| | #include <algorithm> |
| | #include <iostream> |
| | #include <set> |
| | #include <tuple> |
| | #include <utility> |
| | #include <vector> |
| | using namespace std; |
| |
|
| | const int INF = 1000000000; |
| | const int LIM = 1000002; |
| |
|
| | struct UnionFind { |
| | int N; |
| | vector<int> root, rank, sidx; |
| | vector<set<pair<int, int>>> S; |
| |
|
| | UnionFind(int _N) : N(_N), root(_N), rank(_N, 0), sidx(_N), S(_N) { |
| | for (int i = 0; i < N; i++) { |
| | root[i] = i; |
| | sidx[i] = i; |
| | S[i].emplace(-INF, -INF); |
| | S[i].emplace(INF, INF); |
| | } |
| | } |
| |
|
| | int find(int i) { |
| | if (root[i] != i) { |
| | root[i] = find(root[i]); |
| | } |
| | return root[i]; |
| | } |
| |
|
| | void merge(int i, int j) { |
| | i = find(i); |
| | j = find(j); |
| | if (i == j) { |
| | return; |
| | } |
| | if (rank[i] > rank[j]) { |
| | swap(i, j); |
| | } |
| | root[i] = j; |
| | if (rank[i] == rank[j]) { |
| | rank[j]++; |
| | } |
| | |
| | |
| | if (S[sidx[i]].size() > S[sidx[j]].size()) { |
| | swap(sidx[i], sidx[j]); |
| | } |
| | auto &SA = S[sidx[i]], &SB = S[sidx[j]]; |
| | for (auto p : SA) { |
| | if (p.first == -INF || p.first == INF) { |
| | continue; |
| | } |
| | auto it = prev(SB.lower_bound(make_pair(p.first + 1, -1))); |
| | if (it->second < p.first - 1) { |
| | it++; |
| | } |
| | while (it->first <= p.second + 1) { |
| | p.first = min(p.first, it->first); |
| | p.second = max(p.second, it->second); |
| | it = SB.erase(it); |
| | } |
| | SB.insert(p); |
| | } |
| | SA.clear(); |
| | } |
| | }; |
| |
|
| | int R, C, N, K; |
| | int H[LIM]; |
| | vector<pair<int, int>> children[LIM]; |
| | vector<tuple<int, int, int, int>> A; |
| |
|
| | pair<long long, long long> solve() { |
| | A.clear(); |
| | for (int i = 0; i < LIM; i++) { |
| | children[i].clear(); |
| | } |
| | |
| | cin >> R >> C; |
| | N = R * C; |
| | for (int i = 0, j; i < N; i++) { |
| | cin >> H[i]; |
| | if ((j = i - C) >= 0) { |
| | A.emplace_back(-min(H[i], H[j]), INF, i, j); |
| | } |
| | if (i % C > 0 && (j = i - 1) >= 0) { |
| | A.emplace_back(-min(H[i], H[j]), INF, i, j); |
| | } |
| | } |
| | for (int i = 0; i < N; i++) { |
| | int s; |
| | cin >> s; |
| | children[i].emplace_back(0, s); |
| | } |
| | cin >> K; |
| | for (int i = 0; i < K; i++) { |
| | int a, b, u; |
| | cin >> a >> b >> u; |
| | a--; |
| | b--; |
| | int j = a * C + b; |
| | if (i == 0) { |
| | children[j].clear(); |
| | } |
| | children[j].emplace_back(i, u); |
| | } |
| | |
| | for (int i = 0; i < N; i++) { |
| | for (int j = 0; j < children[i].size(); j++) { |
| | int a = children[i][j].first; |
| | int b = j < int(children[i].size()) - 1 |
| | ? children[i][j + 1].first - 1 |
| | : K - 1; |
| | A.emplace_back(-children[i][j].second, i, a, b); |
| | } |
| | } |
| | |
| | UnionFind U(N); |
| | sort(A.begin(), A.end()); |
| | pair<long long, long long> ans{0, 0}; |
| | for (const auto &t : A) { |
| | int h = -get<0>(t), i = get<1>(t), a = get<2>(t), b = get<3>(t); |
| | if (i < INF) { |
| | if (H[i] <= h) { |
| | continue; |
| | } |
| | ans.first += b - a + 1; |
| | auto &S = U.S[U.sidx[U.find(i)]]; |
| | |
| | auto it = prev(S.lower_bound(make_pair(a + 1, -1))); |
| | if (it->second < a - 1) { |
| | it++; |
| | } |
| | while (it->first <= b + 1) { |
| | a = min(a, it->first); |
| | b = max(b, it->second); |
| | ans.second -= it->second - it->first + 1; |
| | it = S.erase(it); |
| | } |
| | S.emplace(a, b); |
| | ans.second += b - a + 1; |
| | continue; |
| | } |
| | U.merge(a, b); |
| | } |
| | return ans; |
| | } |
| |
|
| | int main() { |
| | int T; |
| | cin >> T; |
| | for (int t = 1; t <= T; t++) { |
| | auto ans = solve(); |
| | cout << "Case #" << t << ": " << ans.first << " " << ans.second << endl; |
| | } |
| | return 0; |
| | } |
| |
|