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values | time-limit stringclasses 8
values | memory-limit stringclasses 8
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|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
991 | A | If at first you don't succeed... | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Each student eagerly awaits the day he would pass the exams successfully. Thus, Vasya was ready to celebrate, but, alas, he didn't pass it. However, many of Vasya's fellow students from the same group were more successful and celebrated after the exam.
Some of them celebrated in the BugDonalds restaurant, some of them — in the BeaverKing restaurant, the most successful ones were fast enough to celebrate in both of restaurants. Students which didn't pass the exam didn't celebrate in any of those restaurants and elected to stay home to prepare for their reexamination. However, this quickly bored Vasya and he started checking celebration photos on the Kilogramm. He found out that, in total, BugDonalds was visited by $A$ students, BeaverKing — by $B$ students and $C$ students visited both restaurants. Vasya also knows that there are $N$ students in his group.
Based on this info, Vasya wants to determine either if his data contradicts itself or, if it doesn't, how many students in his group didn't pass the exam. Can you help him so he won't waste his valuable preparation time? | The first line contains four integers — $A$, $B$, $C$ and $N$ ($0 \leq A, B, C, N \leq 100$). | If a distribution of $N$ students exists in which $A$ students visited BugDonalds, $B$ — BeaverKing, $C$ — both of the restaurants and at least one student is left home (it is known that Vasya didn't pass the exam and stayed at home), output one integer — amount of students (including Vasya) who did not pass the exam.
If such a distribution does not exist and Vasya made a mistake while determining the numbers $A$, $B$, $C$ or $N$ (as in samples 2 and 3), output $-1$. | [
"10 10 5 20\n",
"2 2 0 4\n",
"2 2 2 1\n"
] | [
"5",
"-1",
"-1"
] | The first sample describes following situation: $5$ only visited BugDonalds, $5$ students only visited BeaverKing, $5$ visited both of them and $5$ students (including Vasya) didn't pass the exam.
In the second sample $2$ students only visited BugDonalds and $2$ only visited BeaverKing, but that means all $4$ students in group passed the exam which contradicts the fact that Vasya didn't pass meaning that this situation is impossible.
The third sample describes a situation where $2$ students visited BugDonalds but the group has only $1$ which makes it clearly impossible. | 500 | [
{
"input": "10 10 5 20",
"output": "5"
},
{
"input": "2 2 0 4",
"output": "-1"
},
{
"input": "2 2 2 1",
"output": "-1"
},
{
"input": "98 98 97 100",
"output": "1"
},
{
"input": "1 5 2 10",
"output": "-1"
},
{
"input": "5 1 2 10",
"output": "-1"
}... | 1,625,327,899 | 2,147,483,647 | PyPy 3 | OK | TESTS | 76 | 124 | 0 | A,B,C,N=map(int,input().split())
AUB=A+B-C
if AUB>=N:
print(-1)
elif AUB<0:
print(-1)
elif A<C:
print(-1)
elif B<C:
print(-1)
else:
print(N-AUB)
| Title: If at first you don't succeed...
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Each student eagerly awaits the day he would pass the exams successfully. Thus, Vasya was ready to celebrate, but, alas, he didn't pass it. However, many of Vasya's fellow students from the same group were more successful and celebrated after the exam.
Some of them celebrated in the BugDonalds restaurant, some of them — in the BeaverKing restaurant, the most successful ones were fast enough to celebrate in both of restaurants. Students which didn't pass the exam didn't celebrate in any of those restaurants and elected to stay home to prepare for their reexamination. However, this quickly bored Vasya and he started checking celebration photos on the Kilogramm. He found out that, in total, BugDonalds was visited by $A$ students, BeaverKing — by $B$ students and $C$ students visited both restaurants. Vasya also knows that there are $N$ students in his group.
Based on this info, Vasya wants to determine either if his data contradicts itself or, if it doesn't, how many students in his group didn't pass the exam. Can you help him so he won't waste his valuable preparation time?
Input Specification:
The first line contains four integers — $A$, $B$, $C$ and $N$ ($0 \leq A, B, C, N \leq 100$).
Output Specification:
If a distribution of $N$ students exists in which $A$ students visited BugDonalds, $B$ — BeaverKing, $C$ — both of the restaurants and at least one student is left home (it is known that Vasya didn't pass the exam and stayed at home), output one integer — amount of students (including Vasya) who did not pass the exam.
If such a distribution does not exist and Vasya made a mistake while determining the numbers $A$, $B$, $C$ or $N$ (as in samples 2 and 3), output $-1$.
Demo Input:
['10 10 5 20\n', '2 2 0 4\n', '2 2 2 1\n']
Demo Output:
['5', '-1', '-1']
Note:
The first sample describes following situation: $5$ only visited BugDonalds, $5$ students only visited BeaverKing, $5$ visited both of them and $5$ students (including Vasya) didn't pass the exam.
In the second sample $2$ students only visited BugDonalds and $2$ only visited BeaverKing, but that means all $4$ students in group passed the exam which contradicts the fact that Vasya didn't pass meaning that this situation is impossible.
The third sample describes a situation where $2$ students visited BugDonalds but the group has only $1$ which makes it clearly impossible. | ```python
A,B,C,N=map(int,input().split())
AUB=A+B-C
if AUB>=N:
print(-1)
elif AUB<0:
print(-1)
elif A<C:
print(-1)
elif B<C:
print(-1)
else:
print(N-AUB)
``` | 3 | |
450 | B | Jzzhu and Sequences | PROGRAMMING | 1,300 | [
"implementation",
"math"
] | null | null | Jzzhu has invented a kind of sequences, they meet the following property:
You are given *x* and *y*, please calculate *f**n* modulo 1000000007 (109<=+<=7). | The first line contains two integers *x* and *y* (|*x*|,<=|*y*|<=≤<=109). The second line contains a single integer *n* (1<=≤<=*n*<=≤<=2·109). | Output a single integer representing *f**n* modulo 1000000007 (109<=+<=7). | [
"2 3\n3\n",
"0 -1\n2\n"
] | [
"1\n",
"1000000006\n"
] | In the first sample, *f*<sub class="lower-index">2</sub> = *f*<sub class="lower-index">1</sub> + *f*<sub class="lower-index">3</sub>, 3 = 2 + *f*<sub class="lower-index">3</sub>, *f*<sub class="lower-index">3</sub> = 1.
In the second sample, *f*<sub class="lower-index">2</sub> = - 1; - 1 modulo (10<sup class="upper-index">9</sup> + 7) equals (10<sup class="upper-index">9</sup> + 6). | 1,000 | [
{
"input": "2 3\n3",
"output": "1"
},
{
"input": "0 -1\n2",
"output": "1000000006"
},
{
"input": "-9 -11\n12345",
"output": "1000000005"
},
{
"input": "0 0\n1000000000",
"output": "0"
},
{
"input": "-1000000000 1000000000\n2000000000",
"output": "1000000000"
... | 1,692,740,467 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 6 | 93 | 0 | def f(n,x,y):
if n%6==1:
return(x)
if n%6==2:
return(y)
if n%6==3:
return(y-x)
if n%6==4:
return(-x)
if n%6==5:
return(-y)
if n%6==0:
return(x-y)
x,y=map(int,input().split())
n=int(input())
print(f(n,x,y%1000000007))
| Title: Jzzhu and Sequences
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jzzhu has invented a kind of sequences, they meet the following property:
You are given *x* and *y*, please calculate *f**n* modulo 1000000007 (109<=+<=7).
Input Specification:
The first line contains two integers *x* and *y* (|*x*|,<=|*y*|<=≤<=109). The second line contains a single integer *n* (1<=≤<=*n*<=≤<=2·109).
Output Specification:
Output a single integer representing *f**n* modulo 1000000007 (109<=+<=7).
Demo Input:
['2 3\n3\n', '0 -1\n2\n']
Demo Output:
['1\n', '1000000006\n']
Note:
In the first sample, *f*<sub class="lower-index">2</sub> = *f*<sub class="lower-index">1</sub> + *f*<sub class="lower-index">3</sub>, 3 = 2 + *f*<sub class="lower-index">3</sub>, *f*<sub class="lower-index">3</sub> = 1.
In the second sample, *f*<sub class="lower-index">2</sub> = - 1; - 1 modulo (10<sup class="upper-index">9</sup> + 7) equals (10<sup class="upper-index">9</sup> + 6). | ```python
def f(n,x,y):
if n%6==1:
return(x)
if n%6==2:
return(y)
if n%6==3:
return(y-x)
if n%6==4:
return(-x)
if n%6==5:
return(-y)
if n%6==0:
return(x-y)
x,y=map(int,input().split())
n=int(input())
print(f(n,x,y%1000000007))
``` | 0 | |
980 | A | Links and Pearls | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | A necklace can be described as a string of links ('-') and pearls ('o'), with the last link or pearl connected to the first one.
You can remove a link or a pearl and insert it between two other existing links or pearls (or between a link and a pearl) on the necklace. This process can be repeated as many times as you like, but you can't throw away any parts.
Can you make the number of links between every two adjacent pearls equal? Two pearls are considered to be adjacent if there is no other pearl between them.
Note that the final necklace should remain as one circular part of the same length as the initial necklace. | The only line of input contains a string $s$ ($3 \leq |s| \leq 100$), representing the necklace, where a dash '-' represents a link and the lowercase English letter 'o' represents a pearl. | Print "YES" if the links and pearls can be rejoined such that the number of links between adjacent pearls is equal. Otherwise print "NO".
You can print each letter in any case (upper or lower). | [
"-o-o--",
"-o---\n",
"-o---o-\n",
"ooo\n"
] | [
"YES",
"YES",
"NO",
"YES\n"
] | none | 500 | [
{
"input": "-o-o--",
"output": "YES"
},
{
"input": "-o---",
"output": "YES"
},
{
"input": "-o---o-",
"output": "NO"
},
{
"input": "ooo",
"output": "YES"
},
{
"input": "---",
"output": "YES"
},
{
"input": "--o-o-----o----o--oo-o-----ooo-oo---o--",
"... | 1,627,950,509 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
using namespace std;
int n,k,p,f,i,j;
int a[100003];
int main()
{
cin>>n>>k
for(i=1;i<=n;i++)
{
if(i<=k)
{
if(i%2==1) a[i]=i/2+1,f=0;
else a[i]=n-i/2+1,f=1;
}
else
{
if(f==0) a[i]=a[i-1]+1;
else a[i]=a[i-1]-1;
}
}
for(i=1;i<=n;i++) cout<<a[i]<<" ";
return 0;
} | Title: Links and Pearls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A necklace can be described as a string of links ('-') and pearls ('o'), with the last link or pearl connected to the first one.
You can remove a link or a pearl and insert it between two other existing links or pearls (or between a link and a pearl) on the necklace. This process can be repeated as many times as you like, but you can't throw away any parts.
Can you make the number of links between every two adjacent pearls equal? Two pearls are considered to be adjacent if there is no other pearl between them.
Note that the final necklace should remain as one circular part of the same length as the initial necklace.
Input Specification:
The only line of input contains a string $s$ ($3 \leq |s| \leq 100$), representing the necklace, where a dash '-' represents a link and the lowercase English letter 'o' represents a pearl.
Output Specification:
Print "YES" if the links and pearls can be rejoined such that the number of links between adjacent pearls is equal. Otherwise print "NO".
You can print each letter in any case (upper or lower).
Demo Input:
['-o-o--', '-o---\n', '-o---o-\n', 'ooo\n']
Demo Output:
['YES', 'YES', 'NO', 'YES\n']
Note:
none | ```python
#include <bits/stdc++.h>
using namespace std;
int n,k,p,f,i,j;
int a[100003];
int main()
{
cin>>n>>k
for(i=1;i<=n;i++)
{
if(i<=k)
{
if(i%2==1) a[i]=i/2+1,f=0;
else a[i]=n-i/2+1,f=1;
}
else
{
if(f==0) a[i]=a[i-1]+1;
else a[i]=a[i-1]-1;
}
}
for(i=1;i<=n;i++) cout<<a[i]<<" ";
return 0;
}
``` | -1 | |
652 | B | z-sort | PROGRAMMING | 1,000 | [
"sortings"
] | null | null | A student of *z*-school found a kind of sorting called *z*-sort. The array *a* with *n* elements are *z*-sorted if two conditions hold:
1. *a**i*<=≥<=*a**i*<=-<=1 for all even *i*, 1. *a**i*<=≤<=*a**i*<=-<=1 for all odd *i*<=><=1.
For example the arrays [1,2,1,2] and [1,1,1,1] are *z*-sorted while the array [1,2,3,4] isn’t *z*-sorted.
Can you make the array *z*-sorted? | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of elements in the array *a*.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the elements of the array *a*. | If it's possible to make the array *a* *z*-sorted print *n* space separated integers *a**i* — the elements after *z*-sort. Otherwise print the only word "Impossible". | [
"4\n1 2 2 1\n",
"5\n1 3 2 2 5\n"
] | [
"1 2 1 2\n",
"1 5 2 3 2\n"
] | none | 0 | [
{
"input": "4\n1 2 2 1",
"output": "1 2 1 2"
},
{
"input": "5\n1 3 2 2 5",
"output": "1 5 2 3 2"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "10\n1 1 1 1 1 1 1 1 1 1",
"output": "1 1 1 1 1 1 1 1 1 1"
},
{
"input": "10\n1 9 7 6 2 4 7 8 1 3",
"output": "1 ... | 1,460,580,859 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | import itertools
n = int(input())
mass = list(map(int, input().split()))
odds = []
evens = []
for i in range(n):
if i % 2 == 0:
odds.append(mass[i])
else:
evens.append(mass[i])
odds.sort(reverse = True)
evens.sort()
#print(odds, evens)
tmp_mass = []
for a in itertools.zip_longest(odds, evens):
tmp_mass.append(a[0])
tmp_mass.append(a[1])
if n % 2 == 0:
print(' '.join(map(str, tmp_mass)))
else:
print(' '.join(map(str, tmp_mass[:n])))
| Title: z-sort
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A student of *z*-school found a kind of sorting called *z*-sort. The array *a* with *n* elements are *z*-sorted if two conditions hold:
1. *a**i*<=≥<=*a**i*<=-<=1 for all even *i*, 1. *a**i*<=≤<=*a**i*<=-<=1 for all odd *i*<=><=1.
For example the arrays [1,2,1,2] and [1,1,1,1] are *z*-sorted while the array [1,2,3,4] isn’t *z*-sorted.
Can you make the array *z*-sorted?
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of elements in the array *a*.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=109) — the elements of the array *a*.
Output Specification:
If it's possible to make the array *a* *z*-sorted print *n* space separated integers *a**i* — the elements after *z*-sort. Otherwise print the only word "Impossible".
Demo Input:
['4\n1 2 2 1\n', '5\n1 3 2 2 5\n']
Demo Output:
['1 2 1 2\n', '1 5 2 3 2\n']
Note:
none | ```python
import itertools
n = int(input())
mass = list(map(int, input().split()))
odds = []
evens = []
for i in range(n):
if i % 2 == 0:
odds.append(mass[i])
else:
evens.append(mass[i])
odds.sort(reverse = True)
evens.sort()
#print(odds, evens)
tmp_mass = []
for a in itertools.zip_longest(odds, evens):
tmp_mass.append(a[0])
tmp_mass.append(a[1])
if n % 2 == 0:
print(' '.join(map(str, tmp_mass)))
else:
print(' '.join(map(str, tmp_mass[:n])))
``` | 0 | |
451 | A | Game With Sticks | PROGRAMMING | 900 | [
"implementation"
] | null | null | After winning gold and silver in IOI 2014, Akshat and Malvika want to have some fun. Now they are playing a game on a grid made of *n* horizontal and *m* vertical sticks.
An intersection point is any point on the grid which is formed by the intersection of one horizontal stick and one vertical stick.
In the grid shown below, *n*<==<=3 and *m*<==<=3. There are *n*<=+<=*m*<==<=6 sticks in total (horizontal sticks are shown in red and vertical sticks are shown in green). There are *n*·*m*<==<=9 intersection points, numbered from 1 to 9.
The rules of the game are very simple. The players move in turns. Akshat won gold, so he makes the first move. During his/her move, a player must choose any remaining intersection point and remove from the grid all sticks which pass through this point. A player will lose the game if he/she cannot make a move (i.e. there are no intersection points remaining on the grid at his/her move).
Assume that both players play optimally. Who will win the game? | The first line of input contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100). | Print a single line containing "Akshat" or "Malvika" (without the quotes), depending on the winner of the game. | [
"2 2\n",
"2 3\n",
"3 3\n"
] | [
"Malvika\n",
"Malvika\n",
"Akshat\n"
] | Explanation of the first sample:
The grid has four intersection points, numbered from 1 to 4.
If Akshat chooses intersection point 1, then he will remove two sticks (1 - 2 and 1 - 3). The resulting grid will look like this.
Now there is only one remaining intersection point (i.e. 4). Malvika must choose it and remove both remaining sticks. After her move the grid will be empty.
In the empty grid, Akshat cannot make any move, hence he will lose.
Since all 4 intersection points of the grid are equivalent, Akshat will lose no matter which one he picks. | 500 | [
{
"input": "2 2",
"output": "Malvika"
},
{
"input": "2 3",
"output": "Malvika"
},
{
"input": "3 3",
"output": "Akshat"
},
{
"input": "20 68",
"output": "Malvika"
},
{
"input": "1 1",
"output": "Akshat"
},
{
"input": "1 2",
"output": "Akshat"
},
... | 1,696,264,518 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 31 | 0 | m,n = map(int,input().split())
if (m * n) % 2 == 0:
print('Malvika')
else:
print('Akshat') | Title: Game With Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After winning gold and silver in IOI 2014, Akshat and Malvika want to have some fun. Now they are playing a game on a grid made of *n* horizontal and *m* vertical sticks.
An intersection point is any point on the grid which is formed by the intersection of one horizontal stick and one vertical stick.
In the grid shown below, *n*<==<=3 and *m*<==<=3. There are *n*<=+<=*m*<==<=6 sticks in total (horizontal sticks are shown in red and vertical sticks are shown in green). There are *n*·*m*<==<=9 intersection points, numbered from 1 to 9.
The rules of the game are very simple. The players move in turns. Akshat won gold, so he makes the first move. During his/her move, a player must choose any remaining intersection point and remove from the grid all sticks which pass through this point. A player will lose the game if he/she cannot make a move (i.e. there are no intersection points remaining on the grid at his/her move).
Assume that both players play optimally. Who will win the game?
Input Specification:
The first line of input contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100).
Output Specification:
Print a single line containing "Akshat" or "Malvika" (without the quotes), depending on the winner of the game.
Demo Input:
['2 2\n', '2 3\n', '3 3\n']
Demo Output:
['Malvika\n', 'Malvika\n', 'Akshat\n']
Note:
Explanation of the first sample:
The grid has four intersection points, numbered from 1 to 4.
If Akshat chooses intersection point 1, then he will remove two sticks (1 - 2 and 1 - 3). The resulting grid will look like this.
Now there is only one remaining intersection point (i.e. 4). Malvika must choose it and remove both remaining sticks. After her move the grid will be empty.
In the empty grid, Akshat cannot make any move, hence he will lose.
Since all 4 intersection points of the grid are equivalent, Akshat will lose no matter which one he picks. | ```python
m,n = map(int,input().split())
if (m * n) % 2 == 0:
print('Malvika')
else:
print('Akshat')
``` | 0 | |
136 | A | Presents | PROGRAMMING | 800 | [
"implementation"
] | null | null | Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on this occasion he organized a New Year party at his place and invited *n* his friends there.
If there's one thing Petya likes more that receiving gifts, that's watching others giving gifts to somebody else. Thus, he safely hid the laptop until the next New Year and made up his mind to watch his friends exchanging gifts while he does not participate in the process. He numbered all his friends with integers from 1 to *n*. Petya remembered that a friend number *i* gave a gift to a friend number *p**i*. He also remembered that each of his friends received exactly one gift.
Now Petya wants to know for each friend *i* the number of a friend who has given him a gift. | The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the quantity of friends Petya invited to the party. The second line contains *n* space-separated integers: the *i*-th number is *p**i* — the number of a friend who gave a gift to friend number *i*. It is guaranteed that each friend received exactly one gift. It is possible that some friends do not share Petya's ideas of giving gifts to somebody else. Those friends gave the gifts to themselves. | Print *n* space-separated integers: the *i*-th number should equal the number of the friend who gave a gift to friend number *i*. | [
"4\n2 3 4 1\n",
"3\n1 3 2\n",
"2\n1 2\n"
] | [
"4 1 2 3\n",
"1 3 2\n",
"1 2\n"
] | none | 500 | [
{
"input": "4\n2 3 4 1",
"output": "4 1 2 3"
},
{
"input": "3\n1 3 2",
"output": "1 3 2"
},
{
"input": "2\n1 2",
"output": "1 2"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "10\n1 3 2 6 4 5 7 9 8 10",
"output": "1 3 2 5 6 4 7 9 8 10"
},
{
"input"... | 1,690,498,180 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 101 | 124 | 0 | import sys
input = sys.stdin.readline
n = int(input())
a = list(map(int, input().split()))
ans = [i for i in range(n)]
for i, v in enumerate(a):
ans[v-1] = i+1
print(*ans) | Title: Presents
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Petya very much likes gifts. Recently he has received a new laptop as a New Year gift from his mother. He immediately decided to give it to somebody else as what can be more pleasant than giving somebody gifts. And on this occasion he organized a New Year party at his place and invited *n* his friends there.
If there's one thing Petya likes more that receiving gifts, that's watching others giving gifts to somebody else. Thus, he safely hid the laptop until the next New Year and made up his mind to watch his friends exchanging gifts while he does not participate in the process. He numbered all his friends with integers from 1 to *n*. Petya remembered that a friend number *i* gave a gift to a friend number *p**i*. He also remembered that each of his friends received exactly one gift.
Now Petya wants to know for each friend *i* the number of a friend who has given him a gift.
Input Specification:
The first line contains one integer *n* (1<=≤<=*n*<=≤<=100) — the quantity of friends Petya invited to the party. The second line contains *n* space-separated integers: the *i*-th number is *p**i* — the number of a friend who gave a gift to friend number *i*. It is guaranteed that each friend received exactly one gift. It is possible that some friends do not share Petya's ideas of giving gifts to somebody else. Those friends gave the gifts to themselves.
Output Specification:
Print *n* space-separated integers: the *i*-th number should equal the number of the friend who gave a gift to friend number *i*.
Demo Input:
['4\n2 3 4 1\n', '3\n1 3 2\n', '2\n1 2\n']
Demo Output:
['4 1 2 3\n', '1 3 2\n', '1 2\n']
Note:
none | ```python
import sys
input = sys.stdin.readline
n = int(input())
a = list(map(int, input().split()))
ans = [i for i in range(n)]
for i, v in enumerate(a):
ans[v-1] = i+1
print(*ans)
``` | 3 | |
730 | H | Delete Them | PROGRAMMING | 1,300 | [
"constructive algorithms",
"implementation"
] | null | null | Polycarp is a beginner programmer. He is studying how to use a command line.
Polycarp faced the following problem. There are *n* files in a directory and he needs to delete some of them. Polycarp wants to run a single delete command with filename pattern as an argument. All the files to be deleted should match the pattern and all other files shouldn't match the pattern.
Polycarp doesn't know about an asterisk '*', the only special character he knows is a question mark '?' which matches any single character. All other characters in the pattern match themselves only.
Formally, a pattern matches a filename if and only if they have equal lengths and all characters in the corresponding positions are equal except when the character in the pattern is '?', in which case the corresponding filename character does not matter.
For example, the filename pattern "a?ba?":
- matches filenames "aabaa", "abba.", "a.ba9" and "a.ba."; - does not match filenames "aaba", "abaab", "aabaaa" and "aabaa.".
Help Polycarp find a pattern which matches files to be deleted and only them or report if there is no such pattern. | The first line of the input contains two integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — the total number of files and the number of files to be deleted.
The following *n* lines contain filenames, single filename per line. All filenames are non-empty strings containing only lowercase English letters, digits and dots ('.'). The length of each filename doesn't exceed 100. It is guaranteed that all filenames are distinct.
The last line of the input contains *m* distinct integer numbers in ascending order *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=*n*) — indices of files to be deleted. All files are indexed from 1 to *n* in order of their appearance in the input. | If the required pattern exists, print "Yes" in the first line of the output. The second line should contain the required pattern. If there are multiple solutions, print any of them.
If the required pattern doesn't exist, print the only line containing "No". | [
"3 2\nab\nac\ncd\n1 2\n",
"5 3\ntest\ntezt\ntest.\n.est\ntes.\n1 4 5\n",
"4 4\na\nb\nc\ndd\n1 2 3 4\n",
"6 3\n.svn\n.git\n....\n...\n..\n.\n1 2 3\n"
] | [
"Yes\na?\n",
"Yes\n?es?\n",
"No\n",
"Yes\n.???\n"
] | none | 0 | [
{
"input": "3 2\nab\nac\ncd\n1 2",
"output": "Yes\na?"
},
{
"input": "5 3\ntest\ntezt\ntest.\n.est\ntes.\n1 4 5",
"output": "Yes\n?es?"
},
{
"input": "4 4\na\nb\nc\ndd\n1 2 3 4",
"output": "No"
},
{
"input": "6 3\n.svn\n.git\n....\n...\n..\n.\n1 2 3",
"output": "Yes\n.???... | 1,477,210,840 | 1,240 | Python 3 | WRONG_ANSWER | TESTS | 4 | 62 | 0 | num_file,num_delete = map(int, input().split())
list_file = []
for i in range(num_file):
list_file.append(input())
delete_file = [int(i)-1 for i in input().split()]
ans=""
tmp = list(list_file[delete_file[0]])
for i in delete_file[1:]:
name = list(list_file[i])
for j in range(len(tmp)):
if name[j] != tmp[j]:
tmp[j] = "?"
if tmp == ['?']:
print("No")
else:
print("Yes")
for c in tmp:
print(c,end="") | Title: Delete Them
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is a beginner programmer. He is studying how to use a command line.
Polycarp faced the following problem. There are *n* files in a directory and he needs to delete some of them. Polycarp wants to run a single delete command with filename pattern as an argument. All the files to be deleted should match the pattern and all other files shouldn't match the pattern.
Polycarp doesn't know about an asterisk '*', the only special character he knows is a question mark '?' which matches any single character. All other characters in the pattern match themselves only.
Formally, a pattern matches a filename if and only if they have equal lengths and all characters in the corresponding positions are equal except when the character in the pattern is '?', in which case the corresponding filename character does not matter.
For example, the filename pattern "a?ba?":
- matches filenames "aabaa", "abba.", "a.ba9" and "a.ba."; - does not match filenames "aaba", "abaab", "aabaaa" and "aabaa.".
Help Polycarp find a pattern which matches files to be deleted and only them or report if there is no such pattern.
Input Specification:
The first line of the input contains two integers *n* and *m* (1<=≤<=*m*<=≤<=*n*<=≤<=100) — the total number of files and the number of files to be deleted.
The following *n* lines contain filenames, single filename per line. All filenames are non-empty strings containing only lowercase English letters, digits and dots ('.'). The length of each filename doesn't exceed 100. It is guaranteed that all filenames are distinct.
The last line of the input contains *m* distinct integer numbers in ascending order *a*1,<=*a*2,<=...,<=*a**m* (1<=≤<=*a**i*<=≤<=*n*) — indices of files to be deleted. All files are indexed from 1 to *n* in order of their appearance in the input.
Output Specification:
If the required pattern exists, print "Yes" in the first line of the output. The second line should contain the required pattern. If there are multiple solutions, print any of them.
If the required pattern doesn't exist, print the only line containing "No".
Demo Input:
['3 2\nab\nac\ncd\n1 2\n', '5 3\ntest\ntezt\ntest.\n.est\ntes.\n1 4 5\n', '4 4\na\nb\nc\ndd\n1 2 3 4\n', '6 3\n.svn\n.git\n....\n...\n..\n.\n1 2 3\n']
Demo Output:
['Yes\na?\n', 'Yes\n?es?\n', 'No\n', 'Yes\n.???\n']
Note:
none | ```python
num_file,num_delete = map(int, input().split())
list_file = []
for i in range(num_file):
list_file.append(input())
delete_file = [int(i)-1 for i in input().split()]
ans=""
tmp = list(list_file[delete_file[0]])
for i in delete_file[1:]:
name = list(list_file[i])
for j in range(len(tmp)):
if name[j] != tmp[j]:
tmp[j] = "?"
if tmp == ['?']:
print("No")
else:
print("Yes")
for c in tmp:
print(c,end="")
``` | 0 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*. | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,586,775,748 | 2,147,483,647 | PyPy 3 | OK | TESTS | 40 | 140 | 0 | def find(needle, haystack):
if not needle: return True
if needle[0] not in haystack:
return False
return find(needle[1:], haystack[haystack.find(needle[0])+1:])
if find("hello", input()):
print("YES")
else:
print("NO") | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*.
Input Specification:
The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters.
Output Specification:
If Vasya managed to say hello, print "YES", otherwise print "NO".
Demo Input:
['ahhellllloou\n', 'hlelo\n']
Demo Output:
['YES\n', 'NO\n']
Note:
none | ```python
def find(needle, haystack):
if not needle: return True
if needle[0] not in haystack:
return False
return find(needle[1:], haystack[haystack.find(needle[0])+1:])
if find("hello", input()):
print("YES")
else:
print("NO")
``` | 3.93 |
633 | C | Spy Syndrome 2 | PROGRAMMING | 1,900 | [
"data structures",
"dp",
"hashing",
"implementation",
"sortings",
"string suffix structures",
"strings"
] | null | null | After observing the results of Spy Syndrome, Yash realised the errors of his ways. He now believes that a super spy such as Siddhant can't use a cipher as basic and ancient as Caesar cipher. After many weeks of observation of Siddhant’s sentences, Yash determined a new cipher technique.
For a given sentence, the cipher is processed as:
1. Convert all letters of the sentence to lowercase. 1. Reverse each of the words of the sentence individually. 1. Remove all the spaces in the sentence.
For example, when this cipher is applied to the sentence
Kira is childish and he hates losing
the resulting string is
ariksihsidlihcdnaehsetahgnisol
Now Yash is given some ciphered string and a list of words. Help him to find out any original sentence composed using only words from the list. Note, that any of the given words could be used in the sentence multiple times. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=10<=000) — the length of the ciphered text. The second line consists of *n* lowercase English letters — the ciphered text *t*.
The third line contains a single integer *m* (1<=≤<=*m*<=≤<=100<=000) — the number of words which will be considered while deciphering the text. Each of the next *m* lines contains a non-empty word *w**i* (|*w**i*|<=≤<=1<=000) consisting of uppercase and lowercase English letters only. It's guaranteed that the total length of all words doesn't exceed 1<=000<=000. | Print one line — the original sentence. It is guaranteed that at least one solution exists. If there are multiple solutions, you may output any of those. | [
"30\nariksihsidlihcdnaehsetahgnisol\n10\nKira\nhates\nis\nhe\nlosing\ndeath\nchildish\nL\nand\nNote\n",
"12\niherehtolleh\n5\nHI\nHo\nthere\nHeLLo\nhello\n"
] | [
"Kira is childish and he hates losing \n",
"HI there HeLLo \n"
] | In sample case 2 there may be multiple accepted outputs, "HI there HeLLo" and "HI there hello" you may output any of them. | 1,500 | [
{
"input": "30\nariksihsidlihcdnaehsetahgnisol\n10\nKira\nhates\nis\nhe\nlosing\ndeath\nchildish\nL\nand\nNote",
"output": "Kira is childish and he hates losing "
},
{
"input": "12\niherehtolleh\n5\nHI\nHo\nthere\nHeLLo\nhello",
"output": "HI there HeLLo "
},
{
"input": "71\nbaaaaaaaaaaa... | 1,678,903,477 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 2 | 92 | 6,860,800 | # import sys
# sys.stdout=open('C:\Program Files (x86)\Sublime Text 3\cp_setup\output.txt','w')
# sys.stdin=open('C:\Program Files (x86)\Sublime Text 3\cp_setup\input.txt','r')
import heapq
import math
import collections
import bisect
mod=10**9+7
maxi=10**3
ppow=[0]*maxi
p=31
ppow[0]=1
for i in range(1,maxi):
ppow[i]=(ppow[i-1]*p)%mod
def hash(st):
st=st.lower()
hash1=0
for i in range(len(st)):
hash1=(hash1+(ord(st[i])-96)*ppow[i])%mod
return hash1
def solve(n,s,d):
res=[]
def findall(ind,curr,li):
if ind==n:
if curr==0:
res.append(li)
return True
return False
curr=(curr*p+ord(s[ind])-96)%mod
if curr in d:
if findall(ind+1,0,li+d[curr]+" "):
return True
return findall(ind+1,curr,li)
findall(0,0,"")
return res[0]
# t=int(input())
# for _ in range(t):
n=int(input())
s=input()
m=int(input())
d={}
for i in range(m):
name=input()
val=hash(name)
d[val]=name
print(solve(n,s,d)) | Title: Spy Syndrome 2
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After observing the results of Spy Syndrome, Yash realised the errors of his ways. He now believes that a super spy such as Siddhant can't use a cipher as basic and ancient as Caesar cipher. After many weeks of observation of Siddhant’s sentences, Yash determined a new cipher technique.
For a given sentence, the cipher is processed as:
1. Convert all letters of the sentence to lowercase. 1. Reverse each of the words of the sentence individually. 1. Remove all the spaces in the sentence.
For example, when this cipher is applied to the sentence
Kira is childish and he hates losing
the resulting string is
ariksihsidlihcdnaehsetahgnisol
Now Yash is given some ciphered string and a list of words. Help him to find out any original sentence composed using only words from the list. Note, that any of the given words could be used in the sentence multiple times.
Input Specification:
The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=10<=000) — the length of the ciphered text. The second line consists of *n* lowercase English letters — the ciphered text *t*.
The third line contains a single integer *m* (1<=≤<=*m*<=≤<=100<=000) — the number of words which will be considered while deciphering the text. Each of the next *m* lines contains a non-empty word *w**i* (|*w**i*|<=≤<=1<=000) consisting of uppercase and lowercase English letters only. It's guaranteed that the total length of all words doesn't exceed 1<=000<=000.
Output Specification:
Print one line — the original sentence. It is guaranteed that at least one solution exists. If there are multiple solutions, you may output any of those.
Demo Input:
['30\nariksihsidlihcdnaehsetahgnisol\n10\nKira\nhates\nis\nhe\nlosing\ndeath\nchildish\nL\nand\nNote\n', '12\niherehtolleh\n5\nHI\nHo\nthere\nHeLLo\nhello\n']
Demo Output:
['Kira is childish and he hates losing \n', 'HI there HeLLo \n']
Note:
In sample case 2 there may be multiple accepted outputs, "HI there HeLLo" and "HI there hello" you may output any of them. | ```python
# import sys
# sys.stdout=open('C:\Program Files (x86)\Sublime Text 3\cp_setup\output.txt','w')
# sys.stdin=open('C:\Program Files (x86)\Sublime Text 3\cp_setup\input.txt','r')
import heapq
import math
import collections
import bisect
mod=10**9+7
maxi=10**3
ppow=[0]*maxi
p=31
ppow[0]=1
for i in range(1,maxi):
ppow[i]=(ppow[i-1]*p)%mod
def hash(st):
st=st.lower()
hash1=0
for i in range(len(st)):
hash1=(hash1+(ord(st[i])-96)*ppow[i])%mod
return hash1
def solve(n,s,d):
res=[]
def findall(ind,curr,li):
if ind==n:
if curr==0:
res.append(li)
return True
return False
curr=(curr*p+ord(s[ind])-96)%mod
if curr in d:
if findall(ind+1,0,li+d[curr]+" "):
return True
return findall(ind+1,curr,li)
findall(0,0,"")
return res[0]
# t=int(input())
# for _ in range(t):
n=int(input())
s=input()
m=int(input())
d={}
for i in range(m):
name=input()
val=hash(name)
d[val]=name
print(solve(n,s,d))
``` | -1 | |
549 | A | Face Detection | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them.
In this problem an image is a rectangular table that consists of lowercase Latin letters. A face on the image is a 2<=×<=2 square, such that from the four letters of this square you can make word "face".
You need to write a program that determines the number of faces on the image. The squares that correspond to the faces can overlap. | The first line contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50) — the height and the width of the image, respectively.
Next *n* lines define the image. Each line contains *m* lowercase Latin letters. | In the single line print the number of faces on the image. | [
"4 4\nxxxx\nxfax\nxcex\nxxxx\n",
"4 2\nxx\ncf\nae\nxx\n",
"2 3\nfac\ncef\n",
"1 4\nface\n"
] | [
"1\n",
"1\n",
"2\n",
"0\n"
] | In the first sample the image contains a single face, located in a square with the upper left corner at the second line and the second column:
In the second sample the image also contains exactly one face, its upper left corner is at the second row and the first column.
In the third sample two faces are shown:
In the fourth sample the image has no faces on it. | 250 | [
{
"input": "4 4\nxxxx\nxfax\nxcex\nxxxx",
"output": "1"
},
{
"input": "4 2\nxx\ncf\nae\nxx",
"output": "1"
},
{
"input": "2 3\nfac\ncef",
"output": "2"
},
{
"input": "1 4\nface",
"output": "0"
},
{
"input": "5 5\nwmmwn\nlurcm\nkeetd\nfokon\ncxxgx",
"output": "... | 1,595,404,657 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 0 | 202 | 22,220,800 | n,m=map(int, input().split())
p=[]
for i in range (0,n):
l=list(map(str, input().split()))
p.append(l)
#del l[:]
l=[]
ans=[]
for i in range(n-1):
for j in range(m-1):
if p[i][j]!="x":
ans.append(p[i][j])
ans.append(p[i+1][j])
ans.append(p[i][j+1])
ans.append(p[i+1][j+1])
if ans.sort()=="acef":
print(1)
else:
print(0)
| Title: Face Detection
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The developers of Looksery have to write an efficient algorithm that detects faces on a picture. Unfortunately, they are currently busy preparing a contest for you, so you will have to do it for them.
In this problem an image is a rectangular table that consists of lowercase Latin letters. A face on the image is a 2<=×<=2 square, such that from the four letters of this square you can make word "face".
You need to write a program that determines the number of faces on the image. The squares that correspond to the faces can overlap.
Input Specification:
The first line contains two space-separated integers, *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50) — the height and the width of the image, respectively.
Next *n* lines define the image. Each line contains *m* lowercase Latin letters.
Output Specification:
In the single line print the number of faces on the image.
Demo Input:
['4 4\nxxxx\nxfax\nxcex\nxxxx\n', '4 2\nxx\ncf\nae\nxx\n', '2 3\nfac\ncef\n', '1 4\nface\n']
Demo Output:
['1\n', '1\n', '2\n', '0\n']
Note:
In the first sample the image contains a single face, located in a square with the upper left corner at the second line and the second column:
In the second sample the image also contains exactly one face, its upper left corner is at the second row and the first column.
In the third sample two faces are shown:
In the fourth sample the image has no faces on it. | ```python
n,m=map(int, input().split())
p=[]
for i in range (0,n):
l=list(map(str, input().split()))
p.append(l)
#del l[:]
l=[]
ans=[]
for i in range(n-1):
for j in range(m-1):
if p[i][j]!="x":
ans.append(p[i][j])
ans.append(p[i+1][j])
ans.append(p[i][j+1])
ans.append(p[i+1][j+1])
if ans.sort()=="acef":
print(1)
else:
print(0)
``` | -1 | |
208 | A | Dubstep | PROGRAMMING | 900 | [
"strings"
] | null | null | Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain number of words "WUB" before the first word of the song (the number may be zero), after the last word (the number may be zero), and between words (at least one between any pair of neighbouring words), and then the boy glues together all the words, including "WUB", in one string and plays the song at the club.
For example, a song with words "I AM X" can transform into a dubstep remix as "WUBWUBIWUBAMWUBWUBX" and cannot transform into "WUBWUBIAMWUBX".
Recently, Petya has heard Vasya's new dubstep track, but since he isn't into modern music, he decided to find out what was the initial song that Vasya remixed. Help Petya restore the original song. | The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the song had at least one word. | Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space. | [
"WUBWUBABCWUB\n",
"WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB\n"
] | [
"ABC ",
"WE ARE THE CHAMPIONS MY FRIEND "
] | In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE" and "THE" — between them Vasya added two "WUB". | 500 | [
{
"input": "WUBWUBABCWUB",
"output": "ABC "
},
{
"input": "WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB",
"output": "WE ARE THE CHAMPIONS MY FRIEND "
},
{
"input": "WUBWUBWUBSR",
"output": "SR "
},
{
"input": "RWUBWUBWUBLWUB",
"output": "R L "
},
{
"input": "... | 1,688,968,001 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 3 | 92 | 0 | a = input()
new_string = a.split("WUB")
#print(new_string)
del new_string[0]
final_string = ""
#print(new_string)
for stri in new_string:
final_string=final_string+stri+" "
print(final_string)
| Title: Dubstep
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain number of words "WUB" before the first word of the song (the number may be zero), after the last word (the number may be zero), and between words (at least one between any pair of neighbouring words), and then the boy glues together all the words, including "WUB", in one string and plays the song at the club.
For example, a song with words "I AM X" can transform into a dubstep remix as "WUBWUBIWUBAMWUBWUBX" and cannot transform into "WUBWUBIAMWUBX".
Recently, Petya has heard Vasya's new dubstep track, but since he isn't into modern music, he decided to find out what was the initial song that Vasya remixed. Help Petya restore the original song.
Input Specification:
The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the song had at least one word.
Output Specification:
Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space.
Demo Input:
['WUBWUBABCWUB\n', 'WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB\n']
Demo Output:
['ABC ', 'WE ARE THE CHAMPIONS MY FRIEND ']
Note:
In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE" and "THE" — between them Vasya added two "WUB". | ```python
a = input()
new_string = a.split("WUB")
#print(new_string)
del new_string[0]
final_string = ""
#print(new_string)
for stri in new_string:
final_string=final_string+stri+" "
print(final_string)
``` | 0 | |
810 | A | Straight <<A>> | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
In school, where Noora is studying, teachers are putting down marks to the online class register, which are integers from 1 to *k*. The worst mark is 1, the best is *k*. Mark that is going to the certificate, is calculated as an average of all the marks, rounded to the closest integer. If several answers are possible, rounding up is produced. For example, 7.3 is rounded to 7, but 7.5 and 7.8784 — to 8.
For instance, if Noora has marks [8,<=9], then the mark to the certificate is 9, because the average is equal to 8.5 and rounded to 9, but if the marks are [8,<=8,<=9], Noora will have graduation certificate with 8.
To graduate with «A» certificate, Noora has to have mark *k*.
Noora got *n* marks in register this year. However, she is afraid that her marks are not enough to get final mark *k*. Noora decided to ask for help in the internet, where hacker Leha immediately responded to her request. He is ready to hack class register for Noora and to add Noora any number of additional marks from 1 to *k*. At the same time, Leha want his hack be unseen to everyone, so he decided to add as less as possible additional marks. Please help Leha to calculate the minimal number of marks he has to add, so that final Noora's mark will become equal to *k*. | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*k*<=≤<=100) denoting the number of marks, received by Noora and the value of highest possible mark.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*k*) denoting marks received by Noora before Leha's hack. | Print a single integer — minimal number of additional marks, that Leha has to add in order to change Noora's final mark to *k*. | [
"2 10\n8 9\n",
"3 5\n4 4 4\n"
] | [
"4",
"3"
] | Consider the first example testcase.
Maximal mark is 10, Noora received two marks — 8 and 9, so current final mark is 9. To fix it, Leha can add marks [10, 10, 10, 10] (4 marks in total) to the registry, achieving Noora having average mark equal to <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/1b961585522f76271546da990a6228e7c666277f.png" style="max-width: 100.0%;max-height: 100.0%;"/>. Consequently, new final mark is 10. Less number of marks won't fix the situation.
In the second example Leha can add [5, 5, 5] to the registry, so that making average mark equal to 4.5, which is enough to have 5 in the certificate. | 500 | [
{
"input": "2 10\n8 9",
"output": "4"
},
{
"input": "3 5\n4 4 4",
"output": "3"
},
{
"input": "3 10\n10 8 9",
"output": "3"
},
{
"input": "2 23\n21 23",
"output": "2"
},
{
"input": "5 10\n5 10 10 9 10",
"output": "7"
},
{
"input": "12 50\n18 10 26 22 2... | 1,538,482,458 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 26 | 1,000 | 307,200 | n,k = map(int,input().split())
a = list(map(int,input().split()))
p = k - (1/2)
l = 0
while sum(a) / len(a) < p:
l += 1
a.append(k)
print(l) | Title: Straight <<A>>
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Noora is a student of one famous high school. It's her final year in school — she is going to study in university next year. However, she has to get an «A» graduation certificate in order to apply to a prestigious one.
In school, where Noora is studying, teachers are putting down marks to the online class register, which are integers from 1 to *k*. The worst mark is 1, the best is *k*. Mark that is going to the certificate, is calculated as an average of all the marks, rounded to the closest integer. If several answers are possible, rounding up is produced. For example, 7.3 is rounded to 7, but 7.5 and 7.8784 — to 8.
For instance, if Noora has marks [8,<=9], then the mark to the certificate is 9, because the average is equal to 8.5 and rounded to 9, but if the marks are [8,<=8,<=9], Noora will have graduation certificate with 8.
To graduate with «A» certificate, Noora has to have mark *k*.
Noora got *n* marks in register this year. However, she is afraid that her marks are not enough to get final mark *k*. Noora decided to ask for help in the internet, where hacker Leha immediately responded to her request. He is ready to hack class register for Noora and to add Noora any number of additional marks from 1 to *k*. At the same time, Leha want his hack be unseen to everyone, so he decided to add as less as possible additional marks. Please help Leha to calculate the minimal number of marks he has to add, so that final Noora's mark will become equal to *k*.
Input Specification:
The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*k*<=≤<=100) denoting the number of marks, received by Noora and the value of highest possible mark.
The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*k*) denoting marks received by Noora before Leha's hack.
Output Specification:
Print a single integer — minimal number of additional marks, that Leha has to add in order to change Noora's final mark to *k*.
Demo Input:
['2 10\n8 9\n', '3 5\n4 4 4\n']
Demo Output:
['4', '3']
Note:
Consider the first example testcase.
Maximal mark is 10, Noora received two marks — 8 and 9, so current final mark is 9. To fix it, Leha can add marks [10, 10, 10, 10] (4 marks in total) to the registry, achieving Noora having average mark equal to <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/1b961585522f76271546da990a6228e7c666277f.png" style="max-width: 100.0%;max-height: 100.0%;"/>. Consequently, new final mark is 10. Less number of marks won't fix the situation.
In the second example Leha can add [5, 5, 5] to the registry, so that making average mark equal to 4.5, which is enough to have 5 in the certificate. | ```python
n,k = map(int,input().split())
a = list(map(int,input().split()))
p = k - (1/2)
l = 0
while sum(a) / len(a) < p:
l += 1
a.append(k)
print(l)
``` | 0 | |
653 | A | Bear and Three Balls | PROGRAMMING | 900 | [
"brute force",
"implementation",
"sortings"
] | null | null | Limak is a little polar bear. He has *n* balls, the *i*-th ball has size *t**i*.
Limak wants to give one ball to each of his three friends. Giving gifts isn't easy — there are two rules Limak must obey to make friends happy:
- No two friends can get balls of the same size. - No two friends can get balls of sizes that differ by more than 2.
For example, Limak can choose balls with sizes 4, 5 and 3, or balls with sizes 90, 91 and 92. But he can't choose balls with sizes 5, 5 and 6 (two friends would get balls of the same size), and he can't choose balls with sizes 30, 31 and 33 (because sizes 30 and 33 differ by more than 2).
Your task is to check whether Limak can choose three balls that satisfy conditions above. | The first line of the input contains one integer *n* (3<=≤<=*n*<=≤<=50) — the number of balls Limak has.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=1000) where *t**i* denotes the size of the *i*-th ball. | Print "YES" (without quotes) if Limak can choose three balls of distinct sizes, such that any two of them differ by no more than 2. Otherwise, print "NO" (without quotes). | [
"4\n18 55 16 17\n",
"6\n40 41 43 44 44 44\n",
"8\n5 972 3 4 1 4 970 971\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | In the first sample, there are 4 balls and Limak is able to choose three of them to satisfy the rules. He must must choose balls with sizes 18, 16 and 17.
In the second sample, there is no way to give gifts to three friends without breaking the rules.
In the third sample, there is even more than one way to choose balls:
1. Choose balls with sizes 3, 4 and 5. 1. Choose balls with sizes 972, 970, 971. | 500 | [
{
"input": "4\n18 55 16 17",
"output": "YES"
},
{
"input": "6\n40 41 43 44 44 44",
"output": "NO"
},
{
"input": "8\n5 972 3 4 1 4 970 971",
"output": "YES"
},
{
"input": "3\n959 747 656",
"output": "NO"
},
{
"input": "4\n1 2 2 3",
"output": "YES"
},
{
... | 1,651,259,560 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 46 | 512,000 | #Problema G
def insertionSort(arr):
for i in range(1, len(arr)):
key = arr[i]
j = i-1
while j >= 0 and key < arr[j] :
arr[j + 1] = arr[j]
j -= 1
arr[j + 1] = key
a = int(input())
b = str(input())
n = b.split()
for i in range (a):
n[i] = int(n[i])
insertionSort(n)
encontrado =0
if (a<3):
print("NO")
else:
for i in range (a-2):
c = n[i]
d = n[i+1]
e = n[i+2]
if (e-d == 1 and d-c == 1):
encontrado =1
if (encontrado == 0):
print("NO")
else:
print("YES")
| Title: Bear and Three Balls
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is a little polar bear. He has *n* balls, the *i*-th ball has size *t**i*.
Limak wants to give one ball to each of his three friends. Giving gifts isn't easy — there are two rules Limak must obey to make friends happy:
- No two friends can get balls of the same size. - No two friends can get balls of sizes that differ by more than 2.
For example, Limak can choose balls with sizes 4, 5 and 3, or balls with sizes 90, 91 and 92. But he can't choose balls with sizes 5, 5 and 6 (two friends would get balls of the same size), and he can't choose balls with sizes 30, 31 and 33 (because sizes 30 and 33 differ by more than 2).
Your task is to check whether Limak can choose three balls that satisfy conditions above.
Input Specification:
The first line of the input contains one integer *n* (3<=≤<=*n*<=≤<=50) — the number of balls Limak has.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=1000) where *t**i* denotes the size of the *i*-th ball.
Output Specification:
Print "YES" (without quotes) if Limak can choose three balls of distinct sizes, such that any two of them differ by no more than 2. Otherwise, print "NO" (without quotes).
Demo Input:
['4\n18 55 16 17\n', '6\n40 41 43 44 44 44\n', '8\n5 972 3 4 1 4 970 971\n']
Demo Output:
['YES\n', 'NO\n', 'YES\n']
Note:
In the first sample, there are 4 balls and Limak is able to choose three of them to satisfy the rules. He must must choose balls with sizes 18, 16 and 17.
In the second sample, there is no way to give gifts to three friends without breaking the rules.
In the third sample, there is even more than one way to choose balls:
1. Choose balls with sizes 3, 4 and 5. 1. Choose balls with sizes 972, 970, 971. | ```python
#Problema G
def insertionSort(arr):
for i in range(1, len(arr)):
key = arr[i]
j = i-1
while j >= 0 and key < arr[j] :
arr[j + 1] = arr[j]
j -= 1
arr[j + 1] = key
a = int(input())
b = str(input())
n = b.split()
for i in range (a):
n[i] = int(n[i])
insertionSort(n)
encontrado =0
if (a<3):
print("NO")
else:
for i in range (a-2):
c = n[i]
d = n[i+1]
e = n[i+2]
if (e-d == 1 and d-c == 1):
encontrado =1
if (encontrado == 0):
print("NO")
else:
print("YES")
``` | 0 | |
877 | B | Nikita and string | PROGRAMMING | 1,500 | [
"brute force",
"dp"
] | null | null | One day Nikita found the string containing letters "a" and "b" only.
Nikita thinks that string is beautiful if it can be cut into 3 strings (possibly empty) without changing the order of the letters, where the 1-st and the 3-rd one contain only letters "a" and the 2-nd contains only letters "b".
Nikita wants to make the string beautiful by removing some (possibly none) of its characters, but without changing their order. What is the maximum length of the string he can get? | The first line contains a non-empty string of length not greater than 5<=000 containing only lowercase English letters "a" and "b". | Print a single integer — the maximum possible size of beautiful string Nikita can get. | [
"abba\n",
"bab\n"
] | [
"4",
"2"
] | It the first sample the string is already beautiful.
In the second sample he needs to delete one of "b" to make it beautiful. | 1,000 | [
{
"input": "abba",
"output": "4"
},
{
"input": "bab",
"output": "2"
},
{
"input": "bbabbbaabbbb",
"output": "9"
},
{
"input": "bbabbbbbaaba",
"output": "10"
},
{
"input": "bbabbbababaa",
"output": "9"
},
{
"input": "aabbaababbab",
"output": "8"
}... | 1,510,080,596 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 46 | 0 | a=input()
n=len(a)
la=0
lb=0
fa=1
fb=0
f=0
asd=0
if (a[0]=='a'):
la=1
else:
lb=1
fb=1
asd=1
for i in range(1, n):
if (a[i]=='a'):
if (fb==1):
la=lb+1
else:
la=max(la+1, lb+1)
else:
if (f==0 and asd!=1):
f=1
lb=la+1
else:
lb=lb+1
print (max(la, lb)) | Title: Nikita and string
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Nikita found the string containing letters "a" and "b" only.
Nikita thinks that string is beautiful if it can be cut into 3 strings (possibly empty) without changing the order of the letters, where the 1-st and the 3-rd one contain only letters "a" and the 2-nd contains only letters "b".
Nikita wants to make the string beautiful by removing some (possibly none) of its characters, but without changing their order. What is the maximum length of the string he can get?
Input Specification:
The first line contains a non-empty string of length not greater than 5<=000 containing only lowercase English letters "a" and "b".
Output Specification:
Print a single integer — the maximum possible size of beautiful string Nikita can get.
Demo Input:
['abba\n', 'bab\n']
Demo Output:
['4', '2']
Note:
It the first sample the string is already beautiful.
In the second sample he needs to delete one of "b" to make it beautiful. | ```python
a=input()
n=len(a)
la=0
lb=0
fa=1
fb=0
f=0
asd=0
if (a[0]=='a'):
la=1
else:
lb=1
fb=1
asd=1
for i in range(1, n):
if (a[i]=='a'):
if (fb==1):
la=lb+1
else:
la=max(la+1, lb+1)
else:
if (f==0 and asd!=1):
f=1
lb=la+1
else:
lb=lb+1
print (max(la, lb))
``` | 0 | |
165 | A | Supercentral Point | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | One day Vasya painted a Cartesian coordinate system on a piece of paper and marked some set of points (*x*1,<=*y*1),<=(*x*2,<=*y*2),<=...,<=(*x**n*,<=*y**n*). Let's define neighbors for some fixed point from the given set (*x*,<=*y*):
- point (*x*',<=*y*') is (*x*,<=*y*)'s right neighbor, if *x*'<=><=*x* and *y*'<==<=*y* - point (*x*',<=*y*') is (*x*,<=*y*)'s left neighbor, if *x*'<=<<=*x* and *y*'<==<=*y* - point (*x*',<=*y*') is (*x*,<=*y*)'s lower neighbor, if *x*'<==<=*x* and *y*'<=<<=*y* - point (*x*',<=*y*') is (*x*,<=*y*)'s upper neighbor, if *x*'<==<=*x* and *y*'<=><=*y*
We'll consider point (*x*,<=*y*) from the given set supercentral, if it has at least one upper, at least one lower, at least one left and at least one right neighbor among this set's points.
Vasya marked quite many points on the paper. Analyzing the picture manually is rather a challenge, so Vasya asked you to help him. Your task is to find the number of supercentral points in the given set. | The first input line contains the only integer *n* (1<=≤<=*n*<=≤<=200) — the number of points in the given set. Next *n* lines contain the coordinates of the points written as "*x* *y*" (without the quotes) (|*x*|,<=|*y*|<=≤<=1000), all coordinates are integers. The numbers in the line are separated by exactly one space. It is guaranteed that all points are different. | Print the only number — the number of supercentral points of the given set. | [
"8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3\n",
"5\n0 0\n0 1\n1 0\n0 -1\n-1 0\n"
] | [
"2\n",
"1\n"
] | In the first sample the supercentral points are only points (1, 1) and (1, 2).
In the second sample there is one supercental point — point (0, 0). | 500 | [
{
"input": "8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3",
"output": "2"
},
{
"input": "5\n0 0\n0 1\n1 0\n0 -1\n-1 0",
"output": "1"
},
{
"input": "9\n-565 -752\n-184 723\n-184 -752\n-184 1\n950 723\n-565 723\n950 -752\n950 1\n-565 1",
"output": "1"
},
{
"input": "25\n-651 897\n... | 1,645,738,298 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 26 | 124 | 2,969,600 | r=lambda:[*map(int,input().split())]
l=list(r()for _ in' '*int(input()))
cm=lambda a,b:(a>b)-(a<b)
p=sum(len({(cm(a,x),cm(b,y))for a,b in l if(a==x or b==y)})>4 for x,y in l)
print(p)
| Title: Supercentral Point
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Vasya painted a Cartesian coordinate system on a piece of paper and marked some set of points (*x*1,<=*y*1),<=(*x*2,<=*y*2),<=...,<=(*x**n*,<=*y**n*). Let's define neighbors for some fixed point from the given set (*x*,<=*y*):
- point (*x*',<=*y*') is (*x*,<=*y*)'s right neighbor, if *x*'<=><=*x* and *y*'<==<=*y* - point (*x*',<=*y*') is (*x*,<=*y*)'s left neighbor, if *x*'<=<<=*x* and *y*'<==<=*y* - point (*x*',<=*y*') is (*x*,<=*y*)'s lower neighbor, if *x*'<==<=*x* and *y*'<=<<=*y* - point (*x*',<=*y*') is (*x*,<=*y*)'s upper neighbor, if *x*'<==<=*x* and *y*'<=><=*y*
We'll consider point (*x*,<=*y*) from the given set supercentral, if it has at least one upper, at least one lower, at least one left and at least one right neighbor among this set's points.
Vasya marked quite many points on the paper. Analyzing the picture manually is rather a challenge, so Vasya asked you to help him. Your task is to find the number of supercentral points in the given set.
Input Specification:
The first input line contains the only integer *n* (1<=≤<=*n*<=≤<=200) — the number of points in the given set. Next *n* lines contain the coordinates of the points written as "*x* *y*" (without the quotes) (|*x*|,<=|*y*|<=≤<=1000), all coordinates are integers. The numbers in the line are separated by exactly one space. It is guaranteed that all points are different.
Output Specification:
Print the only number — the number of supercentral points of the given set.
Demo Input:
['8\n1 1\n4 2\n3 1\n1 2\n0 2\n0 1\n1 0\n1 3\n', '5\n0 0\n0 1\n1 0\n0 -1\n-1 0\n']
Demo Output:
['2\n', '1\n']
Note:
In the first sample the supercentral points are only points (1, 1) and (1, 2).
In the second sample there is one supercental point — point (0, 0). | ```python
r=lambda:[*map(int,input().split())]
l=list(r()for _ in' '*int(input()))
cm=lambda a,b:(a>b)-(a<b)
p=sum(len({(cm(a,x),cm(b,y))for a,b in l if(a==x or b==y)})>4 for x,y in l)
print(p)
``` | 3 | |
32 | A | Reconnaissance | PROGRAMMING | 800 | [
"brute force"
] | A. Reconnaissance | 2 | 256 | According to the regulations of Berland's army, a reconnaissance unit should consist of exactly two soldiers. Since these two soldiers shouldn't differ much, their heights can differ by at most *d* centimeters. Captain Bob has *n* soldiers in his detachment. Their heights are *a*1,<=*a*2,<=...,<=*a**n* centimeters. Some soldiers are of the same height. Bob wants to know, how many ways exist to form a reconnaissance unit of two soldiers from his detachment.
Ways (1,<=2) and (2,<=1) should be regarded as different. | The first line contains two integers *n* and *d* (1<=≤<=*n*<=≤<=1000,<=1<=≤<=*d*<=≤<=109) — amount of soldiers in Bob's detachment and the maximum allowed height difference respectively. The second line contains *n* space-separated integers — heights of all the soldiers in Bob's detachment. These numbers don't exceed 109. | Output one number — amount of ways to form a reconnaissance unit of two soldiers, whose height difference doesn't exceed *d*. | [
"5 10\n10 20 50 60 65\n",
"5 1\n55 30 29 31 55\n"
] | [
"6\n",
"6\n"
] | none | 500 | [
{
"input": "5 10\n10 20 50 60 65",
"output": "6"
},
{
"input": "5 1\n55 30 29 31 55",
"output": "6"
},
{
"input": "6 10\n4 6 4 1 9 3",
"output": "30"
},
{
"input": "7 100\n19 1694 261 162 1 234 513",
"output": "8"
},
{
"input": "8 42\n37 53 74 187 568 22 5 65",
... | 1,640,929,674 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 966 | 0 | n, d =map( int ,input().split())
l=[int(i) for i in input().split(" ")]
x=0
for i in range(len(l)):
for j in range(len(l)):
if i!=j and abs(l[i]-l[j]) <= d:
x+=1
print(x) | Title: Reconnaissance
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
According to the regulations of Berland's army, a reconnaissance unit should consist of exactly two soldiers. Since these two soldiers shouldn't differ much, their heights can differ by at most *d* centimeters. Captain Bob has *n* soldiers in his detachment. Their heights are *a*1,<=*a*2,<=...,<=*a**n* centimeters. Some soldiers are of the same height. Bob wants to know, how many ways exist to form a reconnaissance unit of two soldiers from his detachment.
Ways (1,<=2) and (2,<=1) should be regarded as different.
Input Specification:
The first line contains two integers *n* and *d* (1<=≤<=*n*<=≤<=1000,<=1<=≤<=*d*<=≤<=109) — amount of soldiers in Bob's detachment and the maximum allowed height difference respectively. The second line contains *n* space-separated integers — heights of all the soldiers in Bob's detachment. These numbers don't exceed 109.
Output Specification:
Output one number — amount of ways to form a reconnaissance unit of two soldiers, whose height difference doesn't exceed *d*.
Demo Input:
['5 10\n10 20 50 60 65\n', '5 1\n55 30 29 31 55\n']
Demo Output:
['6\n', '6\n']
Note:
none | ```python
n, d =map( int ,input().split())
l=[int(i) for i in input().split(" ")]
x=0
for i in range(len(l)):
for j in range(len(l)):
if i!=j and abs(l[i]-l[j]) <= d:
x+=1
print(x)
``` | 3.7585 |
617 | A | Elephant | PROGRAMMING | 800 | [
"math"
] | null | null | An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make in order to get to his friend's house. | The first line of the input contains an integer *x* (1<=≤<=*x*<=≤<=1<=000<=000) — The coordinate of the friend's house. | Print the minimum number of steps that elephant needs to make to get from point 0 to point *x*. | [
"5\n",
"12\n"
] | [
"1\n",
"3\n"
] | In the first sample the elephant needs to make one step of length 5 to reach the point *x*.
In the second sample the elephant can get to point *x* if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach *x* in less than three moves. | 500 | [
{
"input": "5",
"output": "1"
},
{
"input": "12",
"output": "3"
},
{
"input": "999999",
"output": "200000"
},
{
"input": "41",
"output": "9"
},
{
"input": "1000000",
"output": "200000"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
... | 1,694,085,900 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 46 | 0 | def min_steps_to_reach(x):
steps = x // 5
if x % 5 != 0:
steps += 1
return steps
x = int(input())
result = min_steps_to_reach(x)
print(result)
| Title: Elephant
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point *x*(*x*<=><=0) of the coordinate line. In one step the elephant can move 1, 2, 3, 4 or 5 positions forward. Determine, what is the minimum number of steps he need to make in order to get to his friend's house.
Input Specification:
The first line of the input contains an integer *x* (1<=≤<=*x*<=≤<=1<=000<=000) — The coordinate of the friend's house.
Output Specification:
Print the minimum number of steps that elephant needs to make to get from point 0 to point *x*.
Demo Input:
['5\n', '12\n']
Demo Output:
['1\n', '3\n']
Note:
In the first sample the elephant needs to make one step of length 5 to reach the point *x*.
In the second sample the elephant can get to point *x* if he moves by 3, 5 and 4. There are other ways to get the optimal answer but the elephant cannot reach *x* in less than three moves. | ```python
def min_steps_to_reach(x):
steps = x // 5
if x % 5 != 0:
steps += 1
return steps
x = int(input())
result = min_steps_to_reach(x)
print(result)
``` | 3 | |
625 | B | War of the Corporations | PROGRAMMING | 1,200 | [
"constructive algorithms",
"greedy",
"strings"
] | null | null | A long time ago, in a galaxy far far away two giant IT-corporations Pineapple and Gogol continue their fierce competition. Crucial moment is just around the corner: Gogol is ready to release it's new tablet Lastus 3000.
This new device is equipped with specially designed artificial intelligence (AI). Employees of Pineapple did their best to postpone the release of Lastus 3000 as long as possible. Finally, they found out, that the name of the new artificial intelligence is similar to the name of the phone, that Pineapple released 200 years ago. As all rights on its name belong to Pineapple, they stand on changing the name of Gogol's artificial intelligence.
Pineapple insists, that the name of their phone occurs in the name of AI as a substring. Because the name of technology was already printed on all devices, the Gogol's director decided to replace some characters in AI name with "#". As this operation is pretty expensive, you should find the minimum number of characters to replace with "#", such that the name of AI doesn't contain the name of the phone as a substring.
Substring is a continuous subsequence of a string. | The first line of the input contains the name of AI designed by Gogol, its length doesn't exceed 100<=000 characters. Second line contains the name of the phone released by Pineapple 200 years ago, its length doesn't exceed 30. Both string are non-empty and consist of only small English letters. | Print the minimum number of characters that must be replaced with "#" in order to obtain that the name of the phone doesn't occur in the name of AI as a substring. | [
"intellect\ntell\n",
"google\napple\n",
"sirisiri\nsir\n"
] | [
"1",
"0",
"2"
] | In the first sample AI's name may be replaced with "int#llect".
In the second sample Gogol can just keep things as they are.
In the third sample one of the new possible names of AI may be "s#ris#ri". | 750 | [
{
"input": "intellect\ntell",
"output": "1"
},
{
"input": "google\napple",
"output": "0"
},
{
"input": "sirisiri\nsir",
"output": "2"
},
{
"input": "sirisiri\nsiri",
"output": "2"
},
{
"input": "aaaaaaa\naaaa",
"output": "1"
},
{
"input": "bbbbbb\nbb",... | 1,454,841,342 | 5,442 | Python 3 | OK | TESTS | 56 | 62 | 307,200 | a = str(input())
b = str(input())
print(a.count(b))
| Title: War of the Corporations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A long time ago, in a galaxy far far away two giant IT-corporations Pineapple and Gogol continue their fierce competition. Crucial moment is just around the corner: Gogol is ready to release it's new tablet Lastus 3000.
This new device is equipped with specially designed artificial intelligence (AI). Employees of Pineapple did their best to postpone the release of Lastus 3000 as long as possible. Finally, they found out, that the name of the new artificial intelligence is similar to the name of the phone, that Pineapple released 200 years ago. As all rights on its name belong to Pineapple, they stand on changing the name of Gogol's artificial intelligence.
Pineapple insists, that the name of their phone occurs in the name of AI as a substring. Because the name of technology was already printed on all devices, the Gogol's director decided to replace some characters in AI name with "#". As this operation is pretty expensive, you should find the minimum number of characters to replace with "#", such that the name of AI doesn't contain the name of the phone as a substring.
Substring is a continuous subsequence of a string.
Input Specification:
The first line of the input contains the name of AI designed by Gogol, its length doesn't exceed 100<=000 characters. Second line contains the name of the phone released by Pineapple 200 years ago, its length doesn't exceed 30. Both string are non-empty and consist of only small English letters.
Output Specification:
Print the minimum number of characters that must be replaced with "#" in order to obtain that the name of the phone doesn't occur in the name of AI as a substring.
Demo Input:
['intellect\ntell\n', 'google\napple\n', 'sirisiri\nsir\n']
Demo Output:
['1', '0', '2']
Note:
In the first sample AI's name may be replaced with "int#llect".
In the second sample Gogol can just keep things as they are.
In the third sample one of the new possible names of AI may be "s#ris#ri". | ```python
a = str(input())
b = str(input())
print(a.count(b))
``` | 3 | |
104 | A | Blackjack | PROGRAMMING | 800 | [
"implementation"
] | A. Blackjack | 2 | 256 | One rainy gloomy evening when all modules hid in the nearby cafes to drink hot energetic cocktails, the Hexadecimal virus decided to fly over the Mainframe to look for a Great Idea. And she has found one!
Why not make her own Codeforces, with blackjack and other really cool stuff? Many people will surely be willing to visit this splendid shrine of high culture.
In Mainframe a standard pack of 52 cards is used to play blackjack. The pack contains cards of 13 values: 2, 3, 4, 5, 6, 7, 8, 9, 10, jacks, queens, kings and aces. Each value also exists in one of four suits: hearts, diamonds, clubs and spades. Also, each card earns some value in points assigned to it: cards with value from two to ten earn from 2 to 10 points, correspondingly. An ace can either earn 1 or 11, whatever the player wishes. The picture cards (king, queen and jack) earn 10 points. The number of points a card earns does not depend on the suit. The rules of the game are very simple. The player gets two cards, if the sum of points of those cards equals *n*, then the player wins, otherwise the player loses.
The player has already got the first card, it's the queen of spades. To evaluate chances for victory, you should determine how many ways there are to get the second card so that the sum of points exactly equals *n*. | The only line contains *n* (1<=≤<=*n*<=≤<=25) — the required sum of points. | Print the numbers of ways to get the second card in the required way if the first card is the queen of spades. | [
"12\n",
"20\n",
"10\n"
] | [
"4",
"15",
"0"
] | In the first sample only four two's of different suits can earn the required sum of points.
In the second sample we can use all tens, jacks, queens and kings; overall it's 15 cards, as the queen of spades (as any other card) is only present once in the pack of cards and it's already in use.
In the third sample there is no card, that would add a zero to the current ten points. | 500 | [
{
"input": "12",
"output": "4"
},
{
"input": "20",
"output": "15"
},
{
"input": "10",
"output": "0"
},
{
"input": "11",
"output": "4"
},
{
"input": "15",
"output": "4"
},
{
"input": "18",
"output": "4"
},
{
"input": "25",
"output": "0"
... | 1,594,096,149 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 22 | 278 | 20,172,800 | n=int(input())
c=n-10
if c<=0:
print('0')
exit(0)
elif c>10:
print('0')
exit(0)
elif c==10:
print('15')
exit(0)
else:
print('4')
| Title: Blackjack
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One rainy gloomy evening when all modules hid in the nearby cafes to drink hot energetic cocktails, the Hexadecimal virus decided to fly over the Mainframe to look for a Great Idea. And she has found one!
Why not make her own Codeforces, with blackjack and other really cool stuff? Many people will surely be willing to visit this splendid shrine of high culture.
In Mainframe a standard pack of 52 cards is used to play blackjack. The pack contains cards of 13 values: 2, 3, 4, 5, 6, 7, 8, 9, 10, jacks, queens, kings and aces. Each value also exists in one of four suits: hearts, diamonds, clubs and spades. Also, each card earns some value in points assigned to it: cards with value from two to ten earn from 2 to 10 points, correspondingly. An ace can either earn 1 or 11, whatever the player wishes. The picture cards (king, queen and jack) earn 10 points. The number of points a card earns does not depend on the suit. The rules of the game are very simple. The player gets two cards, if the sum of points of those cards equals *n*, then the player wins, otherwise the player loses.
The player has already got the first card, it's the queen of spades. To evaluate chances for victory, you should determine how many ways there are to get the second card so that the sum of points exactly equals *n*.
Input Specification:
The only line contains *n* (1<=≤<=*n*<=≤<=25) — the required sum of points.
Output Specification:
Print the numbers of ways to get the second card in the required way if the first card is the queen of spades.
Demo Input:
['12\n', '20\n', '10\n']
Demo Output:
['4', '15', '0']
Note:
In the first sample only four two's of different suits can earn the required sum of points.
In the second sample we can use all tens, jacks, queens and kings; overall it's 15 cards, as the queen of spades (as any other card) is only present once in the pack of cards and it's already in use.
In the third sample there is no card, that would add a zero to the current ten points. | ```python
n=int(input())
c=n-10
if c<=0:
print('0')
exit(0)
elif c>10:
print('0')
exit(0)
elif c==10:
print('15')
exit(0)
else:
print('4')
``` | 0 |
825 | A | Binary Protocol | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Polycarp has just invented a new binary protocol for data transmission. He is encoding positive integer decimal number to binary string using following algorithm:
- Each digit is represented with number of '1' characters equal to the value of that digit (for 0 it is zero ones). - Digits are written one by one in order corresponding to number and separated by single '0' character.
Though Polycarp learnt how to encode the numbers, he has no idea how to decode them back. Help him calculate the decoded number. | The first line contains one integer number *n* (1<=≤<=*n*<=≤<=89) — length of the string *s*.
The second line contains string *s* — sequence of '0' and '1' characters, number in its encoded format. It is guaranteed that the number corresponding to the string is positive and doesn't exceed 109. The string always starts with '1'. | Print the decoded number. | [
"3\n111\n",
"9\n110011101\n"
] | [
"3\n",
"2031\n"
] | none | 0 | [
{
"input": "3\n111",
"output": "3"
},
{
"input": "9\n110011101",
"output": "2031"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "3\n100",
"output": "100"
},
{
"input": "5\n10001",
"output": "1001"
},
{
"input": "14\n11001100011000",
"output": "... | 1,587,125,080 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 2 | 202 | 2,048,000 | n=int(input())
s=input()
c=0
r=''
for i in range(n-1):
if(s[0]=='0'):
c=0
elif(s[i]=='1'):
c=c+1
elif(s[i-1]=='1' and s[i]=='0'):
r=r+str(c)
c=0
elif(s[i-1]=='0' and s[i]=='0'):
r=r+'0'
c=0
if(s[-1]=='1' and s[-2]=='0'):
r=r+'1'
elif(s[-1]=='1' and s[-2]=='1'):
c=c+1
r=r+str(c)
print(r)
| Title: Binary Protocol
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp has just invented a new binary protocol for data transmission. He is encoding positive integer decimal number to binary string using following algorithm:
- Each digit is represented with number of '1' characters equal to the value of that digit (for 0 it is zero ones). - Digits are written one by one in order corresponding to number and separated by single '0' character.
Though Polycarp learnt how to encode the numbers, he has no idea how to decode them back. Help him calculate the decoded number.
Input Specification:
The first line contains one integer number *n* (1<=≤<=*n*<=≤<=89) — length of the string *s*.
The second line contains string *s* — sequence of '0' and '1' characters, number in its encoded format. It is guaranteed that the number corresponding to the string is positive and doesn't exceed 109. The string always starts with '1'.
Output Specification:
Print the decoded number.
Demo Input:
['3\n111\n', '9\n110011101\n']
Demo Output:
['3\n', '2031\n']
Note:
none | ```python
n=int(input())
s=input()
c=0
r=''
for i in range(n-1):
if(s[0]=='0'):
c=0
elif(s[i]=='1'):
c=c+1
elif(s[i-1]=='1' and s[i]=='0'):
r=r+str(c)
c=0
elif(s[i-1]=='0' and s[i]=='0'):
r=r+'0'
c=0
if(s[-1]=='1' and s[-2]=='0'):
r=r+'1'
elif(s[-1]=='1' and s[-2]=='1'):
c=c+1
r=r+str(c)
print(r)
``` | -1 | |
813 | B | The Golden Age | PROGRAMMING | 1,800 | [
"brute force",
"math"
] | null | null | Unlucky year in Berland is such a year that its number *n* can be represented as *n*<==<=*x**a*<=+<=*y**b*, where *a* and *b* are non-negative integer numbers.
For example, if *x*<==<=2 and *y*<==<=3 then the years 4 and 17 are unlucky (4<==<=20<=+<=31, 17<==<=23<=+<=32<==<=24<=+<=30) and year 18 isn't unlucky as there is no such representation for it.
Such interval of years that there are no unlucky years in it is called The Golden Age.
You should write a program which will find maximum length of The Golden Age which starts no earlier than the year *l* and ends no later than the year *r*. If all years in the interval [*l*,<=*r*] are unlucky then the answer is 0. | The first line contains four integer numbers *x*, *y*, *l* and *r* (2<=≤<=*x*,<=*y*<=≤<=1018, 1<=≤<=*l*<=≤<=*r*<=≤<=1018). | Print the maximum length of The Golden Age within the interval [*l*,<=*r*].
If all years in the interval [*l*,<=*r*] are unlucky then print 0. | [
"2 3 1 10\n",
"3 5 10 22\n",
"2 3 3 5\n"
] | [
"1\n",
"8\n",
"0\n"
] | In the first example the unlucky years are 2, 3, 4, 5, 7, 9 and 10. So maximum length of The Golden Age is achived in the intervals [1, 1], [6, 6] and [8, 8].
In the second example the longest Golden Age is the interval [15, 22]. | 0 | [
{
"input": "2 3 1 10",
"output": "1"
},
{
"input": "3 5 10 22",
"output": "8"
},
{
"input": "2 3 3 5",
"output": "0"
},
{
"input": "2 2 1 10",
"output": "1"
},
{
"input": "2 2 1 1000000",
"output": "213568"
},
{
"input": "2 2 1 1000000000000000000",
... | 1,496,678,024 | 2,924 | Python 3 | OK | TESTS | 85 | 62 | 307,200 | def parser():
while 1:
data = list(input().split(' '))
for number in data:
if len(number) > 0:
yield(number)
input_parser = parser()
def get_word():
global input_parser
return next(input_parser)
def get_number():
data = get_word()
try:
return int(data)
except ValueError:
return float(data)
x = get_number()
y = get_number()
l = get_number()
r = get_number()
n1 = 1;
a = list()
a.append(l - 1)
for i in range(0, 300):
if n1 > r:
break
n2 = 1
for j in range(0, 300):
if n1 + n2 > r:
break
if n1 + n2 >= l and n1 + n2 <= r:
a.append(n1 + n2)
n2 = n2 * y
n1 = n1 * x
a.append(r + 1)
a.sort()
ans = 0
for i in range(0, len(a) - 1):
ans = max(ans, a[i + 1] - a[i] - 1)
print(ans) | Title: The Golden Age
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Unlucky year in Berland is such a year that its number *n* can be represented as *n*<==<=*x**a*<=+<=*y**b*, where *a* and *b* are non-negative integer numbers.
For example, if *x*<==<=2 and *y*<==<=3 then the years 4 and 17 are unlucky (4<==<=20<=+<=31, 17<==<=23<=+<=32<==<=24<=+<=30) and year 18 isn't unlucky as there is no such representation for it.
Such interval of years that there are no unlucky years in it is called The Golden Age.
You should write a program which will find maximum length of The Golden Age which starts no earlier than the year *l* and ends no later than the year *r*. If all years in the interval [*l*,<=*r*] are unlucky then the answer is 0.
Input Specification:
The first line contains four integer numbers *x*, *y*, *l* and *r* (2<=≤<=*x*,<=*y*<=≤<=1018, 1<=≤<=*l*<=≤<=*r*<=≤<=1018).
Output Specification:
Print the maximum length of The Golden Age within the interval [*l*,<=*r*].
If all years in the interval [*l*,<=*r*] are unlucky then print 0.
Demo Input:
['2 3 1 10\n', '3 5 10 22\n', '2 3 3 5\n']
Demo Output:
['1\n', '8\n', '0\n']
Note:
In the first example the unlucky years are 2, 3, 4, 5, 7, 9 and 10. So maximum length of The Golden Age is achived in the intervals [1, 1], [6, 6] and [8, 8].
In the second example the longest Golden Age is the interval [15, 22]. | ```python
def parser():
while 1:
data = list(input().split(' '))
for number in data:
if len(number) > 0:
yield(number)
input_parser = parser()
def get_word():
global input_parser
return next(input_parser)
def get_number():
data = get_word()
try:
return int(data)
except ValueError:
return float(data)
x = get_number()
y = get_number()
l = get_number()
r = get_number()
n1 = 1;
a = list()
a.append(l - 1)
for i in range(0, 300):
if n1 > r:
break
n2 = 1
for j in range(0, 300):
if n1 + n2 > r:
break
if n1 + n2 >= l and n1 + n2 <= r:
a.append(n1 + n2)
n2 = n2 * y
n1 = n1 * x
a.append(r + 1)
a.sort()
ans = 0
for i in range(0, len(a) - 1):
ans = max(ans, a[i + 1] - a[i] - 1)
print(ans)
``` | 3 | |
48 | A | Rock-paper-scissors | PROGRAMMING | 900 | [
"implementation",
"schedules"
] | A. Rock-paper-scissors | 2 | 256 | Uncle Fyodor, Matroskin the Cat and Sharic the Dog live their simple but happy lives in Prostokvashino. Sometimes they receive parcels from Uncle Fyodor’s parents and sometimes from anonymous benefactors, in which case it is hard to determine to which one of them the package has been sent. A photographic rifle is obviously for Sharic who loves hunting and fish is for Matroskin, but for whom was a new video game console meant? Every one of the three friends claimed that the present is for him and nearly quarreled. Uncle Fyodor had an idea how to solve the problem justly: they should suppose that the console was sent to all three of them and play it in turns. Everybody got relieved but then yet another burning problem popped up — who will play first? This time Matroskin came up with a brilliant solution, suggesting the most fair way to find it out: play rock-paper-scissors together. The rules of the game are very simple. On the count of three every player shows a combination with his hand (or paw). The combination corresponds to one of three things: a rock, scissors or paper. Some of the gestures win over some other ones according to well-known rules: the rock breaks the scissors, the scissors cut the paper, and the paper gets wrapped over the stone. Usually there are two players. Yet there are three friends, that’s why they decided to choose the winner like that: If someone shows the gesture that wins over the other two players, then that player wins. Otherwise, another game round is required. Write a program that will determine the winner by the gestures they have shown. | The first input line contains the name of the gesture that Uncle Fyodor showed, the second line shows which gesture Matroskin showed and the third line shows Sharic’s gesture. | Print "F" (without quotes) if Uncle Fyodor wins. Print "M" if Matroskin wins and "S" if Sharic wins. If it is impossible to find the winner, print "?". | [
"rock\nrock\nrock\n",
"paper\nrock\nrock\n",
"scissors\nrock\nrock\n",
"scissors\npaper\nrock\n"
] | [
"?\n",
"F\n",
"?\n",
"?\n"
] | none | 0 | [
{
"input": "rock\nrock\nrock",
"output": "?"
},
{
"input": "paper\nrock\nrock",
"output": "F"
},
{
"input": "scissors\nrock\nrock",
"output": "?"
},
{
"input": "scissors\npaper\nrock",
"output": "?"
},
{
"input": "paper\npaper\nrock",
"output": "?"
},
{
... | 1,634,927,514 | 2,147,483,647 | Python 3 | OK | TESTS | 27 | 92 | 4,505,600 | F=input()
M=input()
S=input()
Beater={"paper":"scissors","scissors":"rock","rock":"paper"}
if S==Beater[F] and F==M:
print("S")
elif F==Beater[S] and S==M:
print("F")
elif M==Beater[F] and F==S:
print("M")
else:
print("?")
| Title: Rock-paper-scissors
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Uncle Fyodor, Matroskin the Cat and Sharic the Dog live their simple but happy lives in Prostokvashino. Sometimes they receive parcels from Uncle Fyodor’s parents and sometimes from anonymous benefactors, in which case it is hard to determine to which one of them the package has been sent. A photographic rifle is obviously for Sharic who loves hunting and fish is for Matroskin, but for whom was a new video game console meant? Every one of the three friends claimed that the present is for him and nearly quarreled. Uncle Fyodor had an idea how to solve the problem justly: they should suppose that the console was sent to all three of them and play it in turns. Everybody got relieved but then yet another burning problem popped up — who will play first? This time Matroskin came up with a brilliant solution, suggesting the most fair way to find it out: play rock-paper-scissors together. The rules of the game are very simple. On the count of three every player shows a combination with his hand (or paw). The combination corresponds to one of three things: a rock, scissors or paper. Some of the gestures win over some other ones according to well-known rules: the rock breaks the scissors, the scissors cut the paper, and the paper gets wrapped over the stone. Usually there are two players. Yet there are three friends, that’s why they decided to choose the winner like that: If someone shows the gesture that wins over the other two players, then that player wins. Otherwise, another game round is required. Write a program that will determine the winner by the gestures they have shown.
Input Specification:
The first input line contains the name of the gesture that Uncle Fyodor showed, the second line shows which gesture Matroskin showed and the third line shows Sharic’s gesture.
Output Specification:
Print "F" (without quotes) if Uncle Fyodor wins. Print "M" if Matroskin wins and "S" if Sharic wins. If it is impossible to find the winner, print "?".
Demo Input:
['rock\nrock\nrock\n', 'paper\nrock\nrock\n', 'scissors\nrock\nrock\n', 'scissors\npaper\nrock\n']
Demo Output:
['?\n', 'F\n', '?\n', '?\n']
Note:
none | ```python
F=input()
M=input()
S=input()
Beater={"paper":"scissors","scissors":"rock","rock":"paper"}
if S==Beater[F] and F==M:
print("S")
elif F==Beater[S] and S==M:
print("F")
elif M==Beater[F] and F==S:
print("M")
else:
print("?")
``` | 3.968608 |
593 | B | Anton and Lines | PROGRAMMING | 1,600 | [
"geometry",
"sortings"
] | null | null | The teacher gave Anton a large geometry homework, but he didn't do it (as usual) as he participated in a regular round on Codeforces. In the task he was given a set of *n* lines defined by the equations *y*<==<=*k**i*·*x*<=+<=*b**i*. It was necessary to determine whether there is at least one point of intersection of two of these lines, that lays strictly inside the strip between *x*1<=<<=*x*2. In other words, is it true that there are 1<=≤<=*i*<=<<=*j*<=≤<=*n* and *x*',<=*y*', such that:
- *y*'<==<=*k**i*<=*<=*x*'<=+<=*b**i*, that is, point (*x*',<=*y*') belongs to the line number *i*; - *y*'<==<=*k**j*<=*<=*x*'<=+<=*b**j*, that is, point (*x*',<=*y*') belongs to the line number *j*; - *x*1<=<<=*x*'<=<<=*x*2, that is, point (*x*',<=*y*') lies inside the strip bounded by *x*1<=<<=*x*2.
You can't leave Anton in trouble, can you? Write a program that solves the given task. | The first line of the input contains an integer *n* (2<=≤<=*n*<=≤<=100<=000) — the number of lines in the task given to Anton. The second line contains integers *x*1 and *x*2 (<=-<=1<=000<=000<=≤<=*x*1<=<<=*x*2<=≤<=1<=000<=000) defining the strip inside which you need to find a point of intersection of at least two lines.
The following *n* lines contain integers *k**i*, *b**i* (<=-<=1<=000<=000<=≤<=*k**i*,<=*b**i*<=≤<=1<=000<=000) — the descriptions of the lines. It is guaranteed that all lines are pairwise distinct, that is, for any two *i*<=≠<=*j* it is true that either *k**i*<=≠<=*k**j*, or *b**i*<=≠<=*b**j*. | Print "Yes" (without quotes), if there is at least one intersection of two distinct lines, located strictly inside the strip. Otherwise print "No" (without quotes). | [
"4\n1 2\n1 2\n1 0\n0 1\n0 2\n",
"2\n1 3\n1 0\n-1 3\n",
"2\n1 3\n1 0\n0 2\n",
"2\n1 3\n1 0\n0 3\n"
] | [
"NO",
"YES",
"YES",
"NO"
] | In the first sample there are intersections located on the border of the strip, but there are no intersections located strictly inside it. | 1,000 | [
{
"input": "4\n1 2\n1 2\n1 0\n0 1\n0 2",
"output": "NO"
},
{
"input": "2\n1 3\n1 0\n-1 3",
"output": "YES"
},
{
"input": "2\n1 3\n1 0\n0 2",
"output": "YES"
},
{
"input": "2\n1 3\n1 0\n0 3",
"output": "NO"
},
{
"input": "2\n0 1\n-1000000 1000000\n1000000 -1000000"... | 1,698,433,706 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 15 | 1,000 | 19,660,800 | import sys
def log(*args,**kwargs):
kwargs["file"] = kwargs.get("file",sys.stderr)
print(*args,**kwargs)
n = int(input())
x1,x2 = map(int,input().strip().split())
y1s = []
y2s = []
for i in range(n):
m,c = map(int,input().strip().split())
y1s.append(m*x1+c)
y2s.append(m*x2+c)
# log(m*x1+c, m*x2+c)
hmm = sorted(range(n),key=lambda x: y1s[x])
for i,j in zip(hmm,hmm[1:]):
if y1s[i] != y1s[j] and y2s[i] > y2s[j]:
print("YES")
exit()
print("NO") | Title: Anton and Lines
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The teacher gave Anton a large geometry homework, but he didn't do it (as usual) as he participated in a regular round on Codeforces. In the task he was given a set of *n* lines defined by the equations *y*<==<=*k**i*·*x*<=+<=*b**i*. It was necessary to determine whether there is at least one point of intersection of two of these lines, that lays strictly inside the strip between *x*1<=<<=*x*2. In other words, is it true that there are 1<=≤<=*i*<=<<=*j*<=≤<=*n* and *x*',<=*y*', such that:
- *y*'<==<=*k**i*<=*<=*x*'<=+<=*b**i*, that is, point (*x*',<=*y*') belongs to the line number *i*; - *y*'<==<=*k**j*<=*<=*x*'<=+<=*b**j*, that is, point (*x*',<=*y*') belongs to the line number *j*; - *x*1<=<<=*x*'<=<<=*x*2, that is, point (*x*',<=*y*') lies inside the strip bounded by *x*1<=<<=*x*2.
You can't leave Anton in trouble, can you? Write a program that solves the given task.
Input Specification:
The first line of the input contains an integer *n* (2<=≤<=*n*<=≤<=100<=000) — the number of lines in the task given to Anton. The second line contains integers *x*1 and *x*2 (<=-<=1<=000<=000<=≤<=*x*1<=<<=*x*2<=≤<=1<=000<=000) defining the strip inside which you need to find a point of intersection of at least two lines.
The following *n* lines contain integers *k**i*, *b**i* (<=-<=1<=000<=000<=≤<=*k**i*,<=*b**i*<=≤<=1<=000<=000) — the descriptions of the lines. It is guaranteed that all lines are pairwise distinct, that is, for any two *i*<=≠<=*j* it is true that either *k**i*<=≠<=*k**j*, or *b**i*<=≠<=*b**j*.
Output Specification:
Print "Yes" (without quotes), if there is at least one intersection of two distinct lines, located strictly inside the strip. Otherwise print "No" (without quotes).
Demo Input:
['4\n1 2\n1 2\n1 0\n0 1\n0 2\n', '2\n1 3\n1 0\n-1 3\n', '2\n1 3\n1 0\n0 2\n', '2\n1 3\n1 0\n0 3\n']
Demo Output:
['NO', 'YES', 'YES', 'NO']
Note:
In the first sample there are intersections located on the border of the strip, but there are no intersections located strictly inside it. | ```python
import sys
def log(*args,**kwargs):
kwargs["file"] = kwargs.get("file",sys.stderr)
print(*args,**kwargs)
n = int(input())
x1,x2 = map(int,input().strip().split())
y1s = []
y2s = []
for i in range(n):
m,c = map(int,input().strip().split())
y1s.append(m*x1+c)
y2s.append(m*x2+c)
# log(m*x1+c, m*x2+c)
hmm = sorted(range(n),key=lambda x: y1s[x])
for i,j in zip(hmm,hmm[1:]):
if y1s[i] != y1s[j] and y2s[i] > y2s[j]:
print("YES")
exit()
print("NO")
``` | 0 | |
911 | F | Tree Destruction | PROGRAMMING | 2,400 | [
"constructive algorithms",
"dfs and similar",
"graphs",
"greedy",
"trees"
] | null | null | You are given an unweighted tree with *n* vertices. Then *n*<=-<=1 following operations are applied to the tree. A single operation consists of the following steps:
1. choose two leaves; 1. add the length of the simple path between them to the answer; 1. remove one of the chosen leaves from the tree.
Initial answer (before applying operations) is 0. Obviously after *n*<=-<=1 such operations the tree will consist of a single vertex.
Calculate the maximal possible answer you can achieve, and construct a sequence of operations that allows you to achieve this answer! | The first line contains one integer number *n* (2<=≤<=*n*<=≤<=2·105) — the number of vertices in the tree.
Next *n*<=-<=1 lines describe the edges of the tree in form *a**i*,<=*b**i* (1<=≤<=*a**i*, *b**i*<=≤<=*n*, *a**i*<=≠<=*b**i*). It is guaranteed that given graph is a tree. | In the first line print one integer number — maximal possible answer.
In the next *n*<=-<=1 lines print the operations in order of their applying in format *a**i*,<=*b**i*,<=*c**i*, where *a**i*,<=*b**i* — pair of the leaves that are chosen in the current operation (1<=≤<=*a**i*, *b**i*<=≤<=*n*), *c**i* (1<=≤<=*c**i*<=≤<=*n*, *c**i*<==<=*a**i* or *c**i*<==<=*b**i*) — choosen leaf that is removed from the tree in the current operation.
See the examples for better understanding. | [
"3\n1 2\n1 3\n",
"5\n1 2\n1 3\n2 4\n2 5\n"
] | [
"3\n2 3 3\n2 1 1\n",
"9\n3 5 5\n4 3 3\n4 1 1\n4 2 2\n"
] | none | 0 | [
{
"input": "3\n1 2\n1 3",
"output": "3\n2 3 3\n2 1 1"
},
{
"input": "5\n1 2\n1 3\n2 4\n2 5",
"output": "9\n3 5 5\n4 3 3\n4 1 1\n4 2 2"
},
{
"input": "2\n1 2",
"output": "1\n2 1 1"
},
{
"input": "4\n1 3\n1 4\n1 2",
"output": "5\n3 4 4\n2 3 3\n2 1 1"
},
{
"input": "... | 1,693,562,841 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("_RANDOM_GUESS_1693562841.5007517")# 1693562841.500775 | Title: Tree Destruction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an unweighted tree with *n* vertices. Then *n*<=-<=1 following operations are applied to the tree. A single operation consists of the following steps:
1. choose two leaves; 1. add the length of the simple path between them to the answer; 1. remove one of the chosen leaves from the tree.
Initial answer (before applying operations) is 0. Obviously after *n*<=-<=1 such operations the tree will consist of a single vertex.
Calculate the maximal possible answer you can achieve, and construct a sequence of operations that allows you to achieve this answer!
Input Specification:
The first line contains one integer number *n* (2<=≤<=*n*<=≤<=2·105) — the number of vertices in the tree.
Next *n*<=-<=1 lines describe the edges of the tree in form *a**i*,<=*b**i* (1<=≤<=*a**i*, *b**i*<=≤<=*n*, *a**i*<=≠<=*b**i*). It is guaranteed that given graph is a tree.
Output Specification:
In the first line print one integer number — maximal possible answer.
In the next *n*<=-<=1 lines print the operations in order of their applying in format *a**i*,<=*b**i*,<=*c**i*, where *a**i*,<=*b**i* — pair of the leaves that are chosen in the current operation (1<=≤<=*a**i*, *b**i*<=≤<=*n*), *c**i* (1<=≤<=*c**i*<=≤<=*n*, *c**i*<==<=*a**i* or *c**i*<==<=*b**i*) — choosen leaf that is removed from the tree in the current operation.
See the examples for better understanding.
Demo Input:
['3\n1 2\n1 3\n', '5\n1 2\n1 3\n2 4\n2 5\n']
Demo Output:
['3\n2 3 3\n2 1 1\n', '9\n3 5 5\n4 3 3\n4 1 1\n4 2 2\n']
Note:
none | ```python
print("_RANDOM_GUESS_1693562841.5007517")# 1693562841.500775
``` | 0 | |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that is different in evenness. | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,651,426,180 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 92 | 0 | n=int(input())
a=list(map(int,input().split()))
even=[]
uneven=[]
for i in range(n):
if a[i]%2==0:
even.append(i)
else:
uneven.append(i)
#print(i, even, uneven)
if len(even)<len(uneven):
print(even[0]+1)
else:
print(uneven[0]+1)
| Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that is different in evenness.
Input Specification:
The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness.
Output Specification:
Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order.
Demo Input:
['5\n2 4 7 8 10\n', '4\n1 2 1 1\n']
Demo Output:
['3\n', '2\n']
Note:
none | ```python
n=int(input())
a=list(map(int,input().split()))
even=[]
uneven=[]
for i in range(n):
if a[i]%2==0:
even.append(i)
else:
uneven.append(i)
#print(i, even, uneven)
if len(even)<len(uneven):
print(even[0]+1)
else:
print(uneven[0]+1)
``` | 3.977 |
54 | A | Presents | PROGRAMMING | 1,300 | [
"implementation"
] | A. Presents | 2 | 256 | The Hedgehog likes to give presents to his friend, but no less he likes to receive them.
Having received another present today, the Hedgehog suddenly understood that he has no place to put it as there was no room left on the special shelf in the cupboard. He will have to choose another shelf, but which one should he choose, how large should it be?
In order to get to know this, the Hedgehog asks you to write him a program that will count the estimated number of presents that he will receive during the following *N* days. Besides, he is guided by the principle:
- on each holiday day the Hedgehog will necessarily receive a present, - he receives presents at least every *K* days (i.e., if he received a present on the *i*-th day, he will receive the next present no later than on the *i*<=+<=*K*-th day).
For the given *N* and *K*, as well as the list of holidays among the following *N* days count the minimal number of presents that could be given to the Hedgehog. The number of today's day is zero, and you should regard today's present as already given (i.e., you shouldn't count it in the answer). | The first line contains integers *N* and *K* (1<=≤<=*N*<=≤<=365, 1<=≤<=*K*<=≤<=*N*).
The second line contains a number *C* which represents the number of holidays (0<=≤<=*C*<=≤<=*N*). Then in the same line follow *C* numbers ranging from 1 to *N* which are the numbers of holiday days. The numbers are given in the increasing order, without repeating numbers among them. | Print a single number — the minimal number of presents the Hedgehog will receive over the following *N* days. | [
"5 2\n1 3\n",
"10 1\n3 6 7 8\n"
] | [
"3",
"10"
] | none | 500 | [
{
"input": "5 2\n1 3",
"output": "3"
},
{
"input": "10 1\n3 6 7 8",
"output": "10"
},
{
"input": "5 5\n1 3",
"output": "1"
},
{
"input": "10 3\n3 3 6 9",
"output": "3"
},
{
"input": "5 2\n0",
"output": "2"
},
{
"input": "1 1\n0",
"output": "1"
},... | 1,546,844,076 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 218 | 0 | n,k = map(int,input().split())
a = list(map(int,input().split()))
ans = n//k
for i in range(1,a[0]+1):
ans += (a[i]%k!=0)
print(ans) | Title: Presents
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The Hedgehog likes to give presents to his friend, but no less he likes to receive them.
Having received another present today, the Hedgehog suddenly understood that he has no place to put it as there was no room left on the special shelf in the cupboard. He will have to choose another shelf, but which one should he choose, how large should it be?
In order to get to know this, the Hedgehog asks you to write him a program that will count the estimated number of presents that he will receive during the following *N* days. Besides, he is guided by the principle:
- on each holiday day the Hedgehog will necessarily receive a present, - he receives presents at least every *K* days (i.e., if he received a present on the *i*-th day, he will receive the next present no later than on the *i*<=+<=*K*-th day).
For the given *N* and *K*, as well as the list of holidays among the following *N* days count the minimal number of presents that could be given to the Hedgehog. The number of today's day is zero, and you should regard today's present as already given (i.e., you shouldn't count it in the answer).
Input Specification:
The first line contains integers *N* and *K* (1<=≤<=*N*<=≤<=365, 1<=≤<=*K*<=≤<=*N*).
The second line contains a number *C* which represents the number of holidays (0<=≤<=*C*<=≤<=*N*). Then in the same line follow *C* numbers ranging from 1 to *N* which are the numbers of holiday days. The numbers are given in the increasing order, without repeating numbers among them.
Output Specification:
Print a single number — the minimal number of presents the Hedgehog will receive over the following *N* days.
Demo Input:
['5 2\n1 3\n', '10 1\n3 6 7 8\n']
Demo Output:
['3', '10']
Note:
none | ```python
n,k = map(int,input().split())
a = list(map(int,input().split()))
ans = n//k
for i in range(1,a[0]+1):
ans += (a[i]%k!=0)
print(ans)
``` | 0 |
994 | B | Knights of a Polygonal Table | PROGRAMMING | 1,400 | [
"greedy",
"implementation",
"sortings"
] | null | null | Unlike Knights of a Round Table, Knights of a Polygonal Table deprived of nobility and happy to kill each other. But each knight has some power and a knight can kill another knight if and only if his power is greater than the power of victim. However, even such a knight will torment his conscience, so he can kill no more than $k$ other knights. Also, each knight has some number of coins. After a kill, a knight can pick up all victim's coins.
Now each knight ponders: how many coins he can have if only he kills other knights?
You should answer this question for each knight. | The first line contains two integers $n$ and $k$ $(1 \le n \le 10^5, 0 \le k \le \min(n-1,10))$ — the number of knights and the number $k$ from the statement.
The second line contains $n$ integers $p_1, p_2 ,\ldots,p_n$ $(1 \le p_i \le 10^9)$ — powers of the knights. All $p_i$ are distinct.
The third line contains $n$ integers $c_1, c_2 ,\ldots,c_n$ $(0 \le c_i \le 10^9)$ — the number of coins each knight has. | Print $n$ integers — the maximum number of coins each knight can have it only he kills other knights. | [
"4 2\n4 5 9 7\n1 2 11 33\n",
"5 1\n1 2 3 4 5\n1 2 3 4 5\n",
"1 0\n2\n3\n"
] | [
"1 3 46 36 ",
"1 3 5 7 9 ",
"3 "
] | Consider the first example.
- The first knight is the weakest, so he can't kill anyone. That leaves him with the only coin he initially has. - The second knight can kill the first knight and add his coin to his own two. - The third knight is the strongest, but he can't kill more than $k = 2$ other knights. It is optimal to kill the second and the fourth knights: $2+11+33 = 46$. - The fourth knight should kill the first and the second knights: $33+1+2 = 36$.
In the second example the first knight can't kill anyone, while all the others should kill the one with the index less by one than their own.
In the third example there is only one knight, so he can't kill anyone. | 1,000 | [
{
"input": "4 2\n4 5 9 7\n1 2 11 33",
"output": "1 3 46 36 "
},
{
"input": "5 1\n1 2 3 4 5\n1 2 3 4 5",
"output": "1 3 5 7 9 "
},
{
"input": "1 0\n2\n3",
"output": "3 "
},
{
"input": "7 1\n2 3 4 5 7 8 9\n0 3 7 9 5 8 9",
"output": "0 3 10 16 14 17 18 "
},
{
"input"... | 1,529,257,658 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 108 | 409,600 | #!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
@author: alpha
"""
from functools import reduce
maxNumOfKill = list(map(lambda x: int(x), input().split()))[1] + 1
powerArr = list(map(lambda x: int(x), input().split()))
coinsArr = list(map(lambda x: int(x), input().split()))
knightInfo = list(map(lambda x,y:(x,y), powerArr, coinsArr))
knightInfo.sort()
k_largest = []
res = {}
for knight in knightInfo:
if len(k_largest) < maxNumOfKill:
k_largest.append(knight[1])
elif min(k_largest) < knight[1]:
k_largest.remove(min(k_largest))
k_largest.append(knight[1])
res[knight[0]] = str(sum(k_largest))
out = []
for i in powerArr:
out.append(str(res[i]))
print(reduce(lambda x, y: x+' '+y, out) + '' ) | Title: Knights of a Polygonal Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Unlike Knights of a Round Table, Knights of a Polygonal Table deprived of nobility and happy to kill each other. But each knight has some power and a knight can kill another knight if and only if his power is greater than the power of victim. However, even such a knight will torment his conscience, so he can kill no more than $k$ other knights. Also, each knight has some number of coins. After a kill, a knight can pick up all victim's coins.
Now each knight ponders: how many coins he can have if only he kills other knights?
You should answer this question for each knight.
Input Specification:
The first line contains two integers $n$ and $k$ $(1 \le n \le 10^5, 0 \le k \le \min(n-1,10))$ — the number of knights and the number $k$ from the statement.
The second line contains $n$ integers $p_1, p_2 ,\ldots,p_n$ $(1 \le p_i \le 10^9)$ — powers of the knights. All $p_i$ are distinct.
The third line contains $n$ integers $c_1, c_2 ,\ldots,c_n$ $(0 \le c_i \le 10^9)$ — the number of coins each knight has.
Output Specification:
Print $n$ integers — the maximum number of coins each knight can have it only he kills other knights.
Demo Input:
['4 2\n4 5 9 7\n1 2 11 33\n', '5 1\n1 2 3 4 5\n1 2 3 4 5\n', '1 0\n2\n3\n']
Demo Output:
['1 3 46 36 ', '1 3 5 7 9 ', '3 ']
Note:
Consider the first example.
- The first knight is the weakest, so he can't kill anyone. That leaves him with the only coin he initially has. - The second knight can kill the first knight and add his coin to his own two. - The third knight is the strongest, but he can't kill more than $k = 2$ other knights. It is optimal to kill the second and the fourth knights: $2+11+33 = 46$. - The fourth knight should kill the first and the second knights: $33+1+2 = 36$.
In the second example the first knight can't kill anyone, while all the others should kill the one with the index less by one than their own.
In the third example there is only one knight, so he can't kill anyone. | ```python
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
@author: alpha
"""
from functools import reduce
maxNumOfKill = list(map(lambda x: int(x), input().split()))[1] + 1
powerArr = list(map(lambda x: int(x), input().split()))
coinsArr = list(map(lambda x: int(x), input().split()))
knightInfo = list(map(lambda x,y:(x,y), powerArr, coinsArr))
knightInfo.sort()
k_largest = []
res = {}
for knight in knightInfo:
if len(k_largest) < maxNumOfKill:
k_largest.append(knight[1])
elif min(k_largest) < knight[1]:
k_largest.remove(min(k_largest))
k_largest.append(knight[1])
res[knight[0]] = str(sum(k_largest))
out = []
for i in powerArr:
out.append(str(res[i]))
print(reduce(lambda x, y: x+' '+y, out) + '' )
``` | 0 | |
960 | B | Minimize the error | PROGRAMMING | 1,500 | [
"data structures",
"greedy",
"sortings"
] | null | null | You are given two arrays *A* and *B*, each of size *n*. The error, *E*, between these two arrays is defined . You have to perform exactly *k*1 operations on array *A* and exactly *k*2 operations on array *B*. In one operation, you have to choose one element of the array and increase or decrease it by 1.
Output the minimum possible value of error after *k*1 operations on array *A* and *k*2 operations on array *B* have been performed. | The first line contains three space-separated integers *n* (1<=≤<=*n*<=≤<=103), *k*1 and *k*2 (0<=≤<=*k*1<=+<=*k*2<=≤<=103, *k*1 and *k*2 are non-negative) — size of arrays and number of operations to perform on *A* and *B* respectively.
Second line contains *n* space separated integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=106<=≤<=*a**i*<=≤<=106) — array *A*.
Third line contains *n* space separated integers *b*1,<=*b*2,<=...,<=*b**n* (<=-<=106<=≤<=*b**i*<=≤<=106)— array *B*. | Output a single integer — the minimum possible value of after doing exactly *k*1 operations on array *A* and exactly *k*2 operations on array *B*. | [
"2 0 0\n1 2\n2 3\n",
"2 1 0\n1 2\n2 2\n",
"2 5 7\n3 4\n14 4\n"
] | [
"2",
"0",
"1"
] | In the first sample case, we cannot perform any operations on *A* or *B*. Therefore the minimum possible error *E* = (1 - 2)<sup class="upper-index">2</sup> + (2 - 3)<sup class="upper-index">2</sup> = 2.
In the second sample case, we are required to perform exactly one operation on *A*. In order to minimize error, we increment the first element of *A* by 1. Now, *A* = [2, 2]. The error is now *E* = (2 - 2)<sup class="upper-index">2</sup> + (2 - 2)<sup class="upper-index">2</sup> = 0. This is the minimum possible error obtainable.
In the third sample case, we can increase the first element of *A* to 8, using the all of the 5 moves available to us. Also, the first element of *B* can be reduced to 8 using the 6 of the 7 available moves. Now *A* = [8, 4] and *B* = [8, 4]. The error is now *E* = (8 - 8)<sup class="upper-index">2</sup> + (4 - 4)<sup class="upper-index">2</sup> = 0, but we are still left with 1 move for array *B*. Increasing the second element of *B* to 5 using the left move, we get *B* = [8, 5] and *E* = (8 - 8)<sup class="upper-index">2</sup> + (4 - 5)<sup class="upper-index">2</sup> = 1. | 1,000 | [
{
"input": "2 0 0\n1 2\n2 3",
"output": "2"
},
{
"input": "2 1 0\n1 2\n2 2",
"output": "0"
},
{
"input": "2 5 7\n3 4\n14 4",
"output": "1"
},
{
"input": "2 0 1\n1 2\n2 2",
"output": "0"
},
{
"input": "2 1 1\n0 0\n1 1",
"output": "0"
},
{
"input": "5 5 ... | 1,648,277,287 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 80 | 77 | 2,560,000 | n, k1, k2 = map(int, input().split())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
c = [0]*n
for i in range(n):
c[i] = abs(a[i] - b[i])
k = k1 + k2
while k != 0:
max_value = c[0]
max_index = 0
for i, v in enumerate(c):
if v > max_value:
max_value = v
max_index = i
if max_value == 0:
break
else:
c[max_index] -= 1
k -= 1
if k == 0:
sum = 0
for i in range(n):
sum += c[i]*c[i]
print(sum)
else:
if k % 2 == 0:
print(0)
else:
print(1) | Title: Minimize the error
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two arrays *A* and *B*, each of size *n*. The error, *E*, between these two arrays is defined . You have to perform exactly *k*1 operations on array *A* and exactly *k*2 operations on array *B*. In one operation, you have to choose one element of the array and increase or decrease it by 1.
Output the minimum possible value of error after *k*1 operations on array *A* and *k*2 operations on array *B* have been performed.
Input Specification:
The first line contains three space-separated integers *n* (1<=≤<=*n*<=≤<=103), *k*1 and *k*2 (0<=≤<=*k*1<=+<=*k*2<=≤<=103, *k*1 and *k*2 are non-negative) — size of arrays and number of operations to perform on *A* and *B* respectively.
Second line contains *n* space separated integers *a*1,<=*a*2,<=...,<=*a**n* (<=-<=106<=≤<=*a**i*<=≤<=106) — array *A*.
Third line contains *n* space separated integers *b*1,<=*b*2,<=...,<=*b**n* (<=-<=106<=≤<=*b**i*<=≤<=106)— array *B*.
Output Specification:
Output a single integer — the minimum possible value of after doing exactly *k*1 operations on array *A* and exactly *k*2 operations on array *B*.
Demo Input:
['2 0 0\n1 2\n2 3\n', '2 1 0\n1 2\n2 2\n', '2 5 7\n3 4\n14 4\n']
Demo Output:
['2', '0', '1']
Note:
In the first sample case, we cannot perform any operations on *A* or *B*. Therefore the minimum possible error *E* = (1 - 2)<sup class="upper-index">2</sup> + (2 - 3)<sup class="upper-index">2</sup> = 2.
In the second sample case, we are required to perform exactly one operation on *A*. In order to minimize error, we increment the first element of *A* by 1. Now, *A* = [2, 2]. The error is now *E* = (2 - 2)<sup class="upper-index">2</sup> + (2 - 2)<sup class="upper-index">2</sup> = 0. This is the minimum possible error obtainable.
In the third sample case, we can increase the first element of *A* to 8, using the all of the 5 moves available to us. Also, the first element of *B* can be reduced to 8 using the 6 of the 7 available moves. Now *A* = [8, 4] and *B* = [8, 4]. The error is now *E* = (8 - 8)<sup class="upper-index">2</sup> + (4 - 4)<sup class="upper-index">2</sup> = 0, but we are still left with 1 move for array *B*. Increasing the second element of *B* to 5 using the left move, we get *B* = [8, 5] and *E* = (8 - 8)<sup class="upper-index">2</sup> + (4 - 5)<sup class="upper-index">2</sup> = 1. | ```python
n, k1, k2 = map(int, input().split())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
c = [0]*n
for i in range(n):
c[i] = abs(a[i] - b[i])
k = k1 + k2
while k != 0:
max_value = c[0]
max_index = 0
for i, v in enumerate(c):
if v > max_value:
max_value = v
max_index = i
if max_value == 0:
break
else:
c[max_index] -= 1
k -= 1
if k == 0:
sum = 0
for i in range(n):
sum += c[i]*c[i]
print(sum)
else:
if k % 2 == 0:
print(0)
else:
print(1)
``` | 3 | |
155 | A | I_love_\%username\% | PROGRAMMING | 800 | [
"brute force"
] | null | null | Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the results of all contests where his favorite coder participated and track the progress of his coolness. For each contest where this coder participated, he wrote out a single non-negative number — the number of points his favorite coder earned in the contest. Vasya wrote out the points for the contest in the order, in which the contests run (naturally, no two contests ran simultaneously).
Vasya considers a coder's performance in a contest amazing in two situations: he can break either his best or his worst performance record. First, it is amazing if during the contest the coder earns strictly more points that he earned on each past contest. Second, it is amazing if during the contest the coder earns strictly less points that he earned on each past contest. A coder's first contest isn't considered amazing. Now he wants to count the number of amazing performances the coder had throughout his whole history of participating in contests. But the list of earned points turned out long and Vasya can't code... That's why he asks you to help him. | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of contests where the coder participated.
The next line contains *n* space-separated non-negative integer numbers — they are the points which the coder has earned. The points are given in the chronological order. All points do not exceed 10000. | Print the single number — the number of amazing performances the coder has had during his whole history of participating in the contests. | [
"5\n100 50 200 150 200\n",
"10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242\n"
] | [
"2\n",
"4\n"
] | In the first sample the performances number 2 and 3 are amazing.
In the second sample the performances number 2, 4, 9 and 10 are amazing. | 500 | [
{
"input": "5\n100 50 200 150 200",
"output": "2"
},
{
"input": "10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242",
"output": "4"
},
{
"input": "1\n6",
"output": "0"
},
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "5\n100 36 53 7 81",
"output": "2"
... | 1,692,455,876 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | n = int(input())
points = list(map(int, input().split()))
amazing_performances = 0
for i in range(1, n):
if points[i] > points[0:i]:
amazing_performances += 1
print(amazing_performances) | Title: I_love_\%username\%
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the results of all contests where his favorite coder participated and track the progress of his coolness. For each contest where this coder participated, he wrote out a single non-negative number — the number of points his favorite coder earned in the contest. Vasya wrote out the points for the contest in the order, in which the contests run (naturally, no two contests ran simultaneously).
Vasya considers a coder's performance in a contest amazing in two situations: he can break either his best or his worst performance record. First, it is amazing if during the contest the coder earns strictly more points that he earned on each past contest. Second, it is amazing if during the contest the coder earns strictly less points that he earned on each past contest. A coder's first contest isn't considered amazing. Now he wants to count the number of amazing performances the coder had throughout his whole history of participating in contests. But the list of earned points turned out long and Vasya can't code... That's why he asks you to help him.
Input Specification:
The first line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of contests where the coder participated.
The next line contains *n* space-separated non-negative integer numbers — they are the points which the coder has earned. The points are given in the chronological order. All points do not exceed 10000.
Output Specification:
Print the single number — the number of amazing performances the coder has had during his whole history of participating in the contests.
Demo Input:
['5\n100 50 200 150 200\n', '10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242\n']
Demo Output:
['2\n', '4\n']
Note:
In the first sample the performances number 2 and 3 are amazing.
In the second sample the performances number 2, 4, 9 and 10 are amazing. | ```python
n = int(input())
points = list(map(int, input().split()))
amazing_performances = 0
for i in range(1, n):
if points[i] > points[0:i]:
amazing_performances += 1
print(amazing_performances)
``` | -1 | |
311 | A | The Closest Pair | PROGRAMMING | 1,300 | [
"constructive algorithms",
"implementation"
] | null | null | Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the follows. Given *n* points in the plane, find a pair of points between which the distance is minimized. Distance between (*x*1,<=*y*1) and (*x*2,<=*y*2) is .
The pseudo code of the unexpected code is as follows:
Here, *tot* can be regarded as the running time of the code. Due to the fact that a computer can only run a limited number of operations per second, *tot* should not be more than *k* in order not to get Time Limit Exceeded.
You are a great hacker. Would you please help Tiny generate a test data and let the code get Time Limit Exceeded? | A single line which contains two space-separated integers *n* and *k* (2<=≤<=*n*<=≤<=2000, 1<=≤<=*k*<=≤<=109). | If there doesn't exist such a data which let the given code get TLE, print "no solution" (without quotes); else print *n* lines, and the *i*-th line contains two integers *x**i*,<=*y**i* (|*x**i*|,<=|*y**i*|<=≤<=109) representing the coordinates of the *i*-th point.
The conditions below must be held:
- All the points must be distinct. - |*x**i*|,<=|*y**i*|<=≤<=109. - After running the given code, the value of *tot* should be larger than *k*. | [
"4 3\n",
"2 100\n"
] | [
"0 0\n0 1\n1 0\n1 1\n",
"no solution\n"
] | none | 500 | [
{
"input": "4 3",
"output": "0 0\n0 1\n1 0\n1 1"
},
{
"input": "2 100",
"output": "no solution"
},
{
"input": "5 6",
"output": "0 0\n0 1\n0 2\n0 3\n0 4"
},
{
"input": "8 20",
"output": "0 0\n0 1\n0 2\n0 3\n0 4\n0 5\n0 6\n0 7"
},
{
"input": "6 15",
"output": "n... | 1,550,930,211 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 109 | 0 | n, k = map(int, input().split())
if (2 * k > n * (n-1)):
print("no solution")
else:
print('\n'.join(["{} {}".format(0,i) for i in range(0,n)]))
| Title: The Closest Pair
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the follows. Given *n* points in the plane, find a pair of points between which the distance is minimized. Distance between (*x*1,<=*y*1) and (*x*2,<=*y*2) is .
The pseudo code of the unexpected code is as follows:
Here, *tot* can be regarded as the running time of the code. Due to the fact that a computer can only run a limited number of operations per second, *tot* should not be more than *k* in order not to get Time Limit Exceeded.
You are a great hacker. Would you please help Tiny generate a test data and let the code get Time Limit Exceeded?
Input Specification:
A single line which contains two space-separated integers *n* and *k* (2<=≤<=*n*<=≤<=2000, 1<=≤<=*k*<=≤<=109).
Output Specification:
If there doesn't exist such a data which let the given code get TLE, print "no solution" (without quotes); else print *n* lines, and the *i*-th line contains two integers *x**i*,<=*y**i* (|*x**i*|,<=|*y**i*|<=≤<=109) representing the coordinates of the *i*-th point.
The conditions below must be held:
- All the points must be distinct. - |*x**i*|,<=|*y**i*|<=≤<=109. - After running the given code, the value of *tot* should be larger than *k*.
Demo Input:
['4 3\n', '2 100\n']
Demo Output:
['0 0\n0 1\n1 0\n1 1\n', 'no solution\n']
Note:
none | ```python
n, k = map(int, input().split())
if (2 * k > n * (n-1)):
print("no solution")
else:
print('\n'.join(["{} {}".format(0,i) for i in range(0,n)]))
``` | 0 | |
160 | A | Twins | PROGRAMMING | 900 | [
"greedy",
"sortings"
] | null | null | Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, *n* coins of arbitrary values *a*1,<=*a*2,<=...,<=*a**n*. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" — you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner. | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces. | In the single line print the single number — the minimum needed number of coins. | [
"2\n3 3\n",
"3\n2 1 2\n"
] | [
"2\n",
"2\n"
] | In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2. | 500 | [
{
"input": "2\n3 3",
"output": "2"
},
{
"input": "3\n2 1 2",
"output": "2"
},
{
"input": "1\n5",
"output": "1"
},
{
"input": "5\n4 2 2 2 2",
"output": "3"
},
{
"input": "7\n1 10 1 2 1 1 1",
"output": "1"
},
{
"input": "5\n3 2 3 3 1",
"output": "3"
... | 1,686,771,330 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 92 | 0 | s=int(input())
b=list(map(int,input().split()))
c=0
p=0
k=sum(b)
for i in b:
p+=i
k-=i
c+=1
if p>k:
break
print(c) | Title: Twins
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, *n* coins of arbitrary values *a*1,<=*a*2,<=...,<=*a**n*. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" — you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of coins. The second line contains a sequence of *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=100) — the coins' values. All numbers are separated with spaces.
Output Specification:
In the single line print the single number — the minimum needed number of coins.
Demo Input:
['2\n3 3\n', '3\n2 1 2\n']
Demo Output:
['2\n', '2\n']
Note:
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2. | ```python
s=int(input())
b=list(map(int,input().split()))
c=0
p=0
k=sum(b)
for i in b:
p+=i
k-=i
c+=1
if p>k:
break
print(c)
``` | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Two participants are each given a pair of distinct numbers from 1 to 9 such that there's exactly one number that is present in both pairs. They want to figure out the number that matches by using a communication channel you have access to without revealing it to you.
Both participants communicated to each other a set of pairs of numbers, that includes the pair given to them. Each pair in the communicated sets comprises two different numbers.
Determine if you can with certainty deduce the common number, or if you can determine with certainty that both participants know the number but you do not. | The first line contains two integers $n$ and $m$ ($1 \le n, m \le 12$) — the number of pairs the first participant communicated to the second and vice versa.
The second line contains $n$ pairs of integers, each between $1$ and $9$, — pairs of numbers communicated from first participant to the second.
The third line contains $m$ pairs of integers, each between $1$ and $9$, — pairs of numbers communicated from the second participant to the first.
All pairs within each set are distinct (in particular, if there is a pair $(1,2)$, there will be no pair $(2,1)$ within the same set), and no pair contains the same number twice.
It is guaranteed that the two sets do not contradict the statements, in other words, there is pair from the first set and a pair from the second set that share exactly one number. | If you can deduce the shared number with certainty, print that number.
If you can with certainty deduce that both participants know the shared number, but you do not know it, print $0$.
Otherwise print $-1$. | [
"2 2\n1 2 3 4\n1 5 3 4\n",
"2 2\n1 2 3 4\n1 5 6 4\n",
"2 3\n1 2 4 5\n1 2 1 3 2 3\n"
] | [
"1\n",
"0\n",
"-1\n"
] | In the first example the first participant communicated pairs $(1,2)$ and $(3,4)$, and the second communicated $(1,5)$, $(3,4)$. Since we know that the actual pairs they received share exactly one number, it can't be that they both have $(3,4)$. Thus, the first participant has $(1,2)$ and the second has $(1,5)$, and at this point you already know the shared number is $1$.
In the second example either the first participant has $(1,2)$ and the second has $(1,5)$, or the first has $(3,4)$ and the second has $(6,4)$. In the first case both of them know the shared number is $1$, in the second case both of them know the shared number is $4$. You don't have enough information to tell $1$ and $4$ apart.
In the third case if the first participant was given $(1,2)$, they don't know what the shared number is, since from their perspective the second participant might have been given either $(1,3)$, in which case the shared number is $1$, or $(2,3)$, in which case the shared number is $2$. While the second participant does know the number with certainty, neither you nor the first participant do, so the output is $-1$. | 0 | [
{
"input": "2 2\n1 2 3 4\n1 5 3 4",
"output": "1"
},
{
"input": "2 2\n1 2 3 4\n1 5 6 4",
"output": "0"
},
{
"input": "2 3\n1 2 4 5\n1 2 1 3 2 3",
"output": "-1"
},
{
"input": "2 1\n1 2 1 3\n1 2",
"output": "1"
},
{
"input": "4 4\n1 2 3 4 5 6 7 8\n2 3 4 5 6 7 8 1",... | 1,529,171,705 | 4,805 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 77 | 0 | n , m = map(int,input().split())
l = [int(x) for x in input().split()]
k = [int(x) for x in input().split()]
o = 0
d = []
def divide_chunks(l, n):
for i in range(0, len(l), n):
yield l[i:i + n]
x = list(divide_chunks(l, 2))
y = list(divide_chunks(k, 2))
for i in x:
if i in y:
x.remove(i)
y.remove(i)
o = ( ', '.join(str(u) for u in x))
p = (', '.join(str(u) for u in y))
if o!=p:
for i in o:
if i in p and i!='[' and i!=']' and i!=',' and i!=' ':
d.append(i)
if len(d)>=2:
print('0')
elif len(o)!=len(p):
print('-1')
elif len(d)==1:
print(' '.join(d))
| Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two participants are each given a pair of distinct numbers from 1 to 9 such that there's exactly one number that is present in both pairs. They want to figure out the number that matches by using a communication channel you have access to without revealing it to you.
Both participants communicated to each other a set of pairs of numbers, that includes the pair given to them. Each pair in the communicated sets comprises two different numbers.
Determine if you can with certainty deduce the common number, or if you can determine with certainty that both participants know the number but you do not.
Input Specification:
The first line contains two integers $n$ and $m$ ($1 \le n, m \le 12$) — the number of pairs the first participant communicated to the second and vice versa.
The second line contains $n$ pairs of integers, each between $1$ and $9$, — pairs of numbers communicated from first participant to the second.
The third line contains $m$ pairs of integers, each between $1$ and $9$, — pairs of numbers communicated from the second participant to the first.
All pairs within each set are distinct (in particular, if there is a pair $(1,2)$, there will be no pair $(2,1)$ within the same set), and no pair contains the same number twice.
It is guaranteed that the two sets do not contradict the statements, in other words, there is pair from the first set and a pair from the second set that share exactly one number.
Output Specification:
If you can deduce the shared number with certainty, print that number.
If you can with certainty deduce that both participants know the shared number, but you do not know it, print $0$.
Otherwise print $-1$.
Demo Input:
['2 2\n1 2 3 4\n1 5 3 4\n', '2 2\n1 2 3 4\n1 5 6 4\n', '2 3\n1 2 4 5\n1 2 1 3 2 3\n']
Demo Output:
['1\n', '0\n', '-1\n']
Note:
In the first example the first participant communicated pairs $(1,2)$ and $(3,4)$, and the second communicated $(1,5)$, $(3,4)$. Since we know that the actual pairs they received share exactly one number, it can't be that they both have $(3,4)$. Thus, the first participant has $(1,2)$ and the second has $(1,5)$, and at this point you already know the shared number is $1$.
In the second example either the first participant has $(1,2)$ and the second has $(1,5)$, or the first has $(3,4)$ and the second has $(6,4)$. In the first case both of them know the shared number is $1$, in the second case both of them know the shared number is $4$. You don't have enough information to tell $1$ and $4$ apart.
In the third case if the first participant was given $(1,2)$, they don't know what the shared number is, since from their perspective the second participant might have been given either $(1,3)$, in which case the shared number is $1$, or $(2,3)$, in which case the shared number is $2$. While the second participant does know the number with certainty, neither you nor the first participant do, so the output is $-1$. | ```python
n , m = map(int,input().split())
l = [int(x) for x in input().split()]
k = [int(x) for x in input().split()]
o = 0
d = []
def divide_chunks(l, n):
for i in range(0, len(l), n):
yield l[i:i + n]
x = list(divide_chunks(l, 2))
y = list(divide_chunks(k, 2))
for i in x:
if i in y:
x.remove(i)
y.remove(i)
o = ( ', '.join(str(u) for u in x))
p = (', '.join(str(u) for u in y))
if o!=p:
for i in o:
if i in p and i!='[' and i!=']' and i!=',' and i!=' ':
d.append(i)
if len(d)>=2:
print('0')
elif len(o)!=len(p):
print('-1')
elif len(d)==1:
print(' '.join(d))
``` | 0 | |
677 | A | Vanya and Fence | PROGRAMMING | 800 | [
"implementation"
] | null | null | Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some person is greater than *h* he can bend down and then he surely won't be noticed by the guard. The height of the *i*-th person is equal to *a**i*.
Consider the width of the person walking as usual to be equal to 1, while the width of the bent person is equal to 2. Friends want to talk to each other while walking, so they would like to walk in a single row. What is the minimum width of the road, such that friends can walk in a row and remain unattended by the guard? | The first line of the input contains two integers *n* and *h* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=1000) — the number of friends and the height of the fence, respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=2*h*), the *i*-th of them is equal to the height of the *i*-th person. | Print a single integer — the minimum possible valid width of the road. | [
"3 7\n4 5 14\n",
"6 1\n1 1 1 1 1 1\n",
"6 5\n7 6 8 9 10 5\n"
] | [
"4\n",
"6\n",
"11\n"
] | In the first sample, only person number 3 must bend down, so the required width is equal to 1 + 1 + 2 = 4.
In the second sample, all friends are short enough and no one has to bend, so the width 1 + 1 + 1 + 1 + 1 + 1 = 6 is enough.
In the third sample, all the persons have to bend, except the last one. The required minimum width of the road is equal to 2 + 2 + 2 + 2 + 2 + 1 = 11. | 500 | [
{
"input": "3 7\n4 5 14",
"output": "4"
},
{
"input": "6 1\n1 1 1 1 1 1",
"output": "6"
},
{
"input": "6 5\n7 6 8 9 10 5",
"output": "11"
},
{
"input": "10 420\n214 614 297 675 82 740 174 23 255 15",
"output": "13"
},
{
"input": "10 561\n657 23 1096 487 785 66 481... | 1,694,087,554 | 2,147,483,647 | Python 3 | OK | TESTS | 29 | 46 | 0 | n , h = map(int, input().split())
l = list(map(int, input().split()))
width = n
for i in l:
if i > h:
width += 1
print(width) | Title: Vanya and Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vanya and his friends are walking along the fence of height *h* and they do not want the guard to notice them. In order to achieve this the height of each of the friends should not exceed *h*. If the height of some person is greater than *h* he can bend down and then he surely won't be noticed by the guard. The height of the *i*-th person is equal to *a**i*.
Consider the width of the person walking as usual to be equal to 1, while the width of the bent person is equal to 2. Friends want to talk to each other while walking, so they would like to walk in a single row. What is the minimum width of the road, such that friends can walk in a row and remain unattended by the guard?
Input Specification:
The first line of the input contains two integers *n* and *h* (1<=≤<=*n*<=≤<=1000, 1<=≤<=*h*<=≤<=1000) — the number of friends and the height of the fence, respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=2*h*), the *i*-th of them is equal to the height of the *i*-th person.
Output Specification:
Print a single integer — the minimum possible valid width of the road.
Demo Input:
['3 7\n4 5 14\n', '6 1\n1 1 1 1 1 1\n', '6 5\n7 6 8 9 10 5\n']
Demo Output:
['4\n', '6\n', '11\n']
Note:
In the first sample, only person number 3 must bend down, so the required width is equal to 1 + 1 + 2 = 4.
In the second sample, all friends are short enough and no one has to bend, so the width 1 + 1 + 1 + 1 + 1 + 1 = 6 is enough.
In the third sample, all the persons have to bend, except the last one. The required minimum width of the road is equal to 2 + 2 + 2 + 2 + 2 + 1 = 11. | ```python
n , h = map(int, input().split())
l = list(map(int, input().split()))
width = n
for i in l:
if i > h:
width += 1
print(width)
``` | 3 | |
131 | A | cAPS lOCK | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentally switched on, if:
- either it only contains uppercase letters; - or all letters except for the first one are uppercase.
In this case we should automatically change the case of all letters. For example, the case of the letters that form words "hELLO", "HTTP", "z" should be changed.
Write a program that applies the rule mentioned above. If the rule cannot be applied, the program should leave the word unchanged. | The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive. | Print the result of the given word's processing. | [
"cAPS\n",
"Lock\n"
] | [
"Caps",
"Lock\n"
] | none | 500 | [
{
"input": "cAPS",
"output": "Caps"
},
{
"input": "Lock",
"output": "Lock"
},
{
"input": "cAPSlOCK",
"output": "cAPSlOCK"
},
{
"input": "CAPs",
"output": "CAPs"
},
{
"input": "LoCK",
"output": "LoCK"
},
{
"input": "OOPS",
"output": "oops"
},
{
... | 1,698,558,583 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 31 | 0 | s=input()
print([s,s.capitalize()][s[1:]==s[1:].upper()]) | Title: cAPS lOCK
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
wHAT DO WE NEED cAPS LOCK FOR?
Caps lock is a computer keyboard key. Pressing it sets an input mode in which typed letters are capital by default. If it is pressed by accident, it leads to accidents like the one we had in the first passage.
Let's consider that a word has been typed with the Caps lock key accidentally switched on, if:
- either it only contains uppercase letters; - or all letters except for the first one are uppercase.
In this case we should automatically change the case of all letters. For example, the case of the letters that form words "hELLO", "HTTP", "z" should be changed.
Write a program that applies the rule mentioned above. If the rule cannot be applied, the program should leave the word unchanged.
Input Specification:
The first line of the input data contains a word consisting of uppercase and lowercase Latin letters. The word's length is from 1 to 100 characters, inclusive.
Output Specification:
Print the result of the given word's processing.
Demo Input:
['cAPS\n', 'Lock\n']
Demo Output:
['Caps', 'Lock\n']
Note:
none | ```python
s=input()
print([s,s.capitalize()][s[1:]==s[1:].upper()])
``` | 0 | |
919 | A | Supermarket | PROGRAMMING | 800 | [
"brute force",
"greedy",
"implementation"
] | null | null | We often go to supermarkets to buy some fruits or vegetables, and on the tag there prints the price for a kilo. But in some supermarkets, when asked how much the items are, the clerk will say that $a$ yuan for $b$ kilos (You don't need to care about what "yuan" is), the same as $a/b$ yuan for a kilo.
Now imagine you'd like to buy $m$ kilos of apples. You've asked $n$ supermarkets and got the prices. Find the minimum cost for those apples.
You can assume that there are enough apples in all supermarkets. | The first line contains two positive integers $n$ and $m$ ($1 \leq n \leq 5\,000$, $1 \leq m \leq 100$), denoting that there are $n$ supermarkets and you want to buy $m$ kilos of apples.
The following $n$ lines describe the information of the supermarkets. Each line contains two positive integers $a, b$ ($1 \leq a, b \leq 100$), denoting that in this supermarket, you are supposed to pay $a$ yuan for $b$ kilos of apples. | The only line, denoting the minimum cost for $m$ kilos of apples. Please make sure that the absolute or relative error between your answer and the correct answer won't exceed $10^{-6}$.
Formally, let your answer be $x$, and the jury's answer be $y$. Your answer is considered correct if $\frac{|x - y|}{\max{(1, |y|)}} \le 10^{-6}$. | [
"3 5\n1 2\n3 4\n1 3\n",
"2 1\n99 100\n98 99\n"
] | [
"1.66666667\n",
"0.98989899\n"
] | In the first sample, you are supposed to buy $5$ kilos of apples in supermarket $3$. The cost is $5/3$ yuan.
In the second sample, you are supposed to buy $1$ kilo of apples in supermarket $2$. The cost is $98/99$ yuan. | 500 | [
{
"input": "3 5\n1 2\n3 4\n1 3",
"output": "1.66666667"
},
{
"input": "2 1\n99 100\n98 99",
"output": "0.98989899"
},
{
"input": "50 37\n78 49\n96 4\n86 62\n28 4\n19 2\n79 43\n79 92\n95 35\n33 60\n54 84\n90 25\n2 25\n53 21\n86 52\n72 25\n6 78\n41 46\n3 68\n42 89\n33 35\n57 43\n99 45\n1 8... | 1,654,537,940 | 2,147,483,647 | Python 3 | OK | TESTS | 43 | 46 | 0 | n,m = list(map(int,input().split()))
lst = []
for nt in range(n):
st = list(map(int,input().split()))
lst.append(st[0]/st[1])
print(min(lst)*m)
| Title: Supermarket
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We often go to supermarkets to buy some fruits or vegetables, and on the tag there prints the price for a kilo. But in some supermarkets, when asked how much the items are, the clerk will say that $a$ yuan for $b$ kilos (You don't need to care about what "yuan" is), the same as $a/b$ yuan for a kilo.
Now imagine you'd like to buy $m$ kilos of apples. You've asked $n$ supermarkets and got the prices. Find the minimum cost for those apples.
You can assume that there are enough apples in all supermarkets.
Input Specification:
The first line contains two positive integers $n$ and $m$ ($1 \leq n \leq 5\,000$, $1 \leq m \leq 100$), denoting that there are $n$ supermarkets and you want to buy $m$ kilos of apples.
The following $n$ lines describe the information of the supermarkets. Each line contains two positive integers $a, b$ ($1 \leq a, b \leq 100$), denoting that in this supermarket, you are supposed to pay $a$ yuan for $b$ kilos of apples.
Output Specification:
The only line, denoting the minimum cost for $m$ kilos of apples. Please make sure that the absolute or relative error between your answer and the correct answer won't exceed $10^{-6}$.
Formally, let your answer be $x$, and the jury's answer be $y$. Your answer is considered correct if $\frac{|x - y|}{\max{(1, |y|)}} \le 10^{-6}$.
Demo Input:
['3 5\n1 2\n3 4\n1 3\n', '2 1\n99 100\n98 99\n']
Demo Output:
['1.66666667\n', '0.98989899\n']
Note:
In the first sample, you are supposed to buy $5$ kilos of apples in supermarket $3$. The cost is $5/3$ yuan.
In the second sample, you are supposed to buy $1$ kilo of apples in supermarket $2$. The cost is $98/99$ yuan. | ```python
n,m = list(map(int,input().split()))
lst = []
for nt in range(n):
st = list(map(int,input().split()))
lst.append(st[0]/st[1])
print(min(lst)*m)
``` | 3 | |
915 | B | Browser | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Luba is surfing the Internet. She currently has *n* opened tabs in her browser, indexed from 1 to *n* from left to right. The mouse cursor is currently located at the *pos*-th tab. Luba needs to use the tabs with indices from *l* to *r* (inclusive) for her studies, and she wants to close all the tabs that don't belong to this segment as fast as possible.
Each second Luba can either try moving the cursor to the left or to the right (if the cursor is currently at the tab *i*, then she can move it to the tab *max*(*i*<=-<=1,<=*a*) or to the tab *min*(*i*<=+<=1,<=*b*)) or try closing all the tabs to the left or to the right of the cursor (if the cursor is currently at the tab *i*, she can close all the tabs with indices from segment [*a*,<=*i*<=-<=1] or from segment [*i*<=+<=1,<=*b*]). In the aforementioned expressions *a* and *b* denote the minimum and maximum index of an unclosed tab, respectively. For example, if there were 7 tabs initially and tabs 1, 2 and 7 are closed, then *a*<==<=3, *b*<==<=6.
What is the minimum number of seconds Luba has to spend in order to leave only the tabs with initial indices from *l* to *r* inclusive opened? | The only line of input contains four integer numbers *n*, *pos*, *l*, *r* (1<=≤<=*n*<=≤<=100, 1<=≤<=*pos*<=≤<=*n*, 1<=≤<=*l*<=≤<=*r*<=≤<=*n*) — the number of the tabs, the cursor position and the segment which Luba needs to leave opened. | Print one integer equal to the minimum number of seconds required to close all the tabs outside the segment [*l*,<=*r*]. | [
"6 3 2 4\n",
"6 3 1 3\n",
"5 2 1 5\n"
] | [
"5\n",
"1\n",
"0\n"
] | In the first test Luba can do the following operations: shift the mouse cursor to the tab 2, close all the tabs to the left of it, shift the mouse cursor to the tab 3, then to the tab 4, and then close all the tabs to the right of it.
In the second test she only needs to close all the tabs to the right of the current position of the cursor.
In the third test Luba doesn't need to do anything. | 0 | [
{
"input": "6 3 2 4",
"output": "5"
},
{
"input": "6 3 1 3",
"output": "1"
},
{
"input": "5 2 1 5",
"output": "0"
},
{
"input": "100 1 1 99",
"output": "99"
},
{
"input": "100 50 1 99",
"output": "50"
},
{
"input": "100 99 1 99",
"output": "1"
},... | 1,516,354,424 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 5,632,000 | import sys
a = list(map(int,input().split()))
n,pos,l,r = a[0],a[1],a[2],a[3]
res = 0
if l != 1 and r != n and l <= pos and pos <= r :
res = min( pos - l + 1 + r - l + 1, r - pos + 1 + r - l + 1 )
elif l == 1 and r != n:
res = abs(r - pos) + 1
elif r == n and l != 1:
res = abs(l - pos) + 1 | Title: Browser
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Luba is surfing the Internet. She currently has *n* opened tabs in her browser, indexed from 1 to *n* from left to right. The mouse cursor is currently located at the *pos*-th tab. Luba needs to use the tabs with indices from *l* to *r* (inclusive) for her studies, and she wants to close all the tabs that don't belong to this segment as fast as possible.
Each second Luba can either try moving the cursor to the left or to the right (if the cursor is currently at the tab *i*, then she can move it to the tab *max*(*i*<=-<=1,<=*a*) or to the tab *min*(*i*<=+<=1,<=*b*)) or try closing all the tabs to the left or to the right of the cursor (if the cursor is currently at the tab *i*, she can close all the tabs with indices from segment [*a*,<=*i*<=-<=1] or from segment [*i*<=+<=1,<=*b*]). In the aforementioned expressions *a* and *b* denote the minimum and maximum index of an unclosed tab, respectively. For example, if there were 7 tabs initially and tabs 1, 2 and 7 are closed, then *a*<==<=3, *b*<==<=6.
What is the minimum number of seconds Luba has to spend in order to leave only the tabs with initial indices from *l* to *r* inclusive opened?
Input Specification:
The only line of input contains four integer numbers *n*, *pos*, *l*, *r* (1<=≤<=*n*<=≤<=100, 1<=≤<=*pos*<=≤<=*n*, 1<=≤<=*l*<=≤<=*r*<=≤<=*n*) — the number of the tabs, the cursor position and the segment which Luba needs to leave opened.
Output Specification:
Print one integer equal to the minimum number of seconds required to close all the tabs outside the segment [*l*,<=*r*].
Demo Input:
['6 3 2 4\n', '6 3 1 3\n', '5 2 1 5\n']
Demo Output:
['5\n', '1\n', '0\n']
Note:
In the first test Luba can do the following operations: shift the mouse cursor to the tab 2, close all the tabs to the left of it, shift the mouse cursor to the tab 3, then to the tab 4, and then close all the tabs to the right of it.
In the second test she only needs to close all the tabs to the right of the current position of the cursor.
In the third test Luba doesn't need to do anything. | ```python
import sys
a = list(map(int,input().split()))
n,pos,l,r = a[0],a[1],a[2],a[3]
res = 0
if l != 1 and r != n and l <= pos and pos <= r :
res = min( pos - l + 1 + r - l + 1, r - pos + 1 + r - l + 1 )
elif l == 1 and r != n:
res = abs(r - pos) + 1
elif r == n and l != 1:
res = abs(l - pos) + 1
``` | 0 | |
182 | B | Vasya's Calendar | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Vasya lives in a strange world. The year has *n* months and the *i*-th month has *a**i* days. Vasya got a New Year present — the clock that shows not only the time, but also the date.
The clock's face can display any number from 1 to *d*. It is guaranteed that *a**i*<=≤<=*d* for all *i* from 1 to *n*. The clock does not keep information about the current month, so when a new day comes, it simply increases the current day number by one. The clock cannot display number *d*<=+<=1, so after day number *d* it shows day 1 (the current day counter resets). The mechanism of the clock allows you to increase the day number by one manually. When you execute this operation, day *d* is also followed by day 1.
Vasya begins each day checking the day number on the clock. If the day number on the clock does not match the actual day number in the current month, then Vasya manually increases it by one. Vasya is persistent and repeats this operation until the day number on the clock matches the actual number of the current day in the current month.
A year passed and Vasya wonders how many times he manually increased the day number by one, from the first day of the first month to the last day of the *n*-th month inclusive, considering that on the first day of the first month the clock display showed day 1. | The first line contains the single number *d* — the maximum number of the day that Vasya's clock can show (1<=≤<=*d*<=≤<=106).
The second line contains a single integer *n* — the number of months in the year (1<=≤<=*n*<=≤<=2000).
The third line contains *n* space-separated integers: *a**i* (1<=≤<=*a**i*<=≤<=*d*) — the number of days in each month in the order in which they follow, starting from the first one. | Print a single number — the number of times Vasya manually increased the day number by one throughout the last year. | [
"4\n2\n2 2\n",
"5\n3\n3 4 3\n",
"31\n12\n31 28 31 30 31 30 31 31 30 31 30 31\n"
] | [
"2\n",
"3\n",
"7\n"
] | In the first sample the situation is like this:
- Day 1. Month 1. The clock shows 1. Vasya changes nothing. - Day 2. Month 1. The clock shows 2. Vasya changes nothing. - Day 1. Month 2. The clock shows 3. Vasya manually increases the day number by 1. After that the clock shows 4. Vasya increases the day number by 1 manually. After that the clock shows 1. - Day 2. Month 2. The clock shows 2. Vasya changes nothing. | 500 | [
{
"input": "4\n2\n2 2",
"output": "2"
},
{
"input": "5\n3\n3 4 3",
"output": "3"
},
{
"input": "31\n12\n31 28 31 30 31 30 31 31 30 31 30 31",
"output": "7"
},
{
"input": "1\n1\n1",
"output": "0"
},
{
"input": "1\n2\n1 1",
"output": "0"
},
{
"input": "2... | 1,647,265,053 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 92 | 0 |
def solve() :
c=0
for i in arr[:-1]:
c+= d - i
return c
d=int(input())
n=int(input())
arr=[int(x) for x in input().split()]
print(solve())
'''
t=int(input())
for i in range(t) :
print(solve())
n,m= [int(x) for x in input().split()]
n=int(input())
arr=[]
for i in range(n):
arr.append([int(x) for x in input().split()])
n=int(input())
arr=[int(x) for x in input().split()]
''' | Title: Vasya's Calendar
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya lives in a strange world. The year has *n* months and the *i*-th month has *a**i* days. Vasya got a New Year present — the clock that shows not only the time, but also the date.
The clock's face can display any number from 1 to *d*. It is guaranteed that *a**i*<=≤<=*d* for all *i* from 1 to *n*. The clock does not keep information about the current month, so when a new day comes, it simply increases the current day number by one. The clock cannot display number *d*<=+<=1, so after day number *d* it shows day 1 (the current day counter resets). The mechanism of the clock allows you to increase the day number by one manually. When you execute this operation, day *d* is also followed by day 1.
Vasya begins each day checking the day number on the clock. If the day number on the clock does not match the actual day number in the current month, then Vasya manually increases it by one. Vasya is persistent and repeats this operation until the day number on the clock matches the actual number of the current day in the current month.
A year passed and Vasya wonders how many times he manually increased the day number by one, from the first day of the first month to the last day of the *n*-th month inclusive, considering that on the first day of the first month the clock display showed day 1.
Input Specification:
The first line contains the single number *d* — the maximum number of the day that Vasya's clock can show (1<=≤<=*d*<=≤<=106).
The second line contains a single integer *n* — the number of months in the year (1<=≤<=*n*<=≤<=2000).
The third line contains *n* space-separated integers: *a**i* (1<=≤<=*a**i*<=≤<=*d*) — the number of days in each month in the order in which they follow, starting from the first one.
Output Specification:
Print a single number — the number of times Vasya manually increased the day number by one throughout the last year.
Demo Input:
['4\n2\n2 2\n', '5\n3\n3 4 3\n', '31\n12\n31 28 31 30 31 30 31 31 30 31 30 31\n']
Demo Output:
['2\n', '3\n', '7\n']
Note:
In the first sample the situation is like this:
- Day 1. Month 1. The clock shows 1. Vasya changes nothing. - Day 2. Month 1. The clock shows 2. Vasya changes nothing. - Day 1. Month 2. The clock shows 3. Vasya manually increases the day number by 1. After that the clock shows 4. Vasya increases the day number by 1 manually. After that the clock shows 1. - Day 2. Month 2. The clock shows 2. Vasya changes nothing. | ```python
def solve() :
c=0
for i in arr[:-1]:
c+= d - i
return c
d=int(input())
n=int(input())
arr=[int(x) for x in input().split()]
print(solve())
'''
t=int(input())
for i in range(t) :
print(solve())
n,m= [int(x) for x in input().split()]
n=int(input())
arr=[]
for i in range(n):
arr.append([int(x) for x in input().split()])
n=int(input())
arr=[int(x) for x in input().split()]
'''
``` | 3 | |
22 | A | Second Order Statistics | PROGRAMMING | 800 | [
"brute force"
] | A. Second Order Statistics | 2 | 256 | Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. Help Bob solve this problem. | The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value. | If the given sequence has the second order statistics, output this order statistics, otherwise output NO. | [
"4\n1 2 2 -4\n",
"5\n1 2 3 1 1\n"
] | [
"1\n",
"2\n"
] | none | 0 | [
{
"input": "4\n1 2 2 -4",
"output": "1"
},
{
"input": "5\n1 2 3 1 1",
"output": "2"
},
{
"input": "1\n28",
"output": "NO"
},
{
"input": "2\n-28 12",
"output": "12"
},
{
"input": "3\n-83 40 -80",
"output": "-80"
},
{
"input": "8\n93 77 -92 26 21 -48 53 ... | 1,618,896,437 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 122 | 0 | x=int(input())
p=101
q=101
arr=[int(x) for x in input().split()]
for n in arr:
#n=int(input())
if n<p:
q=p
p=n
elif(n!=p and n<q):
q=n
if(q==101):
print("No")
else:
print(q)
| Title: Second Order Statistics
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Once Bob needed to find the second order statistics of a sequence of integer numbers. Lets choose each number from the sequence exactly once and sort them. The value on the second position is the second order statistics of the given sequence. In other words it is the smallest element strictly greater than the minimum. Help Bob solve this problem.
Input Specification:
The first input line contains integer *n* (1<=≤<=*n*<=≤<=100) — amount of numbers in the sequence. The second line contains *n* space-separated integer numbers — elements of the sequence. These numbers don't exceed 100 in absolute value.
Output Specification:
If the given sequence has the second order statistics, output this order statistics, otherwise output NO.
Demo Input:
['4\n1 2 2 -4\n', '5\n1 2 3 1 1\n']
Demo Output:
['1\n', '2\n']
Note:
none | ```python
x=int(input())
p=101
q=101
arr=[int(x) for x in input().split()]
for n in arr:
#n=int(input())
if n<p:
q=p
p=n
elif(n!=p and n<q):
q=n
if(q==101):
print("No")
else:
print(q)
``` | 0 |
197 | B | Limit | PROGRAMMING | 1,400 | [
"math"
] | null | null | You are given two polynomials:
- *P*(*x*)<==<=*a*0·*x**n*<=+<=*a*1·*x**n*<=-<=1<=+<=...<=+<=*a**n*<=-<=1·*x*<=+<=*a**n* and - *Q*(*x*)<==<=*b*0·*x**m*<=+<=*b*1·*x**m*<=-<=1<=+<=...<=+<=*b**m*<=-<=1·*x*<=+<=*b**m*.
Calculate limit . | The first line contains two space-separated integers *n* and *m* (0<=≤<=*n*,<=*m*<=≤<=100) — degrees of polynomials *P*(*x*) and *Q*(*x*) correspondingly.
The second line contains *n*<=+<=1 space-separated integers — the factors of polynomial *P*(*x*): *a*0, *a*1, ..., *a**n*<=-<=1, *a**n* (<=-<=100<=≤<=*a**i*<=≤<=100,<=*a*0<=≠<=0).
The third line contains *m*<=+<=1 space-separated integers — the factors of polynomial *Q*(*x*): *b*0, *b*1, ..., *b**m*<=-<=1, *b**m* (<=-<=100<=≤<=*b**i*<=≤<=100,<=*b*0<=≠<=0). | If the limit equals <=+<=∞, print "Infinity" (without quotes). If the limit equals <=-<=∞, print "-Infinity" (without the quotes).
If the value of the limit equals zero, print "0/1" (without the quotes).
Otherwise, print an irreducible fraction — the value of limit , in the format "p/q" (without the quotes), where *p* is the — numerator, *q* (*q*<=><=0) is the denominator of the fraction. | [
"2 1\n1 1 1\n2 5\n",
"1 0\n-1 3\n2\n",
"0 1\n1\n1 0\n",
"2 2\n2 1 6\n4 5 -7\n",
"1 1\n9 0\n-5 2\n"
] | [
"Infinity\n",
"-Infinity\n",
"0/1\n",
"1/2\n",
"-9/5\n"
] | Let's consider all samples:
1. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c28febca257452afdfcbd6984ba8623911f9bdbc.png" style="max-width: 100.0%;max-height: 100.0%;"/> 1. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/1e55ecd04e54a45e5e0092ec9a5c1ea03bb29255.png" style="max-width: 100.0%;max-height: 100.0%;"/> 1. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/2c95fb684d373fcc1a481cfabeda4d5c2f3673ee.png" style="max-width: 100.0%;max-height: 100.0%;"/> 1. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4dc40cb8b3cd6375c42445366e50369649a2801a.png" style="max-width: 100.0%;max-height: 100.0%;"/> 1. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c6455aba35cfb3c4397505121d1f77afcd17c98e.png" style="max-width: 100.0%;max-height: 100.0%;"/>
You can learn more about the definition and properties of limits if you follow the link: http://en.wikipedia.org/wiki/Limit_of_a_function | 500 | [
{
"input": "2 1\n1 1 1\n2 5",
"output": "Infinity"
},
{
"input": "1 0\n-1 3\n2",
"output": "-Infinity"
},
{
"input": "0 1\n1\n1 0",
"output": "0/1"
},
{
"input": "2 2\n2 1 6\n4 5 -7",
"output": "1/2"
},
{
"input": "1 1\n9 0\n-5 2",
"output": "-9/5"
},
{
... | 1,636,914,240 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 7 | 62 | 0 | import sys
import math
from sys import stdin, stdout
# TAKE INPUT
def get_ints_in_variables():
return map(int, sys.stdin.readline().strip().split())
def get_int(): return int(input())
def get_ints_in_list(): return list(
map(int, sys.stdin.readline().strip().split()))
def get_list_of_list(n): return [list(
map(int, sys.stdin.readline().strip().split())) for _ in range(n)]
def get_string(): return sys.stdin.readline().strip()
def main():
# Write Your Code Here
n, m = get_ints_in_variables()
px = get_ints_in_list()
qx = get_ints_in_list()
if n > m:
if (qx[0] > 0 and px[0] > 0) or (qx[0] < 0 and px < 0):
print("Infinity")
else:
print("-Infinity")
elif m > n:
print("0/1")
else:
tmp = math.gcd(px[0], qx[0])
px[0] //= tmp
qx[0] //= tmp
if (qx[0] > 0 and px[0] > 0) or (qx[0] < 0 and px[0] < 0):
res = ""
res += str(px[0])
res += "/"
res += str(qx[0])
print(res)
else:
res = "-"
res += str(abs(px[0]))
res += "/"
res += str(abs(qx[0]))
print(res)
# calling main Function
if __name__ == "__main__":
main() | Title: Limit
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two polynomials:
- *P*(*x*)<==<=*a*0·*x**n*<=+<=*a*1·*x**n*<=-<=1<=+<=...<=+<=*a**n*<=-<=1·*x*<=+<=*a**n* and - *Q*(*x*)<==<=*b*0·*x**m*<=+<=*b*1·*x**m*<=-<=1<=+<=...<=+<=*b**m*<=-<=1·*x*<=+<=*b**m*.
Calculate limit .
Input Specification:
The first line contains two space-separated integers *n* and *m* (0<=≤<=*n*,<=*m*<=≤<=100) — degrees of polynomials *P*(*x*) and *Q*(*x*) correspondingly.
The second line contains *n*<=+<=1 space-separated integers — the factors of polynomial *P*(*x*): *a*0, *a*1, ..., *a**n*<=-<=1, *a**n* (<=-<=100<=≤<=*a**i*<=≤<=100,<=*a*0<=≠<=0).
The third line contains *m*<=+<=1 space-separated integers — the factors of polynomial *Q*(*x*): *b*0, *b*1, ..., *b**m*<=-<=1, *b**m* (<=-<=100<=≤<=*b**i*<=≤<=100,<=*b*0<=≠<=0).
Output Specification:
If the limit equals <=+<=∞, print "Infinity" (without quotes). If the limit equals <=-<=∞, print "-Infinity" (without the quotes).
If the value of the limit equals zero, print "0/1" (without the quotes).
Otherwise, print an irreducible fraction — the value of limit , in the format "p/q" (without the quotes), where *p* is the — numerator, *q* (*q*<=><=0) is the denominator of the fraction.
Demo Input:
['2 1\n1 1 1\n2 5\n', '1 0\n-1 3\n2\n', '0 1\n1\n1 0\n', '2 2\n2 1 6\n4 5 -7\n', '1 1\n9 0\n-5 2\n']
Demo Output:
['Infinity\n', '-Infinity\n', '0/1\n', '1/2\n', '-9/5\n']
Note:
Let's consider all samples:
1. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c28febca257452afdfcbd6984ba8623911f9bdbc.png" style="max-width: 100.0%;max-height: 100.0%;"/> 1. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/1e55ecd04e54a45e5e0092ec9a5c1ea03bb29255.png" style="max-width: 100.0%;max-height: 100.0%;"/> 1. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/2c95fb684d373fcc1a481cfabeda4d5c2f3673ee.png" style="max-width: 100.0%;max-height: 100.0%;"/> 1. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/4dc40cb8b3cd6375c42445366e50369649a2801a.png" style="max-width: 100.0%;max-height: 100.0%;"/> 1. <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c6455aba35cfb3c4397505121d1f77afcd17c98e.png" style="max-width: 100.0%;max-height: 100.0%;"/>
You can learn more about the definition and properties of limits if you follow the link: http://en.wikipedia.org/wiki/Limit_of_a_function | ```python
import sys
import math
from sys import stdin, stdout
# TAKE INPUT
def get_ints_in_variables():
return map(int, sys.stdin.readline().strip().split())
def get_int(): return int(input())
def get_ints_in_list(): return list(
map(int, sys.stdin.readline().strip().split()))
def get_list_of_list(n): return [list(
map(int, sys.stdin.readline().strip().split())) for _ in range(n)]
def get_string(): return sys.stdin.readline().strip()
def main():
# Write Your Code Here
n, m = get_ints_in_variables()
px = get_ints_in_list()
qx = get_ints_in_list()
if n > m:
if (qx[0] > 0 and px[0] > 0) or (qx[0] < 0 and px < 0):
print("Infinity")
else:
print("-Infinity")
elif m > n:
print("0/1")
else:
tmp = math.gcd(px[0], qx[0])
px[0] //= tmp
qx[0] //= tmp
if (qx[0] > 0 and px[0] > 0) or (qx[0] < 0 and px[0] < 0):
res = ""
res += str(px[0])
res += "/"
res += str(qx[0])
print(res)
else:
res = "-"
res += str(abs(px[0]))
res += "/"
res += str(abs(qx[0]))
print(res)
# calling main Function
if __name__ == "__main__":
main()
``` | -1 | |
2 | A | Winner | PROGRAMMING | 1,500 | [
"hashing",
"implementation"
] | A. Winner | 1 | 64 | The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a player gains or loses a particular number of points. In the course of the game the number of points is registered in the line "name score", where name is a player's name, and score is the number of points gained in this round, which is an integer number. If score is negative, this means that the player has lost in the round. So, if two or more players have the maximum number of points (say, it equals to *m*) at the end of the game, than wins the one of them who scored at least *m* points first. Initially each player has 0 points. It's guaranteed that at the end of the game at least one player has a positive number of points. | The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is an integer number between -1000 and 1000, inclusive. | Print the name of the winner. | [
"3\nmike 3\nandrew 5\nmike 2\n",
"3\nandrew 3\nandrew 2\nmike 5\n"
] | [
"andrew\n",
"andrew\n"
] | none | 0 | [
{
"input": "3\nmike 3\nandrew 5\nmike 2",
"output": "andrew"
},
{
"input": "3\nandrew 3\nandrew 2\nmike 5",
"output": "andrew"
},
{
"input": "5\nkaxqybeultn -352\nmgochgrmeyieyskhuourfg -910\nkaxqybeultn 691\nmgochgrmeyieyskhuourfg -76\nkaxqybeultn -303",
"output": "kaxqybeultn"
},... | 1,602,514,573 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 186 | 307,200 | n = int(input())
inp = []
users = {}
for elem in range(n):
a = input().split()
a[1] = int(a[1])
inp.append(a)
if users.get(a[0]):
users[a[0]] += a[1]
else:
users[a[0]] = a[1]
# print(inp)
# print(users)
max = -1000000000000000001
user = ''
count_max = 0
for i in users:
if max < users[i]:
max = users[i]
user = i
count_max = 1
elif max == users[i]:
count_max += 1
if count_max == 1:
print(user)
else:
users.clear()
for i in inp:
if users.get(i[0]):
users[i[0]] += i[1]
else:
users[i[0]] = i[1]
if users[i[0]] >= max:
print(i[0])
break | Title: Winner
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a player gains or loses a particular number of points. In the course of the game the number of points is registered in the line "name score", where name is a player's name, and score is the number of points gained in this round, which is an integer number. If score is negative, this means that the player has lost in the round. So, if two or more players have the maximum number of points (say, it equals to *m*) at the end of the game, than wins the one of them who scored at least *m* points first. Initially each player has 0 points. It's guaranteed that at the end of the game at least one player has a positive number of points.
Input Specification:
The first line contains an integer number *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000), *n* is the number of rounds played. Then follow *n* lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is an integer number between -1000 and 1000, inclusive.
Output Specification:
Print the name of the winner.
Demo Input:
['3\nmike 3\nandrew 5\nmike 2\n', '3\nandrew 3\nandrew 2\nmike 5\n']
Demo Output:
['andrew\n', 'andrew\n']
Note:
none | ```python
n = int(input())
inp = []
users = {}
for elem in range(n):
a = input().split()
a[1] = int(a[1])
inp.append(a)
if users.get(a[0]):
users[a[0]] += a[1]
else:
users[a[0]] = a[1]
# print(inp)
# print(users)
max = -1000000000000000001
user = ''
count_max = 0
for i in users:
if max < users[i]:
max = users[i]
user = i
count_max = 1
elif max == users[i]:
count_max += 1
if count_max == 1:
print(user)
else:
users.clear()
for i in inp:
if users.get(i[0]):
users[i[0]] += i[1]
else:
users[i[0]] = i[1]
if users[i[0]] >= max:
print(i[0])
break
``` | 0 |
772 | B | Volatile Kite | PROGRAMMING | 1,800 | [
"geometry"
] | null | null | You are given a convex polygon *P* with *n* distinct vertices *p*1,<=*p*2,<=...,<=*p**n*. Vertex *p**i* has coordinates (*x**i*,<=*y**i*) in the 2D plane. These vertices are listed in clockwise order.
You can choose a real number *D* and move each vertex of the polygon a distance of at most *D* from their original positions.
Find the maximum value of *D* such that no matter how you move the vertices, the polygon does not intersect itself and stays convex. | The first line has one integer *n* (4<=≤<=*n*<=≤<=1<=000) — the number of vertices.
The next *n* lines contain the coordinates of the vertices. Line *i* contains two integers *x**i* and *y**i* (<=-<=109<=≤<=*x**i*,<=*y**i*<=≤<=109) — the coordinates of the *i*-th vertex. These points are guaranteed to be given in clockwise order, and will form a strictly convex polygon (in particular, no three consecutive points lie on the same straight line). | Print one real number *D*, which is the maximum real number such that no matter how you move the vertices, the polygon stays convex.
Your answer will be considered correct if its absolute or relative error does not exceed 10<=-<=6.
Namely, let's assume that your answer is *a* and the answer of the jury is *b*. The checker program will consider your answer correct if . | [
"4\n0 0\n0 1\n1 1\n1 0\n",
"6\n5 0\n10 0\n12 -4\n10 -8\n5 -8\n3 -4\n"
] | [
"0.3535533906\n",
"1.0000000000\n"
] | Here is a picture of the first sample
<img class="tex-graphics" src="https://espresso.codeforces.com/f83aa076d2f437f9bb785cae769c3ae310eff351.png" style="max-width: 100.0%;max-height: 100.0%;"/>
Here is an example of making the polygon non-convex.
<img class="tex-graphics" src="https://espresso.codeforces.com/fbadb81630251ca642bd4ddf9088876ade761630.png" style="max-width: 100.0%;max-height: 100.0%;"/>
This is not an optimal solution, since the maximum distance we moved one point is ≈ 0.4242640687, whereas we can make it non-convex by only moving each point a distance of at most ≈ 0.3535533906. | 1,000 | [
{
"input": "4\n0 0\n0 1\n1 1\n1 0",
"output": "0.3535533906"
},
{
"input": "6\n5 0\n10 0\n12 -4\n10 -8\n5 -8\n3 -4",
"output": "1.0000000000"
},
{
"input": "19\n449447997 711296339\n530233434 692216537\n535464528 613140435\n535533467 100893188\n530498867 -265063956\n519107979 -271820709\... | 1,492,360,994 | 4,094 | Python 3 | WRONG_ANSWER | PRETESTS | 3 | 62 | 5,529,600 | import math
from decimal import Decimal
n = int(input())
d = [[0,0] for i in range(n)]
for i in range(n):
d[i] = list(map(int,input().split()))
def cnt(m):
l = m - 1;
if (l < 0): l = n - 1;
r = (m + 1) % n
a = math.sqrt((d[l][0] - d[m][0])**2 + (d[l][1] - d[m][1]) ** 2)
b = math.sqrt((d[m][0] - d[r][0]) ** 2 + (d[m][1] - d[r][1]) ** 2)
c = math.sqrt((d[l][0] - d[r][0]) ** 2 + (d[l][1] - d[r][1]) ** 2)
p = (a + b + c) / 2
s = math.sqrt(p * (p - a) * (p - b) * (p - c))
return s / c
ans = cnt(0)
for i in range(1,n):
ans = min(ans, cnt(i))
print(ans) | Title: Volatile Kite
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a convex polygon *P* with *n* distinct vertices *p*1,<=*p*2,<=...,<=*p**n*. Vertex *p**i* has coordinates (*x**i*,<=*y**i*) in the 2D plane. These vertices are listed in clockwise order.
You can choose a real number *D* and move each vertex of the polygon a distance of at most *D* from their original positions.
Find the maximum value of *D* such that no matter how you move the vertices, the polygon does not intersect itself and stays convex.
Input Specification:
The first line has one integer *n* (4<=≤<=*n*<=≤<=1<=000) — the number of vertices.
The next *n* lines contain the coordinates of the vertices. Line *i* contains two integers *x**i* and *y**i* (<=-<=109<=≤<=*x**i*,<=*y**i*<=≤<=109) — the coordinates of the *i*-th vertex. These points are guaranteed to be given in clockwise order, and will form a strictly convex polygon (in particular, no three consecutive points lie on the same straight line).
Output Specification:
Print one real number *D*, which is the maximum real number such that no matter how you move the vertices, the polygon stays convex.
Your answer will be considered correct if its absolute or relative error does not exceed 10<=-<=6.
Namely, let's assume that your answer is *a* and the answer of the jury is *b*. The checker program will consider your answer correct if .
Demo Input:
['4\n0 0\n0 1\n1 1\n1 0\n', '6\n5 0\n10 0\n12 -4\n10 -8\n5 -8\n3 -4\n']
Demo Output:
['0.3535533906\n', '1.0000000000\n']
Note:
Here is a picture of the first sample
<img class="tex-graphics" src="https://espresso.codeforces.com/f83aa076d2f437f9bb785cae769c3ae310eff351.png" style="max-width: 100.0%;max-height: 100.0%;"/>
Here is an example of making the polygon non-convex.
<img class="tex-graphics" src="https://espresso.codeforces.com/fbadb81630251ca642bd4ddf9088876ade761630.png" style="max-width: 100.0%;max-height: 100.0%;"/>
This is not an optimal solution, since the maximum distance we moved one point is ≈ 0.4242640687, whereas we can make it non-convex by only moving each point a distance of at most ≈ 0.3535533906. | ```python
import math
from decimal import Decimal
n = int(input())
d = [[0,0] for i in range(n)]
for i in range(n):
d[i] = list(map(int,input().split()))
def cnt(m):
l = m - 1;
if (l < 0): l = n - 1;
r = (m + 1) % n
a = math.sqrt((d[l][0] - d[m][0])**2 + (d[l][1] - d[m][1]) ** 2)
b = math.sqrt((d[m][0] - d[r][0]) ** 2 + (d[m][1] - d[r][1]) ** 2)
c = math.sqrt((d[l][0] - d[r][0]) ** 2 + (d[l][1] - d[r][1]) ** 2)
p = (a + b + c) / 2
s = math.sqrt(p * (p - a) * (p - b) * (p - c))
return s / c
ans = cnt(0)
for i in range(1,n):
ans = min(ans, cnt(i))
print(ans)
``` | 0 | |
437 | A | The Child and Homework | PROGRAMMING | 1,300 | [
"implementation"
] | null | null | Once upon a time a child got a test consisting of multiple-choice questions as homework. A multiple-choice question consists of four choices: A, B, C and D. Each choice has a description, and the child should find out the only one that is correct.
Fortunately the child knows how to solve such complicated test. The child will follow the algorithm:
- If there is some choice whose description at least twice shorter than all other descriptions, or at least twice longer than all other descriptions, then the child thinks the choice is great. - If there is exactly one great choice then the child chooses it. Otherwise the child chooses C (the child think it is the luckiest choice).
You are given a multiple-choice questions, can you predict child's choose? | The first line starts with "A." (without quotes), then followed the description of choice A. The next three lines contains the descriptions of the other choices in the same format. They are given in order: B, C, D. Please note, that the description goes after prefix "X.", so the prefix mustn't be counted in description's length.
Each description is non-empty and consists of at most 100 characters. Each character can be either uppercase English letter or lowercase English letter, or "_". | Print a single line with the child's choice: "A", "B", "C" or "D" (without quotes). | [
"A.VFleaKing_is_the_author_of_this_problem\nB.Picks_is_the_author_of_this_problem\nC.Picking_is_the_author_of_this_problem\nD.Ftiasch_is_cute\n",
"A.ab\nB.abcde\nC.ab\nD.abc\n",
"A.c\nB.cc\nC.c\nD.c\n"
] | [
"D\n",
"C\n",
"B\n"
] | In the first sample, the first choice has length 39, the second one has length 35, the third one has length 37, and the last one has length 15. The choice D (length 15) is twice shorter than all other choices', so it is great choice. There is no other great choices so the child will choose D.
In the second sample, no choice is great, so the child will choose the luckiest choice C.
In the third sample, the choice B (length 2) is twice longer than all other choices', so it is great choice. There is no other great choices so the child will choose B. | 500 | [
{
"input": "A.VFleaKing_is_the_author_of_this_problem\nB.Picks_is_the_author_of_this_problem\nC.Picking_is_the_author_of_this_problem\nD.Ftiasch_is_cute",
"output": "D"
},
{
"input": "A.ab\nB.abcde\nC.ab\nD.abc",
"output": "C"
},
{
"input": "A.c\nB.cc\nC.c\nD.c",
"output": "B"
},
... | 1,503,461,549 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 62 | 0 | a=['0']*4
b=[""]*4
c=[0]*4
for i in range(4):
a[i],b[i]=map(str,input().split('.'))
c[i]=len(b[i])
c=sorted(c)
x=0
if(c[0]*2<=c[1]):
x=1
if(c[2]*2<=c[3]):
if(x==0):
x=2
else:
x=0
if(x==1):
for i in range(4):
if(len(b[i])==c[0]):
print(a[i])
break
elif(x==2):
for i in range(4):
if(len(b[i])==c[3]):
print(a[i])
break
else:
print('C') | Title: The Child and Homework
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once upon a time a child got a test consisting of multiple-choice questions as homework. A multiple-choice question consists of four choices: A, B, C and D. Each choice has a description, and the child should find out the only one that is correct.
Fortunately the child knows how to solve such complicated test. The child will follow the algorithm:
- If there is some choice whose description at least twice shorter than all other descriptions, or at least twice longer than all other descriptions, then the child thinks the choice is great. - If there is exactly one great choice then the child chooses it. Otherwise the child chooses C (the child think it is the luckiest choice).
You are given a multiple-choice questions, can you predict child's choose?
Input Specification:
The first line starts with "A." (without quotes), then followed the description of choice A. The next three lines contains the descriptions of the other choices in the same format. They are given in order: B, C, D. Please note, that the description goes after prefix "X.", so the prefix mustn't be counted in description's length.
Each description is non-empty and consists of at most 100 characters. Each character can be either uppercase English letter or lowercase English letter, or "_".
Output Specification:
Print a single line with the child's choice: "A", "B", "C" or "D" (without quotes).
Demo Input:
['A.VFleaKing_is_the_author_of_this_problem\nB.Picks_is_the_author_of_this_problem\nC.Picking_is_the_author_of_this_problem\nD.Ftiasch_is_cute\n', 'A.ab\nB.abcde\nC.ab\nD.abc\n', 'A.c\nB.cc\nC.c\nD.c\n']
Demo Output:
['D\n', 'C\n', 'B\n']
Note:
In the first sample, the first choice has length 39, the second one has length 35, the third one has length 37, and the last one has length 15. The choice D (length 15) is twice shorter than all other choices', so it is great choice. There is no other great choices so the child will choose D.
In the second sample, no choice is great, so the child will choose the luckiest choice C.
In the third sample, the choice B (length 2) is twice longer than all other choices', so it is great choice. There is no other great choices so the child will choose B. | ```python
a=['0']*4
b=[""]*4
c=[0]*4
for i in range(4):
a[i],b[i]=map(str,input().split('.'))
c[i]=len(b[i])
c=sorted(c)
x=0
if(c[0]*2<=c[1]):
x=1
if(c[2]*2<=c[3]):
if(x==0):
x=2
else:
x=0
if(x==1):
for i in range(4):
if(len(b[i])==c[0]):
print(a[i])
break
elif(x==2):
for i in range(4):
if(len(b[i])==c[3]):
print(a[i])
break
else:
print('C')
``` | 3 | |
980 | C | Posterized | PROGRAMMING | 1,700 | [
"games",
"greedy"
] | null | null | Professor Ibrahim has prepared the final homework for his algorithm’s class. He asked his students to implement the Posterization Image Filter.
Their algorithm will be tested on an array of integers, where the $i$-th integer represents the color of the $i$-th pixel in the image. The image is in black and white, therefore the color of each pixel will be an integer between 0 and 255 (inclusive).
To implement the filter, students are required to divide the black and white color range [0, 255] into groups of consecutive colors, and select one color in each group to be the group’s key. In order to preserve image details, the size of a group must not be greater than $k$, and each color should belong to exactly one group.
Finally, the students will replace the color of each pixel in the array with that color’s assigned group key.
To better understand the effect, here is an image of a basking turtle where the Posterization Filter was applied with increasing $k$ to the right.
To make the process of checking the final answer easier, Professor Ibrahim wants students to divide the groups and assign the keys in a way that produces the lexicographically smallest possible array. | The first line of input contains two integers $n$ and $k$ ($1 \leq n \leq 10^5$, $1 \leq k \leq 256$), the number of pixels in the image, and the maximum size of a group, respectively.
The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($0 \leq p_i \leq 255$), where $p_i$ is the color of the $i$-th pixel. | Print $n$ space-separated integers; the lexicographically smallest possible array that represents the image after applying the Posterization filter. | [
"4 3\n2 14 3 4\n",
"5 2\n0 2 1 255 254\n"
] | [
"0 12 3 3\n",
"0 1 1 254 254\n"
] | One possible way to group colors and assign keys for the first sample:
Color $2$ belongs to the group $[0,2]$, with group key $0$.
Color $14$ belongs to the group $[12,14]$, with group key $12$.
Colors $3$ and $4$ belong to group $[3, 5]$, with group key $3$.
Other groups won't affect the result so they are not listed here. | 1,500 | [
{
"input": "4 3\n2 14 3 4",
"output": "0 12 3 3"
},
{
"input": "5 2\n0 2 1 255 254",
"output": "0 1 1 254 254"
},
{
"input": "10 3\n112 184 161 156 118 231 191 128 91 229",
"output": "110 182 159 154 116 229 189 126 89 229"
},
{
"input": "9 3\n174 149 118 124 166 146 219 233 ... | 1,614,955,891 | 2,147,483,647 | PyPy 3 | RUNTIME_ERROR | TESTS | 8 | 108 | 2,150,400 | # cook your dish here
from collections import Counter
from sys import stdin, stdout
n,kkkkk=map(int, stdin.readline().split())
x=list(map(int, stdin.readline().split()))
dic=Counter()
for i in x:
if dic[i]!=0:
print(min(dic[i]),end=" ")
else:
a=i-kkkkk+1
if a<0:
a=0
if dic[a]==0:
dic[a]=[]
for j in range(a,i+1):
dic[a].append(j)
for k in range(a+1,i+1):
dic[k]=dic[a].copy()
else:
if (i-a)+len(dic[a])<=kkkkk:
#print('ans',i,a,kkkkk,(i-a)+len(dic[a]))
for j in range(a+1,i+1):
if j not in dic[a]:
dic[a].append(j)
for k in dic[a]:
dic[k]=dic[a].copy()
else:
for j in range(a+1,i+1):
if dic[j]==0:
dic[j]=[]
for k in range(j,i+1):
dic[k].append(k)
for l in range(j,i+1):
dic[l]=dic[k].copy()
break
else:
if (i-j)+len(dic[j])<=kkkkk:
for jj in range(j+1,i+1):
if jj not in dic[j]:
dic[j].append(jj)
for kk in dic[j]:
dic[kk]=dic[j].copy()
break
print(min(dic[i]),end=" ") | Title: Posterized
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor Ibrahim has prepared the final homework for his algorithm’s class. He asked his students to implement the Posterization Image Filter.
Their algorithm will be tested on an array of integers, where the $i$-th integer represents the color of the $i$-th pixel in the image. The image is in black and white, therefore the color of each pixel will be an integer between 0 and 255 (inclusive).
To implement the filter, students are required to divide the black and white color range [0, 255] into groups of consecutive colors, and select one color in each group to be the group’s key. In order to preserve image details, the size of a group must not be greater than $k$, and each color should belong to exactly one group.
Finally, the students will replace the color of each pixel in the array with that color’s assigned group key.
To better understand the effect, here is an image of a basking turtle where the Posterization Filter was applied with increasing $k$ to the right.
To make the process of checking the final answer easier, Professor Ibrahim wants students to divide the groups and assign the keys in a way that produces the lexicographically smallest possible array.
Input Specification:
The first line of input contains two integers $n$ and $k$ ($1 \leq n \leq 10^5$, $1 \leq k \leq 256$), the number of pixels in the image, and the maximum size of a group, respectively.
The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($0 \leq p_i \leq 255$), where $p_i$ is the color of the $i$-th pixel.
Output Specification:
Print $n$ space-separated integers; the lexicographically smallest possible array that represents the image after applying the Posterization filter.
Demo Input:
['4 3\n2 14 3 4\n', '5 2\n0 2 1 255 254\n']
Demo Output:
['0 12 3 3\n', '0 1 1 254 254\n']
Note:
One possible way to group colors and assign keys for the first sample:
Color $2$ belongs to the group $[0,2]$, with group key $0$.
Color $14$ belongs to the group $[12,14]$, with group key $12$.
Colors $3$ and $4$ belong to group $[3, 5]$, with group key $3$.
Other groups won't affect the result so they are not listed here. | ```python
# cook your dish here
from collections import Counter
from sys import stdin, stdout
n,kkkkk=map(int, stdin.readline().split())
x=list(map(int, stdin.readline().split()))
dic=Counter()
for i in x:
if dic[i]!=0:
print(min(dic[i]),end=" ")
else:
a=i-kkkkk+1
if a<0:
a=0
if dic[a]==0:
dic[a]=[]
for j in range(a,i+1):
dic[a].append(j)
for k in range(a+1,i+1):
dic[k]=dic[a].copy()
else:
if (i-a)+len(dic[a])<=kkkkk:
#print('ans',i,a,kkkkk,(i-a)+len(dic[a]))
for j in range(a+1,i+1):
if j not in dic[a]:
dic[a].append(j)
for k in dic[a]:
dic[k]=dic[a].copy()
else:
for j in range(a+1,i+1):
if dic[j]==0:
dic[j]=[]
for k in range(j,i+1):
dic[k].append(k)
for l in range(j,i+1):
dic[l]=dic[k].copy()
break
else:
if (i-j)+len(dic[j])<=kkkkk:
for jj in range(j+1,i+1):
if jj not in dic[j]:
dic[j].append(jj)
for kk in dic[j]:
dic[kk]=dic[j].copy()
break
print(min(dic[i]),end=" ")
``` | -1 | |
50 | A | Domino piling | PROGRAMMING | 800 | [
"greedy",
"math"
] | A. Domino piling | 2 | 256 | You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions. | In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16). | Output one number — the maximal number of dominoes, which can be placed. | [
"2 4\n",
"3 3\n"
] | [
"4\n",
"4\n"
] | none | 500 | [
{
"input": "2 4",
"output": "4"
},
{
"input": "3 3",
"output": "4"
},
{
"input": "1 5",
"output": "2"
},
{
"input": "1 6",
"output": "3"
},
{
"input": "1 15",
"output": "7"
},
{
"input": "1 16",
"output": "8"
},
{
"input": "2 5",
"outpu... | 1,691,467,695 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 92 | 0 | M, N = map(int, input().split())
if M > N:
M, N = N, M
max_dominos = (M * N) // 2
print(max_dominos)
| Title: Domino piling
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
You are given a rectangular board of *M*<=×<=*N* squares. Also you are given an unlimited number of standard domino pieces of 2<=×<=1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions:
1. Each domino completely covers two squares.
2. No two dominoes overlap.
3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board.
Find the maximum number of dominoes, which can be placed under these restrictions.
Input Specification:
In a single line you are given two integers *M* and *N* — board sizes in squares (1<=≤<=*M*<=≤<=*N*<=≤<=16).
Output Specification:
Output one number — the maximal number of dominoes, which can be placed.
Demo Input:
['2 4\n', '3 3\n']
Demo Output:
['4\n', '4\n']
Note:
none | ```python
M, N = map(int, input().split())
if M > N:
M, N = N, M
max_dominos = (M * N) // 2
print(max_dominos)
``` | 3.977 |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,587,045,249 | 2,147,483,647 | PyPy 3 | OK | TESTS | 81 | 342 | 0 | '''Young Physicist Solution
'''
N = int(input())
x, y, z = 0, 0, 0
for row in range(N):
xn, yn, zn = list(map(int, input().split()))
x += xn
y += yn
z += zn
if x == 0 and y == 0 and z == 0:
print('YES')
else:
print('NO') | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).
Output Specification:
Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.
Demo Input:
['3\n4 1 7\n-2 4 -1\n1 -5 -3\n', '3\n3 -1 7\n-5 2 -4\n2 -1 -3\n']
Demo Output:
['NO', 'YES']
Note:
none | ```python
'''Young Physicist Solution
'''
N = int(input())
x, y, z = 0, 0, 0
for row in range(N):
xn, yn, zn = list(map(int, input().split()))
x += xn
y += yn
z += zn
if x == 0 and y == 0 and z == 0:
print('YES')
else:
print('NO')
``` | 3.9145 |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note that there is exactly one next prime number after each number. So 5 is not the next prime number for 2.
One cold April morning Panoramix predicted that soon Kakofonix will break free from his straitjacket, and this will be a black day for the residents of the Gallic countryside.
Panoramix's prophecy tells that if some day Asterix and Obelix beat exactly *x* Roman soldiers, where *x* is a prime number, and next day they beat exactly *y* Roman soldiers, where *y* is the next prime number after *x*, then it's time to wait for Armageddon, for nothing can shut Kakofonix up while he sings his infernal song.
Yesterday the Gauls beat *n* Roman soldiers and it turned out that the number *n* was prime! Today their victims were a troop of *m* Romans (*m*<=><=*n*). Determine whether the Gauls should wait for the black day after today's victory of Asterix and Obelix? | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,669,439,483 | 2,147,483,647 | Python 3 | OK | TESTS | 45 | 124 | 0 | a,b = map(int,input().split(" "))
status = True
def isPrime(num):
i =2
while i <=num//2:
if num%i ==0:
return False
i+=1
return True
i =a
while i <=b:
if not isPrime(i) and (i ==a or i ==b):
status = False
break
if isPrime(i) and i != a and i !=b:
status = False
break
i+=1
if status:
print('YES')
else:
print('NO')
| Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note that there is exactly one next prime number after each number. So 5 is not the next prime number for 2.
One cold April morning Panoramix predicted that soon Kakofonix will break free from his straitjacket, and this will be a black day for the residents of the Gallic countryside.
Panoramix's prophecy tells that if some day Asterix and Obelix beat exactly *x* Roman soldiers, where *x* is a prime number, and next day they beat exactly *y* Roman soldiers, where *y* is the next prime number after *x*, then it's time to wait for Armageddon, for nothing can shut Kakofonix up while he sings his infernal song.
Yesterday the Gauls beat *n* Roman soldiers and it turned out that the number *n* was prime! Today their victims were a troop of *m* Romans (*m*<=><=*n*). Determine whether the Gauls should wait for the black day after today's victory of Asterix and Obelix?
Input Specification:
The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4.
Output Specification:
Print YES, if *m* is the next prime number after *n*, or NO otherwise.
Demo Input:
['3 5\n', '7 11\n', '7 9\n']
Demo Output:
['YES', 'YES', 'NO']
Note:
none | ```python
a,b = map(int,input().split(" "))
status = True
def isPrime(num):
i =2
while i <=num//2:
if num%i ==0:
return False
i+=1
return True
i =a
while i <=b:
if not isPrime(i) and (i ==a or i ==b):
status = False
break
if isPrime(i) and i != a and i !=b:
status = False
break
i+=1
if status:
print('YES')
else:
print('NO')
``` | 3.969 |
8 | A | Train and Peter | PROGRAMMING | 1,200 | [
"strings"
] | A. Train and Peter | 1 | 64 | Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours. | The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order. | Output one of the four words without inverted commas:
- «forward» — if Peter could see such sequences only on the way from A to B; - «backward» — if Peter could see such sequences on the way from B to A; - «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A; - «fantasy» — if Peter could not see such sequences. | [
"atob\na\nb\n",
"aaacaaa\naca\naa\n"
] | [
"forward\n",
"both\n"
] | It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B. | 0 | [
{
"input": "atob\na\nb",
"output": "forward"
},
{
"input": "aaacaaa\naca\naa",
"output": "both"
},
{
"input": "aaa\naa\naa",
"output": "fantasy"
},
{
"input": "astalavista\nastla\nlavista",
"output": "fantasy"
},
{
"input": "abacabadabacaba\nabacaba\nabacaba",
... | 1,684,979,005 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 54 | 124 | 0 | f = input()
b = f[::-1]
s1 = input()
s2 = input()
i = -1
j = -1
try:
i = f.index(s1)
j = f.index(s2, i+len(s1))
except:
pass
forward = bool(j > -1)
i = -1
j = -1
try:
i = b.index(s1)
j = b.index(s2, i+len(s1))
except:
pass
backward = bool(j > -1)
if forward:
if backward:
print('both')
else:
print('forward')
elif backward:
print('backward')
else:
print('fantasy')
| Title: Train and Peter
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Peter likes to travel by train. He likes it so much that on the train he falls asleep.
Once in summer Peter was going by train from city A to city B, and as usual, was sleeping. Then he woke up, started to look through the window and noticed that every railway station has a flag of a particular colour.
The boy started to memorize the order of the flags' colours that he had seen. But soon he fell asleep again. Unfortunately, he didn't sleep long, he woke up and went on memorizing the colours. Then he fell asleep again, and that time he slept till the end of the journey.
At the station he told his parents about what he was doing, and wrote two sequences of the colours that he had seen before and after his sleep, respectively.
Peter's parents know that their son likes to fantasize. They give you the list of the flags' colours at the stations that the train passes sequentially on the way from A to B, and ask you to find out if Peter could see those sequences on the way from A to B, or from B to A. Remember, please, that Peter had two periods of wakefulness.
Peter's parents put lowercase Latin letters for colours. The same letter stands for the same colour, different letters — for different colours.
Input Specification:
The input data contains three lines. The first line contains a non-empty string, whose length does not exceed 105, the string consists of lowercase Latin letters — the flags' colours at the stations on the way from A to B. On the way from B to A the train passes the same stations, but in reverse order.
The second line contains the sequence, written by Peter during the first period of wakefulness. The third line contains the sequence, written during the second period of wakefulness. Both sequences are non-empty, consist of lowercase Latin letters, and the length of each does not exceed 100 letters. Each of the sequences is written in chronological order.
Output Specification:
Output one of the four words without inverted commas:
- «forward» — if Peter could see such sequences only on the way from A to B; - «backward» — if Peter could see such sequences on the way from B to A; - «both» — if Peter could see such sequences both on the way from A to B, and on the way from B to A; - «fantasy» — if Peter could not see such sequences.
Demo Input:
['atob\na\nb\n', 'aaacaaa\naca\naa\n']
Demo Output:
['forward\n', 'both\n']
Note:
It is assumed that the train moves all the time, so one flag cannot be seen twice. There are no flags at stations A and B. | ```python
f = input()
b = f[::-1]
s1 = input()
s2 = input()
i = -1
j = -1
try:
i = f.index(s1)
j = f.index(s2, i+len(s1))
except:
pass
forward = bool(j > -1)
i = -1
j = -1
try:
i = b.index(s1)
j = b.index(s2, i+len(s1))
except:
pass
backward = bool(j > -1)
if forward:
if backward:
print('both')
else:
print('forward')
elif backward:
print('backward')
else:
print('fantasy')
``` | 3.938 |
389 | B | Fox and Cross | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n*<=×<=*n* cells. Each cell contains either a symbol '.', or a symbol '#'.
A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.
Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.
Please, tell Ciel if she can draw the crosses in the described way. | The first line contains an integer *n* (3<=≤<=*n*<=≤<=100) — the size of the board.
Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'. | Output a single line with "YES" if Ciel can draw the crosses in the described way. Otherwise output a single line with "NO". | [
"5\n.#...\n####.\n.####\n...#.\n.....\n",
"4\n####\n####\n####\n####\n",
"6\n.#....\n####..\n.####.\n.#.##.\n######\n.#..#.\n",
"6\n.#..#.\n######\n.####.\n.####.\n######\n.#..#.\n",
"3\n...\n...\n...\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"NO\n",
"YES\n"
] | In example 1, you can draw two crosses. The picture below shows what they look like.
In example 2, the board contains 16 cells with '#', but each cross contains 5. Since 16 is not a multiple of 5, so it's impossible to cover all. | 1,000 | [
{
"input": "4\n####\n####\n####\n####",
"output": "NO"
},
{
"input": "6\n.#....\n####..\n.####.\n.#.##.\n######\n.#..#.",
"output": "YES"
},
{
"input": "6\n.#..#.\n######\n.####.\n.####.\n######\n.#..#.",
"output": "NO"
},
{
"input": "5\n.....\n.#...\n####.\n.####\n...#.",
... | 1,623,887,009 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 24 | 62 | 0 | qtd = int(input())
matriz = []*qtd
velha = 0
for i in range(qtd):
lista = list(input())
matriz.append(lista)
for i in range(qtd):
for j in range(qtd):
if (matriz[i][j] == '#'):
velha+=1
if (velha %5==0):
print("YES")
else:
print("NO")
| Title: Fox and Cross
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Fox Ciel has a board with *n* rows and *n* columns. So, the board consists of *n*<=×<=*n* cells. Each cell contains either a symbol '.', or a symbol '#'.
A cross on the board is a connected set of exactly five cells of the board that looks like a cross. The picture below shows how it looks.
Ciel wants to draw several (may be zero) crosses on the board. Each cross must cover exactly five cells with symbols '#', and any cell with symbol '#' must belong to some cross. No two crosses can share a cell.
Please, tell Ciel if she can draw the crosses in the described way.
Input Specification:
The first line contains an integer *n* (3<=≤<=*n*<=≤<=100) — the size of the board.
Each of the next *n* lines describes one row of the board. The *i*-th line describes the *i*-th row of the board and consists of *n* characters. Each character is either a symbol '.', or a symbol '#'.
Output Specification:
Output a single line with "YES" if Ciel can draw the crosses in the described way. Otherwise output a single line with "NO".
Demo Input:
['5\n.#...\n####.\n.####\n...#.\n.....\n', '4\n####\n####\n####\n####\n', '6\n.#....\n####..\n.####.\n.#.##.\n######\n.#..#.\n', '6\n.#..#.\n######\n.####.\n.####.\n######\n.#..#.\n', '3\n...\n...\n...\n']
Demo Output:
['YES\n', 'NO\n', 'YES\n', 'NO\n', 'YES\n']
Note:
In example 1, you can draw two crosses. The picture below shows what they look like.
In example 2, the board contains 16 cells with '#', but each cross contains 5. Since 16 is not a multiple of 5, so it's impossible to cover all. | ```python
qtd = int(input())
matriz = []*qtd
velha = 0
for i in range(qtd):
lista = list(input())
matriz.append(lista)
for i in range(qtd):
for j in range(qtd):
if (matriz[i][j] == '#'):
velha+=1
if (velha %5==0):
print("YES")
else:
print("NO")
``` | 0 | |
220 | B | Little Elephant and Array | PROGRAMMING | 1,800 | [
"constructive algorithms",
"data structures"
] | null | null | The Little Elephant loves playing with arrays. He has array *a*, consisting of *n* positive integers, indexed from 1 to *n*. Let's denote the number with index *i* as *a**i*.
Additionally the Little Elephant has *m* queries to the array, each query is characterised by a pair of integers *l**j* and *r**j* (1<=≤<=*l**j*<=≤<=*r**j*<=≤<=*n*). For each query *l**j*,<=*r**j* the Little Elephant has to count, how many numbers *x* exist, such that number *x* occurs exactly *x* times among numbers *a**l**j*,<=*a**l**j*<=+<=1,<=...,<=*a**r**j*.
Help the Little Elephant to count the answers to all queries. | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105) — the size of array *a* and the number of queries to it. The next line contains *n* space-separated positive integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=109). Next *m* lines contain descriptions of queries, one per line. The *j*-th of these lines contains the description of the *j*-th query as two space-separated integers *l**j* and *r**j* (1<=≤<=*l**j*<=≤<=*r**j*<=≤<=*n*). | In *m* lines print *m* integers — the answers to the queries. The *j*-th line should contain the answer to the *j*-th query. | [
"7 2\n3 1 2 2 3 3 7\n1 7\n3 4\n"
] | [
"3\n1\n"
] | none | 1,000 | [
{
"input": "7 2\n3 1 2 2 3 3 7\n1 7\n3 4",
"output": "3\n1"
},
{
"input": "6 6\n1 2 2 3 3 3\n1 2\n2 2\n1 3\n2 4\n4 6\n1 6",
"output": "1\n0\n2\n1\n1\n3"
},
{
"input": "1 2\n1\n1 1\n1 1",
"output": "1\n1"
},
{
"input": "1 1\n1000000000\n1 1",
"output": "0"
}
] | 1,515,522,601 | 3,301 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 13 | 4,000 | 35,328,000 | from sys import stdin, stdout
n, m = map(int, stdin.readline().split())
values = list(map(int, stdin.readline().split()))
d = {}
for i in range(n):
v = values[i]
if v in d:
d[v].append(i)
else:
d[v] = [i]
challengers = []
for v in d:
if len(d[v]) >= v:
challengers.append(v)
for i in range(m):
lb, rb = map(int, stdin.readline().split())
ans = 0
lb -= 1
rb -= 1
for v in challengers:
l, r = -1, len(d[v])
while r - l > 1:
m = (l + r) >> 1
if d[v][m] > rb:
r = m
else:
l = m
right = l
l, r = -1, len(d[v])
while r - l > 1:
m = (l + r) >> 1
if d[v][m] >= lb:
r = m
else:
l = m
left = r
if right - left + 1 == v:
ans += 1
stdout.write(str(ans) + '\n') | Title: Little Elephant and Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant loves playing with arrays. He has array *a*, consisting of *n* positive integers, indexed from 1 to *n*. Let's denote the number with index *i* as *a**i*.
Additionally the Little Elephant has *m* queries to the array, each query is characterised by a pair of integers *l**j* and *r**j* (1<=≤<=*l**j*<=≤<=*r**j*<=≤<=*n*). For each query *l**j*,<=*r**j* the Little Elephant has to count, how many numbers *x* exist, such that number *x* occurs exactly *x* times among numbers *a**l**j*,<=*a**l**j*<=+<=1,<=...,<=*a**r**j*.
Help the Little Elephant to count the answers to all queries.
Input Specification:
The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=105) — the size of array *a* and the number of queries to it. The next line contains *n* space-separated positive integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=109). Next *m* lines contain descriptions of queries, one per line. The *j*-th of these lines contains the description of the *j*-th query as two space-separated integers *l**j* and *r**j* (1<=≤<=*l**j*<=≤<=*r**j*<=≤<=*n*).
Output Specification:
In *m* lines print *m* integers — the answers to the queries. The *j*-th line should contain the answer to the *j*-th query.
Demo Input:
['7 2\n3 1 2 2 3 3 7\n1 7\n3 4\n']
Demo Output:
['3\n1\n']
Note:
none | ```python
from sys import stdin, stdout
n, m = map(int, stdin.readline().split())
values = list(map(int, stdin.readline().split()))
d = {}
for i in range(n):
v = values[i]
if v in d:
d[v].append(i)
else:
d[v] = [i]
challengers = []
for v in d:
if len(d[v]) >= v:
challengers.append(v)
for i in range(m):
lb, rb = map(int, stdin.readline().split())
ans = 0
lb -= 1
rb -= 1
for v in challengers:
l, r = -1, len(d[v])
while r - l > 1:
m = (l + r) >> 1
if d[v][m] > rb:
r = m
else:
l = m
right = l
l, r = -1, len(d[v])
while r - l > 1:
m = (l + r) >> 1
if d[v][m] >= lb:
r = m
else:
l = m
left = r
if right - left + 1 == v:
ans += 1
stdout.write(str(ans) + '\n')
``` | 0 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word. | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,695,162,628 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 92 | 0 | word = input()
word_lowercase = word.lower()
count_uppercase = 0
for i in range(0, len(word)):
if word[i] != word_lowercase[i]:
count_uppercase += 1
if count_uppercase > len(word)/2:
print(word.upper())
else:
print(word_lowercase) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word.
Input Specification:
The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100.
Output Specification:
Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one.
Demo Input:
['HoUse\n', 'ViP\n', 'maTRIx\n']
Demo Output:
['house\n', 'VIP\n', 'matrix\n']
Note:
none | ```python
word = input()
word_lowercase = word.lower()
count_uppercase = 0
for i in range(0, len(word)):
if word[i] != word_lowercase[i]:
count_uppercase += 1
if count_uppercase > len(word)/2:
print(word.upper())
else:
print(word_lowercase)
``` | 3.977 |
894 | C | Marco and GCD Sequence | PROGRAMMING | 1,900 | [
"constructive algorithms",
"math"
] | null | null | In a dream Marco met an elderly man with a pair of black glasses. The man told him the key to immortality and then disappeared with the wind of time.
When he woke up, he only remembered that the key was a sequence of positive integers of some length *n*, but forgot the exact sequence. Let the elements of the sequence be *a*1,<=*a*2,<=...,<=*a**n*. He remembered that he calculated *gcd*(*a**i*,<=*a**i*<=+<=1,<=...,<=*a**j*) for every 1<=≤<=*i*<=≤<=*j*<=≤<=*n* and put it into a set *S*. *gcd* here means the [greatest common divisor](https://en.wikipedia.org/wiki/Greatest_common_divisor).
Note that even if a number is put into the set *S* twice or more, it only appears once in the set.
Now Marco gives you the set *S* and asks you to help him figure out the initial sequence. If there are many solutions, print any of them. It is also possible that there are no sequences that produce the set *S*, in this case print -1. | The first line contains a single integer *m* (1<=≤<=*m*<=≤<=1000) — the size of the set *S*.
The second line contains *m* integers *s*1,<=*s*2,<=...,<=*s**m* (1<=≤<=*s**i*<=≤<=106) — the elements of the set *S*. It's guaranteed that the elements of the set are given in strictly increasing order, that means *s*1<=<<=*s*2<=<<=...<=<<=*s**m*. | If there is no solution, print a single line containing -1.
Otherwise, in the first line print a single integer *n* denoting the length of the sequence, *n* should not exceed 4000.
In the second line print *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=106) — the sequence.
We can show that if a solution exists, then there is a solution with *n* not exceeding 4000 and *a**i* not exceeding 106.
If there are multiple solutions, print any of them. | [
"4\n2 4 6 12\n",
"2\n2 3\n"
] | [
"3\n4 6 12",
"-1\n"
] | In the first example 2 = *gcd*(4, 6), the other elements from the set appear in the sequence, and we can show that there are no values different from 2, 4, 6 and 12 among *gcd*(*a*<sub class="lower-index">*i*</sub>, *a*<sub class="lower-index">*i* + 1</sub>, ..., *a*<sub class="lower-index">*j*</sub>) for every 1 ≤ *i* ≤ *j* ≤ *n*. | 1,500 | [
{
"input": "4\n2 4 6 12",
"output": "7\n2 2 4 2 6 2 12"
},
{
"input": "2\n2 3",
"output": "-1"
},
{
"input": "2\n1 6",
"output": "3\n1 1 6"
},
{
"input": "3\n1 2 7",
"output": "5\n1 1 2 1 7"
},
{
"input": "1\n1",
"output": "1\n1"
},
{
"input": "2\n1 10... | 1,619,530,620 | 2,147,483,647 | PyPy 3 | OK | TESTS | 56 | 109 | 2,457,600 | n=int(input());
s=list(map(int,input().split()));
p=s[0];
for i in s:
if(i%p):
print(-1);
exit(0);
ans=[];
for i in s:
ans+=[i,p];
print(len(ans));
print(*ans); | Title: Marco and GCD Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a dream Marco met an elderly man with a pair of black glasses. The man told him the key to immortality and then disappeared with the wind of time.
When he woke up, he only remembered that the key was a sequence of positive integers of some length *n*, but forgot the exact sequence. Let the elements of the sequence be *a*1,<=*a*2,<=...,<=*a**n*. He remembered that he calculated *gcd*(*a**i*,<=*a**i*<=+<=1,<=...,<=*a**j*) for every 1<=≤<=*i*<=≤<=*j*<=≤<=*n* and put it into a set *S*. *gcd* here means the [greatest common divisor](https://en.wikipedia.org/wiki/Greatest_common_divisor).
Note that even if a number is put into the set *S* twice or more, it only appears once in the set.
Now Marco gives you the set *S* and asks you to help him figure out the initial sequence. If there are many solutions, print any of them. It is also possible that there are no sequences that produce the set *S*, in this case print -1.
Input Specification:
The first line contains a single integer *m* (1<=≤<=*m*<=≤<=1000) — the size of the set *S*.
The second line contains *m* integers *s*1,<=*s*2,<=...,<=*s**m* (1<=≤<=*s**i*<=≤<=106) — the elements of the set *S*. It's guaranteed that the elements of the set are given in strictly increasing order, that means *s*1<=<<=*s*2<=<<=...<=<<=*s**m*.
Output Specification:
If there is no solution, print a single line containing -1.
Otherwise, in the first line print a single integer *n* denoting the length of the sequence, *n* should not exceed 4000.
In the second line print *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=106) — the sequence.
We can show that if a solution exists, then there is a solution with *n* not exceeding 4000 and *a**i* not exceeding 106.
If there are multiple solutions, print any of them.
Demo Input:
['4\n2 4 6 12\n', '2\n2 3\n']
Demo Output:
['3\n4 6 12', '-1\n']
Note:
In the first example 2 = *gcd*(4, 6), the other elements from the set appear in the sequence, and we can show that there are no values different from 2, 4, 6 and 12 among *gcd*(*a*<sub class="lower-index">*i*</sub>, *a*<sub class="lower-index">*i* + 1</sub>, ..., *a*<sub class="lower-index">*j*</sub>) for every 1 ≤ *i* ≤ *j* ≤ *n*. | ```python
n=int(input());
s=list(map(int,input().split()));
p=s[0];
for i in s:
if(i%p):
print(-1);
exit(0);
ans=[];
for i in s:
ans+=[i,p];
print(len(ans));
print(*ans);
``` | 3 | |
622 | B | The Time | PROGRAMMING | 900 | [
"implementation"
] | null | null | You are given the current time in 24-hour format hh:mm. Find and print the time after *a* minutes.
Note that you should find only the time after *a* minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here [https://en.wikipedia.org/wiki/24-hour_clock](https://en.wikipedia.org/wiki/24-hour_clock). | The first line contains the current time in the format hh:mm (0<=≤<=*hh*<=<<=24,<=0<=≤<=*mm*<=<<=60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer *a* (0<=≤<=*a*<=≤<=104) — the number of the minutes passed. | The only line should contain the time after *a* minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format. | [
"23:59\n10\n",
"20:20\n121\n",
"10:10\n0\n"
] | [
"00:09\n",
"22:21\n",
"10:10\n"
] | none | 0 | [
{
"input": "23:59\n10",
"output": "00:09"
},
{
"input": "20:20\n121",
"output": "22:21"
},
{
"input": "10:10\n0",
"output": "10:10"
},
{
"input": "12:34\n10000",
"output": "11:14"
},
{
"input": "00:00\n10000",
"output": "22:40"
},
{
"input": "00:00\n14... | 1,656,473,344 | 2,147,483,647 | Python 3 | OK | TESTS | 59 | 46 | 0 | # -*- coding: utf-8 -*-
"""codeforces 622B
Automatically generated by Colaboratory.
Original file is located at
https://colab.research.google.com/drive/1fnRVrX6kGGXBPnaZduqeU_eo6w87jUi5
"""
T=input()
a=int(input())
h=int(T[ :-3])
m=int(T[-2: ])
x=a//60
y=a%60
hour=h+x
min=m+y
if min>=60:
min=min-60
hour=hour+1
z=hour//24
if hour>=24:
hour=hour-(24*z)
if len(str(hour))==2 and len(str(min))==1:
print(f"{hour}:0{min}")
elif len(str(hour))==1 and len(str(min))==2:
print(f"0{hour}:{min}")
elif len(str(hour))==1 and len(str(min))==1:
print(f"0{hour}:0{min}")
else:
print(f"{hour}:{min}") | Title: The Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the current time in 24-hour format hh:mm. Find and print the time after *a* minutes.
Note that you should find only the time after *a* minutes, see the examples to clarify the problem statement.
You can read more about 24-hour format here [https://en.wikipedia.org/wiki/24-hour_clock](https://en.wikipedia.org/wiki/24-hour_clock).
Input Specification:
The first line contains the current time in the format hh:mm (0<=≤<=*hh*<=<<=24,<=0<=≤<=*mm*<=<<=60). The hours and the minutes are given with two digits (the hours or the minutes less than 10 are given with the leading zeroes).
The second line contains integer *a* (0<=≤<=*a*<=≤<=104) — the number of the minutes passed.
Output Specification:
The only line should contain the time after *a* minutes in the format described in the input. Note that you should print exactly two digits for the hours and the minutes (add leading zeroes to the numbers if needed).
See the examples to check the input/output format.
Demo Input:
['23:59\n10\n', '20:20\n121\n', '10:10\n0\n']
Demo Output:
['00:09\n', '22:21\n', '10:10\n']
Note:
none | ```python
# -*- coding: utf-8 -*-
"""codeforces 622B
Automatically generated by Colaboratory.
Original file is located at
https://colab.research.google.com/drive/1fnRVrX6kGGXBPnaZduqeU_eo6w87jUi5
"""
T=input()
a=int(input())
h=int(T[ :-3])
m=int(T[-2: ])
x=a//60
y=a%60
hour=h+x
min=m+y
if min>=60:
min=min-60
hour=hour+1
z=hour//24
if hour>=24:
hour=hour-(24*z)
if len(str(hour))==2 and len(str(min))==1:
print(f"{hour}:0{min}")
elif len(str(hour))==1 and len(str(min))==2:
print(f"0{hour}:{min}")
elif len(str(hour))==1 and len(str(min))==1:
print(f"0{hour}:0{min}")
else:
print(f"{hour}:{min}")
``` | 3 | |
356 | A | Knight Tournament | PROGRAMMING | 1,500 | [
"data structures",
"dsu"
] | null | null | Hooray! Berl II, the king of Berland is making a knight tournament. The king has already sent the message to all knights in the kingdom and they in turn agreed to participate in this grand event.
As for you, you're just a simple peasant. There's no surprise that you slept in this morning and were late for the tournament (it was a weekend, after all). Now you are really curious about the results of the tournament. This time the tournament in Berland went as follows:
- There are *n* knights participating in the tournament. Each knight was assigned his unique number — an integer from 1 to *n*. - The tournament consisted of *m* fights, in the *i*-th fight the knights that were still in the game with numbers at least *l**i* and at most *r**i* have fought for the right to continue taking part in the tournament. - After the *i*-th fight among all participants of the fight only one knight won — the knight number *x**i*, he continued participating in the tournament. Other knights left the tournament. - The winner of the last (the *m*-th) fight (the knight number *x**m*) became the winner of the tournament.
You fished out all the information about the fights from your friends. Now for each knight you want to know the name of the knight he was conquered by. We think that the knight number *b* was conquered by the knight number *a*, if there was a fight with both of these knights present and the winner was the knight number *a*.
Write the code that calculates for each knight, the name of the knight that beat him. | The first line contains two integers *n*, *m* (2<=≤<=*n*<=≤<=3·105; 1<=≤<=*m*<=≤<=3·105) — the number of knights and the number of fights. Each of the following *m* lines contains three integers *l**i*,<=*r**i*,<=*x**i* (1<=≤<=*l**i*<=<<=*r**i*<=≤<=*n*; *l**i*<=≤<=*x**i*<=≤<=*r**i*) — the description of the *i*-th fight.
It is guaranteed that the input is correct and matches the problem statement. It is guaranteed that at least two knights took part in each battle. | Print *n* integers. If the *i*-th knight lost, then the *i*-th number should equal the number of the knight that beat the knight number *i*. If the *i*-th knight is the winner, then the *i*-th number must equal 0. | [
"4 3\n1 2 1\n1 3 3\n1 4 4\n",
"8 4\n3 5 4\n3 7 6\n2 8 8\n1 8 1\n"
] | [
"3 1 4 0 ",
"0 8 4 6 4 8 6 1 "
] | Consider the first test case. Knights 1 and 2 fought the first fight and knight 1 won. Knights 1 and 3 fought the second fight and knight 3 won. The last fight was between knights 3 and 4, knight 4 won. | 500 | [
{
"input": "4 3\n1 2 1\n1 3 3\n1 4 4",
"output": "3 1 4 0 "
},
{
"input": "8 4\n3 5 4\n3 7 6\n2 8 8\n1 8 1",
"output": "0 8 4 6 4 8 6 1 "
},
{
"input": "2 1\n1 2 1",
"output": "0 1 "
},
{
"input": "2 1\n1 2 2",
"output": "2 0 "
},
{
"input": "3 1\n1 3 1",
"out... | 1,682,608,460 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 3,000 | 13,004,800 | n, m = map(int, input().split())
vivo, vencedor = [True] * (n + 2), [0] * (n + 2)
for _ in range(m):
l, r, x = map(int, input().split())
for i in range(l, r + 1):
if i != x and vivo[i]:
vencedor[i] = x
vivo[i] = False
print(' '.join(map(str, vencedor[1:-1])))
| Title: Knight Tournament
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hooray! Berl II, the king of Berland is making a knight tournament. The king has already sent the message to all knights in the kingdom and they in turn agreed to participate in this grand event.
As for you, you're just a simple peasant. There's no surprise that you slept in this morning and were late for the tournament (it was a weekend, after all). Now you are really curious about the results of the tournament. This time the tournament in Berland went as follows:
- There are *n* knights participating in the tournament. Each knight was assigned his unique number — an integer from 1 to *n*. - The tournament consisted of *m* fights, in the *i*-th fight the knights that were still in the game with numbers at least *l**i* and at most *r**i* have fought for the right to continue taking part in the tournament. - After the *i*-th fight among all participants of the fight only one knight won — the knight number *x**i*, he continued participating in the tournament. Other knights left the tournament. - The winner of the last (the *m*-th) fight (the knight number *x**m*) became the winner of the tournament.
You fished out all the information about the fights from your friends. Now for each knight you want to know the name of the knight he was conquered by. We think that the knight number *b* was conquered by the knight number *a*, if there was a fight with both of these knights present and the winner was the knight number *a*.
Write the code that calculates for each knight, the name of the knight that beat him.
Input Specification:
The first line contains two integers *n*, *m* (2<=≤<=*n*<=≤<=3·105; 1<=≤<=*m*<=≤<=3·105) — the number of knights and the number of fights. Each of the following *m* lines contains three integers *l**i*,<=*r**i*,<=*x**i* (1<=≤<=*l**i*<=<<=*r**i*<=≤<=*n*; *l**i*<=≤<=*x**i*<=≤<=*r**i*) — the description of the *i*-th fight.
It is guaranteed that the input is correct and matches the problem statement. It is guaranteed that at least two knights took part in each battle.
Output Specification:
Print *n* integers. If the *i*-th knight lost, then the *i*-th number should equal the number of the knight that beat the knight number *i*. If the *i*-th knight is the winner, then the *i*-th number must equal 0.
Demo Input:
['4 3\n1 2 1\n1 3 3\n1 4 4\n', '8 4\n3 5 4\n3 7 6\n2 8 8\n1 8 1\n']
Demo Output:
['3 1 4 0 ', '0 8 4 6 4 8 6 1 ']
Note:
Consider the first test case. Knights 1 and 2 fought the first fight and knight 1 won. Knights 1 and 3 fought the second fight and knight 3 won. The last fight was between knights 3 and 4, knight 4 won. | ```python
n, m = map(int, input().split())
vivo, vencedor = [True] * (n + 2), [0] * (n + 2)
for _ in range(m):
l, r, x = map(int, input().split())
for i in range(l, r + 1):
if i != x and vivo[i]:
vencedor[i] = x
vivo[i] = False
print(' '.join(map(str, vencedor[1:-1])))
``` | 0 | |
349 | A | Cinema Line | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | The new "Die Hard" movie has just been released! There are *n* people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the booking clerk sell a ticket to each person and give the change if he initially has no money and sells the tickets strictly in the order people follow in the line? | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of people in the line. The next line contains *n* integers, each of them equals 25, 50 or 100 — the values of the bills the people have. The numbers are given in the order from the beginning of the line (at the box office) to the end of the line. | Print "YES" (without the quotes) if the booking clerk can sell a ticket to each person and give the change. Otherwise print "NO". | [
"4\n25 25 50 50\n",
"2\n25 100\n",
"4\n50 50 25 25\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "4\n25 25 50 50",
"output": "YES"
},
{
"input": "2\n25 100",
"output": "NO"
},
{
"input": "4\n50 50 25 25",
"output": "NO"
},
{
"input": "3\n25 50 100",
"output": "NO"
},
{
"input": "10\n25 25 25 25 25 25 25 25 25 25",
"output": "YES"
},
{
"... | 1,695,104,106 | 2,147,483,647 | Python 3 | OK | TESTS | 40 | 154 | 10,854,400 | n = int(input())
bills = list(map(int, input().split()))
change_25 = 0
change_50 = 0
for bill in bills:
if bill == 25:
change_25 += 1
elif bill == 50:
if change_25 >= 1:
change_25 -= 1
change_50 += 1
else:
print("NO")
break
elif bill == 100:
if change_50 >= 1 and change_25 >= 1:
change_50 -= 1
change_25 -= 1
elif change_25 >= 3:
change_25 -= 3
else:
print("NO")
break
else:
print("YES")
| Title: Cinema Line
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The new "Die Hard" movie has just been released! There are *n* people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the booking clerk sell a ticket to each person and give the change if he initially has no money and sells the tickets strictly in the order people follow in the line?
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of people in the line. The next line contains *n* integers, each of them equals 25, 50 or 100 — the values of the bills the people have. The numbers are given in the order from the beginning of the line (at the box office) to the end of the line.
Output Specification:
Print "YES" (without the quotes) if the booking clerk can sell a ticket to each person and give the change. Otherwise print "NO".
Demo Input:
['4\n25 25 50 50\n', '2\n25 100\n', '4\n50 50 25 25\n']
Demo Output:
['YES\n', 'NO\n', 'NO\n']
Note:
none | ```python
n = int(input())
bills = list(map(int, input().split()))
change_25 = 0
change_50 = 0
for bill in bills:
if bill == 25:
change_25 += 1
elif bill == 50:
if change_25 >= 1:
change_25 -= 1
change_50 += 1
else:
print("NO")
break
elif bill == 100:
if change_50 >= 1 and change_25 >= 1:
change_50 -= 1
change_25 -= 1
elif change_25 >= 3:
change_25 -= 3
else:
print("NO")
break
else:
print("YES")
``` | 3 | |
499 | B | Lecture | PROGRAMMING | 1,000 | [
"implementation",
"strings"
] | null | null | You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consists of several words. For each language, all words are distinct, i.e. they are spelled differently. Moreover, the words of these languages have a one-to-one correspondence, that is, for each word in each language, there exists exactly one word in the other language having has the same meaning.
You can write down every word the professor says in either the first language or the second language. Of course, during the lecture you write down each word in the language in which the word is shorter. In case of equal lengths of the corresponding words you prefer the word of the first language.
You are given the text of the lecture the professor is going to read. Find out how the lecture will be recorded in your notes. | The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* belongs to the first language, the word *b**i* belongs to the second language, and these two words have the same meaning. It is guaranteed that no word occurs in both languages, and each word occurs in its language exactly once.
The next line contains *n* space-separated strings *c*1,<=*c*2,<=...,<=*c**n* — the text of the lecture. It is guaranteed that each of the strings *c**i* belongs to the set of strings {*a*1,<=*a*2,<=... *a**m*}.
All the strings in the input are non-empty, each consisting of no more than 10 lowercase English letters. | Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input. | [
"4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n",
"5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n"
] | [
"codeforces round letter round\n",
"hbnyiyc joll joll un joll\n"
] | none | 500 | [
{
"input": "4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest",
"output": "codeforces round letter round"
},
{
"input": "5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll",
"output": "hbnyiyc joll joll un joll"
},
{
"input"... | 1,597,941,579 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 8 | 1,000 | 8,806,400 | n,m = map(int,input().split())
a=[]
s = ''
for i in range(m):
a.append(input())
lec = input().split()
for r in lec:
for b in a:
c = b.split()
if r in c:
if len(c[0])==len(c[1]):
s += c[0] + " "
elif len(c[0])<len(c[1]) :
s+= c[0] + ' '
else:
s+= c[1] +' '
print(s)
| Title: Lecture
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consists of several words. For each language, all words are distinct, i.e. they are spelled differently. Moreover, the words of these languages have a one-to-one correspondence, that is, for each word in each language, there exists exactly one word in the other language having has the same meaning.
You can write down every word the professor says in either the first language or the second language. Of course, during the lecture you write down each word in the language in which the word is shorter. In case of equal lengths of the corresponding words you prefer the word of the first language.
You are given the text of the lecture the professor is going to read. Find out how the lecture will be recorded in your notes.
Input Specification:
The first line contains two integers, *n* and *m* (1<=≤<=*n*<=≤<=3000, 1<=≤<=*m*<=≤<=3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following *m* lines contain the words. The *i*-th line contains two strings *a**i*, *b**i* meaning that the word *a**i* belongs to the first language, the word *b**i* belongs to the second language, and these two words have the same meaning. It is guaranteed that no word occurs in both languages, and each word occurs in its language exactly once.
The next line contains *n* space-separated strings *c*1,<=*c*2,<=...,<=*c**n* — the text of the lecture. It is guaranteed that each of the strings *c**i* belongs to the set of strings {*a*1,<=*a*2,<=... *a**m*}.
All the strings in the input are non-empty, each consisting of no more than 10 lowercase English letters.
Output Specification:
Output exactly *n* words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input.
Demo Input:
['4 3\ncodeforces codesecrof\ncontest round\nletter message\ncodeforces contest letter contest\n', '5 3\njoll wuqrd\neuzf un\nhbnyiyc rsoqqveh\nhbnyiyc joll joll euzf joll\n']
Demo Output:
['codeforces round letter round\n', 'hbnyiyc joll joll un joll\n']
Note:
none | ```python
n,m = map(int,input().split())
a=[]
s = ''
for i in range(m):
a.append(input())
lec = input().split()
for r in lec:
for b in a:
c = b.split()
if r in c:
if len(c[0])==len(c[1]):
s += c[0] + " "
elif len(c[0])<len(c[1]) :
s+= c[0] + ' '
else:
s+= c[1] +' '
print(s)
``` | 0 | |
26 | A | Almost Prime | PROGRAMMING | 900 | [
"number theory"
] | A. Almost Prime | 2 | 256 | A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, inclusive. | Input contains one integer number *n* (1<=≤<=*n*<=≤<=3000). | Output the amount of almost prime numbers between 1 and *n*, inclusive. | [
"10\n",
"21\n"
] | [
"2\n",
"8\n"
] | none | 500 | [
{
"input": "10",
"output": "2"
},
{
"input": "21",
"output": "8"
},
{
"input": "1",
"output": "0"
},
{
"input": "2",
"output": "0"
},
{
"input": "4",
"output": "0"
},
{
"input": "3",
"output": "0"
},
{
"input": "8",
"output": "1"
},
... | 1,692,398,077 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 23 | 124 | 2,867,200 | def prime(n):
factor = set()
d = 2
while d * d <= n:
while n % d == 0:
factor.add(d)
n //= d
d += 1
if n >1:
factor.add(n)
return factor
n = int(input())
count = 0
for i in range(2, n+1):
ans = prime(i)
if len(ans) == 2:
count += 1
print(count)
| Title: Almost Prime
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A number is called almost prime if it has exactly two distinct prime divisors. For example, numbers 6, 18, 24 are almost prime, while 4, 8, 9, 42 are not. Find the amount of almost prime numbers which are between 1 and *n*, inclusive.
Input Specification:
Input contains one integer number *n* (1<=≤<=*n*<=≤<=3000).
Output Specification:
Output the amount of almost prime numbers between 1 and *n*, inclusive.
Demo Input:
['10\n', '21\n']
Demo Output:
['2\n', '8\n']
Note:
none | ```python
def prime(n):
factor = set()
d = 2
while d * d <= n:
while n % d == 0:
factor.add(d)
n //= d
d += 1
if n >1:
factor.add(n)
return factor
n = int(input())
count = 0
for i in range(2, n+1):
ans = prime(i)
if len(ans) == 2:
count += 1
print(count)
``` | 3.963659 |
70 | A | Cookies | PROGRAMMING | 1,300 | [
"math"
] | A. Cookies | 1 | 256 | Fangy collects cookies. Once he decided to take a box and put cookies into it in some way. If we take a square *k*<=×<=*k* in size, divided into blocks 1<=×<=1 in size and paint there the main diagonal together with cells, which lie above it, then the painted area will be equal to the area occupied by one cookie *k* in size. Fangy also has a box with a square base 2*n*<=×<=2*n*, divided into blocks 1<=×<=1 in size. In a box the cookies should not overlap, and they should not be turned over or rotated. See cookies of sizes 2 and 4 respectively on the figure:
To stack the cookies the little walrus uses the following algorithm. He takes out of the repository the largest cookie which can fit in some place in the box and puts it there. Everything could be perfect but alas, in the repository the little walrus has infinitely many cookies of size 2 and larger, and there are no cookies of size 1, therefore, empty cells will remain in the box. Fangy wants to know how many empty cells will be left in the end. | The first line contains a single integer *n* (0<=≤<=*n*<=≤<=1000). | Print the single number, equal to the number of empty cells in the box. The answer should be printed modulo 106<=+<=3. | [
"3\n"
] | [
"9"
] | If the box possesses the base of 2<sup class="upper-index">3</sup> × 2<sup class="upper-index">3</sup> (as in the example), then the cookies will be put there in the following manner: | 500 | [
{
"input": "3",
"output": "9"
},
{
"input": "1",
"output": "1"
},
{
"input": "2",
"output": "3"
},
{
"input": "4",
"output": "27"
},
{
"input": "6",
"output": "243"
},
{
"input": "11",
"output": "59049"
},
{
"input": "14",
"output": "59... | 1,492,533,589 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 62 | 5,529,600 | n = int(input())
if n == 0:
print(1)
else:
ans = 1
for i in range(n - 1):
ans *= 3
print(ans % 1000003) | Title: Cookies
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Fangy collects cookies. Once he decided to take a box and put cookies into it in some way. If we take a square *k*<=×<=*k* in size, divided into blocks 1<=×<=1 in size and paint there the main diagonal together with cells, which lie above it, then the painted area will be equal to the area occupied by one cookie *k* in size. Fangy also has a box with a square base 2*n*<=×<=2*n*, divided into blocks 1<=×<=1 in size. In a box the cookies should not overlap, and they should not be turned over or rotated. See cookies of sizes 2 and 4 respectively on the figure:
To stack the cookies the little walrus uses the following algorithm. He takes out of the repository the largest cookie which can fit in some place in the box and puts it there. Everything could be perfect but alas, in the repository the little walrus has infinitely many cookies of size 2 and larger, and there are no cookies of size 1, therefore, empty cells will remain in the box. Fangy wants to know how many empty cells will be left in the end.
Input Specification:
The first line contains a single integer *n* (0<=≤<=*n*<=≤<=1000).
Output Specification:
Print the single number, equal to the number of empty cells in the box. The answer should be printed modulo 106<=+<=3.
Demo Input:
['3\n']
Demo Output:
['9']
Note:
If the box possesses the base of 2<sup class="upper-index">3</sup> × 2<sup class="upper-index">3</sup> (as in the example), then the cookies will be put there in the following manner: | ```python
n = int(input())
if n == 0:
print(1)
else:
ans = 1
for i in range(n - 1):
ans *= 3
print(ans % 1000003)
``` | 3.9587 |
938 | B | Run For Your Prize | PROGRAMMING | 1,100 | [
"brute force",
"greedy"
] | null | null | You and your friend are participating in a TV show "Run For Your Prize".
At the start of the show *n* prizes are located on a straight line. *i*-th prize is located at position *a**i*. Positions of all prizes are distinct. You start at position 1, your friend — at position 106 (and there is no prize in any of these two positions). You have to work as a team and collect all prizes in minimum possible time, in any order.
You know that it takes exactly 1 second to move from position *x* to position *x*<=+<=1 or *x*<=-<=1, both for you and your friend. You also have trained enough to instantly pick up any prize, if its position is equal to your current position (and the same is true for your friend). Carrying prizes does not affect your speed (or your friend's speed) at all.
Now you may discuss your strategy with your friend and decide who will pick up each prize. Remember that every prize must be picked up, either by you or by your friend.
What is the minimum number of seconds it will take to pick up all the prizes? | The first line contains one integer *n* (1<=≤<=*n*<=≤<=105) — the number of prizes.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (2<=≤<=*a**i*<=≤<=106<=-<=1) — the positions of the prizes. No two prizes are located at the same position. Positions are given in ascending order. | Print one integer — the minimum number of seconds it will take to collect all prizes. | [
"3\n2 3 9\n",
"2\n2 999995\n"
] | [
"8\n",
"5\n"
] | In the first example you take all the prizes: take the first at 1, the second at 2 and the third at 8.
In the second example you take the first prize in 1 second and your friend takes the other in 5 seconds, you do this simultaneously, so the total time is 5. | 0 | [
{
"input": "3\n2 3 9",
"output": "8"
},
{
"input": "2\n2 999995",
"output": "5"
},
{
"input": "1\n20",
"output": "19"
},
{
"input": "6\n2 3 500000 999997 999998 999999",
"output": "499999"
},
{
"input": "1\n999999",
"output": "1"
},
{
"input": "1\n5100... | 1,615,464,531 | 531 | PyPy 3 | OK | TESTS | 48 | 171 | 10,444,800 | import sys,math,itertools
from collections import Counter,deque,defaultdict
from bisect import bisect_left,bisect_right
from heapq import heappop,heappush,heapify, nlargest
from copy import deepcopy
mod = 10**9+7
INF = float('inf')
def inp(): return int(sys.stdin.readline())
def inpl(): return list(map(int, sys.stdin.readline().split()))
def inpl_1(): return list(map(lambda x:int(x)-1, sys.stdin.readline().split()))
def inps(): return sys.stdin.readline()
def inpsl(x): tmp = sys.stdin.readline(); return list(tmp[:x])
def err(x): print(x); exit()
n = inp()
a = [0] + inpl() + [10**6]
res = INF
for i in range(n+1):
res = min(res, max(a[i]-1,10**6-a[i+1]))
print(res) | Title: Run For Your Prize
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You and your friend are participating in a TV show "Run For Your Prize".
At the start of the show *n* prizes are located on a straight line. *i*-th prize is located at position *a**i*. Positions of all prizes are distinct. You start at position 1, your friend — at position 106 (and there is no prize in any of these two positions). You have to work as a team and collect all prizes in minimum possible time, in any order.
You know that it takes exactly 1 second to move from position *x* to position *x*<=+<=1 or *x*<=-<=1, both for you and your friend. You also have trained enough to instantly pick up any prize, if its position is equal to your current position (and the same is true for your friend). Carrying prizes does not affect your speed (or your friend's speed) at all.
Now you may discuss your strategy with your friend and decide who will pick up each prize. Remember that every prize must be picked up, either by you or by your friend.
What is the minimum number of seconds it will take to pick up all the prizes?
Input Specification:
The first line contains one integer *n* (1<=≤<=*n*<=≤<=105) — the number of prizes.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (2<=≤<=*a**i*<=≤<=106<=-<=1) — the positions of the prizes. No two prizes are located at the same position. Positions are given in ascending order.
Output Specification:
Print one integer — the minimum number of seconds it will take to collect all prizes.
Demo Input:
['3\n2 3 9\n', '2\n2 999995\n']
Demo Output:
['8\n', '5\n']
Note:
In the first example you take all the prizes: take the first at 1, the second at 2 and the third at 8.
In the second example you take the first prize in 1 second and your friend takes the other in 5 seconds, you do this simultaneously, so the total time is 5. | ```python
import sys,math,itertools
from collections import Counter,deque,defaultdict
from bisect import bisect_left,bisect_right
from heapq import heappop,heappush,heapify, nlargest
from copy import deepcopy
mod = 10**9+7
INF = float('inf')
def inp(): return int(sys.stdin.readline())
def inpl(): return list(map(int, sys.stdin.readline().split()))
def inpl_1(): return list(map(lambda x:int(x)-1, sys.stdin.readline().split()))
def inps(): return sys.stdin.readline()
def inpsl(x): tmp = sys.stdin.readline(); return list(tmp[:x])
def err(x): print(x); exit()
n = inp()
a = [0] + inpl() + [10**6]
res = INF
for i in range(n+1):
res = min(res, max(a[i]-1,10**6-a[i+1]))
print(res)
``` | 3 | |
746 | B | Decoding | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Polycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the two middle letters. In the following examples, the median letter is highlighted: contest, info. If the word consists of single letter, then according to above definition this letter is the median letter.
Polycarp encodes each word in the following way: he writes down the median letter of the word, then deletes it and repeats the process until there are no letters left. For example, he encodes the word volga as logva.
You are given an encoding *s* of some word, your task is to decode it. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=2000) — the length of the encoded word.
The second line contains the string *s* of length *n* consisting of lowercase English letters — the encoding. | Print the word that Polycarp encoded. | [
"5\nlogva\n",
"2\nno\n",
"4\nabba\n"
] | [
"volga\n",
"no\n",
"baba\n"
] | In the first example Polycarp encoded the word volga. At first, he wrote down the letter l from the position 3, after that his word looked like voga. After that Polycarp wrote down the letter o from the position 2, his word became vga. Then Polycarp wrote down the letter g which was at the second position, the word became va. Then he wrote down the letter v, then the letter a. Thus, the encoding looked like logva.
In the second example Polycarp encoded the word no. He wrote down the letter n, the word became o, and he wrote down the letter o. Thus, in this example, the word and its encoding are the same.
In the third example Polycarp encoded the word baba. At first, he wrote down the letter a, which was at the position 2, after that the word looked like bba. Then he wrote down the letter b, which was at the position 2, his word looked like ba. After that he wrote down the letter b, which was at the position 1, the word looked like a, and he wrote down that letter a. Thus, the encoding is abba. | 1,000 | [
{
"input": "5\nlogva",
"output": "volga"
},
{
"input": "2\nno",
"output": "no"
},
{
"input": "4\nabba",
"output": "baba"
},
{
"input": "51\nkfsmpaeviowvkdbuhdagquxxqniselafnfbrgbhmsugcbbnlrvv",
"output": "vlbcumbrfflsnxugdudvovamfkspeiwkbhaqxqieanbghsgbnrv"
},
{
"... | 1,655,216,780 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 46 | 0 | n=int(input())
str=input()
if n%2:
print(str[1::2][::-1]+str[0::2])
else:
print(str[0::2][::-1]+str[1::2])
| Title: Decoding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp is mad about coding, that is why he writes Sveta encoded messages. He calls the median letter in a word the letter which is in the middle of the word. If the word's length is even, the median letter is the left of the two middle letters. In the following examples, the median letter is highlighted: contest, info. If the word consists of single letter, then according to above definition this letter is the median letter.
Polycarp encodes each word in the following way: he writes down the median letter of the word, then deletes it and repeats the process until there are no letters left. For example, he encodes the word volga as logva.
You are given an encoding *s* of some word, your task is to decode it.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=2000) — the length of the encoded word.
The second line contains the string *s* of length *n* consisting of lowercase English letters — the encoding.
Output Specification:
Print the word that Polycarp encoded.
Demo Input:
['5\nlogva\n', '2\nno\n', '4\nabba\n']
Demo Output:
['volga\n', 'no\n', 'baba\n']
Note:
In the first example Polycarp encoded the word volga. At first, he wrote down the letter l from the position 3, after that his word looked like voga. After that Polycarp wrote down the letter o from the position 2, his word became vga. Then Polycarp wrote down the letter g which was at the second position, the word became va. Then he wrote down the letter v, then the letter a. Thus, the encoding looked like logva.
In the second example Polycarp encoded the word no. He wrote down the letter n, the word became o, and he wrote down the letter o. Thus, in this example, the word and its encoding are the same.
In the third example Polycarp encoded the word baba. At first, he wrote down the letter a, which was at the position 2, after that the word looked like bba. Then he wrote down the letter b, which was at the position 2, his word looked like ba. After that he wrote down the letter b, which was at the position 1, the word looked like a, and he wrote down that letter a. Thus, the encoding is abba. | ```python
n=int(input())
str=input()
if n%2:
print(str[1::2][::-1]+str[0::2])
else:
print(str[0::2][::-1]+str[1::2])
``` | 3 | |
346 | A | Alice and Bob | PROGRAMMING | 1,600 | [
"games",
"math",
"number theory"
] | null | null | It is so boring in the summer holiday, isn't it? So Alice and Bob have invented a new game to play. The rules are as follows. First, they get a set of *n* distinct integers. And then they take turns to make the following moves. During each move, either Alice or Bob (the player whose turn is the current) can choose two distinct integers *x* and *y* from the set, such that the set doesn't contain their absolute difference |*x*<=-<=*y*|. Then this player adds integer |*x*<=-<=*y*| to the set (so, the size of the set increases by one).
If the current player has no valid move, he (or she) loses the game. The question is who will finally win the game if both players play optimally. Remember that Alice always moves first. | The first line contains an integer *n* (2<=≤<=*n*<=≤<=100) — the initial number of elements in the set. The second line contains *n* distinct space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the elements of the set. | Print a single line with the winner's name. If Alice wins print "Alice", otherwise print "Bob" (without quotes). | [
"2\n2 3\n",
"2\n5 3\n",
"3\n5 6 7\n"
] | [
"Alice\n",
"Alice\n",
"Bob\n"
] | Consider the first test sample. Alice moves first, and the only move she can do is to choose 2 and 3, then to add 1 to the set. Next Bob moves, there is no valid move anymore, so the winner is Alice. | 500 | [
{
"input": "2\n2 3",
"output": "Alice"
},
{
"input": "2\n5 3",
"output": "Alice"
},
{
"input": "3\n5 6 7",
"output": "Bob"
},
{
"input": "10\n72 96 24 66 6 18 12 30 60 48",
"output": "Bob"
},
{
"input": "10\n78 66 6 60 18 84 36 96 72 48",
"output": "Bob"
},
... | 1,586,279,540 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 248 | 0 | n=int(input())
arr=list(map(int,input().split(' ')))
c=0
for el1 in arr:
for el2 in arr:
if(abs(el1-el2) not in arr and el1!=el2):
arr.append(abs(el1-el2))
c+=1
else:
break
if(c%2==0):
print("Bob")
else:
print("Alice")
| Title: Alice and Bob
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It is so boring in the summer holiday, isn't it? So Alice and Bob have invented a new game to play. The rules are as follows. First, they get a set of *n* distinct integers. And then they take turns to make the following moves. During each move, either Alice or Bob (the player whose turn is the current) can choose two distinct integers *x* and *y* from the set, such that the set doesn't contain their absolute difference |*x*<=-<=*y*|. Then this player adds integer |*x*<=-<=*y*| to the set (so, the size of the set increases by one).
If the current player has no valid move, he (or she) loses the game. The question is who will finally win the game if both players play optimally. Remember that Alice always moves first.
Input Specification:
The first line contains an integer *n* (2<=≤<=*n*<=≤<=100) — the initial number of elements in the set. The second line contains *n* distinct space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=109) — the elements of the set.
Output Specification:
Print a single line with the winner's name. If Alice wins print "Alice", otherwise print "Bob" (without quotes).
Demo Input:
['2\n2 3\n', '2\n5 3\n', '3\n5 6 7\n']
Demo Output:
['Alice\n', 'Alice\n', 'Bob\n']
Note:
Consider the first test sample. Alice moves first, and the only move she can do is to choose 2 and 3, then to add 1 to the set. Next Bob moves, there is no valid move anymore, so the winner is Alice. | ```python
n=int(input())
arr=list(map(int,input().split(' ')))
c=0
for el1 in arr:
for el2 in arr:
if(abs(el1-el2) not in arr and el1!=el2):
arr.append(abs(el1-el2))
c+=1
else:
break
if(c%2==0):
print("Bob")
else:
print("Alice")
``` | 0 | |
300 | A | Array | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. The product of all numbers in the second set is greater than zero (<=><=0). 1. The product of all numbers in the third set is equal to zero. 1. Each number from the initial array must occur in exactly one set.
Help Vitaly. Divide the given array. | The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=100). The second line contains *n* space-separated distinct integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=103) — the array elements. | In the first line print integer *n*1 (*n*1<=><=0) — the number of elements in the first set. Then print *n*1 numbers — the elements that got to the first set.
In the next line print integer *n*2 (*n*2<=><=0) — the number of elements in the second set. Then print *n*2 numbers — the elements that got to the second set.
In the next line print integer *n*3 (*n*3<=><=0) — the number of elements in the third set. Then print *n*3 numbers — the elements that got to the third set.
The printed sets must meet the described conditions. It is guaranteed that the solution exists. If there are several solutions, you are allowed to print any of them. | [
"3\n-1 2 0\n",
"4\n-1 -2 -3 0\n"
] | [
"1 -1\n1 2\n1 0\n",
"1 -1\n2 -3 -2\n1 0\n"
] | none | 500 | [
{
"input": "3\n-1 2 0",
"output": "1 -1\n1 2\n1 0"
},
{
"input": "4\n-1 -2 -3 0",
"output": "1 -1\n2 -3 -2\n1 0"
},
{
"input": "5\n-1 -2 1 2 0",
"output": "1 -1\n2 1 2\n2 0 -2"
},
{
"input": "100\n-64 -51 -75 -98 74 -26 -1 -8 -99 -76 -53 -80 -43 -22 -100 -62 -34 -5 -65 -81 -1... | 1,687,157,367 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | import sys
n = int(input())
a = list(map(int, input().split()))
#first array should have odd negative numbers
#second array should have even negative numbers
#third array should have one or more zeroes
#each array should have atleast one integer
neg = 0
ze = 0
for i in a:
if i < 0:
neg += 1
if i == 0:
ze += 1
#since a solution is always possible then neg should always be odd and ze > 0
a1,a2,a3 = [], [], []
for i in a:
if i < 0 and neg%2 != 0:
a1.append(i)
neg -= 1
elif i != 0 and neg % 2 == 0:
a2.append(i)
else:
a3.append(i)
ans1 = ""
ans2 = ""
ans3 = ""
for i in a1:
ans1 += str(i)+" "
for i in a2:
ans2 += str(i)+" "
for i in a3:
ans3 += str(i)+" "
print(len(a1), ans1)
print(len(a2), ans2)
print(len(a3), ans3) | Title: Array
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitaly has an array of *n* distinct integers. Vitaly wants to divide this array into three non-empty sets so as the following conditions hold:
1. The product of all numbers in the first set is less than zero (<=<<=0). 1. The product of all numbers in the second set is greater than zero (<=><=0). 1. The product of all numbers in the third set is equal to zero. 1. Each number from the initial array must occur in exactly one set.
Help Vitaly. Divide the given array.
Input Specification:
The first line of the input contains integer *n* (3<=≤<=*n*<=≤<=100). The second line contains *n* space-separated distinct integers *a*1,<=*a*2,<=...,<=*a**n* (|*a**i*|<=≤<=103) — the array elements.
Output Specification:
In the first line print integer *n*1 (*n*1<=><=0) — the number of elements in the first set. Then print *n*1 numbers — the elements that got to the first set.
In the next line print integer *n*2 (*n*2<=><=0) — the number of elements in the second set. Then print *n*2 numbers — the elements that got to the second set.
In the next line print integer *n*3 (*n*3<=><=0) — the number of elements in the third set. Then print *n*3 numbers — the elements that got to the third set.
The printed sets must meet the described conditions. It is guaranteed that the solution exists. If there are several solutions, you are allowed to print any of them.
Demo Input:
['3\n-1 2 0\n', '4\n-1 -2 -3 0\n']
Demo Output:
['1 -1\n1 2\n1 0\n', '1 -1\n2 -3 -2\n1 0\n']
Note:
none | ```python
import sys
n = int(input())
a = list(map(int, input().split()))
#first array should have odd negative numbers
#second array should have even negative numbers
#third array should have one or more zeroes
#each array should have atleast one integer
neg = 0
ze = 0
for i in a:
if i < 0:
neg += 1
if i == 0:
ze += 1
#since a solution is always possible then neg should always be odd and ze > 0
a1,a2,a3 = [], [], []
for i in a:
if i < 0 and neg%2 != 0:
a1.append(i)
neg -= 1
elif i != 0 and neg % 2 == 0:
a2.append(i)
else:
a3.append(i)
ans1 = ""
ans2 = ""
ans3 = ""
for i in a1:
ans1 += str(i)+" "
for i in a2:
ans2 += str(i)+" "
for i in a3:
ans3 += str(i)+" "
print(len(a1), ans1)
print(len(a2), ans2)
print(len(a3), ans3)
``` | 0 | |
983 | A | Finite or not? | PROGRAMMING | 1,700 | [
"implementation",
"math"
] | null | null | You are given several queries. Each query consists of three integers $p$, $q$ and $b$. You need to answer whether the result of $p/q$ in notation with base $b$ is a finite fraction.
A fraction in notation with base $b$ is finite if it contains finite number of numerals after the decimal point. It is also possible that a fraction has zero numerals after the decimal point. | The first line contains a single integer $n$ ($1 \le n \le 10^5$) — the number of queries.
Next $n$ lines contain queries, one per line. Each line contains three integers $p$, $q$, and $b$ ($0 \le p \le 10^{18}$, $1 \le q \le 10^{18}$, $2 \le b \le 10^{18}$). All numbers are given in notation with base $10$. | For each question, in a separate line, print Finite if the fraction is finite and Infinite otherwise. | [
"2\n6 12 10\n4 3 10\n",
"4\n1 1 2\n9 36 2\n4 12 3\n3 5 4\n"
] | [
"Finite\nInfinite\n",
"Finite\nFinite\nFinite\nInfinite\n"
] | $\frac{6}{12} = \frac{1}{2} = 0,5_{10}$
$\frac{4}{3} = 1,(3)_{10}$
$\frac{9}{36} = \frac{1}{4} = 0,01_2$
$\frac{4}{12} = \frac{1}{3} = 0,1_3$ | 500 | [
{
"input": "2\n6 12 10\n4 3 10",
"output": "Finite\nInfinite"
},
{
"input": "4\n1 1 2\n9 36 2\n4 12 3\n3 5 4",
"output": "Finite\nFinite\nFinite\nInfinite"
},
{
"input": "10\n10 5 3\n1 7 10\n7 5 7\n4 4 9\n6 5 2\n6 7 5\n9 9 7\n7 5 5\n6 6 4\n10 8 2",
"output": "Finite\nInfinite\nInfini... | 1,698,611,386 | 2,147,483,647 | PyPy 3-64 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | #include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
cout.tie(nullptr);
int t;
cin >> t;
while (t--) {
long long p, q, b;
cin >> p >> q >> b;
long long g = __gcd(p, q);
q /= g;
b = __gcd(q, b);
while (b != 1){
while (q % b == 0)
q /= b;
b = __gcd(q, b);
}
if (q == 1)
cout << "Finite\n";
else
cout << "Infinite\n";
}
return 0;
} | Title: Finite or not?
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given several queries. Each query consists of three integers $p$, $q$ and $b$. You need to answer whether the result of $p/q$ in notation with base $b$ is a finite fraction.
A fraction in notation with base $b$ is finite if it contains finite number of numerals after the decimal point. It is also possible that a fraction has zero numerals after the decimal point.
Input Specification:
The first line contains a single integer $n$ ($1 \le n \le 10^5$) — the number of queries.
Next $n$ lines contain queries, one per line. Each line contains three integers $p$, $q$, and $b$ ($0 \le p \le 10^{18}$, $1 \le q \le 10^{18}$, $2 \le b \le 10^{18}$). All numbers are given in notation with base $10$.
Output Specification:
For each question, in a separate line, print Finite if the fraction is finite and Infinite otherwise.
Demo Input:
['2\n6 12 10\n4 3 10\n', '4\n1 1 2\n9 36 2\n4 12 3\n3 5 4\n']
Demo Output:
['Finite\nInfinite\n', 'Finite\nFinite\nFinite\nInfinite\n']
Note:
$\frac{6}{12} = \frac{1}{2} = 0,5_{10}$
$\frac{4}{3} = 1,(3)_{10}$
$\frac{9}{36} = \frac{1}{4} = 0,01_2$
$\frac{4}{12} = \frac{1}{3} = 0,1_3$ | ```python
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
cout.tie(nullptr);
int t;
cin >> t;
while (t--) {
long long p, q, b;
cin >> p >> q >> b;
long long g = __gcd(p, q);
q /= g;
b = __gcd(q, b);
while (b != 1){
while (q % b == 0)
q /= b;
b = __gcd(q, b);
}
if (q == 1)
cout << "Finite\n";
else
cout << "Infinite\n";
}
return 0;
}
``` | -1 | |
0 | none | none | none | 0 | [
"none"
] | null | null | In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build exactly two teams.
After practice competition, participant number *i* got a score of *a**i*. Team score is defined as sum of scores of its participants. High school management is interested if it's possible to build two teams with equal scores. Your task is to answer that question. | The single line contains six integers *a*1,<=...,<=*a*6 (0<=≤<=*a**i*<=≤<=1000) — scores of the participants | Print "YES" (quotes for clarity), if it is possible to build teams with equal score, and "NO" otherwise.
You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES"). | [
"1 3 2 1 2 1\n",
"1 1 1 1 1 99\n"
] | [
"YES\n",
"NO\n"
] | In the first sample, first team can be composed of 1st, 2nd and 6th participant, second — of 3rd, 4th and 5th: team scores are 1 + 3 + 1 = 2 + 1 + 2 = 5.
In the second sample, score of participant number 6 is too high: his team score will be definitely greater. | 0 | [
{
"input": "1 3 2 1 2 1",
"output": "YES"
},
{
"input": "1 1 1 1 1 99",
"output": "NO"
},
{
"input": "1000 1000 1000 1000 1000 1000",
"output": "YES"
},
{
"input": "0 0 0 0 0 0",
"output": "YES"
},
{
"input": "633 609 369 704 573 416",
"output": "NO"
},
{
... | 1,511,414,127 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | num1, num2, num3, num4, num5, num6= input('Enter 6 numbers: ').split()
num1 = int(num1)
num2 = int(num2)
num3 = int(num3)
num4 = int(num4)
num5 = int(num5)
num6 = int(num6)
if ((num1+num2+num3)==(num4+num5+num6)):
print("Yes")
elif ((num1+num2+num4)==(num3+num5+num6)):
print("Yes")
elif ((num1+num2+num5)==(num3+num4+num6)):
print("Yes")
elif ((num1+num2+num6)==(num3+num4+num5)):
print("Yes")
elif ((num1+num3+num4)==(num2+num5+num6)):
print("Yes")
elif ((num1+num3+num5)==(num2+num4+num6)):
print("Yes")
elif ((num1+num3+num6)==(num2+num4+num5)):
print("Yes")
elif ((num1+num4+num5)==(num2+num3+num6)):
print("Yes")
elif ((num1+num4+num6)==(num2+num3+num5)):
print("Yes")
elif ((num1+num5+num6)==(num2+num3+num4)):
print("Yes")
else:
print("No") | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
In a small but very proud high school it was decided to win ACM ICPC. This goal requires to compose as many teams of three as possible, but since there were only 6 students who wished to participate, the decision was to build exactly two teams.
After practice competition, participant number *i* got a score of *a**i*. Team score is defined as sum of scores of its participants. High school management is interested if it's possible to build two teams with equal scores. Your task is to answer that question.
Input Specification:
The single line contains six integers *a*1,<=...,<=*a*6 (0<=≤<=*a**i*<=≤<=1000) — scores of the participants
Output Specification:
Print "YES" (quotes for clarity), if it is possible to build teams with equal score, and "NO" otherwise.
You can print each character either upper- or lowercase ("YeS" and "yes" are valid when the answer is "YES").
Demo Input:
['1 3 2 1 2 1\n', '1 1 1 1 1 99\n']
Demo Output:
['YES\n', 'NO\n']
Note:
In the first sample, first team can be composed of 1st, 2nd and 6th participant, second — of 3rd, 4th and 5th: team scores are 1 + 3 + 1 = 2 + 1 + 2 = 5.
In the second sample, score of participant number 6 is too high: his team score will be definitely greater. | ```python
num1, num2, num3, num4, num5, num6= input('Enter 6 numbers: ').split()
num1 = int(num1)
num2 = int(num2)
num3 = int(num3)
num4 = int(num4)
num5 = int(num5)
num6 = int(num6)
if ((num1+num2+num3)==(num4+num5+num6)):
print("Yes")
elif ((num1+num2+num4)==(num3+num5+num6)):
print("Yes")
elif ((num1+num2+num5)==(num3+num4+num6)):
print("Yes")
elif ((num1+num2+num6)==(num3+num4+num5)):
print("Yes")
elif ((num1+num3+num4)==(num2+num5+num6)):
print("Yes")
elif ((num1+num3+num5)==(num2+num4+num6)):
print("Yes")
elif ((num1+num3+num6)==(num2+num4+num5)):
print("Yes")
elif ((num1+num4+num5)==(num2+num3+num6)):
print("Yes")
elif ((num1+num4+num6)==(num2+num3+num5)):
print("Yes")
elif ((num1+num5+num6)==(num2+num3+num4)):
print("Yes")
else:
print("No")
``` | 0 | |
590 | C | Three States | PROGRAMMING | 2,200 | [
"dfs and similar",
"graphs",
"shortest paths"
] | null | null | The famous global economic crisis is approaching rapidly, so the states of Berman, Berance and Bertaly formed an alliance and allowed the residents of all member states to freely pass through the territory of any of them. In addition, it was decided that a road between the states should be built to guarantee so that one could any point of any country can be reached from any point of any other State.
Since roads are always expensive, the governments of the states of the newly formed alliance asked you to help them assess the costs. To do this, you have been issued a map that can be represented as a rectangle table consisting of *n* rows and *m* columns. Any cell of the map either belongs to one of three states, or is an area where it is allowed to build a road, or is an area where the construction of the road is not allowed. A cell is called passable, if it belongs to one of the states, or the road was built in this cell. From any passable cells you can move up, down, right and left, if the cell that corresponds to the movement exists and is passable.
Your task is to construct a road inside a minimum number of cells, so that it would be possible to get from any cell of any state to any cell of any other state using only passable cells.
It is guaranteed that initially it is possible to reach any cell of any state from any cell of this state, moving only along its cells. It is also guaranteed that for any state there is at least one cell that belongs to it. | The first line of the input contains the dimensions of the map *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of rows and columns respectively.
Each of the next *n* lines contain *m* characters, describing the rows of the map. Digits from 1 to 3 represent the accessory to the corresponding state. The character '.' corresponds to the cell where it is allowed to build a road and the character '#' means no construction is allowed in this cell. | Print a single integer — the minimum number of cells you need to build a road inside in order to connect all the cells of all states. If such a goal is unachievable, print -1. | [
"4 5\n11..2\n#..22\n#.323\n.#333",
"1 5\n1#2#3\n"
] | [
"2",
"-1\n"
] | none | 1,250 | [
{
"input": "4 5\n11..2\n#..22\n#.323\n.#333",
"output": "2"
},
{
"input": "1 5\n1#2#3",
"output": "-1"
},
{
"input": "3 4\n.2..\n...3\n.1#.",
"output": "2"
},
{
"input": "10 10\n##.#..#.#2\n...###....\n#..#....##\n.....#....\n.#........\n.....#####\n...#..#...\n....###...\n##... | 1,650,763,915 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 0 | from collections import deque
r, c = tuple(map(int, input().replace("\n","").split()))
land_map = [[0]*c for _ in range(r)]
for i in range(r):
line = input().rstrip("\n")
for j in range(c):
if line[j] == '.' or line[j] == '#':
land_map[i][j] = line[j]
else:
land_map[i][j] = int(line[j])
direc = [-1, 0, 1, 0, -1]
def find_road():
accessories = 0
start = (0, 0)
for i in range(r):
for j in range(c):
if land_map[i][j] != '.' and land_map[i][j] != '#':
accessories += 1
if land_map[start[0]][start[1]] == '.' or land_map[start[0]][start[1]] == '#':
start = (i, j)
dq = deque()
dq.append([0, start])
vis = set()
while dq:
dis, points = dq.pop()
if points in vis:
continue
if len(vis) == accessories:
return dis
vis.add(points)
x, y = points
for i in range(4):
dr, dc = x + direc[i], y + direc[i + 1]
if 0 <= dr < r and 0 <= dc < c:
if land_map[dr][dc] == '.':
dq.appendleft([dis+1, (dr, dc)])
elif land_map[dr][dc] != '#':
dq.append([dis, (dr, dc)])
return -1
print(find_road())
| Title: Three States
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The famous global economic crisis is approaching rapidly, so the states of Berman, Berance and Bertaly formed an alliance and allowed the residents of all member states to freely pass through the territory of any of them. In addition, it was decided that a road between the states should be built to guarantee so that one could any point of any country can be reached from any point of any other State.
Since roads are always expensive, the governments of the states of the newly formed alliance asked you to help them assess the costs. To do this, you have been issued a map that can be represented as a rectangle table consisting of *n* rows and *m* columns. Any cell of the map either belongs to one of three states, or is an area where it is allowed to build a road, or is an area where the construction of the road is not allowed. A cell is called passable, if it belongs to one of the states, or the road was built in this cell. From any passable cells you can move up, down, right and left, if the cell that corresponds to the movement exists and is passable.
Your task is to construct a road inside a minimum number of cells, so that it would be possible to get from any cell of any state to any cell of any other state using only passable cells.
It is guaranteed that initially it is possible to reach any cell of any state from any cell of this state, moving only along its cells. It is also guaranteed that for any state there is at least one cell that belongs to it.
Input Specification:
The first line of the input contains the dimensions of the map *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=1000) — the number of rows and columns respectively.
Each of the next *n* lines contain *m* characters, describing the rows of the map. Digits from 1 to 3 represent the accessory to the corresponding state. The character '.' corresponds to the cell where it is allowed to build a road and the character '#' means no construction is allowed in this cell.
Output Specification:
Print a single integer — the minimum number of cells you need to build a road inside in order to connect all the cells of all states. If such a goal is unachievable, print -1.
Demo Input:
['4 5\n11..2\n#..22\n#.323\n.#333', '1 5\n1#2#3\n']
Demo Output:
['2', '-1\n']
Note:
none | ```python
from collections import deque
r, c = tuple(map(int, input().replace("\n","").split()))
land_map = [[0]*c for _ in range(r)]
for i in range(r):
line = input().rstrip("\n")
for j in range(c):
if line[j] == '.' or line[j] == '#':
land_map[i][j] = line[j]
else:
land_map[i][j] = int(line[j])
direc = [-1, 0, 1, 0, -1]
def find_road():
accessories = 0
start = (0, 0)
for i in range(r):
for j in range(c):
if land_map[i][j] != '.' and land_map[i][j] != '#':
accessories += 1
if land_map[start[0]][start[1]] == '.' or land_map[start[0]][start[1]] == '#':
start = (i, j)
dq = deque()
dq.append([0, start])
vis = set()
while dq:
dis, points = dq.pop()
if points in vis:
continue
if len(vis) == accessories:
return dis
vis.add(points)
x, y = points
for i in range(4):
dr, dc = x + direc[i], y + direc[i + 1]
if 0 <= dr < r and 0 <= dc < c:
if land_map[dr][dc] == '.':
dq.appendleft([dis+1, (dr, dc)])
elif land_map[dr][dc] != '#':
dq.append([dis, (dr, dc)])
return -1
print(find_road())
``` | 0 | |
638 | B | Making Genome in Berland | PROGRAMMING | 1,500 | [
"*special",
"dfs and similar",
"strings"
] | null | null | Berland scientists face a very important task - given the parts of short DNA fragments, restore the dinosaur DNA! The genome of a berland dinosaur has noting in common with the genome that we've used to: it can have 26 distinct nucleotide types, a nucleotide of each type can occur at most once. If we assign distinct English letters to all nucleotides, then the genome of a Berland dinosaur will represent a non-empty string consisting of small English letters, such that each letter occurs in it at most once.
Scientists have *n* genome fragments that are represented as substrings (non-empty sequences of consecutive nucleotides) of the sought genome.
You face the following problem: help scientists restore the dinosaur genome. It is guaranteed that the input is not contradictory and at least one suitable line always exists. When the scientists found out that you are a strong programmer, they asked you in addition to choose the one with the minimum length. If there are multiple such strings, choose any string. | The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of genome fragments.
Each of the next lines contains one descriptions of a fragment. Each fragment is a non-empty string consisting of distinct small letters of the English alphabet. It is not guaranteed that the given fragments are distinct. Fragments could arbitrarily overlap and one fragment could be a substring of another one.
It is guaranteed that there is such string of distinct letters that contains all the given fragments as substrings. | In the single line of the output print the genome of the minimum length that contains all the given parts. All the nucleotides in the genome must be distinct. If there are multiple suitable strings, print the string of the minimum length. If there also are multiple suitable strings, you can print any of them. | [
"3\nbcd\nab\ncdef\n",
"4\nx\ny\nz\nw\n"
] | [
"abcdef\n",
"xyzw\n"
] | none | 1,000 | [
{
"input": "3\nbcd\nab\ncdef",
"output": "abcdef"
},
{
"input": "4\nx\ny\nz\nw",
"output": "xyzw"
},
{
"input": "25\nef\nfg\ngh\nhi\nij\njk\nkl\nlm\nmn\nno\nab\nbc\ncd\nde\nop\npq\nqr\nrs\nst\ntu\nuv\nvw\nwx\nxy\nyz",
"output": "abcdefghijklmnopqrstuvwxyz"
},
{
"input": "1\nf... | 1,458,548,892 | 73,692 | Python 3 | WRONG_ANSWER | PRETESTS | 2 | 46 | 5,120,000 | #number = random.randrange(start, stop, step)
n = int(input())
arr = []
arr2 = ""
for i in range(n):
arr.append(str(input()))
res = []
count = -1
z = 0
while len(arr) != 0:
z = 0
flag = False
for j in range(len(arr)):
for k in arr[j]:
for s in range(j,len(arr)):
if arr[s].find(k) != -1:
res.append(arr[j])
del arr[j]
flag = True
break
if flag:
break
if flag:
break
count += 1
for i in range(len(arr)):
if res[count].find(arr[i-z]) != -1:
del arr[i-z]
z+=1
continue
elif arr[i-z].find(res[count])!= -1:
res[count] = arr[i-z]
del arr[i-z]
z+=1
continue
if res[count].find(arr[i-z][0]) != -1:
res[count] += arr[i-z]
del arr[i-z]
z+=1
elif res[count].find(arr[i-z][-1]) != -1:
res[count] = arr[i-z] + res[count]
del arr[i-z]
z+=1
for t in res:
for m in t:
if arr2.find(m) == -1:
arr2 += m
print(arr2)
| Title: Making Genome in Berland
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Berland scientists face a very important task - given the parts of short DNA fragments, restore the dinosaur DNA! The genome of a berland dinosaur has noting in common with the genome that we've used to: it can have 26 distinct nucleotide types, a nucleotide of each type can occur at most once. If we assign distinct English letters to all nucleotides, then the genome of a Berland dinosaur will represent a non-empty string consisting of small English letters, such that each letter occurs in it at most once.
Scientists have *n* genome fragments that are represented as substrings (non-empty sequences of consecutive nucleotides) of the sought genome.
You face the following problem: help scientists restore the dinosaur genome. It is guaranteed that the input is not contradictory and at least one suitable line always exists. When the scientists found out that you are a strong programmer, they asked you in addition to choose the one with the minimum length. If there are multiple such strings, choose any string.
Input Specification:
The first line of the input contains a positive integer *n* (1<=≤<=*n*<=≤<=100) — the number of genome fragments.
Each of the next lines contains one descriptions of a fragment. Each fragment is a non-empty string consisting of distinct small letters of the English alphabet. It is not guaranteed that the given fragments are distinct. Fragments could arbitrarily overlap and one fragment could be a substring of another one.
It is guaranteed that there is such string of distinct letters that contains all the given fragments as substrings.
Output Specification:
In the single line of the output print the genome of the minimum length that contains all the given parts. All the nucleotides in the genome must be distinct. If there are multiple suitable strings, print the string of the minimum length. If there also are multiple suitable strings, you can print any of them.
Demo Input:
['3\nbcd\nab\ncdef\n', '4\nx\ny\nz\nw\n']
Demo Output:
['abcdef\n', 'xyzw\n']
Note:
none | ```python
#number = random.randrange(start, stop, step)
n = int(input())
arr = []
arr2 = ""
for i in range(n):
arr.append(str(input()))
res = []
count = -1
z = 0
while len(arr) != 0:
z = 0
flag = False
for j in range(len(arr)):
for k in arr[j]:
for s in range(j,len(arr)):
if arr[s].find(k) != -1:
res.append(arr[j])
del arr[j]
flag = True
break
if flag:
break
if flag:
break
count += 1
for i in range(len(arr)):
if res[count].find(arr[i-z]) != -1:
del arr[i-z]
z+=1
continue
elif arr[i-z].find(res[count])!= -1:
res[count] = arr[i-z]
del arr[i-z]
z+=1
continue
if res[count].find(arr[i-z][0]) != -1:
res[count] += arr[i-z]
del arr[i-z]
z+=1
elif res[count].find(arr[i-z][-1]) != -1:
res[count] = arr[i-z] + res[count]
del arr[i-z]
z+=1
for t in res:
for m in t:
if arr2.find(m) == -1:
arr2 += m
print(arr2)
``` | 0 | |
854 | A | Fraction | PROGRAMMING | 800 | [
"brute force",
"constructive algorithms",
"math"
] | null | null | Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction is called proper iff its numerator is smaller than its denominator (*a*<=<<=*b*) and that the fraction is called irreducible if its numerator and its denominator are coprime (they do not have positive common divisors except 1).
During his free time, Petya thinks about proper irreducible fractions and converts them to decimals using the calculator. One day he mistakenly pressed addition button (<=+<=) instead of division button (÷) and got sum of numerator and denominator that was equal to *n* instead of the expected decimal notation.
Petya wanted to restore the original fraction, but soon he realized that it might not be done uniquely. That's why he decided to determine maximum possible proper irreducible fraction such that sum of its numerator and denominator equals *n*. Help Petya deal with this problem. | In the only line of input there is an integer *n* (3<=≤<=*n*<=≤<=1000), the sum of numerator and denominator of the fraction. | Output two space-separated positive integers *a* and *b*, numerator and denominator of the maximum possible proper irreducible fraction satisfying the given sum. | [
"3\n",
"4\n",
"12\n"
] | [
"1 2\n",
"1 3\n",
"5 7\n"
] | none | 500 | [
{
"input": "3",
"output": "1 2"
},
{
"input": "4",
"output": "1 3"
},
{
"input": "12",
"output": "5 7"
},
{
"input": "34",
"output": "15 19"
},
{
"input": "13",
"output": "6 7"
},
{
"input": "11",
"output": "5 6"
},
{
"input": "24",
"ou... | 1,648,879,625 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 0 | #██████████ █ █ /█\ █ █ ███ /█\ ██████████████
"█ █ █ /███\ █ █ █ ██ /███\ /██/ "
#█ █ █ /█████\ █ █ █ ██ /█████\ /██/
"█ █ █ █!:) █ █ █ █ ██ █ █ /██/ "
#██████████ █████████ █(:| █ ████████ ████ █ █ /██/ "
" █ █ █ █!:) █ █ █ █ ██ █ █ /██/ "
# █ █ █ ███████ █ █ █ ██ ███████ /██/
" █ █ █ █ █ █ █ █ ██ █ █ ██/ "
#██████████ █ █ █ █ █ █ ███ █ █ ██████████████
a=int(input())
print(1,a-1) | Title: Fraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petya is a big fan of mathematics, especially its part related to fractions. Recently he learned that a fraction is called proper iff its numerator is smaller than its denominator (*a*<=<<=*b*) and that the fraction is called irreducible if its numerator and its denominator are coprime (they do not have positive common divisors except 1).
During his free time, Petya thinks about proper irreducible fractions and converts them to decimals using the calculator. One day he mistakenly pressed addition button (<=+<=) instead of division button (÷) and got sum of numerator and denominator that was equal to *n* instead of the expected decimal notation.
Petya wanted to restore the original fraction, but soon he realized that it might not be done uniquely. That's why he decided to determine maximum possible proper irreducible fraction such that sum of its numerator and denominator equals *n*. Help Petya deal with this problem.
Input Specification:
In the only line of input there is an integer *n* (3<=≤<=*n*<=≤<=1000), the sum of numerator and denominator of the fraction.
Output Specification:
Output two space-separated positive integers *a* and *b*, numerator and denominator of the maximum possible proper irreducible fraction satisfying the given sum.
Demo Input:
['3\n', '4\n', '12\n']
Demo Output:
['1 2\n', '1 3\n', '5 7\n']
Note:
none | ```python
#██████████ █ █ /█\ █ █ ███ /█\ ██████████████
"█ █ █ /███\ █ █ █ ██ /███\ /██/ "
#█ █ █ /█████\ █ █ █ ██ /█████\ /██/
"█ █ █ █!:) █ █ █ █ ██ █ █ /██/ "
#██████████ █████████ █(:| █ ████████ ████ █ █ /██/ "
" █ █ █ █!:) █ █ █ █ ██ █ █ /██/ "
# █ █ █ ███████ █ █ █ ██ ███████ /██/
" █ █ █ █ █ █ █ █ ██ █ █ ██/ "
#██████████ █ █ █ █ █ █ ███ █ █ ██████████████
a=int(input())
print(1,a-1)
``` | 0 | |
1,008 | A | Romaji | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after every consonant, but there can be any letter after any vowel. The only exception is a consonant "n"; after this letter, there can be any letter (not only a vowel) or there can be no letter at all. For example, the words "harakiri", "yupie", "man", and "nbo" are Berlanese while the words "horse", "king", "my", and "nz" are not.
Help Vitya find out if a word $s$ is Berlanese. | The first line of the input contains the string $s$ consisting of $|s|$ ($1\leq |s|\leq 100$) lowercase Latin letters. | Print "YES" (without quotes) if there is a vowel after every consonant except "n", otherwise print "NO".
You can print each letter in any case (upper or lower). | [
"sumimasen\n",
"ninja\n",
"codeforces\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first and second samples, a vowel goes after each consonant except "n", so the word is Berlanese.
In the third sample, the consonant "c" goes after the consonant "r", and the consonant "s" stands on the end, so the word is not Berlanese. | 500 | [
{
"input": "sumimasen",
"output": "YES"
},
{
"input": "ninja",
"output": "YES"
},
{
"input": "codeforces",
"output": "NO"
},
{
"input": "auuaoonntanonnuewannnnpuuinniwoonennyolonnnvienonpoujinndinunnenannmuveoiuuhikucuziuhunnnmunzancenen",
"output": "YES"
},
{
"in... | 1,636,880,611 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 46 | 4,505,600 | flag=True
s=input()
for i in range(len(s)-1):
if s[i] not in 'aeioun':
if str[i+1] not in 'aeiou':
flag=False
if i==len(str)-2:
if str[-1] not in 'aeioun':
flag=False
if flag == True:
print('YES')
else:
print('NO')
| Title: Romaji
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vitya has just started learning Berlanese language. It is known that Berlanese uses the Latin alphabet. Vowel letters are "a", "o", "u", "i", and "e". Other letters are consonant.
In Berlanese, there has to be a vowel after every consonant, but there can be any letter after any vowel. The only exception is a consonant "n"; after this letter, there can be any letter (not only a vowel) or there can be no letter at all. For example, the words "harakiri", "yupie", "man", and "nbo" are Berlanese while the words "horse", "king", "my", and "nz" are not.
Help Vitya find out if a word $s$ is Berlanese.
Input Specification:
The first line of the input contains the string $s$ consisting of $|s|$ ($1\leq |s|\leq 100$) lowercase Latin letters.
Output Specification:
Print "YES" (without quotes) if there is a vowel after every consonant except "n", otherwise print "NO".
You can print each letter in any case (upper or lower).
Demo Input:
['sumimasen\n', 'ninja\n', 'codeforces\n']
Demo Output:
['YES\n', 'YES\n', 'NO\n']
Note:
In the first and second samples, a vowel goes after each consonant except "n", so the word is Berlanese.
In the third sample, the consonant "c" goes after the consonant "r", and the consonant "s" stands on the end, so the word is not Berlanese. | ```python
flag=True
s=input()
for i in range(len(s)-1):
if s[i] not in 'aeioun':
if str[i+1] not in 'aeiou':
flag=False
if i==len(str)-2:
if str[-1] not in 'aeioun':
flag=False
if flag == True:
print('YES')
else:
print('NO')
``` | -1 | |
650 | A | Watchmen | PROGRAMMING | 1,400 | [
"data structures",
"geometry",
"math"
] | null | null | Watchmen are in a danger and Doctor Manhattan together with his friend Daniel Dreiberg should warn them as soon as possible. There are *n* watchmen on a plane, the *i*-th watchman is located at point (*x**i*,<=*y**i*).
They need to arrange a plan, but there are some difficulties on their way. As you know, Doctor Manhattan considers the distance between watchmen *i* and *j* to be |*x**i*<=-<=*x**j*|<=+<=|*y**i*<=-<=*y**j*|. Daniel, as an ordinary person, calculates the distance using the formula .
The success of the operation relies on the number of pairs (*i*,<=*j*) (1<=≤<=*i*<=<<=*j*<=≤<=*n*), such that the distance between watchman *i* and watchmen *j* calculated by Doctor Manhattan is equal to the distance between them calculated by Daniel. You were asked to compute the number of such pairs. | The first line of the input contains the single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of watchmen.
Each of the following *n* lines contains two integers *x**i* and *y**i* (|*x**i*|,<=|*y**i*|<=≤<=109).
Some positions may coincide. | Print the number of pairs of watchmen such that the distance between them calculated by Doctor Manhattan is equal to the distance calculated by Daniel. | [
"3\n1 1\n7 5\n1 5\n",
"6\n0 0\n0 1\n0 2\n-1 1\n0 1\n1 1\n"
] | [
"2\n",
"11\n"
] | In the first sample, the distance between watchman 1 and watchman 2 is equal to |1 - 7| + |1 - 5| = 10 for Doctor Manhattan and <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/bcb5b7064b5f02088da0fdcf677e6fda495dd0df.png" style="max-width: 100.0%;max-height: 100.0%;"/> for Daniel. For pairs (1, 1), (1, 5) and (7, 5), (1, 5) Doctor Manhattan and Daniel will calculate the same distances. | 500 | [
{
"input": "3\n1 1\n7 5\n1 5",
"output": "2"
},
{
"input": "6\n0 0\n0 1\n0 2\n-1 1\n0 1\n1 1",
"output": "11"
},
{
"input": "10\n46 -55\n46 45\n46 45\n83 -55\n46 45\n83 -55\n46 45\n83 45\n83 45\n46 -55",
"output": "33"
},
{
"input": "1\n-5 -90",
"output": "0"
},
{
... | 1,458,888,639 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 4,812,800 | #!/usr/bin/env python
from __future__ import print_function
from six.moves import input, range
uniq_elems = {}
dups = []
n = int(input())
l = []
for i in range(0, n):
x, y = [int(j) for j in input().split()]
if x == y:
l.append((x, y))
else:
if (x, y) in uniq_elems:
assert (y, x) in uniq_elems
if uniq_elems[(x, y)] > uniq_elems[(y, x)]:
if uniq_elems[(x, y)] == 1:
dups.append((x, y))
uniq_elems[(x, y)] += 1
else:
if uniq_elems[(y, x)] == 1:
dups.append((y, x))
uniq_elems[(y, x)] += 1
else:
uniq_elems[(x, y)] = 1
uniq_elems[(y, x)] = 1
l.append((x, y))
l.append((y, x))
l = sorted(l)
total_count = 0
count = 1
prev = None
for i in l:
if prev:
if prev[0] == i[0]:
count += 1
else:
if count > 1:
total_count += count * (count - 1) // 2
count = 1
prev = i
if count > 1:
total_count += count * (count - 1) // 2
for dup in dups:
total_count -= uniq_elems[dup] * (uniq_elems[dup] - 1) // 2
print(total_count)
| Title: Watchmen
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Watchmen are in a danger and Doctor Manhattan together with his friend Daniel Dreiberg should warn them as soon as possible. There are *n* watchmen on a plane, the *i*-th watchman is located at point (*x**i*,<=*y**i*).
They need to arrange a plan, but there are some difficulties on their way. As you know, Doctor Manhattan considers the distance between watchmen *i* and *j* to be |*x**i*<=-<=*x**j*|<=+<=|*y**i*<=-<=*y**j*|. Daniel, as an ordinary person, calculates the distance using the formula .
The success of the operation relies on the number of pairs (*i*,<=*j*) (1<=≤<=*i*<=<<=*j*<=≤<=*n*), such that the distance between watchman *i* and watchmen *j* calculated by Doctor Manhattan is equal to the distance between them calculated by Daniel. You were asked to compute the number of such pairs.
Input Specification:
The first line of the input contains the single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of watchmen.
Each of the following *n* lines contains two integers *x**i* and *y**i* (|*x**i*|,<=|*y**i*|<=≤<=109).
Some positions may coincide.
Output Specification:
Print the number of pairs of watchmen such that the distance between them calculated by Doctor Manhattan is equal to the distance calculated by Daniel.
Demo Input:
['3\n1 1\n7 5\n1 5\n', '6\n0 0\n0 1\n0 2\n-1 1\n0 1\n1 1\n']
Demo Output:
['2\n', '11\n']
Note:
In the first sample, the distance between watchman 1 and watchman 2 is equal to |1 - 7| + |1 - 5| = 10 for Doctor Manhattan and <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/bcb5b7064b5f02088da0fdcf677e6fda495dd0df.png" style="max-width: 100.0%;max-height: 100.0%;"/> for Daniel. For pairs (1, 1), (1, 5) and (7, 5), (1, 5) Doctor Manhattan and Daniel will calculate the same distances. | ```python
#!/usr/bin/env python
from __future__ import print_function
from six.moves import input, range
uniq_elems = {}
dups = []
n = int(input())
l = []
for i in range(0, n):
x, y = [int(j) for j in input().split()]
if x == y:
l.append((x, y))
else:
if (x, y) in uniq_elems:
assert (y, x) in uniq_elems
if uniq_elems[(x, y)] > uniq_elems[(y, x)]:
if uniq_elems[(x, y)] == 1:
dups.append((x, y))
uniq_elems[(x, y)] += 1
else:
if uniq_elems[(y, x)] == 1:
dups.append((y, x))
uniq_elems[(y, x)] += 1
else:
uniq_elems[(x, y)] = 1
uniq_elems[(y, x)] = 1
l.append((x, y))
l.append((y, x))
l = sorted(l)
total_count = 0
count = 1
prev = None
for i in l:
if prev:
if prev[0] == i[0]:
count += 1
else:
if count > 1:
total_count += count * (count - 1) // 2
count = 1
prev = i
if count > 1:
total_count += count * (count - 1) // 2
for dup in dups:
total_count -= uniq_elems[dup] * (uniq_elems[dup] - 1) // 2
print(total_count)
``` | -1 | |
924 | A | Mystical Mosaic | PROGRAMMING | 1,300 | [
"greedy",
"implementation"
] | null | null | There is a rectangular grid of *n* rows of *m* initially-white cells each.
Arkady performed a certain number (possibly zero) of operations on it. In the *i*-th operation, a non-empty subset of rows *R**i* and a non-empty subset of columns *C**i* are chosen. For each row *r* in *R**i* and each column *c* in *C**i*, the intersection of row *r* and column *c* is coloured black.
There's another constraint: a row or a column can only be chosen at most once among all operations. In other words, it means that no pair of (*i*,<=*j*) (*i*<=<<=*j*) exists such that or , where denotes intersection of sets, and denotes the empty set.
You are to determine whether a valid sequence of operations exists that produces a given final grid. | The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50) — the number of rows and columns of the grid, respectively.
Each of the following *n* lines contains a string of *m* characters, each being either '.' (denoting a white cell) or '#' (denoting a black cell), representing the desired setup. | If the given grid can be achieved by any valid sequence of operations, output "Yes"; otherwise output "No" (both without quotes).
You can print each character in any case (upper or lower). | [
"5 8\n.#.#..#.\n.....#..\n.#.#..#.\n#.#....#\n.....#..\n",
"5 5\n..#..\n..#..\n#####\n..#..\n..#..\n",
"5 9\n........#\n#........\n..##.#...\n.......#.\n....#.#.#\n"
] | [
"Yes\n",
"No\n",
"No\n"
] | For the first example, the desired setup can be produced by 3 operations, as is shown below.
For the second example, the desired setup cannot be produced, since in order to colour the center row, the third row and all columns must be selected in one operation, but after that no column can be selected again, hence it won't be possible to colour the other cells in the center column. | 500 | [
{
"input": "5 8\n.#.#..#.\n.....#..\n.#.#..#.\n#.#....#\n.....#..",
"output": "Yes"
},
{
"input": "5 5\n..#..\n..#..\n#####\n..#..\n..#..",
"output": "No"
},
{
"input": "5 9\n........#\n#........\n..##.#...\n.......#.\n....#.#.#",
"output": "No"
},
{
"input": "1 1\n#",
"o... | 1,690,495,599 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | print("_RANDOM_GUESS_1690495599.0685108")# 1690495599.0685327 | Title: Mystical Mosaic
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There is a rectangular grid of *n* rows of *m* initially-white cells each.
Arkady performed a certain number (possibly zero) of operations on it. In the *i*-th operation, a non-empty subset of rows *R**i* and a non-empty subset of columns *C**i* are chosen. For each row *r* in *R**i* and each column *c* in *C**i*, the intersection of row *r* and column *c* is coloured black.
There's another constraint: a row or a column can only be chosen at most once among all operations. In other words, it means that no pair of (*i*,<=*j*) (*i*<=<<=*j*) exists such that or , where denotes intersection of sets, and denotes the empty set.
You are to determine whether a valid sequence of operations exists that produces a given final grid.
Input Specification:
The first line contains two space-separated integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=50) — the number of rows and columns of the grid, respectively.
Each of the following *n* lines contains a string of *m* characters, each being either '.' (denoting a white cell) or '#' (denoting a black cell), representing the desired setup.
Output Specification:
If the given grid can be achieved by any valid sequence of operations, output "Yes"; otherwise output "No" (both without quotes).
You can print each character in any case (upper or lower).
Demo Input:
['5 8\n.#.#..#.\n.....#..\n.#.#..#.\n#.#....#\n.....#..\n', '5 5\n..#..\n..#..\n#####\n..#..\n..#..\n', '5 9\n........#\n#........\n..##.#...\n.......#.\n....#.#.#\n']
Demo Output:
['Yes\n', 'No\n', 'No\n']
Note:
For the first example, the desired setup can be produced by 3 operations, as is shown below.
For the second example, the desired setup cannot be produced, since in order to colour the center row, the third row and all columns must be selected in one operation, but after that no column can be selected again, hence it won't be possible to colour the other cells in the center column. | ```python
print("_RANDOM_GUESS_1690495599.0685108")# 1690495599.0685327
``` | 0 | |
43 | A | Football | PROGRAMMING | 1,000 | [
"strings"
] | A. Football | 2 | 256 | One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process. On the whole there are *n* lines in that description each of which described one goal. Every goal was marked with the name of the team that had scored it. Help Vasya, learn the name of the team that won the finals. It is guaranteed that the match did not end in a tie. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the description. Then follow *n* lines — for each goal the names of the teams that scored it. The names are non-empty lines consisting of uppercase Latin letters whose lengths do not exceed 10 symbols. It is guaranteed that the match did not end in a tie and the description contains no more than two different teams. | Print the name of the winning team. We remind you that in football the team that scores more goals is considered the winner. | [
"1\nABC\n",
"5\nA\nABA\nABA\nA\nA\n"
] | [
"ABC\n",
"A\n"
] | none | 500 | [
{
"input": "1\nABC",
"output": "ABC"
},
{
"input": "5\nA\nABA\nABA\nA\nA",
"output": "A"
},
{
"input": "2\nXTSJEP\nXTSJEP",
"output": "XTSJEP"
},
{
"input": "3\nXZYDJAEDZ\nXZYDJAEDZ\nXZYDJAEDZ",
"output": "XZYDJAEDZ"
},
{
"input": "3\nQCCYXL\nQCCYXL\nAXGLFQDD",
... | 1,601,552,909 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 218 | 0 | d = {}
res = ''
t = 0
for _ in range(int(input())):
s = input()
if s not in d:
d[s] = 1
else:
d[s] += 1
if d[s] > t:
res = s
t = d[s]
print(res) | Title: Football
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process. On the whole there are *n* lines in that description each of which described one goal. Every goal was marked with the name of the team that had scored it. Help Vasya, learn the name of the team that won the finals. It is guaranteed that the match did not end in a tie.
Input Specification:
The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the description. Then follow *n* lines — for each goal the names of the teams that scored it. The names are non-empty lines consisting of uppercase Latin letters whose lengths do not exceed 10 symbols. It is guaranteed that the match did not end in a tie and the description contains no more than two different teams.
Output Specification:
Print the name of the winning team. We remind you that in football the team that scores more goals is considered the winner.
Demo Input:
['1\nABC\n', '5\nA\nABA\nABA\nA\nA\n']
Demo Output:
['ABC\n', 'A\n']
Note:
none | ```python
d = {}
res = ''
t = 0
for _ in range(int(input())):
s = input()
if s not in d:
d[s] = 1
else:
d[s] += 1
if d[s] > t:
res = s
t = d[s]
print(res)
``` | 3.9455 |
703 | A | Mishka and Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mishka is a little polar bear. As known, little bears loves spending their free time playing dice for chocolates. Once in a wonderful sunny morning, walking around blocks of ice, Mishka met her friend Chris, and they started playing the game.
Rules of the game are very simple: at first number of rounds *n* is defined. In every round each of the players throws a cubical dice with distinct numbers from 1 to 6 written on its faces. Player, whose value after throwing the dice is greater, wins the round. In case if player dice values are equal, no one of them is a winner.
In average, player, who won most of the rounds, is the winner of the game. In case if two players won the same number of rounds, the result of the game is draw.
Mishka is still very little and can't count wins and losses, so she asked you to watch their game and determine its result. Please help her! | The first line of the input contains single integer *n* *n* (1<=≤<=*n*<=≤<=100) — the number of game rounds.
The next *n* lines contains rounds description. *i*-th of them contains pair of integers *m**i* and *c**i* (1<=≤<=*m**i*,<=<=*c**i*<=≤<=6) — values on dice upper face after Mishka's and Chris' throws in *i*-th round respectively. | If Mishka is the winner of the game, print "Mishka" (without quotes) in the only line.
If Chris is the winner of the game, print "Chris" (without quotes) in the only line.
If the result of the game is draw, print "Friendship is magic!^^" (without quotes) in the only line. | [
"3\n3 5\n2 1\n4 2\n",
"2\n6 1\n1 6\n",
"3\n1 5\n3 3\n2 2\n"
] | [
"Mishka",
"Friendship is magic!^^",
"Chris"
] | In the first sample case Mishka loses the first round, but wins second and third rounds and thus she is the winner of the game.
In the second sample case Mishka wins the first round, Chris wins the second round, and the game ends with draw with score 1:1.
In the third sample case Chris wins the first round, but there is no winner of the next two rounds. The winner of the game is Chris. | 500 | [
{
"input": "3\n3 5\n2 1\n4 2",
"output": "Mishka"
},
{
"input": "2\n6 1\n1 6",
"output": "Friendship is magic!^^"
},
{
"input": "3\n1 5\n3 3\n2 2",
"output": "Chris"
},
{
"input": "6\n4 1\n4 2\n5 3\n5 1\n5 3\n4 1",
"output": "Mishka"
},
{
"input": "8\n2 4\n1 4\n1 ... | 1,671,295,054 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 31 | 0 | for i in range(int(input())):
c=0
d=0
s=[]
x=[]
a,b=map(int,input().split())
c,d=map(int,input().split())
e,f=map(int,input().split())
a=s.append(a)
a=s.append(c)
a=s.append(e)
b=x.append(b)
b=x.append(d)
b=x.append(f)
for i in range(len(s)):
if(s[i]>x[i]):
c=c+1
else:
d=d+1
q="Mishka"
w="Chris"
r="Friendship is magic!^^"
if(c>d):
print(q)
elif(c<d):
print(w)
else:
print(r) | Title: Mishka and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mishka is a little polar bear. As known, little bears loves spending their free time playing dice for chocolates. Once in a wonderful sunny morning, walking around blocks of ice, Mishka met her friend Chris, and they started playing the game.
Rules of the game are very simple: at first number of rounds *n* is defined. In every round each of the players throws a cubical dice with distinct numbers from 1 to 6 written on its faces. Player, whose value after throwing the dice is greater, wins the round. In case if player dice values are equal, no one of them is a winner.
In average, player, who won most of the rounds, is the winner of the game. In case if two players won the same number of rounds, the result of the game is draw.
Mishka is still very little and can't count wins and losses, so she asked you to watch their game and determine its result. Please help her!
Input Specification:
The first line of the input contains single integer *n* *n* (1<=≤<=*n*<=≤<=100) — the number of game rounds.
The next *n* lines contains rounds description. *i*-th of them contains pair of integers *m**i* and *c**i* (1<=≤<=*m**i*,<=<=*c**i*<=≤<=6) — values on dice upper face after Mishka's and Chris' throws in *i*-th round respectively.
Output Specification:
If Mishka is the winner of the game, print "Mishka" (without quotes) in the only line.
If Chris is the winner of the game, print "Chris" (without quotes) in the only line.
If the result of the game is draw, print "Friendship is magic!^^" (without quotes) in the only line.
Demo Input:
['3\n3 5\n2 1\n4 2\n', '2\n6 1\n1 6\n', '3\n1 5\n3 3\n2 2\n']
Demo Output:
['Mishka', 'Friendship is magic!^^', 'Chris']
Note:
In the first sample case Mishka loses the first round, but wins second and third rounds and thus she is the winner of the game.
In the second sample case Mishka wins the first round, Chris wins the second round, and the game ends with draw with score 1:1.
In the third sample case Chris wins the first round, but there is no winner of the next two rounds. The winner of the game is Chris. | ```python
for i in range(int(input())):
c=0
d=0
s=[]
x=[]
a,b=map(int,input().split())
c,d=map(int,input().split())
e,f=map(int,input().split())
a=s.append(a)
a=s.append(c)
a=s.append(e)
b=x.append(b)
b=x.append(d)
b=x.append(f)
for i in range(len(s)):
if(s[i]>x[i]):
c=c+1
else:
d=d+1
q="Mishka"
w="Chris"
r="Friendship is magic!^^"
if(c>d):
print(q)
elif(c<d):
print(w)
else:
print(r)
``` | -1 | |
591 | B | Rebranding | PROGRAMMING | 1,200 | [
"implementation",
"strings"
] | null | null | The name of one small but proud corporation consists of *n* lowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand (both for the company and the goods it produces) or its components: the name, the logo, the slogan. They decided to start with the name.
For this purpose the corporation has consecutively hired *m* designers. Once a company hires the *i*-th designer, he immediately contributes to the creation of a new corporation name as follows: he takes the newest version of the name and replaces all the letters *x**i* by *y**i*, and all the letters *y**i* by *x**i*. This results in the new version. It is possible that some of these letters do no occur in the string. It may also happen that *x**i* coincides with *y**i*. The version of the name received after the work of the last designer becomes the new name of the corporation.
Manager Arkady has recently got a job in this company, but is already soaked in the spirit of teamwork and is very worried about the success of the rebranding. Naturally, he can't wait to find out what is the new name the Corporation will receive.
Satisfy Arkady's curiosity and tell him the final version of the name. | The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=200<=000) — the length of the initial name and the number of designers hired, respectively.
The second line consists of *n* lowercase English letters and represents the original name of the corporation.
Next *m* lines contain the descriptions of the designers' actions: the *i*-th of them contains two space-separated lowercase English letters *x**i* and *y**i*. | Print the new name of the corporation. | [
"6 1\npolice\np m\n",
"11 6\nabacabadaba\na b\nb c\na d\ne g\nf a\nb b\n"
] | [
"molice\n",
"cdcbcdcfcdc\n"
] | In the second sample the name of the corporation consecutively changes as follows:
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c7648432f7138ca53234357d7e08d1d119166055.png" style="max-width: 100.0%;max-height: 100.0%;"/>
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/de89ad7bc7f27c46ec34f5e66ce0dc23bd5bc90a.png" style="max-width: 100.0%;max-height: 100.0%;"/>
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/812e653c8d7ff496e6a0f04c676423806751531e.png" style="max-width: 100.0%;max-height: 100.0%;"/>
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/19c564fcefb8dde36256240a8b877bb6a4792bfe.png" style="max-width: 100.0%;max-height: 100.0%;"/>
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/e1cafd93792430ad1a49e893e04715383bdae757.png" style="max-width: 100.0%;max-height: 100.0%;"/> | 1,000 | [
{
"input": "6 1\npolice\np m",
"output": "molice"
},
{
"input": "11 6\nabacabadaba\na b\nb c\na d\ne g\nf a\nb b",
"output": "cdcbcdcfcdc"
},
{
"input": "1 1\nf\nz h",
"output": "f"
},
{
"input": "1 1\na\na b",
"output": "b"
},
{
"input": "10 10\nlellelleel\ne l\n... | 1,445,765,417 | 1,817 | Python 3 | OK | TESTS | 27 | 420 | 3,174,400 | def solve():
N, M = map(int, input().split())
name = input()
td = {}
for c in 'abcdefghijklmnopqrstuvwxyz':
td[c] = c
for i in range(M):
p, m = input().split()
if p == m:
continue
pt = td[p]
mt = td[m]
del td[p]
del td[m]
td[m] = pt
td[p] = mt
nd = {f: t for t, f in td.items()}
ans = ''.join([nd[c] for c in name])
print(ans)
if __name__ == '__main__':
solve()
| Title: Rebranding
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The name of one small but proud corporation consists of *n* lowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand (both for the company and the goods it produces) or its components: the name, the logo, the slogan. They decided to start with the name.
For this purpose the corporation has consecutively hired *m* designers. Once a company hires the *i*-th designer, he immediately contributes to the creation of a new corporation name as follows: he takes the newest version of the name and replaces all the letters *x**i* by *y**i*, and all the letters *y**i* by *x**i*. This results in the new version. It is possible that some of these letters do no occur in the string. It may also happen that *x**i* coincides with *y**i*. The version of the name received after the work of the last designer becomes the new name of the corporation.
Manager Arkady has recently got a job in this company, but is already soaked in the spirit of teamwork and is very worried about the success of the rebranding. Naturally, he can't wait to find out what is the new name the Corporation will receive.
Satisfy Arkady's curiosity and tell him the final version of the name.
Input Specification:
The first line of the input contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=200<=000) — the length of the initial name and the number of designers hired, respectively.
The second line consists of *n* lowercase English letters and represents the original name of the corporation.
Next *m* lines contain the descriptions of the designers' actions: the *i*-th of them contains two space-separated lowercase English letters *x**i* and *y**i*.
Output Specification:
Print the new name of the corporation.
Demo Input:
['6 1\npolice\np m\n', '11 6\nabacabadaba\na b\nb c\na d\ne g\nf a\nb b\n']
Demo Output:
['molice\n', 'cdcbcdcfcdc\n']
Note:
In the second sample the name of the corporation consecutively changes as follows:
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c7648432f7138ca53234357d7e08d1d119166055.png" style="max-width: 100.0%;max-height: 100.0%;"/>
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/de89ad7bc7f27c46ec34f5e66ce0dc23bd5bc90a.png" style="max-width: 100.0%;max-height: 100.0%;"/>
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/812e653c8d7ff496e6a0f04c676423806751531e.png" style="max-width: 100.0%;max-height: 100.0%;"/>
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/19c564fcefb8dde36256240a8b877bb6a4792bfe.png" style="max-width: 100.0%;max-height: 100.0%;"/>
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/e1cafd93792430ad1a49e893e04715383bdae757.png" style="max-width: 100.0%;max-height: 100.0%;"/> | ```python
def solve():
N, M = map(int, input().split())
name = input()
td = {}
for c in 'abcdefghijklmnopqrstuvwxyz':
td[c] = c
for i in range(M):
p, m = input().split()
if p == m:
continue
pt = td[p]
mt = td[m]
del td[p]
del td[m]
td[m] = pt
td[p] = mt
nd = {f: t for t, f in td.items()}
ans = ''.join([nd[c] for c in name])
print(ans)
if __name__ == '__main__':
solve()
``` | 3 | |
626 | A | Robot Sequence | PROGRAMMING | 1,000 | [
"brute force",
"implementation"
] | null | null | Calvin the robot lies in an infinite rectangular grid. Calvin's source code contains a list of *n* commands, each either 'U', 'R', 'D', or 'L' — instructions to move a single square up, right, down, or left, respectively. How many ways can Calvin execute a non-empty contiguous substrings of commands and return to the same square he starts in? Two substrings are considered different if they have different starting or ending indices. | The first line of the input contains a single positive integer, *n* (1<=≤<=*n*<=≤<=200) — the number of commands.
The next line contains *n* characters, each either 'U', 'R', 'D', or 'L' — Calvin's source code. | Print a single integer — the number of contiguous substrings that Calvin can execute and return to his starting square. | [
"6\nURLLDR\n",
"4\nDLUU\n",
"7\nRLRLRLR\n"
] | [
"2\n",
"0\n",
"12\n"
] | In the first case, the entire source code works, as well as the "RL" substring in the second and third characters.
Note that, in the third case, the substring "LR" appears three times, and is therefore counted three times to the total result. | 500 | [
{
"input": "6\nURLLDR",
"output": "2"
},
{
"input": "4\nDLUU",
"output": "0"
},
{
"input": "7\nRLRLRLR",
"output": "12"
},
{
"input": "1\nR",
"output": "0"
},
{
"input": "100\nURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDLURDL... | 1,566,419,574 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 140 | 0 | n=int(input())
a=input()
ans=0
for i in range(n+1):
for j in range(i):
l=a[j:i].count("L")
r=a[j:i].count("R")
u=a[j:i].count("U")
d=a[j:i].count("D")
if l==r and u==d:
ans+=1
print(ans)
| Title: Robot Sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Calvin the robot lies in an infinite rectangular grid. Calvin's source code contains a list of *n* commands, each either 'U', 'R', 'D', or 'L' — instructions to move a single square up, right, down, or left, respectively. How many ways can Calvin execute a non-empty contiguous substrings of commands and return to the same square he starts in? Two substrings are considered different if they have different starting or ending indices.
Input Specification:
The first line of the input contains a single positive integer, *n* (1<=≤<=*n*<=≤<=200) — the number of commands.
The next line contains *n* characters, each either 'U', 'R', 'D', or 'L' — Calvin's source code.
Output Specification:
Print a single integer — the number of contiguous substrings that Calvin can execute and return to his starting square.
Demo Input:
['6\nURLLDR\n', '4\nDLUU\n', '7\nRLRLRLR\n']
Demo Output:
['2\n', '0\n', '12\n']
Note:
In the first case, the entire source code works, as well as the "RL" substring in the second and third characters.
Note that, in the third case, the substring "LR" appears three times, and is therefore counted three times to the total result. | ```python
n=int(input())
a=input()
ans=0
for i in range(n+1):
for j in range(i):
l=a[j:i].count("L")
r=a[j:i].count("R")
u=a[j:i].count("U")
d=a[j:i].count("D")
if l==r and u==d:
ans+=1
print(ans)
``` | 3 | |
839 | B | Game of the Rows | PROGRAMMING | 1,900 | [
"brute force",
"greedy",
"implementation"
] | null | null | Daenerys Targaryen has an army consisting of *k* groups of soldiers, the *i*-th group contains *a**i* soldiers. She wants to bring her army to the other side of the sea to get the Iron Throne. She has recently bought an airplane to carry her army through the sea. The airplane has *n* rows, each of them has 8 seats. We call two seats neighbor, if they are in the same row and in seats {1,<=2}, {3,<=4}, {4,<=5}, {5,<=6} or {7,<=8}.
Daenerys Targaryen wants to place her army in the plane so that there are no two soldiers from different groups sitting on neighboring seats.
Your task is to determine if there is a possible arranging of her army in the airplane such that the condition above is satisfied. | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10000, 1<=≤<=*k*<=≤<=100) — the number of rows and the number of groups of soldiers, respectively.
The second line contains *k* integers *a*1,<=*a*2,<=*a*3,<=...,<=*a**k* (1<=≤<=*a**i*<=≤<=10000), where *a**i* denotes the number of soldiers in the *i*-th group.
It is guaranteed that *a*1<=+<=*a*2<=+<=...<=+<=*a**k*<=≤<=8·*n*. | If we can place the soldiers in the airplane print "YES" (without quotes). Otherwise print "NO" (without quotes).
You can choose the case (lower or upper) for each letter arbitrary. | [
"2 2\n5 8\n",
"1 2\n7 1\n",
"1 2\n4 4\n",
"1 4\n2 2 1 2\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"YES\n"
] | In the first sample, Daenerys can place the soldiers like in the figure below:
In the second sample, there is no way to place the soldiers in the plane since the second group soldier will always have a seat neighboring to someone from the first group.
In the third example Daenerys can place the first group on seats (1, 2, 7, 8), and the second group an all the remaining seats.
In the fourth example she can place the first two groups on seats (1, 2) and (7, 8), the third group on seats (3), and the fourth group on seats (5, 6). | 1,000 | [
{
"input": "2 2\n5 8",
"output": "YES"
},
{
"input": "1 2\n7 1",
"output": "NO"
},
{
"input": "1 2\n4 4",
"output": "YES"
},
{
"input": "1 4\n2 2 1 2",
"output": "YES"
},
{
"input": "10000 100\n749 2244 949 2439 2703 44 2394 124 285 3694 3609 717 1413 155 974 1778... | 1,598,273,154 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 12 | 156 | 20,172,800 | from sys import stdin
n,k = [int(x) for x in stdin.readline().split()]
a = [int(x) for x in stdin.readline().split()]
if sum(a) <= n*3:
print('YES')
else:
a.sort(reverse=True)
four = n
two = n*2
one = 0
v = True
for x in a:
if x%2 == 1:
if one:
one -= 1
x -= 1
f = min(x//4,four)
x -= f*4
four -= f
t = x//2+x%2
if t > two+four:
v = False
break
elif t > two:
four -= t-two
one += t-two
two = 0
else:
two -= t
if v:
print('YES')
else:
print('NO')
| Title: Game of the Rows
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Daenerys Targaryen has an army consisting of *k* groups of soldiers, the *i*-th group contains *a**i* soldiers. She wants to bring her army to the other side of the sea to get the Iron Throne. She has recently bought an airplane to carry her army through the sea. The airplane has *n* rows, each of them has 8 seats. We call two seats neighbor, if they are in the same row and in seats {1,<=2}, {3,<=4}, {4,<=5}, {5,<=6} or {7,<=8}.
Daenerys Targaryen wants to place her army in the plane so that there are no two soldiers from different groups sitting on neighboring seats.
Your task is to determine if there is a possible arranging of her army in the airplane such that the condition above is satisfied.
Input Specification:
The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10000, 1<=≤<=*k*<=≤<=100) — the number of rows and the number of groups of soldiers, respectively.
The second line contains *k* integers *a*1,<=*a*2,<=*a*3,<=...,<=*a**k* (1<=≤<=*a**i*<=≤<=10000), where *a**i* denotes the number of soldiers in the *i*-th group.
It is guaranteed that *a*1<=+<=*a*2<=+<=...<=+<=*a**k*<=≤<=8·*n*.
Output Specification:
If we can place the soldiers in the airplane print "YES" (without quotes). Otherwise print "NO" (without quotes).
You can choose the case (lower or upper) for each letter arbitrary.
Demo Input:
['2 2\n5 8\n', '1 2\n7 1\n', '1 2\n4 4\n', '1 4\n2 2 1 2\n']
Demo Output:
['YES\n', 'NO\n', 'YES\n', 'YES\n']
Note:
In the first sample, Daenerys can place the soldiers like in the figure below:
In the second sample, there is no way to place the soldiers in the plane since the second group soldier will always have a seat neighboring to someone from the first group.
In the third example Daenerys can place the first group on seats (1, 2, 7, 8), and the second group an all the remaining seats.
In the fourth example she can place the first two groups on seats (1, 2) and (7, 8), the third group on seats (3), and the fourth group on seats (5, 6). | ```python
from sys import stdin
n,k = [int(x) for x in stdin.readline().split()]
a = [int(x) for x in stdin.readline().split()]
if sum(a) <= n*3:
print('YES')
else:
a.sort(reverse=True)
four = n
two = n*2
one = 0
v = True
for x in a:
if x%2 == 1:
if one:
one -= 1
x -= 1
f = min(x//4,four)
x -= f*4
four -= f
t = x//2+x%2
if t > two+four:
v = False
break
elif t > two:
four -= t-two
one += t-two
two = 0
else:
two -= t
if v:
print('YES')
else:
print('NO')
``` | 0 | |
915 | C | Permute Digits | PROGRAMMING | 1,700 | [
"dp",
"greedy"
] | null | null | You are given two positive integer numbers *a* and *b*. Permute (change order) of the digits of *a* to construct maximal number not exceeding *b*. No number in input and/or output can start with the digit 0.
It is allowed to leave *a* as it is. | The first line contains integer *a* (1<=≤<=*a*<=≤<=1018). The second line contains integer *b* (1<=≤<=*b*<=≤<=1018). Numbers don't have leading zeroes. It is guaranteed that answer exists. | Print the maximum possible number that is a permutation of digits of *a* and is not greater than *b*. The answer can't have any leading zeroes. It is guaranteed that the answer exists.
The number in the output should have exactly the same length as number *a*. It should be a permutation of digits of *a*. | [
"123\n222\n",
"3921\n10000\n",
"4940\n5000\n"
] | [
"213\n",
"9321\n",
"4940\n"
] | none | 0 | [
{
"input": "123\n222",
"output": "213"
},
{
"input": "3921\n10000",
"output": "9321"
},
{
"input": "4940\n5000",
"output": "4940"
},
{
"input": "23923472834\n23589234723",
"output": "23498743322"
},
{
"input": "102391019\n491010301",
"output": "399211100"
},... | 1,618,489,650 | 2,147,483,647 | Python 3 | OK | TESTS | 157 | 62 | 0 | a, b = sorted(input()), int(input())
for i in range(len(a)):
for j in range(i+1, len(a)):
c = int(str.join('', a))
a[i], a[j] = a[j], a[i]
d = int(str.join('', a))
if c <= d <= b:
continue
else:
a[i], a[j] = a[j], a[i]
print(str.join('', a)) | Title: Permute Digits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given two positive integer numbers *a* and *b*. Permute (change order) of the digits of *a* to construct maximal number not exceeding *b*. No number in input and/or output can start with the digit 0.
It is allowed to leave *a* as it is.
Input Specification:
The first line contains integer *a* (1<=≤<=*a*<=≤<=1018). The second line contains integer *b* (1<=≤<=*b*<=≤<=1018). Numbers don't have leading zeroes. It is guaranteed that answer exists.
Output Specification:
Print the maximum possible number that is a permutation of digits of *a* and is not greater than *b*. The answer can't have any leading zeroes. It is guaranteed that the answer exists.
The number in the output should have exactly the same length as number *a*. It should be a permutation of digits of *a*.
Demo Input:
['123\n222\n', '3921\n10000\n', '4940\n5000\n']
Demo Output:
['213\n', '9321\n', '4940\n']
Note:
none | ```python
a, b = sorted(input()), int(input())
for i in range(len(a)):
for j in range(i+1, len(a)):
c = int(str.join('', a))
a[i], a[j] = a[j], a[i]
d = int(str.join('', a))
if c <= d <= b:
continue
else:
a[i], a[j] = a[j], a[i]
print(str.join('', a))
``` | 3 | |
577 | A | Multiplication Table | PROGRAMMING | 1,000 | [
"implementation",
"number theory"
] | null | null | Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
You are given a positive integer *x*. Your task is to count the number of cells in a table that contain number *x*. | The single line contains numbers *n* and *x* (1<=≤<=*n*<=≤<=105, 1<=≤<=*x*<=≤<=109) — the size of the table and the number that we are looking for in the table. | Print a single number: the number of times *x* occurs in the table. | [
"10 5\n",
"6 12\n",
"5 13\n"
] | [
"2\n",
"4\n",
"0\n"
] | A table for the second sample test is given below. The occurrences of number 12 are marked bold. | 500 | [
{
"input": "10 5",
"output": "2"
},
{
"input": "6 12",
"output": "4"
},
{
"input": "5 13",
"output": "0"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "2 1",
"output": "1"
},
{
"input": "100000 1",
"output": "1"
},
{
"input": "1 10000000... | 1,641,304,581 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 5 | 1,000 | 0 | """https://codeforces.com/problemset/problem/577/A"""
rows, num = [int(x) for x in input().split()]
times = 0
for row in range(rows):
for column in range(rows):
if (row + 1) * (column + 1) == num:
times += 1
print(times)
| Title: Multiplication Table
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Let's consider a table consisting of *n* rows and *n* columns. The cell located at the intersection of *i*-th row and *j*-th column contains number *i*<=×<=*j*. The rows and columns are numbered starting from 1.
You are given a positive integer *x*. Your task is to count the number of cells in a table that contain number *x*.
Input Specification:
The single line contains numbers *n* and *x* (1<=≤<=*n*<=≤<=105, 1<=≤<=*x*<=≤<=109) — the size of the table and the number that we are looking for in the table.
Output Specification:
Print a single number: the number of times *x* occurs in the table.
Demo Input:
['10 5\n', '6 12\n', '5 13\n']
Demo Output:
['2\n', '4\n', '0\n']
Note:
A table for the second sample test is given below. The occurrences of number 12 are marked bold. | ```python
"""https://codeforces.com/problemset/problem/577/A"""
rows, num = [int(x) for x in input().split()]
times = 0
for row in range(rows):
for column in range(rows):
if (row + 1) * (column + 1) == num:
times += 1
print(times)
``` | 0 | |
855 | A | Tom Riddle's Diary | PROGRAMMING | 800 | [
"brute force",
"implementation",
"strings"
] | null | null | Harry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber of Secrets. Harry wants to know the different people who had ever possessed the diary to make sure they are not under its influence.
He has names of *n* people who possessed the diary in order. You need to tell, for each person, if he/she possessed the diary at some point before or not.
Formally, for a name *s**i* in the *i*-th line, output "YES" (without quotes) if there exists an index *j* such that *s**i*<==<=*s**j* and *j*<=<<=*i*, otherwise, output "NO" (without quotes). | First line of input contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of names in the list.
Next *n* lines each contain a string *s**i*, consisting of lowercase English letters. The length of each string is between 1 and 100. | Output *n* lines each containing either "YES" or "NO" (without quotes), depending on whether this string was already present in the stream or not.
You can print each letter in any case (upper or lower). | [
"6\ntom\nlucius\nginny\nharry\nginny\nharry\n",
"3\na\na\na\n"
] | [
"NO\nNO\nNO\nNO\nYES\nYES\n",
"NO\nYES\nYES\n"
] | In test case 1, for *i* = 5 there exists *j* = 3 such that *s*<sub class="lower-index">*i*</sub> = *s*<sub class="lower-index">*j*</sub> and *j* < *i*, which means that answer for *i* = 5 is "YES". | 500 | [
{
"input": "6\ntom\nlucius\nginny\nharry\nginny\nharry",
"output": "NO\nNO\nNO\nNO\nYES\nYES"
},
{
"input": "3\na\na\na",
"output": "NO\nYES\nYES"
},
{
"input": "1\nzn",
"output": "NO"
},
{
"input": "9\nliyzmbjwnzryjokufuxcqtzwworjeoxkbaqrujrhdidqdvwdfzilwszgnzglnnbogaclckfnb... | 1,584,771,694 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 3 | 139 | 0 | tests = int(input())
list =[]
for number in range(tests):
a= str(input())
list.append(a)
flag = 0
for temp in range(tests):
for temp1 in range(temp):
if list[temp]==list[temp1]:
flag = 1
break
if flag :
print('YES')
else:
print('NO') | Title: Tom Riddle's Diary
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Harry Potter is on a mission to destroy You-Know-Who's Horcruxes. The first Horcrux that he encountered in the Chamber of Secrets is Tom Riddle's diary. The diary was with Ginny and it forced her to open the Chamber of Secrets. Harry wants to know the different people who had ever possessed the diary to make sure they are not under its influence.
He has names of *n* people who possessed the diary in order. You need to tell, for each person, if he/she possessed the diary at some point before or not.
Formally, for a name *s**i* in the *i*-th line, output "YES" (without quotes) if there exists an index *j* such that *s**i*<==<=*s**j* and *j*<=<<=*i*, otherwise, output "NO" (without quotes).
Input Specification:
First line of input contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of names in the list.
Next *n* lines each contain a string *s**i*, consisting of lowercase English letters. The length of each string is between 1 and 100.
Output Specification:
Output *n* lines each containing either "YES" or "NO" (without quotes), depending on whether this string was already present in the stream or not.
You can print each letter in any case (upper or lower).
Demo Input:
['6\ntom\nlucius\nginny\nharry\nginny\nharry\n', '3\na\na\na\n']
Demo Output:
['NO\nNO\nNO\nNO\nYES\nYES\n', 'NO\nYES\nYES\n']
Note:
In test case 1, for *i* = 5 there exists *j* = 3 such that *s*<sub class="lower-index">*i*</sub> = *s*<sub class="lower-index">*j*</sub> and *j* < *i*, which means that answer for *i* = 5 is "YES". | ```python
tests = int(input())
list =[]
for number in range(tests):
a= str(input())
list.append(a)
flag = 0
for temp in range(tests):
for temp1 in range(temp):
if list[temp]==list[temp1]:
flag = 1
break
if flag :
print('YES')
else:
print('NO')
``` | 0 | |
29 | A | Spit Problem | PROGRAMMING | 1,000 | [
"brute force"
] | A. Spit Problem | 2 | 256 | In a Berland's zoo there is an enclosure with camels. It is known that camels like to spit. Bob watched these interesting animals for the whole day and registered in his notepad where each animal spitted. Now he wants to know if in the zoo there are two camels, which spitted at each other. Help him to solve this task.
The trajectory of a camel's spit is an arc, i.e. if the camel in position *x* spits *d* meters right, he can hit only the camel in position *x*<=+<=*d*, if such a camel exists. | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the amount of camels in the zoo. Each of the following *n* lines contains two integers *x**i* and *d**i* (<=-<=104<=≤<=*x**i*<=≤<=104,<=1<=≤<=|*d**i*|<=≤<=2·104) — records in Bob's notepad. *x**i* is a position of the *i*-th camel, and *d**i* is a distance at which the *i*-th camel spitted. Positive values of *d**i* correspond to the spits right, negative values correspond to the spits left. No two camels may stand in the same position. | If there are two camels, which spitted at each other, output YES. Otherwise, output NO. | [
"2\n0 1\n1 -1\n",
"3\n0 1\n1 1\n2 -2\n",
"5\n2 -10\n3 10\n0 5\n5 -5\n10 1\n"
] | [
"YES\n",
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "2\n0 1\n1 -1",
"output": "YES"
},
{
"input": "3\n0 1\n1 1\n2 -2",
"output": "NO"
},
{
"input": "5\n2 -10\n3 10\n0 5\n5 -5\n10 1",
"output": "YES"
},
{
"input": "10\n-9897 -1144\n-4230 -6350\n2116 -3551\n-3635 4993\n3907 -9071\n-2362 4120\n-6542 984\n5807 3745\n759... | 1,533,847,305 | 2,147,483,647 | Python 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | n = int(input())
pos = []
land = []
for i in range(n):
p, l = list(map(int,input().strip().split(' ')))
pos.append(p):
land.append(p + l)
c = 0
for i in land:
if i in pos:
c += 1
if c == 2:
print("YES")
break
if c != 2:
print("NO") | Title: Spit Problem
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
In a Berland's zoo there is an enclosure with camels. It is known that camels like to spit. Bob watched these interesting animals for the whole day and registered in his notepad where each animal spitted. Now he wants to know if in the zoo there are two camels, which spitted at each other. Help him to solve this task.
The trajectory of a camel's spit is an arc, i.e. if the camel in position *x* spits *d* meters right, he can hit only the camel in position *x*<=+<=*d*, if such a camel exists.
Input Specification:
The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the amount of camels in the zoo. Each of the following *n* lines contains two integers *x**i* and *d**i* (<=-<=104<=≤<=*x**i*<=≤<=104,<=1<=≤<=|*d**i*|<=≤<=2·104) — records in Bob's notepad. *x**i* is a position of the *i*-th camel, and *d**i* is a distance at which the *i*-th camel spitted. Positive values of *d**i* correspond to the spits right, negative values correspond to the spits left. No two camels may stand in the same position.
Output Specification:
If there are two camels, which spitted at each other, output YES. Otherwise, output NO.
Demo Input:
['2\n0 1\n1 -1\n', '3\n0 1\n1 1\n2 -2\n', '5\n2 -10\n3 10\n0 5\n5 -5\n10 1\n']
Demo Output:
['YES\n', 'NO\n', 'YES\n']
Note:
none | ```python
n = int(input())
pos = []
land = []
for i in range(n):
p, l = list(map(int,input().strip().split(' ')))
pos.append(p):
land.append(p + l)
c = 0
for i in land:
if i in pos:
c += 1
if c == 2:
print("YES")
break
if c != 2:
print("NO")
``` | -1 |
404 | A | Valera and X | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Valera is a little boy. Yesterday he got a huge Math hometask at school, so Valera didn't have enough time to properly learn the English alphabet for his English lesson. Unfortunately, the English teacher decided to have a test on alphabet today. At the test Valera got a square piece of squared paper. The length of the side equals *n* squares (*n* is an odd number) and each unit square contains some small letter of the English alphabet.
Valera needs to know if the letters written on the square piece of paper form letter "X". Valera's teacher thinks that the letters on the piece of paper form an "X", if:
- on both diagonals of the square paper all letters are the same; - all other squares of the paper (they are not on the diagonals) contain the same letter that is different from the letters on the diagonals.
Help Valera, write the program that completes the described task for him. | The first line contains integer *n* (3<=≤<=*n*<=<<=300; *n* is odd). Each of the next *n* lines contains *n* small English letters — the description of Valera's paper. | Print string "YES", if the letters on the paper form letter "X". Otherwise, print string "NO". Print the strings without quotes. | [
"5\nxooox\noxoxo\nsoxoo\noxoxo\nxooox\n",
"3\nwsw\nsws\nwsw\n",
"3\nxpx\npxp\nxpe\n"
] | [
"NO\n",
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "5\nxooox\noxoxo\nsoxoo\noxoxo\nxooox",
"output": "NO"
},
{
"input": "3\nwsw\nsws\nwsw",
"output": "YES"
},
{
"input": "3\nxpx\npxp\nxpe",
"output": "NO"
},
{
"input": "5\nliiil\nilili\niilii\nilili\nliiil",
"output": "YES"
},
{
"input": "7\nbwccccb\nck... | 1,697,557,705 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 7 | 46 | 0 | n = int(input())
a = []
for i in range(n):
a.append([*input()])
yes = True
for i in range(n):
for j in range(n):
if i == j or i + j == n-1:
if a[i][j] != a[0][0]:
yes = not yes
break
elif a[i][j] == a[0][0] or a[i][j] != a[0][1]:
yes = not yes
break
print('YES' if yes else 'NO')
| Title: Valera and X
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera is a little boy. Yesterday he got a huge Math hometask at school, so Valera didn't have enough time to properly learn the English alphabet for his English lesson. Unfortunately, the English teacher decided to have a test on alphabet today. At the test Valera got a square piece of squared paper. The length of the side equals *n* squares (*n* is an odd number) and each unit square contains some small letter of the English alphabet.
Valera needs to know if the letters written on the square piece of paper form letter "X". Valera's teacher thinks that the letters on the piece of paper form an "X", if:
- on both diagonals of the square paper all letters are the same; - all other squares of the paper (they are not on the diagonals) contain the same letter that is different from the letters on the diagonals.
Help Valera, write the program that completes the described task for him.
Input Specification:
The first line contains integer *n* (3<=≤<=*n*<=<<=300; *n* is odd). Each of the next *n* lines contains *n* small English letters — the description of Valera's paper.
Output Specification:
Print string "YES", if the letters on the paper form letter "X". Otherwise, print string "NO". Print the strings without quotes.
Demo Input:
['5\nxooox\noxoxo\nsoxoo\noxoxo\nxooox\n', '3\nwsw\nsws\nwsw\n', '3\nxpx\npxp\nxpe\n']
Demo Output:
['NO\n', 'YES\n', 'NO\n']
Note:
none | ```python
n = int(input())
a = []
for i in range(n):
a.append([*input()])
yes = True
for i in range(n):
for j in range(n):
if i == j or i + j == n-1:
if a[i][j] != a[0][0]:
yes = not yes
break
elif a[i][j] == a[0][0] or a[i][j] != a[0][1]:
yes = not yes
break
print('YES' if yes else 'NO')
``` | 0 | |
777 | B | Game of Credit Cards | PROGRAMMING | 1,300 | [
"data structures",
"dp",
"greedy",
"sortings"
] | null | null | After the fourth season Sherlock and Moriary have realized the whole foolishness of the battle between them and decided to continue their competitions in peaceful game of Credit Cards.
Rules of this game are simple: each player bring his favourite *n*-digit credit card. Then both players name the digits written on their cards one by one. If two digits are not equal, then the player, whose digit is smaller gets a flick (knock in the forehead usually made with a forefinger) from the other player. For example, if *n*<==<=3, Sherlock's card is 123 and Moriarty's card has number 321, first Sherlock names 1 and Moriarty names 3 so Sherlock gets a flick. Then they both digit 2 so no one gets a flick. Finally, Sherlock names 3, while Moriarty names 1 and gets a flick.
Of course, Sherlock will play honestly naming digits one by one in the order they are given, while Moriary, as a true villain, plans to cheat. He is going to name his digits in some other order (however, he is not going to change the overall number of occurences of each digit). For example, in case above Moriarty could name 1, 2, 3 and get no flicks at all, or he can name 2, 3 and 1 to give Sherlock two flicks.
Your goal is to find out the minimum possible number of flicks Moriarty will get (no one likes flicks) and the maximum possible number of flicks Sherlock can get from Moriarty. Note, that these two goals are different and the optimal result may be obtained by using different strategies. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of digits in the cards Sherlock and Moriarty are going to use.
The second line contains *n* digits — Sherlock's credit card number.
The third line contains *n* digits — Moriarty's credit card number. | First print the minimum possible number of flicks Moriarty will get. Then print the maximum possible number of flicks that Sherlock can get from Moriarty. | [
"3\n123\n321\n",
"2\n88\n00\n"
] | [
"0\n2\n",
"2\n0\n"
] | First sample is elaborated in the problem statement. In the second sample, there is no way Moriarty can avoid getting two flicks. | 1,000 | [
{
"input": "3\n123\n321",
"output": "0\n2"
},
{
"input": "2\n88\n00",
"output": "2\n0"
},
{
"input": "1\n4\n5",
"output": "0\n1"
},
{
"input": "1\n8\n7",
"output": "1\n0"
},
{
"input": "2\n55\n55",
"output": "0\n0"
},
{
"input": "3\n534\n432",
"out... | 1,585,051,404 | 2,147,483,647 | PyPy 3 | OK | TESTS | 55 | 156 | 0 | import sys
n=int(sys.stdin.readline())
sher=list(input())
mon=list(input())
sher.sort()
mon.sort()
#minimum no of flicks Mon will get
c=mon.copy()
d=sher.copy()
i=0
j=0
ans1=0
ans2=0
while(i<n and j<n):
if c[i]>=d[j]:
i+=1
j+=1
else:
i+=1
ans1+=1
print(ans1)
#max no off flick Mon can hit
c=mon.copy()
d=sher.copy()
i=0
j=0
while(i<n and j<n):
if c[i]>d[j]:
ans2+=1
i+=1
j+=1
else:
i+=1
print(ans2)
| Title: Game of Credit Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
After the fourth season Sherlock and Moriary have realized the whole foolishness of the battle between them and decided to continue their competitions in peaceful game of Credit Cards.
Rules of this game are simple: each player bring his favourite *n*-digit credit card. Then both players name the digits written on their cards one by one. If two digits are not equal, then the player, whose digit is smaller gets a flick (knock in the forehead usually made with a forefinger) from the other player. For example, if *n*<==<=3, Sherlock's card is 123 and Moriarty's card has number 321, first Sherlock names 1 and Moriarty names 3 so Sherlock gets a flick. Then they both digit 2 so no one gets a flick. Finally, Sherlock names 3, while Moriarty names 1 and gets a flick.
Of course, Sherlock will play honestly naming digits one by one in the order they are given, while Moriary, as a true villain, plans to cheat. He is going to name his digits in some other order (however, he is not going to change the overall number of occurences of each digit). For example, in case above Moriarty could name 1, 2, 3 and get no flicks at all, or he can name 2, 3 and 1 to give Sherlock two flicks.
Your goal is to find out the minimum possible number of flicks Moriarty will get (no one likes flicks) and the maximum possible number of flicks Sherlock can get from Moriarty. Note, that these two goals are different and the optimal result may be obtained by using different strategies.
Input Specification:
The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of digits in the cards Sherlock and Moriarty are going to use.
The second line contains *n* digits — Sherlock's credit card number.
The third line contains *n* digits — Moriarty's credit card number.
Output Specification:
First print the minimum possible number of flicks Moriarty will get. Then print the maximum possible number of flicks that Sherlock can get from Moriarty.
Demo Input:
['3\n123\n321\n', '2\n88\n00\n']
Demo Output:
['0\n2\n', '2\n0\n']
Note:
First sample is elaborated in the problem statement. In the second sample, there is no way Moriarty can avoid getting two flicks. | ```python
import sys
n=int(sys.stdin.readline())
sher=list(input())
mon=list(input())
sher.sort()
mon.sort()
#minimum no of flicks Mon will get
c=mon.copy()
d=sher.copy()
i=0
j=0
ans1=0
ans2=0
while(i<n and j<n):
if c[i]>=d[j]:
i+=1
j+=1
else:
i+=1
ans1+=1
print(ans1)
#max no off flick Mon can hit
c=mon.copy()
d=sher.copy()
i=0
j=0
while(i<n and j<n):
if c[i]>d[j]:
ans2+=1
i+=1
j+=1
else:
i+=1
print(ans2)
``` | 3 | |
200 | B | Drinks | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Little Vasya loves orange juice very much. That's why any food and drink in his kitchen necessarily contains orange juice. There are *n* drinks in his fridge, the volume fraction of orange juice in the *i*-th drink equals *p**i* percent.
One day Vasya decided to make himself an orange cocktail. He took equal proportions of each of the *n* drinks and mixed them. Then he wondered, how much orange juice the cocktail has.
Find the volume fraction of orange juice in the final drink. | The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of orange-containing drinks in Vasya's fridge. The second line contains *n* integers *p**i* (0<=≤<=*p**i*<=≤<=100) — the volume fraction of orange juice in the *i*-th drink, in percent. The numbers are separated by a space. | Print the volume fraction in percent of orange juice in Vasya's cocktail. The answer will be considered correct if the absolute or relative error does not exceed 10<=<=-<=4. | [
"3\n50 50 100\n",
"4\n0 25 50 75\n"
] | [
"66.666666666667\n",
"37.500000000000\n"
] | Note to the first sample: let's assume that Vasya takes *x* milliliters of each drink from the fridge. Then the volume of pure juice in the cocktail will equal <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c1fac6e64d3a8ee6a5ac138cbe51e60039b22473.png" style="max-width: 100.0%;max-height: 100.0%;"/> milliliters. The total cocktail's volume equals 3·*x* milliliters, so the volume fraction of the juice in the cocktail equals <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/ceb0664e55a1f9f5fa1243ec74680a4665a4d58d.png" style="max-width: 100.0%;max-height: 100.0%;"/>, that is, 66.(6) percent. | 500 | [
{
"input": "3\n50 50 100",
"output": "66.666666666667"
},
{
"input": "4\n0 25 50 75",
"output": "37.500000000000"
},
{
"input": "3\n0 1 8",
"output": "3.000000000000"
},
{
"input": "5\n96 89 93 95 70",
"output": "88.600000000000"
},
{
"input": "7\n62 41 78 4 38 39... | 1,695,846,408 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 92 | 0 | n = int(input())
percent = list(map(int, input().split()))
print(sum(percent)/n) | Title: Drinks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Vasya loves orange juice very much. That's why any food and drink in his kitchen necessarily contains orange juice. There are *n* drinks in his fridge, the volume fraction of orange juice in the *i*-th drink equals *p**i* percent.
One day Vasya decided to make himself an orange cocktail. He took equal proportions of each of the *n* drinks and mixed them. Then he wondered, how much orange juice the cocktail has.
Find the volume fraction of orange juice in the final drink.
Input Specification:
The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of orange-containing drinks in Vasya's fridge. The second line contains *n* integers *p**i* (0<=≤<=*p**i*<=≤<=100) — the volume fraction of orange juice in the *i*-th drink, in percent. The numbers are separated by a space.
Output Specification:
Print the volume fraction in percent of orange juice in Vasya's cocktail. The answer will be considered correct if the absolute or relative error does not exceed 10<=<=-<=4.
Demo Input:
['3\n50 50 100\n', '4\n0 25 50 75\n']
Demo Output:
['66.666666666667\n', '37.500000000000\n']
Note:
Note to the first sample: let's assume that Vasya takes *x* milliliters of each drink from the fridge. Then the volume of pure juice in the cocktail will equal <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c1fac6e64d3a8ee6a5ac138cbe51e60039b22473.png" style="max-width: 100.0%;max-height: 100.0%;"/> milliliters. The total cocktail's volume equals 3·*x* milliliters, so the volume fraction of the juice in the cocktail equals <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/ceb0664e55a1f9f5fa1243ec74680a4665a4d58d.png" style="max-width: 100.0%;max-height: 100.0%;"/>, that is, 66.(6) percent. | ```python
n = int(input())
percent = list(map(int, input().split()))
print(sum(percent)/n)
``` | 3 | |
522 | A | Reposts | PROGRAMMING | 1,200 | [
"*special",
"dfs and similar",
"dp",
"graphs",
"trees"
] | null | null | One day Polycarp published a funny picture in a social network making a poll about the color of his handle. Many of his friends started reposting Polycarp's joke to their news feed. Some of them reposted the reposts and so on.
These events are given as a sequence of strings "name1 reposted name2", where name1 is the name of the person who reposted the joke, and name2 is the name of the person from whose news feed the joke was reposted. It is guaranteed that for each string "name1 reposted name2" user "name1" didn't have the joke in his feed yet, and "name2" already had it in his feed by the moment of repost. Polycarp was registered as "Polycarp" and initially the joke was only in his feed.
Polycarp measures the popularity of the joke as the length of the largest repost chain. Print the popularity of Polycarp's joke. | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=200) — the number of reposts. Next follow the reposts in the order they were made. Each of them is written on a single line and looks as "name1 reposted name2". All the names in the input consist of lowercase or uppercase English letters and/or digits and have lengths from 2 to 24 characters, inclusive.
We know that the user names are case-insensitive, that is, two names that only differ in the letter case correspond to the same social network user. | Print a single integer — the maximum length of a repost chain. | [
"5\ntourist reposted Polycarp\nPetr reposted Tourist\nWJMZBMR reposted Petr\nsdya reposted wjmzbmr\nvepifanov reposted sdya\n",
"6\nMike reposted Polycarp\nMax reposted Polycarp\nEveryOne reposted Polycarp\n111 reposted Polycarp\nVkCup reposted Polycarp\nCodeforces reposted Polycarp\n",
"1\nSoMeStRaNgEgUe repos... | [
"6\n",
"2\n",
"2\n"
] | none | 500 | [
{
"input": "5\ntourist reposted Polycarp\nPetr reposted Tourist\nWJMZBMR reposted Petr\nsdya reposted wjmzbmr\nvepifanov reposted sdya",
"output": "6"
},
{
"input": "6\nMike reposted Polycarp\nMax reposted Polycarp\nEveryOne reposted Polycarp\n111 reposted Polycarp\nVkCup reposted Polycarp\nCodeforc... | 1,654,917,753 | 2,147,483,647 | PyPy 3 | OK | TESTS | 36 | 93 | 307,200 | import sys
input = sys.stdin.readline
from collections import defaultdict
n = int(input())
g = [input()[:-1].lower().split(' reposted ') for _ in range(n)]
d = defaultdict(int)
d['polycarp'] = 1
for i in range(n):
d[g[i][0]] += d[g[i][1]] + 1
print(max(d.values()))
| Title: Reposts
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Polycarp published a funny picture in a social network making a poll about the color of his handle. Many of his friends started reposting Polycarp's joke to their news feed. Some of them reposted the reposts and so on.
These events are given as a sequence of strings "name1 reposted name2", where name1 is the name of the person who reposted the joke, and name2 is the name of the person from whose news feed the joke was reposted. It is guaranteed that for each string "name1 reposted name2" user "name1" didn't have the joke in his feed yet, and "name2" already had it in his feed by the moment of repost. Polycarp was registered as "Polycarp" and initially the joke was only in his feed.
Polycarp measures the popularity of the joke as the length of the largest repost chain. Print the popularity of Polycarp's joke.
Input Specification:
The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=200) — the number of reposts. Next follow the reposts in the order they were made. Each of them is written on a single line and looks as "name1 reposted name2". All the names in the input consist of lowercase or uppercase English letters and/or digits and have lengths from 2 to 24 characters, inclusive.
We know that the user names are case-insensitive, that is, two names that only differ in the letter case correspond to the same social network user.
Output Specification:
Print a single integer — the maximum length of a repost chain.
Demo Input:
['5\ntourist reposted Polycarp\nPetr reposted Tourist\nWJMZBMR reposted Petr\nsdya reposted wjmzbmr\nvepifanov reposted sdya\n', '6\nMike reposted Polycarp\nMax reposted Polycarp\nEveryOne reposted Polycarp\n111 reposted Polycarp\nVkCup reposted Polycarp\nCodeforces reposted Polycarp\n', '1\nSoMeStRaNgEgUe reposted PoLyCaRp\n']
Demo Output:
['6\n', '2\n', '2\n']
Note:
none | ```python
import sys
input = sys.stdin.readline
from collections import defaultdict
n = int(input())
g = [input()[:-1].lower().split(' reposted ') for _ in range(n)]
d = defaultdict(int)
d['polycarp'] = 1
for i in range(n):
d[g[i][0]] += d[g[i][1]] + 1
print(max(d.values()))
``` | 3 | |
267 | A | Subtractions | PROGRAMMING | 900 | [
"math",
"number theory"
] | null | null | You've got two numbers. As long as they are both larger than zero, they go through the same operation: subtract the lesser number from the larger one. If they equal substract one number from the another. For example, one operation transforms pair (4,17) to pair (4,13), it transforms (5,5) to (0,5).
You've got some number of pairs (*a**i*,<=*b**i*). How many operations will be performed for each of them? | The first line contains the number of pairs *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000). Then follow *n* lines, each line contains a pair of positive integers *a**i*,<=*b**i* (1<=<=≤<=<=*a**i*,<=<=*b**i*<=<=≤<=<=109). | Print the sought number of operations for each pair on a single line. | [
"2\n4 17\n7 987654321\n"
] | [
"8\n141093479\n"
] | none | 500 | [
{
"input": "2\n4 17\n7 987654321",
"output": "8\n141093479"
},
{
"input": "10\n7 987654321\n7 987654321\n7 987654321\n7 987654321\n7 987654321\n7 987654321\n7 987654321\n7 987654321\n7 987654321\n7 987654321",
"output": "141093479\n141093479\n141093479\n141093479\n141093479\n141093479\n141093479... | 1,635,453,267 | 2,147,483,647 | PyPy 3 | OK | TESTS | 35 | 140 | 20,684,800 | n = int(input())
def compute(a, b):
iters = 0
while a > 0 and b > 0:
if a > b:
iters += a // b
a %= b
else:
iters += b // a
b %= a
return iters
for _ in range(n):
a, b = tuple(map(int, input().split()))
print(compute(a, b)) | Title: Subtractions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You've got two numbers. As long as they are both larger than zero, they go through the same operation: subtract the lesser number from the larger one. If they equal substract one number from the another. For example, one operation transforms pair (4,17) to pair (4,13), it transforms (5,5) to (0,5).
You've got some number of pairs (*a**i*,<=*b**i*). How many operations will be performed for each of them?
Input Specification:
The first line contains the number of pairs *n* (1<=<=≤<=<=*n*<=<=≤<=<=1000). Then follow *n* lines, each line contains a pair of positive integers *a**i*,<=*b**i* (1<=<=≤<=<=*a**i*,<=<=*b**i*<=<=≤<=<=109).
Output Specification:
Print the sought number of operations for each pair on a single line.
Demo Input:
['2\n4 17\n7 987654321\n']
Demo Output:
['8\n141093479\n']
Note:
none | ```python
n = int(input())
def compute(a, b):
iters = 0
while a > 0 and b > 0:
if a > b:
iters += a // b
a %= b
else:
iters += b // a
b %= a
return iters
for _ in range(n):
a, b = tuple(map(int, input().split()))
print(compute(a, b))
``` | 3 | |
439 | B | Devu, the Dumb Guy | PROGRAMMING | 1,200 | [
"implementation",
"sortings"
] | null | null | Devu is a dumb guy, his learning curve is very slow. You are supposed to teach him *n* subjects, the *i**th* subject has *c**i* chapters. When you teach him, you are supposed to teach all the chapters of a subject continuously.
Let us say that his initial per chapter learning power of a subject is *x* hours. In other words he can learn a chapter of a particular subject in *x* hours.
Well Devu is not complete dumb, there is a good thing about him too. If you teach him a subject, then time required to teach any chapter of the next subject will require exactly 1 hour less than previously required (see the examples to understand it more clearly). Note that his per chapter learning power can not be less than 1 hour.
You can teach him the *n* subjects in any possible order. Find out minimum amount of time (in hours) Devu will take to understand all the subjects and you will be free to do some enjoying task rather than teaching a dumb guy.
Please be careful that answer might not fit in 32 bit data type. | The first line will contain two space separated integers *n*, *x* (1<=≤<=*n*,<=*x*<=≤<=105). The next line will contain *n* space separated integers: *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=105). | Output a single integer representing the answer to the problem. | [
"2 3\n4 1\n",
"4 2\n5 1 2 1\n",
"3 3\n1 1 1\n"
] | [
"11\n",
"10\n",
"6\n"
] | Look at the first example. Consider the order of subjects: 1, 2. When you teach Devu the first subject, it will take him 3 hours per chapter, so it will take 12 hours to teach first subject. After teaching first subject, his per chapter learning time will be 2 hours. Now teaching him second subject will take 2 × 1 = 2 hours. Hence you will need to spend 12 + 2 = 14 hours.
Consider the order of subjects: 2, 1. When you teach Devu the second subject, then it will take him 3 hours per chapter, so it will take 3 × 1 = 3 hours to teach the second subject. After teaching the second subject, his per chapter learning time will be 2 hours. Now teaching him the first subject will take 2 × 4 = 8 hours. Hence you will need to spend 11 hours.
So overall, minimum of both the cases is 11 hours.
Look at the third example. The order in this example doesn't matter. When you teach Devu the first subject, it will take him 3 hours per chapter. When you teach Devu the second subject, it will take him 2 hours per chapter. When you teach Devu the third subject, it will take him 1 hours per chapter. In total it takes 6 hours. | 1,000 | [
{
"input": "2 3\n4 1",
"output": "11"
},
{
"input": "4 2\n5 1 2 1",
"output": "10"
},
{
"input": "3 3\n1 1 1",
"output": "6"
},
{
"input": "20 4\n1 1 3 5 5 1 3 4 2 5 2 4 3 1 3 3 3 3 4 3",
"output": "65"
},
{
"input": "20 10\n6 6 1 2 6 4 5 3 6 5 4 5 6 5 4 6 6 2 3 3... | 1,619,779,498 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 186 | 7,577,600 | n,m=map(int,input().split())
x=list(map(int,input().split()))
x.sort()
c=0
for i in range(n):
c+=x[i]*max((m-i),1)
print(c) | Title: Devu, the Dumb Guy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Devu is a dumb guy, his learning curve is very slow. You are supposed to teach him *n* subjects, the *i**th* subject has *c**i* chapters. When you teach him, you are supposed to teach all the chapters of a subject continuously.
Let us say that his initial per chapter learning power of a subject is *x* hours. In other words he can learn a chapter of a particular subject in *x* hours.
Well Devu is not complete dumb, there is a good thing about him too. If you teach him a subject, then time required to teach any chapter of the next subject will require exactly 1 hour less than previously required (see the examples to understand it more clearly). Note that his per chapter learning power can not be less than 1 hour.
You can teach him the *n* subjects in any possible order. Find out minimum amount of time (in hours) Devu will take to understand all the subjects and you will be free to do some enjoying task rather than teaching a dumb guy.
Please be careful that answer might not fit in 32 bit data type.
Input Specification:
The first line will contain two space separated integers *n*, *x* (1<=≤<=*n*,<=*x*<=≤<=105). The next line will contain *n* space separated integers: *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=105).
Output Specification:
Output a single integer representing the answer to the problem.
Demo Input:
['2 3\n4 1\n', '4 2\n5 1 2 1\n', '3 3\n1 1 1\n']
Demo Output:
['11\n', '10\n', '6\n']
Note:
Look at the first example. Consider the order of subjects: 1, 2. When you teach Devu the first subject, it will take him 3 hours per chapter, so it will take 12 hours to teach first subject. After teaching first subject, his per chapter learning time will be 2 hours. Now teaching him second subject will take 2 × 1 = 2 hours. Hence you will need to spend 12 + 2 = 14 hours.
Consider the order of subjects: 2, 1. When you teach Devu the second subject, then it will take him 3 hours per chapter, so it will take 3 × 1 = 3 hours to teach the second subject. After teaching the second subject, his per chapter learning time will be 2 hours. Now teaching him the first subject will take 2 × 4 = 8 hours. Hence you will need to spend 11 hours.
So overall, minimum of both the cases is 11 hours.
Look at the third example. The order in this example doesn't matter. When you teach Devu the first subject, it will take him 3 hours per chapter. When you teach Devu the second subject, it will take him 2 hours per chapter. When you teach Devu the third subject, it will take him 1 hours per chapter. In total it takes 6 hours. | ```python
n,m=map(int,input().split())
x=list(map(int,input().split()))
x.sort()
c=0
for i in range(n):
c+=x[i]*max((m-i),1)
print(c)
``` | 3 | |
507 | A | Amr and Music | PROGRAMMING | 1,000 | [
"greedy",
"implementation",
"sortings"
] | null | null | Amr is a young coder who likes music a lot. He always wanted to learn how to play music but he was busy coding so he got an idea.
Amr has *n* instruments, it takes *a**i* days to learn *i*-th instrument. Being busy, Amr dedicated *k* days to learn how to play the maximum possible number of instruments.
Amr asked for your help to distribute his free days between instruments so that he can achieve his goal. | The first line contains two numbers *n*, *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=10<=000), the number of instruments and number of days respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=100), representing number of days required to learn the *i*-th instrument. | In the first line output one integer *m* representing the maximum number of instruments Amr can learn.
In the second line output *m* space-separated integers: the indices of instruments to be learnt. You may output indices in any order.
if there are multiple optimal solutions output any. It is not necessary to use all days for studying. | [
"4 10\n4 3 1 2\n",
"5 6\n4 3 1 1 2\n",
"1 3\n4\n"
] | [
"4\n1 2 3 4",
"3\n1 3 4",
"0\n"
] | In the first test Amr can learn all 4 instruments.
In the second test other possible solutions are: {2, 3, 5} or {3, 4, 5}.
In the third test Amr doesn't have enough time to learn the only presented instrument. | 500 | [
{
"input": "4 10\n4 3 1 2",
"output": "4\n1 2 3 4"
},
{
"input": "5 6\n4 3 1 1 2",
"output": "3\n3 4 5"
},
{
"input": "1 3\n4",
"output": "0"
},
{
"input": "2 100\n100 100",
"output": "1\n1"
},
{
"input": "3 150\n50 50 50",
"output": "3\n1 2 3"
},
{
"i... | 1,664,028,488 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | from collections import defaultdict
n, k = map(int,input().split())
arr = list(map(int,input().split()))
index = defaultdict(list)
for i,n in enumerate(arr):
index[n].append(i)
ans = []
for n in sorted(set(arr)):
i = 0
while k-n>=0 and i<len(index[n]):
k-=n
ans.append(str(index[n][i]+1))
i += 1
print(len(arr))
print(" ".join(ans)) | Title: Amr and Music
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr is a young coder who likes music a lot. He always wanted to learn how to play music but he was busy coding so he got an idea.
Amr has *n* instruments, it takes *a**i* days to learn *i*-th instrument. Being busy, Amr dedicated *k* days to learn how to play the maximum possible number of instruments.
Amr asked for your help to distribute his free days between instruments so that he can achieve his goal.
Input Specification:
The first line contains two numbers *n*, *k* (1<=≤<=*n*<=≤<=100, 0<=≤<=*k*<=≤<=10<=000), the number of instruments and number of days respectively.
The second line contains *n* integers *a**i* (1<=≤<=*a**i*<=≤<=100), representing number of days required to learn the *i*-th instrument.
Output Specification:
In the first line output one integer *m* representing the maximum number of instruments Amr can learn.
In the second line output *m* space-separated integers: the indices of instruments to be learnt. You may output indices in any order.
if there are multiple optimal solutions output any. It is not necessary to use all days for studying.
Demo Input:
['4 10\n4 3 1 2\n', '5 6\n4 3 1 1 2\n', '1 3\n4\n']
Demo Output:
['4\n1 2 3 4', '3\n1 3 4', '0\n']
Note:
In the first test Amr can learn all 4 instruments.
In the second test other possible solutions are: {2, 3, 5} or {3, 4, 5}.
In the third test Amr doesn't have enough time to learn the only presented instrument. | ```python
from collections import defaultdict
n, k = map(int,input().split())
arr = list(map(int,input().split()))
index = defaultdict(list)
for i,n in enumerate(arr):
index[n].append(i)
ans = []
for n in sorted(set(arr)):
i = 0
while k-n>=0 and i<len(index[n]):
k-=n
ans.append(str(index[n][i]+1))
i += 1
print(len(arr))
print(" ".join(ans))
``` | 0 | |
887 | A | Div. 64 | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Top-model Izabella participates in the competition. She wants to impress judges and show her mathematical skills.
Her problem is following: for given string, consisting of only 0 and 1, tell if it's possible to remove some digits in such a way, that remaining number is a representation of some positive integer, divisible by 64, in the binary numerical system. | In the only line given a non-empty binary string *s* with length up to 100. | Print «yes» (without quotes) if it's possible to remove digits required way and «no» otherwise. | [
"100010001\n",
"100\n"
] | [
"yes",
"no"
] | In the first test case, you can get string 1 000 000 after removing two ones which is a representation of number 64 in the binary numerical system.
You can read more about binary numeral system representation here: [https://en.wikipedia.org/wiki/Binary_system](https://en.wikipedia.org/wiki/Binary_system) | 500 | [
{
"input": "100010001",
"output": "yes"
},
{
"input": "100",
"output": "no"
},
{
"input": "0000001000000",
"output": "yes"
},
{
"input": "1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111",
"output": "no"
},
{
"in... | 1,517,938,478 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 5,632,000 | number = input().strip()
if len(number) <= 4:
print("no")
else:
numOne = 0
for x in range(len(number)-4, len(number)):
if number[x] == 1:
numOne += 1
if numOne <= 1:
print("yes")
else:
pring("no")
| Title: Div. 64
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Top-model Izabella participates in the competition. She wants to impress judges and show her mathematical skills.
Her problem is following: for given string, consisting of only 0 and 1, tell if it's possible to remove some digits in such a way, that remaining number is a representation of some positive integer, divisible by 64, in the binary numerical system.
Input Specification:
In the only line given a non-empty binary string *s* with length up to 100.
Output Specification:
Print «yes» (without quotes) if it's possible to remove digits required way and «no» otherwise.
Demo Input:
['100010001\n', '100\n']
Demo Output:
['yes', 'no']
Note:
In the first test case, you can get string 1 000 000 after removing two ones which is a representation of number 64 in the binary numerical system.
You can read more about binary numeral system representation here: [https://en.wikipedia.org/wiki/Binary_system](https://en.wikipedia.org/wiki/Binary_system) | ```python
number = input().strip()
if len(number) <= 4:
print("no")
else:
numOne = 0
for x in range(len(number)-4, len(number)):
if number[x] == 1:
numOne += 1
if numOne <= 1:
print("yes")
else:
pring("no")
``` | 0 | |
678 | A | Johny Likes Numbers | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Johny likes numbers *n* and *k* very much. Now Johny wants to find the smallest integer *x* greater than *n*, so it is divisible by the number *k*. | The only line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=109). | Print the smallest integer *x*<=><=*n*, so it is divisible by the number *k*. | [
"5 3\n",
"25 13\n",
"26 13\n"
] | [
"6\n",
"26\n",
"39\n"
] | none | 0 | [
{
"input": "5 3",
"output": "6"
},
{
"input": "25 13",
"output": "26"
},
{
"input": "26 13",
"output": "39"
},
{
"input": "1 1",
"output": "2"
},
{
"input": "8 8",
"output": "16"
},
{
"input": "14 15",
"output": "15"
},
{
"input": "197 894"... | 1,676,617,905 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 37 | 78 | 0 | def solve():
n, k = [int(x) for x in input().split()]
print((n + k) - (n % k))
solve()
| Title: Johny Likes Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Johny likes numbers *n* and *k* very much. Now Johny wants to find the smallest integer *x* greater than *n*, so it is divisible by the number *k*.
Input Specification:
The only line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=109).
Output Specification:
Print the smallest integer *x*<=><=*n*, so it is divisible by the number *k*.
Demo Input:
['5 3\n', '25 13\n', '26 13\n']
Demo Output:
['6\n', '26\n', '39\n']
Note:
none | ```python
def solve():
n, k = [int(x) for x in input().split()]
print((n + k) - (n % k))
solve()
``` | 3 | |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,619,866,969 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 124 | 0 | d={"":0,"-":1,"--":2}
c=input()
pos=0
l=[]
for i in range(len(c)):
if c[i]==".":
l.append(c[pos:i+1])
pos=i+1
for j in l:
if len(j)%2==0:
l1=(len(j)-2)//2
print("2"*l1,end="")
print("1",end="")
else:
l1=(len(j)-1)//2
print("2"*l1,end="")
print("0",end="")
if c[len(c)-1]=="-":
a=c[pos:]
b=len(a)//2
print("2"*b)
| Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet.
Input Specification:
The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes).
Output Specification:
Output the decoded ternary number. It can have leading zeroes.
Demo Input:
['.-.--\n', '--.\n', '-..-.--\n']
Demo Output:
['012', '20', '1012']
Note:
none | ```python
d={"":0,"-":1,"--":2}
c=input()
pos=0
l=[]
for i in range(len(c)):
if c[i]==".":
l.append(c[pos:i+1])
pos=i+1
for j in l:
if len(j)%2==0:
l1=(len(j)-2)//2
print("2"*l1,end="")
print("1",end="")
else:
l1=(len(j)-1)//2
print("2"*l1,end="")
print("0",end="")
if c[len(c)-1]=="-":
a=c[pos:]
b=len(a)//2
print("2"*b)
``` | 3.969 |
839 | C | Journey | PROGRAMMING | 1,500 | [
"dfs and similar",
"dp",
"graphs",
"probabilities",
"trees"
] | null | null | There are *n* cities and *n*<=-<=1 roads in the Seven Kingdoms, each road connects two cities and we can reach any city from any other by the roads.
Theon and Yara Greyjoy are on a horse in the first city, they are starting traveling through the roads. But the weather is foggy, so they can’t see where the horse brings them. When the horse reaches a city (including the first one), it goes to one of the cities connected to the current city. But it is a strange horse, it only goes to cities in which they weren't before. In each such city, the horse goes with equal probabilities and it stops when there are no such cities.
Let the length of each road be 1. The journey starts in the city 1. What is the expected length (expected value of length) of their journey? You can read about expected (average) value by the link [https://en.wikipedia.org/wiki/Expected_value](https://en.wikipedia.org/wiki/Expected_value). | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100000) — number of cities.
Then *n*<=-<=1 lines follow. The *i*-th line of these lines contains two integers *u**i* and *v**i* (1<=≤<=*u**i*,<=*v**i*<=≤<=*n*, *u**i*<=≠<=*v**i*) — the cities connected by the *i*-th road.
It is guaranteed that one can reach any city from any other by the roads. | Print a number — the expected length of their journey. The journey starts in the city 1.
Your answer will be considered correct if its absolute or relative error does not exceed 10<=-<=6.
Namely: let's assume that your answer is *a*, and the answer of the jury is *b*. The checker program will consider your answer correct, if . | [
"4\n1 2\n1 3\n2 4\n",
"5\n1 2\n1 3\n3 4\n2 5\n"
] | [
"1.500000000000000\n",
"2.000000000000000\n"
] | In the first sample, their journey may end in cities 3 or 4 with equal probability. The distance to city 3 is 1 and to city 4 is 2, so the expected length is 1.5.
In the second sample, their journey may end in city 4 or 5. The distance to the both cities is 2, so the expected length is 2. | 1,500 | [
{
"input": "4\n1 2\n1 3\n2 4",
"output": "1.500000000000000"
},
{
"input": "5\n1 2\n1 3\n3 4\n2 5",
"output": "2.000000000000000"
},
{
"input": "70\n1 25\n57 1\n18 1\n65 1\n38 1\n1 41\n1 5\n1 69\n1 3\n31 1\n1 8\n1 9\n53 1\n70 1\n45 1\n1 24\n1 42\n1 30\n1 12\n1 37\n64 1\n1 28\n1 58\n1 22\... | 1,631,788,433 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 3 | 77 | 6,963,200 | def dfs(x,p):
if x==1:
l[x]=0
prob[x]=1
else:
l[x]=l[p]+1
prob[x]=1/(len(graph[p])-1)*prob[p]
if p==1:
prob[x]=1/(len(graph[p]))*prob[p]
for k in graph[x]:
if k!=p:
dfs(k,x)
if len(graph[x])==1 and x!=1:
leaf.append(x)
n = int(input())
graph = [[]]
for i in range(n+1):
graph.append([])
for i in range(n-1):
x,y=list(map(int,input().split(' ')))
graph[x].append(y)
graph[y].append(x)
l=[0 for i in range(n+1)]
prob=[0 for i in range(n+1)]
ans=0;
leaf =[]
dfs(1,0)
for i in leaf:
ans+=prob[i]*l[i]
if n==1:
print(1)
else:
print(ans)
| Title: Journey
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* cities and *n*<=-<=1 roads in the Seven Kingdoms, each road connects two cities and we can reach any city from any other by the roads.
Theon and Yara Greyjoy are on a horse in the first city, they are starting traveling through the roads. But the weather is foggy, so they can’t see where the horse brings them. When the horse reaches a city (including the first one), it goes to one of the cities connected to the current city. But it is a strange horse, it only goes to cities in which they weren't before. In each such city, the horse goes with equal probabilities and it stops when there are no such cities.
Let the length of each road be 1. The journey starts in the city 1. What is the expected length (expected value of length) of their journey? You can read about expected (average) value by the link [https://en.wikipedia.org/wiki/Expected_value](https://en.wikipedia.org/wiki/Expected_value).
Input Specification:
The first line contains a single integer *n* (1<=≤<=*n*<=≤<=100000) — number of cities.
Then *n*<=-<=1 lines follow. The *i*-th line of these lines contains two integers *u**i* and *v**i* (1<=≤<=*u**i*,<=*v**i*<=≤<=*n*, *u**i*<=≠<=*v**i*) — the cities connected by the *i*-th road.
It is guaranteed that one can reach any city from any other by the roads.
Output Specification:
Print a number — the expected length of their journey. The journey starts in the city 1.
Your answer will be considered correct if its absolute or relative error does not exceed 10<=-<=6.
Namely: let's assume that your answer is *a*, and the answer of the jury is *b*. The checker program will consider your answer correct, if .
Demo Input:
['4\n1 2\n1 3\n2 4\n', '5\n1 2\n1 3\n3 4\n2 5\n']
Demo Output:
['1.500000000000000\n', '2.000000000000000\n']
Note:
In the first sample, their journey may end in cities 3 or 4 with equal probability. The distance to city 3 is 1 and to city 4 is 2, so the expected length is 1.5.
In the second sample, their journey may end in city 4 or 5. The distance to the both cities is 2, so the expected length is 2. | ```python
def dfs(x,p):
if x==1:
l[x]=0
prob[x]=1
else:
l[x]=l[p]+1
prob[x]=1/(len(graph[p])-1)*prob[p]
if p==1:
prob[x]=1/(len(graph[p]))*prob[p]
for k in graph[x]:
if k!=p:
dfs(k,x)
if len(graph[x])==1 and x!=1:
leaf.append(x)
n = int(input())
graph = [[]]
for i in range(n+1):
graph.append([])
for i in range(n-1):
x,y=list(map(int,input().split(' ')))
graph[x].append(y)
graph[y].append(x)
l=[0 for i in range(n+1)]
prob=[0 for i in range(n+1)]
ans=0;
leaf =[]
dfs(1,0)
for i in leaf:
ans+=prob[i]*l[i]
if n==1:
print(1)
else:
print(ans)
``` | -1 | |
433 | A | Kitahara Haruki's Gift | PROGRAMMING | 1,100 | [
"brute force",
"implementation"
] | null | null | Kitahara Haruki has bought *n* apples for Touma Kazusa and Ogiso Setsuna. Now he wants to divide all the apples between the friends.
Each apple weights 100 grams or 200 grams. Of course Kitahara Haruki doesn't want to offend any of his friend. Therefore the total weight of the apples given to Touma Kazusa must be equal to the total weight of the apples given to Ogiso Setsuna.
But unfortunately Kitahara Haruki doesn't have a knife right now, so he cannot split any apple into some parts. Please, tell him: is it possible to divide all the apples in a fair way between his friends? | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of apples. The second line contains *n* integers *w*1,<=*w*2,<=...,<=*w**n* (*w**i*<==<=100 or *w**i*<==<=200), where *w**i* is the weight of the *i*-th apple. | In a single line print "YES" (without the quotes) if it is possible to divide all the apples between his friends. Otherwise print "NO" (without the quotes). | [
"3\n100 200 100\n",
"4\n100 100 100 200\n"
] | [
"YES\n",
"NO\n"
] | In the first test sample Kitahara Haruki can give the first and the last apple to Ogiso Setsuna and the middle apple to Touma Kazusa. | 500 | [
{
"input": "3\n100 200 100",
"output": "YES"
},
{
"input": "4\n100 100 100 200",
"output": "NO"
},
{
"input": "1\n100",
"output": "NO"
},
{
"input": "1\n200",
"output": "NO"
},
{
"input": "2\n100 100",
"output": "YES"
},
{
"input": "2\n200 200",
"o... | 1,634,934,223 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 15 | 4,505,600 | n = int(input())
a = list(map(int, input().split()))
# v = "YES"
# if(sum(a)%200==0):
# if(n%2!=0):
# if(100 not in a):
# v = "NO"
# else:
# v = "NO"
# print(v)
count1 = 0
count2 = 0
for i in a:
if(i==100):
count1 += 1
elif(i==200):
count2 += 1
if(count1%2==0 and count2%2==0):
print("YES")
else:
print("NO") | Title: Kitahara Haruki's Gift
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kitahara Haruki has bought *n* apples for Touma Kazusa and Ogiso Setsuna. Now he wants to divide all the apples between the friends.
Each apple weights 100 grams or 200 grams. Of course Kitahara Haruki doesn't want to offend any of his friend. Therefore the total weight of the apples given to Touma Kazusa must be equal to the total weight of the apples given to Ogiso Setsuna.
But unfortunately Kitahara Haruki doesn't have a knife right now, so he cannot split any apple into some parts. Please, tell him: is it possible to divide all the apples in a fair way between his friends?
Input Specification:
The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of apples. The second line contains *n* integers *w*1,<=*w*2,<=...,<=*w**n* (*w**i*<==<=100 or *w**i*<==<=200), where *w**i* is the weight of the *i*-th apple.
Output Specification:
In a single line print "YES" (without the quotes) if it is possible to divide all the apples between his friends. Otherwise print "NO" (without the quotes).
Demo Input:
['3\n100 200 100\n', '4\n100 100 100 200\n']
Demo Output:
['YES\n', 'NO\n']
Note:
In the first test sample Kitahara Haruki can give the first and the last apple to Ogiso Setsuna and the middle apple to Touma Kazusa. | ```python
n = int(input())
a = list(map(int, input().split()))
# v = "YES"
# if(sum(a)%200==0):
# if(n%2!=0):
# if(100 not in a):
# v = "NO"
# else:
# v = "NO"
# print(v)
count1 = 0
count2 = 0
for i in a:
if(i==100):
count1 += 1
elif(i==200):
count2 += 1
if(count1%2==0 and count2%2==0):
print("YES")
else:
print("NO")
``` | 0 | |
58 | A | Chat room | PROGRAMMING | 1,000 | [
"greedy",
"strings"
] | A. Chat room | 1 | 256 | Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*. | The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters. | If Vasya managed to say hello, print "YES", otherwise print "NO". | [
"ahhellllloou\n",
"hlelo\n"
] | [
"YES\n",
"NO\n"
] | none | 500 | [
{
"input": "ahhellllloou",
"output": "YES"
},
{
"input": "hlelo",
"output": "NO"
},
{
"input": "helhcludoo",
"output": "YES"
},
{
"input": "hehwelloho",
"output": "YES"
},
{
"input": "pnnepelqomhhheollvlo",
"output": "YES"
},
{
"input": "tymbzjyqhymeda... | 1,606,293,213 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 77 | 307,200 | def main():
char_in_hello = [char for char in 'hello']
message = input()
chars_to_remove = [char for char in message if char not in char_in_hello]
final_word = message
for char in chars_to_remove:
final_word = final_word.replace(char, '')
word_list = [char for char in final_word] # [h, e, l, h, l, o, o]
for char in char_in_hello:
num = 0
if char in 'heo':
num = 1
elif char == 'l':
num = 2
while word_list.count(char) != num:
if word_list.count(char) == 0:
break
if num == 1:
first_instance_index = word_list.index('char')
remove_index = word_list[first_instance_index+1:].index('char')
word_list.remove(remove_index)
elif num == 2:
first_instance_index = word_list.index('char')
second_instance = word_list[first_instance_index + 1:].index('char')
remove_index = word_list[second_instance + 1:].index('char')
word_list.remove(remove_index)
if word_list == char_in_hello:
print('YES')
else:
print('NO')
if __name__ == '__main__':
main() | Title: Chat room
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya has recently learned to type and log on to the Internet. He immediately entered a chat room and decided to say hello to everybody. Vasya typed the word *s*. It is considered that Vasya managed to say hello if several letters can be deleted from the typed word so that it resulted in the word "hello". For example, if Vasya types the word "ahhellllloou", it will be considered that he said hello, and if he types "hlelo", it will be considered that Vasya got misunderstood and he didn't manage to say hello. Determine whether Vasya managed to say hello by the given word *s*.
Input Specification:
The first and only line contains the word *s*, which Vasya typed. This word consisits of small Latin letters, its length is no less that 1 and no more than 100 letters.
Output Specification:
If Vasya managed to say hello, print "YES", otherwise print "NO".
Demo Input:
['ahhellllloou\n', 'hlelo\n']
Demo Output:
['YES\n', 'NO\n']
Note:
none | ```python
def main():
char_in_hello = [char for char in 'hello']
message = input()
chars_to_remove = [char for char in message if char not in char_in_hello]
final_word = message
for char in chars_to_remove:
final_word = final_word.replace(char, '')
word_list = [char for char in final_word] # [h, e, l, h, l, o, o]
for char in char_in_hello:
num = 0
if char in 'heo':
num = 1
elif char == 'l':
num = 2
while word_list.count(char) != num:
if word_list.count(char) == 0:
break
if num == 1:
first_instance_index = word_list.index('char')
remove_index = word_list[first_instance_index+1:].index('char')
word_list.remove(remove_index)
elif num == 2:
first_instance_index = word_list.index('char')
second_instance = word_list[first_instance_index + 1:].index('char')
remove_index = word_list[second_instance + 1:].index('char')
word_list.remove(remove_index)
if word_list == char_in_hello:
print('YES')
else:
print('NO')
if __name__ == '__main__':
main()
``` | -1 |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,601,907,227 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 80 | 466 | 0 | s=0
for _ in range(int(input())):
x,y,z=map(int,input().split())
s+=x+y+z
if(s):
print("NO")
else:
print("YES")
| Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).
Output Specification:
Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.
Demo Input:
['3\n4 1 7\n-2 4 -1\n1 -5 -3\n', '3\n3 -1 7\n-5 2 -4\n2 -1 -3\n']
Demo Output:
['NO', 'YES']
Note:
none | ```python
s=0
for _ in range(int(input())):
x,y,z=map(int,input().split())
s+=x+y+z
if(s):
print("NO")
else:
print("YES")
``` | 0 |
651 | B | Beautiful Paintings | PROGRAMMING | 1,200 | [
"greedy",
"sortings"
] | null | null | There are *n* pictures delivered for the new exhibition. The *i*-th painting has beauty *a**i*. We know that a visitor becomes happy every time he passes from a painting to a more beautiful one.
We are allowed to arranged pictures in any order. What is the maximum possible number of times the visitor may become happy while passing all pictures from first to last? In other words, we are allowed to rearrange elements of *a* in any order. What is the maximum possible number of indices *i* (1<=≤<=*i*<=≤<=*n*<=-<=1), such that *a**i*<=+<=1<=><=*a**i*. | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of painting.
The second line contains the sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000), where *a**i* means the beauty of the *i*-th painting. | Print one integer — the maximum possible number of neighbouring pairs, such that *a**i*<=+<=1<=><=*a**i*, after the optimal rearrangement. | [
"5\n20 30 10 50 40\n",
"4\n200 100 100 200\n"
] | [
"4\n",
"2\n"
] | In the first sample, the optimal order is: 10, 20, 30, 40, 50.
In the second sample, the optimal order is: 100, 200, 100, 200. | 1,000 | [
{
"input": "5\n20 30 10 50 40",
"output": "4"
},
{
"input": "4\n200 100 100 200",
"output": "2"
},
{
"input": "10\n2 2 2 2 2 2 2 2 2 2",
"output": "0"
},
{
"input": "1\n1000",
"output": "0"
},
{
"input": "2\n444 333",
"output": "1"
},
{
"input": "100\n... | 1,638,351,844 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 5 | 61 | 0 |
def main_function():
n = int(input())
a = sorted([int(i) for i in input().split(" ")])
hash_a = {}
for i in a:
if i in hash_a:
hash_a[i] += 1
else:
hash_a[i] = 1
counter = 0
is_there_non_zero = True
while is_there_non_zero:
internal_counter = -1
for i in hash_a:
if hash_a[i] > 0:
internal_counter += 1
hash_a[i] -= 1
counter += internal_counter
#print(hash_a)
for i in hash_a:
if hash_a[i] == 0:
is_there_non_zero = False
break
print(counter)
main_function() | Title: Beautiful Paintings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
There are *n* pictures delivered for the new exhibition. The *i*-th painting has beauty *a**i*. We know that a visitor becomes happy every time he passes from a painting to a more beautiful one.
We are allowed to arranged pictures in any order. What is the maximum possible number of times the visitor may become happy while passing all pictures from first to last? In other words, we are allowed to rearrange elements of *a* in any order. What is the maximum possible number of indices *i* (1<=≤<=*i*<=≤<=*n*<=-<=1), such that *a**i*<=+<=1<=><=*a**i*.
Input Specification:
The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=1000) — the number of painting.
The second line contains the sequence *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000), where *a**i* means the beauty of the *i*-th painting.
Output Specification:
Print one integer — the maximum possible number of neighbouring pairs, such that *a**i*<=+<=1<=><=*a**i*, after the optimal rearrangement.
Demo Input:
['5\n20 30 10 50 40\n', '4\n200 100 100 200\n']
Demo Output:
['4\n', '2\n']
Note:
In the first sample, the optimal order is: 10, 20, 30, 40, 50.
In the second sample, the optimal order is: 100, 200, 100, 200. | ```python
def main_function():
n = int(input())
a = sorted([int(i) for i in input().split(" ")])
hash_a = {}
for i in a:
if i in hash_a:
hash_a[i] += 1
else:
hash_a[i] = 1
counter = 0
is_there_non_zero = True
while is_there_non_zero:
internal_counter = -1
for i in hash_a:
if hash_a[i] > 0:
internal_counter += 1
hash_a[i] -= 1
counter += internal_counter
#print(hash_a)
for i in hash_a:
if hash_a[i] == 0:
is_there_non_zero = False
break
print(counter)
main_function()
``` | 0 | |
489 | C | Given Length and Sum of Digits... | PROGRAMMING | 1,400 | [
"dp",
"greedy",
"implementation"
] | null | null | You have a positive integer *m* and a non-negative integer *s*. Your task is to find the smallest and the largest of the numbers that have length *m* and sum of digits *s*. The required numbers should be non-negative integers written in the decimal base without leading zeroes. | The single line of the input contains a pair of integers *m*, *s* (1<=≤<=*m*<=≤<=100,<=0<=≤<=*s*<=≤<=900) — the length and the sum of the digits of the required numbers. | In the output print the pair of the required non-negative integer numbers — first the minimum possible number, then — the maximum possible number. If no numbers satisfying conditions required exist, print the pair of numbers "-1 -1" (without the quotes). | [
"2 15\n",
"3 0\n"
] | [
"69 96\n",
"-1 -1\n"
] | none | 1,500 | [
{
"input": "2 15",
"output": "69 96"
},
{
"input": "3 0",
"output": "-1 -1"
},
{
"input": "2 1",
"output": "10 10"
},
{
"input": "3 10",
"output": "109 910"
},
{
"input": "100 100",
"output": "1000000000000000000000000000000000000000000000000000000000000000000... | 1,683,715,622 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 2 | 46 | 0 | m, s = map(int, input().split())
ns = ""
while s > 0:
if s - 9 > 0:
s = s - 9
ns += '9'
else:
break
if s > 0:
ns += str(s)
if len(ns) == m:
print(ns[::-1], ns)
else:
print(-1, -1)
| Title: Given Length and Sum of Digits...
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a positive integer *m* and a non-negative integer *s*. Your task is to find the smallest and the largest of the numbers that have length *m* and sum of digits *s*. The required numbers should be non-negative integers written in the decimal base without leading zeroes.
Input Specification:
The single line of the input contains a pair of integers *m*, *s* (1<=≤<=*m*<=≤<=100,<=0<=≤<=*s*<=≤<=900) — the length and the sum of the digits of the required numbers.
Output Specification:
In the output print the pair of the required non-negative integer numbers — first the minimum possible number, then — the maximum possible number. If no numbers satisfying conditions required exist, print the pair of numbers "-1 -1" (without the quotes).
Demo Input:
['2 15\n', '3 0\n']
Demo Output:
['69 96\n', '-1 -1\n']
Note:
none | ```python
m, s = map(int, input().split())
ns = ""
while s > 0:
if s - 9 > 0:
s = s - 9
ns += '9'
else:
break
if s > 0:
ns += str(s)
if len(ns) == m:
print(ns[::-1], ns)
else:
print(-1, -1)
``` | 0 | |
59 | A | Word | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Word | 2 | 256 | Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word. | The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100. | Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one. | [
"HoUse\n",
"ViP\n",
"maTRIx\n"
] | [
"house\n",
"VIP\n",
"matrix\n"
] | none | 500 | [
{
"input": "HoUse",
"output": "house"
},
{
"input": "ViP",
"output": "VIP"
},
{
"input": "maTRIx",
"output": "matrix"
},
{
"input": "BNHWpnpawg",
"output": "bnhwpnpawg"
},
{
"input": "VTYGP",
"output": "VTYGP"
},
{
"input": "CHNenu",
"output": "chn... | 1,640,890,138 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 216 | 0 | s = input()
up = [i for i in s if i.isupper()]
sm = [i for i in s if i.islower()]
if len(up) <= len(sm):
print(s.lower())
else:
print(s.upper()) | Title: Word
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya is very upset that many people on the Net mix uppercase and lowercase letters in one word. That's why he decided to invent an extension for his favorite browser that would change the letters' register in every word so that it either only consisted of lowercase letters or, vice versa, only of uppercase ones. At that as little as possible letters should be changed in the word. For example, the word HoUse must be replaced with house, and the word ViP — with VIP. If a word contains an equal number of uppercase and lowercase letters, you should replace all the letters with lowercase ones. For example, maTRIx should be replaced by matrix. Your task is to use the given method on one given word.
Input Specification:
The first line contains a word *s* — it consists of uppercase and lowercase Latin letters and possesses the length from 1 to 100.
Output Specification:
Print the corrected word *s*. If the given word *s* has strictly more uppercase letters, make the word written in the uppercase register, otherwise - in the lowercase one.
Demo Input:
['HoUse\n', 'ViP\n', 'maTRIx\n']
Demo Output:
['house\n', 'VIP\n', 'matrix\n']
Note:
none | ```python
s = input()
up = [i for i in s if i.isupper()]
sm = [i for i in s if i.islower()]
if len(up) <= len(sm):
print(s.lower())
else:
print(s.upper())
``` | 3.946 |
49 | A | Sleuth | PROGRAMMING | 800 | [
"implementation"
] | A. Sleuth | 2 | 256 | Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions whatsoever that can be answered with "Yes" or "No". All the rest agree beforehand to answer the questions like that: if the question’s last letter is a vowel, they answer "Yes" and if the last letter is a consonant, they answer "No". Of course, the sleuth knows nothing about it and his task is to understand that.
Unfortunately, Vasya is not very smart. After 5 hours of endless stupid questions everybody except Vasya got bored. That’s why Vasya’s friends ask you to write a program that would give answers instead of them.
The English alphabet vowels are: A, E, I, O, U, Y
The English alphabet consonants are: B, C, D, F, G, H, J, K, L, M, N, P, Q, R, S, T, V, W, X, Z | The single line contains a question represented by a non-empty line consisting of large and small Latin letters, spaces and a question mark. The line length does not exceed 100. It is guaranteed that the question mark occurs exactly once in the line — as the last symbol and that the line contains at least one letter. | Print answer for the question in a single line: YES if the answer is "Yes", NO if the answer is "No".
Remember that in the reply to the question the last letter, not the last character counts. I. e. the spaces and the question mark do not count as letters. | [
"Is it a melon?\n",
"Is it an apple?\n",
"Is it a banana ?\n",
"Is it an apple and a banana simultaneouSLY?\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | none | 500 | [
{
"input": "Is it a melon?",
"output": "NO"
},
{
"input": "Is it an apple?",
"output": "YES"
},
{
"input": " Is it a banana ?",
"output": "YES"
},
{
"input": "Is it an apple and a banana simultaneouSLY?",
"output": "YES"
},
{
"input": "oHtSbDwzHb?",
... | 1,585,396,607 | 2,147,483,647 | Python 3 | OK | TESTS | 35 | 218 | 0 | from sys import stdin,stdout
str1 = stdin.readline().strip()
str1 = str1.replace(' ','')
print('YES' if str1[-2].upper() in ['A', 'E', 'I', 'O', 'U', 'Y'] else 'NO') | Title: Sleuth
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions whatsoever that can be answered with "Yes" or "No". All the rest agree beforehand to answer the questions like that: if the question’s last letter is a vowel, they answer "Yes" and if the last letter is a consonant, they answer "No". Of course, the sleuth knows nothing about it and his task is to understand that.
Unfortunately, Vasya is not very smart. After 5 hours of endless stupid questions everybody except Vasya got bored. That’s why Vasya’s friends ask you to write a program that would give answers instead of them.
The English alphabet vowels are: A, E, I, O, U, Y
The English alphabet consonants are: B, C, D, F, G, H, J, K, L, M, N, P, Q, R, S, T, V, W, X, Z
Input Specification:
The single line contains a question represented by a non-empty line consisting of large and small Latin letters, spaces and a question mark. The line length does not exceed 100. It is guaranteed that the question mark occurs exactly once in the line — as the last symbol and that the line contains at least one letter.
Output Specification:
Print answer for the question in a single line: YES if the answer is "Yes", NO if the answer is "No".
Remember that in the reply to the question the last letter, not the last character counts. I. e. the spaces and the question mark do not count as letters.
Demo Input:
['Is it a melon?\n', 'Is it an apple?\n', 'Is it a banana ?\n', 'Is it an apple and a banana simultaneouSLY?\n']
Demo Output:
['NO\n', 'YES\n', 'YES\n', 'YES\n']
Note:
none | ```python
from sys import stdin,stdout
str1 = stdin.readline().strip()
str1 = str1.replace(' ','')
print('YES' if str1[-2].upper() in ['A', 'E', 'I', 'O', 'U', 'Y'] else 'NO')
``` | 3.9455 |
11 | A | Increasing Sequence | PROGRAMMING | 900 | [
"constructive algorithms",
"implementation",
"math"
] | A. Increasing Sequence | 1 | 64 | A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*. In each move you may choose one element of the given sequence and add *d* to it. What is the least number of moves required to make the given sequence increasing? | The first line of the input contains two integer numbers *n* and *d* (2<=≤<=*n*<=≤<=2000,<=1<=≤<=*d*<=≤<=106). The second line contains space separated sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 (1<=≤<=*b**i*<=≤<=106). | Output the minimal number of moves needed to make the sequence increasing. | [
"4 2\n1 3 3 2\n"
] | [
"3\n"
] | none | 0 | [
{
"input": "4 2\n1 3 3 2",
"output": "3"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 1\n2 5",
"output": "0"
},
{
"input": "2 1\n1 2",
"output": "0"
},
{
"input": "2 1\n1 1",
"output": "1"
},
{
"input": "2 7\n10 20",
"output": "0"
},
... | 1,590,390,507 | 507 | Python 3 | WRONG_ANSWER | TESTS | 1 | 186 | 204,800 | import math
n,d = map(int,input().split())
l = list(map(int,input().split()))
c=0
for i in range(1,n):
if l[i]<=l[i-1]:
m = abs(l[i]-l[i-1])
c+=int(math.ceil(m/d))
l[i] = l[i]+(d)*2
print(c)
| Title: Increasing Sequence
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
A sequence *a*0,<=*a*1,<=...,<=*a**t*<=-<=1 is called increasing if *a**i*<=-<=1<=<<=*a**i* for each *i*:<=0<=<<=*i*<=<<=*t*.
You are given a sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 and a positive integer *d*. In each move you may choose one element of the given sequence and add *d* to it. What is the least number of moves required to make the given sequence increasing?
Input Specification:
The first line of the input contains two integer numbers *n* and *d* (2<=≤<=*n*<=≤<=2000,<=1<=≤<=*d*<=≤<=106). The second line contains space separated sequence *b*0,<=*b*1,<=...,<=*b**n*<=-<=1 (1<=≤<=*b**i*<=≤<=106).
Output Specification:
Output the minimal number of moves needed to make the sequence increasing.
Demo Input:
['4 2\n1 3 3 2\n']
Demo Output:
['3\n']
Note:
none | ```python
import math
n,d = map(int,input().split())
l = list(map(int,input().split()))
c=0
for i in range(1,n):
if l[i]<=l[i-1]:
m = abs(l[i]-l[i-1])
c+=int(math.ceil(m/d))
l[i] = l[i]+(d)*2
print(c)
``` | 0 |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces. | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,576,251,422 | 2,147,483,647 | Python 3 | OK | TESTS | 81 | 218 | 0 | n=int(input())
l=[]
for i in range(n):
l1=[int(x) for x in input().split()]
l.append(l1)
x=0
y=0
z=0
for i in l:
x=x+i[0]
y=y+i[1]
z=z+i[2]
if(x==0 and y==0 and z==0):
print("YES")
else:
print("NO") | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasya and decided to teach him a lesson. He gave the lazy student a seemingly easy task: You are given an idle body in space and the forces that affect it. The body can be considered as a material point with coordinates (0; 0; 0). Vasya had only to answer whether it is in equilibrium. "Piece of cake" — thought Vasya, we need only to check if the sum of all vectors is equal to 0. So, Vasya began to solve the problem. But later it turned out that there can be lots and lots of these forces, and Vasya can not cope without your help. Help him. Write a program that determines whether a body is idle or is moving by the given vectors of forces.
Input Specification:
The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100).
Output Specification:
Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not.
Demo Input:
['3\n4 1 7\n-2 4 -1\n1 -5 -3\n', '3\n3 -1 7\n-5 2 -4\n2 -1 -3\n']
Demo Output:
['NO', 'YES']
Note:
none | ```python
n=int(input())
l=[]
for i in range(n):
l1=[int(x) for x in input().split()]
l.append(l1)
x=0
y=0
z=0
for i in l:
x=x+i[0]
y=y+i[1]
z=z+i[2]
if(x==0 and y==0 and z==0):
print("YES")
else:
print("NO")
``` | 3.9455 |
912 | A | Tricky Alchemy | PROGRAMMING | 800 | [
"implementation"
] | null | null | During the winter holidays, the demand for Christmas balls is exceptionally high. Since it's already 2018, the advances in alchemy allow easy and efficient ball creation by utilizing magic crystals.
Grisha needs to obtain some yellow, green and blue balls. It's known that to produce a yellow ball one needs two yellow crystals, green — one yellow and one blue, and for a blue ball, three blue crystals are enough.
Right now there are *A* yellow and *B* blue crystals in Grisha's disposal. Find out how many additional crystals he should acquire in order to produce the required number of balls. | The first line features two integers *A* and *B* (0<=≤<=*A*,<=*B*<=≤<=109), denoting the number of yellow and blue crystals respectively at Grisha's disposal.
The next line contains three integers *x*, *y* and *z* (0<=≤<=*x*,<=*y*,<=*z*<=≤<=109) — the respective amounts of yellow, green and blue balls to be obtained. | Print a single integer — the minimum number of crystals that Grisha should acquire in addition. | [
"4 3\n2 1 1\n",
"3 9\n1 1 3\n",
"12345678 87654321\n43043751 1000000000 53798715\n"
] | [
"2\n",
"1\n",
"2147483648\n"
] | In the first sample case, Grisha needs five yellow and four blue crystals to create two yellow balls, one green ball, and one blue ball. To do that, Grisha needs to obtain two additional crystals: one yellow and one blue. | 500 | [
{
"input": "4 3\n2 1 1",
"output": "2"
},
{
"input": "3 9\n1 1 3",
"output": "1"
},
{
"input": "12345678 87654321\n43043751 1000000000 53798715",
"output": "2147483648"
},
{
"input": "12 12\n3 5 2",
"output": "0"
},
{
"input": "770 1390\n170 442 311",
"output"... | 1,558,037,451 | 2,147,483,647 | PyPy 3 | OK | TESTS | 38 | 139 | 0 | a, b = map(int, input().split())
x, y, z = map(int, input().split())
a_need = 0
b_need = 0
# yellow
a_need = x * 2
# green
a_need += y
b_need += y
# blue
b_need += z * 3
a_need = (a_need - a) if a_need > a else 0
b_need = (b_need - b) if b_need > b else 0
need_total = a_need + b_need
if need_total > 0:
print(need_total)
else:
print(0) | Title: Tricky Alchemy
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
During the winter holidays, the demand for Christmas balls is exceptionally high. Since it's already 2018, the advances in alchemy allow easy and efficient ball creation by utilizing magic crystals.
Grisha needs to obtain some yellow, green and blue balls. It's known that to produce a yellow ball one needs two yellow crystals, green — one yellow and one blue, and for a blue ball, three blue crystals are enough.
Right now there are *A* yellow and *B* blue crystals in Grisha's disposal. Find out how many additional crystals he should acquire in order to produce the required number of balls.
Input Specification:
The first line features two integers *A* and *B* (0<=≤<=*A*,<=*B*<=≤<=109), denoting the number of yellow and blue crystals respectively at Grisha's disposal.
The next line contains three integers *x*, *y* and *z* (0<=≤<=*x*,<=*y*,<=*z*<=≤<=109) — the respective amounts of yellow, green and blue balls to be obtained.
Output Specification:
Print a single integer — the minimum number of crystals that Grisha should acquire in addition.
Demo Input:
['4 3\n2 1 1\n', '3 9\n1 1 3\n', '12345678 87654321\n43043751 1000000000 53798715\n']
Demo Output:
['2\n', '1\n', '2147483648\n']
Note:
In the first sample case, Grisha needs five yellow and four blue crystals to create two yellow balls, one green ball, and one blue ball. To do that, Grisha needs to obtain two additional crystals: one yellow and one blue. | ```python
a, b = map(int, input().split())
x, y, z = map(int, input().split())
a_need = 0
b_need = 0
# yellow
a_need = x * 2
# green
a_need += y
b_need += y
# blue
b_need += z * 3
a_need = (a_need - a) if a_need > a else 0
b_need = (b_need - b) if b_need > b else 0
need_total = a_need + b_need
if need_total > 0:
print(need_total)
else:
print(0)
``` | 3 | |
75 | C | Modified GCD | PROGRAMMING | 1,600 | [
"binary search",
"number theory"
] | C. Modified GCD | 2 | 256 | Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two positive numbers is a number which both numbers are divisible by.
But your teacher wants to give you a harder task, in this task you have to find the greatest common divisor *d* between two integers *a* and *b* that is in a given range from *low* to *high* (inclusive), i.e. *low*<=≤<=*d*<=≤<=*high*. It is possible that there is no common divisor in the given range.
You will be given the two integers *a* and *b*, then *n* queries. Each query is a range from *low* to *high* and you have to answer each query. | The first line contains two integers *a* and *b*, the two integers as described above (1<=≤<=*a*,<=*b*<=≤<=109). The second line contains one integer *n*, the number of queries (1<=≤<=*n*<=≤<=104). Then *n* lines follow, each line contains one query consisting of two integers, *low* and *high* (1<=≤<=*low*<=≤<=*high*<=≤<=109). | Print *n* lines. The *i*-th of them should contain the result of the *i*-th query in the input. If there is no common divisor in the given range for any query, you should print -1 as a result for this query. | [
"9 27\n3\n1 5\n10 11\n9 11\n"
] | [
"3\n-1\n9\n"
] | none | 1,500 | [
{
"input": "9 27\n3\n1 5\n10 11\n9 11",
"output": "3\n-1\n9"
},
{
"input": "48 72\n2\n8 29\n29 37",
"output": "24\n-1"
},
{
"input": "90 100\n10\n51 61\n6 72\n1 84\n33 63\n37 69\n18 21\n9 54\n49 90\n14 87\n37 90",
"output": "-1\n10\n10\n-1\n-1\n-1\n10\n-1\n-1\n-1"
},
{
"input... | 1,529,495,158 | 2,147,483,647 | PyPy 3 | OK | TESTS | 60 | 810 | 8,396,800 | import math
a,b=input().split()
a,b=[int(a),int(b)]
n=int(input())
g=math.gcd(a,b)
ar=[]
i=1
while i*i<=g:
if g%i==0:
ar.append(i)
ar.append(g//i)
i+=1
ar.sort(reverse=True)
for i in range(0,n):
c,d=input().split()
c,d=[int(c),int(d)]
i=0
flag=0
if c==d:
if a%c==0 and b%c==0:
print(c)
else:
print("-1")
else:
while i < len(ar):
if ar[i] >= c and ar[i] <= d:
flag = 1
break
i += 1
if flag == 1:
print(ar[i])
else:
print("-1") | Title: Modified GCD
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Well, here is another math class task. In mathematics, GCD is the greatest common divisor, and it's an easy task to calculate the GCD between two positive integers.
A common divisor for two positive numbers is a number which both numbers are divisible by.
But your teacher wants to give you a harder task, in this task you have to find the greatest common divisor *d* between two integers *a* and *b* that is in a given range from *low* to *high* (inclusive), i.e. *low*<=≤<=*d*<=≤<=*high*. It is possible that there is no common divisor in the given range.
You will be given the two integers *a* and *b*, then *n* queries. Each query is a range from *low* to *high* and you have to answer each query.
Input Specification:
The first line contains two integers *a* and *b*, the two integers as described above (1<=≤<=*a*,<=*b*<=≤<=109). The second line contains one integer *n*, the number of queries (1<=≤<=*n*<=≤<=104). Then *n* lines follow, each line contains one query consisting of two integers, *low* and *high* (1<=≤<=*low*<=≤<=*high*<=≤<=109).
Output Specification:
Print *n* lines. The *i*-th of them should contain the result of the *i*-th query in the input. If there is no common divisor in the given range for any query, you should print -1 as a result for this query.
Demo Input:
['9 27\n3\n1 5\n10 11\n9 11\n']
Demo Output:
['3\n-1\n9\n']
Note:
none | ```python
import math
a,b=input().split()
a,b=[int(a),int(b)]
n=int(input())
g=math.gcd(a,b)
ar=[]
i=1
while i*i<=g:
if g%i==0:
ar.append(i)
ar.append(g//i)
i+=1
ar.sort(reverse=True)
for i in range(0,n):
c,d=input().split()
c,d=[int(c),int(d)]
i=0
flag=0
if c==d:
if a%c==0 and b%c==0:
print(c)
else:
print("-1")
else:
while i < len(ar):
if ar[i] >= c and ar[i] <= d:
flag = 1
break
i += 1
if flag == 1:
print(ar[i])
else:
print("-1")
``` | 3.78186 |
Subsets and Splits
Successful Python Submissions
Retrieves all records from the train dataset where the verdict is 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Retrieves records of users with a rating of 1600 or higher and a verdict of 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Counts the number of entries with a rating above 2000 and a verdict of 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Counts the number of entries with a 'OK' verdict, providing a basic overview of a specific category within the dataset.