = [int(i) for i in input().split()]
print(min(a[0], a[1], a[2] // 2, a[3] // 7, a[4] // 4))
``` | 3 | |
315 | A | Sereja and Bottles | PROGRAMMING | 1,400 | [
"brute force"
] | null | null | Sereja and his friends went to a picnic. The guys had *n* soda bottles just for it. Sereja forgot the bottle opener as usual, so the guys had to come up with another way to open bottles.
Sereja knows that the *i*-th bottle is from brand *a**i*, besides, you can use it to open other bottles of brand *b**i*. You can use one bottle to open multiple other bottles. Sereja can open bottle with opened bottle or closed bottle.
Knowing this, Sereja wants to find out the number of bottles they've got that they won't be able to open in any way. Help him and find this number. | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of bottles. The next *n* lines contain the bottles' description. The *i*-th line contains two integers *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the description of the *i*-th bottle. | In a single line print a single integer — the answer to the problem. | [
"4\n1 1\n2 2\n3 3\n4 4\n",
"4\n1 2\n2 3\n3 4\n4 1\n"
] | [
"4\n",
"0\n"
] | none | 500 | [
{
"input": "4\n1 1\n2 2\n3 3\n4 4",
"output": "4"
},
{
"input": "4\n1 2\n2 3\n3 4\n4 1",
"output": "0"
},
{
"input": "3\n2 828\n4 392\n4 903",
"output": "3"
},
{
"input": "4\n2 3\n1 772\n3 870\n3 668",
"output": "2"
},
{
"input": "5\n1 4\n6 6\n4 3\n3 4\n4 758",
... | 1,615,454,062 | 2,147,483,647 | PyPy 3 | OK | TESTS | 34 | 216 | 1,228,800 | n=int(input())
l=[]
for i in range(n):
p=[]
a,b=map(int,input().split())
p.append(a)
p.append(b)
l.append(p)
ans=0
for i in range(n):
for j in range(n):
if(i!=j and l[i][0]==l[j][1]):
ans=ans+1
break
print(n-ans) | Title: Sereja and Bottles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja and his friends went to a picnic. The guys had *n* soda bottles just for it. Sereja forgot the bottle opener as usual, so the guys had to come up with another way to open bottles.
Sereja knows that the *i*-th bottle is from brand *a**i*, besides, you can use it to open other bottles of brand *b**i*. You can use one bottle to open multiple other bottles. Sereja can open bottle with opened bottle or closed bottle.
Knowing this, Sereja wants to find out the number of bottles they've got that they won't be able to open in any way. Help him and find this number.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of bottles. The next *n* lines contain the bottles' description. The *i*-th line contains two integers *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the description of the *i*-th bottle.
Output Specification:
In a single line print a single integer — the answer to the problem.
Demo Input:
['4\n1 1\n2 2\n3 3\n4 4\n', '4\n1 2\n2 3\n3 4\n4 1\n']
Demo Output:
['4\n', '0\n']
Note:
none | ```python
n=int(input())
l=[]
for i in range(n):
p=[]
a,b=map(int,input().split())
p.append(a)
p.append(b)
l.append(p)
ans=0
for i in range(n):
for j in range(n):
if(i!=j and l[i][0]==l[j][1]):
ans=ans+1
break
print(n-ans)
``` | 3 | |
919 | D | Substring | PROGRAMMING | 1,700 | [
"dfs and similar",
"dp",
"graphs"
] | null | null | You are given a graph with $n$ nodes and $m$ directed edges. One lowercase letter is assigned to each node. We define a path's value as the number of the most frequently occurring letter. For example, if letters on a path are "abaca", then the value of that path is $3$. Your task is find a path whose value is the largest. | The first line contains two positive integers $n, m$ ($1 \leq n, m \leq 300\,000$), denoting that the graph has $n$ nodes and $m$ directed edges.
The second line contains a string $s$ with only lowercase English letters. The $i$-th character is the letter assigned to the $i$-th node.
Then $m$ lines follow. Each line contains two integers $x, y$ ($1 \leq x, y \leq n$), describing a directed edge from $x$ to $y$. Note that $x$ can be equal to $y$ and there can be multiple edges between $x$ and $y$. Also the graph can be not connected. | Output a single line with a single integer denoting the largest value. If the value can be arbitrarily large, output -1 instead. | [
"5 4\nabaca\n1 2\n1 3\n3 4\n4 5\n",
"6 6\nxzyabc\n1 2\n3 1\n2 3\n5 4\n4 3\n6 4\n",
"10 14\nxzyzyzyzqx\n1 2\n2 4\n3 5\n4 5\n2 6\n6 8\n6 5\n2 10\n3 9\n10 9\n4 6\n1 10\n2 8\n3 7\n"
] | [
"3\n",
"-1\n",
"4\n"
] | In the first sample, the path with largest value is $1 \to 3 \to 4 \to 5$. The value is $3$ because the letter 'a' appears $3$ times. | 1,500 | [
{
"input": "5 4\nabaca\n1 2\n1 3\n3 4\n4 5",
"output": "3"
},
{
"input": "6 6\nxzyabc\n1 2\n3 1\n2 3\n5 4\n4 3\n6 4",
"output": "-1"
},
{
"input": "10 14\nxzyzyzyzqx\n1 2\n2 4\n3 5\n4 5\n2 6\n6 8\n6 5\n2 10\n3 9\n10 9\n4 6\n1 10\n2 8\n3 7",
"output": "4"
},
{
"input": "1 1\nf... | 1,622,616,502 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 108 | 102,400 | from collections import deque
n,m=map(int,input().split())
s=input()
graph=[ [] for i in range(n)]
dp=[ [0]*26 for i in rnage(n)]
degree=[0]*n
degree[0]=0
for i in range(m):
x,y=map(int,input().split())
graph[x-1].append(y-1)
degree[i]+=1
d=deque()
for i in range(n):
if degree[i]==0:
d.append(i)
dp[i][ord(s[i])-97]+=1
c=0
m=1
while(d):
c+=1
x=d.popleft()
for i in graph[x]:
for j in range(26):
dp[i][j]=max(dp[i][j],dp[x][j])
degree[i]-=1
if degree[i]==0:
dp[i][ord(s[i])-97]+=1
for j in range(26):
m=max(m,dp[i][j])
d.append(i)
if c!=n:
print(-1)
else:
print(m) | Title: Substring
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a graph with $n$ nodes and $m$ directed edges. One lowercase letter is assigned to each node. We define a path's value as the number of the most frequently occurring letter. For example, if letters on a path are "abaca", then the value of that path is $3$. Your task is find a path whose value is the largest.
Input Specification:
The first line contains two positive integers $n, m$ ($1 \leq n, m \leq 300\,000$), denoting that the graph has $n$ nodes and $m$ directed edges.
The second line contains a string $s$ with only lowercase English letters. The $i$-th character is the letter assigned to the $i$-th node.
Then $m$ lines follow. Each line contains two integers $x, y$ ($1 \leq x, y \leq n$), describing a directed edge from $x$ to $y$. Note that $x$ can be equal to $y$ and there can be multiple edges between $x$ and $y$. Also the graph can be not connected.
Output Specification:
Output a single line with a single integer denoting the largest value. If the value can be arbitrarily large, output -1 instead.
Demo Input:
['5 4\nabaca\n1 2\n1 3\n3 4\n4 5\n', '6 6\nxzyabc\n1 2\n3 1\n2 3\n5 4\n4 3\n6 4\n', '10 14\nxzyzyzyzqx\n1 2\n2 4\n3 5\n4 5\n2 6\n6 8\n6 5\n2 10\n3 9\n10 9\n4 6\n1 10\n2 8\n3 7\n']
Demo Output:
['3\n', '-1\n', '4\n']
Note:
In the first sample, the path with largest value is $1 \to 3 \to 4 \to 5$. The value is $3$ because the letter 'a' appears $3$ times. | ```python
from collections import deque
n,m=map(int,input().split())
s=input()
graph=[ [] for i in range(n)]
dp=[ [0]*26 for i in rnage(n)]
degree=[0]*n
degree[0]=0
for i in range(m):
x,y=map(int,input().split())
graph[x-1].append(y-1)
degree[i]+=1
d=deque()
for i in range(n):
if degree[i]==0:
d.append(i)
dp[i][ord(s[i])-97]+=1
c=0
m=1
while(d):
c+=1
x=d.popleft()
for i in graph[x]:
for j in range(26):
dp[i][j]=max(dp[i][j],dp[x][j])
degree[i]-=1
if degree[i]==0:
dp[i][ord(s[i])-97]+=1
for j in range(26):
m=max(m,dp[i][j])
d.append(i)
if c!=n:
print(-1)
else:
print(m)
``` | -1 | |
805 | A | Fake NP | PROGRAMMING | 1,000 | [
"greedy",
"math"
] | null | null | Tavak and Seyyed are good friends. Seyyed is very funny and he told Tavak to solve the following problem instead of longest-path.
You are given *l* and *r*. For all integers from *l* to *r*, inclusive, we wrote down all of their integer divisors except 1. Find the integer that we wrote down the maximum number of times.
Solve the problem to show that it's not a NP problem. | The first line contains two integers *l* and *r* (2<=≤<=*l*<=≤<=*r*<=≤<=109). | Print single integer, the integer that appears maximum number of times in the divisors.
If there are multiple answers, print any of them. | [
"19 29\n",
"3 6\n"
] | [
"2\n",
"3\n"
] | Definition of a divisor: [https://www.mathsisfun.com/definitions/divisor-of-an-integer-.html](https://www.mathsisfun.com/definitions/divisor-of-an-integer-.html)
The first example: from 19 to 29 these numbers are divisible by 2: {20, 22, 24, 26, 28}.
The second example: from 3 to 6 these numbers are divisible by 3: {3, 6}. | 500 | [
{
"input": "19 29",
"output": "2"
},
{
"input": "3 6",
"output": "2"
},
{
"input": "39 91",
"output": "2"
},
{
"input": "76 134",
"output": "2"
},
{
"input": "93 95",
"output": "2"
},
{
"input": "17 35",
"output": "2"
},
{
"input": "94 95",... | 1,691,698,167 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 23 | 93 | 3,481,600 | l, r = map(int, input().split())
if l == r:
flag = 1
for i in range(l, int(l ** 0.5 + 1)):
if l % i == 0:
flag = 0
print(i)
break
if flag: pritn(l)
else: print(2) | Title: Fake NP
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Tavak and Seyyed are good friends. Seyyed is very funny and he told Tavak to solve the following problem instead of longest-path.
You are given *l* and *r*. For all integers from *l* to *r*, inclusive, we wrote down all of their integer divisors except 1. Find the integer that we wrote down the maximum number of times.
Solve the problem to show that it's not a NP problem.
Input Specification:
The first line contains two integers *l* and *r* (2<=≤<=*l*<=≤<=*r*<=≤<=109).
Output Specification:
Print single integer, the integer that appears maximum number of times in the divisors.
If there are multiple answers, print any of them.
Demo Input:
['19 29\n', '3 6\n']
Demo Output:
['2\n', '3\n']
Note:
Definition of a divisor: [https://www.mathsisfun.com/definitions/divisor-of-an-integer-.html](https://www.mathsisfun.com/definitions/divisor-of-an-integer-.html)
The first example: from 19 to 29 these numbers are divisible by 2: {20, 22, 24, 26, 28}.
The second example: from 3 to 6 these numbers are divisible by 3: {3, 6}. | ```python
l, r = map(int, input().split())
if l == r:
flag = 1
for i in range(l, int(l ** 0.5 + 1)):
if l % i == 0:
flag = 0
print(i)
break
if flag: pritn(l)
else: print(2)
``` | -1 | |
450 | A | Jzzhu and Children | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | There are *n* children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to *n*. The *i*-th child wants to get at least *a**i* candies.
Jzzhu asks children to line up. Initially, the *i*-th child stands at the *i*-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:
1. Give *m* candies to the first child of the line. 1. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home. 1. Repeat the first two steps while the line is not empty.
Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order? | The first line contains two integers *n*,<=*m* (1<=≤<=*n*<=≤<=100; 1<=≤<=*m*<=≤<=100). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100). | Output a single integer, representing the number of the last child. | [
"5 2\n1 3 1 4 2\n",
"6 4\n1 1 2 2 3 3\n"
] | [
"4\n",
"6\n"
] | Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.
Child 4 is the last one who goes home. | 500 | [
{
"input": "5 2\n1 3 1 4 2",
"output": "4"
},
{
"input": "6 4\n1 1 2 2 3 3",
"output": "6"
},
{
"input": "7 3\n6 1 5 4 2 3 1",
"output": "4"
},
{
"input": "10 5\n2 7 3 6 2 5 1 3 4 5",
"output": "4"
},
{
"input": "100 1\n1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18... | 1,697,410,283 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 49 | 62 | 0 | #https://codeforces.com/problemset/problem/450/A
import math
(n,m) = (int(x) for x in input().split())
a = [int(x) for x in input().split()]
max_value = 0
for index in range(n):
curr_value = math.ceil(a[index]/m)
if curr_value >= max_value:
max_value = curr_value
answer = index+1
print(answer) | Title: Jzzhu and Children
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to *n*. The *i*-th child wants to get at least *a**i* candies.
Jzzhu asks children to line up. Initially, the *i*-th child stands at the *i*-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:
1. Give *m* candies to the first child of the line. 1. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home. 1. Repeat the first two steps while the line is not empty.
Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?
Input Specification:
The first line contains two integers *n*,<=*m* (1<=≤<=*n*<=≤<=100; 1<=≤<=*m*<=≤<=100). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=100).
Output Specification:
Output a single integer, representing the number of the last child.
Demo Input:
['5 2\n1 3 1 4 2\n', '6 4\n1 1 2 2 3 3\n']
Demo Output:
['4\n', '6\n']
Note:
Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.
Child 4 is the last one who goes home. | ```python
#https://codeforces.com/problemset/problem/450/A
import math
(n,m) = (int(x) for x in input().split())
a = [int(x) for x in input().split()]
max_value = 0
for index in range(n):
curr_value = math.ceil(a[index]/m)
if curr_value >= max_value:
max_value = curr_value
answer = index+1
print(answer)
``` | 3 | |
615 | D | Multipliers | PROGRAMMING | 2,000 | [
"math",
"number theory"
] | null | null | Ayrat has number *n*, represented as it's prime factorization *p**i* of size *m*, i.e. *n*<==<=*p*1·*p*2·...·*p**m*. Ayrat got secret information that that the product of all divisors of *n* taken modulo 109<=+<=7 is the password to the secret data base. Now he wants to calculate this value. | The first line of the input contains a single integer *m* (1<=≤<=*m*<=≤<=200<=000) — the number of primes in factorization of *n*.
The second line contains *m* primes numbers *p**i* (2<=≤<=*p**i*<=≤<=200<=000). | Print one integer — the product of all divisors of *n* modulo 109<=+<=7. | [
"2\n2 3\n",
"3\n2 3 2\n"
] | [
"36\n",
"1728\n"
] | In the first sample *n* = 2·3 = 6. The divisors of 6 are 1, 2, 3 and 6, their product is equal to 1·2·3·6 = 36.
In the second sample 2·3·2 = 12. The divisors of 12 are 1, 2, 3, 4, 6 and 12. 1·2·3·4·6·12 = 1728. | 2,000 | [
{
"input": "2\n2 3",
"output": "36"
},
{
"input": "3\n2 3 2",
"output": "1728"
},
{
"input": "1\n2017",
"output": "2017"
},
{
"input": "2\n63997 63997",
"output": "135893224"
},
{
"input": "5\n11 7 11 7 11",
"output": "750455957"
},
{
"input": "5\n2 2 ... | 1,605,258,952 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 124 | 0 | import math
m = int(input())
n = 1
u = 1
a = list(map(int, input().split()))
for i in range(len(a)):
n *= a[i]
for i in range(1, int(math.sqrt(n)) + 1, 1):
if int(n / i) * int(i) == n:
u *= i % 1000000007;
if int(i) * int(n / i) == n and i * i != n:
u *= (n / i) % 1000000007
print(i)
u %= 1000000007
print(int(u)) | Title: Multipliers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ayrat has number *n*, represented as it's prime factorization *p**i* of size *m*, i.e. *n*<==<=*p*1·*p*2·...·*p**m*. Ayrat got secret information that that the product of all divisors of *n* taken modulo 109<=+<=7 is the password to the secret data base. Now he wants to calculate this value.
Input Specification:
The first line of the input contains a single integer *m* (1<=≤<=*m*<=≤<=200<=000) — the number of primes in factorization of *n*.
The second line contains *m* primes numbers *p**i* (2<=≤<=*p**i*<=≤<=200<=000).
Output Specification:
Print one integer — the product of all divisors of *n* modulo 109<=+<=7.
Demo Input:
['2\n2 3\n', '3\n2 3 2\n']
Demo Output:
['36\n', '1728\n']
Note:
In the first sample *n* = 2·3 = 6. The divisors of 6 are 1, 2, 3 and 6, their product is equal to 1·2·3·6 = 36.
In the second sample 2·3·2 = 12. The divisors of 12 are 1, 2, 3, 4, 6 and 12. 1·2·3·4·6·12 = 1728. | ```python
import math
m = int(input())
n = 1
u = 1
a = list(map(int, input().split()))
for i in range(len(a)):
n *= a[i]
for i in range(1, int(math.sqrt(n)) + 1, 1):
if int(n / i) * int(i) == n:
u *= i % 1000000007;
if int(i) * int(n / i) == n and i * i != n:
u *= (n / i) % 1000000007
print(i)
u %= 1000000007
print(int(u))
``` | 0 | |
670 | D1 | Magic Powder - 1 | PROGRAMMING | 1,400 | [
"binary search",
"brute force",
"implementation"
] | null | null | This problem is given in two versions that differ only by constraints. If you can solve this problem in large constraints, then you can just write a single solution to the both versions. If you find the problem too difficult in large constraints, you can write solution to the simplified version only.
Waking up in the morning, Apollinaria decided to bake cookies. To bake one cookie, she needs *n* ingredients, and for each ingredient she knows the value *a**i* — how many grams of this ingredient one needs to bake a cookie. To prepare one cookie Apollinaria needs to use all *n* ingredients.
Apollinaria has *b**i* gram of the *i*-th ingredient. Also she has *k* grams of a magic powder. Each gram of magic powder can be turned to exactly 1 gram of any of the *n* ingredients and can be used for baking cookies.
Your task is to determine the maximum number of cookies, which Apollinaria is able to bake using the ingredients that she has and the magic powder. | The first line of the input contains two positive integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1000) — the number of ingredients and the number of grams of the magic powder.
The second line contains the sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000), where the *i*-th number is equal to the number of grams of the *i*-th ingredient, needed to bake one cookie.
The third line contains the sequence *b*1,<=*b*2,<=...,<=*b**n* (1<=≤<=*b**i*<=≤<=1000), where the *i*-th number is equal to the number of grams of the *i*-th ingredient, which Apollinaria has. | Print the maximum number of cookies, which Apollinaria will be able to bake using the ingredients that she has and the magic powder. | [
"3 1\n2 1 4\n11 3 16\n",
"4 3\n4 3 5 6\n11 12 14 20\n"
] | [
"4\n",
"3\n"
] | In the first sample it is profitably for Apollinaria to make the existing 1 gram of her magic powder to ingredient with the index 2, then Apollinaria will be able to bake 4 cookies.
In the second sample Apollinaria should turn 1 gram of magic powder to ingredient with the index 1 and 1 gram of magic powder to ingredient with the index 3. Then Apollinaria will be able to bake 3 cookies. The remaining 1 gram of the magic powder can be left, because it can't be used to increase the answer. | 1,000 | [
{
"input": "3 1\n2 1 4\n11 3 16",
"output": "4"
},
{
"input": "4 3\n4 3 5 6\n11 12 14 20",
"output": "3"
},
{
"input": "10 926\n5 6 8 1 2 5 1 8 4 4\n351 739 998 725 953 970 906 691 707 1000",
"output": "137"
},
{
"input": "20 925\n7 3 1 2 1 3 1 3 1 2 3 1 5 8 1 3 7 3 4 2\n837 ... | 1,670,255,958 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 2 | 124 | 2,150,400 | n,k = map(int,input().split())
lis1 = list(map(int,input().split()))
lis2 = list(map(int,input().split()))
lis = sorted(list(map(list,zip(lis1,lis2))),key = lambda x:x[1]//x[0])
#print(lis)
while(k>0):
val = lis[0][0]*((lis[0][1]//lis[0][0])+1)
if k>=val-lis[0][1]:
k-=val-lis[0][1]
else:
break
lis[0][1]+=val-lis[0][1]
#print(lis)
i = 1
while(lis[0][1]//lis[0][0]!=lis[i][1]//lis[i][0]):
i+=1
lis.insert(i,lis[0])
#print(lis)
lis.pop(0)
minn = float('inf')
for i,j in lis:
minn= min(j//i,minn)
print(minn)
| Title: Magic Powder - 1
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
This problem is given in two versions that differ only by constraints. If you can solve this problem in large constraints, then you can just write a single solution to the both versions. If you find the problem too difficult in large constraints, you can write solution to the simplified version only.
Waking up in the morning, Apollinaria decided to bake cookies. To bake one cookie, she needs *n* ingredients, and for each ingredient she knows the value *a**i* — how many grams of this ingredient one needs to bake a cookie. To prepare one cookie Apollinaria needs to use all *n* ingredients.
Apollinaria has *b**i* gram of the *i*-th ingredient. Also she has *k* grams of a magic powder. Each gram of magic powder can be turned to exactly 1 gram of any of the *n* ingredients and can be used for baking cookies.
Your task is to determine the maximum number of cookies, which Apollinaria is able to bake using the ingredients that she has and the magic powder.
Input Specification:
The first line of the input contains two positive integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1000) — the number of ingredients and the number of grams of the magic powder.
The second line contains the sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000), where the *i*-th number is equal to the number of grams of the *i*-th ingredient, needed to bake one cookie.
The third line contains the sequence *b*1,<=*b*2,<=...,<=*b**n* (1<=≤<=*b**i*<=≤<=1000), where the *i*-th number is equal to the number of grams of the *i*-th ingredient, which Apollinaria has.
Output Specification:
Print the maximum number of cookies, which Apollinaria will be able to bake using the ingredients that she has and the magic powder.
Demo Input:
['3 1\n2 1 4\n11 3 16\n', '4 3\n4 3 5 6\n11 12 14 20\n']
Demo Output:
['4\n', '3\n']
Note:
In the first sample it is profitably for Apollinaria to make the existing 1 gram of her magic powder to ingredient with the index 2, then Apollinaria will be able to bake 4 cookies.
In the second sample Apollinaria should turn 1 gram of magic powder to ingredient with the index 1 and 1 gram of magic powder to ingredient with the index 3. Then Apollinaria will be able to bake 3 cookies. The remaining 1 gram of the magic powder can be left, because it can't be used to increase the answer. | ```python
n,k = map(int,input().split())
lis1 = list(map(int,input().split()))
lis2 = list(map(int,input().split()))
lis = sorted(list(map(list,zip(lis1,lis2))),key = lambda x:x[1]//x[0])
#print(lis)
while(k>0):
val = lis[0][0]*((lis[0][1]//lis[0][0])+1)
if k>=val-lis[0][1]:
k-=val-lis[0][1]
else:
break
lis[0][1]+=val-lis[0][1]
#print(lis)
i = 1
while(lis[0][1]//lis[0][0]!=lis[i][1]//lis[i][0]):
i+=1
lis.insert(i,lis[0])
#print(lis)
lis.pop(0)
minn = float('inf')
for i,j in lis:
minn= min(j//i,minn)
print(minn)
``` | -1 | |
920 | A | Water The Garden | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | It is winter now, and Max decided it's about time he watered the garden.
The garden can be represented as *n* consecutive garden beds, numbered from 1 to *n*. *k* beds contain water taps (*i*-th tap is located in the bed *x**i*), which, if turned on, start delivering water to neighbouring beds. If the tap on the bed *x**i* is turned on, then after one second has passed, the bed *x**i* will be watered; after two seconds have passed, the beds from the segment [*x**i*<=-<=1,<=*x**i*<=+<=1] will be watered (if they exist); after *j* seconds have passed (*j* is an integer number), the beds from the segment [*x**i*<=-<=(*j*<=-<=1),<=*x**i*<=+<=(*j*<=-<=1)] will be watered (if they exist). Nothing changes during the seconds, so, for example, we can't say that the segment [*x**i*<=-<=2.5,<=*x**i*<=+<=2.5] will be watered after 2.5 seconds have passed; only the segment [*x**i*<=-<=2,<=*x**i*<=+<=2] will be watered at that moment.
Max wants to turn on all the water taps at the same moment, and now he wonders, what is the minimum number of seconds that have to pass after he turns on some taps until the whole garden is watered. Help him to find the answer! | The first line contains one integer *t* — the number of test cases to solve (1<=≤<=*t*<=≤<=200).
Then *t* test cases follow. The first line of each test case contains two integers *n* and *k* (1<=≤<=*n*<=≤<=200, 1<=≤<=*k*<=≤<=*n*) — the number of garden beds and water taps, respectively.
Next line contains *k* integers *x**i* (1<=≤<=*x**i*<=≤<=*n*) — the location of *i*-th water tap. It is guaranteed that for each condition *x**i*<=-<=1<=<<=*x**i* holds.
It is guaranteed that the sum of *n* over all test cases doesn't exceed 200.
Note that in hacks you have to set *t*<==<=1. | For each test case print one integer — the minimum number of seconds that have to pass after Max turns on some of the water taps, until the whole garden is watered. | [
"3\n5 1\n3\n3 3\n1 2 3\n4 1\n1\n"
] | [
"3\n1\n4\n"
] | The first example consists of 3 tests:
1. There are 5 garden beds, and a water tap in the bed 3. If we turn it on, then after 1 second passes, only bed 3 will be watered; after 2 seconds pass, beds [1, 3] will be watered, and after 3 seconds pass, everything will be watered. 1. There are 3 garden beds, and there is a water tap in each one. If we turn all of them on, then everything will be watered after 1 second passes. 1. There are 4 garden beds, and only one tap in the bed 1. It will take 4 seconds to water, for example, bed 4. | 0 | [
{
"input": "3\n5 1\n3\n3 3\n1 2 3\n4 1\n1",
"output": "3\n1\n4"
},
{
"input": "26\n1 1\n1\n2 1\n2\n2 1\n1\n2 2\n1 2\n3 1\n3\n3 1\n2\n3 2\n2 3\n3 1\n1\n3 2\n1 3\n3 2\n1 2\n3 3\n1 2 3\n4 1\n4\n4 1\n3\n4 2\n3 4\n4 1\n2\n4 2\n2 4\n4 2\n2 3\n4 3\n2 3 4\n4 1\n1\n4 2\n1 4\n4 2\n1 3\n4 3\n1 3 4\n4 2\n1 2\n4... | 1,517,704,362 | 2,147,483,647 | Python 3 | OK | TESTS | 21 | 77 | 5,632,000 | import math
t = int(input())
for i in range(t):
n, k = input().split(" ")
n = int(n)
k = int(k)
arr = input().split(" ")
if n == k:
print(1, '\n')
continue
for j in range(len(arr)):
arr[j] = int(arr[j])
maxi = 0
for j in range(1, k):
if arr[j] - arr[j - 1] - 1 > maxi:
maxi = arr[j] - arr[j - 1] - 1
maxi = math.ceil(maxi / 2.0) + 1
if arr[0] > maxi:
maxi = arr[0]
if n - arr[len(arr) - 1] + 1 > maxi:
maxi = n - arr[len(arr) - 1] + 1
print(maxi) | Title: Water The Garden
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It is winter now, and Max decided it's about time he watered the garden.
The garden can be represented as *n* consecutive garden beds, numbered from 1 to *n*. *k* beds contain water taps (*i*-th tap is located in the bed *x**i*), which, if turned on, start delivering water to neighbouring beds. If the tap on the bed *x**i* is turned on, then after one second has passed, the bed *x**i* will be watered; after two seconds have passed, the beds from the segment [*x**i*<=-<=1,<=*x**i*<=+<=1] will be watered (if they exist); after *j* seconds have passed (*j* is an integer number), the beds from the segment [*x**i*<=-<=(*j*<=-<=1),<=*x**i*<=+<=(*j*<=-<=1)] will be watered (if they exist). Nothing changes during the seconds, so, for example, we can't say that the segment [*x**i*<=-<=2.5,<=*x**i*<=+<=2.5] will be watered after 2.5 seconds have passed; only the segment [*x**i*<=-<=2,<=*x**i*<=+<=2] will be watered at that moment.
Max wants to turn on all the water taps at the same moment, and now he wonders, what is the minimum number of seconds that have to pass after he turns on some taps until the whole garden is watered. Help him to find the answer!
Input Specification:
The first line contains one integer *t* — the number of test cases to solve (1<=≤<=*t*<=≤<=200).
Then *t* test cases follow. The first line of each test case contains two integers *n* and *k* (1<=≤<=*n*<=≤<=200, 1<=≤<=*k*<=≤<=*n*) — the number of garden beds and water taps, respectively.
Next line contains *k* integers *x**i* (1<=≤<=*x**i*<=≤<=*n*) — the location of *i*-th water tap. It is guaranteed that for each condition *x**i*<=-<=1<=<<=*x**i* holds.
It is guaranteed that the sum of *n* over all test cases doesn't exceed 200.
Note that in hacks you have to set *t*<==<=1.
Output Specification:
For each test case print one integer — the minimum number of seconds that have to pass after Max turns on some of the water taps, until the whole garden is watered.
Demo Input:
['3\n5 1\n3\n3 3\n1 2 3\n4 1\n1\n']
Demo Output:
['3\n1\n4\n']
Note:
The first example consists of 3 tests:
1. There are 5 garden beds, and a water tap in the bed 3. If we turn it on, then after 1 second passes, only bed 3 will be watered; after 2 seconds pass, beds [1, 3] will be watered, and after 3 seconds pass, everything will be watered. 1. There are 3 garden beds, and there is a water tap in each one. If we turn all of them on, then everything will be watered after 1 second passes. 1. There are 4 garden beds, and only one tap in the bed 1. It will take 4 seconds to water, for example, bed 4. | ```python
import math
t = int(input())
for i in range(t):
n, k = input().split(" ")
n = int(n)
k = int(k)
arr = input().split(" ")
if n == k:
print(1, '\n')
continue
for j in range(len(arr)):
arr[j] = int(arr[j])
maxi = 0
for j in range(1, k):
if arr[j] - arr[j - 1] - 1 > maxi:
maxi = arr[j] - arr[j - 1] - 1
maxi = math.ceil(maxi / 2.0) + 1
if arr[0] > maxi:
maxi = arr[0]
if n - arr[len(arr) - 1] + 1 > maxi:
maxi = n - arr[len(arr) - 1] + 1
print(maxi)
``` | 3 | |
27 | A | Next Test | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | A. Next Test | 2 | 256 | «Polygon» is a system which allows to create programming tasks in a simple and professional way. When you add a test to the problem, the corresponding form asks you for the test index. As in most cases it is clear which index the next test will have, the system suggests the default value of the index. It is calculated as the smallest positive integer which is not used as an index for some previously added test.
You are to implement this feature. Create a program which determines the default index of the next test, given the indexes of the previously added tests. | The first line contains one integer *n* (1<=≤<=*n*<=≤<=3000) — the amount of previously added tests. The second line contains *n* distinct integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=3000) — indexes of these tests. | Output the required default value for the next test index. | [
"3\n1 7 2\n"
] | [
"3\n"
] | none | 500 | [
{
"input": "1\n1",
"output": "2"
},
{
"input": "2\n2 1",
"output": "3"
},
{
"input": "3\n3 4 1",
"output": "2"
},
{
"input": "4\n6 4 3 5",
"output": "1"
},
{
"input": "5\n3 2 1 7 4",
"output": "5"
},
{
"input": "6\n4 1 2 5 3 7",
"output": "6"
},
... | 1,695,353,405 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 124 | 1,740,800 | # Read input
n = int(input())
arr = list(map(int, input().split()))
arr.sort()
if arr[0] != 1:
print(1)
else:
f = 0
for i in range(len(arr)-1):
if arr[i+1] - arr[i] > 1:
f= 1
break
if f:
print(arr[i]+1)
else:
print(arr[-1]+1)
| Title: Next Test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
«Polygon» is a system which allows to create programming tasks in a simple and professional way. When you add a test to the problem, the corresponding form asks you for the test index. As in most cases it is clear which index the next test will have, the system suggests the default value of the index. It is calculated as the smallest positive integer which is not used as an index for some previously added test.
You are to implement this feature. Create a program which determines the default index of the next test, given the indexes of the previously added tests.
Input Specification:
The first line contains one integer *n* (1<=≤<=*n*<=≤<=3000) — the amount of previously added tests. The second line contains *n* distinct integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=3000) — indexes of these tests.
Output Specification:
Output the required default value for the next test index.
Demo Input:
['3\n1 7 2\n']
Demo Output:
['3\n']
Note:
none | ```python
# Read input
n = int(input())
arr = list(map(int, input().split()))
arr.sort()
if arr[0] != 1:
print(1)
else:
f = 0
for i in range(len(arr)-1):
if arr[i+1] - arr[i] > 1:
f= 1
break
if f:
print(arr[i]+1)
else:
print(arr[-1]+1)
``` | 3.965758 |
771 | C | Bear and Tree Jumps | PROGRAMMING | 2,100 | [
"dfs and similar",
"dp",
"trees"
] | null | null | A tree is an undirected connected graph without cycles. The distance between two vertices is the number of edges in a simple path between them.
Limak is a little polar bear. He lives in a tree that consists of *n* vertices, numbered 1 through *n*.
Limak recently learned how to jump. He can jump from a vertex to any vertex within distance at most *k*.
For a pair of vertices (*s*,<=*t*) we define *f*(*s*,<=*t*) as the minimum number of jumps Limak needs to get from *s* to *t*. Your task is to find the sum of *f*(*s*,<=*t*) over all pairs of vertices (*s*,<=*t*) such that *s*<=<<=*t*. | The first line of the input contains two integers *n* and *k* (2<=≤<=*n*<=≤<=200<=000, 1<=≤<=*k*<=≤<=5) — the number of vertices in the tree and the maximum allowed jump distance respectively.
The next *n*<=-<=1 lines describe edges in the tree. The *i*-th of those lines contains two integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*) — the indices on vertices connected with *i*-th edge.
It's guaranteed that the given edges form a tree. | Print one integer, denoting the sum of *f*(*s*,<=*t*) over all pairs of vertices (*s*,<=*t*) such that *s*<=<<=*t*. | [
"6 2\n1 2\n1 3\n2 4\n2 5\n4 6\n",
"13 3\n1 2\n3 2\n4 2\n5 2\n3 6\n10 6\n6 7\n6 13\n5 8\n5 9\n9 11\n11 12\n",
"3 5\n2 1\n3 1\n"
] | [
"20\n",
"114\n",
"3\n"
] | In the first sample, the given tree has 6 vertices and it's displayed on the drawing below. Limak can jump to any vertex within distance at most 2. For example, from the vertex 5 he can jump to any of vertices: 1, 2 and 4 (well, he can also jump to the vertex 5 itself).
There are <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c0295201207e28a36e641d8cf599f45986059e71.png" style="max-width: 100.0%;max-height: 100.0%;"/> pairs of vertices (*s*, *t*) such that *s* < *t*. For 5 of those pairs Limak would need two jumps: (1, 6), (3, 4), (3, 5), (3, 6), (5, 6). For other 10 pairs one jump is enough. So, the answer is 5·2 + 10·1 = 20.
In the third sample, Limak can jump between every two vertices directly. There are 3 pairs of vertices (*s* < *t*), so the answer is 3·1 = 3. | 1,000 | [
{
"input": "6 2\n1 2\n1 3\n2 4\n2 5\n4 6",
"output": "20"
},
{
"input": "13 3\n1 2\n3 2\n4 2\n5 2\n3 6\n10 6\n6 7\n6 13\n5 8\n5 9\n9 11\n11 12",
"output": "114"
},
{
"input": "3 5\n2 1\n3 1",
"output": "3"
},
{
"input": "2 1\n1 2",
"output": "1"
},
{
"input": "2 5... | 1,689,251,174 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("_RANDOM_GUESS_1689251171.5054982")# 1689251171.505547 | Title: Bear and Tree Jumps
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A tree is an undirected connected graph without cycles. The distance between two vertices is the number of edges in a simple path between them.
Limak is a little polar bear. He lives in a tree that consists of *n* vertices, numbered 1 through *n*.
Limak recently learned how to jump. He can jump from a vertex to any vertex within distance at most *k*.
For a pair of vertices (*s*,<=*t*) we define *f*(*s*,<=*t*) as the minimum number of jumps Limak needs to get from *s* to *t*. Your task is to find the sum of *f*(*s*,<=*t*) over all pairs of vertices (*s*,<=*t*) such that *s*<=<<=*t*.
Input Specification:
The first line of the input contains two integers *n* and *k* (2<=≤<=*n*<=≤<=200<=000, 1<=≤<=*k*<=≤<=5) — the number of vertices in the tree and the maximum allowed jump distance respectively.
The next *n*<=-<=1 lines describe edges in the tree. The *i*-th of those lines contains two integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*) — the indices on vertices connected with *i*-th edge.
It's guaranteed that the given edges form a tree.
Output Specification:
Print one integer, denoting the sum of *f*(*s*,<=*t*) over all pairs of vertices (*s*,<=*t*) such that *s*<=<<=*t*.
Demo Input:
['6 2\n1 2\n1 3\n2 4\n2 5\n4 6\n', '13 3\n1 2\n3 2\n4 2\n5 2\n3 6\n10 6\n6 7\n6 13\n5 8\n5 9\n9 11\n11 12\n', '3 5\n2 1\n3 1\n']
Demo Output:
['20\n', '114\n', '3\n']
Note:
In the first sample, the given tree has 6 vertices and it's displayed on the drawing below. Limak can jump to any vertex within distance at most 2. For example, from the vertex 5 he can jump to any of vertices: 1, 2 and 4 (well, he can also jump to the vertex 5 itself).
There are <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c0295201207e28a36e641d8cf599f45986059e71.png" style="max-width: 100.0%;max-height: 100.0%;"/> pairs of vertices (*s*, *t*) such that *s* < *t*. For 5 of those pairs Limak would need two jumps: (1, 6), (3, 4), (3, 5), (3, 6), (5, 6). For other 10 pairs one jump is enough. So, the answer is 5·2 + 10·1 = 20.
In the third sample, Limak can jump between every two vertices directly. There are 3 pairs of vertices (*s* < *t*), so the answer is 3·1 = 3. | ```python
print("_RANDOM_GUESS_1689251171.5054982")# 1689251171.505547
``` | 0 | |
139 | A | Petr and Book | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly *n* pages.
Petr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight schedule and for each day of the week he knows how many pages he will be able to read on that day. Some days are so busy that Petr will have no time to read whatsoever. However, we know that he will be able to read at least one page a week.
Assuming that Petr will not skip days and will read as much as he can every day, determine on which day of the week he will read the last page of the book. | The first input line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of pages in the book.
The second line contains seven non-negative space-separated integers that do not exceed 1000 — those integers represent how many pages Petr can read on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and Sunday correspondingly. It is guaranteed that at least one of those numbers is larger than zero. | Print a single number — the number of the day of the week, when Petr will finish reading the book. The days of the week are numbered starting with one in the natural order: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. | [
"100\n15 20 20 15 10 30 45\n",
"2\n1 0 0 0 0 0 0\n"
] | [
"6\n",
"1\n"
] | Note to the first sample:
By the end of Monday and therefore, by the beginning of Tuesday Petr has 85 pages left. He has 65 pages left by Wednesday, 45 by Thursday, 30 by Friday, 20 by Saturday and on Saturday Petr finishes reading the book (and he also has time to read 10 pages of something else).
Note to the second sample:
On Monday of the first week Petr will read the first page. On Monday of the second week Petr will read the second page and will finish reading the book. | 500 | [
{
"input": "100\n15 20 20 15 10 30 45",
"output": "6"
},
{
"input": "2\n1 0 0 0 0 0 0",
"output": "1"
},
{
"input": "100\n100 200 100 200 300 400 500",
"output": "1"
},
{
"input": "3\n1 1 1 1 1 1 1",
"output": "3"
},
{
"input": "1\n1 1 1 1 1 1 1",
"output": "1... | 1,691,184,473 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 0 | 122 | 0 | n = int(input())
a = [int(i) for i in input().split()]
if sum(a) > n:
sm = 0
for i in range(7):
if sm >= n:
print(i + 1)
break
elif sum(a) == n:
print(7)
else:
n_new = n / sum(a)
for i in range(7):
if sm >= n:
print(i + 1)
break | Title: Petr and Book
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One Sunday Petr went to a bookshop and bought a new book on sports programming. The book had exactly *n* pages.
Petr decided to start reading it starting from the next day, that is, from Monday. Petr's got a very tight schedule and for each day of the week he knows how many pages he will be able to read on that day. Some days are so busy that Petr will have no time to read whatsoever. However, we know that he will be able to read at least one page a week.
Assuming that Petr will not skip days and will read as much as he can every day, determine on which day of the week he will read the last page of the book.
Input Specification:
The first input line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of pages in the book.
The second line contains seven non-negative space-separated integers that do not exceed 1000 — those integers represent how many pages Petr can read on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and Sunday correspondingly. It is guaranteed that at least one of those numbers is larger than zero.
Output Specification:
Print a single number — the number of the day of the week, when Petr will finish reading the book. The days of the week are numbered starting with one in the natural order: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.
Demo Input:
['100\n15 20 20 15 10 30 45\n', '2\n1 0 0 0 0 0 0\n']
Demo Output:
['6\n', '1\n']
Note:
Note to the first sample:
By the end of Monday and therefore, by the beginning of Tuesday Petr has 85 pages left. He has 65 pages left by Wednesday, 45 by Thursday, 30 by Friday, 20 by Saturday and on Saturday Petr finishes reading the book (and he also has time to read 10 pages of something else).
Note to the second sample:
On Monday of the first week Petr will read the first page. On Monday of the second week Petr will read the second page and will finish reading the book. | ```python
n = int(input())
a = [int(i) for i in input().split()]
if sum(a) > n:
sm = 0
for i in range(7):
if sm >= n:
print(i + 1)
break
elif sum(a) == n:
print(7)
else:
n_new = n / sum(a)
for i in range(7):
if sm >= n:
print(i + 1)
break
``` | 0 | |
832 | A | Sasha and Sticks | PROGRAMMING | 800 | [
"games",
"math"
] | null | null | It's one more school day now. Sasha doesn't like classes and is always bored at them. So, each day he invents some game and plays in it alone or with friends.
Today he invented one simple game to play with Lena, with whom he shares a desk. The rules are simple. Sasha draws *n* sticks in a row. After that the players take turns crossing out exactly *k* sticks from left or right in each turn. Sasha moves first, because he is the inventor of the game. If there are less than *k* sticks on the paper before some turn, the game ends. Sasha wins if he makes strictly more moves than Lena. Sasha wants to know the result of the game before playing, you are to help him. | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1018, *k*<=≤<=*n*) — the number of sticks drawn by Sasha and the number *k* — the number of sticks to be crossed out on each turn. | If Sasha wins, print "YES" (without quotes), otherwise print "NO" (without quotes).
You can print each letter in arbitrary case (upper of lower). | [
"1 1\n",
"10 4\n"
] | [
"YES\n",
"NO\n"
] | In the first example Sasha crosses out 1 stick, and then there are no sticks. So Lena can't make a move, and Sasha wins.
In the second example Sasha crosses out 4 sticks, then Lena crosses out 4 sticks, and after that there are only 2 sticks left. Sasha can't make a move. The players make equal number of moves, so Sasha doesn't win. | 500 | [
{
"input": "1 1",
"output": "YES"
},
{
"input": "10 4",
"output": "NO"
},
{
"input": "251656215122324104 164397544865601257",
"output": "YES"
},
{
"input": "963577813436662285 206326039287271924",
"output": "NO"
},
{
"input": "1000000000000000000 1",
"output":... | 1,633,178,894 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 6,758,400 | n,k = map(int,input().split())
if n>k*3 or n<=k:
print("YES")
else:
print("NO")
| Title: Sasha and Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's one more school day now. Sasha doesn't like classes and is always bored at them. So, each day he invents some game and plays in it alone or with friends.
Today he invented one simple game to play with Lena, with whom he shares a desk. The rules are simple. Sasha draws *n* sticks in a row. After that the players take turns crossing out exactly *k* sticks from left or right in each turn. Sasha moves first, because he is the inventor of the game. If there are less than *k* sticks on the paper before some turn, the game ends. Sasha wins if he makes strictly more moves than Lena. Sasha wants to know the result of the game before playing, you are to help him.
Input Specification:
The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1018, *k*<=≤<=*n*) — the number of sticks drawn by Sasha and the number *k* — the number of sticks to be crossed out on each turn.
Output Specification:
If Sasha wins, print "YES" (without quotes), otherwise print "NO" (without quotes).
You can print each letter in arbitrary case (upper of lower).
Demo Input:
['1 1\n', '10 4\n']
Demo Output:
['YES\n', 'NO\n']
Note:
In the first example Sasha crosses out 1 stick, and then there are no sticks. So Lena can't make a move, and Sasha wins.
In the second example Sasha crosses out 4 sticks, then Lena crosses out 4 sticks, and after that there are only 2 sticks left. Sasha can't make a move. The players make equal number of moves, so Sasha doesn't win. | ```python
n,k = map(int,input().split())
if n>k*3 or n<=k:
print("YES")
else:
print("NO")
``` | 0 | |
6 | A | Triangle | PROGRAMMING | 900 | [
"brute force",
"geometry"
] | A. Triangle | 2 | 64 | Johnny has a younger sister Anne, who is very clever and smart. As she came home from the kindergarten, she told his brother about the task that her kindergartener asked her to solve. The task was just to construct a triangle out of four sticks of different colours. Naturally, one of the sticks is extra. It is not allowed to break the sticks or use their partial length. Anne has perfectly solved this task, now she is asking Johnny to do the same.
The boy answered that he would cope with it without any difficulty. However, after a while he found out that different tricky things can occur. It can happen that it is impossible to construct a triangle of a positive area, but it is possible to construct a degenerate triangle. It can be so, that it is impossible to construct a degenerate triangle even. As Johnny is very lazy, he does not want to consider such a big amount of cases, he asks you to help him. | The first line of the input contains four space-separated positive integer numbers not exceeding 100 — lengthes of the sticks. | Output TRIANGLE if it is possible to construct a non-degenerate triangle. Output SEGMENT if the first case cannot take place and it is possible to construct a degenerate triangle. Output IMPOSSIBLE if it is impossible to construct any triangle. Remember that you are to use three sticks. It is not allowed to break the sticks or use their partial length. | [
"4 2 1 3\n",
"7 2 2 4\n",
"3 5 9 1\n"
] | [
"TRIANGLE\n",
"SEGMENT\n",
"IMPOSSIBLE\n"
] | none | 0 | [
{
"input": "4 2 1 3",
"output": "TRIANGLE"
},
{
"input": "7 2 2 4",
"output": "SEGMENT"
},
{
"input": "3 5 9 1",
"output": "IMPOSSIBLE"
},
{
"input": "3 1 5 1",
"output": "IMPOSSIBLE"
},
{
"input": "10 10 10 10",
"output": "TRIANGLE"
},
{
"input": "11 ... | 1,685,080,381 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 60 | 0 | # LUOGU_RID: 111258892
array = []
j = 0
while j <= 3:
a = input()
array.append(a)
j += 1
array.sort()
print(array)
if array[1]+array[2] > array[3]:
print('TRIANGLE')
if array[1]+array[2] == array[3]:
print('SEGMENT')
else:
print('IMPOSSIBLE')
| Title: Triangle
Time Limit: 2 seconds
Memory Limit: 64 megabytes
Problem Description:
Johnny has a younger sister Anne, who is very clever and smart. As she came home from the kindergarten, she told his brother about the task that her kindergartener asked her to solve. The task was just to construct a triangle out of four sticks of different colours. Naturally, one of the sticks is extra. It is not allowed to break the sticks or use their partial length. Anne has perfectly solved this task, now she is asking Johnny to do the same.
The boy answered that he would cope with it without any difficulty. However, after a while he found out that different tricky things can occur. It can happen that it is impossible to construct a triangle of a positive area, but it is possible to construct a degenerate triangle. It can be so, that it is impossible to construct a degenerate triangle even. As Johnny is very lazy, he does not want to consider such a big amount of cases, he asks you to help him.
Input Specification:
The first line of the input contains four space-separated positive integer numbers not exceeding 100 — lengthes of the sticks.
Output Specification:
Output TRIANGLE if it is possible to construct a non-degenerate triangle. Output SEGMENT if the first case cannot take place and it is possible to construct a degenerate triangle. Output IMPOSSIBLE if it is impossible to construct any triangle. Remember that you are to use three sticks. It is not allowed to break the sticks or use their partial length.
Demo Input:
['4 2 1 3\n', '7 2 2 4\n', '3 5 9 1\n']
Demo Output:
['TRIANGLE\n', 'SEGMENT\n', 'IMPOSSIBLE\n']
Note:
none | ```python
# LUOGU_RID: 111258892
array = []
j = 0
while j <= 3:
a = input()
array.append(a)
j += 1
array.sort()
print(array)
if array[1]+array[2] > array[3]:
print('TRIANGLE')
if array[1]+array[2] == array[3]:
print('SEGMENT')
else:
print('IMPOSSIBLE')
``` | -1 |
918 | B | Radio Station | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | As the guys fried the radio station facilities, the school principal gave them tasks as a punishment. Dustin's task was to add comments to nginx configuration for school's website. The school has *n* servers. Each server has a name and an ip (names aren't necessarily unique, but ips are). Dustin knows the ip and name of each server. For simplicity, we'll assume that an nginx command is of form "command ip;" where command is a string consisting of English lowercase letter only, and ip is the ip of one of school servers.
Each ip is of form "a.b.c.d" where *a*, *b*, *c* and *d* are non-negative integers less than or equal to 255 (with no leading zeros). The nginx configuration file Dustin has to add comments to has *m* commands. Nobody ever memorizes the ips of servers, so to understand the configuration better, Dustin has to comment the name of server that the ip belongs to at the end of each line (after each command). More formally, if a line is "command ip;" Dustin has to replace it with "command ip; #name" where name is the name of the server with ip equal to ip.
Dustin doesn't know anything about nginx, so he panicked again and his friends asked you to do his task for him. | The first line of input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000).
The next *n* lines contain the names and ips of the servers. Each line contains a string name, name of the server and a string ip, ip of the server, separated by space (1<=≤<=|*name*|<=≤<=10, *name* only consists of English lowercase letters). It is guaranteed that all ip are distinct.
The next *m* lines contain the commands in the configuration file. Each line is of form "command ip;" (1<=≤<=|*command*|<=≤<=10, command only consists of English lowercase letters). It is guaranteed that ip belongs to one of the *n* school servers. | Print *m* lines, the commands in the configuration file after Dustin did his task. | [
"2 2\nmain 192.168.0.2\nreplica 192.168.0.1\nblock 192.168.0.1;\nproxy 192.168.0.2;\n",
"3 5\ngoogle 8.8.8.8\ncodeforces 212.193.33.27\nserver 138.197.64.57\nredirect 138.197.64.57;\nblock 8.8.8.8;\ncf 212.193.33.27;\nunblock 8.8.8.8;\ncheck 138.197.64.57;\n"
] | [
"block 192.168.0.1; #replica\nproxy 192.168.0.2; #main\n",
"redirect 138.197.64.57; #server\nblock 8.8.8.8; #google\ncf 212.193.33.27; #codeforces\nunblock 8.8.8.8; #google\ncheck 138.197.64.57; #server\n"
] | none | 1,000 | [
{
"input": "2 2\nmain 192.168.0.2\nreplica 192.168.0.1\nblock 192.168.0.1;\nproxy 192.168.0.2;",
"output": "block 192.168.0.1; #replica\nproxy 192.168.0.2; #main"
},
{
"input": "3 5\ngoogle 8.8.8.8\ncodeforces 212.193.33.27\nserver 138.197.64.57\nredirect 138.197.64.57;\nblock 8.8.8.8;\ncf 212.193.3... | 1,550,827,974 | 2,147,483,647 | PyPy 3 | OK | TESTS | 28 | 218 | 2,764,800 | n,m=map(int,input().split())
alfa,betta=[],[]
for i in range(n):
x,y=map(str,input().split())
x="#"+x
alfa.append(x)
betta.append(y)
for j in range(m):
x1,y1=map(str,input().split())
for j in range(n):
if y1[0:len(y1)-1]==betta[j]:
print(x1,y1,alfa[j])
| Title: Radio Station
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
As the guys fried the radio station facilities, the school principal gave them tasks as a punishment. Dustin's task was to add comments to nginx configuration for school's website. The school has *n* servers. Each server has a name and an ip (names aren't necessarily unique, but ips are). Dustin knows the ip and name of each server. For simplicity, we'll assume that an nginx command is of form "command ip;" where command is a string consisting of English lowercase letter only, and ip is the ip of one of school servers.
Each ip is of form "a.b.c.d" where *a*, *b*, *c* and *d* are non-negative integers less than or equal to 255 (with no leading zeros). The nginx configuration file Dustin has to add comments to has *m* commands. Nobody ever memorizes the ips of servers, so to understand the configuration better, Dustin has to comment the name of server that the ip belongs to at the end of each line (after each command). More formally, if a line is "command ip;" Dustin has to replace it with "command ip; #name" where name is the name of the server with ip equal to ip.
Dustin doesn't know anything about nginx, so he panicked again and his friends asked you to do his task for him.
Input Specification:
The first line of input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000).
The next *n* lines contain the names and ips of the servers. Each line contains a string name, name of the server and a string ip, ip of the server, separated by space (1<=≤<=|*name*|<=≤<=10, *name* only consists of English lowercase letters). It is guaranteed that all ip are distinct.
The next *m* lines contain the commands in the configuration file. Each line is of form "command ip;" (1<=≤<=|*command*|<=≤<=10, command only consists of English lowercase letters). It is guaranteed that ip belongs to one of the *n* school servers.
Output Specification:
Print *m* lines, the commands in the configuration file after Dustin did his task.
Demo Input:
['2 2\nmain 192.168.0.2\nreplica 192.168.0.1\nblock 192.168.0.1;\nproxy 192.168.0.2;\n', '3 5\ngoogle 8.8.8.8\ncodeforces 212.193.33.27\nserver 138.197.64.57\nredirect 138.197.64.57;\nblock 8.8.8.8;\ncf 212.193.33.27;\nunblock 8.8.8.8;\ncheck 138.197.64.57;\n']
Demo Output:
['block 192.168.0.1; #replica\nproxy 192.168.0.2; #main\n', 'redirect 138.197.64.57; #server\nblock 8.8.8.8; #google\ncf 212.193.33.27; #codeforces\nunblock 8.8.8.8; #google\ncheck 138.197.64.57; #server\n']
Note:
none | ```python
n,m=map(int,input().split())
alfa,betta=[],[]
for i in range(n):
x,y=map(str,input().split())
x="#"+x
alfa.append(x)
betta.append(y)
for j in range(m):
x1,y1=map(str,input().split())
for j in range(n):
if y1[0:len(y1)-1]==betta[j]:
print(x1,y1,alfa[j])
``` | 3 | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that is different in evenness. | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,580,495,102 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 218 | 0 | # _ = int(input())
# child = [int(a) for a in input().split()]
# total=sum(child)
# print(total//4+1 if total%4>0 else total//4)
# print(' '.join(input().replace("WUB",' ').split()))
_=int(input())
x=[int(a) for a in input().split()]
odd_odd=False
if len(list(filter(lambda x: x%2==0,x)))>len(list(filter(lambda x: x%2!=0,x))):
for number in x:
if number%2>0:
print(x.index(number)+1)
break
else:
for number in x:
if number %2==0:
print(x.index(number)+1)
| Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that is different in evenness.
Input Specification:
The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness.
Output Specification:
Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order.
Demo Input:
['5\n2 4 7 8 10\n', '4\n1 2 1 1\n']
Demo Output:
['3\n', '2\n']
Note:
none | ```python
# _ = int(input())
# child = [int(a) for a in input().split()]
# total=sum(child)
# print(total//4+1 if total%4>0 else total//4)
# print(' '.join(input().replace("WUB",' ').split()))
_=int(input())
x=[int(a) for a in input().split()]
odd_odd=False
if len(list(filter(lambda x: x%2==0,x)))>len(list(filter(lambda x: x%2!=0,x))):
for number in x:
if number%2>0:
print(x.index(number)+1)
break
else:
for number in x:
if number %2==0:
print(x.index(number)+1)
``` | 3.9455 |
519 | B | A and B and Compilation Errors | PROGRAMMING | 1,100 | [
"data structures",
"implementation",
"sortings"
] | null | null | A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler displayed *n* compilation errors, each of them is represented as a positive integer. After some effort, B managed to fix some mistake and then another one mistake.
However, despite the fact that B is sure that he corrected the two errors, he can not understand exactly what compilation errors disappeared — the compiler of the language which B uses shows errors in the new order every time! B is sure that unlike many other programming languages, compilation errors for his programming language do not depend on each other, that is, if you correct one error, the set of other error does not change.
Can you help B find out exactly what two errors he corrected? | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=105) — the initial number of compilation errors.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the errors the compiler displayed for the first time.
The third line contains *n*<=-<=1 space-separated integers *b*1,<=*b*2,<=...,<=*b**n*<=-<=1 — the errors displayed at the second compilation. It is guaranteed that the sequence in the third line contains all numbers of the second string except for exactly one.
The fourth line contains *n*<=-<=2 space-separated integers *с*1,<=*с*2,<=...,<=*с**n*<=-<=2 — the errors displayed at the third compilation. It is guaranteed that the sequence in the fourth line contains all numbers of the third line except for exactly one. | Print two numbers on a single line: the numbers of the compilation errors that disappeared after B made the first and the second correction, respectively. | [
"5\n1 5 8 123 7\n123 7 5 1\n5 1 7\n",
"6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5\n"
] | [
"8\n123\n",
"1\n3\n"
] | In the first test sample B first corrects the error number 8, then the error number 123.
In the second test sample B first corrects the error number 1, then the error number 3. Note that if there are multiple errors with the same number, B can correct only one of them in one step. | 1,000 | [
{
"input": "5\n1 5 8 123 7\n123 7 5 1\n5 1 7",
"output": "8\n123"
},
{
"input": "6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5",
"output": "1\n3"
},
{
"input": "3\n1 2 3\n3 2\n2",
"output": "1\n3"
},
{
"input": "10\n460626451 802090732 277246428 661369649 388684428 784303821 376287098 6... | 1,626,210,543 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 217 | 18,739,200 | n = int(input())
t1 = 0
for i in range(3):
s = str(input()).split()
t = 0
for a in s:
t += int(a)
if i!=0:
print(t1 - t)
t1 = t
| Title: A and B and Compilation Errors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A and B are preparing themselves for programming contests.
B loves to debug his code. But before he runs the solution and starts debugging, he has to first compile the code.
Initially, the compiler displayed *n* compilation errors, each of them is represented as a positive integer. After some effort, B managed to fix some mistake and then another one mistake.
However, despite the fact that B is sure that he corrected the two errors, he can not understand exactly what compilation errors disappeared — the compiler of the language which B uses shows errors in the new order every time! B is sure that unlike many other programming languages, compilation errors for his programming language do not depend on each other, that is, if you correct one error, the set of other error does not change.
Can you help B find out exactly what two errors he corrected?
Input Specification:
The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=105) — the initial number of compilation errors.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the errors the compiler displayed for the first time.
The third line contains *n*<=-<=1 space-separated integers *b*1,<=*b*2,<=...,<=*b**n*<=-<=1 — the errors displayed at the second compilation. It is guaranteed that the sequence in the third line contains all numbers of the second string except for exactly one.
The fourth line contains *n*<=-<=2 space-separated integers *с*1,<=*с*2,<=...,<=*с**n*<=-<=2 — the errors displayed at the third compilation. It is guaranteed that the sequence in the fourth line contains all numbers of the third line except for exactly one.
Output Specification:
Print two numbers on a single line: the numbers of the compilation errors that disappeared after B made the first and the second correction, respectively.
Demo Input:
['5\n1 5 8 123 7\n123 7 5 1\n5 1 7\n', '6\n1 4 3 3 5 7\n3 7 5 4 3\n4 3 7 5\n']
Demo Output:
['8\n123\n', '1\n3\n']
Note:
In the first test sample B first corrects the error number 8, then the error number 123.
In the second test sample B first corrects the error number 1, then the error number 3. Note that if there are multiple errors with the same number, B can correct only one of them in one step. | ```python
n = int(input())
t1 = 0
for i in range(3):
s = str(input()).split()
t = 0
for a in s:
t += int(a)
if i!=0:
print(t1 - t)
t1 = t
``` | 3 | |
828 | B | Black Square | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Polycarp has a checkered sheet of paper of size *n*<=×<=*m*. Polycarp painted some of cells with black, the others remained white. Inspired by Malevich's "Black Square", Polycarp wants to paint minimum possible number of white cells with black so that all black cells form a square.
You are to determine the minimum possible number of cells needed to be painted black so that the black cells form a black square with sides parallel to the painting's sides. All the cells that do not belong to the square should be white. The square's side should have positive length. | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the sizes of the sheet.
The next *n* lines contain *m* letters 'B' or 'W' each — the description of initial cells' colors. If a letter is 'B', then the corresponding cell is painted black, otherwise it is painted white. | Print the minimum number of cells needed to be painted black so that the black cells form a black square with sides parallel to the painting's sides. All the cells that do not belong to the square should be white. If it is impossible, print -1. | [
"5 4\nWWWW\nWWWB\nWWWB\nWWBB\nWWWW\n",
"1 2\nBB\n",
"3 3\nWWW\nWWW\nWWW\n"
] | [
"5\n",
"-1\n",
"1\n"
] | In the first example it is needed to paint 5 cells — (2, 2), (2, 3), (3, 2), (3, 3) and (4, 2). Then there will be a square with side equal to three, and the upper left corner in (2, 2).
In the second example all the cells are painted black and form a rectangle, so it's impossible to get a square.
In the third example all cells are colored white, so it's sufficient to color any cell black. | 750 | [
{
"input": "5 4\nWWWW\nWWWB\nWWWB\nWWBB\nWWWW",
"output": "5"
},
{
"input": "1 2\nBB",
"output": "-1"
},
{
"input": "3 3\nWWW\nWWW\nWWW",
"output": "1"
},
{
"input": "100 1\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nB\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\nW\n... | 1,502,916,661 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 91 | 62 | 0 | n, m = map(int, input().split())
g = [input() for i in range(n)]
b, r1, r2, c1, c2 = 0, n, -1, m, -1
for i in range(n):
for j in range(m):
if g[i][j] == 'B':
b += 1
r1 = min(r1, i)
r2 = max(r2, i)
c1 = min(c1, j)
c2 = max(c2, j)
s = max(r2 - r1 + 1, c2 - c1 + 1)
if b == 0:
print(1)
elif r1 > n - s and r2 < s - 1 or c1 > m - s and c2 < s - 1:
print(-1)
else:
print(s ** 2 - b) | Title: Black Square
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has a checkered sheet of paper of size *n*<=×<=*m*. Polycarp painted some of cells with black, the others remained white. Inspired by Malevich's "Black Square", Polycarp wants to paint minimum possible number of white cells with black so that all black cells form a square.
You are to determine the minimum possible number of cells needed to be painted black so that the black cells form a black square with sides parallel to the painting's sides. All the cells that do not belong to the square should be white. The square's side should have positive length.
Input Specification:
The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the sizes of the sheet.
The next *n* lines contain *m* letters 'B' or 'W' each — the description of initial cells' colors. If a letter is 'B', then the corresponding cell is painted black, otherwise it is painted white.
Output Specification:
Print the minimum number of cells needed to be painted black so that the black cells form a black square with sides parallel to the painting's sides. All the cells that do not belong to the square should be white. If it is impossible, print -1.
Demo Input:
['5 4\nWWWW\nWWWB\nWWWB\nWWBB\nWWWW\n', '1 2\nBB\n', '3 3\nWWW\nWWW\nWWW\n']
Demo Output:
['5\n', '-1\n', '1\n']
Note:
In the first example it is needed to paint 5 cells — (2, 2), (2, 3), (3, 2), (3, 3) and (4, 2). Then there will be a square with side equal to three, and the upper left corner in (2, 2).
In the second example all the cells are painted black and form a rectangle, so it's impossible to get a square.
In the third example all cells are colored white, so it's sufficient to color any cell black. | ```python
n, m = map(int, input().split())
g = [input() for i in range(n)]
b, r1, r2, c1, c2 = 0, n, -1, m, -1
for i in range(n):
for j in range(m):
if g[i][j] == 'B':
b += 1
r1 = min(r1, i)
r2 = max(r2, i)
c1 = min(c1, j)
c2 = max(c2, j)
s = max(r2 - r1 + 1, c2 - c1 + 1)
if b == 0:
print(1)
elif r1 > n - s and r2 < s - 1 or c1 > m - s and c2 < s - 1:
print(-1)
else:
print(s ** 2 - b)
``` | 0 | |
567 | A | Lineland Mail | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love to send letters to each other. A person may send a letter only if the recipient lives in another city (because if they live in the same city, then it is easier to drop in).
Strange but true, the cost of sending the letter is exactly equal to the distance between the sender's city and the recipient's city.
For each city calculate two values *min**i* and *max**i*, where *min**i* is the minimum cost of sending a letter from the *i*-th city to some other city, and *max**i* is the the maximum cost of sending a letter from the *i*-th city to some other city | The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=105) — the number of cities in Lineland. The second line contains the sequence of *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=109<=≤<=*x**i*<=≤<=109), where *x**i* is the *x*-coordinate of the *i*-th city. All the *x**i*'s are distinct and follow in ascending order. | Print *n* lines, the *i*-th line must contain two integers *min**i*,<=*max**i*, separated by a space, where *min**i* is the minimum cost of sending a letter from the *i*-th city, and *max**i* is the maximum cost of sending a letter from the *i*-th city. | [
"4\n-5 -2 2 7\n",
"2\n-1 1\n"
] | [
"3 12\n3 9\n4 7\n5 12\n",
"2 2\n2 2\n"
] | none | 500 | [
{
"input": "4\n-5 -2 2 7",
"output": "3 12\n3 9\n4 7\n5 12"
},
{
"input": "2\n-1 1",
"output": "2 2\n2 2"
},
{
"input": "3\n-1 0 1",
"output": "1 2\n1 1\n1 2"
},
{
"input": "4\n-1 0 1 3",
"output": "1 4\n1 3\n1 2\n2 4"
},
{
"input": "3\n-1000000000 0 1000000000",
... | 1,648,202,417 | 2,147,483,647 | Python 3 | OK | TESTS | 54 | 514 | 8,089,600 | n = int(input())
a = [int(i) for i in input().split()]
for i in range(n):
if i == 0:
print(abs(a[i] - a[i + 1]) , abs(a[i] - a[n - 1]))
elif i == (n - 1):
print(abs(a[i] - a[i - 1]) , abs(a[i] - a[0]))
else:
print(min(abs(a[i] - a[i + 1]) , abs(a[i] - a[i - 1])) , max(abs(a[i] - a[0]) , abs(a[i] - a[n - 1])))
| Title: Lineland Mail
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
All cities of Lineland are located on the *Ox* coordinate axis. Thus, each city is associated with its position *x**i* — a coordinate on the *Ox* axis. No two cities are located at a single point.
Lineland residents love to send letters to each other. A person may send a letter only if the recipient lives in another city (because if they live in the same city, then it is easier to drop in).
Strange but true, the cost of sending the letter is exactly equal to the distance between the sender's city and the recipient's city.
For each city calculate two values *min**i* and *max**i*, where *min**i* is the minimum cost of sending a letter from the *i*-th city to some other city, and *max**i* is the the maximum cost of sending a letter from the *i*-th city to some other city
Input Specification:
The first line of the input contains integer *n* (2<=≤<=*n*<=≤<=105) — the number of cities in Lineland. The second line contains the sequence of *n* distinct integers *x*1,<=*x*2,<=...,<=*x**n* (<=-<=109<=≤<=*x**i*<=≤<=109), where *x**i* is the *x*-coordinate of the *i*-th city. All the *x**i*'s are distinct and follow in ascending order.
Output Specification:
Print *n* lines, the *i*-th line must contain two integers *min**i*,<=*max**i*, separated by a space, where *min**i* is the minimum cost of sending a letter from the *i*-th city, and *max**i* is the maximum cost of sending a letter from the *i*-th city.
Demo Input:
['4\n-5 -2 2 7\n', '2\n-1 1\n']
Demo Output:
['3 12\n3 9\n4 7\n5 12\n', '2 2\n2 2\n']
Note:
none | ```python
n = int(input())
a = [int(i) for i in input().split()]
for i in range(n):
if i == 0:
print(abs(a[i] - a[i + 1]) , abs(a[i] - a[n - 1]))
elif i == (n - 1):
print(abs(a[i] - a[i - 1]) , abs(a[i] - a[0]))
else:
print(min(abs(a[i] - a[i + 1]) , abs(a[i] - a[i - 1])) , max(abs(a[i] - a[0]) , abs(a[i] - a[n - 1])))
``` | 3 | |
621 | B | Wet Shark and Bishops | PROGRAMMING | 1,300 | [
"combinatorics",
"implementation"
] | null | null | Today, Wet Shark is given *n* bishops on a 1000 by 1000 grid. Both rows and columns of the grid are numbered from 1 to 1000. Rows are numbered from top to bottom, while columns are numbered from left to right.
Wet Shark thinks that two bishops attack each other if they share the same diagonal. Note, that this is the only criteria, so two bishops may attack each other (according to Wet Shark) even if there is another bishop located between them. Now Wet Shark wants to count the number of pairs of bishops that attack each other. | The first line of the input contains *n* (1<=≤<=*n*<=≤<=200<=000) — the number of bishops.
Each of next *n* lines contains two space separated integers *x**i* and *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=1000) — the number of row and the number of column where *i*-th bishop is positioned. It's guaranteed that no two bishops share the same position. | Output one integer — the number of pairs of bishops which attack each other. | [
"5\n1 1\n1 5\n3 3\n5 1\n5 5\n",
"3\n1 1\n2 3\n3 5\n"
] | [
"6\n",
"0\n"
] | In the first sample following pairs of bishops attack each other: (1, 3), (1, 5), (2, 3), (2, 4), (3, 4) and (3, 5). Pairs (1, 2), (1, 4), (2, 5) and (4, 5) do not attack each other because they do not share the same diagonal. | 1,000 | [
{
"input": "5\n1 1\n1 5\n3 3\n5 1\n5 5",
"output": "6"
},
{
"input": "3\n1 1\n2 3\n3 5",
"output": "0"
},
{
"input": "3\n859 96\n634 248\n808 72",
"output": "0"
},
{
"input": "3\n987 237\n891 429\n358 145",
"output": "0"
},
{
"input": "3\n411 81\n149 907\n611 114"... | 1,591,381,625 | 2,147,483,647 | PyPy 3 | OK | TESTS | 68 | 1,497 | 9,420,800 | sum=[0]*2000;mi=[0]*2000;ans=0
for i in range(int(input())):
x,y=map(int,input().split())
sum[x+y-1]+=1
mi[x-y]+=1
for i in range(2000):
if sum[i] > 1:
ans+=(sum[i]*(sum[i]+1)//2)-sum[i]
if mi[i] > 1:
ans+=(mi[i]*(mi[i]+1)//2)-mi[i]
print(ans) | Title: Wet Shark and Bishops
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today, Wet Shark is given *n* bishops on a 1000 by 1000 grid. Both rows and columns of the grid are numbered from 1 to 1000. Rows are numbered from top to bottom, while columns are numbered from left to right.
Wet Shark thinks that two bishops attack each other if they share the same diagonal. Note, that this is the only criteria, so two bishops may attack each other (according to Wet Shark) even if there is another bishop located between them. Now Wet Shark wants to count the number of pairs of bishops that attack each other.
Input Specification:
The first line of the input contains *n* (1<=≤<=*n*<=≤<=200<=000) — the number of bishops.
Each of next *n* lines contains two space separated integers *x**i* and *y**i* (1<=≤<=*x**i*,<=*y**i*<=≤<=1000) — the number of row and the number of column where *i*-th bishop is positioned. It's guaranteed that no two bishops share the same position.
Output Specification:
Output one integer — the number of pairs of bishops which attack each other.
Demo Input:
['5\n1 1\n1 5\n3 3\n5 1\n5 5\n', '3\n1 1\n2 3\n3 5\n']
Demo Output:
['6\n', '0\n']
Note:
In the first sample following pairs of bishops attack each other: (1, 3), (1, 5), (2, 3), (2, 4), (3, 4) and (3, 5). Pairs (1, 2), (1, 4), (2, 5) and (4, 5) do not attack each other because they do not share the same diagonal. | ```python
sum=[0]*2000;mi=[0]*2000;ans=0
for i in range(int(input())):
x,y=map(int,input().split())
sum[x+y-1]+=1
mi[x-y]+=1
for i in range(2000):
if sum[i] > 1:
ans+=(sum[i]*(sum[i]+1)//2)-sum[i]
if mi[i] > 1:
ans+=(mi[i]*(mi[i]+1)//2)-mi[i]
print(ans)
``` | 3 | |
11 | A | Increasing Sequence | PROGRAMMING | 900 | [
"constructive algorithms",
"implementation",
"math"
] | A. Increasing Sequence | 1 | 64 | A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*. In each move you may choose one element of the given sequence and add *d* to it. What is the least number of moves required to make the given sequence increasing? | The first line of the input contains two integer numbers *n* and *d* (2<=≤<=*n*<=≤<=2000,<=1<=≤<=*d*<=≤<=106). The second line contains space separated sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 (1<=≤<=*b**i*<=≤<=106). | Output the minimal number of moves needed to make the sequence increasing. | [
"4 2\n1 3 3 2\n"
] | [
"3\n"
] | none | 0 | [
{
"input": "4 2\n1 3 3 2",
"output": "3"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 1\n2 5",
"output": "0"
},
{
"input": "2 1\n1 2",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 7\n10 20",
"output": "0"
},
... | 1,675,678,678 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 15 | 1,000 | 0 | # LUOGU_RID: 101582314
n,d=map(int,input().split())
a=list(map(int,input().split()))
b=0
for i in range(0,n-1):
while a[i]>=a[i+1]:
a[i+1]+=d
b+=1
print(b) | Title: Increasing Sequence
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*. In each move you may choose one element of the given sequence and add *d* to it. What is the least number of moves required to make the given sequence increasing?
Input Specification:
The first line of the input contains two integer numbers *n* and *d* (2<=≤<=*n*<=≤<=2000,<=1<=≤<=*d*<=≤<=106). The second line contains space separated sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 (1<=≤<=*b**i*<=≤<=106).
Output Specification:
Output the minimal number of moves needed to make the sequence increasing.
Demo Input:
['4 2\n1 3 3 2\n']
Demo Output:
['3\n']
Note:
none | ```python
# LUOGU_RID: 101582314
n,d=map(int,input().split())
a=list(map(int,input().split()))
b=0
for i in range(0,n-1):
while a[i]>=a[i+1]:
a[i+1]+=d
b+=1
print(b)
``` | 0 |
918 | A | Eleven | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Eleven wants to choose a new name for herself. As a bunch of geeks, her friends suggested an algorithm to choose a name for her. Eleven wants her name to have exactly *n* characters.
Her friend suggested that her name should only consist of uppercase and lowercase letters 'O'. More precisely, they suggested that the *i*-th letter of her name should be 'O' (uppercase) if *i* is a member of Fibonacci sequence, and 'o' (lowercase) otherwise. The letters in the name are numbered from 1 to *n*. Fibonacci sequence is the sequence *f* where
- *f*1<==<=1, - *f*2<==<=1, - *f**n*<==<=*f**n*<=-<=2<=+<=*f**n*<=-<=1 (*n*<=><=2).
As her friends are too young to know what Fibonacci sequence is, they asked you to help Eleven determine her new name. | The first and only line of input contains an integer *n* (1<=≤<=*n*<=≤<=1000). | Print Eleven's new name on the first and only line of output. | [
"8\n",
"15\n"
] | [
"OOOoOooO\n",
"OOOoOooOooooOoo\n"
] | none | 500 | [
{
"input": "8",
"output": "OOOoOooO"
},
{
"input": "15",
"output": "OOOoOooOooooOoo"
},
{
"input": "85",
"output": "OOOoOooOooooOoooooooOooooooooooooOooooooooooooooooooooOoooooooooooooooooooooooooooooo"
},
{
"input": "381",
"output": "OOOoOooOooooOoooooooOooooooooooooOooo... | 1,548,867,462 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 109 | 409,600 | n=int(input())
A=[]
A.append(0)
A.append(1)
for i in range(2,n+1):
A.append(A[i-2]+A[i-1])
for i in range(1,n+1):
if i in A:
print('O',end="")
else:
print('o',end="") | Title: Eleven
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eleven wants to choose a new name for herself. As a bunch of geeks, her friends suggested an algorithm to choose a name for her. Eleven wants her name to have exactly *n* characters.
Her friend suggested that her name should only consist of uppercase and lowercase letters 'O'. More precisely, they suggested that the *i*-th letter of her name should be 'O' (uppercase) if *i* is a member of Fibonacci sequence, and 'o' (lowercase) otherwise. The letters in the name are numbered from 1 to *n*. Fibonacci sequence is the sequence *f* where
- *f*1<==<=1, - *f*2<==<=1, - *f**n*<==<=*f**n*<=-<=2<=+<=*f**n*<=-<=1 (*n*<=><=2).
As her friends are too young to know what Fibonacci sequence is, they asked you to help Eleven determine her new name.
Input Specification:
The first and only line of input contains an integer *n* (1<=≤<=*n*<=≤<=1000).
Output Specification:
Print Eleven's new name on the first and only line of output.
Demo Input:
['8\n', '15\n']
Demo Output:
['OOOoOooO\n', 'OOOoOooOooooOoo\n']
Note:
none | ```python
n=int(input())
A=[]
A.append(0)
A.append(1)
for i in range(2,n+1):
A.append(A[i-2]+A[i-1])
for i in range(1,n+1):
if i in A:
print('O',end="")
else:
print('o',end="")
``` | 0 | |
910 | A | The Way to Home | PROGRAMMING | 800 | [
"dfs and similar",
"dp",
"greedy",
"implementation"
] | null | null | A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she can reach the point *x*<=+<=*a*, where *a* is an integer from 1 to *d*.
For each point from 1 to *n* is known if there is a lily flower in it. The frog can jump only in points with a lilies. Guaranteed that there are lilies in the points 1 and *n*.
Determine the minimal number of jumps that the frog needs to reach home which is in the point *n* from the point 1. Consider that initially the frog is in the point 1. If the frog can not reach home, print -1. | The first line contains two integers *n* and *d* (2<=≤<=*n*<=≤<=100, 1<=≤<=*d*<=≤<=*n*<=-<=1) — the point, which the frog wants to reach, and the maximal length of the frog jump.
The second line contains a string *s* of length *n*, consisting of zeros and ones. If a character of the string *s* equals to zero, then in the corresponding point there is no lily flower. In the other case, in the corresponding point there is a lily flower. Guaranteed that the first and the last characters of the string *s* equal to one. | If the frog can not reach the home, print -1.
In the other case, print the minimal number of jumps that the frog needs to reach the home which is in the point *n* from the point 1. | [
"8 4\n10010101\n",
"4 2\n1001\n",
"8 4\n11100101\n",
"12 3\n101111100101\n"
] | [
"2\n",
"-1\n",
"3\n",
"4\n"
] | In the first example the from can reach home in two jumps: the first jump from the point 1 to the point 4 (the length of the jump is three), and the second jump from the point 4 to the point 8 (the length of the jump is four).
In the second example the frog can not reach home, because to make it she need to jump on a distance three, but the maximum length of her jump equals to two. | 500 | [
{
"input": "8 4\n10010101",
"output": "2"
},
{
"input": "4 2\n1001",
"output": "-1"
},
{
"input": "8 4\n11100101",
"output": "3"
},
{
"input": "12 3\n101111100101",
"output": "4"
},
{
"input": "5 4\n11011",
"output": "1"
},
{
"input": "5 4\n10001",
... | 1,696,696,511 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 63 | 62 | 0 | n, d = map(int, input().split())
line = input()
zeros_streak = 0
count = 0
for i in line:
if i == '0':
count += 1
if count > zeros_streak:
zeros_streak = count
else:
count = 0
if zeros_streak >= d:
print(-1)
else:
tps = 0
i = 0
while i < n - 1:
if line[i] == '1':
i += d
tps += 1
else:
i -= 1
print(tps)
| Title: The Way to Home
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A frog lives on the axis *Ox* and needs to reach home which is in the point *n*. She starts from the point 1. The frog can jump to the right at a distance not more than *d*. So, after she jumped from the point *x* she can reach the point *x*<=+<=*a*, where *a* is an integer from 1 to *d*.
For each point from 1 to *n* is known if there is a lily flower in it. The frog can jump only in points with a lilies. Guaranteed that there are lilies in the points 1 and *n*.
Determine the minimal number of jumps that the frog needs to reach home which is in the point *n* from the point 1. Consider that initially the frog is in the point 1. If the frog can not reach home, print -1.
Input Specification:
The first line contains two integers *n* and *d* (2<=≤<=*n*<=≤<=100, 1<=≤<=*d*<=≤<=*n*<=-<=1) — the point, which the frog wants to reach, and the maximal length of the frog jump.
The second line contains a string *s* of length *n*, consisting of zeros and ones. If a character of the string *s* equals to zero, then in the corresponding point there is no lily flower. In the other case, in the corresponding point there is a lily flower. Guaranteed that the first and the last characters of the string *s* equal to one.
Output Specification:
If the frog can not reach the home, print -1.
In the other case, print the minimal number of jumps that the frog needs to reach the home which is in the point *n* from the point 1.
Demo Input:
['8 4\n10010101\n', '4 2\n1001\n', '8 4\n11100101\n', '12 3\n101111100101\n']
Demo Output:
['2\n', '-1\n', '3\n', '4\n']
Note:
In the first example the from can reach home in two jumps: the first jump from the point 1 to the point 4 (the length of the jump is three), and the second jump from the point 4 to the point 8 (the length of the jump is four).
In the second example the frog can not reach home, because to make it she need to jump on a distance three, but the maximum length of her jump equals to two. | ```python
n, d = map(int, input().split())
line = input()
zeros_streak = 0
count = 0
for i in line:
if i == '0':
count += 1
if count > zeros_streak:
zeros_streak = count
else:
count = 0
if zeros_streak >= d:
print(-1)
else:
tps = 0
i = 0
while i < n - 1:
if line[i] == '1':
i += d
tps += 1
else:
i -= 1
print(tps)
``` | 3 | |
797 | B | Odd sum | PROGRAMMING | 1,400 | [
"dp",
"greedy",
"implementation"
] | null | null | You are given sequence *a*1,<=*a*2,<=...,<=*a**n* of integer numbers of length *n*. Your task is to find such subsequence that its sum is odd and maximum among all such subsequences. It's guaranteed that given sequence contains subsequence with odd sum.
Subsequence is a sequence that can be derived from another sequence by deleting some elements without changing the order of the remaining elements.
You should write a program which finds sum of the best subsequence. | The first line contains integer number *n* (1<=≤<=*n*<=≤<=105).
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=104<=≤<=*a**i*<=≤<=104). The sequence contains at least one subsequence with odd sum. | Print sum of resulting subseqeuence. | [
"4\n-2 2 -3 1\n",
"3\n2 -5 -3\n"
] | [
"3\n",
"-1\n"
] | In the first example sum of the second and the fourth elements is 3. | 0 | [
{
"input": "4\n-2 2 -3 1",
"output": "3"
},
{
"input": "3\n2 -5 -3",
"output": "-1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "1\n-1",
"output": "-1"
},
{
"input": "15\n-6004 4882 9052 413 6056 4306 9946 -4616 -6135 906 -1718 5252 -2866 9061 4046",
"ou... | 1,587,640,533 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 16 | 124 | 409,600 | from collections import Counter,defaultdict,deque
import heapq as hq
from itertools import count, islice
#alph = 'abcdefghijklmnopqrstuvwxyz'
#from math import factorial as fact
import math
import sys
input=sys.stdin.readline
#print=sys.stdout.write
#tt = int(input())
#total=0
#n = int(input())
#n,m,k = [int(x) for x in input().split()]
#n = int(input())
#l,r = [int(x) for x in input().split()]
n = int(input())
arr = [int(x) for x in input().split()]
pos = []
neg = []
s = 0
for i in range(n):
if arr[i]>0:
pos.append(arr[i])
s+=arr[i]
else:
neg.append(arr[i])
if s%2:
print(s)
else:
pos.sort()
neg.sort(reverse=True)
lp = len(pos)
ln = len(neg)
if lp>ln:
neg.extend([0]*(lp-ln))
else:
pos.extend([0]*(ln-lp))
for i in range(max(ln,lp)):
if neg[i]%2:
if pos[i]%2:
print(s-min(pos[i],-neg[i]))
break
else:
print(s+neg[i])
break
elif pos[i]%2:
print(s-pos[i])
break
| Title: Odd sum
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given sequence *a*1,<=*a*2,<=...,<=*a**n* of integer numbers of length *n*. Your task is to find such subsequence that its sum is odd and maximum among all such subsequences. It's guaranteed that given sequence contains subsequence with odd sum.
Subsequence is a sequence that can be derived from another sequence by deleting some elements without changing the order of the remaining elements.
You should write a program which finds sum of the best subsequence.
Input Specification:
The first line contains integer number *n* (1<=≤<=*n*<=≤<=105).
The second line contains *n* integer numbers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=104<=≤<=*a**i*<=≤<=104). The sequence contains at least one subsequence with odd sum.
Output Specification:
Print sum of resulting subseqeuence.
Demo Input:
['4\n-2 2 -3 1\n', '3\n2 -5 -3\n']
Demo Output:
['3\n', '-1\n']
Note:
In the first example sum of the second and the fourth elements is 3. | ```python
from collections import Counter,defaultdict,deque
import heapq as hq
from itertools import count, islice
#alph = 'abcdefghijklmnopqrstuvwxyz'
#from math import factorial as fact
import math
import sys
input=sys.stdin.readline
#print=sys.stdout.write
#tt = int(input())
#total=0
#n = int(input())
#n,m,k = [int(x) for x in input().split()]
#n = int(input())
#l,r = [int(x) for x in input().split()]
n = int(input())
arr = [int(x) for x in input().split()]
pos = []
neg = []
s = 0
for i in range(n):
if arr[i]>0:
pos.append(arr[i])
s+=arr[i]
else:
neg.append(arr[i])
if s%2:
print(s)
else:
pos.sort()
neg.sort(reverse=True)
lp = len(pos)
ln = len(neg)
if lp>ln:
neg.extend([0]*(lp-ln))
else:
pos.extend([0]*(ln-lp))
for i in range(max(ln,lp)):
if neg[i]%2:
if pos[i]%2:
print(s-min(pos[i],-neg[i]))
break
else:
print(s+neg[i])
break
elif pos[i]%2:
print(s-pos[i])
break
``` | 0 | |
626 | C | Block Towers | PROGRAMMING | 1,600 | [
"brute force",
"greedy",
"math",
"number theory"
] | null | null | Students in a class are making towers of blocks. Each student makes a (non-zero) tower by stacking pieces lengthwise on top of each other. *n* of the students use pieces made of two blocks and *m* of the students use pieces made of three blocks.
The students don’t want to use too many blocks, but they also want to be unique, so no two students’ towers may contain the same number of blocks. Find the minimum height necessary for the tallest of the students' towers. | The first line of the input contains two space-separated integers *n* and *m* (0<=≤<=*n*,<=*m*<=≤<=1<=000<=000, *n*<=+<=*m*<=><=0) — the number of students using two-block pieces and the number of students using three-block pieces, respectively. | Print a single integer, denoting the minimum possible height of the tallest tower. | [
"1 3\n",
"3 2\n",
"5 0\n"
] | [
"9\n",
"8\n",
"10\n"
] | In the first case, the student using two-block pieces can make a tower of height 4, and the students using three-block pieces can make towers of height 3, 6, and 9 blocks. The tallest tower has a height of 9 blocks.
In the second case, the students can make towers of heights 2, 4, and 8 with two-block pieces and towers of heights 3 and 6 with three-block pieces, for a maximum height of 8 blocks. | 1,000 | [
{
"input": "1 3",
"output": "9"
},
{
"input": "3 2",
"output": "8"
},
{
"input": "5 0",
"output": "10"
},
{
"input": "4 2",
"output": "9"
},
{
"input": "0 1000000",
"output": "3000000"
},
{
"input": "1000000 1",
"output": "2000000"
},
{
"in... | 1,455,831,042 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | a, b = map(int, input().split(' '))
print(max(a*2, b*3)) | Title: Block Towers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Students in a class are making towers of blocks. Each student makes a (non-zero) tower by stacking pieces lengthwise on top of each other. *n* of the students use pieces made of two blocks and *m* of the students use pieces made of three blocks.
The students don’t want to use too many blocks, but they also want to be unique, so no two students’ towers may contain the same number of blocks. Find the minimum height necessary for the tallest of the students' towers.
Input Specification:
The first line of the input contains two space-separated integers *n* and *m* (0<=≤<=*n*,<=*m*<=≤<=1<=000<=000, *n*<=+<=*m*<=><=0) — the number of students using two-block pieces and the number of students using three-block pieces, respectively.
Output Specification:
Print a single integer, denoting the minimum possible height of the tallest tower.
Demo Input:
['1 3\n', '3 2\n', '5 0\n']
Demo Output:
['9\n', '8\n', '10\n']
Note:
In the first case, the student using two-block pieces can make a tower of height 4, and the students using three-block pieces can make towers of height 3, 6, and 9 blocks. The tallest tower has a height of 9 blocks.
In the second case, the students can make towers of heights 2, 4, and 8 with two-block pieces and towers of heights 3 and 6 with three-block pieces, for a maximum height of 8 blocks. | ```python
a, b = map(int, input().split(' '))
print(max(a*2, b*3))
``` | 0 | |
877 | A | Alex and broken contest | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | One day Alex was creating a contest about his friends, but accidentally deleted it. Fortunately, all the problems were saved, but now he needs to find them among other problems.
But there are too many problems, to do it manually. Alex asks you to write a program, which will determine if a problem is from this contest by its name.
It is known, that problem is from this contest if and only if its name contains one of Alex's friends' name exactly once. His friends' names are "Danil", "Olya", "Slava", "Ann" and "Nikita".
Names are case sensitive. | The only line contains string from lowercase and uppercase letters and "_" symbols of length, not more than 100 — the name of the problem. | Print "YES", if problem is from this contest, and "NO" otherwise. | [
"Alex_and_broken_contest\n",
"NikitaAndString\n",
"Danil_and_Olya\n"
] | [
"NO",
"YES",
"NO"
] | none | 500 | [
{
"input": "Alex_and_broken_contest",
"output": "NO"
},
{
"input": "NikitaAndString",
"output": "YES"
},
{
"input": "Danil_and_Olya",
"output": "NO"
},
{
"input": "Slava____and_the_game",
"output": "YES"
},
{
"input": "Olya_and_energy_drinks",
"output": "YES"
... | 1,668,668,628 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 55 | 62 | 0 | s = input()
names = ['Danil', 'Olya', 'Slava', 'Ann', 'Nikita']
count = 0
for n in names:
count += s.count(n)
print('YES' if count ==1 else 'NO')
| Title: Alex and broken contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Alex was creating a contest about his friends, but accidentally deleted it. Fortunately, all the problems were saved, but now he needs to find them among other problems.
But there are too many problems, to do it manually. Alex asks you to write a program, which will determine if a problem is from this contest by its name.
It is known, that problem is from this contest if and only if its name contains one of Alex's friends' name exactly once. His friends' names are "Danil", "Olya", "Slava", "Ann" and "Nikita".
Names are case sensitive.
Input Specification:
The only line contains string from lowercase and uppercase letters and "_" symbols of length, not more than 100 — the name of the problem.
Output Specification:
Print "YES", if problem is from this contest, and "NO" otherwise.
Demo Input:
['Alex_and_broken_contest\n', 'NikitaAndString\n', 'Danil_and_Olya\n']
Demo Output:
['NO', 'YES', 'NO']
Note:
none | ```python
s = input()
names = ['Danil', 'Olya', 'Slava', 'Ann', 'Nikita']
count = 0
for n in names:
count += s.count(n)
print('YES' if count ==1 else 'NO')
``` | 3 | |
148 | A | Insomnia cure | PROGRAMMING | 800 | [
"constructive algorithms",
"implementation",
"math"
] | null | null | «One dragon. Two dragon. Three dragon», — the princess was counting. She had trouble falling asleep, and she got bored of counting lambs when she was nine.
However, just counting dragons was boring as well, so she entertained herself at best she could. Tonight she imagined that all dragons were here to steal her, and she was fighting them off. Every *k*-th dragon got punched in the face with a frying pan. Every *l*-th dragon got his tail shut into the balcony door. Every *m*-th dragon got his paws trampled with sharp heels. Finally, she threatened every *n*-th dragon to call her mom, and he withdrew in panic.
How many imaginary dragons suffered moral or physical damage tonight, if the princess counted a total of *d* dragons? | Input data contains integer numbers *k*,<=*l*,<=*m*,<=*n* and *d*, each number in a separate line (1<=≤<=*k*,<=*l*,<=*m*,<=*n*<=≤<=10, 1<=≤<=*d*<=≤<=105). | Output the number of damaged dragons. | [
"1\n2\n3\n4\n12\n",
"2\n3\n4\n5\n24\n"
] | [
"12\n",
"17\n"
] | In the first case every first dragon got punched with a frying pan. Some of the dragons suffered from other reasons as well, but the pan alone would be enough.
In the second case dragons 1, 7, 11, 13, 17, 19 and 23 escaped unharmed. | 1,000 | [
{
"input": "1\n2\n3\n4\n12",
"output": "12"
},
{
"input": "2\n3\n4\n5\n24",
"output": "17"
},
{
"input": "1\n1\n1\n1\n100000",
"output": "100000"
},
{
"input": "10\n9\n8\n7\n6",
"output": "0"
},
{
"input": "8\n4\n4\n3\n65437",
"output": "32718"
},
{
"i... | 1,685,465,596 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 40 | 154 | 2,150,400 | k=int(input())
l=int(input())
m=int(input())
n=int(input())
d=int(input())
#d_list=[]
#not_in_list=[]
#c=0
'''print(d//k + d//l + d//m + d//n - d//(k*l) - d//(k*m) - d//(k*n) - d//(l*m) - d//(l*n) - d//(m*n) + d//(k*l*m) + d//(l*m*n) + d//(m*n*k) + d//(k*l*n) - 2*d//(k*l*m*n))'''
'''for i in range(1,d+1):
d_list.append(i)
for i in range(k,d+1,k):
d_list.remove(i)
for i in range(l,d+1,l):
if i in d_list:
d_list.remove(i)
for i in range(m,d+1,m):
if i in d_list:
d_list.remove(i)
for i in range(n,d+1,n):
if i in d_list:
d_list.remove(i)
print(d-len(d_list))'''
'''for i in range(k,d+1,k):
c+=1
not_in_list.append(i)
for i in range(l,d+1,l):
if i not in not_in_list:
not_in_list.append(i)
c+=1
for i in range(m,d+1,m):
if i not in not_in_list:
not_in_list.append(i)
c+=1
for i in range(n,d+1,n):
if i not in not_in_list:
#not_in_list.append(i)
c+=1
print(c)'''
if k==1 or l==1 or m==1 or n==1:
print(d)
else:
count=d//k+d//l+d//m+d//n
for i in range(l,d+1,l):
if i%k==0:
count-=1
for i in range(m,d+1,m):
if i%k==0 or i%l==0:
count-=1
for i in range(n,d+1,n):
if i%k==0 or i%l==0 or i%m==0:
count-=1
print(count)
| Title: Insomnia cure
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
«One dragon. Two dragon. Three dragon», — the princess was counting. She had trouble falling asleep, and she got bored of counting lambs when she was nine.
However, just counting dragons was boring as well, so she entertained herself at best she could. Tonight she imagined that all dragons were here to steal her, and she was fighting them off. Every *k*-th dragon got punched in the face with a frying pan. Every *l*-th dragon got his tail shut into the balcony door. Every *m*-th dragon got his paws trampled with sharp heels. Finally, she threatened every *n*-th dragon to call her mom, and he withdrew in panic.
How many imaginary dragons suffered moral or physical damage tonight, if the princess counted a total of *d* dragons?
Input Specification:
Input data contains integer numbers *k*,<=*l*,<=*m*,<=*n* and *d*, each number in a separate line (1<=≤<=*k*,<=*l*,<=*m*,<=*n*<=≤<=10, 1<=≤<=*d*<=≤<=105).
Output Specification:
Output the number of damaged dragons.
Demo Input:
['1\n2\n3\n4\n12\n', '2\n3\n4\n5\n24\n']
Demo Output:
['12\n', '17\n']
Note:
In the first case every first dragon got punched with a frying pan. Some of the dragons suffered from other reasons as well, but the pan alone would be enough.
In the second case dragons 1, 7, 11, 13, 17, 19 and 23 escaped unharmed. | ```python
k=int(input())
l=int(input())
m=int(input())
n=int(input())
d=int(input())
#d_list=[]
#not_in_list=[]
#c=0
'''print(d//k + d//l + d//m + d//n - d//(k*l) - d//(k*m) - d//(k*n) - d//(l*m) - d//(l*n) - d//(m*n) + d//(k*l*m) + d//(l*m*n) + d//(m*n*k) + d//(k*l*n) - 2*d//(k*l*m*n))'''
'''for i in range(1,d+1):
d_list.append(i)
for i in range(k,d+1,k):
d_list.remove(i)
for i in range(l,d+1,l):
if i in d_list:
d_list.remove(i)
for i in range(m,d+1,m):
if i in d_list:
d_list.remove(i)
for i in range(n,d+1,n):
if i in d_list:
d_list.remove(i)
print(d-len(d_list))'''
'''for i in range(k,d+1,k):
c+=1
not_in_list.append(i)
for i in range(l,d+1,l):
if i not in not_in_list:
not_in_list.append(i)
c+=1
for i in range(m,d+1,m):
if i not in not_in_list:
not_in_list.append(i)
c+=1
for i in range(n,d+1,n):
if i not in not_in_list:
#not_in_list.append(i)
c+=1
print(c)'''
if k==1 or l==1 or m==1 or n==1:
print(d)
else:
count=d//k+d//l+d//m+d//n
for i in range(l,d+1,l):
if i%k==0:
count-=1
for i in range(m,d+1,m):
if i%k==0 or i%l==0:
count-=1
for i in range(n,d+1,n):
if i%k==0 or i%l==0 or i%m==0:
count-=1
print(count)
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | In Absurdistan, there are *n* towns (numbered 1 through *n*) and *m* bidirectional railways. There is also an absurdly simple road network — for each pair of different towns *x* and *y*, there is a bidirectional road between towns *x* and *y* if and only if there is no railway between them. Travelling to a different town using one railway or one road always takes exactly one hour.
A train and a bus leave town 1 at the same time. They both have the same destination, town *n*, and don't make any stops on the way (but they can wait in town *n*). The train can move only along railways and the bus can move only along roads.
You've been asked to plan out routes for the vehicles; each route can use any road/railway multiple times. One of the most important aspects to consider is safety — in order to avoid accidents at railway crossings, the train and the bus must not arrive at the same town (except town *n*) simultaneously.
Under these constraints, what is the minimum number of hours needed for both vehicles to reach town *n* (the maximum of arrival times of the bus and the train)? Note, that bus and train are not required to arrive to the town *n* at the same moment of time, but are allowed to do so. | The first line of the input contains two integers *n* and *m* (2<=≤<=*n*<=≤<=400, 0<=≤<=*m*<=≤<=*n*(*n*<=-<=1)<=/<=2) — the number of towns and the number of railways respectively.
Each of the next *m* lines contains two integers *u* and *v*, denoting a railway between towns *u* and *v* (1<=≤<=*u*,<=*v*<=≤<=*n*, *u*<=≠<=*v*).
You may assume that there is at most one railway connecting any two towns. | Output one integer — the smallest possible time of the later vehicle's arrival in town *n*. If it's impossible for at least one of the vehicles to reach town *n*, output <=-<=1. | [
"4 2\n1 3\n3 4\n",
"4 6\n1 2\n1 3\n1 4\n2 3\n2 4\n3 4\n",
"5 5\n4 2\n3 5\n4 5\n5 1\n1 2\n"
] | [
"2\n",
"-1\n",
"3\n"
] | In the first sample, the train can take the route <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/7c0aa60a06309ef607b7159fd7f3687ea0d943ce.png" style="max-width: 100.0%;max-height: 100.0%;"/> and the bus can take the route <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/a26c2f3e93c9d9be6c21cb5d2bd6ac1f99f4ff55.png" style="max-width: 100.0%;max-height: 100.0%;"/>. Note that they can arrive at town 4 at the same time.
In the second sample, Absurdistan is ruled by railwaymen. There are no roads, so there's no way for the bus to reach town 4. | 0 | [
{
"input": "4 2\n1 3\n3 4",
"output": "2"
},
{
"input": "4 6\n1 2\n1 3\n1 4\n2 3\n2 4\n3 4",
"output": "-1"
},
{
"input": "5 5\n4 2\n3 5\n4 5\n5 1\n1 2",
"output": "3"
},
{
"input": "5 4\n1 2\n3 2\n3 4\n5 4",
"output": "4"
},
{
"input": "3 1\n1 2",
"output": "... | 1,448,388,070 | 5,170 | PyPy 3 | OK | TESTS | 59 | 763 | 6,144,000 | n,m = map(int, input().split())
x = [0] * n
for i in range(n):
x[i] = [0] * n
for i in range(m):
a,b = map(int, input().split())
x[a-1][b-1] = 1
x[b-1][a-1] = 1
visited = set()
visited |= set([0])
stack = []
stack.append((0,0))
while stack != []:
cur = stack.pop(0)
#print( "%d %d" % cur)
t = 0
for i in range(n):
if i not in visited:
if x[cur[0]][i] == 1:
stack.append(( i,cur[1]+1))
visited |= set ( [ i ] )
#print( "add %d" % i)
t += 1
if (n-1) in visited:
break
first = -1
for i in range(len(stack)):
if ( stack[i][0] == (n-1) ):
first = stack[i][1]
#print(first)
visited = set()
visited |= set([0])
stack = []
stack.append((0,0))
while stack != []:
cur = stack.pop(0)
#print( "%d %d" % cur)
t = 0
for i in range(n):
if i not in visited:
if x[cur[0]][i] == 0:
stack.append(( i,cur[1]+1))
visited |= set ( [ i ] )
#print( "add %d" % i)
t += 1
if (n-1) in visited:
break
second = -1
for i in range(len(stack)):
if ( stack[i][0] == (n-1) ):
second = stack[i][1]
#print(second)
if ( first == -1 or second == -1 ):
print("-1")
else:
print ( max ( first, second) )
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In Absurdistan, there are *n* towns (numbered 1 through *n*) and *m* bidirectional railways. There is also an absurdly simple road network — for each pair of different towns *x* and *y*, there is a bidirectional road between towns *x* and *y* if and only if there is no railway between them. Travelling to a different town using one railway or one road always takes exactly one hour.
A train and a bus leave town 1 at the same time. They both have the same destination, town *n*, and don't make any stops on the way (but they can wait in town *n*). The train can move only along railways and the bus can move only along roads.
You've been asked to plan out routes for the vehicles; each route can use any road/railway multiple times. One of the most important aspects to consider is safety — in order to avoid accidents at railway crossings, the train and the bus must not arrive at the same town (except town *n*) simultaneously.
Under these constraints, what is the minimum number of hours needed for both vehicles to reach town *n* (the maximum of arrival times of the bus and the train)? Note, that bus and train are not required to arrive to the town *n* at the same moment of time, but are allowed to do so.
Input Specification:
The first line of the input contains two integers *n* and *m* (2<=≤<=*n*<=≤<=400, 0<=≤<=*m*<=≤<=*n*(*n*<=-<=1)<=/<=2) — the number of towns and the number of railways respectively.
Each of the next *m* lines contains two integers *u* and *v*, denoting a railway between towns *u* and *v* (1<=≤<=*u*,<=*v*<=≤<=*n*, *u*<=≠<=*v*).
You may assume that there is at most one railway connecting any two towns.
Output Specification:
Output one integer — the smallest possible time of the later vehicle's arrival in town *n*. If it's impossible for at least one of the vehicles to reach town *n*, output <=-<=1.
Demo Input:
['4 2\n1 3\n3 4\n', '4 6\n1 2\n1 3\n1 4\n2 3\n2 4\n3 4\n', '5 5\n4 2\n3 5\n4 5\n5 1\n1 2\n']
Demo Output:
['2\n', '-1\n', '3\n']
Note:
In the first sample, the train can take the route <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/7c0aa60a06309ef607b7159fd7f3687ea0d943ce.png" style="max-width: 100.0%;max-height: 100.0%;"/> and the bus can take the route <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/a26c2f3e93c9d9be6c21cb5d2bd6ac1f99f4ff55.png" style="max-width: 100.0%;max-height: 100.0%;"/>. Note that they can arrive at town 4 at the same time.
In the second sample, Absurdistan is ruled by railwaymen. There are no roads, so there's no way for the bus to reach town 4. | ```python
n,m = map(int, input().split())
x = [0] * n
for i in range(n):
x[i] = [0] * n
for i in range(m):
a,b = map(int, input().split())
x[a-1][b-1] = 1
x[b-1][a-1] = 1
visited = set()
visited |= set([0])
stack = []
stack.append((0,0))
while stack != []:
cur = stack.pop(0)
#print( "%d %d" % cur)
t = 0
for i in range(n):
if i not in visited:
if x[cur[0]][i] == 1:
stack.append(( i,cur[1]+1))
visited |= set ( [ i ] )
#print( "add %d" % i)
t += 1
if (n-1) in visited:
break
first = -1
for i in range(len(stack)):
if ( stack[i][0] == (n-1) ):
first = stack[i][1]
#print(first)
visited = set()
visited |= set([0])
stack = []
stack.append((0,0))
while stack != []:
cur = stack.pop(0)
#print( "%d %d" % cur)
t = 0
for i in range(n):
if i not in visited:
if x[cur[0]][i] == 0:
stack.append(( i,cur[1]+1))
visited |= set ( [ i ] )
#print( "add %d" % i)
t += 1
if (n-1) in visited:
break
second = -1
for i in range(len(stack)):
if ( stack[i][0] == (n-1) ):
second = stack[i][1]
#print(second)
if ( first == -1 or second == -1 ):
print("-1")
else:
print ( max ( first, second) )
``` | 3 | |
903 | C | Boxes Packing | PROGRAMMING | 1,200 | [
"greedy"
] | null | null | Mishka has got *n* empty boxes. For every *i* (1<=≤<=*i*<=≤<=*n*), *i*-th box is a cube with side length *a**i*.
Mishka can put a box *i* into another box *j* if the following conditions are met:
- *i*-th box is not put into another box; - *j*-th box doesn't contain any other boxes; - box *i* is smaller than box *j* (*a**i*<=<<=*a**j*).
Mishka can put boxes into each other an arbitrary number of times. He wants to minimize the number of visible boxes. A box is called visible iff it is not put into some another box.
Help Mishka to determine the minimum possible number of visible boxes! | The first line contains one integer *n* (1<=≤<=*n*<=≤<=5000) — the number of boxes Mishka has got.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=109), where *a**i* is the side length of *i*-th box. | Print the minimum possible number of visible boxes. | [
"3\n1 2 3\n",
"4\n4 2 4 3\n"
] | [
"1\n",
"2\n"
] | In the first example it is possible to put box 1 into box 2, and 2 into 3.
In the second example Mishka can put box 2 into box 3, and box 4 into box 1. | 0 | [
{
"input": "3\n1 2 3",
"output": "1"
},
{
"input": "4\n4 2 4 3",
"output": "2"
},
{
"input": "10\n58 58 58 58 58 58 58 58 58 58",
"output": "10"
},
{
"input": "10\n86 89 89 86 86 89 86 86 89 89",
"output": "5"
},
{
"input": "100\n981 288 186 186 292 876 341 288 98... | 1,571,297,476 | 2,147,483,647 | Python 3 | OK | TESTS | 24 | 124 | 512,000 | n=int(input())
lst=list(map(int,input().split()))
d={}
for i,x in enumerate(lst):
if d.get(x)==None:d[x]=0
d[x]+=1
print(max(d.values())) | Title: Boxes Packing
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mishka has got *n* empty boxes. For every *i* (1<=≤<=*i*<=≤<=*n*), *i*-th box is a cube with side length *a**i*.
Mishka can put a box *i* into another box *j* if the following conditions are met:
- *i*-th box is not put into another box; - *j*-th box doesn't contain any other boxes; - box *i* is smaller than box *j* (*a**i*<=<<=*a**j*).
Mishka can put boxes into each other an arbitrary number of times. He wants to minimize the number of visible boxes. A box is called visible iff it is not put into some another box.
Help Mishka to determine the minimum possible number of visible boxes!
Input Specification:
The first line contains one integer *n* (1<=≤<=*n*<=≤<=5000) — the number of boxes Mishka has got.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=109), where *a**i* is the side length of *i*-th box.
Output Specification:
Print the minimum possible number of visible boxes.
Demo Input:
['3\n1 2 3\n', '4\n4 2 4 3\n']
Demo Output:
['1\n', '2\n']
Note:
In the first example it is possible to put box 1 into box 2, and 2 into 3.
In the second example Mishka can put box 2 into box 3, and box 4 into box 1. | ```python
n=int(input())
lst=list(map(int,input().split()))
d={}
for i,x in enumerate(lst):
if d.get(x)==None:d[x]=0
d[x]+=1
print(max(d.values()))
``` | 3 | |
1,004 | C | Sonya and Robots | PROGRAMMING | 1,400 | [
"constructive algorithms",
"implementation"
] | null | null | Since Sonya is interested in robotics too, she decided to construct robots that will read and recognize numbers.
Sonya has drawn $n$ numbers in a row, $a_i$ is located in the $i$-th position. She also has put a robot at each end of the row (to the left of the first number and to the right of the last number). Sonya will give a number to each robot (they can be either same or different) and run them. When a robot is running, it is moving toward to another robot, reading numbers in the row. When a robot is reading a number that is equal to the number that was given to that robot, it will turn off and stay in the same position.
Sonya does not want robots to break, so she will give such numbers that robots will stop before they meet. That is, the girl wants them to stop at different positions so that the first robot is to the left of the second one.
For example, if the numbers $[1, 5, 4, 1, 3]$ are written, and Sonya gives the number $1$ to the first robot and the number $4$ to the second one, the first robot will stop in the $1$-st position while the second one in the $3$-rd position. In that case, robots will not meet each other. As a result, robots will not be broken. But if Sonya gives the number $4$ to the first robot and the number $5$ to the second one, they will meet since the first robot will stop in the $3$-rd position while the second one is in the $2$-nd position.
Sonya understands that it does not make sense to give a number that is not written in the row because a robot will not find this number and will meet the other robot.
Sonya is now interested in finding the number of different pairs that she can give to robots so that they will not meet. In other words, she wants to know the number of pairs ($p$, $q$), where she will give $p$ to the first robot and $q$ to the second one. Pairs ($p_i$, $q_i$) and ($p_j$, $q_j$) are different if $p_i\neq p_j$ or $q_i\neq q_j$.
Unfortunately, Sonya is busy fixing robots that broke after a failed launch. That is why she is asking you to find the number of pairs that she can give to robots so that they will not meet. | The first line contains a single integer $n$ ($1\leq n\leq 10^5$) — the number of numbers in a row.
The second line contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1\leq a_i\leq 10^5$) — the numbers in a row. | Print one number — the number of possible pairs that Sonya can give to robots so that they will not meet. | [
"5\n1 5 4 1 3\n",
"7\n1 2 1 1 1 3 2\n"
] | [
"9\n",
"7\n"
] | In the first example, Sonya can give pairs ($1$, $1$), ($1$, $3$), ($1$, $4$), ($1$, $5$), ($4$, $1$), ($4$, $3$), ($5$, $1$), ($5$, $3$), and ($5$, $4$).
In the second example, Sonya can give pairs ($1$, $1$), ($1$, $2$), ($1$, $3$), ($2$, $1$), ($2$, $2$), ($2$, $3$), and ($3$, $2$). | 1,500 | [
{
"input": "5\n1 5 4 1 3",
"output": "9"
},
{
"input": "7\n1 2 1 1 1 3 2",
"output": "7"
},
{
"input": "10\n2 2 4 4 3 1 1 2 3 2",
"output": "14"
},
{
"input": "15\n1 2 2 1 2 4 2 1 1 6 6 4 2 5 4",
"output": "20"
},
{
"input": "1\n1",
"output": "0"
}
] | 1,530,812,882 | 4,382 | Python 3 | RUNTIME_ERROR | PRETESTS | 0 | 78 | 0 | import numpy
n = [int(s) for s in input().split(" ")]
numbers = [int(s) for s in input().split(" ")]
# lol = np.z[[-1,-1]]*10001
lol = numpy.full((10001,2),-1)
for i in range(0,len(numbers)):
if lol[numbers[i]][0]>-1:
continue
else:
lol[numbers[i]][0]=i
for i in range(len(numbers)-1,0,-1):
if lol[numbers[i]][1]>-1:
continue
else:
lol[numbers[i]][1]=i
print(lol) | Title: Sonya and Robots
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Since Sonya is interested in robotics too, she decided to construct robots that will read and recognize numbers.
Sonya has drawn $n$ numbers in a row, $a_i$ is located in the $i$-th position. She also has put a robot at each end of the row (to the left of the first number and to the right of the last number). Sonya will give a number to each robot (they can be either same or different) and run them. When a robot is running, it is moving toward to another robot, reading numbers in the row. When a robot is reading a number that is equal to the number that was given to that robot, it will turn off and stay in the same position.
Sonya does not want robots to break, so she will give such numbers that robots will stop before they meet. That is, the girl wants them to stop at different positions so that the first robot is to the left of the second one.
For example, if the numbers $[1, 5, 4, 1, 3]$ are written, and Sonya gives the number $1$ to the first robot and the number $4$ to the second one, the first robot will stop in the $1$-st position while the second one in the $3$-rd position. In that case, robots will not meet each other. As a result, robots will not be broken. But if Sonya gives the number $4$ to the first robot and the number $5$ to the second one, they will meet since the first robot will stop in the $3$-rd position while the second one is in the $2$-nd position.
Sonya understands that it does not make sense to give a number that is not written in the row because a robot will not find this number and will meet the other robot.
Sonya is now interested in finding the number of different pairs that she can give to robots so that they will not meet. In other words, she wants to know the number of pairs ($p$, $q$), where she will give $p$ to the first robot and $q$ to the second one. Pairs ($p_i$, $q_i$) and ($p_j$, $q_j$) are different if $p_i\neq p_j$ or $q_i\neq q_j$.
Unfortunately, Sonya is busy fixing robots that broke after a failed launch. That is why she is asking you to find the number of pairs that she can give to robots so that they will not meet.
Input Specification:
The first line contains a single integer $n$ ($1\leq n\leq 10^5$) — the number of numbers in a row.
The second line contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1\leq a_i\leq 10^5$) — the numbers in a row.
Output Specification:
Print one number — the number of possible pairs that Sonya can give to robots so that they will not meet.
Demo Input:
['5\n1 5 4 1 3\n', '7\n1 2 1 1 1 3 2\n']
Demo Output:
['9\n', '7\n']
Note:
In the first example, Sonya can give pairs ($1$, $1$), ($1$, $3$), ($1$, $4$), ($1$, $5$), ($4$, $1$), ($4$, $3$), ($5$, $1$), ($5$, $3$), and ($5$, $4$).
In the second example, Sonya can give pairs ($1$, $1$), ($1$, $2$), ($1$, $3$), ($2$, $1$), ($2$, $2$), ($2$, $3$), and ($3$, $2$). | ```python
import numpy
n = [int(s) for s in input().split(" ")]
numbers = [int(s) for s in input().split(" ")]
# lol = np.z[[-1,-1]]*10001
lol = numpy.full((10001,2),-1)
for i in range(0,len(numbers)):
if lol[numbers[i]][0]>-1:
continue
else:
lol[numbers[i]][0]=i
for i in range(len(numbers)-1,0,-1):
if lol[numbers[i]][1]>-1:
continue
else:
lol[numbers[i]][1]=i
print(lol)
``` | -1 | |
134 | A | Average Numbers | PROGRAMMING | 1,200 | [
"brute force",
"implementation"
] | null | null | You are given a sequence of positive integers *a*1,<=*a*2,<=...,<=*a**n*. Find all such indices *i*, that the *i*-th element equals the arithmetic mean of all other elements (that is all elements except for this one). | The first line contains the integer *n* (2<=≤<=*n*<=≤<=2·105). The second line contains elements of the sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000). All the elements are positive integers. | Print on the first line the number of the sought indices. Print on the second line the sought indices in the increasing order. All indices are integers from 1 to *n*.
If the sought elements do not exist, then the first output line should contain number 0. In this case you may either not print the second line or print an empty line. | [
"5\n1 2 3 4 5\n",
"4\n50 50 50 50\n"
] | [
"1\n3 ",
"4\n1 2 3 4 "
] | none | 500 | [
{
"input": "5\n1 2 3 4 5",
"output": "1\n3 "
},
{
"input": "4\n50 50 50 50",
"output": "4\n1 2 3 4 "
},
{
"input": "3\n2 3 1",
"output": "1\n1 "
},
{
"input": "2\n4 2",
"output": "0"
},
{
"input": "2\n1 1",
"output": "2\n1 2 "
},
{
"input": "10\n3 3 3 ... | 1,656,681,090 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 58 | 186 | 20,275,200 | from math import gcd,lcm,sqrt,factorial
def solve():
s=sum(a)
AVG=s//n
if s%n:print(0);return
li,ans=[],0
for i in range(n):
if AVG==a[i]:
li.append(i+1)
ans+=1
print(ans)
print(*li)
if __name__ == '__main__':
n=int(input())
a=[int(x) for x in input().split()]
solve()
| Title: Average Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a sequence of positive integers *a*1,<=*a*2,<=...,<=*a**n*. Find all such indices *i*, that the *i*-th element equals the arithmetic mean of all other elements (that is all elements except for this one).
Input Specification:
The first line contains the integer *n* (2<=≤<=*n*<=≤<=2·105). The second line contains elements of the sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000). All the elements are positive integers.
Output Specification:
Print on the first line the number of the sought indices. Print on the second line the sought indices in the increasing order. All indices are integers from 1 to *n*.
If the sought elements do not exist, then the first output line should contain number 0. In this case you may either not print the second line or print an empty line.
Demo Input:
['5\n1 2 3 4 5\n', '4\n50 50 50 50\n']
Demo Output:
['1\n3 ', '4\n1 2 3 4 ']
Note:
none | ```python
from math import gcd,lcm,sqrt,factorial
def solve():
s=sum(a)
AVG=s//n
if s%n:print(0);return
li,ans=[],0
for i in range(n):
if AVG==a[i]:
li.append(i+1)
ans+=1
print(ans)
print(*li)
if __name__ == '__main__':
n=int(input())
a=[int(x) for x in input().split()]
solve()
``` | 3 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*. | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,488,529,526 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 4,608,000 | Str=input()
check=False
if 'h' in Str :
Str=Str[Str.index('h')+1:]
if 'e' in Str :
Str=Str[Str.index('e')+1:]
if 'l' in Str :
Str=Str[Str.index('l')+1:]
if 'l' in Str :
Str = Str[Str.index('l') + 1:]
if 'o' in Str :
check=True
print('YES' if check else 'No') | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*.
Input Specification:
The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters.
Output Specification:
If Vasya managed to say hello, print "YES", otherwise print "NO".
Demo Input:
['ahhellllloou\n', 'hlelo\n']
Demo Output:
['YES\n', 'NO\n']
Note:
none | ```python
Str=input()
check=False
if 'h' in Str :
Str=Str[Str.index('h')+1:]
if 'e' in Str :
Str=Str[Str.index('e')+1:]
if 'l' in Str :
Str=Str[Str.index('l')+1:]
if 'l' in Str :
Str = Str[Str.index('l') + 1:]
if 'o' in Str :
check=True
print('YES' if check else 'No')
``` | 0 |
846 | A | Curriculum Vitae | PROGRAMMING | 1,500 | [
"brute force",
"implementation"
] | null | null | Hideo Kojima has just quit his job at Konami. Now he is going to find a new place to work. Despite being such a well-known person, he still needs a CV to apply for a job.
During all his career Hideo has produced *n* games. Some of them were successful, some were not. Hideo wants to remove several of them (possibly zero) from his CV to make a better impression on employers. As a result there should be no unsuccessful game which comes right after successful one in his CV.
More formally, you are given an array *s*1,<=*s*2,<=...,<=*s**n* of zeros and ones. Zero corresponds to an unsuccessful game, one — to a successful one. Games are given in order they were produced, and Hideo can't swap these values. He should remove some elements from this array in such a way that no zero comes right after one.
Besides that, Hideo still wants to mention as much games in his CV as possible. Help this genius of a man determine the maximum number of games he can leave in his CV. | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=100).
The second line contains *n* space-separated integer numbers *s*1,<=*s*2,<=...,<=*s**n* (0<=≤<=*s**i*<=≤<=1). 0 corresponds to an unsuccessful game, 1 — to a successful one. | Print one integer — the maximum number of games Hideo can leave in his CV so that no unsuccessful game comes after a successful one. | [
"4\n1 1 0 1\n",
"6\n0 1 0 0 1 0\n",
"1\n0\n"
] | [
"3\n",
"4\n",
"1\n"
] | none | 0 | [
{
"input": "4\n1 1 0 1",
"output": "3"
},
{
"input": "6\n0 1 0 0 1 0",
"output": "4"
},
{
"input": "1\n0",
"output": "1"
},
{
"input": "100\n0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0... | 1,511,672,993 | 593 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 5,529,600 | n = int(input())
g = list(map(int, input().split()))
ans = [g[0]]
for i in range(1, len(g)):
if ans[-1] == 1 and g[i] == 0:
do = 'nothing'
else:
ans.append(g[i])
# print(ans)
# print(i)
print(len(ans)) | Title: Curriculum Vitae
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hideo Kojima has just quit his job at Konami. Now he is going to find a new place to work. Despite being such a well-known person, he still needs a CV to apply for a job.
During all his career Hideo has produced *n* games. Some of them were successful, some were not. Hideo wants to remove several of them (possibly zero) from his CV to make a better impression on employers. As a result there should be no unsuccessful game which comes right after successful one in his CV.
More formally, you are given an array *s*1,<=*s*2,<=...,<=*s**n* of zeros and ones. Zero corresponds to an unsuccessful game, one — to a successful one. Games are given in order they were produced, and Hideo can't swap these values. He should remove some elements from this array in such a way that no zero comes right after one.
Besides that, Hideo still wants to mention as much games in his CV as possible. Help this genius of a man determine the maximum number of games he can leave in his CV.
Input Specification:
The first line contains one integer number *n* (1<=≤<=*n*<=≤<=100).
The second line contains *n* space-separated integer numbers *s*1,<=*s*2,<=...,<=*s**n* (0<=≤<=*s**i*<=≤<=1). 0 corresponds to an unsuccessful game, 1 — to a successful one.
Output Specification:
Print one integer — the maximum number of games Hideo can leave in his CV so that no unsuccessful game comes after a successful one.
Demo Input:
['4\n1 1 0 1\n', '6\n0 1 0 0 1 0\n', '1\n0\n']
Demo Output:
['3\n', '4\n', '1\n']
Note:
none | ```python
n = int(input())
g = list(map(int, input().split()))
ans = [g[0]]
for i in range(1, len(g)):
if ans[-1] == 1 and g[i] == 0:
do = 'nothing'
else:
ans.append(g[i])
# print(ans)
# print(i)
print(len(ans))
``` | 0 | |
915 | A | Garden | PROGRAMMING | 900 | [
"implementation"
] | null | null | Luba thinks about watering her garden. The garden can be represented as a segment of length *k*. Luba has got *n* buckets, the *i*-th bucket allows her to water some continuous subsegment of garden of length exactly *a**i* each hour. Luba can't water any parts of the garden that were already watered, also she can't water the ground outside the garden.
Luba has to choose one of the buckets in order to water the garden as fast as possible (as mentioned above, each hour she will water some continuous subsegment of length *a**i* if she chooses the *i*-th bucket). Help her to determine the minimum number of hours she has to spend watering the garden. It is guaranteed that Luba can always choose a bucket so it is possible water the garden.
See the examples for better understanding. | The first line of input contains two integer numbers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of buckets and the length of the garden, respectively.
The second line of input contains *n* integer numbers *a**i* (1<=≤<=*a**i*<=≤<=100) — the length of the segment that can be watered by the *i*-th bucket in one hour.
It is guaranteed that there is at least one bucket such that it is possible to water the garden in integer number of hours using only this bucket. | Print one integer number — the minimum number of hours required to water the garden. | [
"3 6\n2 3 5\n",
"6 7\n1 2 3 4 5 6\n"
] | [
"2\n",
"7\n"
] | In the first test the best option is to choose the bucket that allows to water the segment of length 3. We can't choose the bucket that allows to water the segment of length 5 because then we can't water the whole garden.
In the second test we can choose only the bucket that allows us to water the segment of length 1. | 0 | [
{
"input": "3 6\n2 3 5",
"output": "2"
},
{
"input": "6 7\n1 2 3 4 5 6",
"output": "7"
},
{
"input": "5 97\n1 10 50 97 2",
"output": "1"
},
{
"input": "5 97\n1 10 50 100 2",
"output": "97"
},
{
"input": "100 100\n2 46 24 18 86 90 31 38 84 49 58 28 15 80 14 24 87 5... | 1,622,625,694 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 93 | 0 | temp = [int(x) for x in input().split()]
n = temp[0]
k = temp[1]
a = [int(x) for x in input().split()]
for i in range(n-1, -1, -1):
if k % a[i] == 0:
print(i+1)
break
| Title: Garden
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luba thinks about watering her garden. The garden can be represented as a segment of length *k*. Luba has got *n* buckets, the *i*-th bucket allows her to water some continuous subsegment of garden of length exactly *a**i* each hour. Luba can't water any parts of the garden that were already watered, also she can't water the ground outside the garden.
Luba has to choose one of the buckets in order to water the garden as fast as possible (as mentioned above, each hour she will water some continuous subsegment of length *a**i* if she chooses the *i*-th bucket). Help her to determine the minimum number of hours she has to spend watering the garden. It is guaranteed that Luba can always choose a bucket so it is possible water the garden.
See the examples for better understanding.
Input Specification:
The first line of input contains two integer numbers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=100) — the number of buckets and the length of the garden, respectively.
The second line of input contains *n* integer numbers *a**i* (1<=≤<=*a**i*<=≤<=100) — the length of the segment that can be watered by the *i*-th bucket in one hour.
It is guaranteed that there is at least one bucket such that it is possible to water the garden in integer number of hours using only this bucket.
Output Specification:
Print one integer number — the minimum number of hours required to water the garden.
Demo Input:
['3 6\n2 3 5\n', '6 7\n1 2 3 4 5 6\n']
Demo Output:
['2\n', '7\n']
Note:
In the first test the best option is to choose the bucket that allows to water the segment of length 3. We can't choose the bucket that allows to water the segment of length 5 because then we can't water the whole garden.
In the second test we can choose only the bucket that allows us to water the segment of length 1. | ```python
temp = [int(x) for x in input().split()]
n = temp[0]
k = temp[1]
a = [int(x) for x in input().split()]
for i in range(n-1, -1, -1):
if k % a[i] == 0:
print(i+1)
break
``` | 0 | |
577 | A | Multiplication Table | PROGRAMMING | 1,000 | [
"implementation",
"number theory"
] | null | null | Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
You are given a positive integer *x*. Your task is to count the number of cells in a table that contain number *x*. | The single line contains numbers *n* and *x* (1<=≤<=*n*<=≤<=105, 1<=≤<=*x*<=≤<=109) — the size of the table and the number that we are looking for in the table. | Print a single number: the number of times *x* occurs in the table. | [
"10 5\n",
"6 12\n",
"5 13\n"
] | [
"2\n",
"4\n",
"0\n"
] | A table for the second sample test is given below. The occurrences of number 12 are marked bold. | 500 | [
{
"input": "10 5",
"output": "2"
},
{
"input": "6 12",
"output": "4"
},
{
"input": "5 13",
"output": "0"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "100000 1",
"output": "1"
},
{
"input": "1 10000000... | 1,662,112,932 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 47 | 62 | 1,843,200 | n,x=map(int,input().split())
dem=0
if x==1:
print("1")
exit()
for i in range(1,n+1):
if x%i==0 and int(x/i)<=n :
dem=dem+1
print(dem) | Title: Multiplication Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
You are given a positive integer *x*. Your task is to count the number of cells in a table that contain number *x*.
Input Specification:
The single line contains numbers *n* and *x* (1<=≤<=*n*<=≤<=105, 1<=≤<=*x*<=≤<=109) — the size of the table and the number that we are looking for in the table.
Output Specification:
Print a single number: the number of times *x* occurs in the table.
Demo Input:
['10 5\n', '6 12\n', '5 13\n']
Demo Output:
['2\n', '4\n', '0\n']
Note:
A table for the second sample test is given below. The occurrences of number 12 are marked bold. | ```python
n,x=map(int,input().split())
dem=0
if x==1:
print("1")
exit()
for i in range(1,n+1):
if x%i==0 and int(x/i)<=n :
dem=dem+1
print(dem)
``` | 3 | |
584 | A | Olesya and Rodion | PROGRAMMING | 1,000 | [
"math"
] | null | null | Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-<=1. | The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by. | Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them. | [
"3 2\n"
] | [
"712"
] | none | 500 | [
{
"input": "3 2",
"output": "222"
},
{
"input": "2 2",
"output": "22"
},
{
"input": "4 3",
"output": "3333"
},
{
"input": "5 3",
"output": "33333"
},
{
"input": "10 7",
"output": "7777777777"
},
{
"input": "2 9",
"output": "99"
},
{
"input"... | 1,665,848,600 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 25 | 46 | 0 | n, t = [int(_) for _ in input().split()]
if len(str(t)) > len(str(n)):
print(-1)
exit(0)
while len(str(t)) != n:
t *= 10
print(t) | Title: Olesya and Rodion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Olesya loves numbers consisting of *n* digits, and Rodion only likes numbers that are divisible by *t*. Find some number that satisfies both of them.
Your task is: given the *n* and *t* print an integer strictly larger than zero consisting of *n* digits that is divisible by *t*. If such number doesn't exist, print <=-<=1.
Input Specification:
The single line contains two numbers, *n* and *t* (1<=≤<=*n*<=≤<=100, 2<=≤<=*t*<=≤<=10) — the length of the number and the number it should be divisible by.
Output Specification:
Print one such positive number without leading zeroes, — the answer to the problem, or <=-<=1, if such number doesn't exist. If there are multiple possible answers, you are allowed to print any of them.
Demo Input:
['3 2\n']
Demo Output:
['712']
Note:
none | ```python
n, t = [int(_) for _ in input().split()]
if len(str(t)) > len(str(n)):
print(-1)
exit(0)
while len(str(t)) != n:
t *= 10
print(t)
``` | 0 | |
817 | D | Imbalanced Array | PROGRAMMING | 1,900 | [
"data structures",
"divide and conquer",
"dsu",
"sortings"
] | null | null | You are given an array *a* consisting of *n* elements. The imbalance value of some subsegment of this array is the difference between the maximum and minimum element from this segment. The imbalance value of the array is the sum of imbalance values of all subsegments of this array.
For example, the imbalance value of array [1,<=4,<=1] is 9, because there are 6 different subsegments of this array:
- [1] (from index 1 to index 1), imbalance value is 0; - [1,<=4] (from index 1 to index 2), imbalance value is 3; - [1,<=4,<=1] (from index 1 to index 3), imbalance value is 3; - [4] (from index 2 to index 2), imbalance value is 0; - [4,<=1] (from index 2 to index 3), imbalance value is 3; - [1] (from index 3 to index 3), imbalance value is 0;
You have to determine the imbalance value of the array *a*. | The first line contains one integer *n* (1<=≤<=*n*<=≤<=106) — size of the array *a*.
The second line contains *n* integers *a*1,<=*a*2... *a**n* (1<=≤<=*a**i*<=≤<=106) — elements of the array. | Print one integer — the imbalance value of *a*. | [
"3\n1 4 1\n"
] | [
"9\n"
] | none | 0 | [
{
"input": "3\n1 4 1",
"output": "9"
},
{
"input": "10\n1 1 1 1 1 1 1 1 1 1",
"output": "0"
},
{
"input": "10\n1 4 4 3 5 2 4 2 4 5",
"output": "123"
},
{
"input": "10\n9 6 8 5 5 2 8 9 2 2",
"output": "245"
},
{
"input": "30\n4 5 2 2 5 2 3 4 3 3 2 1 3 4 4 5 3 3 1 5... | 1,497,544,869 | 5,769 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 2,000 | 614,400 | n=int(input())
a=[int(i) for i in input().split()]
s=0
for i in range(n):
ma=a[i]
mi=a[i]
for j in range(i,n):
if a[j]>ma:
ma=a[j]
elif a[j]<mi:
mi=a[j]
s+=ma-mi
print(s)
| Title: Imbalanced Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array *a* consisting of *n* elements. The imbalance value of some subsegment of this array is the difference between the maximum and minimum element from this segment. The imbalance value of the array is the sum of imbalance values of all subsegments of this array.
For example, the imbalance value of array [1,<=4,<=1] is 9, because there are 6 different subsegments of this array:
- [1] (from index 1 to index 1), imbalance value is 0; - [1,<=4] (from index 1 to index 2), imbalance value is 3; - [1,<=4,<=1] (from index 1 to index 3), imbalance value is 3; - [4] (from index 2 to index 2), imbalance value is 0; - [4,<=1] (from index 2 to index 3), imbalance value is 3; - [1] (from index 3 to index 3), imbalance value is 0;
You have to determine the imbalance value of the array *a*.
Input Specification:
The first line contains one integer *n* (1<=≤<=*n*<=≤<=106) — size of the array *a*.
The second line contains *n* integers *a*1,<=*a*2... *a**n* (1<=≤<=*a**i*<=≤<=106) — elements of the array.
Output Specification:
Print one integer — the imbalance value of *a*.
Demo Input:
['3\n1 4 1\n']
Demo Output:
['9\n']
Note:
none | ```python
n=int(input())
a=[int(i) for i in input().split()]
s=0
for i in range(n):
ma=a[i]
mi=a[i]
for j in range(i,n):
if a[j]>ma:
ma=a[j]
elif a[j]<mi:
mi=a[j]
s+=ma-mi
print(s)
``` | 0 | |
785 | A | Anton and Polyhedrons | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahedron. Octahedron has 8 triangular faces. - Dodecahedron. Dodecahedron has 12 pentagonal faces. - Icosahedron. Icosahedron has 20 triangular faces.
All five kinds of polyhedrons are shown on the picture below:
Anton has a collection of *n* polyhedrons. One day he decided to know, how many faces his polyhedrons have in total. Help Anton and find this number! | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of polyhedrons in Anton's collection.
Each of the following *n* lines of the input contains a string *s**i* — the name of the *i*-th polyhedron in Anton's collection. The string can look like this:
- "Tetrahedron" (without quotes), if the *i*-th polyhedron in Anton's collection is a tetrahedron. - "Cube" (without quotes), if the *i*-th polyhedron in Anton's collection is a cube. - "Octahedron" (without quotes), if the *i*-th polyhedron in Anton's collection is an octahedron. - "Dodecahedron" (without quotes), if the *i*-th polyhedron in Anton's collection is a dodecahedron. - "Icosahedron" (without quotes), if the *i*-th polyhedron in Anton's collection is an icosahedron. | Output one number — the total number of faces in all the polyhedrons in Anton's collection. | [
"4\nIcosahedron\nCube\nTetrahedron\nDodecahedron\n",
"3\nDodecahedron\nOctahedron\nOctahedron\n"
] | [
"42\n",
"28\n"
] | In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces. | 500 | [
{
"input": "4\nIcosahedron\nCube\nTetrahedron\nDodecahedron",
"output": "42"
},
{
"input": "3\nDodecahedron\nOctahedron\nOctahedron",
"output": "28"
},
{
"input": "25\nIcosahedron\nOctahedron\nTetrahedron\nDodecahedron\nCube\nIcosahedron\nOctahedron\nCube\nTetrahedron\nIcosahedron\nIcosa... | 1,675,329,636 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 1,169 | 12,185,600 | import sys
from math import ceil,floor,sqrt,log,dist
from collections import defaultdict
from operator import itemgetter
rmi=lambda:map(int,input().split())
rs=lambda:input()
ri=lambda:int(rs())
inf=float('inf')
def f():
b=[]
for _ in range(ri()):
s=input()
if s=="Tetrahedron":
b.append(4)
elif s=="Cube":
b.append(6)
elif s=="Octahedron":
b.append(8)
elif s=="Dodecahedron":
b.append(12)
else:
b.append(20)
print(sum(b))
f()
| Title: Anton and Polyhedrons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahedron. Octahedron has 8 triangular faces. - Dodecahedron. Dodecahedron has 12 pentagonal faces. - Icosahedron. Icosahedron has 20 triangular faces.
All five kinds of polyhedrons are shown on the picture below:
Anton has a collection of *n* polyhedrons. One day he decided to know, how many faces his polyhedrons have in total. Help Anton and find this number!
Input Specification:
The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of polyhedrons in Anton's collection.
Each of the following *n* lines of the input contains a string *s**i* — the name of the *i*-th polyhedron in Anton's collection. The string can look like this:
- "Tetrahedron" (without quotes), if the *i*-th polyhedron in Anton's collection is a tetrahedron. - "Cube" (without quotes), if the *i*-th polyhedron in Anton's collection is a cube. - "Octahedron" (without quotes), if the *i*-th polyhedron in Anton's collection is an octahedron. - "Dodecahedron" (without quotes), if the *i*-th polyhedron in Anton's collection is a dodecahedron. - "Icosahedron" (without quotes), if the *i*-th polyhedron in Anton's collection is an icosahedron.
Output Specification:
Output one number — the total number of faces in all the polyhedrons in Anton's collection.
Demo Input:
['4\nIcosahedron\nCube\nTetrahedron\nDodecahedron\n', '3\nDodecahedron\nOctahedron\nOctahedron\n']
Demo Output:
['42\n', '28\n']
Note:
In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces. | ```python
import sys
from math import ceil,floor,sqrt,log,dist
from collections import defaultdict
from operator import itemgetter
rmi=lambda:map(int,input().split())
rs=lambda:input()
ri=lambda:int(rs())
inf=float('inf')
def f():
b=[]
for _ in range(ri()):
s=input()
if s=="Tetrahedron":
b.append(4)
elif s=="Cube":
b.append(6)
elif s=="Octahedron":
b.append(8)
elif s=="Dodecahedron":
b.append(12)
else:
b.append(20)
print(sum(b))
f()
``` | 3 | |
224 | A | Parallelepiped | PROGRAMMING | 1,100 | [
"brute force",
"geometry",
"math"
] | null | null | You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped. | The first and the single line contains three space-separated integers — the areas of the parallelepiped's faces. The area's values are positive (<=><=0) and do not exceed 104. It is guaranteed that there exists at least one parallelepiped that satisfies the problem statement. | Print a single number — the sum of all edges of the parallelepiped. | [
"1 1 1\n",
"4 6 6\n"
] | [
"12\n",
"28\n"
] | In the first sample the parallelepiped has sizes 1 × 1 × 1, in the second one — 2 × 2 × 3. | 500 | [
{
"input": "1 1 1",
"output": "12"
},
{
"input": "4 6 6",
"output": "28"
},
{
"input": "20 10 50",
"output": "68"
},
{
"input": "9 4 36",
"output": "56"
},
{
"input": "324 9 36",
"output": "184"
},
{
"input": "1333 93 129",
"output": "308"
},
{... | 1,587,761,643 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 6 | 186 | 0 | import math
a,b,c=sorted([*map(int,input().split())])
if b!=c:
l=math.gcd(b,c)
w=b/l
h=a/w
else:
l=math.gcd(a,b)
w=a/l
h=c/l
print(int(4*(l+w+h))) | Title: Parallelepiped
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got a rectangular parallelepiped with integer edge lengths. You know the areas of its three faces that have a common vertex. Your task is to find the sum of lengths of all 12 edges of this parallelepiped.
Input Specification:
The first and the single line contains three space-separated integers — the areas of the parallelepiped's faces. The area's values are positive (<=><=0) and do not exceed 104. It is guaranteed that there exists at least one parallelepiped that satisfies the problem statement.
Output Specification:
Print a single number — the sum of all edges of the parallelepiped.
Demo Input:
['1 1 1\n', '4 6 6\n']
Demo Output:
['12\n', '28\n']
Note:
In the first sample the parallelepiped has sizes 1 × 1 × 1, in the second one — 2 × 2 × 3. | ```python
import math
a,b,c=sorted([*map(int,input().split())])
if b!=c:
l=math.gcd(b,c)
w=b/l
h=a/w
else:
l=math.gcd(a,b)
w=a/l
h=c/l
print(int(4*(l+w+h)))
``` | 0 | |
1,003 | A | Polycarp's Pockets | PROGRAMMING | 800 | [
"implementation"
] | null | null | Polycarp has $n$ coins, the value of the $i$-th coin is $a_i$. Polycarp wants to distribute all the coins between his pockets, but he cannot put two coins with the same value into the same pocket.
For example, if Polycarp has got six coins represented as an array $a = [1, 2, 4, 3, 3, 2]$, he can distribute the coins into two pockets as follows: $[1, 2, 3], [2, 3, 4]$.
Polycarp wants to distribute all the coins with the minimum number of used pockets. Help him to do that. | The first line of the input contains one integer $n$ ($1 \le n \le 100$) — the number of coins.
The second line of the input contains $n$ integers $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 100$) — values of coins. | Print only one integer — the minimum number of pockets Polycarp needs to distribute all the coins so no two coins with the same value are put into the same pocket. | [
"6\n1 2 4 3 3 2\n",
"1\n100\n"
] | [
"2\n",
"1\n"
] | none | 0 | [
{
"input": "6\n1 2 4 3 3 2",
"output": "2"
},
{
"input": "1\n100",
"output": "1"
},
{
"input": "100\n100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100 100... | 1,592,401,799 | 299 | PyPy 3 | OK | TESTS | 37 | 156 | 0 | import collections
n = int(input())
a = list(map(int, input().split()))
C = collections.Counter(a).most_common()
print(C[0][1])
| Title: Polycarp's Pockets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has $n$ coins, the value of the $i$-th coin is $a_i$. Polycarp wants to distribute all the coins between his pockets, but he cannot put two coins with the same value into the same pocket.
For example, if Polycarp has got six coins represented as an array $a = [1, 2, 4, 3, 3, 2]$, he can distribute the coins into two pockets as follows: $[1, 2, 3], [2, 3, 4]$.
Polycarp wants to distribute all the coins with the minimum number of used pockets. Help him to do that.
Input Specification:
The first line of the input contains one integer $n$ ($1 \le n \le 100$) — the number of coins.
The second line of the input contains $n$ integers $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 100$) — values of coins.
Output Specification:
Print only one integer — the minimum number of pockets Polycarp needs to distribute all the coins so no two coins with the same value are put into the same pocket.
Demo Input:
['6\n1 2 4 3 3 2\n', '1\n100\n']
Demo Output:
['2\n', '1\n']
Note:
none | ```python
import collections
n = int(input())
a = list(map(int, input().split()))
C = collections.Counter(a).most_common()
print(C[0][1])
``` | 3 | |
474 | B | Worms | PROGRAMMING | 1,200 | [
"binary search",
"implementation"
] | null | null | It is lunch time for Mole. His friend, Marmot, prepared him a nice game for lunch.
Marmot brought Mole *n* ordered piles of worms such that *i*-th pile contains *a**i* worms. He labeled all these worms with consecutive integers: worms in first pile are labeled with numbers 1 to *a*1, worms in second pile are labeled with numbers *a*1<=+<=1 to *a*1<=+<=*a*2 and so on. See the example for a better understanding.
Mole can't eat all the worms (Marmot brought a lot) and, as we all know, Mole is blind, so Marmot tells him the labels of the best juicy worms. Marmot will only give Mole a worm if Mole says correctly in which pile this worm is contained.
Poor Mole asks for your help. For all juicy worms said by Marmot, tell Mole the correct answers. | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), the number of piles.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=103, *a*1<=+<=*a*2<=+<=...<=+<=*a**n*<=≤<=106), where *a**i* is the number of worms in the *i*-th pile.
The third line contains single integer *m* (1<=≤<=*m*<=≤<=105), the number of juicy worms said by Marmot.
The fourth line contains *m* integers *q*1,<=*q*2,<=...,<=*q**m* (1<=≤<=*q**i*<=≤<=*a*1<=+<=*a*2<=+<=...<=+<=*a**n*), the labels of the juicy worms. | Print *m* lines to the standard output. The *i*-th line should contain an integer, representing the number of the pile where the worm labeled with the number *q**i* is. | [
"5\n2 7 3 4 9\n3\n1 25 11\n"
] | [
"1\n5\n3\n"
] | For the sample input:
- The worms with labels from [1, 2] are in the first pile. - The worms with labels from [3, 9] are in the second pile. - The worms with labels from [10, 12] are in the third pile. - The worms with labels from [13, 16] are in the fourth pile. - The worms with labels from [17, 25] are in the fifth pile. | 1,000 | [
{
"input": "5\n2 7 3 4 9\n3\n1 25 11",
"output": "1\n5\n3"
}
] | 1,695,398,497 | 2,147,483,647 | Python 3 | OK | TESTS | 38 | 499 | 115,097,600 | n=int(input())#numero de montones
a=[int(x) for x in input().split(' ')]#cantidad por monton
m=int(input())#gusanos sabrosos
q=[int(x) for x in input().split(' ')]#etiquetas de los gusanos sabrosos
monton={}
contador=1
for i in range(n):
for j in range(a[i]):
monton[contador]=i+1
contador+=1
for x in q:
print(monton[x]) | Title: Worms
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It is lunch time for Mole. His friend, Marmot, prepared him a nice game for lunch.
Marmot brought Mole *n* ordered piles of worms such that *i*-th pile contains *a**i* worms. He labeled all these worms with consecutive integers: worms in first pile are labeled with numbers 1 to *a*1, worms in second pile are labeled with numbers *a*1<=+<=1 to *a*1<=+<=*a*2 and so on. See the example for a better understanding.
Mole can't eat all the worms (Marmot brought a lot) and, as we all know, Mole is blind, so Marmot tells him the labels of the best juicy worms. Marmot will only give Mole a worm if Mole says correctly in which pile this worm is contained.
Poor Mole asks for your help. For all juicy worms said by Marmot, tell Mole the correct answers.
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105), the number of piles.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=103, *a*1<=+<=*a*2<=+<=...<=+<=*a**n*<=≤<=106), where *a**i* is the number of worms in the *i*-th pile.
The third line contains single integer *m* (1<=≤<=*m*<=≤<=105), the number of juicy worms said by Marmot.
The fourth line contains *m* integers *q*1,<=*q*2,<=...,<=*q**m* (1<=≤<=*q**i*<=≤<=*a*1<=+<=*a*2<=+<=...<=+<=*a**n*), the labels of the juicy worms.
Output Specification:
Print *m* lines to the standard output. The *i*-th line should contain an integer, representing the number of the pile where the worm labeled with the number *q**i* is.
Demo Input:
['5\n2 7 3 4 9\n3\n1 25 11\n']
Demo Output:
['1\n5\n3\n']
Note:
For the sample input:
- The worms with labels from [1, 2] are in the first pile. - The worms with labels from [3, 9] are in the second pile. - The worms with labels from [10, 12] are in the third pile. - The worms with labels from [13, 16] are in the fourth pile. - The worms with labels from [17, 25] are in the fifth pile. | ```python
n=int(input())#numero de montones
a=[int(x) for x in input().split(' ')]#cantidad por monton
m=int(input())#gusanos sabrosos
q=[int(x) for x in input().split(' ')]#etiquetas de los gusanos sabrosos
monton={}
contador=1
for i in range(n):
for j in range(a[i]):
monton[contador]=i+1
contador+=1
for x in q:
print(monton[x])
``` | 3 | |
535 | A | Tavas and Nafas | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Today Tavas got his test result as an integer score and he wants to share it with his girlfriend, Nafas.
His phone operating system is Tavdroid, and its keyboard doesn't have any digits! He wants to share his score with Nafas via text, so he has no choice but to send this number using words.
He ate coffee mix without water again, so right now he's really messed up and can't think.
Your task is to help him by telling him what to type. | The first and only line of input contains an integer *s* (0<=≤<=*s*<=≤<=99), Tavas's score. | In the first and only line of output, print a single string consisting only from English lowercase letters and hyphens ('-'). Do not use spaces. | [
"6\n",
"99\n",
"20\n"
] | [
"six\n",
"ninety-nine\n",
"twenty\n"
] | You can find all you need to know about English numerals in [http://en.wikipedia.org/wiki/English_numerals](https://en.wikipedia.org/wiki/English_numerals) . | 500 | [
{
"input": "6",
"output": "six"
},
{
"input": "99",
"output": "ninety-nine"
},
{
"input": "20",
"output": "twenty"
},
{
"input": "10",
"output": "ten"
},
{
"input": "15",
"output": "fifteen"
},
{
"input": "27",
"output": "twenty-seven"
},
{
... | 1,492,500,386 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | def handel_upto_99(number):
predef={0:"zero",1:"one",2:"two",3:"three",4:"four",5:"five",6:"six",7:"seven",8:"eight",9:"nine",10:"ten",11:"eleven",12:"twelve",13:"thirteen",14:"fourteen",15:"fifteen",16:"sixteen",17:"seventeen",18:"eighteen",19:"nineteen",20:"twenty",30:"thirty",40:"fourty",50:"fifty",60:"sixty",70:"seventy",80:"eighty",90:"ninety",100:"hundred",100000:"lakh",10000000:"crore",1000000:"million",1000000000:"billion"}
if number in predef.keys():
return predef[number]
else:
return predef[(number/10)*10]+' '+predef[number%10]
| Title: Tavas and Nafas
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Tavas got his test result as an integer score and he wants to share it with his girlfriend, Nafas.
His phone operating system is Tavdroid, and its keyboard doesn't have any digits! He wants to share his score with Nafas via text, so he has no choice but to send this number using words.
He ate coffee mix without water again, so right now he's really messed up and can't think.
Your task is to help him by telling him what to type.
Input Specification:
The first and only line of input contains an integer *s* (0<=≤<=*s*<=≤<=99), Tavas's score.
Output Specification:
In the first and only line of output, print a single string consisting only from English lowercase letters and hyphens ('-'). Do not use spaces.
Demo Input:
['6\n', '99\n', '20\n']
Demo Output:
['six\n', 'ninety-nine\n', 'twenty\n']
Note:
You can find all you need to know about English numerals in [http://en.wikipedia.org/wiki/English_numerals](https://en.wikipedia.org/wiki/English_numerals) . | ```python
def handel_upto_99(number):
predef={0:"zero",1:"one",2:"two",3:"three",4:"four",5:"five",6:"six",7:"seven",8:"eight",9:"nine",10:"ten",11:"eleven",12:"twelve",13:"thirteen",14:"fourteen",15:"fifteen",16:"sixteen",17:"seventeen",18:"eighteen",19:"nineteen",20:"twenty",30:"thirty",40:"fourty",50:"fifty",60:"sixty",70:"seventy",80:"eighty",90:"ninety",100:"hundred",100000:"lakh",10000000:"crore",1000000:"million",1000000000:"billion"}
if number in predef.keys():
return predef[number]
else:
return predef[(number/10)*10]+' '+predef[number%10]
``` | -1 | |
937 | A | Olympiad | PROGRAMMING | 800 | [
"implementation",
"sortings"
] | null | null | The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with diplomas with respect to the following criteria:
- At least one participant should get a diploma. - None of those with score equal to zero should get awarded. - When someone is awarded, all participants with score not less than his score should also be awarded.
Determine the number of ways to choose a subset of participants that will receive the diplomas. | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants.
The next line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=600) — participants' scores.
It's guaranteed that at least one participant has non-zero score. | Print a single integer — the desired number of ways. | [
"4\n1 3 3 2\n",
"3\n1 1 1\n",
"4\n42 0 0 42\n"
] | [
"3\n",
"1\n",
"1\n"
] | There are three ways to choose a subset in sample case one.
1. Only participants with 3 points will get diplomas. 1. Participants with 2 or 3 points will get diplomas. 1. Everyone will get a diploma!
The only option in sample case two is to award everyone.
Note that in sample case three participants with zero scores cannot get anything. | 500 | [
{
"input": "4\n1 3 3 2",
"output": "3"
},
{
"input": "3\n1 1 1",
"output": "1"
},
{
"input": "4\n42 0 0 42",
"output": "1"
},
{
"input": "10\n1 0 1 0 1 0 0 0 0 1",
"output": "1"
},
{
"input": "10\n572 471 540 163 50 30 561 510 43 200",
"output": "10"
},
{
... | 1,596,289,631 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n=int(input())
l=list(map(int,input().split()))
s=list(set(l))
for i in s:
if i==0;
s.remove (i)
print(len(s))
| Title: Olympiad
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The recent All-Berland Olympiad in Informatics featured *n* participants with each scoring a certain amount of points.
As the head of the programming committee, you are to determine the set of participants to be awarded with diplomas with respect to the following criteria:
- At least one participant should get a diploma. - None of those with score equal to zero should get awarded. - When someone is awarded, all participants with score not less than his score should also be awarded.
Determine the number of ways to choose a subset of participants that will receive the diplomas.
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of participants.
The next line contains a sequence of *n* integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a**i*<=≤<=600) — participants' scores.
It's guaranteed that at least one participant has non-zero score.
Output Specification:
Print a single integer — the desired number of ways.
Demo Input:
['4\n1 3 3 2\n', '3\n1 1 1\n', '4\n42 0 0 42\n']
Demo Output:
['3\n', '1\n', '1\n']
Note:
There are three ways to choose a subset in sample case one.
1. Only participants with 3 points will get diplomas. 1. Participants with 2 or 3 points will get diplomas. 1. Everyone will get a diploma!
The only option in sample case two is to award everyone.
Note that in sample case three participants with zero scores cannot get anything. | ```python
n=int(input())
l=list(map(int,input().split()))
s=list(set(l))
for i in s:
if i==0;
s.remove (i)
print(len(s))
``` | -1 | |
583 | A | Asphalting Roads | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | City X consists of *n* vertical and *n* horizontal infinite roads, forming *n*<=×<=*n* intersections. Roads (both vertical and horizontal) are numbered from 1 to *n*, and the intersections are indicated by the numbers of the roads that form them.
Sand roads have long been recognized out of date, so the decision was made to asphalt them. To do this, a team of workers was hired and a schedule of work was made, according to which the intersections should be asphalted.
Road repairs are planned for *n*2 days. On the *i*-th day of the team arrives at the *i*-th intersection in the list and if none of the two roads that form the intersection were already asphalted they asphalt both roads. Otherwise, the team leaves the intersection, without doing anything with the roads.
According to the schedule of road works tell in which days at least one road will be asphalted. | The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of vertical and horizontal roads in the city.
Next *n*2 lines contain the order of intersections in the schedule. The *i*-th of them contains two numbers *h**i*,<=*v**i* (1<=≤<=*h**i*,<=*v**i*<=≤<=*n*), separated by a space, and meaning that the intersection that goes *i*-th in the timetable is at the intersection of the *h**i*-th horizontal and *v**i*-th vertical roads. It is guaranteed that all the intersections in the timetable are distinct. | In the single line print the numbers of the days when road works will be in progress in ascending order. The days are numbered starting from 1. | [
"2\n1 1\n1 2\n2 1\n2 2\n",
"1\n1 1\n"
] | [
"1 4 \n",
"1 \n"
] | In the sample the brigade acts like that:
1. On the first day the brigade comes to the intersection of the 1-st horizontal and the 1-st vertical road. As none of them has been asphalted, the workers asphalt the 1-st vertical and the 1-st horizontal road; 1. On the second day the brigade of the workers comes to the intersection of the 1-st horizontal and the 2-nd vertical road. The 2-nd vertical road hasn't been asphalted, but as the 1-st horizontal road has been asphalted on the first day, the workers leave and do not asphalt anything; 1. On the third day the brigade of the workers come to the intersection of the 2-nd horizontal and the 1-st vertical road. The 2-nd horizontal road hasn't been asphalted but as the 1-st vertical road has been asphalted on the first day, the workers leave and do not asphalt anything; 1. On the fourth day the brigade come to the intersection formed by the intersection of the 2-nd horizontal and 2-nd vertical road. As none of them has been asphalted, the workers asphalt the 2-nd vertical and the 2-nd horizontal road. | 500 | [
{
"input": "2\n1 1\n1 2\n2 1\n2 2",
"output": "1 4 "
},
{
"input": "1\n1 1",
"output": "1 "
},
{
"input": "2\n1 1\n2 2\n1 2\n2 1",
"output": "1 2 "
},
{
"input": "2\n1 2\n2 2\n2 1\n1 1",
"output": "1 3 "
},
{
"input": "3\n2 2\n1 2\n3 2\n3 3\n1 1\n2 3\n1 3\n3 1\n2 ... | 1,588,631,346 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 109 | 0 | n = int(input())
h = [False]*n
v = [False]*n
day_numbers = []
for day in range(1, n**2 + 1):
hi, vi = [int(x)-1 for x in input().split()]
if not h[hi] and not v[vi]:
h[hi] = v[vi] = True
day_numbers.append(day)
print(*day_numbers) | Title: Asphalting Roads
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
City X consists of *n* vertical and *n* horizontal infinite roads, forming *n*<=×<=*n* intersections. Roads (both vertical and horizontal) are numbered from 1 to *n*, and the intersections are indicated by the numbers of the roads that form them.
Sand roads have long been recognized out of date, so the decision was made to asphalt them. To do this, a team of workers was hired and a schedule of work was made, according to which the intersections should be asphalted.
Road repairs are planned for *n*2 days. On the *i*-th day of the team arrives at the *i*-th intersection in the list and if none of the two roads that form the intersection were already asphalted they asphalt both roads. Otherwise, the team leaves the intersection, without doing anything with the roads.
According to the schedule of road works tell in which days at least one road will be asphalted.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=50) — the number of vertical and horizontal roads in the city.
Next *n*2 lines contain the order of intersections in the schedule. The *i*-th of them contains two numbers *h**i*,<=*v**i* (1<=≤<=*h**i*,<=*v**i*<=≤<=*n*), separated by a space, and meaning that the intersection that goes *i*-th in the timetable is at the intersection of the *h**i*-th horizontal and *v**i*-th vertical roads. It is guaranteed that all the intersections in the timetable are distinct.
Output Specification:
In the single line print the numbers of the days when road works will be in progress in ascending order. The days are numbered starting from 1.
Demo Input:
['2\n1 1\n1 2\n2 1\n2 2\n', '1\n1 1\n']
Demo Output:
['1 4 \n', '1 \n']
Note:
In the sample the brigade acts like that:
1. On the first day the brigade comes to the intersection of the 1-st horizontal and the 1-st vertical road. As none of them has been asphalted, the workers asphalt the 1-st vertical and the 1-st horizontal road; 1. On the second day the brigade of the workers comes to the intersection of the 1-st horizontal and the 2-nd vertical road. The 2-nd vertical road hasn't been asphalted, but as the 1-st horizontal road has been asphalted on the first day, the workers leave and do not asphalt anything; 1. On the third day the brigade of the workers come to the intersection of the 2-nd horizontal and the 1-st vertical road. The 2-nd horizontal road hasn't been asphalted but as the 1-st vertical road has been asphalted on the first day, the workers leave and do not asphalt anything; 1. On the fourth day the brigade come to the intersection formed by the intersection of the 2-nd horizontal and 2-nd vertical road. As none of them has been asphalted, the workers asphalt the 2-nd vertical and the 2-nd horizontal road. | ```python
n = int(input())
h = [False]*n
v = [False]*n
day_numbers = []
for day in range(1, n**2 + 1):
hi, vi = [int(x)-1 for x in input().split()]
if not h[hi] and not v[vi]:
h[hi] = v[vi] = True
day_numbers.append(day)
print(*day_numbers)
``` | 3 | |
417 | B | Crash | PROGRAMMING | 1,400 | [
"implementation"
] | null | null | During the "Russian Code Cup" programming competition, the testing system stores all sent solutions for each participant. We know that many participants use random numbers in their programs and are often sent several solutions with the same source code to check.
Each participant is identified by some unique positive integer *k*, and each sent solution *A* is characterized by two numbers: *x* — the number of different solutions that are sent before the first solution identical to *A*, and *k* — the number of the participant, who is the author of the solution. Consequently, all identical solutions have the same *x*.
It is known that the data in the testing system are stored in the chronological order, that is, if the testing system has a solution with number *x* (*x*<=><=0) of the participant with number *k*, then the testing system has a solution with number *x*<=-<=1 of the same participant stored somewhere before.
During the competition the checking system crashed, but then the data of the submissions of all participants have been restored. Now the jury wants to verify that the recovered data is in chronological order. Help the jury to do so. | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=105) — the number of solutions. Each of the following *n* lines contains two integers separated by space *x* and *k* (0<=≤<=*x*<=≤<=105; 1<=≤<=*k*<=≤<=105) — the number of previous unique solutions and the identifier of the participant. | A single line of the output should contain «YES» if the data is in chronological order, and «NO» otherwise. | [
"2\n0 1\n1 1\n",
"4\n0 1\n1 2\n1 1\n0 2\n",
"4\n0 1\n1 1\n0 1\n0 2\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | none | 1,000 | [
{
"input": "2\n0 1\n1 1",
"output": "YES"
},
{
"input": "4\n0 1\n1 2\n1 1\n0 2",
"output": "NO"
},
{
"input": "4\n0 1\n1 1\n0 1\n0 2",
"output": "YES"
},
{
"input": "4\n7 1\n4 2\n8 2\n1 8",
"output": "NO"
},
{
"input": "2\n0 8\n0 5",
"output": "YES"
},
{
... | 1,397,769,219 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | # -*- coding: utf-8 -*-
"""
@author: Ilych
"""
def input_row():
return list( map(int, input().strip().split(' ')))
if __name__=='__main__':
#print proc2()
n = input_row()[0]
dct={}
for _ in range(n):
x,k = input_row()
if k not in dct:
if x!=0:
print('NO')
break
dct[k]=x
continue
if x>0 and x != dct[k]+1:
print('NO')
break
dct[k]=x
print ('YES')
| Title: Crash
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
During the "Russian Code Cup" programming competition, the testing system stores all sent solutions for each participant. We know that many participants use random numbers in their programs and are often sent several solutions with the same source code to check.
Each participant is identified by some unique positive integer *k*, and each sent solution *A* is characterized by two numbers: *x* — the number of different solutions that are sent before the first solution identical to *A*, and *k* — the number of the participant, who is the author of the solution. Consequently, all identical solutions have the same *x*.
It is known that the data in the testing system are stored in the chronological order, that is, if the testing system has a solution with number *x* (*x*<=><=0) of the participant with number *k*, then the testing system has a solution with number *x*<=-<=1 of the same participant stored somewhere before.
During the competition the checking system crashed, but then the data of the submissions of all participants have been restored. Now the jury wants to verify that the recovered data is in chronological order. Help the jury to do so.
Input Specification:
The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=105) — the number of solutions. Each of the following *n* lines contains two integers separated by space *x* and *k* (0<=≤<=*x*<=≤<=105; 1<=≤<=*k*<=≤<=105) — the number of previous unique solutions and the identifier of the participant.
Output Specification:
A single line of the output should contain «YES» if the data is in chronological order, and «NO» otherwise.
Demo Input:
['2\n0 1\n1 1\n', '4\n0 1\n1 2\n1 1\n0 2\n', '4\n0 1\n1 1\n0 1\n0 2\n']
Demo Output:
['YES\n', 'NO\n', 'YES\n']
Note:
none | ```python
# -*- coding: utf-8 -*-
"""
@author: Ilych
"""
def input_row():
return list( map(int, input().strip().split(' ')))
if __name__=='__main__':
#print proc2()
n = input_row()[0]
dct={}
for _ in range(n):
x,k = input_row()
if k not in dct:
if x!=0:
print('NO')
break
dct[k]=x
continue
if x>0 and x != dct[k]+1:
print('NO')
break
dct[k]=x
print ('YES')
``` | 0 | |
302 | A | Eugeny and Array | PROGRAMMING | 800 | [
"implementation"
] | null | null | Eugeny has array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* integers. Each integer *a**i* equals to -1, or to 1. Also, he has *m* queries:
- Query number *i* is given as a pair of integers *l**i*, *r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). - The response to the query will be integer 1, if the elements of array *a* can be rearranged so as the sum *a**l**i*<=+<=*a**l**i*<=+<=1<=+<=...<=+<=*a**r**i*<==<=0, otherwise the response to the query will be integer 0.
Help Eugeny, answer all his queries. | The first line contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=2·105). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (*a**i*<==<=-1,<=1). Next *m* lines contain Eugene's queries. The *i*-th line contains integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). | Print *m* integers — the responses to Eugene's queries in the order they occur in the input. | [
"2 3\n1 -1\n1 1\n1 2\n2 2\n",
"5 5\n-1 1 1 1 -1\n1 1\n2 3\n3 5\n2 5\n1 5\n"
] | [
"0\n1\n0\n",
"0\n1\n0\n1\n0\n"
] | none | 500 | [
{
"input": "2 3\n1 -1\n1 1\n1 2\n2 2",
"output": "0\n1\n0"
},
{
"input": "5 5\n-1 1 1 1 -1\n1 1\n2 3\n3 5\n2 5\n1 5",
"output": "0\n1\n0\n1\n0"
},
{
"input": "3 3\n1 1 1\n2 2\n1 1\n1 1",
"output": "0\n0\n0"
},
{
"input": "4 4\n-1 -1 -1 -1\n1 3\n1 2\n1 2\n1 1",
"output": "... | 1,598,418,166 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 7 | 108 | 307,200 | n,m=map(int, input().split())
a=sorted(list(map(int,input().split())))
neg=0
pos=0
for i in range(n):
if a[i]==-1:
neg=i
else:
pos=i
pos=pos-neg
neg=neg+1
for i in range(m):
l, r=map(int,input().split())
d=r-(l-1)
if not d%2:
if d//2<=neg and d//2<=pos:
print(1)
else:
print(0)
if d%2:
print(0) | Title: Eugeny and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Eugeny has array *a*<==<=*a*1,<=*a*2,<=...,<=*a**n*, consisting of *n* integers. Each integer *a**i* equals to -1, or to 1. Also, he has *m* queries:
- Query number *i* is given as a pair of integers *l**i*, *r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*). - The response to the query will be integer 1, if the elements of array *a* can be rearranged so as the sum *a**l**i*<=+<=*a**l**i*<=+<=1<=+<=...<=+<=*a**r**i*<==<=0, otherwise the response to the query will be integer 0.
Help Eugeny, answer all his queries.
Input Specification:
The first line contains integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=2·105). The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (*a**i*<==<=-1,<=1). Next *m* lines contain Eugene's queries. The *i*-th line contains integers *l**i*,<=*r**i* (1<=≤<=*l**i*<=≤<=*r**i*<=≤<=*n*).
Output Specification:
Print *m* integers — the responses to Eugene's queries in the order they occur in the input.
Demo Input:
['2 3\n1 -1\n1 1\n1 2\n2 2\n', '5 5\n-1 1 1 1 -1\n1 1\n2 3\n3 5\n2 5\n1 5\n']
Demo Output:
['0\n1\n0\n', '0\n1\n0\n1\n0\n']
Note:
none | ```python
n,m=map(int, input().split())
a=sorted(list(map(int,input().split())))
neg=0
pos=0
for i in range(n):
if a[i]==-1:
neg=i
else:
pos=i
pos=pos-neg
neg=neg+1
for i in range(m):
l, r=map(int,input().split())
d=r-(l-1)
if not d%2:
if d//2<=neg and d//2<=pos:
print(1)
else:
print(0)
if d%2:
print(0)
``` | 0 | |
348 | A | Mafia | PROGRAMMING | 1,600 | [
"binary search",
"math",
"sortings"
] | null | null | One day *n* friends gathered together to play "Mafia". During each round of the game some player must be the supervisor and other *n*<=-<=1 people take part in the game. For each person we know in how many rounds he wants to be a player, not the supervisor: the *i*-th person wants to play *a**i* rounds. What is the minimum number of rounds of the "Mafia" game they need to play to let each person play at least as many rounds as they want? | The first line contains integer *n* (3<=≤<=*n*<=≤<=105). The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the *i*-th number in the list is the number of rounds the *i*-th person wants to play. | In a single line print a single integer — the minimum number of game rounds the friends need to let the *i*-th person play at least *a**i* rounds.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier. | [
"3\n3 2 2\n",
"4\n2 2 2 2\n"
] | [
"4\n",
"3\n"
] | You don't need to know the rules of "Mafia" to solve this problem. If you're curious, it's a game Russia got from the Soviet times: http://en.wikipedia.org/wiki/Mafia_(party_game). | 500 | [
{
"input": "3\n3 2 2",
"output": "4"
},
{
"input": "4\n2 2 2 2",
"output": "3"
},
{
"input": "7\n9 7 7 8 8 7 8",
"output": "9"
},
{
"input": "10\n13 12 10 13 13 14 10 10 12 12",
"output": "14"
},
{
"input": "10\n94 96 91 95 99 94 96 92 95 99",
"output": "106"
... | 1,624,093,772 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 2,000 | 0 | n=int(input())
l=list(map(int,input().split()))
l.sort()
c=0
while True:
if l[-1]<=0:
print(c)
exit()
for i in range(1,n):
l[i]=l[i]-1
c+=1
l.sort() | Title: Mafia
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day *n* friends gathered together to play "Mafia". During each round of the game some player must be the supervisor and other *n*<=-<=1 people take part in the game. For each person we know in how many rounds he wants to be a player, not the supervisor: the *i*-th person wants to play *a**i* rounds. What is the minimum number of rounds of the "Mafia" game they need to play to let each person play at least as many rounds as they want?
Input Specification:
The first line contains integer *n* (3<=≤<=*n*<=≤<=105). The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the *i*-th number in the list is the number of rounds the *i*-th person wants to play.
Output Specification:
In a single line print a single integer — the minimum number of game rounds the friends need to let the *i*-th person play at least *a**i* rounds.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.
Demo Input:
['3\n3 2 2\n', '4\n2 2 2 2\n']
Demo Output:
['4\n', '3\n']
Note:
You don't need to know the rules of "Mafia" to solve this problem. If you're curious, it's a game Russia got from the Soviet times: http://en.wikipedia.org/wiki/Mafia_(party_game). | ```python
n=int(input())
l=list(map(int,input().split()))
l.sort()
c=0
while True:
if l[-1]<=0:
print(c)
exit()
for i in range(1,n):
l[i]=l[i]-1
c+=1
l.sort()
``` | 0 | |
214 | A | System of Equations | PROGRAMMING | 800 | [
"brute force"
] | null | null | Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you?
You are given a system of equations:
You should count, how many there are pairs of integers (*a*,<=*b*) (0<=≤<=*a*,<=*b*) which satisfy the system. | A single line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the parameters of the system. The numbers on the line are separated by a space. | On a single line print the answer to the problem. | [
"9 3\n",
"14 28\n",
"4 20\n"
] | [
"1\n",
"1\n",
"0\n"
] | In the first sample the suitable pair is integers (3, 0). In the second sample the suitable pair is integers (3, 5). In the third sample there is no suitable pair. | 500 | [
{
"input": "9 3",
"output": "1"
},
{
"input": "14 28",
"output": "1"
},
{
"input": "4 20",
"output": "0"
},
{
"input": "18 198",
"output": "1"
},
{
"input": "22 326",
"output": "1"
},
{
"input": "26 104",
"output": "1"
},
{
"input": "14 10"... | 1,661,953,509 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 11 | 92 | 0 | n,m = map(int,input().split())
count = 0
if m>n:
x = m
else:
x = n
for a in range(x):
b = n-(a*a)
if a+(b*b)==m:
count += 1
print(count) | Title: System of Equations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you?
You are given a system of equations:
You should count, how many there are pairs of integers (*a*,<=*b*) (0<=≤<=*a*,<=*b*) which satisfy the system.
Input Specification:
A single line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the parameters of the system. The numbers on the line are separated by a space.
Output Specification:
On a single line print the answer to the problem.
Demo Input:
['9 3\n', '14 28\n', '4 20\n']
Demo Output:
['1\n', '1\n', '0\n']
Note:
In the first sample the suitable pair is integers (3, 0). In the second sample the suitable pair is integers (3, 5). In the third sample there is no suitable pair. | ```python
n,m = map(int,input().split())
count = 0
if m>n:
x = m
else:
x = n
for a in range(x):
b = n-(a*a)
if a+(b*b)==m:
count += 1
print(count)
``` | 0 | |
368 | B | Sereja and Suffixes | PROGRAMMING | 1,100 | [
"data structures",
"dp"
] | null | null | Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*). For each number *l**i* he wants to know how many distinct numbers are staying on the positions *l**i*, *l**i*<=+<=1, ..., *n*. Formally, he want to find the number of distinct numbers among *a**l**i*,<=*a**l**i*<=+<=1,<=...,<=*a**n*.?
Sereja wrote out the necessary array elements but the array was so large and the boy was so pressed for time. Help him, find the answer for the described question for each *l**i*. | The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105) — the array elements.
Next *m* lines contain integers *l*1,<=*l*2,<=...,<=*l**m*. The *i*-th line contains integer *l**i* (1<=≤<=*l**i*<=≤<=*n*). | Print *m* lines — on the *i*-th line print the answer to the number *l**i*. | [
"10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n"
] | [
"6\n6\n6\n6\n6\n5\n4\n3\n2\n1\n"
] | none | 1,000 | [
{
"input": "10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10",
"output": "6\n6\n6\n6\n6\n5\n4\n3\n2\n1"
},
{
"input": "8 3\n8 6 4 3 4 2 4 8\n6\n4\n2",
"output": "3\n4\n5"
},
{
"input": "7 10\n1 3 8 6 2 2 7\n4\n2\n6\n3\n4\n4\n6\n2\n7\n4",
"output": "3\n5\n2\n4\n3\n3\... | 1,694,570,853 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 108 | 20,275,200 | import sys
input = sys.stdin.readline
def main() -> None :
array:list[int] = []
queries:list[int] = []
_, QUERY_LEN = map(int, input().split())
array = list(map(int, input().split()))
queries = [int(input()) for _ in range(QUERY_LEN)]
answers:list[int] = []
answerTable:list[int] = [0]*len(array)
elementSet:set[int] = set()
for index in range(len(array)-1, 0-1, -1) :
elementSet.add(array[index])
answerTable[index] = len(elementSet)
answers = [answerTable[query-1] for query in queries]
print("\n".join(map(str, answers)))
main() | Title: Sereja and Suffixes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja has an array *a*, consisting of *n* integers *a*1, *a*2, ..., *a**n*. The boy cannot sit and do nothing, he decided to study an array. Sereja took a piece of paper and wrote out *m* integers *l*1,<=*l*2,<=...,<=*l**m* (1<=≤<=*l**i*<=≤<=*n*). For each number *l**i* he wants to know how many distinct numbers are staying on the positions *l**i*, *l**i*<=+<=1, ..., *n*. Formally, he want to find the number of distinct numbers among *a**l**i*,<=*a**l**i*<=+<=1,<=...,<=*a**n*.?
Sereja wrote out the necessary array elements but the array was so large and the boy was so pressed for time. Help him, find the answer for the described question for each *l**i*.
Input Specification:
The first line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105). The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105) — the array elements.
Next *m* lines contain integers *l*1,<=*l*2,<=...,<=*l**m*. The *i*-th line contains integer *l**i* (1<=≤<=*l**i*<=≤<=*n*).
Output Specification:
Print *m* lines — on the *i*-th line print the answer to the number *l**i*.
Demo Input:
['10 10\n1 2 3 4 1 2 3 4 100000 99999\n1\n2\n3\n4\n5\n6\n7\n8\n9\n10\n']
Demo Output:
['6\n6\n6\n6\n6\n5\n4\n3\n2\n1\n']
Note:
none | ```python
import sys
input = sys.stdin.readline
def main() -> None :
array:list[int] = []
queries:list[int] = []
_, QUERY_LEN = map(int, input().split())
array = list(map(int, input().split()))
queries = [int(input()) for _ in range(QUERY_LEN)]
answers:list[int] = []
answerTable:list[int] = [0]*len(array)
elementSet:set[int] = set()
for index in range(len(array)-1, 0-1, -1) :
elementSet.add(array[index])
answerTable[index] = len(elementSet)
answers = [answerTable[query-1] for query in queries]
print("\n".join(map(str, answers)))
main()
``` | 3 | |
712 | B | Memory and Trident | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | Memory is performing a walk on the two-dimensional plane, starting at the origin. He is given a string *s* with his directions for motion:
- An 'L' indicates he should move one unit left. - An 'R' indicates he should move one unit right. - A 'U' indicates he should move one unit up. - A 'D' indicates he should move one unit down.
But now Memory wants to end at the origin. To do this, he has a special trident. This trident can replace any character in *s* with any of 'L', 'R', 'U', or 'D'. However, because he doesn't want to wear out the trident, he wants to make the minimum number of edits possible. Please tell Memory what is the minimum number of changes he needs to make to produce a string that, when walked, will end at the origin, or if there is no such string. | The first and only line contains the string *s* (1<=≤<=|*s*|<=≤<=100<=000) — the instructions Memory is given. | If there is a string satisfying the conditions, output a single integer — the minimum number of edits required. In case it's not possible to change the sequence in such a way that it will bring Memory to to the origin, output -1. | [
"RRU\n",
"UDUR\n",
"RUUR\n"
] | [
"-1\n",
"1\n",
"2\n"
] | In the first sample test, Memory is told to walk right, then right, then up. It is easy to see that it is impossible to edit these instructions to form a valid walk.
In the second sample test, Memory is told to walk up, then down, then up, then right. One possible solution is to change *s* to "LDUR". This string uses 1 edit, which is the minimum possible. It also ends at the origin. | 1,000 | [
{
"input": "RRU",
"output": "-1"
},
{
"input": "UDUR",
"output": "1"
},
{
"input": "RUUR",
"output": "2"
},
{
"input": "DDDD",
"output": "2"
},
{
"input": "RRRR",
"output": "2"
},
{
"input": "RRRUUD",
"output": "2"
},
{
"input": "UDURLRDURL... | 1,479,483,007 | 2,147,483,647 | Python 3 | OK | TESTS | 75 | 108 | 307,200 | if __name__ == '__main__':
h = v = 0
line = str(input())
for it in line:
if it == 'R':
h += 1
elif it == 'L':
h -= 1
elif it == 'U':
v += 1
elif it == 'D':
v -= 1
distance = abs(abs(h) - abs(v))
if distance % 2 > 0:
print(-1)
else:
print(distance // 2 + min(abs(h), abs(v)))
| Title: Memory and Trident
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Memory is performing a walk on the two-dimensional plane, starting at the origin. He is given a string *s* with his directions for motion:
- An 'L' indicates he should move one unit left. - An 'R' indicates he should move one unit right. - A 'U' indicates he should move one unit up. - A 'D' indicates he should move one unit down.
But now Memory wants to end at the origin. To do this, he has a special trident. This trident can replace any character in *s* with any of 'L', 'R', 'U', or 'D'. However, because he doesn't want to wear out the trident, he wants to make the minimum number of edits possible. Please tell Memory what is the minimum number of changes he needs to make to produce a string that, when walked, will end at the origin, or if there is no such string.
Input Specification:
The first and only line contains the string *s* (1<=≤<=|*s*|<=≤<=100<=000) — the instructions Memory is given.
Output Specification:
If there is a string satisfying the conditions, output a single integer — the minimum number of edits required. In case it's not possible to change the sequence in such a way that it will bring Memory to to the origin, output -1.
Demo Input:
['RRU\n', 'UDUR\n', 'RUUR\n']
Demo Output:
['-1\n', '1\n', '2\n']
Note:
In the first sample test, Memory is told to walk right, then right, then up. It is easy to see that it is impossible to edit these instructions to form a valid walk.
In the second sample test, Memory is told to walk up, then down, then up, then right. One possible solution is to change *s* to "LDUR". This string uses 1 edit, which is the minimum possible. It also ends at the origin. | ```python
if __name__ == '__main__':
h = v = 0
line = str(input())
for it in line:
if it == 'R':
h += 1
elif it == 'L':
h -= 1
elif it == 'U':
v += 1
elif it == 'D':
v -= 1
distance = abs(abs(h) - abs(v))
if distance % 2 > 0:
print(-1)
else:
print(distance // 2 + min(abs(h), abs(v)))
``` | 3 | |
479 | A | Expression | PROGRAMMING | 1,000 | [
"brute force",
"math"
] | null | null | Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of operations '+' and '*', and probably brackets between the numbers so that the value of the resulting expression is as large as possible. Let's consider an example: assume that the teacher wrote numbers 1, 2 and 3 on the blackboard. Here are some ways of placing signs and brackets:
- 1+2*3=7 - 1*(2+3)=5 - 1*2*3=6 - (1+2)*3=9
Note that you can insert operation signs only between *a* and *b*, and between *b* and *c*, that is, you cannot swap integers. For instance, in the given sample you cannot get expression (1+3)*2.
It's easy to see that the maximum value that you can obtain is 9.
Your task is: given *a*, *b* and *c* print the maximum value that you can get. | The input contains three integers *a*, *b* and *c*, each on a single line (1<=≤<=*a*,<=*b*,<=*c*<=≤<=10). | Print the maximum value of the expression that you can obtain. | [
"1\n2\n3\n",
"2\n10\n3\n"
] | [
"9\n",
"60\n"
] | none | 500 | [
{
"input": "1\n2\n3",
"output": "9"
},
{
"input": "2\n10\n3",
"output": "60"
},
{
"input": "1\n1\n1",
"output": "3"
},
{
"input": "1\n2\n1",
"output": "4"
},
{
"input": "10\n10\n10",
"output": "1000"
},
{
"input": "5\n1\n3",
"output": "20"
},
{... | 1,698,427,886 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 29 | 77 | 0 | a=int(input())
b=int(input())
c=int(input())
z=[]
z.append(a+b+c)
z.append(a*b*c)
z.append((a+b)*c)
z.append(a*(b+c))
z.append(a+b*c)
z.append(a*b+c)
z.sort()
print(z[-1]) | Title: Expression
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers *a*, *b*, *c* on the blackboard. The task was to insert signs of operations '+' and '*', and probably brackets between the numbers so that the value of the resulting expression is as large as possible. Let's consider an example: assume that the teacher wrote numbers 1, 2 and 3 on the blackboard. Here are some ways of placing signs and brackets:
- 1+2*3=7 - 1*(2+3)=5 - 1*2*3=6 - (1+2)*3=9
Note that you can insert operation signs only between *a* and *b*, and between *b* and *c*, that is, you cannot swap integers. For instance, in the given sample you cannot get expression (1+3)*2.
It's easy to see that the maximum value that you can obtain is 9.
Your task is: given *a*, *b* and *c* print the maximum value that you can get.
Input Specification:
The input contains three integers *a*, *b* and *c*, each on a single line (1<=≤<=*a*,<=*b*,<=*c*<=≤<=10).
Output Specification:
Print the maximum value of the expression that you can obtain.
Demo Input:
['1\n2\n3\n', '2\n10\n3\n']
Demo Output:
['9\n', '60\n']
Note:
none | ```python
a=int(input())
b=int(input())
c=int(input())
z=[]
z.append(a+b+c)
z.append(a*b*c)
z.append((a+b)*c)
z.append(a*(b+c))
z.append(a+b*c)
z.append(a*b+c)
z.sort()
print(z[-1])
``` | 3 | |
934 | A | A Compatible Pair | PROGRAMMING | 1,400 | [
"brute force",
"games"
] | null | null | Nian is a monster which lives deep in the oceans. Once a year, it shows up on the land, devouring livestock and even people. In order to keep the monster away, people fill their villages with red colour, light, and cracking noise, all of which frighten the monster out of coming.
Little Tommy has *n* lanterns and Big Banban has *m* lanterns. Tommy's lanterns have brightness *a*1,<=*a*2,<=...,<=*a**n*, and Banban's have brightness *b*1,<=*b*2,<=...,<=*b**m* respectively.
Tommy intends to hide one of his lanterns, then Banban picks one of Tommy's non-hidden lanterns and one of his own lanterns to form a pair. The pair's brightness will be the product of the brightness of two lanterns.
Tommy wants to make the product as small as possible, while Banban tries to make it as large as possible.
You are asked to find the brightness of the chosen pair if both of them choose optimally. | The first line contains two space-separated integers *n* and *m* (2<=≤<=*n*,<=*m*<=≤<=50).
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n*.
The third line contains *m* space-separated integers *b*1,<=*b*2,<=...,<=*b**m*.
All the integers range from <=-<=109 to 109. | Print a single integer — the brightness of the chosen pair. | [
"2 2\n20 18\n2 14\n",
"5 3\n-1 0 1 2 3\n-1 0 1\n"
] | [
"252\n",
"2\n"
] | In the first example, Tommy will hide 20 and Banban will choose 18 from Tommy and 14 from himself.
In the second example, Tommy will hide 3 and Banban will choose 2 from Tommy and 1 from himself. | 500 | [
{
"input": "2 2\n20 18\n2 14",
"output": "252"
},
{
"input": "5 3\n-1 0 1 2 3\n-1 0 1",
"output": "2"
},
{
"input": "10 2\n1 6 2 10 2 3 2 10 6 4\n5 7",
"output": "70"
},
{
"input": "50 50\n1 6 2 10 2 3 2 10 6 4 5 0 3 1 7 3 2 4 4 2 1 5 0 6 10 1 8 0 10 9 0 4 10 5 5 7 4 9 9 5 5 ... | 1,518,771,706 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 61 | 5,632,000 | n,m=input().split(' ')
a=sorted([int(i) for i in input().split(' ')])
b=sorted([int(i) for i in input().split(' ')])
if(b[-1]>0):
print(max(b[-1]*a[-2],b[0]*a[1]))
else:
print(max(b[-1]*a[1],b[0]*a[-2])) | Title: A Compatible Pair
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Nian is a monster which lives deep in the oceans. Once a year, it shows up on the land, devouring livestock and even people. In order to keep the monster away, people fill their villages with red colour, light, and cracking noise, all of which frighten the monster out of coming.
Little Tommy has *n* lanterns and Big Banban has *m* lanterns. Tommy's lanterns have brightness *a*1,<=*a*2,<=...,<=*a**n*, and Banban's have brightness *b*1,<=*b*2,<=...,<=*b**m* respectively.
Tommy intends to hide one of his lanterns, then Banban picks one of Tommy's non-hidden lanterns and one of his own lanterns to form a pair. The pair's brightness will be the product of the brightness of two lanterns.
Tommy wants to make the product as small as possible, while Banban tries to make it as large as possible.
You are asked to find the brightness of the chosen pair if both of them choose optimally.
Input Specification:
The first line contains two space-separated integers *n* and *m* (2<=≤<=*n*,<=*m*<=≤<=50).
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n*.
The third line contains *m* space-separated integers *b*1,<=*b*2,<=...,<=*b**m*.
All the integers range from <=-<=109 to 109.
Output Specification:
Print a single integer — the brightness of the chosen pair.
Demo Input:
['2 2\n20 18\n2 14\n', '5 3\n-1 0 1 2 3\n-1 0 1\n']
Demo Output:
['252\n', '2\n']
Note:
In the first example, Tommy will hide 20 and Banban will choose 18 from Tommy and 14 from himself.
In the second example, Tommy will hide 3 and Banban will choose 2 from Tommy and 1 from himself. | ```python
n,m=input().split(' ')
a=sorted([int(i) for i in input().split(' ')])
b=sorted([int(i) for i in input().split(' ')])
if(b[-1]>0):
print(max(b[-1]*a[-2],b[0]*a[1]))
else:
print(max(b[-1]*a[1],b[0]*a[-2]))
``` | 0 | |
446 | A | DZY Loves Sequences | PROGRAMMING | 1,600 | [
"dp",
"implementation",
"two pointers"
] | null | null | DZY has a sequence *a*, consisting of *n* integers.
We'll call a sequence *a**i*,<=*a**i*<=+<=1,<=...,<=*a**j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) a subsegment of the sequence *a*. The value (*j*<=-<=*i*<=+<=1) denotes the length of the subsegment.
Your task is to find the longest subsegment of *a*, such that it is possible to change at most one number (change one number to any integer you want) from the subsegment to make the subsegment strictly increasing.
You only need to output the length of the subsegment you find. | The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109). | In a single line print the answer to the problem — the maximum length of the required subsegment. | [
"6\n7 2 3 1 5 6\n"
] | [
"5\n"
] | You can choose subsegment *a*<sub class="lower-index">2</sub>, *a*<sub class="lower-index">3</sub>, *a*<sub class="lower-index">4</sub>, *a*<sub class="lower-index">5</sub>, *a*<sub class="lower-index">6</sub> and change its 3rd element (that is *a*<sub class="lower-index">4</sub>) to 4. | 500 | [
{
"input": "6\n7 2 3 1 5 6",
"output": "5"
},
{
"input": "10\n424238336 649760493 681692778 714636916 719885387 804289384 846930887 957747794 596516650 189641422",
"output": "9"
},
{
"input": "50\n804289384 846930887 681692778 714636916 957747794 424238336 719885387 649760493 596516650 1... | 1,490,391,711 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 4,608,000 | from sys import stdin
N = int(stdin.readline().rstrip())
seq = [int(x) for x in stdin.readline().rstrip().split()]
start_index = 0
change_index = -1
max_count = 1
for n in range(1, N):
if seq[n] <= seq[n - 1]:
if change_index == -1:
change_index = n
else:
diff = n - start_index
if max_count < diff:
max_count = diff
start_index = change_index
change_index = n
diff = n - start_index
if max_count < diff:
max_count = diff
print(max_count + 1) | Title: DZY Loves Sequences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
DZY has a sequence *a*, consisting of *n* integers.
We'll call a sequence *a**i*,<=*a**i*<=+<=1,<=...,<=*a**j* (1<=≤<=*i*<=≤<=*j*<=≤<=*n*) a subsegment of the sequence *a*. The value (*j*<=-<=*i*<=+<=1) denotes the length of the subsegment.
Your task is to find the longest subsegment of *a*, such that it is possible to change at most one number (change one number to any integer you want) from the subsegment to make the subsegment strictly increasing.
You only need to output the length of the subsegment you find.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=105). The next line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109).
Output Specification:
In a single line print the answer to the problem — the maximum length of the required subsegment.
Demo Input:
['6\n7 2 3 1 5 6\n']
Demo Output:
['5\n']
Note:
You can choose subsegment *a*<sub class="lower-index">2</sub>, *a*<sub class="lower-index">3</sub>, *a*<sub class="lower-index">4</sub>, *a*<sub class="lower-index">5</sub>, *a*<sub class="lower-index">6</sub> and change its 3rd element (that is *a*<sub class="lower-index">4</sub>) to 4. | ```python
from sys import stdin
N = int(stdin.readline().rstrip())
seq = [int(x) for x in stdin.readline().rstrip().split()]
start_index = 0
change_index = -1
max_count = 1
for n in range(1, N):
if seq[n] <= seq[n - 1]:
if change_index == -1:
change_index = n
else:
diff = n - start_index
if max_count < diff:
max_count = diff
start_index = change_index
change_index = n
diff = n - start_index
if max_count < diff:
max_count = diff
print(max_count + 1)
``` | 0 |
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